AABC ~ AXYZ
Find the missing side length, s
B
S
8
A
C
s = [?]
+x
A
5
Z
Enter

Answer:

Your answer would be 8.

Step-by-step explanation:

3 + 2 = 5

5 - 1 = 4

4 + 4 = 8

The statement that is true when calculating a 95% confidence interval for the difference between two means is that when the confidence interval ranges from a negative value to a positive value.

When calculating a 95% confidence interval for the difference between two means, the confidence interval represents a range of values that is likely to contain the true difference between the two population means. A confidence interval that ranges from a negative value to a positive value indicates that there is a range of possible differences between the two population means, including the possibility of no difference (i.e., the difference is zero).

However, since the confidence interval does not include zero, we can conclude (at 95% confidence) that there is a statistically significant difference between the two population means. On the other hand, if the confidence interval ranges from a negative value to a negative value or from a positive value to a positive value, we can conclude (at 95% confidence) that both population means are either negative or positive, respectively. Finally, if the confidence interval includes zero, we cannot conclude that there is a significant difference between the two population means.

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The final answer after subtraction is 00000100, in 8-bit two's complement form.

Firstly, we try and convert 3 into its binary form, and then its two's complement.

3 = 1(2¹) + 1(2⁰)

=> 3 = 00000011 (Binary form)

But in two's complement form, we invert all 0s to 1s and vice versa and then add 1 to the number.

So, two's complement of 3 is

11111100+1 = 11111101.

Now, for subtracting 13 from 3, we add the two's complement of 3 with the binary form of 13.

13 = 00001101

So,

00001101 + 11111101 = 0 00001010

We analyze this in two parts. The first bit is called the sign bit, where '0' represents a positive value, and '1' represents a negative value. So our result obtained here is positive.

The rest of the 8 bits are in normal binary form.

So the number in decimal form is 1(2³) + 1(2¹) = 8+2 = 10.

Thus, we get the already known result 13 - 3 = 10, in two's complement subtraction method.

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Answer:

2187

Step-by-step explanation:

Multiply 3 seven times in your calcultor to check this answer or look it up on google

Answer:

44u + 112

Step-by-step explanation:

Answer:

hope it help u !!!

Using Binomial Probability distribution,

the probability that exactly 4 of them never returned any merchandise in 2021 is 4845(0.05)²⁰.

We have given that ,

5% of customers never returned any merchandise.

probability of sucess ( i.e never returned any merchandise) = 5% = 0.05 = p

probability of failure (q) = 1- p = 0.05

Random sample (n) = 20

If X is random variable that customers who never returned any merchandise.

Using Binomial Probability distribution formula,

P(X= x) = ⁿCₓ(p)ˣ(q)⁽ⁿ⁻ˣ⁾

The probability that exactly 4 of them never returned any merchandise in 2021 = P(X=4)

= ²⁰C₄ (0.05)⁴ (0.05)¹⁶

= 20×19×18×17/4×3×2× 1 (0.05)²⁰

= 5×6×17×19/2 (0.05)20

= 4845(0.05)²⁰

Hence, the required probability is 4845(0.05)²⁰.

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Complete question:

Suppose 5% of Amazon customers never returned any merchandise in 2021.

if 20 amazon customers are randomly selected, what is the probability that exactly 4 of them never returned any merchandise in 2021?

The profit for the option writer is $3,900.

In this scenario, the option writer sold a put option on the Canadian dollar with an exercise price of USD 0.76/CAD. The premium received for the option was $0.039/CAD. The contract size is CAD 100,000, and the spot price at maturity is $0.76/CAD. However, since the spot price at maturity is equal to the exercise price of $0.76/CAD, the option is not exercised. As the option writer, the profit is determined by the premium received. In this case, the premium received per contract is $0.039/CAD. Multiplying this by the contract size of CAD 100,000, we get $3,900.

It's important to note that if the spot price at maturity had been lower than the exercise price, the option would have been exercised, resulting in a loss for the option writer equal to the difference between the exercise price and the spot price, multiplied by the contract size.

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Answer:

The length of AD is 70

Step-by-step explanation:

From the given figure

→ In triangle ADC

∵ EB // to DC

→ That means EB divides the sides AD and AC into parts proportional

∴ E divides AD into AE and ED

∴ B divides AC into AB and BC

∴ \(\frac{AE}{ED}\) = \(\frac{AB}{BC}\)

∵ ED = 60

∵ AB = 12

∵ BC = 72

→ Substitute them in the ratio above

∴ \(\frac{AE}{60}\) = \(\frac{12}{72}\)

→ By using cross multiplication

∵ AE × 72 = 12 × 60

∴ 72 AE = 720

→ Divide both sides by 72

∴ AE = 10

∵ AD = AE + ED

∴ AD = 10 + 60

∴ AD = 70

∴ The length of AD is 70

Answer:

Step-by-step explanation:

1

Answer: 1 divided by 8= 0.125

10 divided by 11= 0.90^

Step-by-step explanation:

the polynomial that represents the volume of the box is is 6x^3 +5x^2 -3x-2

V=lwh

l=x+1

w=2x+1

h=3x-2

V=(x+1)(2x+1)(3x-2)

V=(x*2x+x*1+1*2x+1*1)(3x-2)

V=(2x²+x+2x+1)(3x-2)

V=(2x²+3x+1)(3x-2)

V=2x²*3x+2x²*(-2)+3x*3x+3x*(-2)+1*3x+1*(-2)

V=6x³-4x²+9x²-6x+3x-2

V=6x³+5x²-3x-2

complete question is

Find the volume of the box. Use the formula V = lwh.

Rectangular box with sides x plus 1, 2x plus 1, and 3x minus 2.

6x3 – 2

6x3+ x – 2

6x3 – 13x2 – 3x – 2

6x3 + 5x2 – 3x – 2

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This Bay store can also be described as a big box retailer store.

Big Box Retailer

A big box retailer is a physically enormous retail store that is typically a component of a chain of stores (also known as a hyper store, supercenter, superstore, or megastore). By extension, the phrase, big box retailer can also refer to the business that runs the store.

The Bay Store as a Big Box

There are numerous retail chains that only operate in Canada, aside from the large American big box retailer stores like Walmart Canada and the formerly-existent Target Canada. These include places like Hudson's Bay by Home Outfitters, Loblaws by Real Canadian Superstore, Rona, Winners by HomeSense, Canadian Tire by Mark's & Sport Chek, Shoppers Drug Mart, Chapters by Indigo Books and Music, Sobeys, and several others.

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The hypotheses for the test are H₀: σ₁² = σ₂² and H₁: σ₁² ≠ σ₂². This is a two-tailed test to assess if there is a difference in the standard deviations of sound levels between the areas designated as "casualty doors" and operating theaters. The claim being investigated is whether or not there is a difference in the standard deviations.

The hypotheses for the test are:

H₀: σ₁² = σ₂² (There is no difference in the standard deviations of the sound levels between the areas designated as "casualty doors" and operating theaters.)

H₁: σ₁² ≠ σ₂² (There is a difference in the standard deviations of the sound levels between the areas designated as "casualty doors" and operating theaters.)

This hypothesis test is a two-tailed test because the alternative hypothesis is not specifying a direction of difference.

To substantiate the claim that there is a difference in the standard deviations, we will conduct a two-sample F-test at a significance level of 0.10, comparing the variances of the two groups.

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Answer:

They came to different conclusions because if you graph n+10 and 2n+3, eventually 2n+3 will surpass n+10 (see picture for diagram). Since they both plugged in different numbers for n, they received different answers to the question.

Answer:

$1,800

Step-by-step explanation:

Given

Total revenue last year = $2,800

If they spent 1/4 of their revenues on marketing;

Amount spent on marketing = 1/4 * 2800

Amount spent on marketing = $700

Remaining money = 2800 - 700

Remaining money = $2100

If 1/7 of the remaining money is spent on upgrading their facilities, then;

Amount spent on upgrading facilities = 1/7 * 2100

Amount spent on upgrading facilities = $300

Total amount spent on marketing and facilities  = $700 + $300

Total amount spent on marketing and facilities  = $1000

Amount left = $2,800 - $1,000

Amount left = $1,800

It took Amy a total of 18 1/4 minutes (or 18 minutes and 15 seconds) to run her slowest and fastest miles combined, rounded to the nearest 1/4 of a minute.

To find out how long it took for Amy to run her slowest and fastest mile combined, we need to first determine her slowest and fastest mile times.

From the frequency table, we can see that the slowest mile time recorded is 9 2/4 (which can be simplified to 9 1/2) and it occurred once. The fastest mile time recorded is 8 3/4 and it occurred twice.

To find the total time it took for Amy to run her slowest and fastest miles combined, we need to add these two times together.

9 1/2 + 8 3/4 = 18 1/4

Therefore, it took Amy a total of 18 1/4 minutes (or 18 minutes and 15 seconds) to run her slowest and fastest miles combined, rounded to the nearest 1/4 of a minute.

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Here is the complete question:

Amy ran 8 miles. She recorded how long it took her to run each mile, rounded to the nearest 1/4 of a minute?

TIME                                                  FREQUENCY

8 3/4                                                     2

9                                                            3

9 1/4                                                      2

9 2/4                                                      1

How long did it take army to run her slowest and fastest mile combined?

Answer:

The value of x is -16.

Step-by-step explanation:

☆Let's solve!

\( \: \: \: \: \: \: \: \: \: \: \frac{2}{3} x + 1 = \frac{1}{6} x - 7 \\ \frac{ - \frac{1}{6}x \: \: \: \: \: \: \: \: \: = - \frac{1}6{x} }{ \frac{1}{2}x + 1 = - 7} \\ \: \: \: \: \: \frac{ - 1 = - 1}{ \frac{ \frac{1}{2} x}{ \frac{1}{2} } = \frac{ - 8}{ \frac{1}{2} } } \\ x = - 16\)

Answer:

96 tickets were unsold

Answer:

The answer to your question is x= −3 or it can be x=3

Steps of solving

The first step we have to do to solve this equation is to Factor left side of our equation

(x+3)(x−3)(x^2+10)=0

The second step that we would have to do would be Setting the factors that equal to 0.

You can go with any of these

x+3=0, x−3=0 or you can lastly go with x^2+10=0

And that's how you would get your answer : x= −3 or x=3

Answer:

A and B

Step-by-step explanation:

Nadeen started with 18 tokens and will lose 3 with every game he/she/they play.

The equation that would represent this is a) 18 - 3x. b, when distributed, is also 18 - 3x.

3(6 - x) ---> multuply 3 with 6 and 3 with x

18 - 3x

Answer:

Option A

Step-by-step explanation:

Nadeen started with 18 tokens.

Since each game costs 3 tokens, we can see how much she spent using:

\(3x\)

To find how many tokens she have left, we can use:

18 - 3x

Option A should be the correct answer!

Hope this helps!

The equation x = 4t/(t^2 + 1) can be expressed as a function of x and y as y = (16x^2(4 - x^2)^2)/(x^4 + 1).

To eliminate the parameter t, we can start by isolating t in terms of x from the given equation x = 4t/(t^2 + 1). Rearranging the equation, we get t = x/(4 - x^2).

Now, substitute this expression for t into the equation y = (4t)^2/(t^2 + 1). Replace t with x/(4 - x^2) to get y = (4(x/(4 - x^2)))^2/((x/(4 - x^2))^2 + 1).

Simplifying further, we have y = (16x^2/(4 - x^2)^2)/((x^2/(4 - x^2)^2) + 1).

To combine the fractions, we need a common denominator, which is (4 - x^2)^2. Multiply the numerator and denominator of the first fraction by (4 - x^2)^2 to get y = (16x^2(4 - x^2)^2)/(x^2 + (4 - x^2)^2).

Simplifying the numerator, we have y = (16x^2(4 - x^2)^2)/(x^2 + 16 - 8x^2 + x^4 + 8x^2 - 16x^2).

Further simplifying, we get y = (16x^2(4 - x^2)^2)/(x^4 + 1)

Therefore, the equation x = 4t/(t^2 + 1) can be expressed as a function of x and y as y = (16x^2(4 - x^2)^2)/(x^4 + 1).

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Answer:

24 A-(8+8)

Step-by-step explanation:

Answer: 4(6a-4) This is one equivalent expression of 24a-16.

Answer:

O is largest, C is medium, and T is smallest

Step-by-step explanation:

You need to pay close attention to the side length. The higher the length, the smaller the angle.

:)

Explanation:

x = number of coins Liam has in his bag

Each bag Mia has is 3 greater than x.

So x+3 is the number of coins in one bag for Mia. Two such of her bags gives 2(x+3) = 2x+6 coins.

Answer:

Parent Function: y = x^2

Vertex: (1,3)

Axis of Symmetry: x = 1

Y-Intercept(s): (0,1)

X-Intercept(s): (1−√62,0),(1+√62,0)

Step-by-step explanation:

hope this helps! =)

Answer:

The answer should be -2 its always the last whole number of the equation this is y=mx+b so the y intercept should be the number in the b space.

Answer:

Well 40% of 120 is 48 so 48 students

Step-by-step explanation: