\(\qquad\) \(\purple{\twoheadrightarrow\pmb{AC= \sqrt{AB^{2} + BC^{2} -2AB\times BC\cos(\alpha)}}}\)
Substituting the data, we get the following:
\(\qquad\) \(\twoheadrightarrow\sf {AC= \sqrt{(4)^{2} + (6)^{2} -2(4)(6)\cos(60^{\circ})}}\)
\(\qquad\) \(\twoheadrightarrow\sf {AC= \sqrt{16+ 36 -48(1/2)}}\)
\(\qquad\) \(\twoheadrightarrow\sf {AC= \sqrt{52-24}}\)
\(\qquad\) \(\twoheadrightarrow\sf {AC= \sqrt{28}}\)
\(\qquad\) \(\twoheadrightarrow\sf {AC= 2\sqrt{7}}\)
\(\qquad\) \(\purple{\twoheadrightarrow\pmb{AC= 5.30\ cm}}\)
The AC side measurement is 5.30 cm approx.is it possible to make your lifetime displacement zero, if so where would you go?
Answer:
Yes
Explanation:
Displacement is the distance from the starting point to the end point. If you live and die at the same place, you will have 0m as your displacement.
A digital thermometer display reads 20.1 °C. What is the
estimated uncertainty of the measurement?
The estimated uncertainty of the measurement is 0.05 °C.
To determine the estimated uncertainty of the measurement, we need to consider the resolution of the digital thermometer. The resolution is the smallest change in the displayed value that the thermometer can detect.
Given that the resolution of the digital thermometer is 0.1 °C, the estimated uncertainty of the measurement is equal to half of the resolution:
\(\[\frac{{0.1 \, \text{{\°C}}}}{2} = 0.05 \, \text{{\°C}}\]\)
Hence, the estimated uncertainty of the measurement is 0.05 °C.
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If a mass is 1.5 m from the axis of rotation and makes one revolution in 10 seconds, what is its speed in m/s? If m = 0.1 kg and the values above still hold, what is the numerical value of the centripetal acceleration?
The speed of the mass is approximately 0.942 m/s.
The numerical value of the centripetal acceleration is approximately 0.591 m/s².
To find the speed of the mass, we need to know the circumference of the circular path it follows.
The circumference of a circle can be calculated using the formula:
Circumference = 2 * π * radius
Given that the mass is located 1.5 meters from the axis of rotation, the radius (r) is 1.5 meters.
Circumference = 2 * π * 1.5
Circumference ≈ 9.42 meters
Since the mass makes one revolution in 10 seconds, we can calculate its speed by dividing the circumference by the time taken:
Speed = Circumference / Time
Speed = 9.42 meters / 10 seconds
Speed ≈ 0.942 meters per second (m/s)
Therefore, the speed of the mass is approximately 0.942 m/s.
Now, let's calculate the centripetal acceleration.
The centripetal acceleration (ac) can be calculated using the formula:
ac = (v²) / r
Given:
m (mass) = 0.1 kg
r (radius) = 1.5 meters
v (velocity) = 0.942 m/s
Substituting the values into the formula, we can calculate the centripetal acceleration:
ac = (v²) / r
ac = (0.942 m/s)² / 1.5 meters
ac ≈ 0.591 m/s²
Therefore, the numerical value of the centripetal acceleration is approximately 0.591 m/s².
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An astronaut and his space suit have a combined mass of 157 kg. The
astronaut is using a 5 kg tqol kit to repair a solar panel on the International
Space Station. When the têther connecting the astronaut to the space
station becomes unattached, the astronaut, still holding the tool kit, starts
to float away at 0.2 m/s. Calculate the velocity with which the astronaut
must throw the tool kit in order to float back toward the space station at
0.1 m/s. Show your calculations and include units in your answer.
*
Answer:
v₃ = 9.62[m/s]
Explanation:
To solve this type of problem we must use the principle of conservation of linear momentum, which tells us that the momentum is equal to the product of mass by velocity.
We must analyze the moment when the astronaut launches the toolkit, the before and after. In order to return to the ship, the astronaut must launch the toolkit in the opposite direction to the movement.
Let's take the leftward movement as negative, which is when the astronaut moves away from the ship, and rightward as positive, which is when he approaches the ship.
In this way, we can construct the following equation.
\(-(m_{1}+m_{2})*v_{1}=(m_{1}*v_{2})-(m_{2}*v_{3})\)
where:
m₁ = mass of the astronaut = 157 [kg]
m₂ = mass of the toolkit = 5 [kg]
v₁ = velocity combined of the astronaut and the toolkit before throwing the toolkit = 0.2 [m/s]
v₂ = velocity for returning back to the ship after throwing the toolkit [m/s]
v₃ = velocity at which the toolkit should be thrown [m/s]
Now replacing:
\(-(157+5)*0.2=(157*0.1)-(5*v_{3})\\(5*v_{3})= 15.7+32.4\\v_{3}=9.62[m/s]\)
The velocity with which the astronaut must throw the tool kit is 9.62 m/s.
The given parameters:
Mass of the astronaut and space suit, m₁ = 157 kgMass of the tool kit, m₂ = 5 kgVelocity of the astronaut and tool kit, v = 0.2 m/sVelocity of the astronaut and space station, u₁ = -0.1 m/sApply the principle of conservation of linear momentum to determine the velocity of the tool kit;
\(m_1 u_1 + m_2u_2 = v(m_1 + m_2)\\\\-0.1(157) \ + 5u_2 = 0.2(157 + 5) \\\\-15.7 + 5u_2 = 32.4\\\\5u_2 = 32.4 + 15.7\\\\5u_2 = 48.1\\\\u_2 = \frac{48.1}{5} \\\\u_2 = 9.62 \ m/s\)
Thus, the velocity with which the astronaut must throw the tool kit is 9.62 m/s.
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A motor car having a mass of 2 tonnes is being accelerated up a gradient of 1 in 25. At an engine speed of 4 000 rimin the b. P. Is 57 kw the effective tyre radius is 330 mm, the rolling res?stance is 180 n/tonne, and the rear-axle ratio is 4. 4 to 1 assuming a transmission efficiency of 90 % and neglecting air resistance, determine the value of the acceleration at the given speed 262 mls1.
The value of the Acceleration at the given speed of 262 m/s will be 0.245 m / s²
Throughout time, the velocity is shifting. In actuality, the velocity is changing by a fixed rate of 10 m/s every second. An object is considered to be accelerating if its velocity is changing; it has acceleration.
Given that:
Mass of car = 2 Tonnes = 2000 kg.
Wheel's power transfer = Efficiency * b.P.
Power = 0.9 * 57000
Therefore, Power = 51300 W
Wheel's angular velocity = (2\(\pi\)N / 60) * (1 / rear-axle ratio)
Angular Velocity = (2\(\pi\) * 4000) / 60 * (1 / 4.4)
Therefore, Angular Velocity = 95.15 rad / sec
Wheel:
Power = Torque * Angular Velocity
P = F * Tyre Radius * W
⇒ 51300 = F * 0.33 * 95.15
F = 51300 / (0.33 * 95.15)
F = 51300 / 31.4
Therefore, Force = 1633.76 (by the engine)
Resistance:
Rolling Resistance (Fr) = 180 N/tonne * 2 = 360 N
F₁ = 360N
Gradient Resistance:
tanθ = 1 / 25
θ = 2.2906°
Fg = mg * sinθ
Fg = 2000 * 9.84 * sin (2.2906)
Fg = 783.37 N
Acceleration (a):
Net force = Mass * Acceleration
F - (Fr + Fg) = 2000 * a
1633.76 - (360 + 783.37) = 2000 * a
a = 490.39 / 2000
Therefore, Acceleration = 0.245 m / s²
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A 25-W soldering iron runs on 110 V dc. What is its resistance?
a) 0.48 kohms
b) 4.4 ohms
c) 0.0020 ohms
d) 2.8 kohms
On 110 V dc, a 25-W soldering iron operates. R=484 denotes its resistance.
What does resistance mean in its simplest form?The Greek letter omega stands in for the ohm, a unit of resistance measurement. Georg Simon Ohm (1784–1854), a German physicist who investigated the connection between voltage, current, and resistance, is the name given to the unit of resistance.
We know that
V = P/I
Ohm's law, where P stands for power, V for external voltage, and I for internal current.
I = V/R
V = P(VR)
P=V²/R
The power is
P =25W
The potential being provided is
V = 110V
According to Ohm's law:
P = V²/R
R = V²/P
figuring out the resistance R's value as follows:
R = (110V)²/25W
R=484Ω
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The frequency response function used herein during the sweep was OUT/IN = ACCELERATION / FORCE, explain what this means in the Bode plots for multiple degrees of freedom system and how it factors into the correct interpretation of the resonant frequencies.
The frequency response function OUT/IN = ACCELERATION / FORCE is commonly used to describe the behavior of a system in response to an input force. In the context of Bode plots for multiple degrees of freedom system, the frequency response function describes how the acceleration of each degree of freedom responds to an input force.
When interpreting resonant frequencies in the Bode plots for multiple degrees of freedom system, it is important to consider the frequency response function. The resonant frequency of each degree of freedom will be determined by the natural frequency of that degree of freedom and the damping ratio. The frequency response function will affect the amplitude and phase response of each degree of freedom, which can impact the system's overall behavior.
By understanding the frequency response function, you can make more accurate interpretations of the resonant frequencies in the Bode plots for multiple degrees of freedom systems. This can help you to identify potential issues or areas for improvement in the system's design or performance.
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BlueBolt Bottlers has a bottle-filling process with a mean value of 64 ounces and a standard deviation of 8 ounces. a. Suppose that the upper and lower tolerance limits are 71 and 57 ounces, respectively. What is the process capability ratio? What would the standard deviation have to be in order for the process to meet the tolerance limits 99.7% of the time? b. Now suppose BlueBolt Bottlers makes some process improvements, thereby lowering the standard deviation of the process to 1.5 ounces, rather than 8 ounces. Using the data in part (a), and the new standard deviation, calculate the process capability ratio. Is the filling process able to meet the tolerance limits 99.7% of the time? Does the process provide Six Sigma quality levels? Explain.
In part (b), the filling process is unable to meet the tolerance limits 99.7% of the time, and it does not achieve Six Sigma quality levels.
a. To calculate the process capability ratio (Cp) in part (a), we use the formula:
Cp = (Upper Specification Limit - Lower Specification Limit) / (6 * Standard Deviation)
Given:
Mean = 64 ounces
Standard Deviation = 8 ounces
Upper Specification Limit = 71 ounces
Lower Specification Limit = 57 ounces
Cp = (71 - 57) / (6 * 8) = 14 / 48 = 0.2917 (rounded to four decimal places)
To determine the standard deviation required for the process to meet the tolerance limits 99.7% of the time, we use the Z-score corresponding to a 99.7% confidence level, which is approximately 3.
Z = (Upper Specification Limit - Mean) / Standard Deviation
Rearranging the formula, we can solve for the standard deviation:
Standard Deviation = (Upper Specification Limit - Mean) / Z
Standard Deviation = (71 - 64) / 3 = 7 / 3 = 2.3333 (rounded to four decimal places)
b. In part (b), with the improved process having a standard deviation of 1.5 ounces, we can recalculate the process capability ratio using the same formula:
Cp = (Upper Specification Limit - Lower Specification Limit) / (6 * Standard Deviation)
Using the same specification limits as before:
Cp = (71 - 57) / (6 * 1.5) = 14 / 9 = 1.5556 (rounded to four decimal places)
To determine if the filling process is able to meet the tolerance limits 99.7% of the time, we compare the new Cp value to the critical value of 2. Since Cp is less than 2, the process does not provide Six Sigma quality levels.
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state two advantages and two disadvantages for using the newton representation forpolynomial interpolation
The Newton representation for polynomial interpolation offers benefits such as incremental computation and numerical stability, but it also has disadvantages like computational complexity and the absence of a closed-form expression for the coefficients.
Advantages:
1. Incremental computation: The Newton representation allows for incremental computation of the interpolating polynomial. This means that when adding new data points, you don't need to recompute the entire polynomial from scratch. Instead, you can simply update the coefficients of the existing polynomial, making it more efficient for applications that require frequent updates or additional data points.
2. Numerical stability: Compared to other methods like the Lagrange representation, the Newton representation offers better numerical stability. This is particularly important when dealing with higher-order polynomials or when the data points are close together, as it reduces the likelihood of experiencing large errors due to small changes in the input data.
Disadvantages:
1. Complexity: One of the drawbacks of using the Newton representation is its computational complexity. In order to compute the coefficients, you need to calculate divided differences for all possible combinations of data points. This can be time-consuming and computationally intensive, particularly for large data sets or high-degree polynomials.
2. Lack of a closed-form expression: Unlike some other interpolation methods, the Newton representation does not have a closed-form expression for the coefficients. This means that the coefficients must be computed numerically, which can be less convenient for some applications, particularly when working with symbolic or analytical expressions.
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A solid cylinder with mass M. radius R, and rotational inertia 1/2MR² rolls without slipping down the inclined plane
shown above. The cylinder starts from rest at a height H. The inclined plane makes an angle with the horizontal.
Express all solutions in terms of M, R, H, theta, and g.
a. Determine the translational speed of the cylinder when it reaches the bottom of the inclined plane.
b. Show that the acceleration of the center of mass of the cylinder while it is rolling down the inclined plane is (2/3)g sin theta.
c. Determine the minimum coefficient of friction between the cylinder and the inclined plane that is required for the cylinder to roll without slipping.
The acceleration of the center of mass of the cylinder is (2/3)g sinθ, and the minimum coefficient of friction between the cylinder and the inclined plane is μ_min = tanθ.
What is accelaration?Acceleration is the rate of change of velocity of an object. It measures the rate at which an object's speed and direction changes. It is a vector quantity, meaning it has both magnitude and direction. Acceleration can be positive, negative, or zero. Positive acceleration indicates an object is speeding up, while negative acceleration indicates it is slowing down. Zero acceleration indicates an object is maintaining its current speed and direction.
Determine the translational speed of the cylinder when it reaches the bottom of the inclined plane.
b. Show that the acceleration of the center of mass of the cylinder while it is rolling down the inclined plane is (2/3)g sin theta.
c. Determine the minimum coefficient of friction between the cylinder and the inclined plane that is required for the cylinder to roll without slipping.
Answer:
a. The translational speed of the cylinder when it reaches the bottom of the inclined plane is given by v = (2gh sinθ/3)^1/2.
b. The acceleration of the center of mass of the cylinder is given by a = (2/3)g sinθ. This can be shown as follows: The acceleration due to gravity is g cos θ, so the normal force is Mg cos θ. The rotational inertia of the cylinder is 1/2MR², and its angular acceleration is a/R. By Newton's second law, the resultant force acting on the cylinder is ma = Mg cosθ - 1/2MR² a/R. Therefore, a = (2/3)g sinθ.
c. The minimum coefficient of friction between the cylinder and the inclined plane required for the cylinder to roll without slipping is μ_min = tanθ. This can be shown as follows: The force of friction acting between the cylinder and the inclined plane is given by F_f = μN = μMg cos θ. The force of friction must be equal to the centripetal force acting on the cylinder, which is Mv²/R. Therefore, μ = v²/gR = (2gh sinθ/3)^1/2/gR = tanθ.
In conclusion, we have shown that the translational speed of the cylinder when it reaches the bottom of the inclined plane is given by v = (2gh sinθ/3)^1/2, the acceleration of the center of mass of the cylinder is (2/3)g sinθ, and the minimum coefficient of friction between the cylinder and the inclined plane is μ_min = tanθ.
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Sonu is observing his image in a plane mirror. The distance between the mirror and his image is 4 m. If he moves 1 m towards the mirror, the distance between Sonu and his image will be: (a) 3 m (b) 5 m (c) 6 m (d) 8 m
Answer:
Originally Sonu and image is 8 m (4 m to mirror and 4 m to image)
If he moves 1 m towards the mirror the image distance will be reduced to (c) 6 m
write 2 examples of Base physical quantities and their standard unit
Answer:
length centimeters or meters
time seconds
Help ASAP
Frank uses a bowling ball to demonstrate how energy can cause changes. Which
of the following actions would NOT demonstrate a change caused by applying
energy to the ball?
O He spins the bowling ball with one hand
O He rolls the bowling ball across the floor
O He holds the bowling ball in both hands
He lifts the bowling ball to place it on a shelf.
Answer:
he holds the ball in both hands
Explanation:
he's not moving the ball
A car starts to move from point A to B such that its displacement becomes 150m. This
motion was provided by a driving force of 66MN, calculate the Kinetic energy of the
body at B.??
Answer:
sorry I cannot give the answer I know only little bit about it
To calculate the kinetic energy of the car at point B, we first need to determine its velocity at that point. We can use the work-energy principle to relate the work done by the driving force to the change in kinetic energy of the car:
Work done by driving force = Change in kinetic energy
The work done by the driving force is equal to the product of the force and the displacement:
Work done = Force x Displacement = 66 MN x 150 m = 9.9 GJ
The change in kinetic energy is equal to the final kinetic energy minus the initial kinetic energy. Assuming the car starts from rest at point A, its initial kinetic energy is zero. Therefore, the final kinetic energy at point B is equal to the work done by the driving force:
Final kinetic energy = Work done = 9.9 GJ
Note that we converted the force to MN (meganewtons) and the energy to GJ (gigajoules) to match the SI unit system commonly used in physics calculations.
how much energy is needed to heat 2kg of cooking oil with a specific heat capacity of 2000j/kg°c from 20°c to 120°c
Answer:
400kj
Explanation:
h =mass × specific heat capacity × change in temperature
= 2×2000×[120-20]
=2×2000×100
=400000j
=400kj
400kj of energy is needed.
Energy:Energy, which is observable in the execution of labor as well as in the form of heat and light, is the quantitative quality that is transferred to a body or to a physical system in physics. Energy can be transformed in form but cannot be created or destroyed, according to the rule of conservation of energy. The joule, which is the energy supplied to an object by the labor of moving it a distance of one meter against a force of one newton, is the unit of measurement for energy in the International System of Units (SI).Cooking oil:Cooking oil is a liquid fat made of plants, animals, or synthetic materials that are used in baking, frying, and other cooking processes. It may also be referred to as edible oil because it is used in cold food preparation and flavoring, including salad dressings and bread dips.At room temperature, cooking oil is normally a liquid, although some saturated-fat oils, such as coconut oil, palm oil, and palm kernel oil, are solids.Solution -Formula - h = mass × specific heat capacity × change in temperature
So,
\(2\) × \(2000\) × \([120-20]\)
\(2\) × \(2000\) × \(100\)
\(=400000j\\=400kj\)
Therefore, 400kj of energy is needed.
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A No. _____ THHN conductor is required for a 19.7 ampere load if the ambient temperature is 75F and there are nine current-carrying conductors in the raceway.
A No. 12 THHN conductor is required for a 19.7-ampere load if the ambient temperature is 75F and there are nine current-carrying conductors in the raceway.
To determine the size of the THHN conductor required for a 19.7-ampere load, we will need to use the ampacity tables from the National Electric Code (NEC).
The ampacity tables provide the maximum current-carrying capacity of various types and sizes of conductors based on factors such as ambient temperature and the number of current-carrying conductors in the raceway or cable.
Assuming a copper conductor, we can use NEC Table 310.15(B)(16) to find the ampacity of a No. 12 THHN conductor at an ambient temperature of 75F with nine current-carrying conductors. According to the table, the ampacity of a No. 12 THHN conductor with nine current-carrying conductors at 75F is 20 amperes.
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A person is running in a straight line when you measure their velocity. The x-component of the velocity vector is 1.3 m/s2 and the y-component of the velocity vector is -1.4 m/s2.
What is the direction (angle in degrees) of the resultant velocity vector with respect to the + x‐axis? Remember to account for sign in your answer.
Velocity is defined as the rate of change of displacement. It's a vector quantity that specifies both speed and direction. The x-component of the velocity vector is 1.3 m/s², and the y-component of the velocity vector is -1.4 m/s².
To determine the direction of the resultant velocity vector with respect to the + x‐axis, we need to calculate the angle made by the vector with the x-axis.
The tangent of the angle is the ratio of the y-component of the velocity to the x-component of the velocity.
tan θ = (-1.4 m/s²) / (1.3 m/s²)
θ = tan⁻¹ (-1.4/1.3)
θ = -49.78°
Therefore, the direction of the resultant velocity vector with respect to the + x‐axis is -49.78°.
Note: The negative sign in the answer represents that the angle is measured clockwise from the + x-axis.
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potential energy is sometimes called?
Answer:
it can be called PE or sometimes, there are equations which you can use the letter U.
Explanation:
Answer:
STORED ENERGY
Explanation:
Spaceship 1 and Spaceship 2 have equal masses of 300 kg. Spaceship 1 has
a speed of 0 m/s, and Spaceship 2 has a speed of 6 m/s. What is the
magnitude of their combinied momentum?
A. 1,200 kg-m/s
B. 18 kg-m/s
C. 1,800 kg-m/s
D. 3,600 kg-m/s
PLEASE HELP FAST
Answer:
C, 1800kg/s
Explanation:
You multiply the mass (300) by the change in the two velocities (6-0=0). Then you’ll get 1800.. sorry if I’m wrong
An air-track glider is attached to a spring. The glider is pulled to the right and released from rest at tt
In conclusion, when an air-track glider is attached to a spring and pulled to the right before being released from rest, it undergoes simple harmonic motion.
The air-track glider is attached to a spring and is pulled to the right before being released from rest. When the glider is released, it will experience simple harmonic motion due to the spring's restoring force.
During simple harmonic motion, the glider will oscillate back and forth along the air track. The motion is characterized by a period (T) and a frequency (f), which depend on the mass of the glider (m) and the spring constant (k).
The period of the motion, T, is the time it takes for the glider to complete one full oscillation. It can be calculated using the formula T = 2π√(m/k). The frequency, f, is the number of oscillations per second and is the reciprocal of the period (f = 1/T).
As the glider is released from rest, it will initially move to the right due to the pull. As it moves, the spring will stretch and create a restoring force that pulls the glider back towards the equilibrium position.
The glider will then pass the equilibrium position, compressing the spring and causing a restoring force that opposes the glider's motion.
This back and forth motion continues until the energy of the glider is dissipated due to friction or other factors. The glider will gradually come to a stop at the equilibrium position.
In conclusion, when an air-track glider is attached to a spring and pulled to the right before being released from rest, it undergoes simple harmonic motion.
This motion is characterized by oscillations back and forth along the air track, with a period and frequency determined by the mass of the glider and the spring constant.
The glider experiences a restoring force from the spring that opposes its motion, causing it to oscillate until energy is dissipated and it comes to a stop at the equilibrium position.
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Suppose Person A runs off the edge of the cliff at 2 m/s and Person B runs off the edge at 1 m/s. Which will hit the ground farther from the base of the cliff?
Answer:
Person A will hit a distance fatherExplanation:
Based on the fact that the velocity of person A is more than that of person B, that is from the question, person A has a velocity of 2m/s and person B has a velocity of 1m/s, this clearly shows that person A has the tendency to hit a distance farther from the cliff than person B.
Macbeth is more confident after meeting with the three witches and finding out more of their prophesies. what two visions do they give macbeth that assure him he will remain king and not be defeated? use specific evidence to support your answer in 3-5 complete sentences.
The two visions given to Macbeth by the three witches that assure him he will remain king and not be defeated are: "Beware Macduff" and "none of woman born shall harm Macbeth".
The first vision gives him warning about Macduff, who is a potential threat to his throne, and the second vision gives him assurance that he cannot be killed by any man born of a woman. These visions give Macbeth a false sense of security and make him believe that he is invincible. However, as the play progresses, we see that these prophecies prove to be his downfall.
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When an electric current passes through a wire a magnetic field is formed, this is called______________.
A) Atomic force
B) Intermolecular force
C) Electromagnetism
D) Nuclear spin
2. A bar magnet is divided in two pieces . Which of the following statements is true about the force between the broken pieces if they face each other with a small separation ? A. There is an electric repulsive force between the broken pieces B. There is an electric attractive force between the broken pieces C. There is a magnetic repulsive force between the broken pieces D. There is a magnetic attractive force between the broken pieces .
The Eatern coat of South America and the wetern coat of Africa are eparated by the Atlantic Ocean. If cientit find the ame type of plant foil on the eatern coat of South America and wetern coat of Africa, which of thee would be the bet concluion
It can be concluded that at one time in the past, South America and Africa were once one. Beside of the same type of plant foil on the eastern coast of South America and western coat of Africa, we can identify other similar reason that the coastlines of South America and Africa on opposite sides of the Atlantic Ocean seem to fit together.
Is it true that once upon a time South America and Africa is a continent?Yes, is it. Let's back to 1915, a German scientist named Alfred Wegener, proposed that continents could move around on the earth’s surface. He said that in the past there is a supercontinent in the earth named Pangea Continent. Not only South America and Africa, but also all of the continents were all together in the past.
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What happens when light from the Sun passes through any type of matter? The light slows down.
The light speeds up.
Most of the light is absorbed.
Most of the light is reflected.
Answer:
A
Explanation:
THE LIGHT SLOWS DOWN
When light from the Sun passes through any type of matter the light slows down.
Interaction of sunlight with matter:The behavior of light from the Sun as it interacts with any matter depends on the matter and its properties.
Since it comes through a vacuum and enters our atmosphere which is a denser medium and has a definite refractive index, the light slows down.
This also happens when light falls on material such as glass, water, and other transparent and translucent media. When it emerges out of such medium to a rarer medium like air, it speeds up to its initial speed.
A portion of the sunlight is absorbed by almost all the matter present on earth that's why something heats up when exposed to sunlight. While a considerable portion of the sunlight is reflected by the matter.
But the question says what happens when it passes through any matter. The answer is:
It slows down while passing through the matter since any matter is optically denser than the vacuum.
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a spring with a spring constant of 8.0 n/m is initially compressed to 5.0 cm. the work done as it is compressed another 15 cm, to a total compression of 20 cm is: a. 0.85 j. b. 0.54 j. c. 0.25 j. d. 0.15 j. e. 0.09 j.
When a spring with an initial compression of 5.0 cm is compressed by 0.15, a total compressed of 20 cm is achieved. as it is compressed another 15 cm, the work is completed. spring constant 8.0 n/m
The spring constant can be calculated using the spring constant. Springs that are more rigid are more likely to be challenging to stretch. Elastic substances make up springs. spring constant deforms when external forces are applied, but it returns to its original position once the force is removed. A linear elastic deformation has occurred with the spring. The relationship curve between force and displacement is linear.
A type of compressed spring that generates linear force is the spring.
Work completed, w = 0.5 k x - 0.5 ky
W= 1/2K (x^2 - y^2 )
W = 1/2 ( 8 ) / (20 * 10^ -2 ) ^2 - ( 5* 10 ^-2 ) ^2 J
W = 0.15 J
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Which moon shows evidence of rainfall and erosion by some liquid substance?.
Answer:
Titan.It is the largest moon of Saturn
What is the formula for calculating average speed in this situation?
Average Speed = (Total distance)/(Total Time)
-secret_angel-
Answer:
the formula for average speed is
\( averge \: speed \: of \: light= {frequeny} \times {wave \: length} \)
and
\(normal \: average \: speed \: = \frac{distance \: travel}{time} \)
this would help you. :)
A household uses the following electric appliances:
refrigerator of rating 400W for 10 hours each day.
two electric fans of rating 80 W for 6 hours daily.
Six electric tubes of rating 18 W for 6 hours daily.
Calculate the electricity bill for the household for month of June if cost of electricity energy is ₹ 3.00 per unit
The electric bill for the household for the month of June is ₹ 504.72
How do I deterrmine the electric bill for the month of june?We'll begin by obtaining the energy consumed. This is shown below:
For fridge:
Power = 400 WTime = 10 hoursEnergy for fridge =?Energy = power × time
Energy for fridge = 400 × 10
Energy for fridge = 4000 Wh
Divide by 1000 to express in KWh
Energy for fridge = 4000 / 1000
Energy for fridge = 4 kWh
For fan:
Power = 80 WTime = 6 hoursEnergy for fan =?Energy = power × time
Energy for fan = 80 × 6
Energy for fan = 480 Wh
Divide by 1000 to express in KWh
Energy for fan = 480 / 1000
Energy for fan = 0.48 kWh
Energy for 2 fans = 2 × 0.48 = 0.96 kWh
For tube:
Power = 18 WTime = 6 hoursEnergy for tube =?Energy = power × time
Energy for tube = 18 × 6
Energy for tube = 108 Wh
Divide by 1000 to express in KWh
Energy for tube = 108 / 1000
Energy for tube = 0.108 kWh
Energy for 6 tubes = 6 × 0.108 = 0.648 kWh
Total energy consumed per day = 4 + 0.96 + 0.648 = 5.608 kWh
Total energy consumed per month = 30 × 5.608 = 168.24 kWh
Finally, we shall determine the electric bill for the month of june. Details below:
Cost per KWh = ₹ 3.00Total energy (E) = 168.24 KWhElectric bill for June =?Electric bill = energy × Cost per KWh
Electric bill for June= 168.24 × 3
Electric bill for June = ₹ 504.72
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