Question 2
What is the length of DE? (number only)

Answer:

2x^2 - 6x + 7 - (5x^2 + 2x - 8)

Distributive a -1 to each term in the parentheses.

2x^2 - 6x + 7 - 5x^2 - 2x + 8

Combine like terms.

-3x^2 - 8x + 15 is the expression after being subtracted.

Answer:

Step-by-step explanation:

(2x² − 6x + 7) − (5x²  + 2x +8)

To find the opposite of 5x²  + 2x + 8, find the opposite of each term.

2x²  − 6x + 7 − 5x²  − 2x − 8

Combine 2x²  and −5x²  to get −3x²

−3x²  − 6x + 7 − 2x − 8

Combine −6x and −2x to get −8x.

−3x² − 8x + 7 − 8

Subtract 8 from 7 to get −1.

−3x² − 8x − 1

The tree is approximately 12 feet tall to the nearest tenth of a foot.

We have,

To find the height of the tree, we can set up a proportion using the measurements of the shadow.

Since we know that Tyler is 6 feet tall and his shadow is 10 ½ feet long, we can set up the following expression:

Tyler's height / Tyler's shadow length = Tree's height / Tree's shadow length

6 feet / 10.5 feet = Tree's height / 21 feet

To find the tree's height, we can cross-multiply and solve for it:

6 feet x 21 feet = 10.5 feet x Tree's height

126 feet = 10.5 feet x Tree's height

Dividing both sides of the expression by 10.5 feet:

126 feet / 10.5 feet = Tree's height

12 feet = Tree's height

Therefore,

The tree is approximately 12 feet tall to the nearest tenth of a foot.

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Answer:

700

Step-by-step explanation:

The correct answer is John's weekly salary is $240 based on his hourly pay rate and the number of hours worked.

Let's choose the function "Weekly salary is a function of the hourly pay rate and the number of hours worked."Example: John works as a part-time employee at a grocery store. His hourly pay rate is $12, and he worked for 20 hours in a week. We can evaluate the function to find his weekly salary.

Weekly salary = Hourly pay rate * Number of hours worked

Weekly salary = $12/hour * 20 hours

Weekly salary = $240

So, John's weekly salary is $240 based on his hourly pay rate and the number of hours worked.

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Answer:

Step-by-step explanation:

In the Intermediate Phase of mathematics education, one topic that demonstrates a hierarchical and logical progression in patterns, functions, and algebra is the concept of "Linear Equations."

The topic of Linear Equations in the Intermediate Phase builds upon the foundation laid in earlier grades and serves as a stepping stone towards more advanced algebraic concepts. Here is an overview of the topic sequence and content area spread for Linear Equations:

Introduction to Variables and Expressions:

Students are introduced to the concept of variables and expressions, learning to represent unknown quantities using letters or symbols. They understand the difference between constants and variables and learn to evaluate expressions.

Solving One-Step Equations:

Students learn how to solve simple one-step equations involving addition, subtraction, multiplication, and division. They develop the skills to isolate the variable and find its value.

Solving Two-Step Equations:

Building upon the previous knowledge, students progress to solving two-step equations. They learn to perform multiple operations to isolate the variable and find its value.

Writing and Graphing Linear Equations:

Students explore the relationship between variables and learn to write linear equations in slope-intercept form (y = mx + b). They understand the meaning of slope and y-intercept and how they relate to the graph of a line.

Systems of Linear Equations:

Students are introduced to the concept of systems of linear equations, where multiple equations are solved simultaneously. They learn various methods such as substitution, elimination, and graphing to find the solution to the system.

Word Problems and Applications:

Students apply their understanding of linear equations to solve real-life word problems and situations. They learn to translate verbal descriptions into algebraic equations and solve them to find the unknown quantities.

The content area spread for Linear Equations includes concepts such as variables, expressions, equations, operations, graphing, slope, y-intercept, systems, and real-world applications. The progression from simple one-step equations to more complex systems of equations reflects a logical sequence that builds upon prior knowledge and skills.

By following this hierarchical progression, students develop a solid foundation in algebraic thinking and problem-solving skills. They learn to apply mathematical concepts and procedures in a systematic and logical manner, paving the way for further exploration of patterns, functions, and advanced algebraic topics in later phases of mathematics education.

The y-intercept is (0, 10) and the values of x that make sense are x > 0

From the question, we have the following parameters that can be used in our computation:

y = 10(2)^x

The graph is added as an attachment

This is the point of intersection with the y-axis

From the graph, it is (0, 10)

These are the values whose corresponding y values are not negative

In other words, the values are x > 0

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Answer:

The given expression does not define \(y\) as a function of \(x.\) (Answer: No)

Step-by-step explanation:

Let be \(x+9 = y^{2}\), as we have understood from mathematical reading. This function indicates that \(y^{2}\), not \(y\) is a explicit function of \(x\). The correct form is obtained by increasing each side of the formula by \(\frac{1}{2}\), that is to say:

\((x+9)^{\frac{1}{2} } = (y^{2})^{\frac{1}{2} }\)

\(y = \pm \sqrt{x+9}\)

Hence, the given expression does not define \(y\) as a function of \(x.\)

The ranking from the lowest to highest APR for the given companies is A, B, D, C.

The correct option is b.

To rank the companies from the lowest to highest Annual Percentage Rate (APR) based on a $600 loan amount, we need to calculate the APR for each company. The formula to calculate APR is APR = (Fees / Loan Amount) * (365 / Terms of Loan).

Let's calculate the APR for each company:

For Company A:

APR_A = ($60 / $600) x (365 / 18) = 0.1 x 20.28 = 2.028%

For Company B:

APR_B = ($80 / $600) x (365 / 12) = 0.1333 x 30.42 = 4.054%

For Company C:

APR_C = ($90 / $600) x (365 / 10) = 0.15 x 36.5 = 5.475%

For Company D:

APR_D = ($110 / $600) x (365 / 14) = 0.1833 x 26.07 = 4.79%

Now, we can rank the companies from the lowest to highest APR:

Company A - APR: 2.028%

Company B - APR: 4.054%

Company D - APR: 4.79%

Company C - APR: 5.475%

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The value of x is -1 which makes the model true

The equation from the given model will be 5x+6=1

We have to find the value of x

5x+6=1

Subtract 6 from both sides

5x=-5

Divide both sides by 5

x=-1

Hence, the value of x is -1 which makes the model true

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Four times a number: 4*x

Increased by five: 4*x + 5

Triple the difference of a number and two: 3*(x - 2)

Then, the equation is

4*x + 5 = 3*(x - 2)

Applying distributive property:

4*x + 5 = 3*x - 3*2

4*x + 5 = 3*x - 6

3*x is adding on the right, then it will subtract on the left

5 is adding on the left, then it will subtract on the right

4*x - 3*x = - 6 - 5

x = -11

Answer:

7s²7p⁴

Step-by-step explanation:

Livermorium is located in the seventh period and sixteenth column of the periodic table. The noble gas configuration for livermorium is [Rn]7s²5f¹⁴6d¹⁰7p⁴. The valence electrons are the ones in the orbitals with the highest quantum number (coefficient). Remember, there can be up to 8 valence electrons at one time. Therefore, the valence electron configuration is 7s²7p⁴.

Let's check

Electronic configuration

Valence electrons

Answer:

\(m_{perpendicular}\) = 6

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

x + 6y = - 24 ( subtract x from both sides )

6y = - x - 24 ( divide through by 6 )

y = - \(\frac{1}{6}\) x - 4 ← in slope- intercept form

with slope m = - \(\frac{1}{6}\)

given a line with slope m then the slope of a line perpendicular to it is

\(m_{perpendicular}\) = - \(\frac{1}{m}\) = - \(\frac{1}{-\frac{1}{6} }\) = 6

Answer:

a. 14,516.7086

b. shorter

To get the approximate height of Mountain A, we will add the height that we got earlier to 14,514 ft.

b.) Since the distance is over 100 miles away, this would create an effect that will make the peak appear shorter than it actually is.

Step-by-step explanation:

A,

because we can use the formula y=mx+c

Answer:

this question is kinda everywhere can you tell me what it is asking

Step-by-step explanation:

answer:

A' (-3,3) B' (-2,-1) C' (-6, -2)

The mean of a distribution of scores that is strongly skewed to the left is at left , the mode is located at left and median is located to left of mean.

The mean, mode, and median are measures of central tendency that describe the center of a distribution of scores.

In a strongly skewed distribution to the left, the majority of the scores are located on the left side of the distribution and there are relatively few scores on the right side. In this case:

The mean will be pulled to the left by the skewed distribution and will likely be lower than the median.

The mode, or the most frequently occurring score, will also likely be located to the left.

The median, which is the middle value when the scores are ordered, will still be a good representation of the center of the distribution, as it is not affected by extreme values. It will likely be located to the left of the mean, but closer to the center of the distribution than the mean.

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Answer:

16

Step-by-step explanation:

Answer:

27

Step-by-step explanation:

The roots of the equation t² - 3t - 36 = 0 will be 7.68 and negative 4.68.

Let the equation be ax² + bx + c = 0.

Then the roots of the equation will be

\(\rm x = \dfrac{-b \pm \sqrt{b^2 - 4 a c }}{2a}\)

The quadratic equation is given below.

t² - 3t - 36 = 0

Then the roots of the equation will be

\(\rm t = \dfrac{-(-3) \pm \sqrt {(-3)^2 - 4 \times 1 \times -36}}{2 \times 1}\)

Simplify the equation, then we have

t = [3 ± √153] / 2

t = [ 3 ± 12.37] / 2

t = (3 + 12.37) / 2, (3 - 12.37) / 2

t = 7.68, -4.68

The roots of the equation t² - 3t - 36 = 0 will be 7.68 and negative 4.68.

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The exact value of the sine of angle 78° sin(78°) is presented as follows;

\(sin(78^{\circ}) = \dfrac{\sqrt{5}-1+\sqrt{\sqrt{5}\cdot \left(6+6\cdot \sqrt{5} \right) } }{8}\)

The sine of an angle is found by taking the ratio of the opposite side to the hypotenuse side of a right triangle that has the specified angle.

The sine of angle 78° is found from the sine of the sum of two angles (60° + 18°)  as follows;

sin(78°) = sin(60° + 18°)

sin(A + B) = sin(A)·cos(B) + cos(A)·sin(B)

Therefore, sin(78°) = sin(60° + 18°)  = sin(60)·cos(18°) + cos(60°)·sin(18°)

Where, 18° = A, we have;

5·A = 90°

2·A = 90° - 3·A

sin(2·A) = sin(90° - 3·A) = cos(3·A)

2·sin(A)·cos(A) = 4·cos³(A) - 3·cos(A)

2·sin(A)·cos(A) - (4·cos³(A) - 3·cos(A)) = 0

2·sin(A) - (4·cos²(A) - 3) = 0

2·sin(A) - (4·(1 - sin²(A)) - 3) = 0

4·sin²(A) - 2·sin(A) - 1 = 0

Which gives;

\(sin(A) = \dfrac{-1\pm \sqrt{5} }{4}\)

cos²(18°) = 1 - sin²(18°)

cos(18°) = √(1 - sin²(18°))

\(cos(18^{\circ}) =\sqrt{1 - \left( \dfrac{\sqrt{5} -1 }{4}\right)^2} = \dfrac{1}{4} \cdot \sqrt{10+2\cdot \sqrt{5} }\)

\(cos(18^{\circ}) = \dfrac{1}{4} \cdot \sqrt{10+2\cdot \sqrt{5} }\)

Therefore;

\(sin(78^{\circ})=\dfrac{\sqrt{3} }{2} \cdot \left( \dfrac{1}{4} \cdot \sqrt{10+2\cdot \sqrt{5} }\right) +\dfrac{1}{2} \cdot \left( \dfrac{\sqrt{5} -1 }{4}\right)= \dfrac{\sqrt{5}-1+\sqrt{\sqrt{5}\cdot \left(6+6\cdot \sqrt{5} \right) } }{8}\)

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The sοlutiοn οf the system οf equatiοn is x = 0 and y = 7/3.

If there is nο sοlutiοn tο a system οf equatiοns, it is incοnsistent system; οtherwise, there must be at least οne sοlutiοn. If a set οf equatiοns has infinitely many sοlutiοns, it is dependent.

Every οne οf the equatiοns in a system οf equatiοns must have a sοlutiοn in οrder fοr the system tο be cοnsistent. This demοnstrates that a set οf values fοr the variables may simultaneοusly satisfy all οf the system's equatiοns and shοw that they are nοt mutually exclusive.

There is nο sοlutiοn tο an equatiοn system that satisfies all οf the equatiοns in the system. This indicates that nο cοmbinatiοn οf values fοr the variables can cοncurrently satisfy all οf the system's equatiοns since they are incοmpatible.

The given equatiοns are:

y = 2/3x + 7/3

-4x+6y=14

Substituting the value of y in the second equation:

-4x + 6y = 14

-4x + 6(2/3x + 7/3) = 14

-2x + 4x + 14 = 14

2x = 0

x = 0

Substitute the value of x = 0 we have:

y = 2/3(0) + 7/3

y = 7/3

Hence, the solution of the system of equation is x = 0 and y = 7/3.

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Complete question:

Given system of equations y = 2/3x + 7/3 and -4x + 6y = 14

Find the value of x and y.

Answer:

Angle A = tan^-1(11/5)
Angle C = 90 - tan^-1(11/5)
AC = sqrt(146)

Step-by-step explanation:

As this is a right triangle, we can apply the Pythagorean theorem a^2 + b^2 = c^2, where c is the hypotenuse while a and b are the legs, to solve for AC.

11^2 + 5^2 = AC^2

121 + 25 = AC^2

146 = AC^2

sqrt(146) = AC^2

Next, to find angle A, we can use one of the trigonometric functions. Let’s use tangent for simplicity. Tangent of an angle is “opposite divided by adjacent”. If we set the angle to A, opposite is side BC and the adjacent is side AB. Thus, tan(A) = 11/5 and tan^-1(11/5) = A.
Since the sum of angles in a triangle is 180, we can find angle C by setting up this equation: C = 180 - 90 - tan^-1(11/5), which is 90 - tan^-1(11/5)

The images best represents the result is image W.

We have, the image is rotated about the x-axis.

Now, rotating around x axis can give the other half of the image.

Also, rotating about x axis gives the mirror image of the figure.

So, the rotation leads to a circle.

and, In three dimensional we can say that Sphere.

Thus, the required image is W.

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Answer:

C. 3110=90r; 34 rooms

Step-by-step explanation:

budget: $2800 + donation: $310 = $3110

$3110 ÷ 90 (each room) = 34.5555

so.. they can get 34 rooms with some money left over

The class of the equation and the cross section equation are;

The equation is a hyperboloid of two sheets

The cross sections are;

Equation at z = 0 is; y²/8 - x²/8 = 1

Equation at y = -4 is; x²/8 + z² = 1

Equation at y = 0 is; x²/8 + z² = -1

Equation at y = 4 is; x²/8 + z² = 1

Equation at x = 0 is; y²/8 - z² = 1

An equation is a mathematical statement which indicates the equivalence two expressions by joining them with the '=' sign.

The equation can be presented as follows;

y² = x² + 8·z² + 8

y² - x² - 8·z² = 8

y²/8 - x²/8 - z² = 1

The above equation is the equation of an hyperboloid of two sheets, where;

a² = 8, b² = 1, and c² = 8

Please find attached the diagram of the surface, created with an online 3D graphing tool.

The equation for the cross section at z = 0, can be obtained by plugging in z = 0, into the equation as follows;

y²/8 - x²/8 - 0 = 1

y²/8 - x²/8 = 1

The above equation is the equation of an hyperbola in the xy plane

The equation for the cross section at y = -4, can be obtained by plugging in y = -4, into the equation as follows;

4²/8 - x²/8 - z² = 1

- x²/8 - z² = 1 - 4²/8 = -1

- x²/8 - z² = -1

x²/8 + z² = 1

The above is an equation of an ellipse in the xz plane

The equation for the cross section at y = 0, can be obtained by plugging in y = 0, into the equation as follows;

0²/8 - x²/8 - z² = 1

- x²/8 - z² = 1

Therefore; x²/8 + z² = -1

The equation for the cross section at y = 4, can be obtained by plugging in y = 4, into the equation as follows;

4²/8 - x²/8 - z² = 1

- x²/8 - z² = 1 - 2 = -1

x²/8 + z² = 1

The above equation is the equation of an ellipse in the xz plane

The equation for the cross section at x = 0, can be obtained by plugging in x = 0, into the equation as follows;

y²/8 - 0²/8 - z² = 1

y²/8 - z² = 1

The equation is the equation of an hyperbola in the yz plane

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Based on the plot, the number of practice puzzles per week that members solve if they finish the contest puzzle

in one hour is c 4

The line of best fit for the scatter plot shows that there is a positive correlation between the number of practice puzzles solved per week and the time it takes to solve a contest puzzle. This means that as the number of practice puzzles solved per week increases, the time it takes to solve a contest puzzle decreases.

If a member finishes a contest puzzle in one hour, they are on the line of best fit. This means that they solve approximately 4 practice puzzles per week.

The other options are incorrect. Option a is too high, option b is too low, and option d is not on the line of best fit.

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Answer:

- 391

Explanation:

Coterminal angles are the angles that share same sides. For example 360 and 0 are coterimal angles because they describe the same position on a unit circle.

Now for - 31 degrees we have

The two monomials whose greatest common factor is 3x are; 6x and 9x

A monomial is defined as a polynomial, that has just only one term. A monomial is also said to be an algebraic expression with just a single term but then it can have multiple variables and a higher degree as well.

Now, we want to find two monomials whose greatest common factor is 3x.

The GCF(greatest common factor) is defined as the largest number that is a factor of two or more numbers. Thus, two monomials with GCF of 3x are 6x and 9x

To know if the two monomials would have the GCF of 3x, factor the monomials to get;

6x = 2 * 3 * x

9x = 3 * 3 * x

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Answer:

57.3

Step-by-step explanation:

\(\huge\text{Hey there!}\)

\(\mathsf{10 \dfrac{2}{3}\times 5\dfrac{3}{8}}\)

\(\mathsf{= \dfrac{10\times3 + 2}{3}\times\dfrac{5\times8 + 3}{8}}\)

\(\mathsf{= \dfrac{30 + 2}{3} \times \dfrac{40 + 3}{8}}\)

\(\mathsf{= \dfrac{32}{3}\times \dfrac{43}{8}}\)

\(\mathsf{=\dfrac{32\times43}{3\times 8}}\)

\(\mathsf{= \dfrac{172}{3}}\)

\(\mathsf{= 57\dfrac{1}{3}}\)

\(\huge\text{Therefore, your answer should be:}\)

\(\huge\boxed{\mathsf{57\dfrac{1}{3}}}\huge\checkmark\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)