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The mass of a sample of NH₃ containing 3.80 × 10²⁴ molecules of NH₃ is the product of the number of moles and the molar mass of NH₃.

To find the mass of a sample of NH₃ containing 3.80 × 10²⁴ molecules of NH₃.

Step 1: Determine the number of moles of NH₃
We know that there are 6.022 × 10²³ molecules in one mole of any substance (Avogadro's number). To find the number of moles of NH₃, divide the given number of molecules by Avogadro's number:
Number of moles = (3.80 × 10²⁴ molecules) / (6.022 × 10²³ molecules/mol)

Step 2: Calculate the molar mass of NH₃
NH₃ consists of one nitrogen (N) atom and three hydrogen (H) atoms. The atomic mass of nitrogen is approximately 14 g/mol, and the atomic mass of hydrogen is approximately 1 g/mol. So the molar mass of NH₃ is:
Molar mass of NH₃= (1 × 14 g/mol) + (3 × 1 g/mol) = 14 + 3 = 17 g/mol

Step 3: Find the mass of the sample
Now that we know the number of moles and the molar mass, we can find the mass of the sample by multiplying the two values:
Mass of the sample = Number of moles × Molar mass of NH₃

The mass of a sample of NH₃ containing 3.80 × 10²⁴ molecules of NH₃ is the product of the number of moles (calculated in step 1) and the molar mass of NH₃ (calculated in step 2).

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A functional group, a subunit of an organic compound that confers particular chemical and physical properties is termed. Correct answer: letter C.

Since, functional groups are responsible for the formation of chemical bonds between molecules and atoms, and play an important role in the physical and chemical properties of the organic compounds of which they are a part.

The term ‘functional group’ was first coined in 1883 by German chemist Hermann Kolbe, and it is used to refer to a specific group of atoms within an organic compound that has a distinct chemical structure and identity.

Functional groups are often referred to as “active sites”, as they are the main sites of chemical activity within an organic compound.

Functional groups contain atoms that are held together by covalent bonds, which are strong chemical bonds that form when electrons are shared between atoms.

A subunit of an organic compound that confers particular chemical and physical properties is termed ________

A) A monomer.

B) An oligomer.

C) A functional group.

D) A synthetic unit.

E) An isomer.

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Answer:

0.54 J/goC

Explanation:

Recall that we define the heat transferred as ;

H= mcθ

Where;

H= heat transferred = 112300J

m= mass of the metal= 240g or 0.24 Kg

c= specific heat capacity of the metal = the unknown

θ= change in temperature = (880°C-13°C) = 867°C

Substituting values and making the specific heat capacity the subject of the formula;

c= H/mθ

c= 112300/ 240×867

c= 0.54 J/goC

Hence, the specific heat capacity of the metal is 0.54 J/goC.

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\ \)

m is the mass

v is the velocity

From the question we have

\(k = \frac{1}{2} \times 25 \times {2.5}^{2} \\ = 12.5 \times 6.25 \\ = 78.125 \: \: \: \: \: \: \: \: \)

We have the final answer as

Hope this helps you

Answer:

First ionization energy decrease

A resonance form for pyrrole in which nitrogen has a formal charge of +1 can be drawn as follows: Here the nitrogen atom is shown with a lone pair and three single bonds to the carbon atoms, with the fifth bond being a double bond between the nitrogen and the fourth carbon atom.

This form implies that the nitrogen has a formal charge of +1, while the other atoms have a formal charge of zero. Comparable resonance forms are possible for pyridine, although the structure of pyridine is slightly different from that of pyrrole.

Pyridine has one nitrogen atom and five carbon atoms, so the resonance form for pyridine would involve the nitrogen atom having a lone pair and four single bonds to the carbon atoms, with the fifth bond being a double bond between the nitrogen and the fifth carbon atom.

This resonance form would also imply that the nitrogen has a formal charge of +1, while the other atoms have a formal charge of zero.

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Answer:

See explanation

Explanation:

While it is true that there are only about 90 naturally occurring elements, these elements are capable of combining with each other to form millions of substances.

Most of the substances that we see around us today result from a combination of one or more of these naturally occurring elements.

Let us look at three examples;

The carbohydrate in food is composed of carbon, hydrogen and oxygen

The stainless steel materials we use are composed of iron, carbon and other trace elements

Glass is made up of silicon, oxygen and other elements

Only 90 naturally occurring elements capable of combining with each other to form millions of substances.

Compounds:

When two or more elements combine in a certain ratio to form a molecule.

For example-

Water is made up of two hydrogen and one Oxygen ration is 2:1.

If hydrogen and Oxygen combine inn 2:2, they for Hydrogen peroxide.

Water gives life and Hydrogen peroxide can kill a person.

Other examples are,

Therefore, only 90 naturally occurring elements capable of combining with each other to form millions of substances.

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Properties of elements within a period on the periodic table change in a predictable way from one side of the table to the other

From one side of the periodic table to the other, properties of elements within a period vary in a predictable manner. A horizontal row represents a period in the periodic table. The number of electron shells is the same for every atom in a row. Moving through a period causes elements to acquire electrons and protons and become less metallic. -Elements in the same period have the same number of electron shells.

As the atomic number rises, comparable features reoccur on a regular basis, which is reflected in this arrangement. From one side of the periodic table to the other, properties of elements within a blank shift in a predictable manner. those with comparable qualities are displayed in a column.

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Answer:

The molar mass of one molecule of ammonium sulfate (NH4)2 SO4 132.14 grams per mole

Answer: 132.15 g

Explanation:

If this question is from a mastery test on Edmentum, I just took it and this was the correct answer

The answer is 67 108.0888km/s.

Answer: If you double the force you would have to double the Acceleration.

Explanation:Since the mass does not change as the acceleration increases, we can say that force is equal to acceleration. Therefore, if you double the force you double the acceleration.

First, let's remember the formula to calculate an object's density:

Then, we analyze what we have:

We need to determine the volume, so we transform our formula like this:

We replace our data:

Then, the answer is that the volume equals 12.4 cm^3.

Answer:

asdd

Explanation:

adsade4223

Answer:

1.41g

Explanation:

all work is shown in the attached image :-)

NaCl + 3F2 → 2NaF + Cl2

The given chemical equation is a representation of a redox reaction between sodium chloride (NaCl) and fluorine gas (F2). In this reaction, the fluorine gas is being reduced (gains electrons) while the sodium chloride is being oxidized (loses electrons).

The balanced chemical equation shows that one molecule of NaCl reacts with three molecules of F2 to produce two molecules of NaF and one molecule of Cl2. This reaction is highly exothermic and releases a significant amount of energy.

Overall, this reaction demonstrates the chemical properties of the elements involved and serves as a useful example of a redox reaction, where one element is oxidized while another is reduced.

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The volume of dry hydrogen gas collected at STP is 33.6 liters.

When aluminum reacts with acid, it undergoes a single replacement reaction to form aluminum salt and hydrogen gas. The balanced chemical equation for the reaction is:

\(2Al + 6HCl \rightarrow 2AlCl_3 + 3H_2\)

From the equation, we can see that 2 moles of aluminum react with 6 moles of hydrochloric acid to produce 3 moles of hydrogen gas. The molar mass of aluminum is 26.98 g/mol and the molar mass of hydrogen is 1.008 g/mol.

First, we need to calculate the number of moles of aluminum in the sample:

0.885 g / 26.98 g/mol = 0.0328 mol Al

Next, we can use the mole ratio from the balanced chemical equation to find the number of moles of hydrogen gas produced:

\($\frac{3\ \text{mol H}_2}{2\ \text{mol Al}} = 1.5\ \text{mol H}_2$\)

Finally, we can use the ideal gas law to find the volume of dry hydrogen gas produced at standard temperature and pressure (STP):

PV = nRT

where P = 1 atm, V is the volume of gas, n = 1.5 mol, R = 0.08206 L atm/mol K (gas constant), and T = 273.15 K (standard temperature)

\($V = \frac{nRT}{P} = \frac{(1.5\ \text{mol})(0.08206\ \text{L}\cdot\text{atm/mol}\cdot\text{K})(273.15\ \text{K})}{1\ \text{atm}} = 33.6\ \text{L}$\)

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Polymerization of ethylene gives C. Polyethylene.

Ethylene is a simple hydrocarbon with the formula C2H4. During polymerization, many ethylene molecules join together to form a larger molecule called polyethylene. This process is known as addition or chain-growth polymerization. In this reaction, the double bond between the carbon atoms in ethylene molecules is broken, and new single bonds are formed to connect the ethylene units, creating a long chain of repeating ethylene units in the polyethylene molecule. Polyethylene is a versatile and widely used plastic, commonly found in products such as plastic bags, bottles, and food packaging. Therefore the correct option is  C. Polyethylene

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Approximately 372.93 g of lead sulfate is formed when 1.21 g of Pb undergoes oxidation in a lead-acid storage battery.

We need to consider the balanced chemical equation for the reaction.

The balanced equation for the formation of lead sulfate from lead (Pb) in a lead-acid battery is:

\(Pb + H2SO_4 - > PbSO_4 + 2H+\)

From the equation, we can see that one mole of Pb reacts to form one mole of \(PbSO_4\).

The molar mass of Pb is 207.2 g/mol, and the molar mass of \(PbSO_4\) is 303.3 g/mol.

Using the molar ratio, we can calculate the mass of lead sulfate formed:

\((1.21 g Pb) * (1 mol PbSO_4 / 1 mol Pb) * (303.3 g PbSO_4 / 1 mol PbSO_4) = 372.93 g\)

Therefore, approximately 372.93 g of lead sulfate is formed when 1.21 g of Pb undergoes oxidation in a lead-acid storage battery.

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Answer:

–99 °C

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 1.5 atm

Initial temperature (T₁) = 25 °C

Final pressure (P₂) = 1 atm

Change in temperature (ΔT) =?

Next, we shall determine the final temperature. This can be obtained as follow:

Initial pressure (P₁) = 1.5 atm

Initial temperature (T₁) = 25 °C + 273 = 298 K

Final pressure (P₂) = 1 atm

Final temperature (T₂) =?

P₁/T₁ = P₂/T₂

1.5 / 298 = 1 / T₂

Cross multiply

1.5 × T₂ = 298

Divide both side by 1.5

T₂ = 298 / 1.5

T₂ = 199 K

Converting 199 K to °C, we have:

T(°C) = T(K) – 273

T₂ = 199 – 173

T₂ = –74 °C

Finally, we shall determine change in temperature. This can be obtained:

Initial temperature (T₁) = 25 °C

Final temperature (T₂) = –74 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = –74 – 25

ΔT = –99 °C

Thus, the change in the temperature is –99 °C

Answer:

what?

Explanation:

whats the answer

Answer:

oh yea! keep up the great work buddy!!

SDS’s are not denote for consumers. An SDS affects the hazards of working with the material in an occupational fashion.

For example, an SDS for paint is not highly relevant to someone who uses a can of paint once a year but is extremely important to someone who uses that paint 40 hours a week or per day 5-6 hours.

A safety data sheet (SDS), first known as a material safety data sheet) is an important information source for eliminating or minimizing the risks linked with the use of hazardous chemicals (hazardous substances and/or dangerous goods) in workplaces.

While the GHS uses a total of 9 pictograms, OSHA will only impose the use of eight.

The environmental pictogram is not compulsory but may be used to provide additional information.

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Answer:

i dont no this one plz the question is hard

Answer:

The order of relative acidity is Milk (pH 7.8) < Lemon juice (pH 2.2) < Bleach (pH 11.3).

To determine the relative acidity of the substances, we need to arrange them in order of increasing acidity (least acidic to most acidic) based on their pH values.

Values below 7 are considered acidic, while values above 7 are considered basic or alkaline. So, the relative acidity of the substances from least acidic to most acidic would be:

Milk (pH 7.8) - This is close to neutral pH, which means it is the least acidic among the given substances.

Lemon juice (pH 2.2) - This has a lower pH value than milk, making it more acidic.

Bleach (pH 11.3) - This has a higher pH value than milk, making it basic or alkaline. It is the most basic among the given substances.

Therefore, the order of relative acidity is Milk (pH 7.8) < Lemon juice (pH 2.2) < Bleach (pH 11.3).

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The concentration of iron(iii) chloride contaminant in the original groundwater sample is (C1 × V1 / V) × 162.2 g/mol.

Given that the chemist adds m silver nitrate solution to the sample until silver chloride stops forming. He then washes, dries, and weighs the precipitate. He finds he has collected of silver chloride. Let us calculate the concentration of iron(iii) chloride contaminant in the original groundwater sample.Calculating the concentration of iron(iii) chloride contaminant in the original groundwater sample

Here is the given information;

Mass of silver chloride precipitate = m grams

Volume of groundwater sample taken = V ml

Volume of AgNO3 solution used = V1 ml

Concentration of AgNO3 solution = C1

Molar Mass of AgCl precipitated = 143.5 g/mol

The molarity of AgNO3 solution is given as;

Molarity of AgNO3 = Number of equivalents / Volume of solution in liters

We know that 1 mole of AgNO3 gives 1 mole of AgCl, i.e., AgNO3 is equivalent to AgCl.Therefore, the number of equivalents of AgNO3 is the same as the number of equivalents of AgCl.

Number of equivalents of AgNO3 = C1 × V1

Number of equivalents of AgCl = m / 143.5 g/mol

Concentration of FeCl3 = (Number of equivalents of FeCl3 / Volume of sample in liters) × Molar mass of FeCl3

Number of equivalents of FeCl3 = Number of equivalents of AgNO3

Number of equivalents of FeCl3 = C1 × V1

Concentration of FeCl3 = (C1 × V1 / V) × Molar mass of FeCl3

Concentration of FeCl3 = (C1 × V1 / V) × 162.2 g/mol

Hence, the concentration of iron(iii) chloride contaminant in the original groundwater sample is (C1 × V1 / V) × 162.2 g/mol.

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Answer:

0.967mole

Explanation:

Given parameters:

Volume of NH₄Cl  = 21.67L

Unknown:

Number of moles  = ?

Solution:

We assume that the volume was taken at standard temperature and pressure,

 Then;

  Number of moles  = \(\frac{volume }{22.4L}\)  

 Number of moles  = \(\frac{21.67}{22.4}\)   = 0.967mole

The addition of magnesium chloride to the solution results in unaffected chemical equilibrium of the system. Thus, option A is correct.

The given chemical equation has been:

\(\rm CH_3COOH\;\leftrightharpoons\;CH_3COO^-\;+\;H^+\)

The reaction is reversible and can be converted back to the reactant with the increase in the product concentration. The equilibrium has been the condition when the concentration of products and reactants in the reaction are equal.

With an increase in products or reactants, there has been a corresponding chemical shift in the equilibrium.

The addition of Magnesium chloride in the solution, results in the dissociation of compound as:

\(\rm MgCl_2\;\rightleftharpoons \;Mg^+\;+\;2\;Cl^-\)

The compound results in neither the increase of reactants, nor increase of product concentration in the acetic acid equilibrium.

Thus, the equilibrium of the system will remain unaffected by the addition of magnesium chloride. Thus, option A is correct.

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Answer:
A: The chemical equilibrium of the system will be unaffected.

Explanation:

Hope this helps!

Edge 2022

Considering the definition of pure substance and homogeneous mixture, the main difference is that a pure substance consists of only one type of particle and it cannot be separated or divided into more substances whereas a homogeneous mixture is made up of two or more different substances and can be separated into various pure substances.

A pure substance is one that is made up of a single type of particle, whether atoms or molecules, and therefore has the same properties in all its parts. The composition and properties of an element or compound are uniform anywhere in a given sample, or in different samples of the same element or compound.

When a substance is made up of two or more simple substances, it is known as a mixture. Homogeneous mixtures are characterized by being formed by two or more components that cannot be distinguished visually. The composition and properties are uniform throughout any given sample, but may vary from sample to sample. In general, the components of a homogeneous mixture can be in any proportion, and can be recovered using physical separation methods.

The main difference between a pure substance and a mixture is that a pure substance consists of only one type of particle and it cannot be separated or divided into more substances whereas a homogeneous mixture is made up of two or more different substances and can be separated into various pure substances.

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To make 60 mL of a 1.5 mg/mL solution of memantine hydrochloride, we need to mix 2 mL of the available solution (10 mg/5 mL) with 270 mL of a diluent (sorbitol solution).

The concentration of memantine hydrochloride in the available solution is (10 mg/5 mL). This solution is too strong for the requested concentration of 1.5 mg/mL. Therefore, it must be diluted to obtain the desired concentration. We are asked to determine the amount of diluent and the amount of available solution to be mixed to produce 60 mL of the desired solution containing 1.5 mg/mL. This can be done by using the following equation:

Concentration1 × Volume1 = Concentration2 × Volume2

The total amount of drug (memantine hydrochloride) needed to make 60 mL of a 1.5 mg/mL solution is

1.5 × 60 = 90 mg.

To determine the amount of the available solution to use, we can use the concentration of memantine hydrochloride in the available solution:

10 mg/5 mL = 2 mg/mL

If we add 2 mL of this solution to the diluent, the new concentration of memantine hydrochloride will be

(2 mg/mL)/6 = 0.33 mg/mL.

This new concentration is still too strong, so we will need to add more diluent. We can calculate how much diluent to add by using the following equation:

(2 mL)/(6 mL) = (90 mg)/(V2)

Solving for V2, we find that we need

V2 = 270 mL of diluent to obtain a 1.5 mg/mL solution.

To make 60 mL of a 1.5 mg/mL solution of memantine hydrochloride, we need to mix 2 mL of the available solution (10 mg/5 mL) with 270 mL of a diluent (sorbitol solution).

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