PLEASE HELP ME SOLVE FOR X
Answer:
7. x = 10
8. x = 13
9. x = 17
10. x = 5
11. x = 9
12. x = 11
Step-by-step explanation:
Explanation for Number 7.
The exterior angle is always equl to the sum of the two opposite interior angles.
The two opposite interior angles: 62 and (7x + 14)
The exterior angle: (15x - 4)
So you would set it up like _____ = ______ to solve for x
62 + (7x +14) = 15x - 4
62 + 7x + 14 = 15x - 4
Then move the terms
76 + 7x = 15x - 4
Collect the like terms and Calculate
7x - 15x = -4 - 76
Divide both Sides
-8x = -80
/8 /8
-x = -10
/-1 /-1
x = 10
Hope this helps ^^
The ratio of 50 hours to 30 hours
The ratio of 50 hours to 30 hours is 1.33 hours.
What is ratio ?
ratio can be defined as the given value divided by the total value, called as the ratio.
Given ,
To find the ratio of 50 hours to 30 hours
let ratio of x to y is x/ y
similarly,
ratio = 50/30
ratio = 5/3
ratio = 1.33 hours.
in terms of minutes it is = (5/3) * 60
number of minutes = 100 minutes
so the ratio of 50 hours to 30 hours in terms of minutes = 100 minutes
Hence, The ratio of 50 hours to 30 hours is 1.33 hours.
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Tell whether b=6 is a solution of 8b=48
Answer:
b= 6 for sure
Step-by-step explanation:
TOPIC=Rearranging
Task:Make x the subject of these equations
6x + v = 4x + w
ax + 9 = 2x + b
7x - w = vx+4
6 - wx = vx + 4
3(wx-v) = 4(x+v)
All the solutions are,
⇒ x = 1/2 (w- v)
⇒ x = (b - 9)/(a - 2)
⇒ x = (4 + w) / (7 - v)
⇒ x = 2 / (v + w)
⇒ x = 7v/(3w - 4)
Given that;
Expressions are,
⇒ 6x + v = 4x + w
⇒ ax + 9 = 2x + b
⇒ 7x - w = vx+4
⇒ 6 - wx = vx + 4
⇒ 3(wx - v) = 4(x + v)
We can simplify as;
⇒ 6x + v = 4x + w
⇒ 6x - 4x = w - v
⇒ 2x = w - v
⇒ x = 1/2 (w- v)
⇒ ax + 9 = 2x + b
⇒ ax - 2x = b - 9
⇒ (a - 2)x = b - 9
⇒ x = (b - 9)/(a - 2)
⇒ 7x - w = vx+4
⇒ 7x - vx = 4 + w
⇒ (7 - v) x = 4 + w
⇒ x = (4 + w) / (7 - v)
⇒ 6 - wx = vx + 4
⇒ vx + wx = 6 - 4
⇒ (v + w)x = 2
⇒ x = 2 / (v + w)
⇒ 3(wx - v) = 4(x + v)
⇒ 3wx - 3v = 4x + 4v
⇒ 3wx - 4x = 7v
⇒ (3w - 4)x = 7v
⇒ x = 7v/(3w - 4)
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I NEED ANSWER ASAP PLEASE WITH WORK PLEASE AND TY!!!!!! In the image the question is 32!! What is the factored form of x2 + 12x - 64?
A (x-4)(x + 16)
B. (x-2)(x + 32)
C. (x + 4)(x - 16)
D. (x-6)(x + 18)
Answer:
A) (x-4)(x+16)
Step-by-step explanation:
\(x^2+12x-64\\=x^2-4x+16x-64\\=x(x-4)+16(x-4)\\=(x+16)(x-4)\)
pls help image attached! x=?
Answer: x=14
Step-by-step explanation:
Since it’s a rectangle, there are two pairs. In this case 6 and across from it are a pair both being 6, and 14 and above it are the same, 14
Answer:14
Step-by-step explanation: x=14 because both the top and bottom are parallel.
What is the volume of a rectangular prism with a height of 6 m, a length of 4 m, and a
width of 2 m?
Plzzz helppppp!!!!!!! 20+PTS and brainliest!!!!!!!!!!!!!!!
Please show work!!!!!!!!!!!
Refer to the equation y=mx+c
Which statement about the location of √7 on the number line is true?
A= It is located at the number 7 on the number line.
B= It is located at the number 3.5 on the number line.
C= It is located between the numbers 2 and 3 on the number line.
D=It is located between the numbers 4 and 9 on the number line
Jake measured a hotel and made a scale drawing. The scale of the drawing was 8 inches : 7 feet. If the actual length of a room in the hotel is 21 feet, how long is the room in the drawing?
Jake measured a hotel and made a scale drawing, the length of the room in the drawing is 24 inches.
If the scale of the drawing is 8 inches : 7 feet, this means that for every 8 inches in the drawing, there are 7 feet in real life.
To find out length of the room is in the drawing, we need to set up a proportion:
8 inches / 7 feet = x inches / 21 feet
where x is the length of the room in the drawing.
We can cross-multiply and solve for x:
8 inches × 21 feet = 7 feet × x inches
168 inches = 7 feet × x inches
Dividing both sides by 7, we get:
24 inches = x
Therefore, the length of the room in the drawing is 24 inches.
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Find the total cost of 12 boxes of cookies if each box costs $3.
each box costs $3 : The cost of one box = $3
12 boxes of cookies : The total number of boxes = $12
For the total cost of 12 boxes : Multiply the cost of one box by the number of boxes
The total cost of 12 boxes = 12 x $3
The cost of 12 boxes = $36
The cost of 12 boxes of cookies ia $36
Answer : $36
Find X and QT. The shape is a Rhombus
Answer:
See below ~
Step-by-step explanation:
Sides of a rhombus are equal.
⇒ QT = TS
⇒ x² - 4x - 10 = 6x + 14
⇒ x² - 10x - 24 = 0
⇒ x² + 2x - 12x - 24 = 0
⇒ x (x + 2) - 12 (x + 2) = 0
⇒ (x + 2)(x - 12) = 0
⇒ x = -2 or x = 12
Substitute both values and see which gives a positive value for QT :
When x = -2 :
QT = (-2)² - 4(-2) - 10QT = 4 + 8 - 10QT = 2When x = 12 :
QT = (12)² - 4(12) - 10QT = 144 - 48 - 10QT = 86The 2 possible answers are :
x = -2, QT = 2x = 12, QT = 86Amy and Richard each solved an equation using the quadratic formula.
Amy's Equation and Method
Latex: 4x^2+7x-20=0
4
x
2
+
7
x
−
20
=
0
Step 1: Latex: x=\frac{-7\pm \sqrt{7^2-4(1)(20)}}{2(4)}
x
=
−
7
±
√
7
2
−
4
(
1
)
(
20
)
2
(
4
)
Step 2: Latex: x=\frac{-7\pm \sqrt{49-80}}{8}
x
=
−
7
±
√
49
−
80
8
Step 3: Latex: x=\frac{-7\pm \sqrt{-31}}{8}
x
=
−
7
±
√
−
31
8
Step 4: Latex: x=\frac{-7\pm i\sqrt{31}}{8}
x
=
−
7
±
i
√
31
8
Richard's Equation and Method
Latex: x^2-6x+8=0
x
2
−
6
x
+
8
=
0
Step 1: Latex: x=\frac{6\pm \sqrt{(-6)^2-4(1)(8)}}{2(1)}
x
=
6
±
√
(
−
6
)
2
−
4
(
1
)
(
8
)
2
(
1
)
Step 2: Latex: x=\frac{6\pm \sqrt{36-32}}{2}
x
=
6
±
√
36
−
32
2
Step 3: Latex: x=\frac{6\pm \sqrt{4}}{2}
x
=
6
±
√
4
2
Step 4: Latex: x=\frac{6+\sqrt{4}}{2}
x
=
6
+
√
4
2
and Latex: x=\frac{6-\sqrt{4}}{2}
x
=
6
−
√
4
2
Step 5: Latex: x=\frac{6+2}{2}
x
=
6
+
2
2
and Latex: x=\frac{6-2i}{2}
x
=
6
−
2
i
2
Step 6: Latex: x=4
x
=
4
and Latex: x=3-i
x
=
3
−
i
Both students made a mistake.
Describe the mistake each student made.
Explain what each student needs to do to fix their mistake.
Create your own quadratic equation, and explain how to use the quadratic formula to solve it. Be specific, using Latex: a\textsf{, }b\textsf{,} and Latex: c
c
of your equation and giving the solutions to the equation you chose.
Number your responses from 1 to 3 so your instructor can tell which question you're responding to. You may not receive full credit if your teacher cannot determine that you've answered each question.
Search entries or author
The mistake each student made and what each student needs to do to fix their mistake is;
Amy didn't include the negative sign for the 20, so she should include itRichard added a negative sign underneath the radicalQuadratic equationx² - 6x + 8 = 0
x = - b ± √b² - 4ac / 2a
where,
a = 1b = -6c = 8x = - b ± √b² - 4ac / 2a
= -(-6) ± √(-6)² - 4(1)(8) / 2(1)
= 6 ± √36 - 32 / 2
= 6 ± √4 / 2
= 6 ± 2 / 2
x = 6/2 + 2/2 or 6/2 - 2/2
= 3 + 1 or 3 - 1
x = 4 or 2
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Find the slope of the line that passes through the two points. (0, 0), (3, 2)
Answer:
the slope is 2/3 bcoz u do 2-0/3-0
The population of Berlin, Germany was about 3,290,000 in 2011. Its population is
declining continuously at a rate of 2%. What is the predicted population for 2050?
Population rate can be represented using exponential functions
The predicted population for 2050 is 1496280
How to determine the predicted populationThe initial population is given as;
a = 3290000
The rate of decline is given as:
r = 2%
So, the population function is:
\(p = a*(1 - r)^t\)
This gives
\(p = 3290000*(1 - 2\%)^t\)
2050 is 39 years after 2011.
So, we have:
\(p = 3290000*(1 - 2\%)^{39\\\)
Evaluate
\(p = 1496280\)
Hence, the predicted population for 2050 is 1496280
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Andy is comparing how long two tablets can be used after being fully charged.
-
Tablet A Tablet B
(minutes) (minutes)
540
593
Mean
Median
580
589
NOR
21
13
MAD
6
2
Answer:
Part A: On average Tablet B's battery will last longer.
Part B: The MAD is lower in tablet B's battery life so Tablet B is more consistent.
Step-by-step explanation:
calculate the area of this triangle 18cm, 14cm and height is 11cm
Answer : 99cm^2
Hope this helps
The area of the triangle with a height of 11 cm and a base of 18 cm is,
99 cm².
What is a triangle?A triangle is a three-sided closed-plane figure formed by joining three noncolinear points.
Based on the side property triangles are of three types they are Equilateral triangle, Scalene triangle, and Isosceles triangle.
We also know,
The way of classifying a triangle,
If a² + b² < c² then it is an acute angle triangle.
If a² + b² = c² then it is a right-angle triangle.
If a² + b² ≥ c² then it is an obtuse angle triangle.
The area of a triangle is half times the product of the height and base.
The given triangle has a height of 11 cm and a base of 18 cm.
Therefore, The area of the triangle is,
= (1/2)×18×11 cm².
= 99 cm².
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help with 6 please i need to graduate
The expression with the correct coefficients in each block is given as follows:
20x³ + 0x² - 7x.
How to obtain the resultant function?The functions in the context of this problem are defined as follows:
f(x) = 4x.g(x) = 5x² - 4.h(x) = 9x.The operation is given as follows:
f(x)g(x) + h(x).
Hence, to obtain the resultant function, we apply the definitions into the operation and the simplify, applying the distributive property and combining the like terms, as follows:
4x(5x² - 4) + 9x = 20x³ - 16x + 9x = 20x³ - 7x.
As there is no x² term, the coefficient of zero multiplies the term x².
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solve the following by multiplying by the inverse of the fractional coeffident 2/5t=20
Answer:
t=1/50
Step-by-step explanation:
2/5t=20
2=100t
2/100=t
t=1/50
Two methods are proposed for testing a shipment of five items (call them A, B, C, D, and 13). In method 1, an inspector randomly samples two of the five items and tests to see whether either item is defective. In method 2, an inspector randomly samples one item and tests it; the remaining four items are sent to a second inspector who randomly samples one item and tests it. Suppose that only item A is defective in the shipment.
a. What is the probability that item A will be dis-covered by method 1?
b. What is the probability that item A will be dis-covered by method 2?
c. What general statement can you make regarding the effectiveness .of the two methods? Can your statement be extended to methods involving samples of more than two items?
Answer:
a-The probability that item A is discovered as a defective item by method 1 is 0.4
b. The probability that item A is discovered as a defective item by method 2 is 0.4
c-As the probability of detecting A as a defective item is same for the two methods, thus it can be stated that each of the methods is equally effective.
Step-by-step explanation:
a-
The first method where the inspector chooses two of the five items randomly, so the total pairs are as given below:
\(N_{total}=n(S_{total})\\N_{total}=n(\{AB,AC,AD,AE,BC,BD,BE,CD,CE,DE\})\\\)
As the total experiments in the overall space is 10 so \(N_{total}\) is 10.
As A comes in 4 of these experiments, thus the value of \(N_{A}\) is 4.
So the Probability of A is given as
\(P(A)=\dfrac{N_{A}}{N_{total}}\\P(A)=\dfrac{4}{10}\\P(A)=0.4\)
The probability that item A is discovered as a defective item by method 1 is 0.4.
b-
Now in order to find the probability of finding item A as defective by method 2, first consider the probability of not finding item A as defective.
This is given as
\(P(A)=1-P(A)'\)
Here P(A)' is given as
\(P(A)'=P(A)'_{1^{st}}\times P(A)'_{2^{nd}}\)
Here
P(A)'_1st is the probability that the first inspector fails to detect A as a defective item which is given as
\(P(A)'_{1^{st}}=1-\dfrac{1}{N_{total\ items}}\)
Here N_total items is 5. so the equation becomes
\(P(A)'_{1^{st}}=1-\dfrac{1}{N_{total\ items}}\\P(A)'_{1^{st}}=1-\dfrac{1}{5}\\P(A)'_{1^{st}}=\dfrac{5-1}{5}\\P(A)'_{1^{st}}=\dfrac{4}{5}\)
Similarly
P(A)'_2nd is the probability that the second inspector fails to detect A as a defective item which is given as
\(P(A)'_{2^{nd}}=1-\dfrac{1}{N_{total\ items}}\)
Here N_total items is 4 as 1 item has already been checked. so the equation becomes
\(P(A)'_{2^{nd}}=1-\dfrac{1}{N_{total\ items}}\\P(A)'_{2^{nd}}=1-\dfrac{1}{4}\\P(A)'_{2^{nd}}=\dfrac{4-1}{4}\\P(A)'_{2^{nd}}=\dfrac{3}{4}\)
So the main equation becomes
\(P(A)=1-P(A)'\\P(A)=1-(P(A)'_{1^{st}}\times P(A)'_{2^{nd}})\)
Substituting the values give
\(P(A)=1-(P(A)'_{1^{st}}\times P(A)'_{2^{nd}})\\P(A)=1-(\dfrac{4}{5}\times \dfrac{3}{4})\\P(A)=1-\dfrac{3}{5}\\P(A)=\dfrac{5-3}{5}\\P(A)=\dfrac{2}{5}\\P(A)=0.4\)
The probability that item A is discovered as a defective item by method 2 is 0.4.
c-
As evident from the above, that the value of probabilities for both the methods is same therefore the overall effectiveness of each of the methods is same.
A spinner has 4 equal sectors colored yellow, blue, green, and red. If in 100 spins we get
28 blue (B), 25 red (R), 29 green (G), and 18 yellow (Y) outcomes, find the empirical probability of getting color P(R).
O A. 6/25
OB. 1/4
O C. 3/10
O D. 13/50
Answer:
B
Step-by-step explanation:
28+25+29+18 = 100
red = 25
25/100 = 1/4
The required empirical probability is 1/4 which gets the color of red P(R).
What is probability?The probability is defined as the possibility of an event being equal to the ratio of the number of favorable outcomes and the total number of outcomes.
A spinner has 4 equal sectors colored yellow, blue, green, and red. If in 100 spins we get
28 blue (B), 25 red (R), 29 green (G), and 18 yellow (Y) outcomes
To find the empirical probability of getting a red outcome, we need to divide the number of red outcomes by the total number of spins:
P(R) = 25 red outcomes / 100 spins
Apply the division operation, and we get
P(R) = 1/4
Hence, the required empirical probability is 1/4
Therefore, the correct answer is 1/4 or option B.
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Use the histogram to answer the following questions.
Frequency
The frequency of the class 90-93 is
The frequency of the class 94-97 is
This means that a total of
5.5
5
4.5
Your answers should be exact numerical values.
The frequency of the class 86-89 is
86
94
90
Duration of Dormancy (minutes)
dormancy periods were recorded.
The parameters that are needed to calculate a probability are listed as follows:
Number of desired outcomes in the context of a problem or experiment.Number of total outcomes in the context of a problem or experiment.Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes, hence it is the same as a relative frequency.
The total number of periods is given as follows:
5 + 6 + 4 = 15.
The frequency of each class is given as follows:
86 - 89: 5/15 = 1/3.90 - 93: 6/15 = 2/5.94 - 97: 4/15.Learn more about the concept of probability at https://brainly.com/question/24756209
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Solve the given equation by completing the square.
Fill in the values of a, b, and e to complete the solutions.
The solution in this case is x = (4 + sqrt(102+4c))/2 - 4√c, which can be expressed in the form of X = a - b√c.
How to solve quadratic equation?
To solve the equation x²+8x-38=0, we can use the quadratic formula:
x = (-b ± sqrt(b²-4ac)) / 2a
Here, a=1, b=8, and c=-38. Substituting these values into the formula gives:
x = (-8 ± sqrt(8²-4(1)(-38))) / 2(1)
x = (-8 ± sqrt(324)) / 2
x = (-8 ± 18) / 2
So x is either -13 or 5.
To find the values of x in the form of X = a + b√c and X = a - b√c, we can use the following steps:
For X=a+b√c:
Let's assume that x = a + b√c, where a, b, and c are constants to be determined.
Substituting this into the original equation x²+8x-38=0, we get:
(a + b√c)² + 8(a + b√c) - 38 = 0
Expanding the square and simplifying, we get:
(a² + 2ab√c + b²c) + 8a + 8b√c - 38 = 0
Separating the real and imaginary parts, we get:
(a² + b²c + 8a - 38) + (2ab√c + 8b)√c = 0
Since the real and imaginary parts of the equation must both be zero, we can set them each equal to zero and solve for a, b, and c.
First, setting the real part equal to zero gives:
a² + b²c + 8a - 38 = 0
This is a quadratic equation in a, so we can use the quadratic formula:
a = (-8 ± sqrt(8²-4(bc-38))) / 2
Simplifying this gives:
a = -4 ± sqrt(4+b(b-10))
Now, setting the imaginary part equal to zero gives:
2ab + 8b = 0
Solving for b, we get:
b = 0 or b = -4
If b = 0, then a² + b²c + 8a - 38 = a² + 8a - 38 = 0, which has roots a = -5 and a = 3. Therefore, the solution in this case is x = -5 or x = 3, which cannot be expressed in the form of X = a + b√c.
If b = -4, then a² + b²c + 8a - 38 = a² + 16c + 8a - 38 = 0. Plugging this into the quadratic formula for a, we get:
a = -4 ± sqrt(102-4c)/2
Therefore, the solution in this case is x = (-4 + sqrt(102-4c))/2 - 4√c, which can be expressed in the form of X = a + b√c.
For X=a-b√c:
Using the same logic, we can assume that x = a - b√c, where a, b, and c are constants to be determined.
Substituting this into the original equation x²+8x-38=0, we get:
(a - b√c)² + 8(a - b√c) - 38 = 0
Expanding the square and simplifying, we get:
(a² + b²c - 8a - 38) + (-2ab√c - 8b)√c = 0
Since the real and imaginary parts of the equation must both be zero, we can set them each equal to zero and solve for a, b, and c.
Setting the real part equal to zero gives:
a² + b²c - 8a - 38 = 0
This is a quadratic equation in a, so we can use the quadratic formula:
a = (8 ± sqrt(8²+4(bc+38))) / 2
Simplifying this gives:
a = 4 ± sqrt(4+b(b+10))
Setting the imaginary part equal to zero gives:
-2ab - 8b = 0
Solving for b, we get:
b = 0 or b = -4
If b = 0, then a² + b²c - 8a - 38 = a² - 8a - 38 = 0, which has roots a = -3 and a = 11. Therefore, the solution in this case is x = -3 or x = 11, which cannot be expressed in the form of X = a - b√c.
If b = -4, then a² + b²c - 8a - 38 = a² + 16c - 8a - 38 = 0. Plugging this into the quadratic formula for a, we get:
a = 4 ± sqrt(102+4c)/2
Therefore, the solution in this case is x = (4 + sqrt(102+4c))/2 - 4√c, which can be expressed in the form of X = a - b√c.
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Need helping solving for zero domain and range!!
Answer:
Zero: (1,0)
Domain: -infinity, + infinity
Range: -infinity, + infinity
Step-by-step explanation:
I know that the zero answer is right because zero is just another name for x intercept. Range is all possible y values and domain is all possible x values
Which answer choice shows 3.151 rounded to the nearest tenth?
A. 3.15
B. 3.16
C. 3.2
D. 3.1
Answer:
Which answer choice shows 3.151 rounded to the nearest tenth?
A. 3.15
B. 3.16
C. 3.2
D. 3.1
Step-by-step explanation:
You're welcome
Differentiate y=x4 -x
Answer:
Step-by-step explanation:
To differentiate the function y = x^4 - x, we will use the power rule of differentiation. The power rule states that if f(x) = x^n, then the derivative of f(x) is f'(x) = nx^(n-1).
So, for y = x^4 - x, we can find the derivative as follows:
y' = 4x^3 - 1
So, the derivative of the function y = x^4 - x is y' = 4x^3 - 1.
A calf raiser mixes a batch of milk replacer for 15 calves. Each calf gets two
quarts of milk replacer. If the calf raiser uses 960 oz. of replacer and needs to
add 34 as much water as milk replacer, how many ounces of water does she need?
Answer:
The calf raiser uses 960 oz of milk replacer for 15 calves, so each calf gets 960 oz / 15 = 64 oz of milk replacer.
To convert this to quarts, we need to divide by 32 (since there are 32 oz in a quart)
64 oz / 32 oz/quart = 2 quarts
Each calf gets 2 quarts of milk replacer and the calf raiser needs to add 34 as much water as milk replacer
So the total amount of water she needs is 2*34 = 68 quarts
To convert the quarts of water to ounces we need to multiply by 32 (since there are 32 oz in a quart)
68 quarts * 32 oz/quart = 2176 oz of water.
So the calf raiser needs 2176 ounces of water to mix with the milk replacer for 15 calves.
commutative property of (32)-5+7?
Answer:
= 34
Step-by-step explanation:
(32)-5+7
32 - 5 + 7
= 32 + 2
= 34.
If x is the first or smallest of three consecutive even integers what is the second integer
Answer: x+2
Step-by-step explanation:
even integers have a difference of 2 since the next even integer is after an odd integer. Hence, x+2 is the next even integer after x.
Need to solve a math problem
Answer: what do you have problem with.
Step-by-step explanation: