Students performed a stair-climbing experiment to investigate the power output of the human body. Each student claimed a set of stairs while other student used a stopwatch to time the climb. The body mass, time, and vertical height reached by four students is given in the table. (Estimate g as 10m/s^2) which student generated the GREATEST amount of power in the experiment?

If the desk doesn't move, then it's not accelerating.

If it's not accelerating, then the net force on it is zero.

If the net force on it is zero, then any forces on it are balanced.

If there are only two forces on it and they're balanced, then they have equal strengths, and they point in opposite directions.

So the friction on the desk must be equal to your 245N .

Answer:

i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii)  Find the value of k first: F = 400 + k(15^2)                                              k = 28/9    F = 400 +(28/9)(30^2) = 320

Explanation:

Answer:

1.6×10⁻⁶ N.

Explanation:

From the question,

F = (V/r)q......................... Equation 1

Where F = Electric force on the raindrop, V = Potential difference between the base of the cloud and the ground, r = distance between the base of the cloud and the ground, q = the charge on a rain drop.

Given: V = 200MV = 200×10⁶ V, r = 500 m, q = 4.0×10⁻¹² C.

Substitute these values into equation 1

F = [(200×10⁶ )/500]×4.0×10⁻¹²

F = 1.6×10⁻⁶ N.

This question involves the concepts of potential difference and Columb's law.

The electrical force on the raindrop will be "A. 1.6 x 10⁻⁶ N".

According to Columb's Law the electrical force on the raindrop can be given by the following formula:

\(F=\frac{kq_1q_2}{r^2}\)------ equation (1)

where,

Now, the potential difference between cloud and ground can be given by the following formula:

\(V=\frac{kq_1}{r}\)

substituting this value in equation (1), we get:

\(F=\frac{Vq_2}{r}\)

using values:

\(F=\frac{(2\ x\ 10^8\ V)(4\ x\ 10^{-12}\ C)}{500\ m}\)

F = 1.6 x 10⁻⁶ N

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Answer:

Wire

Explanation:

To make a complete circuit, you need to connect the battery, the wire, and the bulb so that electricity will have a path to flow from the bottom of the battery, through the wire, into the little wire on the side of the bulb, up that wire, through the filament, down the other bulb wire to the bottom of the bulb base

Answer:

The sun gives off a type of light that carries energy, and the light from the desk lamp does not

Explanation:

I got it off a Quizlet hope this helps!!

Because of its interactions with molecules that excite them and lead them to move more quickly, infrared energy is perceived as heat, raising the internal temperature of the item receiving it.

Because the light from the desk lamp does not carry energy, whereas the light from the sun does. Due to the fact that sunlight transfers heat to molecules, while a desk lamp does not.

Because compared to light from a desk lamp, UV light contains energy. Because the mirror can only absorb the energy from the infrared lamp, which emits a sort of light that the desk lamp does not.

Sunlight's ultraviolet rays can cause paper and cloth to lose their colour. When ultraviolet light waves are present, the compounds in coloured dyes can degrade. Sunburns can also be brought on by ultraviolet rays.

Therefore, The light from the desk lamp does not carry energy, whereas the light from the sun does.

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Answer:

A= 150 J

Explanation:

Kinetic energy is the energy of an object in motion.

The formula for kinetic energy is ;

K.E = 1/2 * m *v²  where m is mass and v is velocity

Work done is equal to change in kinetic energy

W= Δ K.E

Given that K.E = 150 J

Taking that the ball was stationary before it was thrown, this makes its initial kinetic energy to be 0 J so the work done will be

W=  Δ K.E

W= 150 - 0

W= 150 J

Using the information depicted on the distance - time graph, the slope of the graph is could be used to infer the velocity of each cyclist. Hence, cyclist A and B do not have the same velocity at 3 seconds.

The steepness of slope on the distance - time graph gives the velocity of the cyclist. At time, t = 0 ; the cyclist A has a greater slope than cyclist B. Hence, the velocity of the cyclists is different.

Therefore, the cyclists do not have the same velocity at time, t = 3 seconds.

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The speed of the water current will carry the boat to travel in a diagonal path across the river in 6.0 minutes or 0.1 hours. The distance of the diagonal path is the resultant displacement.

Using Pythagoras' theorem, the components of this resultant velocity are the velocity of the boat and the velocity of the water. Before this can be solved, the displacements must be first calculated.

Solving for the resultant displacement

Resultant^2 = (displacement caused by water)^2 + (0.5 km)^2

Resultant^2 = (8 km/h * 0.1 h)^2 + (0.5 km)^2

Resultant^2 = (0.8 km)^2 + (0.5 km)^2

Resultant^2 = 0.89 km^2

Resultant = 0.9434 km

Solving for the velocity of the boat relative to the water's surface

Velocity = resultant displacement / elapsed time

Velocity = 0.9434 km / 0.1 h

Velocity = 9.43 km/ h

Solving for the speed of the boat relative to the water's surface

Speed = width of river / elapsed time

Speed = 0.5 km / 0.1 h

Therefore the answer is 5 km / h.

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120m per minute

If you take 960 and divide it by 8 you get 120 then you have the answer 120m per minute

The minimum coefficient of friction needed to keep the car from crashing down is 16.3. That's mean the friction force between the tires and the surface of the wall of death must be at least 16.3 times greater than the normal force acting on the car.

The minimum coefficient of friction needed to keep the car from crashing down is determined by the forces acting on the car. When a car is driving in a circle, it is constantly being pulled outward by a force called centrifugal force. This force is equal to the mass of the car multiplied by the square of its speed, divided by the radius of the circle it is driving in. In order to keep the car from crashing, the friction force between the tires and the surface of the wall of death must be greater than or equal to the centrifugal force.

The formula for the minimum coefficient of friction needed is:

μ = Fcentrifugal / Fnormal

where μ is the coefficient of friction, Fcentrifugal is the centrifugal force acting on the car, and Fnormal is the normal force acting on the car.

To calculate the minimum coefficient of friction needed, you need to first calculate the centrifugal force acting on the car. The formula for this is:

Fcentrifugal = \(mv^2 / r\)

where m is the mass of the car, v is the speed of the car, and r is the radius of the circle.

Plugging in the values from your question, the centrifugal force is:

Fcentrifugal = \((800 kg) * (80 km/h)^2 / (5 m)\)

= 128,000 N

The normal force is equal to the weight of the car, which is the mass of the car multiplied by the acceleration due to gravity. The weight of the car is:

Fnormal = (800 kg) * (9.8 m/s²)

= 7,840 N

Plugging these values into the formula for the minimum coefficient of friction, we get:

μ = 128,000 N / 7,840 N

= 16.3

Thus, the minimum coefficient of friction is 16.3.

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There is effort of 75 lbs is required to lift a 250 lbs wheelbarrow load if the handle is five feet from the axle and the center of the load bin is eighteen inches from the axle.

Mechanical advantage is defined as a measure of the ratio of output force to input force in a system, It is used to analyze the forces in simple machines like levers and pulleys.

Mechanical advantage = output force(load) /input force (effort)

As given in the problem there is 250 lbs wheelbarrow load which is 18 inches away from the axle and the effort is acting on handle which is five feet away from the axle

In this situation axle act as the pivot point around both the load and effort are balanced by their moment of forces.

By Balancing the moment of forces on both sides

Load× (distance from axle to load)= effort ×( distance from axle to handle )

250 lb × 18 inches = effort × 5 feet

As we know that 12 inches = 1 feet

250×18 = effort ×5×12

effort = (250×18)/(60)

Effort = 75 lbs

Hence ,an effort of 75 lbs is required to lift a 250 lbs wheelbarrow load if the handle is five feet from the axle and the center of the load bin is eighteen inches from the axle.

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Hope this above expression for fringe width helps you.

Answer:

Explanation:

To obtain an expression for fringe width, we need to consider the phenomenon of interference in wave patterns, such as in the case of Young's double-slit experiment. In this experiment, a coherent light source, such as a laser, is passed through two closely spaced slits, creating an interference pattern of light and dark fringes on a screen placed behind them.

The fringe width (w) can be determined using the following expression:

w = λ * D / d

Where:

- λ represents the wavelength of the light used,

- D is the distance between the double-slit and the screen,

- d is the separation between the two slits.

The diagram accompanying this explanation would illustrate a coherent light source passing through the double slits, with the resulting pattern of light and dark fringes observed on the screen placed behind them. The distance D between the double-slit and the screen, as well as the separation d between the slits, would be indicated in the diagram.

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The intensity reflection coefficient (irc) is 1.

The ratio of the intensity of the reflected wave to the incident (transmitted) wave is known as the intensity reflection coefficient.

Intensity of incident (transmitted) sound wave = 50 W/cm².

As it  is totally reflected,  intensity of the reflected sound  wave = 50 W/cm².

Hence,  intensity reflection coefficient =

intensity of the reflected sound wave ÷ Intensity of incident sound wave

= 50  W/cm² /  50 W/cm².

= 1.

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answer: 3.2 volts

i hope this is right

Answer:

C) To magnetize the needle

Explanation: I took the test!

When a magnet is moved away or towards a needle, current is bound to flow through the needle. The answer is  to give the needle an electric charge.

A magentic is a material that has megnetic properties, it can also be defined as any material that attracts metals to itself.

A major uitlity of a magnet is found in the generator using the principle of electro-magnetic induction to generate electric current.

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Physical activity and exercise typically lead to higher energy levels (C).

Physical activity and exercise refer to any bodily movement that requires energy expenditure by the muscles. This can include activities such as walking, running, cycling, swimming, weightlifting, and team sports, among others.

Physical activity and exercise are important for maintaining good health and well-being, as they can help to improve cardiovascular fitness, muscular strength and endurance, flexibility, and overall body composition.

Physical activity and exercise are known to stimulate the production of endorphins, which are natural mood elevators. This can lead to increased energy levels and a general feeling of well-being.

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For an AP projection of the coccyx, the central ray is directed: The central ray is angled 10 degrees cephalic to the coccyx. The patient is placed in the prone position for this projection. The coccyx is clearly visible on the AP projection because it is projected through the symphysis pubis and the sacrum.

The distal end of the coccyx is visible as well. This AP projection is commonly used to detect sacrococcygeal injuries that are not seen on other projections. In an AP projection of the coccyx, the central ray is directed through the body part of interest from posterior to anterior, in this case, the coccyx. The central ray is angled cephalic to the coccyx at an angle of about 10 degrees, which helps to separate the coccyx from the sacrum and pelvic floor.

The technique for taking the projection is crucial. The patient should lie prone, with their hips extended, and their legs together, in order to correctly position the coccyx. The central ray should be positioned perpendicular to the area of interest, which is the coccyx. Finally, the image should be captured during quiet respiration, as the coccyx is typically displaced by respiratory movement.

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The force exerted by only the fluid on the window of an instrument probe at this depth is 740 N.

To determine the force exerted by only the fluid on the window of an instrument probe, we need to use the equation for pressure:

pressure = density x gravity x depth

where density is the density of the fluid, gravity is the acceleration due to gravity, and depth is the distance from the surface of the fluid to the window of the instrument probe.

Assuming that the fluid is water, with a density of 1000 kg/m³, and that the instrument probe is at a depth of 10 meters, we can calculate the pressure:

pressure = 1000 kg/m³ x 9.81 m/s² x 10 m
pressure = 98,100 Pa

To find the force exerted on the circular window, we need to calculate the area of the window:

area = π x (diameter/2)²
area = π x (3.10 cm/2)²
area = 7.55 cm²

Now we can calculate the force:

force = pressure x area
force = 98,100 Pa x 7.55 cm²
force = 740 N

Therefore, the force exerted by only the fluid on the window of an instrument probe at this depth is 740 N.

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The average flow speed of air through a constriction in the bronchus that is double the speed of air in the bronchus, the pressure drop in the constriction is `0.054 kPa`.

Assuming incompressible flow can be calculated using the Bernoulli's equation. The Bernoulli's equation is given by;` P₁ + 1/2ρv₁² = P₂ + 1/2ρv₂²`Where;`P₁` is the initial pressure, `P₂` is the final pressure,` v₁` is the initial velocity,` v₂` is the final velocity and`ρ` is the density of the fluid. Substituting the values; `P₁ = ?` (unknown)`v₁ = 15 cm/s` `v₂ = 2v₁ = 30 cm/s``ρ = constant` The pressure drop in the constriction, `ΔP = P₁ - P₂`.

Then the Bernoulli's equation can be written as;` P₁ + 1/2ρv₁² = P₂ + 1/2ρv₂²`Now, substituting the given values;` P₁ + 1/2ρv₁² = P₂ + 1/2ρv₂²``P₁ - P₂ = 1/2ρv₂² - 1/2ρv₁²`At first, let's convert the given velocities into meters per second; `v₁ = 15 cm/s = 0.15 m/s`` v₂ = 2v₁ = 30 cm/s = 0.3 m/s` Now substitute the values; `P₁ - P₂ = 1/2ρv₂² - 1/2ρv₁²``P₁ - P₂ = 1/2 × ρ × (0.3 m/s)² - 1/2 × ρ × (0.15 m/s)²`The density of air `ρ` can be assumed to be constant and its value is `1.2 kg/m³

.Substituting the values;` p₁ - P₂ = 1/2 × 1.2 kg/m³ × (0.3 m/s)² - 1/2 × 1.2 kg/m³ × (0.15 m/s)²``P₁ - P₂ = 0.054 kPa` Therefore, the pressure drop in the constriction is `0.054 kPa`.

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The distance to the bending mark when fabricating a 90°-bend is equal to the stub-up minus the take-up. Therefore, the correct answer is option b.

When bending a conduit or pipe to create a 90° angle, the bending mark represents the point at which the bend starts. The stub-up is the length of the conduit that extends vertically from the bottom of the bend to the end of the conduit. The take-up is a measurement that accounts for the additional length of the conduit that is consumed during the bending process.

To find the distance to the bending mark, you need to subtract the take-up from the desired stub-up length. This will give you the correct position to mark on the conduit before starting the bending process. Following this guideline will help ensure that your 90°-bend will be accurate and meet the required specifications.

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The true statement about mitosis and meiosis is that DNA replication occurs before the division of the nucleus.

option B.

Meiosis is the type of cell division that creates egg and sperm cells.

Mitosis on other hand is a fundamental process for life. During mitosis, a cell duplicates all of its contents, including its chromosomes, and splits to form two identical daughter cells.

The similarity between meiosis and mitosis is that both mitosis and meiosis take place in the cell nuclei, which can be observed under a microscope. So both occurs in the nucleus and DNA replication must occur before the division of the nucleus.

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The energy efficiency of the mixer is 70%.

The Sankey diagram shows the amount of energy absorbed, the amount of useful energy, and the amount of non-useful energy.

The efficiency of a device

η = (U/I) × 100%

I = U + W

100% = U + 30%

U = 100% - 30%

U = 70%

The efficiency of the mixer

η = (U/I) × 100%

η = (70%/100%) × 100%

η = (7/10) × 100%

η = 70%

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Correct question:

Imagine that a 1200 kg vehicle speeds up from rest to 20.0 m/s in 80 s.

How much work was done on the car? (Answer in 3 sig figs)

Answer:

the work done on the vehicle is 2.40 x 10⁵ J

Explanation:

Given;

mass of the vehicle, m = 1200 kg

initial velocity of the vehicle, u = 0

final velocity of the vehicle, v = 20 m/s

time of motion of the vehicle, t = 80 s

The distance moved by the vehicle is calculated as;

\(s = (\frac{v + u}{2} )t\\\\s = (\frac{20+ 0}{2} )(80)\\\\s = 800 \ m\)

The force applied to the vehicle is calculated as;

\(F = ma = \frac{m v}{t} = \frac{1200 \times 20}{80} = 300 \ N\\\\\)

The work done on the vehicle is calculated as;

W = F x d

W = 300 x 800

W = 2.4 x 10⁵ J.

Therefore, the work done on the vehicle is 2.40 x 10⁵ J

The necessary radius of the central sheave to make the fall time exactly 4 s, using the same pendulum with weights at R=175 mm, is 19.685 mm.

The fall time of a pendulum depends on its length. The formula for the period of a simple pendulum is given by:

T = 2π√(L/g)

where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

In this case, the pendulum length is the sum of the radius of the central sheave (let's call it R') and twice the radius of the weights (175 mm). Therefore, we have:

L = R' + 2R

Given that the fall time is 4 s, we can substitute the values into the period formula and solve for R':

4 = 2π√((R' + 2R)/g)

Squaring both sides of the equation and rearranging, we get:

16 = 4π²(R' + 2R)/g

Simplifying further:

R' + 2R = 16g/(4π²)

Substituting the value of R (175 mm) and g (acceleration due to gravity), we can calculate the radius of the central sheave:

R' = 16(9.8)/(4π²) - 2(175) ≈ 19.685 mm

The radius of the central sheave necessary to achieve a fall time of exactly 4 s, using the same pendulum with weights at R=175 mm, is approximately 19.685 mm.

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Answer:

Vf = 34.3 m/s

1st equation of motion was used to solve.

Explanation:

In order to find the final speed of the cow, when it hits the bushes, we can use first equation of motion:

Vf = Vi + gt

where,

Vf = Final Velocity of Cow = ?

Vi = Initial Velocity of Cow = 0 m/s

g = acceleration due to gravity = 9.8 m/s²

t = time taken = 3.5 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(3.5 s)

Vf = 34.3 m/s

1st equation of motion was used to solve.

The first one!

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Answer:

Models change to accommodate new discoveries.

Explanation:

Scientific models are based on current scientific knowledge. This means that when new discoveries are made they are subject to change.

Answer:

Bang on a drum.  

Explanation:

Amplitude is making loud sounds

(a) The electric field is zero at a point 0.33 m from the 25.0 μC charge and 0.17 m from the 45.0 μC charge.

(b) The electric field halfway between the charges is 9.98 x 10⁶ N/C.

(a) To find the point at which the electric field is zero, we need to set the electric fields from the two charges equal to each other and solve for the distance from one of the charges.

Let x be the distance from the 25.0 μC charge, then the distance from the 45.0 μC charge is 0.500 - x.

Using Coulomb's law, we can write the electric fields as:

E₂₅ = (k)(25.0 μC) / x²
E₄₅ = (k)(45.0 μC) / (0.500 - x)²

Setting these equal to each other and simplifying gives:

(25.0 μC) / x² = (45.0 μC) / (0.500 - x)²
(25.0 μC)(0.500 - x)² = (45.0 μC)x²

Taking roots on both sides, we get:

5.0 μC(0.500 - x) = 3√5μC x

Solving for x, we then get x= 0.33m.

So the electric field is zero at a point 0.33 m from the 25.0 μC charge and 0.17 m from the 45.0 μC charge.

(b) The electric field halfway between the charges is the sum of the electric fields from each charge at that point.

The distance from each charge is 0.250 m, so we can use Coulomb's law to find the electric fields:

E₂₅ = (k)(25.0 μC) / (0.250 m)² = (k)(25.0 μC) / 0.0625 m²
E₄₅ = (k)(45.0 μC) / (0.250 m)² = (k)(45.0 μC) / 0.0625 m²

The total electric field is then:

E = E₂₅ + E₄₅ = (k)(25.0 μC + 45.0 μC) / 0.0625 m² = (k)(70.0 μC) / 0.0625 m²
E = (8.99 x 10⁹ N·m²/C²)(70.0 x 10⁻⁶ C) / 0.0625 m²
E = 9.98 x 10⁶ N/C

So the electric field halfway between the charges is 9.98 x 10⁶ N/C.

Therefore, the electric field is zero at a point 0.33 m from the 25.0 μC charge and 0.17 m from the 45.0 μC charge, and the electric field halfway between the charges is 9.98 x 10⁶ N/C.

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