Answer: f(−1)=−10
Step-by-step explanation:
f(−1)=3x−7
Substitute −1 for x
f(−1)=3(−1)−7=
f(−1)=−3−7=
f(−1)=-10
An elephant weighed 14,000 pounds. The handlers realized the
elephant was overweight and put it on a special meal plan. The
elephant lost 2,100 pounds. What was the percent of decrease in its
body weight?
14000
The value of the decrease percentage of elephant weight is 15%.
What is percentage?A percentage is a value that indicates 100th part of any quantity. A percentage can be converted into a fraction or a decimal by dividing it by 100.
The original weight of elephant is 14000 pounds.
And, the drop in weight is 2100 pounds.
Now, the percent value of the drop in weight is calculated as follows
Percent drop = Drop in weight / Original weight × 100
⇒ 2100/14000 × 100
⇒ 15%
Hence, the percent of decrease in weight is given as 15%.
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A real-estate agent conducted an experiment to test the effect of selling a staged home vs. selling an empty home. To do so, the agent obtained a list of 10 comparable homes just listed for sale that were currently empty. He randomly assigned 5 of the homes to be "staged,” meaning filled with nice furniture and decorated. The owners of the 5 homes all agreed to have their homes staged by professional decorators. The other 5 homes remained empty. The hypothesis is that empty homes are not as appealing to buyers as staged homes and, therefore, sell for lower prices than staged homes. The mean selling price of the 5 empty homes was $150,000 with a standard deviation of $22,000. The mean selling price of the five staged homes was $175,000 with a standard deviation of 35,000. A dotplot of each sample shows no strong skewness and no outliers.
The agent tests H0: μ1 – μ2 = 0, Ha: μ1 – μ2 < 0, where μ1 = the true mean selling price of all comparable empty homes and μ2 = the true mean selling price of all comparable staged homes. Are the conditions for inference met for carrying out a t-test for a difference in means?
No, the random condition is not met.
No, the 10% condition is not met.
No, the Normal/large sample condition is not met.
Yes, all of the conditions for inference have been met.
Yes, all of the conditions for inference have been met to carry out a t-test for a difference in means.
Three main conditions need to be satisfied: the random condition, the 10% condition, and the Normal/large sample condition.
The random condition is met because the real-estate agent randomly assigned the homes to be staged or empty. This ensures that the sample is representative of the population of comparable homes.
The 10% condition is met because the agent selected 10 comparable homes, and the sample of 5 staged and 5 empty homes represents less than 10% of the population of comparable homes.
The Normal/large sample condition is met because the dot plot of each sample shows no strong skewness and no outliers. Additionally, with a sample size of 5 for each group, the t-test can still be valid even if the population distributions are not exactly normal.
Therefore, all the conditions for inference have been met, allowing the real-estate agent to carry out a t-test for a difference in means and test the hypothesis regarding the selling prices of staged and empty homes.
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A local rec center offers a yearly membership for $265. The center offers aerobics classes for an additional $5 per class. Write an equation that represents the total cost of the membership.
The equation that represents the total cost of the membership will be y = 5x + 265.
What is a linear equation?A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.
The linear equation is given as,
y = mx + c
Where m is the slope of the line and c is the y-intercept of the line.
A local rec center offers a yearly membership for $265. The center offers aerobics classes for an additional $5 per class.
Let 'x' be the number of aerobics classes and 'y' be the total cost. Then the equation is given as,
y = 5x + 265
The equation that represents the total cost of the membership will be y = 5x + 265.
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Can Someone please help me !!! ( you have to fill out the blanks )
Answer:
1. 5(a-6) = 5a-30
2. 2(3a-b) = 6a-2b
3. 5(-5x+3) = -25x+15
4. -(2c+3) = -2c-3
Both of their first step are correct (Show your calculations to explain)
x-9 = 5
x = 14
2x-18 = 10
2x = 28
x = 14
Step-by-step explanation:
All Above
help asap its timed will mark brainliest no need to draw just do the other steps
The difference between the area of the rectangle and the area of the triangles is 56 units.
What are the area of the rectangle and the area of the triangles?Area of the rectangle = 8 * 16
Area of the rectangle = 128 units
Area of triangle 1 = ¹/₂ * 4 * 12
Area of triangle 1 = 24 units
Area of triangle 2 = ¹/₂ * 4 * 16
Area of triangle 2 = 32 units
Area of triangle 2 = ¹/₂ * 4 * 8
Area of triangle 2 = 16 units
Area of rectangle - area of triangle = 128 - ( 24 + 32 + 16)
Area of the rectangle - the area of the triangles = 56 units
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I need help please I can only find 2 of these solutions
Step 1: Isolate the Sin Operator
\(8 sin(\frac{\pi }{6} x)=2\\sin(\frac{\pi }{6} x)=0.25\\\\\)
Step 2: Use Inverse Sin(arcsin) to isolate the term with the x variable
Note that since trig functions have 2 general solutions, this will give us one of our general solutions.
\(x=\frac{6 arcsin(0.25)}{\pi } =0.48\)
x₁= 0.48
Solving for x₂
Use the period identity for Sin Functions
\(sin(x)=sin(\pi -x)\)
X in this case is arcsin(0.25)
\(\frac{\pi }{6} x=\pi -arcsin(0.25) = 5.52\)
So our two general solutions are 0.48 and 5.52
Step 3: Period
Trig Functions have periodic behavior and this function period is
\(\frac{2\pi }{1} (\frac{6}{\pi } )= 12\)
So our general solutions are
0.48±12k, where k is an integer
5.52±12k, where k is an integer
Let k=1, and we get our next set of solutions:
12.48 and 17.52
So our answer is 0.48,5.52,12.48,17.52
You have to conduct a survey in your school to find out which mode of transportation students prefer the most. Arrange the steps for comple
this project in order from start to finish.
Answer:
Here are the steps for conducting a survey in your school to find out which mode of transportation students prefer the most, arranged in order from start to finish:
1) Define the objective: Clearly define the objective of the survey, which is to determine the preferred mode of transportation among students in your school.
2) Determine the sample size: Decide on the number of students you want to include in your survey. This will depend on factors such as the size of your school and the resources available for conducting the survey.
3) Design the survey questionnaire: Create a well-designed survey questionnaire that includes relevant questions about different modes of transportation. Ensure that the questions are clear, unbiased, and cover all the necessary aspects.
4) Seek necessary permissions: If required, seek permission from school authorities or relevant individuals to conduct the survey on school premises and to involve students.
5) Pre-test the survey: Before distributing the survey to the entire student population, pre-test the questionnaire on a small group of students to identify any potential issues or areas for improvement.
6) Distribute the survey: Once the questionnaire has been finalized and pre-tested, distribute it to the selected sample of students. Ensure that the survey is distributed in a fair and unbiased manner, taking into account the diversity of the student population.
7) Collect the survey responses: Set a specific timeframe for students to complete the survey and collect the responses. Consider using a combination of online platforms and physical collection methods to maximize participation.
8) Analyze the data: Once you have collected all the survey responses, analyze the data to determine the preferred mode of transportation among students. Use appropriate statistical tools and techniques to interpret the results accurately.
9) Present the findings: Prepare a report or presentation summarizing the survey findings. Include key insights, trends, and any significant findings related to the preferred mode of transportation among students.
10) Share the results: Share the survey results with the school community, including students, teachers, and administrators. This can be done through presentations, newsletters, or other suitable communication channels.
By following these steps, you will be able to conduct a comprehensive survey to determine the preferred mode of transportation among students in your school.
Hope this helps!
I can not do it for you but I can give you what you should do
Explanation: take a survey
According to a marketing research study, American teenagers watched 16.5 hours of social media posts per month last year, on average. A random sample of 20 American teenagers was surveyed and the mean amount of time per month each teenager watched social media posts was 17.3. This data has a sample standard deviation of 2.1. (Assume that the scores are normally distributed). Researchers conduct a one-mean hypothesis at the 10% significance level to test if the mean amount of time American teenagers watch social media posts per month is greater than the mean amount of time last year. Which answer choice shows the correct null and alternative hypotheses for this test?
H0: μ = 17.3; Ha: μ< 17.3, which is a left-tailed test.
H0: μ = 17.3; Ha: μ > 17.3, which is a right-tailed test.
H0: μ = 16.5; Ha: μ < 16.5, which is a left-tailed test.
H0: μ = 16.5; Ha: μ > 16.5, which is a right-tailed test.
Answer:
H0: μ = 16.5; Ha: μ > 16.5, which is a right-tailed test.
Step-by-step explanation:
Given that:
the population mean μ = 16.5
the sample size n = 20
the sample mean \(\mathbf{\overline x}\) = 17.3
the standard deviation σ = 2.1
level of significance = 0.10
The objective is to choose from the given options, the correct option that state the null hypothesis and the alternative hypothesis.
Given that; we want to determine if the mean amount of time they watch social media posts per month is greater than the mean amount of time last year, then we can say that the test is right-tailed.
Hence, the null hypothesis and alternative hypothesis can be computed as:
The null hypothesis:
\(\mathbf{H_o: \mu = 16.5}\)
The alternative hypothesis:
\(\mathbf{H_1 : \mu > 16.5}\)
Therefore, the fourth option is the right answer.
Elise built a large rectangular vegetable garden that is 9 meters long and has an area of 72 square meters.
What is the perimeter of Elise’s vegetable garden?
Answer ASAP!!
im timed!!!
give me an answer ASAP
Answer: 34 meters.
Step-by-step explanation;
Step One. Find the value of the width. Use an equation with w representing the width and the two values you already have. 9 meters x w = 72 square meters.
Step Two. Solve for width. This is w = 8.
Step Three. Use the value for width in a perimeter formula to calculate the perimeter; 9(2) + 8(2). This is 34 meters for perimeter.
Answer:
Hi
Step-by-step explanation:
Aright triangle with an area of X2-4 square units has a leg that measures
2x + 4 units.
Determine the length of the other leg of the triangle.
Answer:
x - 2
Step-by-step explanation:
First, we know that the area of a triangle can be found using the formula: a = 1/2(bh).
We also know that the area of this triangle can be represented by (x^2-4).
Lastly, we know that one of the legs (let's call it the base) can be represented by (2x+4).
Let's plug in those values to the original formula: x^2 - 4 = 1/2(2x + 4)h
Now, let's solve for h!
We can multiply both sides by 2, then divide each side by (2x + 4) to isolate/solve for h.
If you need help on dividing polynomials, feel free to reach out!! I'd be happy to explain.
h = (x - 2)
Review the Monthly Principal & Interest Factor chart to answer the question:
FICO Score APR 30-Year Term 20-Year Term 15-Year Term
770–789 5.5 $5.68 $6.88 $8.17
750–769 6.0 $6.00 $7.16 $8.44
730–749 6.5 $6.32 $7.46 $8.71
710–729 7.0 $6.65 $7.75 $8.99
690–709 7.5 $6.99 $8.06 $9.27
Determine the percent decrease in total principal and interest paid between a 30-year term mortgage and a 15-year mortgage with a principal balance of $484,500.00 and a 6.5% APR. Round the final answer to the nearest tenth.
31.0%
31.1%
59.0%
68.5%
The percent decrease in total principal and interest paid between a 30-year term mortgage and a 15-year mortgage with a principal balance of $484,500.00 and a 6.5% APR is 31.0%. (Option A)
How is this so ?
To calculate the percent decrease, we can use the following formula.
Percent decrease = ( (30-year factor - 15-year factor) / 30-year factor) x 100
Substituting the values from the chart.
= (($ 6.65 - $8.71) / $6.65) x 100
= ( -$ 2.06 / $6.65) * 100
= -0.309 * 100
Percent decrease ≈ - 30.9 %
Since the question asks for the percent decrease as a positive value, we take the absolute value of the result which is
Percent decrease ≈ 31%
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an 800 deposit for 2 years months earned 200$ in interest
Which equation is modeled below?
O 2x+(-2)=-2x+
O 4x+(-2)=-2x+6
O 2x+4 = 6x + 2
O-2x+4=6x+(-2)
Answer:
4x + (-2) = -2x+6
Step-by-step explanation:
im not gonna explain a diagram but it won't let me submit.
Two mountain peaks are known to be 17 kilometers apart. A person located at a vista point such that a right angle is spanned when he looks from one peak to the other
is told that the distances from the vista point to each peak differ by 7 kilometers. How far is the vista point from each mountain peak?
The person is looking at each peak on a leg of a right triangle. The hypotenuse is the distance between the mountains.
How far is the vista point from each mountain peak?The distance is determined by
x^2+(x+5)^2=25^2
x^2+x^2+10x+25=625
2x^2+10x-600=0
x^2+5x-300=0
(x+20)(x-15)=0
only positive root is x=15
x+5=20
The vista point is 15 miles from one mountain peak and 20 miles from the other.
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Based on the Nielsen ratings, the local CBS affiliate claims its 11 p.m. newscast reaches 41% of the viewing audience in the area. In a survey of 100 viewers, 36% indicated that they watch the late evening news on this local CBS station. What is your decision if α = 0.01?
Select one:
a.
Reject the null hypothesis and conclude the newscast does not reach 41% of the audience.
b.
Fail to reject the alternate and conclude the newscast does not reach 41% of the audience.
c.
Reject the alternate and conclude the newscast reaches about 41% of the audience.
d.
Fail to reject the null hypothesis.
Based on the information given, the null hypothesis states that the newscast reaches 41% of the viewing audience, while the alternate hypothesis states that it does not reach 41% of the audience. So, the correct answer is d. Fail to reject the null hypothesis.
To determine the decision, we need to perform a hypothesis test using the given significance level α = 0.01. This significance level represents the maximum acceptable probability of making a Type I error, which is rejecting the null hypothesis when it is actually true.
In the survey of 100 viewers, 36% indicated that they watch the late evening news on the local CBS station. To test the hypothesis, we can use a one-sample proportion test. We compare this sample proportion to the claimed 41% to see if there is a significant difference.
Using a statistical calculator or software, we calculate the p-value associated with the observed sample proportion. If this p-value is less than α (0.01), we reject the null hypothesis. If the p-value is greater than or equal to α, we fail to reject the null hypothesis.
Based on the decision criteria, if the p-value is less than 0.01, we would reject the null hypothesis and conclude that the newscast does not reach 41% of the audience. However, if the p-value is greater than or equal to 0.01, we would fail to reject the null hypothesis. To summarize, the correct decision, given α = 0.01, would be d. Fail to reject the null hypothesis.
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H
L
MA
56/34%'N
49°
F
124°
41°
G
E
K
Name a pair of nonadjacent supplementary angles.
O ZEGF
ZFGH
OZLJM
OZNJP
OZLJK
ZLJN
======================================================
Explanation:
We have two rules we need to follow:
The angles must add to 180 degrees (since they are supplementary)The angles cannot be touching or sharing a common wall (because they can't be adjacent).Through trial and error, you should find that this works for angle FGH and angle LJM
Note how 124+56 = 180 to show that the angles are supplementary. If they were combined together, then we could form a straight line. However, they aren't touching or combined since they are part of two separate figures. So that's why we consider them nonadjacent angles.
Convert to centimeters: 43 meters
HELP!!!!!! . GIVEN THE INFORMATION BELOW, Fino AC
B B BETWEEN A AND C
• AC=2x +8
• AB=48-16
BC=32-6
Answer:the answer is B
Step-by-step explanation:
Question 4Multiple Choice Worth 2 points)
(04.05 MC)
A chess player ran a simulation twice to estimate the proportion of wins to expect using a new game strategy. Each time, the simulation ran a trial of 1,000 games. The first
simulation returned 212 wins, and the second simulation returned 235 wins. Construct and interpret 95% confidence intervals for the outcomes of each simulation.
The confidence interval from the first simulation is (0.187, 0.237), and the confidence interval from the second simulation is (0.209, 0.261). For the first trial, we are
95% confident the true proportion of wins with the new game strategy is between 0.187 and 0.237. For the second trial, we are 95% confident the true proportion of
wins with the new game strategy is between 0.209 and 0.261.
The confidence interval from the first simulation is (0.187, 0.237), and the confidence interval from the second simulation is (0.209, 0.261). For the first trial, we are
90% confident the true proportion of wins with the new game strategy is between 0.187 and 0.237. For the second trial, we are 90% confident the true proportion of
wins with the new game strategy is between 0.209 and 0.261.
The confidence interval from the first simulation is (0.191, 0.233), and the confidence interval from the second simulation is (0.213, 0.257). For the first trial, we are
95% confident the true proportion of wins with the new game strategy is between 0.191 and 0.233. For the second trial, we are 95% confident the true proportion of
wins with the new game strategy is between 0.213 and 0.257.
The confidence interval from the first simulation is (0.191, 0.233), and the confidence interval from the second simulation is (0.213, 0.257). For the first trial, we are
90% confident the true proportion of wins with the new game strategy is between 0.191 and 0.233. For the second trial, we are 90% confident the true proportion of
wins with the new game strategy is between 0.213 and 0.257.
2
By constructing 95% confidence intervals for each simulation, we can be 95% confident that the true proportion of wins lies within the range of each interval.
What is Confidence Intervals?A confidence interval is a set of values that, given a specific level of certainty, are likely to include a population parameter like a mean or proportion.
The interval is derived using data drawn from a sample of the population and is frequently presented as a range of values with a 95% confidence level.
The probability that the range of values contains the genuine population parameter is quantified by the confidence level.
In the case of a 95% confidence interval, for instance, it means that 95% of the intervals would contain the real population parameter if we sampled the same population more than once and calculated a confidence interval each time.
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HELP PLEASE ASAP 55 POINTS I BEG YOU!!!!!!
A store had a three-day sale. On the first day the store sold 1 bicycle, 3 tricycles, and 1 unicycle for a total of $561. On the second day, 7 bicycles and 1 tricycle were sold for a total of $906. And at the third day, 2 bicycles, 7 tricycles, and 5 unicycles were sold for a total of $1758.
Set up a system and use row reduction to find the price of each item
Answer:
Bicycle : $117
Tricycle : $87
Unicycle : $183
Step-by-step explanation:
Write a system of equations:
x + 3y + z = 561
7x + y = 906
2x + 7y + 5z = 1758
Where:
x = price of bicycle
y = price of tricycle
z = price of unicycle
Solve for x, y, and z.
Please help, I got till the end of the period.
Answer:
85+75+160=v
Step-by-step explanation:
correct answer
what is the value of x?
please help!!
Answer: 20
Step-by-step explanation:
Suppose that 37% of college students own cats. If you were to ask random college students if they own a cat what would the probability that:
a) a single student doesn’t own a cat?
b) 3 students own cats?
c) 2 students own cats while 2 students don't own cats?
Using the binomial distribution, the probabilities are given as follows:
a) 0.37 = 37%.
b) 0.5065 = 50.65%.
c) 0.3260 = 32.60%.
What is the binomial distribution formula?The formula is:
\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)
\(C_{n,x} = \frac{n!}{x!(n-x)!}\)
The parameters are:
x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.For this problem, the fixed parameter is:
p = 0.37.
Item a:
The probability is P(X = 1) when n = 1, hence:
\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)
\(P(X = 1) = C_{1,1}.(0.37)^{1}.(0.63)^{0} = 0.37\)
Item b:
The probability is P(X = 3) when n = 3, hence:
\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)
\(P(X = 3) = C_{3,3}.(0.37)^{3}.(0.63)^{0} = 0.5065\)
Item c:
The probability is P(X = 2) when n = 4, hence:
\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)
\(P(X = 2) = C_{4,2}.(0.37)^{2}.(0.63)^{2} = 0.3260\)
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84 ÷ (17 × 3 - 23) × 4
Answer: 12
Step-by-step explanation:
An SEO account manager is concerned website developers are using too many keywords per web page. The SEO account manager would like to carry out a hypothesis test and test the claim that a web page has, on average, more than 10 keywords. Why is this hypothesis test right-tailed
Answer:
The hypothesis test is right tailed because of claim made by SEO account manager that a web page on average has more than 10 keywords.
Step-by-step explanation:
The given hypothesis test is right tailed due to the claim made by SEO account manager. The tail of hypothesis test decided by looking at alternative hypothesis. The claim stated as " a web on average has more than 10 keywords" and this leads to alternative hypothesis as
Ha:μ>10.
The alternative hypothesis shows the greater than area or also known as right tailed area. Thus, given hypothesis test is right tailed.
Please awnser asap I will brainlist
The roster method of the set X ∪ (Y ∩ Z) = {p, q, r, s, 21, 22, 23, 25}
How to find sets using roster method?The roster method is defined as a way to show the elements of a set by listing the elements inside of brackets.
A typical example of the roster method is to write the set of numbers from 1 to 5 as {1, 2, 3, 4, 5}.
Therefore,
X = {p, q, r, 21, 22, 23}
Y = {q, s, t, 21, 23, 25}
Z = {q, s, 22, 23, 25}
Therefore, let's find X ∪ (Y ∩ Z) as follows:
(Y ∩ Z) = {q, s, 23, 25}
X = {p, q, r, 21, 22, 23}
Therefore,
X ∪ (Y ∩ Z) = {p, q, r, s, 21, 22, 23, 25}
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point a is at (-7,-9) and point b is at (6,3) what is the midpoint of line segment AB
Answer:
(-1/2,-3)
Step-by-step explanation:
(-7,-9) =x1, y1
(6,3) = x2, y2
now,
Mid point= x1+x2 /2 , y1+y2 /2
= -7+6 /2, -9+3 /2
= (-1/2 , -3)
Will someone please help me?
Answer:
1. ) Point Y
2.) Side YX, Side YZ
3.) Point X
4.) Side XZ
Hope this helps!
I need help.. z z s z z z z z. Zz
Answer:
find the area of each figure
The equivalent value of the expression ( 56p - 24 ) ÷ 8 is 7p - 3.
Given data:
The expression is represented as A.
Now, the value of A is \(A=\frac{( 56p - 24 ) }{8}\).
On simplifying the equation:
\(A=\frac{56p}{8}-\frac{24}{8}\)
On dividing each term by 8:
\(A=7p-3\)
Therefore, the value of A is 7p - 3.
Hence, the expression is A = 7p - 3.
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Which of the following is the graph of y=1/2x^2?
PLEASE HELP QUICKLY PLEASE THANK YOU SO MUCH
Given:
\(y = \frac{1}{2}x^2\\\)
Please refer to the attached image for the answer.