Jill graphs the speed of a model train that is travelling at a speed of 15 kilometers per hour. Which graph shows the speed of the model train?

Answer:

yes thats right

Explanation:

Answer:

0.396 J/g°C (to 3 sf)

Explanation:

50.0 = 10.6(24.9-13.0)(c)

c = 0.396 J/g°C (to 3 sf)

Answer:

A,C,D

Explanation:

Variations effect the likelyhood of survival for a organism, it can give off an advantage or disadvantage.

Brainliest? pls

Answer:

0.64 M

Explanation:

Step 1: Given data

Step 2: Calculate the final concentration of the dextrose solution

We want to prepare a diluted solution from a concentrated one. We can find the final concentration using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 1.0 M × 16 mL / 25 mL

C₂ = 0.64 M

Answer:

How do amoeba respire.

Define Diffusion.

Answer:

1.25 g

Explanation:

Now we have to use the formula;

N/No = (1/2)^t/t1/2

N= mass of cesium-137 left after a time t (the unknown)

No= mass of cesium-137 present at the beginning = 5.0 g

t= time taken for 5.0 g of cesium-137 to decay =60 years

t1/2= half life of cesium-137= 30 years

Substituting values;

N/5= (1/2)^60/30

N/5= (1/2)^2

N/5= 1/4

4N= 5

N= 5/4

N= 1.25 g

Therefore, 1.25 g of cesium-137 will remain after 60 years.

Answer:

B

Explanation:

Newton's third law. states that:

Action and reaction are equal and opposite.

Answer:

The volume is decreasing at a rate of 30 cm³/min.

Explanation:

From the question given above, pressure (P) and volume (V) are related by the following equation

PV = C

C => constant

If we make P the subject of the above, we shall have:

P = C/V

From the equation above (i.e P = C/V),

We can say that P is inversely proportional to V. This implies that as P is increasing, V will be decreasing and also, as P is decreasing, V will be increasing.

Considering the question given above, the pressure (P) is increasing at a rate of 30 kPa/min. Therefore, the volume will be decreasing at a rate of 30 cm³/min.

Answer: Answer IS in the explanation.

Explanation: Alkaline Earth metals are group 2 of the periodic tables, whereas alkali metals are in group 2. The major difference between alkaline and Alkali is that Alkaline earth metals have two valence electrons whereas alkali metals have one valence electron.

Answer:

Alkali

Alkaline Earth Metals

Soft metals

Hard metals

One valence electron

Two valence electrons

Form 1+cations

Form 2+cations

More reactive

Less reactive

low melting and boiling point

High(er) melting and boiling point

Group 1

Group 2

Used for group one elements on P.Table

Used for group two elements on P.Table

Lower ionizing energy

High(er) ionizing energy

Explanation: here are the differences

Answer:

reaction?

Explanation:

4na + o2 → 2na2o

Answer: They share electrons and become bonded together.

Explanation: Most interactions among atoms take place in the outermost shell of each atom. The number of each electron in this shell determines how an atom combines with other atoms to form compounds. When atoms combine they gain, lose or share electrons in such a way that the outer shells become chemically complete.

The sound waves from the siren will reflect off the smooth surface of the wall. The light waves from the emergency vehicle will reflect off the smooth surface of the wall. Rougher sections of the wall surface will cause the light waves from the emergency vehicle to scatter.

When sound waves hit a smooth surface, they reflect off the surface in a predictable way called the law of reflection. So, the sound waves from the siren will reflect off the smooth surface of the wall.

Similarly, light waves also follow the law of reflection when they hit a smooth surface. Therefore, the light waves from the emergency vehicle will also reflect off the smooth surface of the wall.

However, when light waves encounter a rough surface, they scatter in all directions due to the irregularities on the surface. Therefore, rougher sections of the wall surface will cause the light waves from the emergency vehicle to scatter.

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The number of formula units that make up 26.4g of magnesium chloride is 1.67 × 10²³ units.

Formula units is the empirical formula of an ionic compound (that does not possess individual molecules) for use in stoichiometric calculations.

The number of formula units of a substance can be calculated by multiplying the number of moles of the substance by its number of moles as follows:

no of formula units = no of moles × 6.02 × 10²³

First, we convert the mass of magnesium chloride to moles by dividing by its molar mass. Molar mass of magnesium chloride is 95.211 g/mol.

moles = 26.4g ÷ 95.211g/mol = 0.277moles

no of formula units = 0.277moles × 6.02 × 10²³

no of formula units = 1.67 × 10²³ units

Therefore, 1.67 × 10²³ units is the number of formula units of magnesium chloride.

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Answer:  A) Mg

Explanation:

Answer:

Ag will replace Pb from Pb(NO3)2.

Explanation:

Stoichiometry means relation between proportion in which compounds reacts with each other. Silver Nitrate (AgNO3) is prepared by dissolving Silver in Nitric acid and evaporating the solution.

3Ag + 4HNO3(cold and diluted) -> 3AgNO3 + 2H2O + NO

Ag+2HNO3(hot and concentrated) -> AgNO3 + H2O + NO2

Step 1 - Understanding the relation between volume and temperature for a gas sample

There are three main variables that can change the state of a gas sample: temperature, pressure and volume. If the pressure (P) is kept constant, the volume (V) becomes proportional to the temperature (T) in K:

Step 2 - Substituting the values in the equation above

We know, from the exercise, that V1 = 9.02 L and T1 = 585.57 K, and V2=2.24 L. Substituting these values in the equation above:

For the extraction of at least 95% of Y in water, 3 extractions are to be performed.

Distribution coefficient can be defined as the ratio of the concentration of solute in an organic solvent to water.

Distribution coefficient = \(\rm \dfrac{concentration\;in\;solvent}{concentration\;in\;water}\)

Concentration in water = 100-X per 50 ml

Distribution coefficient = \(\rm \dfrac{\frac{X}{10} }{\frac{100-X}{50} }\)

4 = \(\rm \dfrac{\frac{X}{10} }{\frac{100-X}{50} }\)

4 = \(\rm \dfrac{50X}{1000-X}\)

4000 - 4X = 50X

X = 74.1 %

Thus, after the first extraction, the amount of Y extracted is 74.1%.

We have to extract at least 95% of Y. Thus, the second extraction is performed.

Remaining y = 25.9%

The concentration in organic solvent = X per 10 ml

Concentration in water = 25.9 -X

Distribution coefficient = \(\rm \dfrac{\frac{X}{10} }{\frac{25.9-X}{50} }\)

4 = \(\rm \dfrac{\frac{X}{10} }{\frac{25.9-X}{50} }\)

4 = \(\rm \dfrac{50X}{259-X}\)

1036 - 4X = 50X

X = 19.2%

Thus, after the second extraction the amount of Y extarcted = first extraction + second extraction

The amount of Y extracted = 74.1 + 19.2 %

The amount of Y extracted = 93.3%

The remaining Y for third extraction = 100 - 93.3

The remaining Y for the third extraction = 6.7%

Concentration in water = 100 - 6.7

Distribution coefficient = \(\rm \dfrac{\frac{X}{10} }{\frac{6.7-X}{50} }\)

4 = \(\rm \dfrac{\frac{X}{10} }{\frac{6.7-X}{50} }\)

4 = \(\rm \dfrac{50X}{67-X}\)

268 - 4X = 50X

X = 5.0%

The total extraction after third extraction = 93.3 + 5%

The total extraction after third extraction = 98.3%.

Thus for the extraction of at least 95% of Y in water, 3 extractions are to be performed.

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Vitamin C drink with 1025 mg of ascorbic acid contains 3.50 × 10^21 molecules of C6H8O6.

What is Molecules?

A molecule is the smallest particle in a chemical element or compound that has the chemical properties of that element or compound. It is made up of two or more atoms that are chemically bonded together. The atoms can be of the same element, as in the case of diatomic molecules like O2 and H2, or they can be different elements, as in the case of water (H2O) or carbon dioxide (CO2).

First, let's calculate the molar mass of ascorbic acid (C6H8O6):

Molar mass of C = 12.01 g/mol

Molar mass of H = 1.008 g/mol

Molar mass of O = 16.00 g/mol

Molar mass of C6H8O6 = (6 × 12.01) + (8 × 1.008) + (6 × 16.00) = 176.12 g/mol

Now we can use the molar mass to convert the given mass of ascorbic acid into moles:

Number of moles = Mass / Molar mass

Mass of ascorbic acid = 1025 mg = 1.025 g

Number of moles of ascorbic acid = 1.025 g / 176.12 g/mol = 0.00582 moles

Finally, we can use Avogadro's number to convert from moles to molecules:

Number of molecules = Number of moles × Avogadro's number

Number of molecules of C6H8O6 = 0.00582 moles × 6.022 × 10^23 molecules/mol = 3.50 × 10^21 molecules

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The root mean square speed of F2(g) molecules under the same conditions is approximately 431.3 m/s.

The root mean square (rms) speed of a gas molecule is related to its average kinetic energy (KE) by the following equation:

rms speed = √(3RT/M)

Where

To solve for the rms speed of F2(g) molecules, we need to know the temperature and molar mass of F2(g). Let's assume that the temperature is the same as the conditions in which He(g) has an average kinetic energy of 7450 J/mol. The molar mass of F2 is 2 x the molar mass of one fluorine atom, which is approximately 19 amu.

Substituting these values into the equation, we get:

Now we can solve for the rms speed by plugging in the given value of average kinetic energy for He(g) and solving for T:

7450 J/mol = (1/2) x (3/2) x R x T

T = 7450 J/mol / (1.5 x 8.314 J/mol·K)

T = 597 K

Substituting this value of T into the equation for rms speed, we get:

rms speed = √(0.6564 J/K x mol x 597 K / 1 mol)

rms speed = 431.3 m/s

Therefore, the root mean square speed of F2(g) molecules under the same conditions is approximately 431.3 m/s.

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The amount of N2O5 to start with would be 35.79 grams

From the balanced equation of the reactions:

\(2N_2O_5 --- > 4NO_2 + O_2\)

Mole ratio of N2O5 and NO2 = 1:2

Since the reaction's actual yield is 82%, the theoretical yield would be: 25 x 100/82 = 30.49 grams

Mole of 25 g NO2 = 30.49/46

                              = 0.66 mole

Equivalent mole of N2O5 = 0.54/2 mole

                                               = 0.33 moles

Mass of 0.27 mole N2O5 = 0.33 x 108.01

                                                = 35.79 grams

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Answer: +2

Explanation::)

Answer:

12000 joules

Explanation:

due to enthalpy of fusion

The addition of hydrochloric acid to a reaction mixture can serve several purposes, depending on the specific reaction and its conditions such as: (1) To provide protons (H⁺), (2) To adjust the pH of the reaction mixture, (3) To remove impurities or byproducts.

(1) To provide protons (H⁺) for acid-catalyzed reactions: HCl is a strong acid, meaning it readily donates protons to other molecules. In some reactions, the presence of HCl can accelerate the reaction by increasing the concentration of protons in the reaction mixture. This can facilitate bond-breaking and bond-forming steps in the reaction mechanism.

(2) To adjust the pH of the reaction mixture: In some reactions, it may be necessary to maintain a specific pH range for the reaction to proceed optimally. By adding HCl, the pH of the reaction mixture can be lowered, making the environment more acidic. Conversely, the addition of a base such as sodium hydroxide (NaOH) can raise the pH of the reaction mixture.

(3) To remove impurities or byproducts: In some reactions, the addition of HCl can help to remove impurities or byproducts that may interfere with the desired reaction. For example, HCl can be used to remove metal oxides or hydroxides from a reaction mixture.

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Answer:

Mathematical Literacy refers to the ability to reason with quantitative expressions in comparative, proportional and percentage terms. It is this definition that most lends itself to an examination of skill levels across Canada's education system - which ones are required for success in society (in the simplest sense) and which ones are superfluous.

*ANSWER MADE BY AN AI*

The equilibrium constant for the system at this temperature is\(1.17 × 10^-31 mol^2/L^2\).

For the chemical equation:

N2(g) + O2(g) ⇌ 2NO(g)

The equilibrium mixture at a temperature of 1500 K is determined to contain 6.4 × 10^-3 mol/L of N2,\(1.7 × 10^-3\)mol/L of O2 and 1.1 × 10^-5 mol/L of NO.  First, we need to calculate the concentration of N2 and O2 required to produce

1.1 × 10^-5 mol/L of NO:

2NO(g) = N2(g) + O2(g)

Given that there are 1.1 × 10^-5 mol/L of NO, the number of moles of N2 and O2 are equal since the stoichiometric ratio is 1:1. Therefore:

\(1.1 × 10^-5 mol/L\) = [N2][O2]Kc = \(([NO]^2)/([N2][O2])Kc\)= \((1.1 × 10^-5 mol/L)^2/(6.4 × 10^-3 mol/L)(1.7 × 10^-3 mol/L)Kc\) =

1.17 × 10^-31 mol^2/L^2.

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Answer:

C.) No, because the Moon reflects most of the Sun's light rather than

absorbing it

Explanation:

:p

Answer:

985.2 moles of nitrogen can produce 1970.4 moles of ammonia.

Explanation:

The balanced chemical equation for the production of ammonia from nitrogen is:

N2 + 3H2 → 2NH3

From the balanced equation, we can see that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.

So, to determine how many moles of ammonia can be produced from 985.2 moles of nitrogen, we need to use the mole ratio from the balanced chemical equation as follows:

985.2 moles N2 x (2 moles NH3 / 1 mole N2) = 1970.4 moles NH3

Therefore, 985.2 moles of nitrogen can produce 1970.4 moles of ammonia.

The percent by mass of each element in C12H22O11 is 42.1 % for C, 6.4 % for H, and 51.43 % for O respectively.

The mass consistent with cent is defined as the grams of solute consistent with grams of solution, accelerated with the aid of one hundred to get the share. The Mass in keeping with cent components is expressed as fixing for the molar mass and also for the mass of each detail in 1 mole of the compound. Mass percent is one way of representing the attention of an element in a compound or a component in a mixture

Calculation:-

Molar Mass of C12H22O11 = 342

C 12 x 12.01 = 144.12 / 342 × 100

                   = 42.1 %

H 22 x 1.00 = 22/ 342 × 100 = 6.4 %

O 11 x 15.99 = 175.89/ 342 × 100 = 51.43 %

Mass percentage composition is likewise recognized percent via weight. it's miles abbreviated as w/w%. For a solution, mass percent equals the mass of an element in a single mole of the compound divided with the aid of the molar mass of the compound, increased with the aid of 100%.

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Answer:

any gas takes up 22.4L per mole so 2.4*22.4=53.76

Explanation:

In 2.4 moles at STP, 53.79 litres of N2 gas are present.

Moles are defined as the amount of substance of a system that contain the same number of entities as the number of atoms in 12g of carbon 12.

STP is defined as the standard temperature and pressure. At STP, as system has s temperature of zero degree centigrade or 273 Kelvin and the pressure is 1 atm.

PV= nRT

P= 1 atm

V= ?

n= 2.4 moles

R= 0.0821 L atm /K/mol

1 x V = 2.4 x 0.0821 x 273

V = 53.79 litres

Hence, 53.79 litres of N2 gas is present in 2.4 moles at STP.

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