Simplify the expression 713t−(1023t−6)

Answer:9

Step-by-step explanation:

basically what you do is 1equal 1 divided by 8 2 68 equals one so yea

Answer: 6.5 cm

Step-by-step explanation:

1 km= 1000000 cm

130 km / 2,000,000 = 6.5

Answer: D

Step-by-step explanation:

Domain is x and Range is y

When solving proportions, we set the cross products equal, and then we solve for the unknown variable.

When solving proportions, we set the cross products equal to each other and then proceed to solve for the unknown variable. A proportion is an equation that states that two ratios or fractions are equal. To solve a proportion, we first identify the two ratios involved and set their cross-products equal.

For example, consider the proportion: a/b = c/d

To solve for the unknown variable, we set the cross products (a * d) and (b * c) equal:

a * d = b * c

This equation allows us to find the value of the unknown variable by manipulating the equation through multiplication or division to isolate the variable on one side of the equation.

By setting the cross products equal, we essentially establish an equality between the two ratios, indicating that the fractions on either side of the proportion are equivalent. Solving for the unknown variable allows us to determine its value based on the relationship between the given ratios.

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a) No, a single spray of 10 grams of butter would not be enough to entirely cover the area of 4 slices of toast at 2 meters. The area of 4 slices of toast is larger than the area of 1 slice of toast, meaning that it would require more butter than 10 grams to cover the entire area.

b) A single spray of 10 grams of butter would be enough to cover the area of 8 slices of toast at 3 meters.

c) These changes would affect the amount of butter on each piece of toast in that there would be more butter on each piece with a larger rack and further distance from the "butter gun".

d) At 5 meters from the gun, our up-and-coming chef would be able to spray 16 slices of toast with a single burst of 10 grams of butter. Each piece of toast would also have more butter than it would if it was sprayed at a closer distance.

e) To duplicate the original single-slice toast at 5 meters from the gun, the chef would need to reduce the amount of butter being sprayed. He could do this by simply reducing the distance between the gun and the toast rack.

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Complete question :

A harried chef can't keep up with his breakfast orders and decides to automate the process with a "butter gun." The gun provides a 10 gram burst of butter spray with each hit of the trigger. He starts with a rack that holds one piece of toast 1 meter away. The demand again exceeds supply and he realizes he can use the same gun to produce more toast by placing a larger rack at a greater distance. He finds that a four-slice rack works at a distance of 2 meters. Pleased with profits he carries the idea a step further and puts a holder 3 meters away, maintaining a 10 gram spray. See figure below.a) If 1 spray entirely covers the area of a single slice at 1 meter, can it entirely cover the area of 4 slices at 2 meters? Why or why not?b) How many slices can one spray cover with a 3 meter arragnement?c) How do these changes affect the amount of butter on each piece of toastd) Our up-and-coming chef moves the fun back to 5 meters. Predict how much toast he can spray and how much better each piece gets.e) Explain how he could duplicate the original single-slice toast at 5 meters from the gun.

When a nonlinear system of equations contains one linear function that touches the quadratic function at its maximum, then the system has one solution

A system of equations is considered nonlinear if it contains at least one nonlinear equation. One linear function in a nonlinear system of equations touches the quadratic function at maximum. It illustrates one solution.

The given system of equation is presented as follows;

Linear function: f(x) = mx + c

Quadratic function: f(x) = ax² + bx + c

It should be noted that given that the linear function touches the quadratic function at maximum we have;

ax² + bx + c = 0

Therefore, if a nonlinear system of equations contains one linear function that touches the quadratic function at its maximum has one solution.

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Answer:

We know that the distance between Paris and Nice is about 920,000 meters. To convert this distance to kilometers we divide by 1000: 920,000/1000= 920 kilometers

We also know that the train travels at a speed of 230 kilometers per hour. To find out how long it will take Lola to travel from Paris to Nice, we divide the distance by the speed:

920/230 = 4 hours

So it will take Lola 4 hours to travel from Paris to Nice by train.

Answer: 4 hours actually kinda ez not gonna lie

Step-by-step explanation: 230 kilometers = 230000 meters. 230 * 1000 = 230000. Distance / speed = time. 920000/230000 = T(as in time). T = 4

To identify the surface, we first need to eliminate the parameters u and v from the vector-valued function r(u, v) = ui + vj + v/2k. This plane intersects the yz-plane along the line y = 2z, and extends infinitely in the x-direction.

r(u, v) =  We can rewrite the components of the vector as follows:
x = u
y = v
z = v/2
Now, to eliminate the parameters, we can simply express v in terms of z:
v = 2z
Thus, the rectangular equation for the surface is given by:
x = u
y = 2z
b) To sketch the graph of the surface, we can plot the equation in the xyz-coordinate system. Since x = u and y = 2z, we see that the surface is a plane. The equation y = 2z describes the plane where x can take any value, and the y-coordinate is twice the z-coordinate at any point on the plane. This plane intersects the yz-plane along the line y = 2z, and extends infinitely in the x-direction.

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Answer:

10651.7 gallons

Step-by-step explanation:

The probability that a woman was wearing a belt given that she was also carrying a purse is 0.333 or 33.3%.

To find the probability that a woman was wearing a belt given that she was also carrying a purse, we need to use conditional probability.

We know that out of the 30 women observed, 18 were carrying purses and 6 were both carrying purses and wearing belts.

This means that the number of women carrying purses who were also wearing belts is 6.
Therefore, the probability that a woman was wearing a belt given that she was also carrying a purse is:
P(wearing a belt | carrying a purse) = number of women wearing a belt and carrying a purse / number of women carrying a purse
P(wearing a belt | carrying a purse) = 6 / 18
P(wearing a belt | carrying a purse) = 0.333
Given the information provided, we can determine the probability of a woman wearing a belt, given that she is also carrying a purse.

First, we need to find the number of women carrying a purse and wearing a belt, which is 6. There are 18 women carrying purses in total.
So, to find the probability, we will use the formula:
P(Belt | Purse) = (Number of women wearing belts and carrying purses) / (Number of women carrying purses)
P(Belt | Purse) = 6 / 18
P(Belt | Purse) = 1/3 or approximately 0.33
Therefore, the probability that a woman was wearing a belt, given that she was also carrying a purse, is 1/3 or approximately 0.33.

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Caleb can choose which 20 items to buy in 1140 ways if he wants all 3 cheeses.

To choose 20 items at the grocery store, Caleb has narrowed down his selections to 5 vegetables, 8 fruits, 3 cheeses, and 7 whole grain breads. Since he wants all 3 cheeses, he only needs to choose 17 more items.

The number of ways he can choose these 17 items from the remaining vegetables, fruits, and breads is given by the combination: C(5+8+7, 17) = C(20, 17) = 1140.

This formula means that there are 20 items to choose from, and Caleb wants to choose 17. The order doesn't matter, so we use a combination.

Therefore, Caleb can choose which 20 items to buy in 1140 ways if he wants all 3 cheeses.

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Answer:

Yes

Step-by-step explanation:

Answer: True.

By definition, a stochastic matrix is a square matrix where each entry is a non-negative real number and the sum of each row is 1.

If A is a stochastic matrix and v is a vector in its 1-eigenspace, then we have:

Av = λv

where λ = 1 is the corresponding eigenvalue.

Multiplying both sides by 1/λ = 1, we get:

v = A v

This means that the vector v is also in the range of A, which is a subspace of the vector space R^n.

Since A is a stochastic matrix, the rows of A sum to 1, and therefore the columns of A also sum to 1. This implies that the vector of all 1's, which we denote by u, is also in the range of A.

Since v is a nonzero vector in the 1-eigenspace and u is a nonzero vector in the range of A, the span of v and u is a two-dimensional subspace of R^n.

Moreover, since A is a stochastic matrix, we have:

Au = u

This means that the vector u is also in the 1-eigenspace.

Therefore, the 1-eigenspace of A is a line spanned by the vector u, which is a nonzero vector in the range of A.

if a is a stochastic matrix, then its 1-eigenspace must be a line: True.


A stochastic matrix is a square matrix with non-negative entries where each row sums to one. The 1-eigenspace of a matrix is the set of all eigenvectors with eigenvalue 1.

Let v be an eigenvector of a stochastic matrix A with eigenvalue 1. Then we have Av = 1v.

Multiplying both sides by the transpose of v, we get v^T Av = v^T v.

Since A is a stochastic matrix, its columns sum to 1 and therefore, its transpose has rows that sum to 1. Thus, v^T Av = 1 and v^T v = 1.

This implies that v^T (A-I) = 0, where I is the identity matrix. Since A is stochastic, I is also stochastic and has a unique 1-eigenspace, which is a line spanned by the vector (1,1,....1)^T.

Therefore, v must be a scalar multiple of (1,1,....1)^T, which implies that the 1-eigenspace of A is a line.

Therefore, the statement "if a is a stochastic matrix, then its 1-eigenspace must be a line" is true.

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DNE in each coordinate of the ordered triplet are y is -7 , DNE ,y is-2.

1.) 2+3 = y + 12

Make y the formula's subject after adding the LHS.

5 = y + 12

Y = 5 - 12

Y = - 7

The answer to the equation is -7

2.) 2 + 13 = 1 +8

The equation cannot have a solution since there is no unknown variable and the sum of the numbers on the left hand side (LHS) does not equal the sum of the numbers on the right hand side (RHS).

3.) y - 7 = 2 - 11

RHS is added, and y is become the formula's subject.

Y - 7 = -9

Y = -9 + 7

Y = -2

The equation's answer is -2.

The complete question is:Solve the following system of equations. If there is no solution, write DNE in each coordinate of theordered triplet. If there are an infinite number of solution, write each coordinate in terms of z.2+3 = y + 12

2 + 13 = 1 +8

y - 7 = 2 - 11

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Answer:

\(\frac{1}{2}\)

Step-by-step explanation:

The computation show that the next number based on the information will be 588886.

From the information given, the numbers are illustrated as:

2x9-2=16

32x9-2=286

432x9-2=3886

5432x9-2=4888

It should be noted that the next number will be:

(65432 × 9) - 2

= 588888 - 2

= 588886

Therefore, it can be seen that the next number based on the information is 588886.

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Answer:

1-B
2-E

3-D

4-A

5-C

Step-by-step explanation:

-4x + 3y = 3

3y = 4y + 3

y = 4/3 y + 1 => slope is 4/3, y-intercept is (0,1)

Equation 1 matches with Letter B

12x - 4y = 8

4y = 12x - 8

y = 3x - 2 => slope is 3, y-intercept is (0,-2)

Equation 2 matches with Letter E

8x + 2y = 16

2y = -8x + 16

y = -4x + 8 => slope is -4, y-intercept is (0,8)

Equation 3 matches with Letter D

-x + 1/3 y = 1/3

1/3 y = x + 1/3

y = 3x + 1 => slope is 3, y-intercept is (0,1)

Equation 4 matches with Letter A

-4x + 3y = -6

3y = 4x = -6

y = 4/3 x - 2 => slope is 4/3, y-intercept is (0,-2)

Equation 5 matches with Letter C

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To prove that the order of u(n) is even when n > 2, we can use Corollary 2 of Lagrange's theorem (Theorem 7.1). Corollary 2 states that if G is a group and a is an element of G of finite order, then the order of a divides the order of G.

Let's consider the group G = U(n), the multiplicative group of integers modulo n, and let a = u(n), an element of G. We want to show that the order of a is even when n > 2.

By definition, the order of an element a in a group is the smallest positive integer k such that a^k = e, where e is the identity element of the group.

Since a = u(n), we have a^n ≡ 1 (mod n) by Euler's theorem. This implies that a^n - 1 is divisible by n.

Now, let's consider the order of a. Assume the order of a is odd, i.e., k is an odd positive integer such that a^k = e. This implies that a^(2k) = (a^k)^2 = e^2 = e.

Since k is odd, 2k is even. Therefore, we have found a positive integer (2k) such that a^(2k) = e, contradicting the assumption that k is the smallest positive integer satisfying a^k = e. Thus, the order of a cannot be odd.

By Corollary 2 of Lagrange's theorem, the order of a divides the order of G. Since n > 2, the order of G is even (it contains the identity element and at least one non-identity element). Therefore, the order of a (u(n)) must also be even.

Hence, we have proven that the order of u(n) is even when n > 2 using Corollary 2 of Lagrange's theorem.

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It would take 5040 cubic inches of water to completely fill the aquarium.

We know that the formula for the volume of cuboid :

V = length × width × height

Let us assume that l represents the length of the aquarium, w represent the width and h represents the height.

Here, l = 20 inches

w = 14 inches

and h = 18 inches

Using the formula for the volume of cuboid, the volume of aquarium would be,

V = l × w × h

V = 20 × 14 × 18

V = 5040 cu.in.

Therefore, it would take 5040 cu.in. of water.

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Therefore, The double integral of 2 over the cylinder is 320π.

I understand you need help calculating a double integral over a cylinder with given parameters. To do so, let's follow these steps:
1. Set up the integral: Since the cylinder is described by the equation x^2 + y^2 = 16 (radius of 4) and has a height of 5 (0 ≤ z ≤ 5), we can use cylindrical coordinates. Let x = 4cos(θ) and y = 4sin(θ), where 0 ≤ θ ≤ 2π. The Jacobian for cylindrical coordinates is 4 in this case.
2. Transform the integral: ∬2 dxdydz = ∬2(4) dzdθdr, with limits 0 ≤ z ≤ 5, 0 ≤ θ ≤ 2π, and 0 ≤ r ≤ 4.
3. Evaluate the integral: First, integrate with respect to z: ∬8 dzdθdr = 8∬(z) |(from 0 to 5) dθdr = 8∬(5 - 0) dθdr = 40∬ dθdr.
Next, integrate with respect to θ: 40∫(θ) |(from 0 to 2π) dr = 80π∫ dr.
Finally, integrate with respect to r: 80π(r) |(from 0 to 4) = 80π(4 - 0) = 320π.

Therefore, The double integral of 2 over the cylinder is 320π.

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Answer:

The answer to your question is 3

Step-by-step explanation:

2 + 7 = 9

9÷3 = 3

John's savings amount as a function of time is S(t) = $24,000 / 25. Initially, he needs to save $24,000 for a new car. After the first month, he has saved $1,000. The savings amount is directly proportional to the time elapsed. The constant of proportionality is 1/24. Thus, John's savings amount can be determined based on the remaining amount he needs to save.

John's savings amount can be represented as a function of time and is proportional to the amount he still needs to save. Let's denote the amount John needs to save as N(t) at time t, and his savings amount as S(t) at time t. Initially, John needs to save $24,000, so we have N(0) = $24,000.

We know that John has saved $1,000 after the first month, which means S(1) = $1,000. Since his savings amount is proportional to the amount he still needs to save, we can write the proportionality as:

S(t) = k * N(t)

where k is a constant of proportionality.

We need to find the value of k to determine John's savings amount at any given time.

Using the initial values, we can substitute t = 0 and t = 1 into the equation above:

S(0) = k * N(0)  =>  $1,000 = k * $24,000  =>  k = 1/24

Now we have the value of k, and we can write John's savings amount as a function of time:

S(t) = (1/24) * N(t)

Since John's savings amount is proportional to the amount he still needs to save, we can express the amount he still needs to save at time t as:

N(t) = $24,000 - S(t)

Substituting the expression for N(t) into the equation for S(t), we get:

S(t) = (1/24) * ($24,000 - S(t))

Simplifying the equation, we have:

24S(t) = $24,000 - S(t)

25S(t) = $24,000

S(t) = $24,000 / 25

Therefore, John's savings amount at any given time t is S(t) = $24,000 / 25.

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Answer:

-43

Step-by-step explanation:

m=8, n=11, and p=-3

mp=8x-3=-24

-24-m=-24-8=-32

-32-n=-32-11=-43

Answer:

The number 540 has the following divisors

1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 27, 30, 36, 45, 54, 60, 90, 108, 135, 180, 270, 540

Step-by-step explanation:

The number 540 has the following divisors

1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 27, 30, 36, 45, 54, 60, 90, 108, 135, 180, 270, 540

Therefore, the number 540 is not a prime number or a deficient number

A deficient number is one that is larger than the sum total of its possible dividing numbers less the number 540 itself that is we have;

1+ 2+ 3+ 4+ 5+ 6+ 9+ 10+ 12+ 15+ 18+ 20+ 27+ 30+ 36+ 45+ 54+ 60+ 90+ 108+ 135+ 180+ 270 = 1140.

Answer:

\(540 = 3 ^{3} \times 2 {}^{2} \times 5\)

so, it is 4*3*2= 24

The theoretical probability of getting 4 or more tails: 0.3438

Histogram and Probability of Getting 4 or More Tails

To visualize the probability distribution, we can create a histogram where the x-axis represents the number of tails (X) and the y-axis represents the corresponding probabilities. The histogram will have bars for each possible value of X (0 to 6) with heights proportional to their probabilities.

Let's denote "T" as a success (getting tails) and "H" as a failure (getting heads) in each coin flip.

Probability of getting 0 tails (all heads):

P(X = 0) = (1/2)^6 = 1/64 ≈ 0.0156

Probability of getting 1 tail:

P(X = 1) = 6C1 * (1/2)^1 * (1/2)^5 = 6/64 ≈ 0.0938

Probability of getting 2 tails:

P(X = 2) = 6C2 * (1/2)^2 * (1/2)^4 = 15/64 ≈ 0.2344

Probability of getting 3 tails:

P(X = 3) = 6C3 * (1/2)^3 * (1/2)^3 = 20/64 ≈ 0.3125

Probability of getting 4 tails:

P(X = 4) = 6C4 * (1/2)^4 * (1/2)^2 = 15/64 ≈ 0.2344

Probability of getting 5 tails:

P(X = 5) = 6C5 * (1/2)^5 * (1/2)^1 = 6/64 ≈ 0.0938

Probability of getting 6 tails:

P(X = 6) = (1/2)^6 = 1/64 ≈ 0.0156

Observing the histogram, we can see that the probability of getting 4 or more tails is the sum of the probabilities for X = 4, 5, and 6:

P(X ≥ 4) = P(X = 4) + P(X = 5) + P(X = 6)

≈ 0.2344 + 0.0938 + 0.0156

≈ 0.3438

Therefore, the theoretical probability of getting 4 or more tails in the binomial experiment is approximately 0.3438.

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Answer:

6.257x(10−7)

=0.000001x

4.25x(105)

=4.25*x*100000

=425000*x

=425000x

Step-by-step explanation:

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Answer:

The correct option is Option C

Step-by-step explanation:

We are given the lines: \(y=-\frac{4}{5}x+2 \ and \ \ y=-\frac{5}{4}x-\frac{1}{2}\)

The lines are perpendicular if they have opposite slopes i,e \(m_1=-\frac{1}{m_2}\)

In line 1 the slope is \(-\frac{4}{5}\) (Comparing with slope-intercept form \(y=mx+b\) we get the value of m=-4/5)

In line 2 the slope is \(-\frac{5}{4}\) (Comparing with slope-intercept form \(y=mx+b\) we get the value of m=-5/4)

The opposite reciprocal of -4/5 is 5/4  

So, the lines are not perpendicular as their slopes are not opposite reciprocal of each other.

If the lines are parallel there slope must be same. Hence lines are not parallel as well.

So, The correct option is Option C

Answer:

c

Step-by-step explanation:

Answer:

Step-by-step explanation:

➊ To find the smallest number, let us consider the three consecutive numbers be x, x + 1, and x + 2.

Given :

According to the question,

↦ x + x + 1 + x + 2 = 18

↦ 3x + 3 = 18

↦ 3x = 18 - 3

↦ 3x = 15

↦ x = 15/3

➦ x = 5

∴ Hence, the required value of x is 5.

➋ Now we have the value of x. So, by putting the value of x in the assumed numbers we will find out the numbers and then check which is the smallest number.

➲ First number = x = 5.

➲ Second number = x + 1 = 5 + 1 = 6.

➲ Third number = x + 2 = 5 + 2 = 7.

∴ Hence, the smallest number is 5.

✻ Verification ✻

↦ x + x + 1 + x + 2 = 18

Putting x = 5 we get,

↦ 5 + 5 + 1 + 5 + 2 = 18

↦ 5 + 6 + 7 = 18

↦ 18 = 18

➦ LHS = RHS

∴ Hence, Verified ✔

Answer:

a

Step-by-step explanation:

When there is no decomposition, the plant is deficient in minerals.