A crowbar having the length of 1.75 m is used to balance a load of 500 N If the distance between the fulcrum and the load is 0.5 calculate MA and VR and efficiency
load distance*l=effort distance*e
o.5*500=x*1.25
250/1.25=x
200=x
ma=load/effort
500/200
2.5
vr=ed/ld
1.25/0.5
2.5
effciency=ma/vr*100
100%
How does the structure of atoms in a substance determine the substance's conductivity? (1 point)
O If an atom's outer shell of electrons is positively charged, the substance is a good conductor.
O If an atom's nucleus is positively charged, the substance is a good conductor.
O If an atom's outer shell of electrons is loosely bound to the nucleus, the substance is a good conductor.
O If an atom's outer shell of electrons is tightly bound to the nucleus, the substance is a good conductor.
Answer:
If an atom's outer shell of electrons is loosely bound to the nucleus, the substance is a good conductor.
The structure of atoms in a substance determines the substance's conductivity is, If an atom's outer shell of the electron is loosely bound to the nucleus, then the substance is a good conductor. Hence, option C is correct.
Substances are differentiated into three types based on the electrons present in the valence shell. The valence shell is the outermost orbital of the atom and the electrons present in it are called valence electrons. The valence electrons are said to be free electrons and these electrons do not involve in chemical bonding.
The types of materials are conductors, insulators, and semiconductors. The material that has free electrons and carries current or heats through it is called a conductor. The materials that do not have free electrons and it does not carry current or heat are called insulators. The material that partially conducting and partially insulating are called semi-conductors.
Hence, the conductivity of the substance is determined by an atom's outer shell of the electron being loosely bound to the nucleus, the substance is a good conductor.
Hence, the ideal solution is option C.
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7) High-amplitude light waves produce high-amplitude sound waves produce
colors, whereas
sounds.
a) bright; louder b) dim; softer
c) bright; softer
d) dim; louder
8) The point on the retina that contains only cones and is responsible for our sharpest vision is called the
a) focal spot
b) vitreous humor c) fovea
d) optic disc
9) Rods are most sensitive and less sensitive
a) to color wavelengths; in dim light
b) in dim light; to low-amplitude light waves c) in dim light; to color wavelengths
d) to color wavelengths; to high-amplitude light waves
10) Myopia (or nearsightedness) results from images focused
a) on the fovea
b) in front of the retina
c) behind the retina d) on the rods
11) The blind spot is
a) the part of the retina that is clogged with receptors b) the area where the optic nerve exit the eye
c) related to how large the pupil in any given moment a when you look away at a white background. aware of those deficits.
d) due to damage to the eye and not something everyone has
12) The color aftereffects phenomenon predicts that, after staring at a bright red rectangle for a period of time, you will see
a) yellow rectangle b) white circle
c) green rectangle d) blue square
13) Which of the following statements is true regarding color-
limited vision?
a) The vast majority of people can see well over 40 million b) Most people with limitations in their color vision are not
different colors.
c) Color blindness is an appropriate term, as most deficits of color perception involve a complete inability to see a given hue. d) To be "color blind" means that one can only see in shades of black, white, and gray.
14) Which theory of pitch perception "solves" the problem of frequency theory's inability to account for high pitched sound
perception?
a) the opponent-process principle ) the trichromatic theory
b c) the place theory
d) the volley prin
The place theory of pitch perception "solves" the problem of frequency theory's inability to account for high pitched sound perception. the correct option is (c) the place theory.
7. High-amplitude light waves produce bright colors, whereas high-amplitude sound waves produce louder sounds.
Therefore, the correct option is (a) bright; louder.8. The point on the retina that contains only cones and is responsible for our sharpest vision is called the fovea.
Therefore, the correct option is (c) fovea.9. Rods are most sensitive to low-amplitude light waves and are less sensitive in dim light.
Therefore, the correct option is (b) in dim light; to low-amplitude light waves.10.
Myopia (or nearsightedness) results from images focused in front of the retina. Therefore, the correct option is (b) in front of the retina.11. The blind spot is the area where the optic nerve exits the eye.
Therefore, the correct option is (b) the area where the optic nerve exits the eye.12.
The color aftereffects phenomenon predicts that, after staring at a bright red rectangle for a period of time, you will see a green rectangle.
Therefore, the correct option is (c) green rectangle.13.
Most people with limitations in their color vision are not color blind, as the vast majority of people can see well over 40 million different colors. Therefore, the correct option is (b) Most people with limitations in their color vision are not color blind.14. The place theory of pitch perception "solves" the problem of frequency theory's inability to account for high pitched sound perception.
Therefore, the correct option is (c) the place theory.
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The first law of thermodynamics states that energy can neither be created nor destroyed. If this is true then why are we always looking for new sources of energy? Use the 2nd law of thermodynamics to answer this question.
Answer:
The second law of thermodynamics states in an isolated system, the entropy (the amount of thermal energy that cannot be converted into mechanical work, also known as the amount of disorder) always increases, therefore, an isolated system always require an external input (new sources) of energy for there to be orderliness or for the available energy of the system to remain constant or increase
Explanation:
the graph shows the relative amount of air pollution over a city for a period of several years. which statement about air pollution over this city is best supported by the graph?
The graph provided shows the relative amount of air pollution over a city for several years. The horizontal axis represents the years, and the vertical axis represents the relative amount of air pollution.
From the graph, we can see that the amount of air pollution over the city decreased over time.
In the first year, the relative amount of air pollution was highest, and in the last year, the relative amount of air pollution was the lowest.
This trend indicates that measures taken to reduce air pollution in the city have been successful over the years.
It is important to note that the graph only shows the relative amount of air pollution and not the actual amount.
Therefore, we cannot make any conclusions about the absolute amount of air pollution in the city. However, the graph does provide evidence that efforts to reduce air pollution have been effective in improving air quality in the city.
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Answer: (3) It is a cyclic event.
Explanation: Though air pollution has been decreasing in real life, the graph portrays a peak in pollution every mid-year. This pattern makes it easy to extrapolate when air pollution will be most. Therefore, this event is cyclic because this event constantly repeats in an orderly fashion.
ACTIVITY 4
Applying the equation learned, answer the following problems:
1. A bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s. What is its momentum? p = m/s. What Is Its Momentum?
Given:
Find:
Formula:
Solution:
2. A skateboard is rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s. What is its mass?
Given:
Find:
Formula:
Solution:
3. A pitcher throws a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s. What is its velocity?
Given:
Find:
Formula:
Solution:
Subject Is Science
Good Perfect Complete=Brainlist
Copy Wrong Incomplete=Report
Good Luck Answer Brainly Users:-)
Answer:
1) 10 kg-m/s
2) 2 kg
3) 20 m/s
Explanation:
The momentum of an object can be calculated using the equation:
\(\large\boxed{p=mv}\)
where:
p is momentum (measured in kilogram meters per second).m is mass (measured in kilograms).v is the velocity (measured in meters per second).\(\hrulefill\)
Question 1For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.
Given values:
m = 4.0 kgv = 2.5 m/sSubstitute the given values into the momentum formula and solve for p:
\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)
\(p=10\;\text{kg m/s}\)
Therefore, the momentum of the bowling ball is 10 kg-m/s.
\(\hrulefill\)
Question 2For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.
Given values:
p = 6.0 kg-m/sv = 3.0 m/sAs we want to find mass, rearrange the momentum formula to isolate m:
\(\large\boxed{m=\dfrac{p}{v}}\)
Substitute the given values into the formula and solve for m:
\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)
\(m=2\;\text{kg}\)
Therefore, the mass of the skateboard is 2 kg.
\(\hrulefill\)
Question 3For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.
Given values:
p = 10 kg-m/sm = 0.5 kgAs we want to find velocity, rearrange the momentum formula to isolate v:
\(\large\boxed{v=\dfrac{p}{m}}\)
Substitute the given values into the formula and solve for v:
\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)
\(v=20\;\text{m/s}\)
Therefore, the velocity of the baseball is 20 m/s.
An apple is thrown across the cafeteria with a force of 10 N and at an acceleration of 6 m/s2. What is the mass of the apple? ... please answer asap
Answer:
Explanation:
F = m * a
The apple's acceleration is not influenced by the acceleration due to gravity for this question. In real life it most certainly is influenced by gravity.
F = m * a
F = 10 Newtons.
a = 6 m/s^2
m = 10/6 = 1.66 kg. Mighty large apple
Instructions Write a for loop that prints the odd integers 11 through 121 inclusive, each value on a separate line Additional Notes: Regarding your code's standard output, CodeLab will check for case errors and will check whitespace (tabs, spaces,etc)
A for loop that prints the odd integers 11 through 121 inclusive, each value on a separate line is
```python
for i in range(11, 122):
if i % 2 == 1:
print(i)
```
Here's a step-by-step explanation to write a for loop that prints the odd integers 11 through 121 inclusive, each value on a separate line, taking into account the CodeLab requirements:
1. First, we need to write a for loop that starts at 11 and ends at 121, inclusive. We can achieve this by using the range() function and setting the start value to 11 and the stop value to 122 (since the stop value is exclusive):
```python
for i in range(11, 122):
```
2. Now, we need to check if the current integer (i) is odd. We can do this by using the modulo operator (%). If i % 2 equals 1, then the integer is odd:
```python
if i % 2 == 1:
```
3. If the integer is odd, we need to print it on a separate line. We can do this by using the print() function:
```python
print(i)
```
4. Combining all the steps, we have the following code:
```python
for i in range(11, 122):
if i % 2 == 1:
print(i)
```
This code will print the odd integers 11 through 121 inclusive, each value on a separate line, and it meets the CodeLab requirements.
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Here's the for loop in Python that prints the odd integers from 11 to 121 (inclusive) on separate lines:
```
for i in range(11, 122, 2):
print(i)
```
In this loop, the `range()` function is used with three arguments: `start`, `stop`, and `step`. The `start` parameter is set to 11, the first odd integer we want to print. The `stop` parameter is set to 122, which is one more than the last odd integer we want to print (121). The `step` parameter is set to 2, so the loop will increment `i` by 2 in each iteration, only considering odd integers. Finally, the `print()` function is called inside the loop to print each odd integer on a separate line.
This code will print the odd integers 11 through 121 inclusive, meeting the requirements of the question.
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A 2 kg marble moving at 4 mi./s collides into a 1 kg marble at rest. After collision, the 2 kg marble speed decreased to 2 mi./s. Calculate the velocity and speed of the 1 kg marble immediately after colliding.
Please show work and please help me as fast as possible because this is time
Please help as soon as possible please
Please I’m begging
Answer:
\(2\sqrt{6}\) \(\frac{mi}{s}\)
Explanation:
Assuming there is no waste of energy:
\(K_{1} = K_{2}\\\frac{1}{2}m_{1}v_{1_{1}}^{2} + \frac{1}{2}m_{2}v_{2_{1}}^2 = \frac{1}{2}m_{1}v_{1_{2}}^{2} + \frac{1}{2}m_{2}v_{2_{2}}^2\\\\=> m_{1}v_{1_{1}}^{2} + m_{2}v_{2_{1}}^2 = m_{1}v_{1_{2}}^{2} + m_{2}v_{2_{2}}^2\\\\m_{1} = 2 kg, m_{2} = 1 kg, v_{1_{1}} = 4 \frac{mi}{s} , v_{2_{1}} = 0\\=> 32 = 8 + v_{2_{2}}^{2} => v_{2_{2}} = 2\sqrt{6} \frac{mi}{s}\)
A3kg crate is placed at the bottom of an inclined frictionless plane making an angle 30 ° above the horizontal and pushed up by a force F - 50N parallel to the incline as shown below . If the incline is 6 m long , then the net work done on this crate when it reaches the top of the incline is equal to :
Answer: 210 J
Explanation:
Since there is no friction, coefficient of friction, μ = 0
The free body diagram is shown below
There must be a downward force due to gravity. Thus,
Net force = applied force - downward force
From the diagram,
Downward force = mgSinθ
where
m is the mass of the crate
θ is the angle between the plane and the horizontal axis
g is the acceleration due to gravity
From the information given,
m = 3
applied force = 50N
θ = 30
g = 10 m/s^2
Net force = (50 - 3 x 9.81Sin30) = 35 N
Net work = net force x distance
Given that distance = 6m,
Net work = 35 x 6
Net work = 210 J
if 1 m = 100 cm , then how many cm^2 are there in a m^2 ?? please hel[p
Answer:if 1 m = 100 cm then there should be 200 cm in m^2
Explanation:
Q3The pressure P (in kilopascals), volume V (in liters) and temperature T(in kelvins) of a mole of an ideal gas are related by the equation PV = 8.31T Find the rate at which the pressure is changing when the temperature is 300 K and increasing at a rate of 0.1 K/s and the volume is 100 L and increasing at a rate of 0.2L/s.
dP/dt = (0.831 - 0.2P) / 100, where P represents pressure (in kilopascals).
This equation represents the rate at which the pressure is changing with the given conditions of temperature and volume.
To find the rate at which the pressure is changing, we need to use partial derivatives. Given the equation PV = 8.31T, we can differentiate both sides of the equation with respect to time t.
Differentiating both sides with respect to time t, we get:
P(dV/dt) + V(dP/dt) = 8.31(dT/dt)
Now, let's substitute the given values:
dT/dt = 0.1 K/s (rate of temperature change)
dV/dt = 0.2 L/s (rate of volume change)
T = 300 K (temperature)
V = 100 L (volume)
Plugging in the values into the equation:
P(0.2) + 100(dP/dt) = 8.31(0.1)
0.2P + 100(dP/dt) = 0.831
Now, we can solve for dP/dt:
100(dP/dt) = 0.831 - 0.2P
dP/dt = (0.831 - 0.2P) / 100
Therefore, the rate at which the pressure is changing when the temperature is 300 K and increasing at a rate of 0.1 K/s, and the volume is 100 L and increasing at a rate of 0.2 L/s is given by:
dP/dt = (0.831 - 0.2P) / 100
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A student pushes a 40-n block across the floor for a distance of 10 m. how much work was done to move the block? responses a. 4 j b. 40 j c. 400 j d. 4,000 j
The work was done to move the block across the floor is 400 Joule.
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
A spring balance can be used to calculate the Force. The Newton is the SI unit of force.
Force applied on the block: F = 40 N.
Displacement of the box = 10 m.
Hence, work done to move the block = Force × Displacement
= 40 × 10 joule
= 400 joule.
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Please help me !! i am tired i worked all day to bring my grade up whitch i did i just gotta do this last assiment I will give brainlsit when i wake up
Plutonium= Pu, 94, 244,94,94
Chromium= Cr, 24,52, 24,24
Neon = Ne, 10,20,10,10
Gold= Au, 79,197,79,79
Radon = Ra ,86,222,86,86
Newton's second law contains in it all the information of Newton's first law. However, Newton's first law is simpler; thus, using the first law instead of the second can simplify an analysis. Whic of the following situations are best understood using Newton's first law of motion, and not Newton's second law of motion. Check all that apply A parked car A free falling rock A car on cruise control turning in a circle A car traveling in a straight line on cruise control
The situation that is understood using Newton's first law of motion, and not Newton's second law of motion are "A parked car" and "A car traveling in a straight line on cruise control"
Newton's first law of motion, also known as the law of inertia, states that an object at rest will remain at rest, and an object in motion will remain in motion at a constant velocity, unless acted upon by an external force. This law is best suited for situations where there is no net force acting on an object, such as a parked car or a car traveling in a straight line on cruise control.
On the other hand, Newton's second law of motion relates the acceleration of an object to the net force acting on it and its mass. This law is better suited for situations where there is a net force acting on an object, such as a free falling rock or a car on cruise control turning in a circle.
Therefore, the situations best understood using Newton's first law of motion are the parked car and the car traveling in a straight line on cruise control, and the situations best understood using Newton's second law of motion are the free falling rock and the car on cruise control turning in a circle.
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Answer please, anyone?
A + 9.4 nC point charge and a - 2.31 nC point charge are 4.94 cm apart. What is the electric field strength at the midpoint between the two charges?
Given:
The charge is q1 = 9.4 nC
The charge q2 = -2.31 nC
The distance between them is r = 4.94 cm
To find the electric field strength at the midpoint between two charges.
Explanation:
The electric field strength at the midpoint will be the sum of electric field strength due to q1 and q2.
The electric field strength can be calculated by the formula
\(E=\frac{kq}{r^2}\)Here, k is the electrostatic constant whose value is
\(k=9\times10^9\text{ N m}^2\text{ /C}^2\)The electric field strength due to the charge q1 is
\(\begin{gathered} E_1=\frac{kq1}{(\frac{r}{2})^2} \\ =\frac{9\times10^9\times9.4\times10^{-9}}{(\frac{4.94}{2}\times10^{-2})^2} \\ =1.39\times10^5\text{ V/m} \end{gathered}\)The electric field strength due to the charge q2 is
\(\begin{gathered} E_2=\frac{kq2}{(\frac{r}{2})^2} \\ =\frac{9\times10^9\times2.31\times10^{-9}}{(\frac{4.94}{2}\times10^{-2})^2} \\ =3.4\times10^4\text{ V/m} \end{gathered}\)The electric field strength at the midpoint will be
\(\begin{gathered} E=E_1+E_2 \\ =(1.39\times10^5)+(3.4\times10^4) \\ =173000\text{ V/m} \end{gathered}\)Thus, the electric field strength at the midpoint between the two charges is 173000 V/m
what is the affect of applying an unbalanced force on an object?
Answer:
An unbalanced force can change an object's motion. An unbalanced force acting on a still object could make the object start moving. An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving
Explanation:
hope this helps :)
In a head-on car crash, the passenger flies forward into the seat belt, steering wheel, or windshield.
This is an example of what principle of motion?
will energy float or sink
Answer:
float
Because it is kept float by force called buoyant force
Answer this please ASAP!!
110 is the answer to the question
Answer:
dont run away
Explanation:
as a roller coaster car crosses the top of a 40-mm-diameter loop-the-loop, its apparent weight is the same as its true weight. for the steps and strategies involved in solving a similar problem, you may view a video tutor solution. part a what is the car's speed at the top?
The car's speed at the top is 0.6 m/s^2
The diameter of loop d = 40 mm
The radius of loop r = 20 mm = 0.02 m
At the top position, we can write,
Weight and Normal reaction combination will provide the centripetal force i.e.
R + W = mv²/R
R = W [apparent weight = Actual weight]
2W = 2mg = mv2/r
v = √2gr
v = 2 x 10 x 0.02 = 0.6 m/s^2
Hence, the car's speed at the top is 0.6 m/s^2
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¿Cuál es el periodo de una onda si la frecuencia es 0. 8 Hz?
The period of the wave is 1.25 seconds.
The period of a wave is the time it takes for one complete cycle to occur. It is the reciprocal of the frequency, meaning that the period (T) is equal to 1 divided by the frequency (f).
Given that the frequency is 0.8 Hz, we can calculate the period as follows:
T = 1 / f
T = 1 / 0.8 Hz
T = 1.25 seconds
Therefore, the period of the wave is 1.25 seconds.
The question is '' What is the period of a wave if the frequency is 0.8 Hz''.
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A wave with a wavelength of 3 m travels with a frequency of 450 Hz. What is its speed? Answer quickly.
The speed of a wave with a wavelength of 3m and frequency of 450Hz is 1350 meters per seconds.
How to calculate the speed of a wave?Wavelength is simply the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.
It is expressed as;
λ = c ÷ f
Where c is speed, f is frequency and λ is wavelength.
Given the data in the question;
Wavelength λ = 3mFrequency f = 450 Hz = 450 s⁻¹Speed c = ?Plug the given values into the above formula and solve for speed v.
λ = c ÷ f
c = λ × f
c = 3m × 450s⁻¹
c = 1350 ms⁻¹
Therefore, the speed of the wave is 1350m/s.
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Which of the following are possible units for a spring constant?
A. J/m
B. cm/N
C. J/N
D. N/km
Answer:
D
Explanation:
The standard international (SI) unit for spring constant is N/m, so N/km is the same thing but bigger.
star a has absolute magnitude 1, while star b has absolute magnitude 0. based only on this information, what can be said about these two stars?
Absolute magnitude is a measure of the intrinsic brightness of a celestial object, such as a star, and is defined as the apparent magnitude the object would have if it were at a distance of 10 parsecs (32.6 light-years) from Earth. The lower the absolute magnitude, the brighter the object is intrinsically.
Given that star b has an absolute magnitude of 0 and star a has an absolute magnitude of 1, we can infer that star b is intrinsically brighter than star a. However, we cannot make any conclusions about other properties of the stars, such as their distance from Earth or their surface temperature. To further understand the properties of these stars, we would need additional information, such as their spectral type, luminosity class, or distance from Earth.
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When you lift a book from the ground to your desk, what kind of work do you do, negative or positive
When you lift the book, you are doing positive work
Because the force you apply to the book is in the same direction as its displacement, lifting it is considered positive work. Inverse work is being done by gravity. The gravitational potential energy of the object increases as you elevate the book.
What is Work ?The product of an object's displacement and the component of the applied force that is directed in the direction of the object's displacement is known as the work done by a force.
Positive Work: When a force is applied to an object in its direction of motion, it is said to have been performed positively.Negative Work Done: When a force is applied to an object in the wrong direction, the work is said to be negative.Learn more about Work here:
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A turtle moves at an average speed of 0.2m/S towards the finish line that is 80m away from the starting line. A rabbit,racing with the turtle,leaves the starting line 5.4 minutes after the turtle. The speed of the rabbit is 3.6km/h. Which one of them wins the race? Justify
Answer:
5.6mls
Explanation:
Calculate the recoil velocity of a rifle with a mass of 5.00 kg (including the bullet) after it fires a 0.005 kg bullet at a speed of 300 m/s ?
Given :
Velocity of bullet, \(v_b=300\ m/s\).
Mass of bullet, m = 0.005 kg.
Mass of rifle, M = 5 kg.
To Find :
The recoil velocity of the rifle.
Solution :
Since, their is no external force is acting.
So, momentum of the system will be conserved :
Initial momentum = Final momentum
m(0) + M(0) = m(300) + Mv
\(v=-\dfrac{300m}{M}\\\\v=-\dfrac{300\times 0.005}{5}\\\\v=-0.3 \ m/s\)
Therefore, recoil velocity of the rifle is 0.3 m/s.
Hence, this is the required solution.
Two drops of mercury each has a charge on 5.44 nC and a voltage of 235.15 V. If the two drops are merged into one drop, what is the voltage on this drop?
To find the voltage of the combined drops, we can just add the voltage of both drops together.
2(235.15) = 470.3 Volts