Answer:
848.23
Step-by-step explanation:
hope this got you the right anwser
The mode is an appropriate measure of central tendency for Group of answer choices data that are bimodal use with other measures of central tendency data that are on a nominal scale all of the above
The correct answer is: data that are bimodal.
The mode is an appropriate measure of central tendency for data that are bimodal. Bimodal data refers to a distribution with two modes, or peaks. In this case, the mode can be helpful in identifying the two most common values in the data.
However, the mode is not suitable for data that are on a nominal scale. Nominal scale refers to data that are categorized into distinct categories or labels, such as colors or names. Since nominal data does not have a natural order or numerical value, it does not make sense to calculate a mode.
So, the correct answer is: data that are bimodal.
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Please help me with my problem it's due today.
The measure of angle m∠EFG formed by the two tangents outside the circle is 53⁰.
What is the measure of angle EFG?
The measure of angle EFG is calculated by applying the following formula as shown below;
difference between exterior and interior arc EG = 2 ( m∠EFG )
"the angle formed by the interception of two tangents outside a circle is half the positive difference of the measure of the intercepted arcs".
So we will have the following equation and determine the value of x;
58x + 1 - ( 360 - (58x + 1)) = 2 (15x - 7)
58x + 1 - (360 - 58x - 1 ) = 30x - 14
58x + 1 - (359 - 58x) = 30x - 14
58x + 58x + 1 - 359 = 30x - 14
116x - 358 = 30x - 14
116x - 30x = 358 - 14
86x = 344
x = 344/86
x = 4
The measure of angle m∠EFG = 15x - 7
m∠EFG = 15(4) - 7
m∠EFG = 60 - 7
m∠EFG = 53 ⁰
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A skydiver must land on a target of three concentric circles. The diameter of the center circle is 2 yards, and the circles are spaced 1 yard apart. Find the probability that she will land on a shaded area. Group
The probability that skydiver will land on a shaded area will be \(\frac{1}{9}\).
We have,
Three concentric circles,
And,
The diameter of the center circle = 2 yards,
Now,
According to the question,
The diameter of the circle next to center circle i.e. 2nd circle = 2 + 2 = 4 yards,
And,
The diameter of the 3rd circle next to 2nd circle = 4 + 2 = 6 yards,
And,
Area of circle = πr²
So,
Area of the shaded circle = πr² = π(1)² = 1π
Now,
the area of the 3rd circle = πr² = π(3)² = 9π
Now,
The probability of landing in shaded area = \(\frac{Area\ of\ Centre\ circle }{Area\ of\ Outer\ circle }\)
i.e.
The probability of landing in shaded area = \(\frac{1\pi }{9\pi }\)
On solving we get,
The probability of landing in shaded area = \(\frac{1}{9}\)
Hence we can say that the probability that skydiver will land on a shaded area will be \(\frac{1}{9}\).
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1. Natoy's rectangular swimming pool has the length of 3m more than thrice its
width. What are the dimensions of the pool if it has an area of 216m2?
Width (w)
Length (/) = 3w + 3
Answer:
Step-by-step explanation:
Given
Natoy's rectangular swimming pool has the length of 3m more than thrice its
width.
Width=w
Length =3w+3
So
Area of the rectangular swimming pool=length×width
216=(3w+3)×w
216=3w^2+3w
3w^2+3w-216=0
3(w^2+w-72)=0
W^2+w-72=0
W^2+(9-8)w-72=0
W^2+9w-8w-72=0
W(w+9)-8(w+9)=0
(W+9)(w-8)=0
Sotwo value of w are 8,-9
We take positive value for rectangular swimming so we take w=8m
Width=8m
Length=3×8+3
= 24+3
=27m
Lincoln High School earned $5,100 in ticket sales for a play. The cost per ticket was 12$. Let t represent the number of tickets sold to the play. Which of the following equations could be used to determine how many tickets were sold to the play
Answer:5100 divided by 12=425
Step-by-step explanation:
Sydney's Games is selling all games at a 25% discount. However, you also have a membership card at the
store, which gives you an additional 15% off. What will you end up paying for $100 worth of games?
Show your work!
The required selling price of the game after two discount is $63.75.
What is discount?The term discount designates a sum or a percentage subtracted from an item's usual selling price. Make sure you need all of the items you plan to get before waiting until after the holiday to make a purchase. A discount is a decrease in the cost of a commodity or service.
According to question:Discount = 25%,
Additional discount = 15%
Then,
Net discount is = 36.25%
We have,
Price of game = $100
Discount amount = 36.25% of $100 = $36.25
So, the selling price of the game after discount = $100 - $36.25
= $63.75
Thus, required selling price of the game is $63.75.
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what is the volume of the cone to the nearest cubic centimeter?
Answer:
301.44
Step-by-step explanation:
five to the power of 3
Answer:
125
Step-by-step explanation:
5 × 5 × 5 = 125
5 x 5 = 25
25 x 5 = 125
Hey there!
5^3
= 5 * 5 * 5
= 25 * 5
= 125
Therefore, your answer is: 125
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
A company makes skis for junior skiers with lengths of 120 to 140 cm inclusive. Identify the compoundinequality and graph that show these lengths.
The juniors skiers can have the lengths of 120 to 140 as we can see the skiers lengths can touch the length of 120 and 140 that is why in the inequality we will use less than or equal to and in the number line we will see a filled circle in 120 and 140.
Therefore the solution is
In this problem you will calculate the area between f(x) = 8x2 +3 and the -axis over the interval (0, 2] using a limit of right-endpoint Riemann sums: F(xk)Ax Area lim k1 Express the following quantities in terms of n, the number of rectangles in the Riemann sum, and k, the index for the rectangles in the Riemann sum. a. We start by subdividing 0, 2 into n equal width subintervals 0, 1, 1,2, ..., [xn 1, Tn] each of width
The width of subintervals of f(x) = \(8x^2+3\) with x-axis over the interval [0,2] is (2/n).
How to calculated width of subintervals?Width of subintervals (Δx) is part of Riemann Sum formula which is represent the interval value of rectangle. For example in attached image, the interval value of first rectangle is 1 (from 0 to 1), the second rectangle is 1 (from 1 to 2), etc.
from x-axis over the interval [0, 2] we get,
a = 0
b = 2
Width of subintervals can be calculated with this formula,
Δx = (b-a)/n
= (2-0)/n
= 2/n
Thus, the width of subinterval is (2/n) for \(8x^2+3\) with x-axis over the interval [0,2].
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Which complex number has an absolute value of 5?
–3 + 4i
2 + 3i
7 – 2i
9 + 4
Answer:
Step-by-step explanation:
-3 + 4i
value = square( (-3)^2 + (4i)^2 ) = sqr(9 + 16) = sqr(25) = 5
The absolute value is like the Pythagoras theorem
a school gives an entry exam for admission. suppose the score of this exam follows a normal distribution n(400, 60). this year, the school decides to admit students who score in the top 30%. suppose a student scored 428 on the test. will the student be admitted? explain your reasoning.
The student whο scοred 428 will nοt be admitted tο the schοοl because their scοre did nοt fall in the tοp 30% οf the distributiοn.
What is frequency distributiοn?The gathered data is arranged in tables based οn frequency distributiοn. The infοrmatiοn cοuld cοnsist οf test results, lοcal weather infοrmatiοn, vοlleyball match results, student grades, etc. Data must be presented meaningfully fοr understanding after data gathering. A frequency distributiοn graph is a different apprοach tο displaying data that has been represented graphically.
Tο find the z-scοre οf the student whο scοred 428, we can use the fοrmula:
z = (x - μ) / σ
where x is the student's scοre, μ is the mean οf the distributiοn (400 in this case), and σ is the standard deviatiοn οf the distributiοn (60 in this case).
Plugging in the values, we get:
z = (428 - 400) / 60 = 0.467
Since the z-scοre οf the student is less than 0.524, which is the z-scοre cοrrespοnding tο the tοp 30% οf the distributiοn, we can cοnclude that the student did nοt scοre in the tοp 30%.
Therefοre, the student will nοt be admitted tο the schοοl based οn the admissiοn criteria οf scοring in the tοp 30%.
Hence, the student whο scοred 428 will nοt be admitted tο the schοοl because their scοre did nοt fall in the tοp 30% οf the distributiοn.
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The slope of the line below is -1/7. write a point slope equation of the line using the coordinates of the labeled point.
The equation of a straight line can be written if its slope and any one point lying on it is given. The equation of the line for given slope and point is (y - 3) = -1 / 7 × (x - 3). The correct answer is option B.
What is the equation for a straight line?A straight line can be written in the form of equation as, y = mx + c.
Two straight lines intersect each other only at one point.
When two straight lines are parallel to each other the angle between them is zero.
Given that,
The slope of the line = -1 / 7
The coordinate of the point on the line = (3,3)
The equation of a line having slope m and passing through a point (x₁, y₁) is given as,
(y - y₁) / (x - x₁) = m
Thus, the equation of the line for given slope and point is given as,
(y - 3) / (x - 3) = -1 / 7
=> (y - 3) = -1 / 7 × (x - 3)
Hence, the equation of the line for given slope and point is (y - 3) = -1 / 7 × (x - 3).
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Which monomial is a perfect cube? 49p9q3r24 81p12q15r12 121p9q3r6 343p6q21r6.
The monomial is a perfect cube is \(\rm 343p^6q^{21}r^6\).
Perfect cubes;Perfect cubes are the numbers that are the triple product of the same number.
We have to determine
Which monomial is a perfect cube?
A perfect cube monomial must have three identical roots, such that the product of the roots equals the perfect square monomial.
It must be possible for the coefficient of a perfect cube monomial to be written in the form n3, where n equals the cube root of the coefficient.
A perfect cube monomial must have exponents on the variables.
Then
The monomial is a perfect cube is;
\(\rm= 343p^6q^{21}r^6\\\\= \sqrt[3]{ 343 }= 7\)
Hence, the monomial is a perfect cube is \(\rm 343p^6q^{21}r^6\).
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Answer:
D
Step-by-step explanation: right on edge
I need help! I'm running out of coins!!!
Answer:
4) m∠F ≈ 67°
5) m∠x ≈ 53°
6) m∠? ≈ 16°
Step-by-step explanation:
(It's not letting me post, so I'll attach screenshots:)
what is the ending value of sum, if the input is: 2 5 7 3? all variables are integers. a. 5 b. 10 c. 15 d. 12
12 is the ending value of sum, if the input is: 2 5 7 3. all variables are integers.
An integer is a whole number with no fractional or decimal components. It is a subset of the real numbers, and can be either positive, negative, or zero. An integer can be written without a decimal point, and can be expressed as an exact, repeating number in a fractional or decimal form. Examples of integers include -2, 5, 0, and 17.
Integers are a special type of whole number that are used to represent counting numbers, negative numbers, and zero. They are a subset of the real numbers, which are any number that can be represented on a number line. Integers are non-fractional numbers that do not contain decimal points or other decimal components. They can be expressed as an exact number, such as -2 or 5, or as a repeating decimal or fraction, such as 3/2 or 0.75.
The answer is d. 12. To calculate the ending value of sum, we need to add up all the integers. In this case, the integers are 2, 5, 7, and 3. When added together, 2 + 5 + 7 + 3 = 17. Therefore, the ending value of sum is 17 - 5 = 12.
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The diagram shows a circle with centre O.
A, B & C lie on the circumference of this circle.
Given that AC is a diameter of the circle and ∠BCA = 5 × ∠BAC, find the size of ∠BCA as highlighted in the diagram.
Answer:
∠ BCA = 75°
Step-by-step explanation:
∠ ABC = 90° ( angle in a semicircle )
then the 2 remaining angles in Δ ABC = 90° , that is
∠ BAC + ∠ BCA = 90° ( ∠ BCA = 5 × ∠ BAC )
∠ BAC + 5 ∠ BAC = 90°
6 ∠ BAC = 90° ( divide both sides by 6 )
∠ BAC = 15°
Then
∠ BCA = 90° - 15° = 75°
let y1 and y2 have the joint density function f(y1, y2) = e−(y1 y2), y1 > 0, y2 > 0, 0, elsewhere. (a) find the marginal density function for y1. f1(y1) = , where y1 >
As per the given joint density function, the marginal density function for y1 is f1(y1) = 1/y1, where y1 > 0.
Joint density functions are used to describe the distribution of two or more variables. They provide the probability of observing certain values for multiple variables at the same time.
For the given joint density function
\(= > f(y1, y2) = e^{-(y1 y2)}, y1 > 0, y2 > 0\)
and 0 elsewhere, we are asked to find the marginal density function for y1, which is denoted by f1(y1).
Here the marginal density function of y1 is found by integrating the joint density function over all possible values of y2. It gives us the probability density for y1 alone, without considering the value of y2.
In order to find f1(y1), we integrate f(y1, y2) with respect to y2, from 0 to infinity:
=> f1(y1) = ∫ f(y1, y2)dy2
\(= > \int f(y1, y2) = \int {e^{-(y1 y2)},dy2}\)
\(= -(1/y1)e^{-(y1 y2)}\)
= −(1/y1) * 0 + (1/y1) = 1/y1
Here it is important to note that the marginal density function must always be non-negative, since it represents a probability density.
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Maria makes $8.55 an hour working at the jewelry store. Her paycheck shows that she worked 32.5 hours over the past week. How much money did Maria make? (Rounded to the nearest cent)
Answer:
277.88
Step-by-step explanation:
\(\mathrm{Multiply\:without\:the\:decimal\:points,\:then\:put\:the\:decimal\:point\:in\:the\:answer}\)
\(855\cdot \:325\)\(=277875\)
\(8.55\mathrm{\:has\:}2\mathrm{\:decimal\:places}\\32.5\mathrm{\:has\:}1\mathrm{\:decimal\:place}\\\mathrm{Therefore,\:the\:answer\:has\:}3\mathrm{\:decimal\:places}\\=277.875\)
Where is the graph of f(x)=4[x-3]+2 discontinuos
Answer:
Below
Step-by-step explanation:
4 [x-3] + 2 = y is not discontinuous anywhere
However 4 / [x-3] + 2 DOES have a discontinuity at x = 3 because this would cause the denominator to be zero <===NOT allowed !!
The histograms display the frequency of temperatures in two different locations in a 30-day period.
A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 14. A shaded bar stops at 10 above 60 to 69, at 9 above 70 to 79, at 5 above 80 to 89, at 4 above 90 to 99, and at 2 above 100 to 109. There is no shaded bar above 110 to 119. The graph is titled Temps in Sunny Town.
A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 16. A shaded bar stops at 2 above 60 to 69, at 4 above 70 to 79, at 12 above 80 to 89, at 6 above 90 to 99, at 4 above 100 to 109, and at 2 above 110 to 119. The graph is titled Temps in Desert Landing.
When comparing the data, which measure of variability should be used for both sets of data to determine the location with the most consistent temperature?
IQR, because Sunny Town is skewed
IQR, because Desert Landing is symmetric
Range, because Sunny Town is skewed
Range, because Desert Landing is symmetric
A. IQR or B. IQR is the correct response since Sunny Town is symmetrical or Sunny Town is asymmetrical.
How do distributions work?The pattern of data distribution across various values or intervals is referred to as a distribution. The form, centre, and dispersion of a set of data can be described and examined in this manner.
We need to measure the fluctuation of the temperature data in both locations in order to decide which place has the most stable temperature. The interquartile range (IQR), which quantifies the spread of the middle 50% of the data, is the ideal measure of variability for this application.
As a result, depending on how the distributions are shaped, the answer is either A. IQR because Sunny Town is symmetric or B. IQR because Sunny Town is skewed. The IQR would be a suitable tool to gauge the data's spread if Sunny Town's temperature data were symmetric. The IQR would also be useful to measure the spread of the data if Sunny Town's temperature data were skewed. Therefore, the range would not be a suitable indicator of variability if the temperature data from either location were not skewed.
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Absolute value equations : solve for all values of y in the simplest form.
21=|7y|
All values of y in the simplest form are 3 and -3
How to solve for all values of y in the simplest form?The equation is given as
21 = |7y|
The above equation is an absolute value equation
When the above equation is expanded, we have the following equations
So, we have
-21 = 7y and 21 = 7y
Divide both sides of the equations by 7
So, we have
-3 = y and 3 = y
Rewrite as
So, we have
y = -3 and y = 3
Hence, all values of y in the simplest form are 3 and -3
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What is the value of x ?
Answer:
x = 9°
Step-by-step explanation:
The full arc of the angles equals 360°. So, we can subtract all of the measures of angles we are given from the total 360 to find the value of x.
We can add the given angles together and subtract the sum from 360 as well.
73 + 63 + 89 = 225
This means the measure outside 15x is a combines 225°.
Now, subtract the known measures from our total, 360.
360 - 225 = 135
The unknown, or 15x, is equal to 135°.
15x = 135
Solve this like a normal equation. Divide both sides by 15 to isolate x and solve for the variable.
\(\frac{15x}{15}\) = \(\frac{135}{15}\)
x = 9
x is equal to 9°.
We can check by adding all our values together again to see if they amount to 360°.
73 + 63 + 89 + 15(9) = 360
360 = 360
The equation is correct, so we can be sure that we are right.
The answer is x = 9°.
Good luck ^^
In a process system with multiple processes, the cost of units completed in Department One is transferred to O A. overhead. O B. WIP in Department Two. ( C. Cost of Goods Sold. OD. Finished Goods Inventory.
In a process system with multiple processes, the cost of units completed in Department One is transferred to WIP (Work in Progress) in Department Two.
Here's a step-by-step explanation:
1. Department One completes units.
2. The cost of completed units in Department One is calculated.
3. This cost is then transferred to Department Two as Work in Progress (WIP).
4. Department Two will then continue working on these units and accumulate more costs.
5. Once completed, the total cost of units will be transferred further, either to Finished Goods Inventory or Cost of Goods Sold.
Remember, in a process system, the costs are transferred from one department to another as the units move through the production process.
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Let Pij = the production of product i in period j. To specify that production of product 2 in period 4 and in period 5 differs by no more than 80 units, we need to add which pair of constraints?
P52-P42 <= 80; P42-P52 <= 80
None of the other above.
P24 - P25 <= 80; P25-P24 >= 80
O P24 - P25 >= 80; P25-P24 >= 80
P24 - P25 <= 80; P25-P24 <= 80
The correct pair of constraints that needs to be added to specify that production of product 2 in period 4 and in period 5 differs by no more than 80 units is: P24 - P25 <= 80; P25-P24 <= 80. Therefore, the correct option is 5.
Here, the given information is Pij = the production of product i in period j. We need to find the pair of constraints that will specify that production of product 2 in period 4 and in period 5 differs by no more than 80 units. Thus, let the production of product 2 in period 4 and in period 5 be represented as P24 and P25 respectively.
Therefore, we can write the following inequalities:
P24 - P25 <= 80
This is because the production of product 2 in period 5 can be at most 80 units less than that of period 4. This inequality represents the difference being less than or equal to 80 units.
P25-P24 <= 80
This is because the production of product 2 in period 5 can be at most 80 units more than that of period 4. This inequality represents the difference being less than or equal to 80 units.
Therefore, we need to add the pair of constraints P24 - P25 <= 80 and P25-P24 <= 80 to specify that production of product 2 in period 4 and in period 5 differs by no more than 80 units. Hence, option 5 is the correct answer.
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1. Kevin regularly travels from Manchester to Oxford.
He travels on two different trains.
His first train is from Manchester to Birmingham and his second train is from Birmingham to
Oxford.
On the 1st train, the probability that a seat has a table is 3/5
On the 2nd train, the probability that a seat has a table is
3/10
The 1st train has a total of 400 seats.
(a) Work out an estimate for the number of these 400 seats that have a table.
Answer:
240 seats with tables
Step-by-step explanation:
Let's start by making our fraction out of 10 on the first train to make it easier on us, this fraction would be \(\frac{6}{10}\). Then, to get the number of seats on this train that would have a table, we need to multiply 400 by our fraction, giving us:
\(400 * \frac{6}{10} = 2400/10 = 240\)
So, the 1st train should have approximately 240 seats with tables.
Hope this helped!
can someone solve -192= -6 (6x - 4) step by step?
Answer:
x= 4 2/3 OR 14/3 OR 4.6... –– 4 2/3 and 4.6... are the simplest form.
Step-by-step explanation:
Your original equation is -192 = -6 (6x - 4):
1. -192 = -6 (6x - 4)
Use distributive property and multiply: -6 x 6x = -36x and -6 x -4 = 24:
2. -192 = -36x + 24
We now move the +24 onto the other side of the equation, -192. Add 24 onto -192 and since we're moving the 24 on the left side of the equation, 24 will removed, so -24 on the right side of the equation:
3. -192 + 24 = -36x + 24 - 24
Divide both sides of the equations by -36 to get "x" by itself:
4. -168 / -36 = -36x / -36
Simplify the fraction of 24/36 by 12:
5. 4 24/36 = 4 2/3 or 14/3 or 4.6... = x
4 2/3, 14/3, 4.6... = x
Which graph represents a system of linear equations that has multiple common coordinate pairs?
sorry if the image is blurry
Answer:
Step-by-step explanation:
The fourth image because when looking for liner equations if you draw a line through them and it only touches once its linear equation!
sorry if im wrong...
for a random sample of 90 such pairs, where is the sampling distribution of x centered, and what is the standard deviation of the x distribution?
The standard deviation of the x distribution for a random sample of 90 pairs will be 0.168 .
As stated in the assertion
The sample n has been provided, and we need to determine the sample's standard deviation.
For this reason, we know that the standard deviation of the sample is equal to the population's standard deviation divided by the square root of the sample's length.
The value of alpha is given as,
alpha = 1.6.
Assume that for a specific type of aluminum alloy sheet, X is the sample mean Young's modulus for a random sample of 90 sheets, and
s = alpha/ 90 s
= 1.6/9.48 s
= 0.168
Therefore, 0.168 is the x distribution's standard deviation.
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Let X1, X2, ... , X30 be a random sample of size 30 from a Poisson distribution with a mean of 2/3. Approximate (a) P 15 < 30 i=1 Xi 22 . (b) P 21 30 i=1 Xi < 27 .
(a) To approximate P(15 < ΣXi < 22), we can use the Central Limit Theorem (CLT) since we have a large enough sample size (n = 30) and the mean and variance of the Poisson distribution are both finite.
First, we need to find the mean and variance of the sample mean, which is also the mean and variance of the Poisson distribution:
μ = λ = 2/3
σ^2 = λ = 2/3
Next, we can standardize the random variable Z = (ΣXi - nμ) / sqrt(nσ^2) to have a standard normal distribution:
Z = (ΣXi - 30(2/3)) / sqrt(30(2/3)) = (ΣXi - 20) / sqrt(20)
Then, we can use a standard normal table or calculator to find the probability:
P(15 < ΣXi < 22) ≈ P(-2.74 < Z < -1.77) ≈ 0.038
Therefore, the approximate probability is 0.038.
(b) To approximate P(21 < ΣXi < 27), we can use the same method with the CLT.
First, we need to find the mean and variance of the sample mean:
μ = λ = 2/3
σ^2 = λ = 2/3
Next, we can standardize the random variable Z = (ΣXi - nμ) / sqrt(nσ^2) to have a standard normal distribution:
Z = (ΣXi - 30(2/3)) / sqrt(30(2/3)) = (ΣXi - 20) / sqrt(20)
Then, we can use a standard normal table or calculator to find the probability:
P(21 < ΣXi < 27) ≈ P(-0.68 < Z < 0.68) ≈ 0.495
Therefore, the approximate probability is 0.495.