plsss answer this rlly need dont answer this for just points plsss :(

Answer: Option D: $7803

Step-by-step explanation:

just multiply 459 by 17 and you get your answer.

Answer:

n is equal to 17 if you want you can plug the number to both equation and try to see if both are equal if they are equal that means you did it right

Answer:

n = 17

Step-by-step explanation:

The opposite angles of a Parallelogram are equal.

So,

4n-2 = 2n+32

4n-2n = 32+2

2n = 34

Dividing both sides by 2

n = 17

The hcf and the lcm of the expressions are x and 6xyz, respectively

From the question, the expressions are given as

3xy and 2yz

The LCM

We start by calculating the LCM of the expressions

Recall that the expressions are given as 3xy and 2yz

Expand both expressions

So, we have

3xy = 3 * x * y

2yz = 2 * y * z

Multiply all the factors (without repetition)

So, we have

LCM = 2 * 3 * x * y * z

Evaluate the products

LCM = 6xyz

The HCF

Recall that the expressions are given as 3xy and 2yz

Expand both expressions

So, we have

3xy = 3 * x * y

2yz = 2 * y * z

Multiply all common factors

So, we have

HCF = x

Hence, the HCF is x

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θ lies in the second quadrant (QII).

Given that csc(θ) > 0 and tan(θ) < 0, we can determine the quadrant in which θ lies based on the signs of the trigonometric function. Recall the signs of trigonometric functions in each quadrant: In the first quadrant (QI), all trigonometric functions are positive. In the second quadrant (QII), only sin(θ) and csc(θ) are positive. In the third quadrant (QIII), only tan(θ) and cot(θ) are positive. In the fourth quadrant (QIV), only cos(θ) and sec(θ) are positive. Given that csc(θ) > 0, we can conclude that θ lies in either QI or QII since csc(θ) is positive in both quadrants. Now, considering that tan(θ) < 0, which means the tangent function is negative, we can narrow down the possibilities. In QI, both tan(θ) and csc(θ) are positive, so it does not satisfy the given condition tan(θ) < 0. Therefore, θ must lie in QII. In conclusion, θ lies in the second quadrant (QII).

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Answer:

Step-by-step explanation:

finding the smallest possible distance from the line to the origin follows as

the normal vector=(-1,-2,1)

using direction vector we need to create the equation of the plane

-1(x-2)-2(y-3)+1(z+7)=0

we get;

-x+2-2y+6+z+7=0

-x-2y+z+13=0

x=2-t; y=2-3t; z=-7+t

on substituting;

-1(2-t)-2(3-2t)+1(-7+t)+13=0

-2+t-6+4t-7+t+13=0

we get;

t=1

so point is(1,1,-6)

distance from point to origin

d=\(\sqrt{(1^2+1^2+(-6)^2)}\)=\(\sqrt{38}\)

therefore

the answer is \(\sqrt{38}\)=6.16

Step-by-step explanation:

1. 3.6 x 10^-1

2. 3.1 x 10^6

3. 5.3 x 10^-6

4. 4.2 x 10^-1

The  reduced exact values for the root of f(x) = x² + 10·x - 5, obtained using the quadratic formula are; x = (-5 + √(30)) and x = (-5 - √(30))

The quadratic formula is a formula that is used to find the roots of a quadratic equation, by plugging in the coefficients of a quadratic equation into the formula.

The roots of the quadratic function, f(x) = x² + 10·x - 5, can be obtained using the quadratic formula as follows;

The quadratic formula, which can be used to find the roots of the quadratic function, f(x) = a·x² + b·x + c is; x = (-b ± √(b² - 4·a·c))/(2·a)

The function f(x) = x² + 10·x - 5, indicates;

a = 1, b = 10, and c = -5, therefore;

x = (-10 ± √(10² - 4 × 1 × (-5)))/(2 × 1) = (-10 ± √(120))/2

(-10 ± √(120))/2 = (-5 × 2 ± 2 × √(30))/2

(-5 × 2 ± 2 × √(30))/2 =  (-5 ± √(30))/2

The roots of the quadratic function are;

x = (-5 + √(30))/2, and x = (-5 - √(30))/2

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The rate, in inches per minute, at which the radius of the sphere is changing when the radius is 4 inches is 2.83

What is the Volume of a Sphere?

The capacity of a sphere is its volume. It is the area that the sphere occupies. Cubic measurements of a sphere's volume include m3, cm3, in3, etc. The sphere has a circular, three-dimensional form. Its form is determined by three axes: the x, y, and z axes. Sports like basketball and football are all instances of spheres with volume.

Since the cross-section of the sphere is a circle, the volume in this case is dependent on the diameter of the sphere's radius. The area or region of a sphere's outer surface is known as its surface area. We may use the following formula to get the volume of a sphere whose radius is "r":

Here, In the question, It is given that:

Radius = 4inch.

Rate of increase = 569 cubic inches;

So, using the Volume of Sphere, formula:

\(\begin{aligned}v=\frac{4}{3} \pi r^3 \\\frac{d v}{d t} &=\frac{d}{d t}\left[\frac{4}{3} \pi r^3\right] \\&=\frac{4 \pi}{3}\left(3 r^2\right) \frac{d r}{d t} \\\frac{d v}{d t} &=4 \pi r^2 \frac{d r}{d t}\end{aligned}\)

\(\begin{aligned}&\frac{d r}{d t}=\frac{\frac{d v}{d t}}{4 \pi r^2}\\&\left.\frac{d r}{d t}=\frac{569}{(4 \pi)(4)^2}=\frac{d}{d t}_{r=4}^{d r^2}=569\right]\\&\frac{d v}{d t}=\frac{569}{64 \pi} \sim 2.83\end{aligned}\)

Hence,  the rate, in inches per minute, at which the radius of the sphere is changing when the radius is 4 inches is 2.83

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Answer:

graph{y=4x+1 [-10, 10, -5, 5]}

Step-by-step explanation:

Since the equation is linear/straight in the form

y = mx + c, you can determine the slope/gradient (m) and y-intercept (c).

m = 4

c = 1

To graph this equation, you'll need to find 2 points on the line and join them together. We know one of the points is (0, 1) as the y-intercept is 1.

You can find another point by substituting an arbitrary number into

x or y in the equation. In this example, I'll substitute 1 into x to find the y coordinate where the x coordinate is 1.

y = 4 (1) + 1

y = 4 + 1

y = 5

So, the second point would be (1, 5).

If you join the points (0, 1) and (1, 5) on a graph, this would be the line of the equation.

hope this helps!

The coordinates for the point for this equation  \(y - 4 = -\frac{1}{3} (x-7),\) is at (7, 4)

The standard form of the equation in point-slope form is expressed as:

\(y-y_0=m(x-x_0)\\\)

m is the slope of the line

\((x_0, y_0)\) is any point on the line

Given the equation \(y - 4 = -\frac{1}{3} (x-7),\)

Compare the original equation with the given equation to get the coordinate for the point \((x_0, y_0)\).

On comparison:

\(-x_0=-7\\x_0=7\\-y_0=-4\\y_0=4\)

Hence the coordinates for the point is at (7, 4)

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a)The formula for the graph of $100 at 8% loss per year will be:

So the first graph function is:

The graph is shown below:The

The point (1,92) lies on this graph.

b) The second graph of $200 at 10% loss per year is given by the equation:

The graph is shown below:

As seen the point (1,180) lies on second graph.

c) The equation for $100 at 10% loss per year is:

The graph is shown below:

The point (1,90) lies on this graph.

d) The equation for $200 at 8% loss per year is given by:

The graph is shown below:

As seen the point (1,184) lies on the graph.

So:

$100 at 8% loss per year has the point (1,92).

$200 at 10% loss per year has the point (1,180).

$100 at 10% loss per year has the point (1,90).

$200 at 8% loss per year has the point (1,184)

Answer:

" There are 23 people in the club."

Step-by-step explanation:

We want to know how many member's friends came to the meeting.

We know that:

There are 23 people in the club

5 members of the club, invited 2 friends each.

So we have 5 times 2 friends invited:

Then there are 5*2 = 10 people invited to the first meeting.

Notice that the fact that there are 23 people in the club is never used, them the information that is not necessary to solve this problem is " There are 23 people in the club."

Answer:

$628

Step-by-step explanation:

The price before tax was 814.27/1.07 = 761

761 - 99 - 34 = 628

The correct formula to calculate the number of tires, t, needed for c cars per day is t = c/4, which is option b).


The formula that shows how to calculate the number of tires, t, needed for c cars per day is option b) t = c/4.

To understand this formula, let's break it down step by step:

1. Each car needs four regular tires and one spare tire for the trunk. So, the total number of tires needed for one car is 4 + 1 = 5.

2. If we want to calculate the total number of tires needed for c cars, we can multiply the number of cars by the number of tires needed per car, which is 5. So, the formula becomes t = 5c.

3. However, we need to find the number of tires needed, which is represented by t. Since we have t on the left side of the equation, we can rearrange the formula by dividing both sides by 5: t/5 = c.

4. Now, we have the number of tires needed (t) expressed in terms of the number of cars (c), but we want to find the number of cars needed given the number of tires (t).


To do this, we can rearrange the formula again by dividing both sides by 4: t/4 = c/4.

Therefore, the correct formula to calculate the number of tires, t, needed for c cars per day is t = c/4, which is option b).

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Answer:

8+3x=20

4 hours

Step-by-step explanation:

8+3x=20

3x=12

x=4

The Upper Control Limit (UCL) and Lower Control Limit (LCL) are calculated for different data sets, as specified in the given values.

The UCL and LCL are statistical control limits used in process control to determine if a process is in a stable and predictable state. These limits define the range within which data points should fall if the process is under control.

In each case provided (A, B, C, D, E), the UCL and LCL values are given. These values represent the calculated control limits for the respective data sets.

To calculate the control limits, a specific statistical method such as the ± 3σ (sigma) method may have been used. This method sets the UCL and LCL at three standard deviations above and below the mean.

The UCL represents the upper threshold or upper boundary, while the LCL represents the lower threshold or lower boundary. These limits help identify any potential deviations or out-of-control situations in the data.

By applying the given values, the corresponding UCL and LCL for each data set can be calculated. These limits are important for quality control and process monitoring, ensuring that the data falls within acceptable ranges.

To calculate the UCL and LCL using ±3σ limits, we use the following formulas:

UCL = Mean + 3σ
LCL = Mean - 3σ

Here, σ represents the standard deviation of the data set. The ±3σ limits provide a range that encompasses most of the data points in a normal distribution, with approximately 99.7% of the data falling within this range.
A) For data set A:
UCL = 7.437
LCL = -2.237

B) For data set B:
UCL = 7.82
LCL = 0

C) For data set C:
UCL = 8.382
LCL = 0

D) For data set D:
UCL = 7.82
LCL = -2.22

E) For data set E:
UCL = 9.112
LCL = 0

The ±3σ limits are derived from the standard deviation (σ) of the data set. Unfortunately, the standard deviation is not provided in the given information. If you have the standard deviation available, we can proceed to calculate the UCL and LCL using the formulas UCL = Mean + 3σ and LCL = Mean - 3σ.

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Question - What are the upper control limit (UCL) and lower control limit (LCL) using a ±3σ limit for the given data sets?

A) For data set A, the UCL is 7.437 and the LCL is -2.237.
B) For data set B, the UCL is 7.82 and the LCL is 0.
C) For data set C, the UCL is 8.382 and the LCL is 0.
D) For data set D, the UCL is 7.82 and the LCL is -2.22.
E) For data set E, the UCL is 9.112 and the LCL is 0.

Answer: |81 - (-29)|==> C

Step-by-step explanation:

h=high temperature

h=81

l=low temperature

l=-29

d=difference in high and low temperature

h-l=d

81-(-29)=d

81+29=d

d=110 ==> |81 - (-29)|=|81 +29|=|110|=110

|81 - (-29)|==> C

|81 -29|=|52|=52

-29 + 81=81-29=52

a) Px * x + Py * y = I.

Solving these equations simultaneously will give us the Marshallian demand for pants (x).

b) Px * x + Py * y = I.

Solving these equations simultaneously will give us the Marshallian demand for shirts (y).

c) ∂U/∂x = 0.4 * x^(-0.6) * y^0.6 = 0.

Solving this equation will give us the Hicksian demand for pants (x) as a function of y.

d) ∂U/∂y = 0.6 * x^0.4 * y^(-0.4) = 0.

Solving this equation will give us the Hicksian demand for shirts (y) as a function of x.

a) Calculate Marshallian Demand for pants (x):

To find the Marshallian demand for pants, we need to maximize the utility function U(x, y) = x^0.4 * y^0.6 with respect to x. We'll use the Lagrange multiplier method to solve this constrained optimization problem.

Let's define the Lagrangian function L as follows:

L(x, y, λ) = x^0.4 * y^0.6 - λ(Px * x + Py * y - I).

Now, we differentiate L with respect to x, y, and λ and set the derivatives equal to zero:

∂L/∂x = 0.4 * x^(-0.6) * y^0.6 - λ * Px = 0,

∂L/∂y = 0.6 * x^0.4 * y^(-0.4) - λ * Py = 0,

Px * x + Py * y = I.

Solving these equations simultaneously will give us the Marshallian demand for pants (x).

b) Calculate Marshallian Demand for shirts (y):

Similarly, to find the Marshallian demand for shirts, we need to maximize the utility function U(x, y) = x^0.4 * y^0.6 with respect to y. We'll use the Lagrange multiplier method again.

Let's define the Lagrangian function L as follows:

L(x, y, λ) = x^0.4 * y^0.6 - λ(Px * x + Py * y - I).

Now, we differentiate L with respect to x, y, and λ and set the derivatives equal to zero:

∂L/∂x = 0.4 * x^(-0.6) * y^0.6 - λ * Px = 0,

∂L/∂y = 0.6 * x^0.4 * y^(-0.4) - λ * Py = 0,

Px * x + Py * y = I.

Solving these equations simultaneously will give us the Marshallian demand for shirts (y).

c) Calculate Hicksian Demand for pants:

Hicksian demand represents the demand for a good at constant utility. To calculate the Hicksian demand for pants, we need to differentiate the utility function with respect to x and y, equate it to zero, and solve for x in terms of y.

Differentiating the utility function with respect to x:

∂U/∂x = 0.4 * x^(-0.6) * y^0.6 = 0.

Solving this equation will give us the Hicksian demand for pants (x) as a function of y.

d) Calculate Hicksian Demand for shirts:

To calculate the Hicksian demand for shirts, we need to differentiate the utility function with respect to y:

∂U/∂y = 0.6 * x^0.4 * y^(-0.4) = 0.

Solving this equation will give us the Hicksian demand for shirts (y) as a function of x.

Please note that without specific values for prices (Px and Py) and income (I), we cannot provide the exact quantities of pants and shirts demanded. The calculations outlined above will give the demand functions as functions of prices and income.

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The difference is that tropical rainforests are near the equator while temperate rainforests are found further north near coastal areas. The Option A is correct.

The tropical rainforests are located near equator and spans across regions such as the Amazon Basin in South America, the Congo Basin in Africa and parts of Southeast Asia. These rainforests are characterized by high temperatures and humidity throughout the year with no distinct seasons.

The temperate rainforests are found further north, primarily in coastal areas of temperate regions. Examples include the Pacific Northwest in North America which experience milder temperatures compared to tropical rainforests and have distinct seasonal variations.

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(a)  (1203)4 is equal to 99 in decimal and 12 in hexadecimal.

(b)  (5243)8 is equal to 2211 in decimal and 1523 in hexadecimal.

To convert numbers from different bases to decimal using the direct method, we multiply each digit of the number by the corresponding power of the base and sum the results. To convert to hexadecimal using the intermediary binary conversion method, we first convert the number to binary and then group the binary digits into groups of 4, starting from the rightmost digit, and convert each group to its hexadecimal equivalent.

(a) Converting (1203)4 to decimal:

(1203)4 = 1 * 4³ + 2 * 4² + 0 * 4¹ + 3 * 4⁰

= 64 + 32 + 0 + 3

= 99

Converting (1203)4 to hexadecimal:

First, convert (1203)4 to binary:

(1203)4 = (10010)2

Next, group the binary digits into groups of 4:

(10010)2 = (0001 0010)2

Finally, convert each group to its hexadecimal equivalent:

(0001 0010)2 = (12)16

Therefore, (1203)4 is equal to 99 in decimal and 12 in hexadecimal.

(b) Converting (5243)8 to decimal:

(5243)8 = 5 * 8³ + 2 * 8² + 4 * 8¹ + 3 * 8⁰

= 2048 + 128 + 32 + 3

= 2211

Converting (5243)8 to hexadecimal:

First, convert (5243)8 to binary:

(5243)8 = (101 010 100 011)2

Next, group the binary digits into groups of 4:

(101 010 100 011)2 = (0001 0101 0010 0011)2

Finally, convert each group to its hexadecimal equivalent:

(0001 0101 0010 0011)2 = (1523)16

Therefore, (5243)8 is equal to 2211 in decimal and 1523 in hexadecimal.

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The linear model for this data is y = 0.63t + 4.922 and the estimated population of Greensboro in 2015 was 11,530

What is slope?

Slope is a measure of the steepness of a line. It is defined as the change in y-coordinate divided by the change in x-coordinate between any two points on the line.

a. To find the linear model for this data, we need to determine the equation of the line that passes through the two given points: (0, 4.922) and (6, 9.1). The slope of this line can be calculated as:

slope = (change in y) / (change in t)

slope = (9.1 - 4.922) / (6 - 0)

slope = 0.63

Using the point-slope form of a linear equation, we can write the equation of the line as:

y - 4.922 = 0.63(t - 0)

Simplifying, we get:

y = 0.63t + 4.922

Therefore, the linear model for this data is y = 0.63t + 4.922.

b. To estimate the population in 2015, we need to find the value of y when t = 11 (since 2015 is 11 years after 2004). Substituting t = 11 into the linear model, we get:

y = 0.63(11) + 4.922

y = 11.53

Therefore, the estimated population of Greensboro in 2015 was 11,530 (rounded to the nearest whole number).

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The scale factor for two hexagonal prisms is obtained as 5.20 : 1.

What is scale factor?

The scale factor of a shape refers to the amount by which it is increased or shrunk. It is applied when a 2D shape, such as a circle, triangle, square, or rectangle, needs to be made larger.

Since the two figures are similar, their corresponding lengths, widths, and heights are proportional.

Therefore, the scale factor between them is the ratio of any corresponding lengths.

One possible choice is to use the height of the two hexagonal prisms as the corresponding length.

Let h1 be the height of the first hexagonal prism, and h2 be the height of the second hexagonal prism.

Then we have -

scale factor = h2 / h1

To find the heights, we can use the formula for the volume of a hexagonal prism -

V = (3√3 / 2) × (base area) × height

For the first hexagonal prism, we are given that V = 432 yd³.

We can solve for the base area by rearranging the formula -

base area = (2/3√3) × (V / height)

Plugging in the values, we get -

base area = (2/3√3) × (432 / h1)

base area = 96 / h1√3

For the second hexagonal prism, we are given that V = 11664 yd³.

Again, we can solve for the base area -

base area = (2/3√3) × (V / height)

base area = 2592 / h2√3

Since the two hexagonal prisms are similar, their base areas are proportional.

Therefore, we can set up a proportion -

base area of first hexagonal prism / base area of second hexagonal prism = scale factor²

(96 / h1√3) / (2592 / h2√3) = scale factor²

Simplifying the fraction, we get -

scale factor² = (1/27) × (h2 / h1)

But we know that V1 / V2 = (h1 / h2)^2, since the volumes are proportional to the cube of the height.

So we can substitute V1 = 432 and V2 = 11664 -

432 / 11664 = (h1 / h2)²

h1 / h2 = √(432 / 11664) = √(1/27) = 1 / 3√3

Plugging this into the formula for the scale factor, we get -

scale factor = h2 / h1 = 3√3 / 1 = 3√3

Therefore, the scale factor of the figure on the left to the figure on the right is 3√3 : 1, or in decimal form approximately 5.20 : 1.

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Answer:

54.75 is the answer I got

Step-by-step explanation:

first I calculated 75÷1.25 then subtracted the fare which is 5.25

Answer:

11 degrees

Step-by-step explanation:

The bottom triangle has 2 given angle, therefore we know the 3rd angle has to be 29 degrees. Given that the 2 lines are parallel, we know that the upper triangle has 140, 29, and x degrees. 180-140-29=x=11 degrees

Hope this helped, feel free to leave a comment if you still have any questions!

Cheers!

Answer:

0.19

Step-by-step explanation:

;)

Answer:

1144

Step-by-step explanation:

100 + 98 + 96 +.... + 78+76 =

(12-0)/2 (176)  

(6.5) (176) = 1144

The sum of the series will be 1068.

We have the following expression -

\(\sum_{i=0}^{12} 100 - 2i\)

We have to rewrite the series as the sum.

A series in mathematics is the sum of a list of numbers that are generated according to some pattern.

We have the following expression -

\(\sum_{i=0}^{12} 100 - 2i\)

The terms of this series can be calculated by calculating the value of the function at different values of i.

The series is as follows -

100 + 98 + 96 +.... + 78+76

This is an arithmetic progression with a = 100 and d = - 2 and n = 12. The sum of this series is -

\(S = \frac{n}{2} \times {2a + (n-1)d}\)

S = \(\frac{12}{2} [{2 \times 100 + (12 -1)(-2)] = 6[200+ 11 \times -2] = 6[200 -22]\)

S = 6 x 178 = 1068

The sum of the series will be 1068.

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Answer:

24 slices

Step-by-step explanation:

There are 3 whole pizzas. He cuts each of them into eighths. That means eight slices. 3 times 8 is 24. There are a total of 24 slices. This can also look like this: 24/8   or 24 over 8.  Which also equals to 3.

Answer:

2

Step-by-step explanation:

-3^3+9/3*-3= 2 ypu have tu substitute the x by -3 always.