Sodium, an alkali metal, and chlorine, a halogen, are both in Period 3 of the periodic table. Which element has
a higher ionization energy? Explain your answer.

Answer:

what's the question?

Explanation:

for real though what's the question?

Answer:

1. Yes, a person can separate this mixture best using a small screen or strainer and magnet.

Explanation:

iron is magnetic

Answer:

It is possible to divide cells into two classifications: eukaryotic cells, which have a nucleus, and prokaryotic cells, which do not possess a nucleus but do contain a nucleoid area. In contrast to prokaryotes, which are one-celled creatures, eukaryotes may be either single-celled or multicellular in nature.

Explanation:

Hope it helps:)

The rate constant when the temperature is increased to 310 is \(k2 = 0.54 * e^(-111,000/(8.314 * 583))\)

By evaluating this expression, you will find the value of k2, which represents the rate constant at 310°C.

To find the rate constant when the temperature is increased to 310°C, we can use the Arrhenius equation, which relates the rate constant (k) to the activation energy (Ea) and temperature (T):
k = A * e^(-Ea/RT)
Here, A is the pre-exponential factor, R is the gas constant (8.314 J/(mol·K)), and T is the temperature in Kelvin (K).

Activation energy (Ea) = 111 kJ/mol
Rate constant at 300°C (573 K) = 0.54 M^-1s^-1

To calculate the rate constant at 310°C (583 K), we need to convert the activation energy from kJ/mol to J/mol:
Ea = 111 kJ/mol * 1000 J/1 kJ = 111,000 J/mol

Now we can substitute the values into the Arrhenius equation:
k1 = 0.54 M^-1s^-1
T1 = 573 K
Ea = 111,000 J/mol
R = 8.314 J/(mol·K)
T2 = 583 K (new temperature)
k2 = k1 * e^(-Ea/RT2)

Let's calculate k2:
k2 = 0.54 * e^(-111,000/(8.314 * 583))

By evaluating this expression, you will find the value of k2, which represents the rate constant at 310°C. Remember to round your answer to the appropriate number of significant figures, typically determined by the given data.

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The compound is polar and the compound is T shaped.

We know that the Lewis structure of a compound tells us the way that electrons are arranged around a central atom in a compound. We can see that the Lewis structure would consist of the central atom and then the atoms that are surrounding the central atom of the molecule.

In any case, the valence electrons that surround each of the atoms in the compound would be shown as dots and they would surround the symbol of the elements to  which the atoms belong. We can now look up at the structure and be able to deduce what the compound can be able to look like.

The compound as shown is polar because of the fact that he compound is non symmetrical.

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Answer:

3. Mitochondria

Explanation:

Numerous mitochondria are found in each muscle cell to provide metabolic energy for muscle contraction.

hope i helped (:

The pH of the solution is determined by the amount of acid or base present in the solution. pH is a measure of the acidity or alkalinity of a solution, with a range of values from 0 to 14. The pH of a solution is equal to the negative logarithm of the hydrogen ion concentration (H+) in the solution

The pH of a solution of 0.080 m trimethylamine and 0.13 m trimethylammonium chloride can be calculated using the following equation:

Kb = [CH3)3N][H2O] / [(CH3)3NH+][OH-]

where Kb is the base dissociation constant of trimethylamine, (CH3)3N. Using the relationship that Kw = Ka × Kb, where Ka is the acid dissociation constant of water (1.0 × 10-14 at 25 °C), the OH- ion concentration of the solution can be found to be 1.23 × 10-5 M. Then, since Kw = [H+][OH-], the H+ ion concentration is found to be 8.12 × 10-10 M. Finally, taking the negative logarithm of the H+ ion concentration gives a pH of 9.09. When a solution is introduced to water, it can either react with the water to form acid or base.

The pH of the solution is determined by the amount of acid or base present in the solution. pH is a measure of the acidity or alkalinity of a solution, with a range of values from 0 to 14. The pH of a solution is equal to the negative logarithm of the hydrogen ion concentration (H+) in the solution. The pH of the solution can be calculated using the pH formula, which is: pH = -log [H+], where [H+] is the concentration of hydrogen ions in the solution. The given solution is composed of 0.080 m trimethylamine and 0.13 m trimethylammonium chloride. Trimethylamine is a weak base and trimethylammonium chloride is its corresponding conjugate acid. When a weak base is added to water, it undergoes a reaction with water to produce hydroxide ions and a conjugate acid.

The base dissociation constant of trimethylamine, Kb is used to find the OH- ion concentration of the solution. The relationship between Kb and Ka is given by Kw = Ka × Kb, where Ka is the acid dissociation constant of water (1.0 × 10-14 at 25 °C).The OH- ion concentration of the solution can be found to be 1.23 × 10-5 M. Then, since Kw = [H+][OH-], the H+ ion concentration is found to be 8.12 × 10-10 M. Finally, taking the negative logarithm of the H+ ion concentration gives a pH of 9.09.

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Assuming all orbitals are in the same energy level, the orbital with the lowest energy is the s orbital.

In the context of the electronic structure of atoms, orbitals are grouped into different energy levels, with each energy level containing one or more sublevels. The energy levels are labeled using the principal quantum number (n), with higher values of n corresponding to higher energy levels.

Within a given energy level, the s orbital is always the orbital with the lowest energy. This is because the s orbital has a spherical shape and is located at the center of the atom. It is shielded from the nuclear charge by the other electrons in the atom, resulting in a lower energy compared to other orbitals within the same energy level.

The p orbitals, on the other hand, have slightly higher energy than the s orbital within the same energy level. The p orbitals are dum bbell-shaped and are oriented along the x, y, and z axes. They have a higher energy due to their orientation and their closer proximity to the nucleus.

Similarly, the d and f orbitals, which exist in higher energy levels, have even higher energies compared to the s and p orbitals within their respective energy levels.

Therefore, if all the orbitals are in the same energy level, the s orbital will have the lowest energy among them.

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Answer:

True

Explanation:

All living things are made from many cells

Answer:

\(\huge\boxed{True}\)

Explanation:

All living things are composed of cells which are the basic building blocks of living things.

Cell => Tissue => Organ => Organ System => Organism

So, Cell is the "basic" unit of living organism without  which living things cannot be mage or cannot function.

\(\rule[225]{225}{2}\)

Hope this helped!

Answer:

Quito is the one..

The mole of ammonia produced from 7.23 x 10⁻⁴ moles of the hydrogen reactant when there is sufficient nitrogen to react is 4.82×10⁻⁴.

Moles is a unit which is used to estimate the amount of any substance and it is represented as:

n = W/M , where

W = given mass

M = molar mass

Given chemical reaction is:

N₂(g) + 3H₂(g) → 2NH₃(g)

In the question it is given that sufficient moles of N₂ is present, so the formation of product depends on the moles of H₂. From the stoichiometry of the reaction, it is clear that:

3 moles of H₂ = produce 2 moles of NH₃

7.23×10⁻⁴ moles of H₂ = produce 2/3 × 7.23×10⁻⁴=4.82×10⁻⁴ moles of NH₃

Hence, option (C) is correct i.e. 4.82×10⁻⁴.

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Answer:

advantage

Explanation:

The balanced chemical equation is:

0.5C7H16 + O2 → 0.5CO2 + H2O

For balancing the chemical equation C7H16 + O2 → CO2 + H2O, we can use linear algebraic techniques. We need to determine the coefficients that balance the number of atoms on both sides of the equation.

Let's denote the coefficients for C7H16, O2, CO2, and H2O as a, b, c, and d, respectively.

The balanced chemical equation can be written as:

aC7H16 + bO2 → cCO2 + dH2O

To balance the carbon (C) atoms, we have:

7a = c (Equation 1)

To balance the hydrogen (H) atoms, we have:

16a = 2d (Equation 2)

To balance the oxygen (O) atoms, we have:

2b = 2c + d (Equation 3)

We have three equations (Equations 1, 2, and 3) and four unknowns (a, b, c, d). To solve this system of equations, we can write it in matrix form and find the solution using linear algebraic techniques.

The augmented matrix for the system of equations is:

[ 7 0 -1 0 | 0 ]

[ 0 0 0 -2 | 0 ]

[ 0 -2 2 -1 | 0 ]

By performing row operations to row-reduce the augmented matrix, we can obtain the solution:

[ 1 0 -0.5 0 ]

[ 0 1 -1 -0.5 ]

[ 0 0 0 0 ]

The solution to the system of equations is:

a = 0.5

b = 1

c = 0.5

d = 1

Putting the values of a,b,c, and d we get the balanced chemical equation as:

0.5C7H16 + O2 → 0.5CO2 + H2O

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Answer:

Follows are the solution to this question:

Explanation:

The characterization with water molecules would be that light waves are made up of 2 different types of atoms (2 hydrogen and 1 oxygen atoms), as per the Dalton theory. There are many multiple times as many atoms of hydrogen as oxygen atoms in each water molecules. For every two hydrogen atoms, all water molecules have one oxygen atom.

Answer:

Sample Response: Dalton’s theory about compounds tells us that all water molecules have different kinds of atoms, two hydrogen atoms for every one oxygen atom.

Explanation:

Answer:

a

Explanation:

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The pressure that would need to be applied for ammonia to boil at 25.00°C is approximately 1.9 *10^{-6} atm.

The Clausius-Clapeyron equation is given as ln(P2/P1) = (ΔHvap/R) × (1/T1 - 1/T2), where P1 and P2 are the initial and final pressures, ΔHvap is the enthalpy of vaporization, R is the ideal gas constant, T1 is the initial temperature, and T2 is the final temperature.

Given:

T1 = -33.34°C (converted to Kelvin: 239.81 K)

T2 = 25.00°C (converted to Kelvin: 298.15 K)

ΔHvap = 23.35 kJ/mol (converted to J/mol: 23,350 J/mol)

To solve for the pressure (P2), we rearrange the equation as follows:

ln(\frac{P2}{P1}) = (\frac{ΔHvap}{R}) * (\frac{1}{T1} -\frac{ 1}{T2})

Substituting the values, we have:

ln(\frac{P2}{1 atm }) = (\frac{23,350 J/mol }{ 8.314 J/(mol·K)}) * (\frac{1}{239.81 K }- \frac{1}{298.15 K})

After solving the equation, we find that ln(\frac{P2}{1 atm }) ≈ -12.526.

Taking the antilog of both sides, we have:

\frac{P2}{1 atm }≈ e^(-12.526) = 1.9 *10^{-6} atm

Therefore, the pressure that would need to be applied for ammonia to boil at 25.00°C is approximately 1.9 *10^{-6} atm.

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The given compound is a tertiary halide. Tertiary halides generally undergo elimination reactions instead of substitution reactions because the bulky substituents prevent the approach of nucleophiles. The given compound will undergo E2 elimination reaction on treatment with a strong base such as sodium ethoxide, to form an alkene as a major product.

The mechanism of this reaction is as follows:

Step 1: The base, in this case, sodium ethoxide (NaOCH2CH3) abstracts a proton from the carbon adjacent to the halogen atom, forming a carbanion intermediate.

Step 2: The carbanion intermediate is highly unstable and seeks to eliminate a leaving group (in this case a chloride ion) to form an alkene. As the carbanion is highly unstable, the chloride ion and a proton are eliminated simultaneously to form the alkene.

The major organic product formed in this E2 reaction is 1-methylcyclohexene, which is formed by the elimination of a chloride ion from the tertiary halide.

The reaction can be represented as follows:

4-Methyl-1-cyclohexanol → HCl + 1-Methylcyclohexene

Thus, the major organic product formed when the given compound undergoes an E2 reaction is 1-methylcyclohexene.

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U has a total of six electrons. This corresponds to carbon (C). A is the second most common element in the atmosphere.

The second most common element in the atmosphere is oxygen (O). E is a noble gas.

Noble gases include helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). Based on the given options, E could be xenon (Xe).

S is an alkali metal.

Alkali metals include lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr). Based on the given options, S could be sodium (Na).

O is a halogen.

Halogens include fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At). Based on the given options, O could be bromine (Br).

O has an atomic number larger than V but smaller than W.

Based on the periodic table, the atomic number of oxygen (O) is 8, which is larger than the atomic number of vanadium (V) (23) and smaller than the atomic number of tungsten (W) (74).

The charge on an L ion is +2.

The charge of +2 indicates that L must lose two electrons to form the ion. Based on the given options, L could be calcium (Ca).

C has five electrons in its outer energy fever.

Carbon (C) has four valence electrons, not five. This contradicts the given statement, so we need to revisit the deductions.

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The element formed after this portion of the decay series is

213,84Po. This is further explained below.

Generally, when the radioactive element francium undergoes a series of nuclear decays the sum of the mass number, the atomic number, and decay particles are equal.

In conclusion, francium-221 decays to to its first beta decay to give 213,84Po

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CQ

The radioactive element francium undergoes a series of nuclear decays, eventually forming a stable isotope of lead. One part of the process involves francium-221 undergoing two alpha decays, followed by a beta decay. What is the element formed after this portion of the decay series? (In the box below, type in the symbol using the isotope tool. An example for carbon-12 is provided.)

Answer:

478.8 g/cm^3

Explanation:

the best thing to remember is that Volume and density are the only ones that multiply to each other. Density to mass and volume to mass is just division.

the ∆hrxn for the given reaction is 2279.4 kJ/mol.

The ∆hrxn for the given reaction can be calculated using the standard enthalpy of formation of the products and reactants.

The formula for calculating ∆hrxn is:

∆hrxn = ∑∆Hf°(products) - ∑∆Hf°(reactants)

Where ∆Hf° is the standard enthalpy of formation of the respective substance.

In the given reaction, the reactant is 2 Cr2O3(s) and the products are 4 Cr(s) and 3 O2(g).

The standard enthalpy of formation of Cr2O3(s) is given as −1139.7 kJ/mol.

The standard enthalpy of formation of Cr(s) and O2(g) are 0 kJ/mol, as they are in their standard states. Plugging in the values into the formula, we get:

∆hrxn = [(4)(0) + (3)(0)] - [(2)(-1139.7)]

∆hrxn = 0 - (-2279.4)

∆hrxn = 2279.4 kJ/mol

Therefore, the ∆hrxn for the given reaction is 2279.4 kJ/mol.

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Answer:

its obviously a chemical change

Explanation: Facts

The addition of the food color in water only causes the change in the cor of water but no new substance is formed. Therefore, the teacher is restarting the physical change.

A physical change can occur when the characteristics of the matter change but the identity does not. Physical changes are classified as: reversible and irreversible. For example, the melting of water is reversible in nature since the melted ice cube will be refrozen.

Physical change can be described as a kind of change where only physical properties of matter such as odor, color, solubility, etc. can change. During physical changes, there is no chemical bonds are broken or formed between atoms of the substance.

The chemical composition as well as the chemical nature of the substance remains unchanged during a physical change.  The molecules of matter can rearrange without changing the internal composition of matter.

Therefore, adding food color to water is a physical change as no new substance formed.

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Explanation:

Good question!

When you react an acid with a base,the pH of the product is determined by the concentrations of the reactants (the acid and the base)

If both reactants (acid and base) are strong,the pH of the product is 7

If the acid is stronger than the base,the pH of the product will be less than 7

If the base is stronger,the pH of the product will be greater than 7

I hope this helps

The mass of (NH4) 2S in the solution is : Mass = 0.0600 mol × 60.08 g/mol = 3.60 g.

The given molarity and volume of the solution can be used to calculate the number of moles of ammonium sulfide (NH4)2S.Then, the number of moles can be converted to mass using the molar mass of (NH4)2S.Mass of ammonium sulfide (NH4)2S in 3.00 L of a 0.0200 M solution is given by : Mass = moles × molar mass.The number of moles of (NH4)2S can be found using the equation:Molarity = Number of moles / Volume.Rearranging this equation, we get:Number of moles = Molarity × Volume Number of moles of (NH4)2S = 0.0200 M × 3.00 L.Number of moles of (NH4)2S = 0.0600 mol.The molar mass of (NH4)2S can be calculated by summing the molar masses of ammonium (NH4) and sulfide (S) ions.Molar mass of (NH4)2S = (2 × Molar mass of NH4) + Molar mass of S= (2 × 14.01 g/mol) + 32.06 g/mol= 60.08 g/mol.

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hey there!

Water is recognized as the universal solvent because it is able to dissolve different substances.

It is needed 1498.25 g of SiO2.

- From the chemical equation, we know that to produce 40.10 g of SiC, it is needed 60.08 g of SiO2 and 36.033 g of C (because in the reaction there are 3 moles of C).

- Calculating we obtain that:

So, it is needed 1498.25 g of SiO2. This can be expressed as 1.50x10^3 g.

Answer:

false

Explanation:

Answer:true

Explanation:

According to the given information, The gas remaining in the first container shows a pressure of 1.710 atm. Calculate the volume of the spherical container. the volume of the spherical container is 10.01 cm³.

The given parameters are as follows:

Temperature (T1) = 25°C or 298K

Pressure (P1) = 1.850 atm

Volume (V1) = unknown temperature

(T2) = 21°C or 294K

Pressure (P2) = 1.00 atm

Volume (V2) = 1.50 cm3

Pressure (P3) = 1.710 atm'

Volume (V3) = unknown volume of the remaining helium in the first container is given as,

V3 = V1 - V2 = (V1 - 1.50) cm³

Now using the ideal gas law,

PV=nRT

Where,

Substituting the values we get,

n2 = (1 atm × 1.50 cm³)/(0.0821 Latm/K mol × 294 K)

= 0.00007835 mol(2)

Finding the number of moles of gas in the first container can find the number of moles of gas using the ideal gas law. Where,

P3V3 = nRT3n3

= P3V3/RT3

Substituting the values we get,

n3 = (1.710 atm × V3 cm³)/(0.0821 Latm/K mol × 298 K)

Now we can find the volume of the first container as follows:n1 = n2 + n3V1 = (n1RT1)/P1

Where, R = gas constant

T1 = 298K

Substituting the values we get, V1 = ((n2 + n3)RT1)/P1V1 = [(0.00007835 mol + n3) × 0.0821 Latm/K mol × 298 K]/1.850 atm

Equating the expression for V1 and V3, we get, V1 = V3 + 1.50 cm³

Substituting V1, V3 and solving the equation, we getV1 = 10.01 cm³

Therefore, the volume of the spherical container is 10.01 cm³.

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