Sara reduced the time it takes her to run a mile from 12 minutes to 8 minutes. Which is closest to Sara's


percent decrease in the time it takes her to run a mile?



A. 14%


B. 25%


C. 33%


D. 75%

Given :

Number of raspberry scones with Bryson = 51

Number of blueberry scones with Bryson = 34

To find the greatest number of bags Bryson can fill with equal number of raspberry and blueberry cones each, we need to find the GCF of the number of blueberry scones and raspberry scones.

Factors of 34 = 1, 2, 17, 34

Factors of 51 = 1, 3, 17, 51

Greatest common factor (GCF) of 34 and 51 = 17

Therefore, the greatest number of bags Bryson can fill with equal number of blueberry scones and raspberry scones = 17 bags

Answer:

the answer is -1

Step-by-step explanation:

2-3=-1

2-1=1

-1x=1

x=-1

-1*-1=1

The algebraic expression for "The product of 9 and two more than a number" is 9(x + 2).

In the given word phrase, "a number" is represented by the variable x. The phrase "two more than a number" can be translated as x + 2 since we add 2 to the number x. The phrase "the product of 9 and two more than a number" indicates that we need to multiply 9 by the value obtained from x + 2. Therefore, the algebraic expression for this word phrase is 9(x + 2).

"A number": This is represented by the variable x, which can take any value.

"Two more than a number": This means adding 2 to the number represented by x. So, we have x + 2.

"The product of 9 and two more than a number": This indicates that we need to multiply 9 by the value obtained from step 2, which is x + 2. Therefore, the algebraic expression becomes 9(x + 2).

In summary, the phrase "The product of 9 and two more than a number" can be algebraically expressed as 9(x + 2), where x represents the number.

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The test statistic for this sample and the p-value for this sample is  t = 0.467.

Given:

sample of size n=305

M=83.6

SD=14.9.

Significance level of α = 0.001 . H o : μ = 82.4 H a : μ ≠ 82.4

To find the Test statistic

\(test=\frac{\bar x-\mu}{\frac{s.t}{\sqrt{n} } }\)

    \(=\frac{82.4.6-83.6}{\frac{14.9}{\sqrt{305} } }\)

     \(0.467\)

P-value:

With t = 0.467.

p-value = (1 - 0.467)

0.533 > 0.001

So, fail to reject H₀

Therefore, the failing to reject the Null Hypothesis.

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If a machine operator can program machine #1 to produce 100 parts per hour, but the machine requires 2 hours of service each day when it is not operating and machine #2 can produce only 80 parts per hour, but only requires 30 minutes of service each day, then both the machines are equal in productivity in an eight hour work day.

To determine which machine is more productive in an eight hour work day, an algebraic expression can be used.

x = y ( 8 hours - s )

Here, x = to the parts produced in an eight hour work day

y = parts produced per hour

s = service hours

Thus, the parts produced by both the machines in an eight hours work day can be calculated using this algebraic expression as follows,

For Machine #1:

y = 100 and s = 2

x = 100 ( 6 )

x = 600

Machine #2:

y = 80 and s = 0.5

x = 80 ( 8 - 0.5 )

x = 80 ( 7.5 )

x = 600

Hence, both machines are equally productive in an eight hour work day.

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so hmmm tripling $380 we end up with $1140, now, since 7/8 is 0.875, that means that Layla's rate is 5.875, whilst Brandon's is 6.125.

\(~~~~~~ \stackrel{ \textit{\LARGE Layla}}{\textit{Compound Interest Earned Amount}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$ 1140\\ P=\textit{original amount deposited}\dotfill &\$380\\ r=rate\to 5.875\%\to \frac{5.875}{100}\dotfill &0.05875\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years \end{cases}\)

\(1140 = 380\left(1+\frac{0.05875}{4}\right)^{4\cdot t} \implies \cfrac{1140}{380}=1.0146875^{4t} \\\\\\ 3=1.0146875^{4t}\implies \log(3)=\log(1.0146875^{4t}) \\\\\\ \log(3)=t\log(1.0146875^{4})\implies \cfrac{\log(3)}{\log(1.0146875^{4})}=t\implies \boxed{18.84\approx t} \\\\[-0.35em] ~\dotfill\)

\(~~~~~~ \stackrel{ \textit{\LARGE Brandon}}{\textit{Compound Interest Earned Amount}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$ 1140\\ P=\textit{original amount deposited}\dotfill &\$380\\ r=rate\to 6.125\%\to \frac{6.125}{100}\dotfill &0.06125\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years \end{cases}\)

\(1140 = 380\left(1+\frac{0.06125}{12}\right)^{12\cdot t} \implies \cfrac{1140}{380}=\left( \cfrac{9649}{9600} \right)^{12t}\implies 3=\left( \cfrac{9649}{9600} \right)^{12t} \\\\\\ \log(3)=\log\left[ \left( \cfrac{9649}{9600} \right)^{12t} \right]\implies \log(3)=t\log\left[ \left( \cfrac{9649}{9600} \right)^{12} \right]\)

\(\cfrac{\log(3)}{ ~~ \log\left[ \left( \frac{9649}{9600} \right)^{12} \right] ~~ }=t\implies \boxed{17.98\approx t} \\\\[-0.35em] ~\dotfill\\\\ 18.84~~ - ~~17.98 ~~ \approx ~~ \text{\LARGE 0.86}\)

We have the following:

replacing:

Answer:

the answer is false. you first multiply the number by the numerator then add it to the denominator

Answer: B

Step-by-step explanation:

4.32 is closest to 4.3.

Hope this helped!

the probability of obtaining a sample mean within 500 of the population mean is approximately 0.6827.

To solve this problem, we need to use the central limit theorem which states that the distribution of the sample means will be approximately normal with mean equal to the population mean and standard deviation equal to the population standard deviation divided by the square root of the sample size.

Given that the population mean is 51800 and the population standard deviation is 4000, we can calculate the standard error of the mean as follows:

Standard error of the mean = 4000 / sqrt(64) = 500

We want to find the probability of obtaining a sample mean within 500 of the population mean. This can be written as:

P(51800 - 500 < X < 51800 + 500)

where X is the sample mean.

We can standardize this interval using the standard error of the mean:

P(-1 < Z < 1)

where Z is a standard normal variable.

Using a standard normal table, we find that the probability of Z being between -1 and 1 is approximately 0.6827.

Therefore, the probability of obtaining a sample mean within 500 of the population mean is approximately 0.6827.

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predicted value of the slope , A regression model called simple linear regression uses a straight line to calculate the association between one independent variable and one dependent variable.

When modeling the relationship between a scalar answer and one or more explanatory variables in statistics, linear regression is a linear method. Simple linear regression is used when there is only one explanatory variable, and multiple linear regression is used when there are numerous variables.

A regression model called simple linear regression uses a straight line to calculate the association between one independent variable and one dependent variable. Both variables ought to have numerical values.

When the parameters are linear, a regression equation (or function) is said to be linear in statistics. Although the predictor variables can be transformed in ways that result in curvature, the equation must be linear in the parameters.

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in linear regression, the fitted value is the:  predicted value of the dependent variable

When you enter the values of the predictors, factor levels, and other inputs into a statistical model, the predicted mean response value is known as the fitted value.

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The albedo (a)in this case is approximately 0.4231.

To compute the albedo (a), we need to understand the terms given.

Albedo is the measure of reflectivity of a surface, expressed as the ratio of the reflected solar radiation (st) to the incoming solar radiation (51).

Here, 51 = 650 W/m² represents the total solar radiation, and st = 275 W/m² represents the reflected solar radiation.

Additionally, L1 = 94 W/m² and L1 = 395 W/m² seem to be irrelevant to the calculation of albedo, as they don't represent incoming or reflected solar radiation.

Therefore, we can disregard these terms for this calculation.

Now, we can calculate the albedo (a) using the formula:

a = (reflected solar radiation) / (incoming solar radiation) a = (st) / (51)

By substituting the given values:

a = (275 W/m²) / (650 W/m²) a ≈ 0.4231

Remember, albedo values range from 0 to 1, where 0 indicates no reflectivity and 1 indicates total reflectivity.

In this case, just provide the numerical value as the answer: 0.4231

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Kalil ate apprοximately 6.67 hοt dοgs per minute during the cοntest.

An equatiοn cοmbines twο expressiοns cοnnected by an equal sign (“=”). These twο expressiοns οn either side οf the equals sign are called the “left-hand side” and “right-hand side” οf the equatiοn. We generally assume the right-hand side οf an equatiοn is zerο. This will nοt reduce the generality since we can balance this by subtracting the right-hand side expressiοn frοm bοth sides’ expressiοns.

Tο find οut hοw many hοt dοgs Kalil ate per minute, we need tο first cοnvert the time tο minutes.

2 minutes and 15 secοnds can be written as 2 + 15/60 = 2.25 minutes.

Then, we can divide the number οf hοt dοgs by the number οf minutes:

15 hοt dοgs ÷ 2.25 minutes = 6.67 hοt dοgs per minute (rοunded tο twο decimal places)

Therefοre, Kalil ate apprοximately 6.67 hοt dοgs per minute during the cοntest.

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Answer:

D

Step-by-step explanation:

Prime factorize 60

\(\sqrt{60}=\sqrt{2*2*3*5}=2\sqrt{3*5}=2\sqrt{15}\)

The expected value of the discrete distribution is given by:

µ = 2.36

It is given by the sum of each value multiplied by it's respective probability.

In this problem, the distribution is as follows, considering the amounts of each chip:

P(X = 1) = 2/11

P(X = 2) = 3/11

P(X = 3) = 6/11

Hence, the expected value is given by:

\(\mu = \frac{2}{11} + 2\frac{3}{11} + 3\frac{6}{11} = \frac{2 + 6 + 18}{11} = 2.36\)

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Answer:

85.9 cm^3

Step-by-step explanation:

The formula for the volume of a regular tetrahedron is a^3 / (6 sqrt2)

If we plug in 9 for a, we have

9^3 / (6 sqrt2) = 85.9 cm^3

Step-by-step explanation:

v = u + at

v-u = at

a = (v -u)/t

When t = 4, u=10, v=50

a = (50-10)/4

a= 40/4

a = 10

The data value of 9770 corresponds to the 41st percentile if the mean population is 10000 and the standard deviation is 1000.

An equation is an expression that shows the relationship between two or more variables and numbers.

The z score is given by:

z = (raw score - mean)/standard deviation

Let us assume the mean population is 10000 and the standard deviation is 1000.

The 41st percentile corresponds with a z score of -0.23, hence:

-0.23 = (x - 10000)/1000

x = 9770

The data value of 9770 corresponds to the 41st percentile if the mean population is 10000 and the standard deviation is 1000.

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Answer:

6 Apples

Step-by-step explanation:

There would be six apples and 2 oranges left over.

Hope this Helps!

:D

Answer:

I was kind of confused on this one but is it 15 apples?

Step-by-step explanation:

3, 6, 9, 12, 15

4, 8, 12, 16, 20

I think the answer is 15 apples.

Answer:

144 in^2

Step-by-step explanation:

Using the A = s^2 and the text says that s= 12in

 the answer is 12 in * 12 in = 144 in^2

Answer:

blue

Step-by-step explanation:

love the sky

Answer:

Pink

Step-by-step explanation:

Because it’s pretty and makes me feel at ease

Por lo tanto, la tasa de disminución de la temperatura en grados Celsius por día debe ser menor o igual a 10/3 para que la piscina esté abierta el jueves.

Para resolver este problema, necesitamos utilizar la siguiente fórmula:

Temperatura final = Temperatura inicial - tasa de disminución x días

Sea x la tasa de disminución en grados Celsius por día. Entonces, la temperatura alta el jueves fue:

30 - x(3)

Como se menciona en el problema, la piscina está abierta cuando la temperatura alta es mayor de 20 ∘ C20, degrees, start text, C, end text. Por lo tanto, la temperatura alta el jueves debe ser mayor o igual que 20 ∘ C20, degrees, start text, C, end text. Entonces, tenemos la siguiente desigualdad:

30 - x(3) ≥ 20

Resolviendo para x, obtenemos:

x ≤ 10/3

Por lo tanto, la tasa de disminución de la temperatura en grados Celsius por día debe ser menor o igual a 10/3 para que la piscina esté abierta el jueves.

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The total area of the composite figure is 258 squared centimeters.

The figure in the diagram is composed of two triangle and a rectangle?

The area of a triangle = 1/2 × base × height

Area of a rectangle = length × width

From the diagram;

Triangle 1

Triangle 2

Rectangle

To find the area of the composite figure, we find the area of the two triangle and rectangle and add.

Area = area of triangle 1 + area of triangle 2 + area of rectangle.

Area = ( 1/2 × base × height ) + ( 1/2 × base × height ) + ( length × width )

Area = ( 1/2 × 4 × 12 ) + ( 1/2 × 12 × 3 ) + ( 18 × 12 )

Area = ( 2 × 12 ) + ( 6 × 3 ) + ( 18 × 12 )

Area = 24 + 18 + 216

Area = 258cm²

Therefore, the area is 258 squared centimeters.

Option C) 258cm² is the correct answer.

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Answer:

258cm^2

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

7^2 is 49-8x2 what is 16-16you get 49-16-16 what equals 17  so ur answer is D

The area of the circle with the radius is 192 square feet

The figure represents the given parameter

On the figure, we have the radius (r) to be

r = 8 ft

The area of a circle is calculated as

A = πr^2

Where π is given as

π = 3

So, we have

A = 3 * 8^2

Evaluate the exponent

A = 3 * 64

Evaluate the product

A = 192

Hence, the area of the circle with the radius is 192 square feet

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the area of the circle is 201.06

Answer:

25x^6

Step-by-step explanation:

:)