PLSSS HELPPPP COUNTS BIG GRADE!!!!!

Answer:

Infinity isn't a number but I think number 0 is a real number since it's used on the number line :3

Step-by-step explanation:

:3

According to the characteristics of ticket sales and the resulting system of linear equations we find that 122 children bought each one a ticket on Sunday.

In this question we have a word problem, whose information must be translated into algebraic expressions to find a solution. Let be x and y the number of children and adults that went to the movie theatre, respectively.

We need two linear equations, one for the number of people assisting to the theatre and another for the total sales:

x - 4 · y = 0     (1)

6.30 · x + 9.50 · y = 1063.20     (2)

By algebraic procedures the solution to this system is: x = 122.559, y = 30.639. Since the number of tickets sold are integers, then we truncate each result: x = 122, y = 30.

According to the characteristics of ticket sales and the resulting system of linear equations we find that 122 children bought each one a ticket on Sunday.

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The correct values for a, b, c, d, and e are a = 16, b = 29, c = 24, d = 22, and e = 30 for group of 75 students on asking whether they like Algebra or Geometry.

For the values of a, b, c, d, and e, we can use the information provided in the table. Let's break it down step-by-step:

We are given that a total of 75 math students were surveyed. Therefore, the total number of students should be equal to the sum of the students who like algebra, the students who like geometry, and the students who do not like either subject.

75 = 45 (Likes Algebra) + 53 (Likes Geometry) + 6 (Does Not Like Either)

Simplifying this equation, we have:

75 = 98 + 6

75 = 104

This equation is incorrect, so we can eliminate options c and d.

Now, let's look at the information given for the students who do not like geometry. We know that a + b = 6, where a represents the number of students who like algebra and do not like geometry, and b represents the number of students who do not like algebra and do not like geometry.

Using the correct values for a and b, we have:

16 + b = 6

b = 6 - 16

b = -10

Since we can't have a negative value for the number of students, option a is also incorrect.

The remaining option is option e, where a = 29, b = 16, c = 24, d = 22, and e = 30. Let's verify if these values satisfy all the given conditions.

Likes Algebra: a + c = 29 + 24 = 53 (Matches the given value)

Does Not Like Algebra: b + d = 16 + 22 = 38 (Matches the given value)

Likes Geometry: c + d = 24 + 22 = 46 (Matches the given value)

Does Not Like Geometry: b + e = 16 + 30 = 46 (Matches the given value)

All the values satisfy the given conditions, confirming that option e (a = 29, b = 16, c = 24, d = 22, and e = 30) is the correct answer.

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Answer: He made $90 last week.

Assumption :

Let, Luis made $X last week.

He made $72 this week which is 80% of $X that he made last week

⇒ X * 80% = 72

⇒ X * 80/100 = 72

⇒ X = (72 * 100)/80

⇒ X = 90

Therefore, he made $90 last week.

To remember :

While solving this type of problems, be careful to understand which one of last time and current time is not given; just assume that one and input other conditions, the problem will be solved.

Answer:

4

Step-by-step explanation:

Answer: 4

Step-by-step explanation: Same thing as 8 / 0.5

Answer:

Command

Simplify

2 power of 4

16

2 power of 4

Step-by-step explanation:

The bucket initially contains 11 2/3 gallons of water and is 5/6 full. To find the capacity of a full bucket, we can use the proportion method.

We set up the proportion with the known quantities and the unknown quantity of a full bucket. Solving the proportion, we find that a full bucket would contain 14 gallons of water.

To find the capacity of a full bucket, we can use the concept of proportions.

Let x represent the capacity of a full bucket in gallons.

We have the following information:

The bucket initially contains 11 2/3 gallons of water, which can be expressed as 11 + 2/3 = 35/3 gallons.

The bucket is 5/6 full, which means it contains 5/6 of its total capacity.

Setting up the proportion:

(5/6) * x = 35/3

To solve the proportion, we cross-multiply:

(5/6) * x = 35/3

Multiply both sides by 6 to eliminate the fraction:

5 * x = (35/3) * 6

Simplifying the right side:

5 * x = 70/3

Multiply both sides by 3 to isolate x:

15 * x = 70

Divide both sides by 15:

x = 70/15

Simplifying the fraction:

x = 14/3

Converting the fraction to a mixed number:

x = 4 2/3

Therefore, a full bucket would contain 4 2/3 gallons of water, which is equivalent to 14 gallons.

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After 20 minutes, the temperature of the can will be 50° + 40° = 90° and over the long term, the temperature of the can will eventually reach the outside temperature of 90°

(a) To find the temperature of the can after 20 minutes, we need to calculate the rate of change in temperature and multiply it by the time elapsed. Given that the outside temperature remains constant at 90o, we can calculate the rate of change as follows:

(50° - 40°) ÷ 5 minutes = 2° per minute

Now, multiplying the rate of change by the time elapsed, we get:

2o per minute × 20 minutes = 40°

Therefore, after 20 minutes, the temperature of the can will be 50° + 40° = 90°.

(b) Over the long term, the temperature of the can will eventually reach the outside temperature of 90°. This is because the can will keep absorbing heat from the outside until it reaches thermal equilibrium, where the temperature of the can is the same as the outside temperature.

However, this process will take a very long time, especially if the can has a high thermal resistance.

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Weighted Mean = (90 × 25% + 79 × 20% + 82 × 10% + 70 × 15% + 85 × 15%) / (25% + 20% + 10% + 15% + 15%)

Unweighted Mean = (90 + 79 + 82 + 70 + 85) / 5

One student, Kyle, hasn't taken his final exam yet, but his marks in the first five categories are 90, 79, 82, 70, and 85. This problem requires determining the weighted mean for Kyle before the final exam and comparing it to the unweighted mean.

To calculate the weighted mean for Kyle before the final exam, we need to multiply each category's mark by its corresponding weight, sum them up, and divide by the total weight. For Kyle, the weighted mean would be calculated as follows:

Weighted Mean = (Knowledge × 25% + Application × 20% + Thinking × 10% + Culminating Project × 15% + Final Exam × 15% + Communication × 15%) / (Total Weight)

However, since Kyle hasn't written his final exam yet, we can exclude the Final Exam mark and its weight from the calculation. The weighted mean would then be:

Weighted Mean = (90 × 25% + 79 × 20% + 82 × 10% + 70 × 15% + 85 × 15%) / (25% + 20% + 10% + 15% + 15%)

To find the difference between the weighted mean and the unweighted mean, we need to calculate the unweighted mean by simply taking the average of the marks in the first five categories:

Unweighted Mean = (90 + 79 + 82 + 70 + 85) / 5

By comparing the weighted mean and the unweighted mean, we can evaluate how much the inclusion of weights for different categories affects Kyle's overall mark.

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Step-by-step explanation:

here is the answer babe. Feel free to ask for more help

Answer:

L bozo just know the asnwer EZ

Step-by-step explanation:

COPE

On solving the provided question, we can say that - so, percentage - 400/500 X 100 = 80%

A percentage in mathematics is a figure or ratio that is stated as a fraction of 100. The abbreviations "pct.," "pct," and "pc" are also occasionally used. It is frequently denoted using the percent symbol "%," though. The amount of percentages has no dimensions. With a denominator of 100, percentages are basically fractions. To show that a number is a percentage, place a percent symbol (%) next to it. For instance, if you correctly answer 75 out of 100 questions on a test (75/100), you receive a 75%. To compute percentages, divide the amount by the total and multiply the result by 100. The percentage is calculated using the formula (value/total) x 100%.

here,

total is 500

obtained is 400

so, percentage - 400/500 X 100 = 80%

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Answer:

(2x+1)(2x-1)

Step-by-step explanation:

4x^2-1

(2x)^2-1

(2x)^2-1^2

(2x+1)(2x-1)

The crucial value (z) relies on the desired level of confidence and is predicated on a normal distribution when creating a confidence interval for a proportion (p) with a confidence level of 93%.

A 93% confidence level in this instance translates to an alpha level of 0.07 (1 - 0.93 = 0.07) that is split evenly between the two tails. In the usual normal distribution table, we search for the value that falls within the range of 0.07 to find the proper z-value. A 93% confidence level corresponds to a z-value of roughly 1.81. The confidence interval for the proportion p may be calculated using this number and provides a range where the genuine proportion is like to fall.

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The normal curve with a mean (μ) of 50 and a standard deviation (σ) of 6 is shown below. To find the probability of the random variable being greater than 55 (P(X > 55)), we need to calculate the area under the curve to the right of 55. This shaded area represents the probability.

The normal curve, also known as the Gaussian curve or bell curve, is a symmetrical probability distribution. It is characterized by its mean (μ) and standard deviation (σ), which determine its shape and location. In this case, the mean is 50 (μ = 50) and the standard deviation is 6 (σ = 6).

To find the probability of the random variable being greater than 55 (P(X > 55)), we calculate the area under the normal curve to the right of 55. Since the normal curve is symmetrical, the area to the left of the mean is 0.5 or 50%.

To calculate the probability, we need to standardize the value 55 using the z-score formula: z = (X - μ) / σ. Plugging in the values, we get z = (55 - 50) / 6 = 5/6. Using a z-table or statistical software, we can find the corresponding area under the curve for this z-value. This area represents the probability of the random variable being less than 55 (P(X < 55)).

However, we are interested in the probability of the random variable being greater than 55 (P(X > 55)). To find this, we subtract the area to the left of 55 from 1 (the total area under the curve). Mathematically, P(X > 55) = 1 - P(X < 55). By referring to the z-table or using software, we can find the area to the left of 55 and subtract it from 1 to obtain the shaded area representing the probability of the random variable being greater than 55.

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Answer:

the answer is number 1

Step-by-step explanation:

Answer:

It has to be the third option.

Happy to help :)

A. The maximum mean weight of the passengers cannot exceed 3500 lb if the gondola is filled to its capacity of 25 passengers.

B. To calculate the probability that the mean weight of 25 randomly selected skiers exceeds the maximum weight from part A, we need to use the Central Limit Theorem and standardize the sample mean using z-scores.

C. If the weight assumptions are revised so that the new capacity becomes 20 passengers, the probability that the mean weight of 20 randomly selected skiers exceeds 175 lb can be calculated by standardizing the sample mean using z-scores.

D. To assess the safety of the new capacity of 20 passengers, we need to determine the probability of exceeding the load limit of 3500 lb.

A. Let's denote the mean weight of the passengers as μ and the standard deviation as σ. We know that μ = 180 lb and σ = 38 lb. Since the gondola can carry 25 passengers, the total weight can be calculated as 25 * μ.

To ensure that the total weight does not exceed 3500 lb, we can set up the following inequality:

25 * μ ≤ 3500

Substituting the given values, we have:

25 * 180 ≤ 3500

4500 ≤ 3500

This inequality is not true, which means that the maximum mean weight of the passengers cannot exceed 3500 lb.

B. To determine the probability that the mean weight exceeds the value from part A, we need to calculate the probability distribution of the sample mean.

Now we can calculate the probability that the mean weight exceeds the value from part A, which is the maximum mean weight we found in part A. Let's denote this value as x.

P(x-bar > x) = P(x-bar > 3500 / 25)

To find this probability, we need to standardize the sample mean using z-scores. The formula for the z-score is:

z = (x - μ_x-bar) / σ_x-bar

Substituting the values, we have:

z = (x - 180) / 7.6

We can then look up the corresponding probability in the standard normal distribution table or use statistical software to find the probability.

C. The mean weight of the passengers (μ) remains the same at 180 lb, and the standard deviation (σ) remains at 38 lb. However, since the capacity has changed to 20 passengers, the sample size (n) is now 20.

μ_x-bar = μ = 180 lb

σ_x-bar = σ / √n = 38 lb / √20 ≈ 8.5 lb

Now we can calculate the probability that the mean weight exceeds 175 lb. Let's denote this value as x.

P(x-bar > x) = P(x-bar > 175)

Similarly to part B, we need to standardize the sample mean using z-scores:

z = (x - 180) / 8.5

Then, we can look up the corresponding probability in the standard normal distribution table or use statistical software to find the probability.

D. Is the new capacity of 20 passengers safe? Since the probability of overloading is (under 5%, over 50%), the new capacity (does not appear, appears) to be safe enough.

To calculate this probability, we need to find the probability that the total weight of the 20 randomly selected skiers exceeds 3500 lb. This requires considering the distribution of the sum of 20 normally distributed variables.

The total weight of the 20 skiers can be calculated as 20 * μ, where μ is the mean weight of the passengers (180 lb).

Let's denote the total weight as X. We need to calculate:

P(X > 3500)

To find this probability, we can standardize the variable X using z-scores and then look up the probability in the standard normal distribution table or use statistical software.

If this probability is less than 5%, it indicates that the probability of overloading is under 5%, suggesting that the new capacity of 20 passengers appears to be safe enough. Conversely, if the probability is greater than 50%, it suggests a high risk of overloading.

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Complete Question:

A ski gondola carries skiers to the top if a mountain. assume the weights of skiers are normally distributed with a mean of 180 lb and a standard deviation of 38 lb. the gondola has a stated compacity of 25 passengers, and the gondola is rated fir a load limit of 3500 lb

A. Given that the gondola is rated for a load limit of 3500 lb what is the max mean weight of the passengers if the gondola is filled to the capacity of 25 passengers?

B. If the gondola is filled with 25 randomly selected skiers, what is the probability that their mean weight exceeds the value from part A.

C. If the weight assumptions were revised so that the new capacity became 20 passengers and the gondola is filled with 20 randomly selected skiers, what is the probability that their mean weight exceeds 175 lb, which is the max weight hat does not cause the total load to exceed 3500lb

D. Is the new capacity of 20 passengers safe? Since the probability of overloading is (under 5%, over 50%) the new capacity (does not appear, appears) to be safe enough.

Answer:

z score = 1.25

Step-by-step explanation:

Buster is a male Labrador Retriever who is 24.5 inches tall. The height of male Labrador Retrievers is normally distributed with a mean of 23.5 inches and a standard deviation of 0.8 inches. (The height of a dog is measured from his shoulder.) Find and interpret Buster's z-score.

The formula for z-score =

z = (x-μ)/σ, where

x is the raw score = 24.5 inches

μ is the population mean = 23.5 inches

σ is the population standard deviation. = 0.8

Hence,

z = 24.5 - 23.5/0.8

z = 1.25

Probability value from Z-Table:

P(x = 24.5) = 0.89435

From the above calculation, the z-score = 1.25

The interpretation of the z score is since the z score is positive, this means the given data is higher or greater than the mean

The value is used for the term p^2 in the equation p^2+ 2pq + q^2 = 1 is 0.16.

According to the statement

we have given that the allele frequency of the dominant allele is 0.4, and we have to find that the value of p^2 in the equation p^2+ 2pq + q^2 = 1.

So, For this purpose, we know that the

The allele frequency represents the incidence of a gene variant in a population. Alleles are variant forms of a gene that are located at the same position, or genetic locus, on a chromosome.

And here

allele frequency is the 0.4 and represent the value of P.

So, The value of p is 0.4 and the

Then p^2 = (0.4)^2

so, the value becomes

p^2 = (0.4)^2

p^2 = 0.16.

So, The value is used for the term p^2 in the equation p^2+ 2pq + q^2 = 1 is 0.16.

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To calculate the discharge through the circular channel, we can use Manning's equation, which relates the flow rate (Q) to the channel properties and flow conditions. Manning's equation is given by:

Q = (1/n) * A * R^(2/3) * S^(1/2)

where:

Q is the discharge (flow rate)

n is Manning's coefficient (0.014 in this case)

A is the cross-sectional area of the channel

R is the hydraulic radius of the channel

S is the slope of the channel bed

First, let's calculate the cross-sectional area (A) of the circular channel. The diameter of the channel is given as 6m, so the radius (r) is half of that, which is 3m. Therefore, the area can be calculated as:

A = π * r^2 = π * (3m)^2 = 9π m^2

Next, let's calculate the hydraulic radius (R) of the channel. For a circular channel, the hydraulic radius is equal to half of the diameter, which is:

R = r = 3m

Now, we can calculate the slope (S) of the channel bed. The given slope is 1 in 600, which means for every 600 units of horizontal distance, there is a 1-unit change in vertical distance. Therefore, the slope can be expressed as:

S = 1/600

Finally, we can substitute these values into Manning's equation to calculate the discharge (Q):

Q = (1/0.014) * (9π m^2) * (3m)^(2/3) * (1/600)^(1/2)

Using a calculator, the discharge can be evaluated to get the final result.

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The range of the attached function is 0 ≤ y ≤ 8

The complete question is added as an attachment

From the graph, we have the following highlights

This means that the y value do not exceed 8, and the minimum is 0

Hence, the range of the attached function is 0 ≤ y ≤ 8

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The types of concurrent constructions that are needed to find the centroid of a triangle include the following: B. intersection of the lines drawn to the midpoint of each side of the triangle to its opposite vertex.

In Mathematics and Geometry, the centroid theorem states that the centroid of a triangle is located at two-third (2/3) of the distance from the vertex to the midpoint of the (opposite) sides.

Generally speaking, the centroid of a triangle simply refers to the point where the three (3) medians of the triangle meet or intersect. This ultimately implies that, a centroid is a point of intersection of the lines from each vertex of a triangle to the midpoint of the opposite sides.

In this context, the types of concurrent constructions would be modeled by answer option B.

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Complete Question:

What types of concurrent constructions are needed to find the centroid of a triangle.

A. intersection of the lines drawn from each vertex of a triangle and perpendicular to its opposite side.

B. intersection of the lines drawn to the midpoint of each side of the triangle to its opposite vertex.

C. intersection of the lines drawn to bisect each vertex of the triangle.

D. intersection of the lines drawn perpendicular to each side of the triangle through its midpoint

Number of cats are 12.

Number of dogs are 15.

What is mean by Ratio?

A ratio indicates how many times one number contain in another number. The ratio of two number is written as x : y, which is equivalent to x/y.

Where, x and y are individual amount of two quantities.

And, Total quantity gives after combine as x + y.

Given that;

The ratio of cats to dogs = 4 : 5

Total number of dogs and cats = 27

Now,

We need to find the number of cats and dogs.

So, We can formulate;

Number of cats = 4x

Number of boys = 5x

So, We get;

4x + 5x = 27

9x = 27

Divide by 9, we get;

x = 3

Hence, Number of cats = 4x

                                    = 4 × 3

                                    = 12

And, Number of dogs = 5x

                                  = 5 × 3

                                 = 15

Thus, Number of cats are 12.

And, Number of dogs are 15.

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Answer:

i think x = 18.5

Step-by-step explanation:

6x-21 = 90°

6x = 90+21

6x = 111

x = 111/6

x = 18.5

Answer:

5

Step-by-step explanation:

The Mean of 7cm,15cm,12cm,5cm,h cm, and 13cm =10

⇒ (7+13+15+12+5+h+13)/7 = 10

⇒(65+h)/7=10

⇒65+h=70

⇒h=5

ANSWER

B. 10 laps in 205 seconds

EXPLANATION

If we write the rate of laps to seconds as a fraction we have:

I simplified the fraction and got 2/41. An equivalent rate must give the same simplified fraction. For option B:

We can reduce both rates to the same rate: 2 laps every 41 seconds. Therefore, these two rates are equivalent.

The probability that more than 16 ounces is dispensed in a cup is approximately 0.1587, or about 15.87%.

To solve this problem, we need to standardize the value of 16 ounces using the mean and standard deviation provided. We can do this by calculating the z-score, which is defined as:

z = (x - μ) / σ

where x is the value we want to standardize, μ is the mean, and σ is the standard deviation.

In this case, we want to find the probability that more than 16 ounces is dispensed, which can be expressed mathematically as:

P(X > 16)

where X is the random variable that represents the number of ounces of soda dispensed per cup.

To calculate this probability, we first standardize the value of 16 ounces using the mean and standard deviation provided. We have:

z = (16 - 12) / 4 = 1

Now we need to find the area under the standard normal distribution curve to the right of z = 1. We can use a standard normal distribution table or calculator to find this probability. Alternatively, we can use the complement rule, which states that:

P(X > 16) = 1 - P(X ≤ 16)

Since the normal distribution is continuous, we can use the cumulative distribution function (CDF) to find the probability of X being less than or equal to 16 ounces. Using the mean and standard deviation provided, we have:

P(X ≤ 16) = Φ((16 - 12) / 4) = Φ(1) = 0.8413

where Φ(z) is the CDF of the standard normal distribution.

Therefore, using the complement rule, we have:

P(X > 16) = 1 - 0.8413 = 0.1587

So the probability that more than 16 ounces is dispensed in a cup is approximately 0.1587, or about 15.87%.

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Answer: Yes

Step-by-step explanation:

Yes area should be right because you are finidng how much it covers which would be area. A way I used to remember it was you looking for the AREA it covers so that awnser is area! Hope that helped!