Solve the following one-step inequality : -12+x ≥9
I GIVE BRAINLEST I KNOW I SPELL WRONG

Answer:

47 students in each bus

Step-by-step explanation:

243-8= 235

235/5=47

Answer: i think its a

Step-by-step explanation:

The answer is in the form of whole number is 6 .

Given,

In the question:

The number is given as:

= \(7\frac{1}{2} - 1\frac{1}{2}\)

Now, According to the question:

= \(7\frac{1}{2} - 1\frac{1}{2}\)

Convert to fraction into mixed fraction:

= 15/2 - 3/2

Calculate the sum or difference:

= 12/2

Cross out the common factor:

= 6

Hence, The answer is in the form of whole number is 6 .

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The area of the largest square that can fit into the remaining space is 1 inch x 1 inch = 1 square inch.

When one-inch squares are cut from the corners of an inch square, the resulting shape is a square with sides that measure (1 inch - 2 1 inch) = (1 - 2) inches = -1 inch. However, this result is illogical because a square cannot have a negative length.

Assume the problem is about cutting one-inch squares from each corner of a 3-inch square, resulting in a square with sides that are 3 - 2 = 1 inch long. In this case, the largest square that can fit into the remaining space is one with sides equal to the length of the remaining square, i.e., one with sides of length one inch.

Consider inserting a square with sides greater than 1 inch into the remaining space to see why this is the case. The square will either hang over the remaining square's edges or will not fit in it. As a result, the largest square that can fit into the remaining space has sides equal to the remaining square's length, which is 1 inch.

As a result, the area of the largest square that can fit into the remaining space is 1 inch x 1 inch = 1 square inch.

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The range of the given function, using it's concept, is given by the following option.

y≤3: y is less than or equal to 3.

The range of a function is the set that is composed by all the output values on a function.

Om the graph of a function, we have that:

Hence from the graph, the range of the function is given by the values of y of the function.

From the graph of the function given at the end of the answer, the function assumes values of 3 and greater, hence the first option is the correct option giving the range of the function.

The function is given by the image presented at the end of the answer.

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If it is raining in Vancouver, the probability that it is a winter day is approximately 0.133 or 13.3%.

a. To find the probability of rain on a randomly chosen day in Vancouver, we need to consider the probabilities of rain in each season and their respective durations.

Given:

Probability of rain in winter = 0.58

Probability of rain in spring = 0.38

Probability of rain in summer = 0.25

Probability of rain in fall = 0.53

Since each season lasts one quarter of the year, we can calculate the overall probability of rain by taking the weighted average of the probabilities:

P(rain) = (P(rain in winter) * P(winter) + P(rain in spring) * P(spring) + P(rain in summer) * P(summer) + P(rain in fall) * P(fall))

P(rain) = (0.58 * 0.25 + 0.38 * 0.25 + 0.25 * 0.25 + 0.53 * 0.25)

P(rain) = 0.145 + 0.095 + 0.0625 + 0.1325

P(rain) = 0.435

Therefore, the probability of rain on a randomly chosen day in Vancouver is 0.435 or 43.5%.

b. To find the probability that a rainy day in Vancouver is a winter day, we can use Bayes' theorem.

Let:

A = Event of it being a winter day

B = Event of it being a rainy day

We need to find P(A|B), the probability of it being a winter day given that it is raining. According to Bayes' theorem:

\(P(A|B) =\frac{ (P(B|A) * P(A))}{P(B)}\)

We are given:

P(B|A) = Probability of rain on a winter day = 0.58 (from the given data)

P(A) = Probability of a winter day = 1/4 (since each season lasts one quarter of the year)

P(B) = Probability of rain = 0.435 (from part a)

Substituting the values into the equation, we have:

\(P(A|B) = \frac{(0.58 * 1/4)}{ 0.435}\)

\(P(A|B) =0.133333\)

Therefore, if it is raining in Vancouver, the probability that it is a winter day is approximately 0.133 or 13.3%.

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Answer:

Ok, a system of equations means that we have a given number of equations with the same solutions.

If we only have tables, this means that we need to have one table for each equation:

For example, if we are working only with two variables, x and y, in those tables we can see the pints (x, y) that belong to each equation.

Now, a point (x, y) will be a solution of the system of equations only if it belongs to the data table for each equation

This would mean that if we graph those data sets, the graphs will intersect at the point (x, y) that belongs to all the tables of data.

Other way may be using the data in the tables to construct the equations, but you said that you only want to use the tables, so this method can be discarded.

Answer:

infinite solutions

Step-by-step explanation:

2(4x - 6) = 8x - 12

8x - 12 = 8x - 12

-12 = -12

Answer:

8x - 12 = 8x - 12

Step-by-step explanation:

\(2(4x - 6) = 8x - 12 \\ 8x - 12 = 8x - 12\)

= x E R

The rank of matrix II in the given model tells us about the possibility of long-run relationships between the variables.

If the rank of matrix II is 3, it means that the matrix is full rank, indicating that all three variables in the vector yt are linearly independent. In this case, there is a possibility of long-run relationships between the variables, suggesting that they are co-integrated. Co-integration implies that the variables move together in the long run, even if they may have short-term fluctuations or deviations from each other.

If the rank of matrix II is less than 3, it means that there are linear dependencies or collinearities among the variables. This indicates that one or more variables in the vector yt are not independent of the others. In such cases, it is not possible to establish long-run relationships between all variables in the vector. The number of linearly independent variables is equal to the rank of matrix II.

If the rank of matrix II is 2 or 1, it suggests that only a subset of the variables in yt have long-run relationships. For example, if the rank is 2, it means that two variables are co-integrated, while the third variable is not part of the long-run relationship.

In summary, the rank of matrix II provides insights into the possibility of long-run relationships between the variables in the vector yt. A higher rank indicates the presence of co-integration among all variables, while a lower rank suggests that only a subset of variables share long-run relationships.

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The limits approach different finite values as x approaches the same value in the domain. Hence the given limit doesn't exist.

Given f(x) = 2x - 5.

We need to evaluate lim Ax-+0 for the function f(x+4x)-S (X).

Also, we need to find the value of "a" and "b" for which the limit exists both as x approaches 1 and as x approaches $\frac{1}{2}$ .

Solution: Given function is f(x+4x)-S (X)

Now, f(x+4x) = 2(x+4x)-5 = 10x-5Also, S(X) = x + 4 + 1/x

Take the limit as Ax-+0lim 10x-5 - x - 4 - 1/x

We know that as x approaches 0, 1/x will tend to infinity and hence limit will be infinity as well.

Therefore, the given limit doesn't exist.

As we know, $f(x)=2x-5$ and we have to find the value of "a" and "b" for which the limit exists both as x approaches 1 and as x approaches $\frac{1}{2}$ .

Therefore, we have to find the values of a and b such that f(1) and f($\frac{1}{2}$) are finite and equal when evaluated at the same limit.

So, for x = 1;

f(x) = 2(1)-5

= -3And for

x = $\frac{1}{2}$;

f(x) = 2($\frac{1}{2}$) - 5 = -4

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Step-by-step explanation:

this is a strange rental company charging no daily fees.

but ok.

so, we have a fixed part of the cost : $24

we have to pay that no matter how many miles we drive. even for 0 miles, just to get the keys to the car.

and then we pay $0.35 for every mile driven.

that makes our function

C(x) = 0.35x + 24

and if we drive 40 miles, that makes x = 40.

C(24) = 0.35×40 + 24 = 14 + 24 = $38

it would cost us $38.

Answer:

66.3333333333 depending on the decimal point you'd go to

Step-by-step explanation:

10w¹⁰ - 19w⁹ + 6w⁸

= w⁸(10w² - 19w + 6)

= w⁸(2w-3)(5w-2)

The value of the equation after factorization is A = w⁸ ( ( 5w - 2 ) ( 2w - 3 ) )

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

A = 10w¹⁰ - 19w⁹ + 6w⁸   be equation (1)

Now , on factorizing the equation , we get

Taking the common factor as w⁸ , we get

A = w⁸ ( 10w² - 19w + 6 )

On further simplification , we get

A = w⁸ ( 10w² - 15w - 4w + 6 )

Now , on factorizing the equation , we get

A = w⁸ ( 5w ( 2w - 3 ) - 2 ( 2w - 3 ) )

And , the equation will be

A = w⁸ ( ( 5w - 2 ) ( 2w - 3 ) )

Therefore , the value of A is w⁸ ( ( 5w - 2 ) ( 2w - 3 ) )

Hence , the equation is A = w⁸ ( ( 5w - 2 ) ( 2w - 3 ) )

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Answer: 0.75, 70%, 11/20, -2/5, -1/2

Step-by-step explanation:

Convert to decimal values and compare:

Q          A

0.75 0.75

70%         0.7

11/20 0.55

-2/5         -0.4

-1/2    -0.5

Step-by-step explanation:

15×2.25

pounds sold = 33.75

For considering the vector field f(x,y,z)= (3y,3x,4z). The f become a gradient vector field f= ∇V by determining the function V which satisfies V(0,0,0)=0, V(x,y,z) = 3xy + 4z².

We have, a vector field, f(x,y,z) =(3y,3x,4z). We have for f is a gradient vector field, that is F = ∇V, by determining the function V which satisfies condition V(0,0,0)=0, that is we have to determine value of function V (x,y,z). Since, F = ∇V

=> \(3y\hat i + 3x \hat j + 4z \hat k = \frac{dV}{dx}\hat i + \frac{dV}{dy}\hat j + \frac{dV}{dz}\hat k \\ \)

Comparing the elements in both sides,

\(\frac{dV}{dx} = 3y\)

\(\frac{dV}{dy} = 3x\)

\( \frac{dV}{dz} = 4z \)

Now, integrating the above differential equations of determining the \(V(x,y,z) = \int3y dx = 3xy + g(y,z) \\ \)

differentiating with respect to y

\(\frac{dV}{dy} = 3x + g_{y} ( y,z) \)

but from using above equation, g_{y} ( y,z) \) = 0

=> g(y,z) = h(z) ( integrating)

V( x,y,z) = 3xy + h( z)

differentiating with respect to z

\(\frac{dV}{dz} = h'(z)\)

but dV/dz = 4z , so h'(z) = 4z

=> h(z) = 2z²

Hence, the required function is V( x,y,z) = 3xy + 2z².

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Considering the definition of perpendicular line, the equation of the straight line passing through the point (0,-1) which is perpendicular to the line y=3/4x-3 is y= -4/3x -1.

A linear equation o line can be expressed in the form y = mx + b

where

Perpendicular lines are lines that intersect at right angles or 90° angles. If you multiply the slopes of two perpendicular lines, you get –1.

The line is y= 3/4x - 3. The line has a slope of  3/4.

If you multiply the slopes of two perpendicular lines, you get –1, you get:

3/4× slope perpendicular line= -1

slope perpendicular line= (-1)÷ (3/4)

slope perpendicular line= -4/3

The perpendicular line has a form of: y= -4/3x + b

The line passes through the point (0, -1). Replacing in the expression for perpendicular line:

-1= -4/3×0 + b

-1= 0 + b

-1= b

Finally, the equation of the perpendicular line is y= -4/3x -1 .

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Answer:

The value of n is 0.64

Step-by-step explanation:

10^3 = 1000

640 divided by 10^3 = 0.64

The upper quartile for NFC is 3 points higher than that of AFC.

A box plot is used to study the distribution and level of a set of scores. The scores are distributed into 4 groups. Each group has a value of 25%

On the box, the third line on the box represents the upper quartile. 75% of the scores represents the upper quartile.

Upper quartile for AFC : 26

Upper quartile for NFC : 23

Difference = 26 - 23 = 3

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10/√3 is the length of side x in simplest radical form with a rational denominator.

The fundamentals of radical form are simple. When a number or algebraic expression is under a radical, the term refers to that form of the expression. To improve that, we can manipulate a number or an algebraic expression in radical form to convert it to simplest radical form.

Simply put, simplifying a radical eliminate any need to find more square roots, cube roots & fourth roots, etc. when expressing it in its simplest radical form. Additionally, it entails eliminating any radicals from the denominator of a fraction.

The triangle is a right triangle, therefore we will apply trigonometry

To obtain the value of X which is the hypotenuse :

We know that

Cosθ = adjacent / hypotenuse

Cos 30 = 5 / X

√3/2 = 5 / X

√3 / 2 × X = 5

X = 5 ÷ √3 / 2

X = 5 × 2 / √3

X = 10/√3

Thus, 10/√3 is the length of side xx in simplest radical form with a rational denominator.

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Tt wiII cοst Janice $126 tο fiII her sandbοx with sand.

Average tοtaI cοst is the tοtaI cοst divided by οutput.

We can start by cοnverting the Iength οf 6 feet tο yards:

6 feet = 6/3 yards = 2 yards

Nοw we have the dimensiοns οf the sandbοx in yards:

Length = 2 yards

Width = 3 yards

Height = 1.75 yards

Tο find the vοIume οf the sandbοx in cubic yards, we can use the fοrmuIa:

VοIume = Length x Width x Height

VοIume = 2 yards x 3 yards x 1.75 yards

VοIume = 10.5 cubic yards

Cοst = VοIume x Cοst per cubic yard

Cοst = 10.5 cubic yards x $12 per cubic yard

Cοst = $126

Therefοre, it wiII cοst Janice $126 tο fiII her sandbοx with sand.

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The sum of the four terms in the given arithmetic and geometric sequence is 379.

We are given a sequence of four positive integers where the first three terms form an arithmetic progression (a, a + d, a + 2d) and the last three terms form a geometric progression (ar, ar²).

Additionally, the first and fourth terms differ by 30, so we have the equation: a + 2d = ar².

To find the values of a and d, we can use the equations derived from the arithmetic and geometric progressions. The equation for the arithmetic progression is 2a + 2d = ar, and the equation for the geometric progression is a(ar²) = (a + d)(ar).

Simplifying the equation from the geometric progression, we get r = (a + d)/a.

From the equation of the arithmetic progression, we have r = (a + 2d)/2a.

Equating these two expressions for r, we can solve for a and d.

After solving the equations, we find two potential solutions: (a, a + d, a + 2d, ar) = (26, 33, 40, 280) if d = 7,

and (a, a + d, a + 2d, ar) = (26, 20.5, 15, 390.625) if d = -13/2.

To calculate the sum of the four terms, we add them up: 26 + 33 + 40 + 280 = 379 (if d = 7) or 26 + 20.5 + 15 + 390.625 = 451.125 (if d = -13/2).

Therefore, the sum of the four terms is 379.

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The 86th percentile is 45.72 (rounded to 2 decimal places).

To solve the given questions, we will assume that births are uniformly distributed across the 52 weeks of the year, following a uniform distribution from 1 to 53.

a. The mean of a uniform distribution can be calculated using the formula:

  Mean = (a + b) / 2,

  where a is the minimum value (1) and b is the maximum value (53).

  Mean = (1 + 53) / 2 = 54 / 2 = 27.

b. The standard deviation of a uniform distribution can be calculated using the formula:

  Standard Deviation = (b - a) / √12,

  where a is the minimum value (1) and b is the maximum value (53).

  Standard Deviation = (53 - 1) / √12 = 52 / √12 ≈ 15.0111 (rounded to 4 decimal places).

c. The probability that a person will be born at the exact moment that week 48 begins is 1/52 since there is only one specific moment corresponding to that week out of the 52 possible weeks.

d. To find the probability that a person will be born between weeks 5 and 9, we need to calculate the cumulative probability for week 9 and subtract the cumulative probability for week 5. Since the distribution is uniform, the probability for each week is 1/52.

  P(5 < z < 9) = P(z ≤ 9) - P(z ≤ 5) = 9/52 - 5/52 = 4/52 = 1/13.

e. The probability that a person will be born after week 35 can be calculated by subtracting the cumulative probability up to week 35 from 1. Again, since the distribution is uniform, the probability for each week is 1/52.

  P(x > 35) = 1 - P(x ≤ 35) = 1 - 35/52 = 18/52 = 9/26 ≈ 0.3462 (rounded to 4 decimal places).

f. P(x > 8 and x < 33) can be calculated by subtracting the cumulative probability up to week 33 from the cumulative probability up to week 8.

  P(8 < x < 33) = P(x ≤ 33) - P(x ≤ 8) = 33/52 - 8/52 = 25/52 ≈ 0.4808 (rounded to 4 decimal places).

g. To find the 86th percentile, we need to calculate the value below which 86% of the data falls. Since the distribution is uniform, we can calculate it as follows:

  86th percentile = a + (b - a) * 0.86,

  where a is the minimum value (1) and b is the maximum value (53).

  86th percentile = 1 + (53 - 1) * 0.86 = 1 + 52 * 0.86 ≈ 45.72 (rounded to 2 decimal places).

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Births are approximately Uniformly distributed between the 52 weeks of the year. They can be said to follow a Uniform distribution from 1 to 53 (a spread of 52 weeks). Round answers to 4 decimal places when possible a. The mean of this distribution is 27b. The standard deviation is 15.0111 c. The probability that a person will be born at the exact moment that week 48 begins is P(x-48)- 1/52d. The probability that a person will be born between weeks 5 and 9 is P(5 < z < 9)-452 e. The probability that a person will be born after week 35 s P(x> 35)-18/5f P> 8 ix33)g Find the 86th percentile.

Step-by-step explanation:

Length (L) = 2 cm

Breadth (b) = 2 / 3 cm

Area of the rectangle

= L * b

= 2 * 2/3

= 4/3 cm²

Hope it will help :)❤

Answer:

x=39°

Step-by-step explanation:

the tangent from the diameter is 90°

x+90+51=180 sum of interior angle of the triangle is 180

x=180-90-51=39°

Answer:

The surface area of the similar prism is 56 square inches

Step-by-step explanation:

Given surface area of prism, A = 224 square inches

The total surface area of a triangular prism = 2 x Area of triangle + ph

Area of triangle = ¹/₂bh

Where;

b is the base of the prism

h is the height of the prism

p is the perimeter of lateral surfaces

Area of prism involves the product of the dimensions, if the new dimensions is 1/4 the original dimensions;

Product of original dimensions = 224 square inches

1/4 of the product of original dimensions = 1/4 x 224 square inches

= 56 square inches

The surface area of the similar prism = 56 square inches

Thus, the surface area of the similar prism is 56 square inches

Answer:

50 students

Step-by-step explanation:

Students at a school went on a trip. The given equation models the total cost of the trip, where x is the number of students who went on the trip.

18x = 900

How many students went on the trip?

Given equation:

18x = 900

Where,

x = number of students who went on the trip

Number of students who went for the trip

18x = 900

x = 900/18

x = 50 students

Therefore, 50 students went for the trip

Answer:

a= 0.5

Step-by-step explanation:

Step-by-step explanation:

sum of angle 1 and angle 2 is 180°

so,

4x + 14 + 8x + 10 = 180

12x + 24 = 180

12x = 180 - 24 = 156

x = 156/12 = 13

x = 13°

therefore, value of x is 13 and option C is correct.

hope this answer helps you!

Work Shown:

i = P*r*t

i = 1250*0.045*5

i = 281.25