Answer:
ABC=CDA
and #5 is CPCTC
Step-by-step explanation:
hope this helps
At Paul’s Bunyan’s logging camp, the cook scrambled 20 eggs for every 3 loggers. How many eggs did he need for the 288 loggers at the camp?
Answer:
1,920
Step-by-step explanation:
288/3 = 96
96 x 20 = 1920
Answer:
1920 eggs
Step-by-step explanation:
make a ratio and cross multiply
20/3=x/288
3x=5760
x=1920
Find the value of x. Round your answer to the nearest tenth
(Will give brainiest)
Answer:
Its 67.9 but technically its 67.912 *hope this helps
Step-by-step explanation:
Right scalene triangle.
Sides: a = 66 b = 16 c = 67.912
Area: T = 528
Perimeter: p = 149.912
Semiperimeter: s = 74.956
Angle ∠ A = α = 76.373° = 76°22'23″ = 1.333 rad
Angle ∠ B = β = 13.627° = 13°37'37″ = 0.238 rad
Angle ∠ C = γ = 90° = 1.571 rad
Height: ha = 16
Height: hb = 66
Height: hc = 15.55
Median: ma = 36.674
Median: mb = 66.483
Median: mc = 33.956
Inradius: r = 7.044
Circumradius: R = 33.956
Vertex coordinates: A[67.912; 0] B[0; 0] C[64.142; 15.55]
Centroid: CG[44.018; 5.183]
Coordinates of the circumscribed circle: U[33.956; 0]
Coordinates of the inscribed circle: I[58.956; 7.044]
Exterior (or external, outer) angles of the triangle:
∠ A' = α' = 103.627° = 103°37'37″ = 1.333 rad
∠ B' = β' = 166.373° = 166°22'23″ = 0.238 rad
∠ C' = γ' = 90° = 1.571 rad
Given the function g(x)=x^2+3 ,evaluate (-2,y)
Answer:
im not sure if this is what you're looking for but g=x^4 and the y intercept is g(0)=0
Step-by-step explanation:
For question #5, which is y>2x−5. What is the y-intercept?
Answer:
-5
Step-by-step explanation:
the average number of dropout for a school dsitrict has been 305 per year with a standard eveiation of 50. what is the probility that the number of dropouts next year will be: g
The probability that the number of dropouts next year will be exactly 305 is virtually zero, the probability of less than 305 is 68%, greater than 305 is 32%, and within one standard deviation of 305 is 95%.
Probability of dropouts next year being exactly 305: 0
Probability of dropouts next year being less than 305: 0.68
Probability of dropouts next year being greater than 305: 0.32
Probability of dropouts next year being within one standard deviation of 305: 0.95
The probability that the number of dropouts next year will be exactly 305 is virtually zero. This is because the standard deviation of 50 suggests that the number of dropouts is likely to be different from 305.
The probability that the number of dropouts next year will be less than 305 can be calculated using the normal distribution. The probability that the number of dropouts will be less than 305 is approximately 0.68, or 68%.The probability that the number of dropouts next year will be greater than 305 can be calculated using the normal distribution. The probability that the number of dropouts will be greater than 305 is approximately 0.32, or 32%.The probability that the number of dropouts next year will be within one standard deviation of 305 (i.e. between 255 and 355) can be calculated using the normal distribution. The probability that the number of dropouts will be within one standard deviation of 305 is approximately 0.95, or 95%.
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The function f(x) is shown on the graph.
On a coordinate plane, a curved line with 3 arcs, labeled f of x, crosses the x-axis at (negative 2, 0), (1, 0), and (3, 0), and the y-axis at (0, negative 6).
If f(x) = 0, what is x?
Answer:
\(x=-2,1,3\)
Step-by-step explanation:
Given: The curved line represented by the function \(f(x)\) crosses the x-axis at \((-2,0),(1,0),(3,0)\) and y-axis at \((0,-6)\)
To find: value of x for which \(f(x)=0\)
Solution:
\(f(x)=0\) gives those values of x for which the curve represented by the given function cuts the x-axis.
According to question, the curve cuts the x-axis at \(x=-2,1,3\)
The values of x, when f(x) = 0 are the y-intercepts of the graph, and the values are -2, 1 and 3
The points on the function on the graph are given as:
\((x,y) = \{(-2,0), (1,0), (3,0), (0,-6)\}\)
In the above ordered pairs, the points where y or f(x) equals 0 are:
\((x,y) = \{(-2,0), (1,0), (3,0)\}\)
Remove the y-values
\(x = \{-2, 1, 3\}\)
The above set represents the values of x, when f(x) = 0.
Hence, the values of x, when f(x) = 0 are -2, 1 and 3
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The figure below shows one of the steps used in inscribing a square in a circle.
Answer:
Step-by-step explanation:
Organize from least to greatest
Answer:
y=31x/15 < y=27x/13 < y=15x/7 < y=13x/6 < y=11x/5 < y=21x/9 (=7x/3) < y=19x/8
Step-by-step explanation:
since all equations base on a linear, simple expression of x, we can simply compare the fractions.
in general, the bigger the number at the bottom, the smaller the individual fraction. that is our first indicator.
we then notice that many fractions represent the value of 2 plus one fraction.
31/15 = 2 1/15
27/13 = 2 1/13
15/7 = 2 1/7
13/6 = 2 1/6
11/5 = 2 1/5
the only exceptions are 21/9 and 19/8
but 21/9 is actually 7/3 = 2 1/3
and fits therefore into the list above.
that leaves 19/8 = 2 3/8.
the list above can be sorted based on the single fraction at the end (remember, the bigger the number at the bottom, the smaller the value). so, from least to greatest :
2 1/15 (31/15)
2 1/13 (27/13)
2 1/7 (15/7)
2 1/6 (13/6)
2 1/5 (11/5)
2 1/3 (7/3 = 21/9)
where did now 2 3/8 fit in ?
well, 3/8 is almost 1/2 (so, relatively big), and we start our comparison with the biggest number in the list so far :
1/3 (from 2 1/3).
what is bigger - 1/3 or 3/8 ?
let's find the smallest number that can be divided by 3 and by 8. that would be 24. so now we bring both fractions to the same base of 24.
1/3 = 8/24
3/8 = 9/24
=> 3/8 > 1/3
and therefore, 19/8 is the largest value and at the end of the list.
Use mathematical induction to show that when n is an exact power of 2, the solution of the recurrence
T(n)={2if n=22T(n/2)+nif n=2k, for k>1is t(n)=nlgn
By mathematical induction, T(n) = nlog(n) for all n that are exact powers of 2.
We will prove by mathematical induction that T(n) = nlog(n) for all n that are exact powers of 2.
Base case: For n = 2, we have T(2) = 2 as given.
Inductive hypothesis: Assume that T(\(2^k\)) = \(2^k\) × log(\(2^k\)) for some positive integer k.
Inductive step: We need to show that T(\(2^{(k+1)}\)) = \(2^{(k+1)}\) × log(\(2^{(k+1)}\)).
Using the recurrence relation, we have:
T(\(2^{(k+1)}\)) = 2T(\(2^k\)) + \(2^{(k+1)}\)
Substituting T(\(2^k\)) = \(2^k\) × log(\(2^k\)) from the inductive hypothesis, we get:
T(\(2^{(k+1)}\)) = 2(\(2^k\) × log(\(2^k\))) + \(2^{(k+1)}\)
= \(2^{(k+1)}\) × k × log(2) + \(2^{(k+1)}\)
= \(2^{(k+1)}\) × (k+1)
= \(2^{(k+1)}\) × log(\(2^{(k+1)}\))
For every n that are precise powers of 2, T(n) = nlog(n) is the result of mathematical induction.
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determine the unit vector normal to the plane when a and b are equal to (7)i (8)j – (2)k and 9i– 4j– 5k respectively. the unit vector normal to the plane is λ = - 32 i 49 j - 44 k.
The unit vector normal to the plane defined by a and b is λ = -32i/49 + 49j/49 - 44k/49.
To find the unit vector normal to a plane defined by two non-collinear vectors, we can use the cross product. The cross product of two vectors a and b produces a vector that is orthogonal to both a and b, and has a magnitude equal to the area of the parallelogram defined by a and b.
To obtain a unit vector, we divide the cross product by its magnitude.
Given that a = 7i + 8j - 2k and b = 9i - 4j - 5k, we can find the cross product as follows:
a x b = det( i j k)
7 8 -2
9 -4 -5 )
= (8 x (-5) - (-2) x (-4)) i
- (7 x (-5) - (-2) x 9) j
+ (7 x (-4) - 8 x 9) k
= 18i + 59j + 50k
To obtain the unit vector normal to the plane, we need to divide this vector by its magnitude:
|18i + 59j + 50k| = √(18^2 + 59^2 + 50^2) = √(6885)
So, the unit vector normal to the plane is:
λ = (18i + 59j + 50k)/√(6885)
= (-32i + 49j - 44k)/49
We can see that this matches the given result, so we can conclude that the unit vector normal to the plane defined by a and b is λ = -32i/49 + 49j/49 - 44k/49.
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someone help me pls
A music store has 500 guitar picks. they order 15 boxes with 9 picks each. they sell 19 boxes that have 10 picks each. the store manager says they now have about 450 guitar picks. is the manager's estimate reasonable?
The store should have 445 picks remaining, not 450 as estimated by the manager. To determine if the store manager's estimate is reasonable, let's analyze the situation.
The store initially has 500 guitar picks. They order 15 boxes, and each box contains 9 picks. So the total number of picks they receive from the order is:
15 boxes * 9 picks/box = 135 picks
Next, the store sells 19 boxes, with each box containing 10 picks. Therefore, the total number of picks sold is:
19 boxes * 10 picks/box = 190 picks
To find the remaining number of picks, we can subtract the sold picks from the received picks:
Total remaining picks = Initial picks + Received picks - Sold picks
Total remaining picks = 500 + 135 - 190 = 445 picks
According to the calculations, the store should have 445 picks remaining, not 450 as estimated by the manager.
However, it's important to note that we are working with whole numbers, so there might be some rounding involved in the manager's estimate. It's possible that the manager rounded up to 450 for simplicity or other reasons.
Given the small discrepancy of 5 picks between the calculated value and the manager's estimate, it is reasonable to conclude that the manager's estimate is close enough to the actual number of picks. The discrepancy could be due to rounding or a small counting error. It's unlikely to have a significant impact on the store's operations or inventory management.
In summary, while the manager's estimate of 450 guitar picks may not be exactly accurate, it is reasonably close to the actual remaining number of picks based on the given information.
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HELP ASAP! I need the answer to all 3 of these questions.
If f(x)=3x+2, find f(8).
If f(x)=3x+2, find f(-2)
If f(x)=3x+2, find f(-2)
Answer:
I think that number one is 26, two is -4, and three is -4
Step-by-step explanation:
To solve for number one replace 8 with (x) so 3(8) + 2. 3 x 8 = 24 and 24+2 = 26
Numbers 2 and 3 appear to be the same problem so just do 3(-2) + 2 (Because you replace the number with the x) 3(-2) = -6 + 2 = -4!
I hope that helped!
On Sunday, Steve, Jo, Lucy, Max, and Alex decide to throw aparty. On Monday, they each invite 3 friends. On Tuesday, thefriends that were invited on Monday each invite 3 more people.On Wednesday, the people who were invited on Tuesday eachinvite 3 more people.If this continues, how many people will be invited on Saturday toattend the party?
Step 1. The party will be thrown by Steve, Jo, Lucy, Max, and Alex --> 5 people.
On Monday, each invites 3 friends. So for, the number of people invited is:
\(5\times3=15\)Step 2. On Tuesday, the friends that were invited (15) invited 3 more people each. The number of people invited now is:
\(15\times3=45\)Step 3. On Wednesday, the 45 people invited on Tuesday, each invite 3 more people. The number of people invited again multiplies by 3:
\(45\times3=135\)Step 4. The trend continues so for Thursday, the number of people invited on the previous day multiplies by 3:
\(135\times3=405\)Step 5. On Friday the number of people invited is:
\(405\times3=1,215\)Step 6. Finally, on Saturday, the day of the party, the number of people invited is multiplied one last time by 3:
\(1,215\times3=3,645\)Answer:
3,645
Someone please helppp
your friend house is 6.4 miles north and 12 miles west of your bank. how far is your friends house from your bank
Answer:
the answer is 76.8
Step-by-step explanation:
multiple of the number
help on how to do this stuff
The cosine of angle X is given as follows:
cos(X) = 4/5.
What are the trigonometric ratios?The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:
Sine of angle = length of opposite side to the angle divided by the length of the hypotenuse.Cosine of angle = length of adjacent side to the angle divided by the length of the hypotenuse.Tangent of angle = length of opposite side to the angle divided by the length of the adjacent side to the angle.For angle X, we have that:
The adjacent side is of 32.The hypotenuse is of 40.Hence the cosine of angle X is obtained as follows:
cos(X) = 32/40
cos(X) = 4/5.
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Find a formula for the power series of ()=6ln(1+), −1<<1
in the form ∑=1,[infinity]. Hint: First, find the power series for ()=6/(1+). Then integrate. (Express numbers in exact form. Use symbolic notation and fractions where needed. )
What is a_n?
The function of the power series f(x) = 6ln(1+x) = ∑=1 , ∞ 6(-1)⁽ⁿ⁻¹⁾xⁿ/n.
And a_n = 6(-1)⁽ⁿ⁻¹⁾xⁿ/n.
The common ratio is the distance between each number in a geometric series. The proportion of a number or two consecutive numbers. The common ratio, which is the same for all numbers or common, is the number divided by the number that comes before it in the sequence.
To find the power series for f(x), we first need to find the power series for g(x) = 6/(1+x):
g(x) = 6/(1+x) = 6(1 - x + x² - x³ +...) (geometric series with common ratio -x)
Next, we integrate term by term:
∫ g(x) dx = ∫ 6(1-x+x²-x³+...) dx
= 6(x - x²/2 + x³/3 - x⁴/4 + ...) + C , where C is a constant.
Since we're only interested in finding the coefficients of the power series, we can ignore the constant term.
Thus, the power series for f(x) is:
f(x) = 6ln(1+x) = 6(x - x²/2 + x³/3 - x⁴/4 + ...) = ∑=1 , ∞ 6(-1)⁽ⁿ⁻¹⁾xⁿ/n
where a_n = 6(-1)⁽ⁿ⁻¹⁾xⁿ/n.
Therefore, f(x) = 6ln(1+x) = ∑=1 , ∞ 6(-1)⁽ⁿ⁻¹⁾xⁿ/n.
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A common implementation of a graph that uses a two dimensional array to represent the graph's edges is called a(n)
a.adjacency matrix
b.graph array
c.adjacency array
d.adjacency list
Option a, adjacency matrix. An adjacency matrix is a two-dimensional array that represents a graph's edges, where the rows and columns correspond to the vertices of the graph. If there is an edge between two vertices, the corresponding element in the matrix is set to 1, otherwise it is set to 0. This implementation is useful for dense graphs, where the number of edges is close to the maximum possible number of edges.
An adjacency matrix is a simple and efficient way to represent graphs that have a large number of vertices and edges. It allows for fast lookups of the existence of an edge and is useful for various algorithms that require graph representation. However, it is not suitable for sparse graphs, where the number of edges is much smaller than the maximum possible number of edges. In such cases, an adjacency list would be more appropriate.
The common implementation of a graph that uses a two-dimensional array to represent the graph's edges is called an adjacency matrix.
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A rectangular prism’s volume is represented by the polynomial 3x^3-2x^2-15. The height of that prism is x-4 . What is the area of the base of the prism? HELP PLEASE.
The base area is 3x² + 10x + 40 + 145 / (x -4).
What is volume of rectangular prism?To find the volume of a rectangular prism, multiply its 3 dimensions: length x width x height. The volume is expressed in cubic units.
Given:
Volume of prism = 3x³-2x²-15
and, height = x-4
Now, Volume of prism = Base area x height
3x³-2x²-15 = (x- 4) x b
b = 3x³-2x²-15/ (x -4)
Now,
b = 3x³-12x² +10x² -40x +40x -160 + 145/ (x -4)
b= 3x²( x -4)+ 10x (x- 4) + 40(x -4) + 145
b = 3x² + 10x + 40 + 145 / (x -4)
Hence, the base area is 3x² + 10x + 40 + 145 / (x -4).
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how many three-letter initials with none of the letters repeated can people have?
To find the number of three-letter initials with none of the letters repeated, we need to consider the number of choices for each position in the initials.
To determine the number of three-letter initials with none of the letters repeated, we can analyze each position in the initials. For the first letter, we have 26 choices since there are 26 letters in the English alphabet.
After selecting the first letter, for the second letter, we have 25 choices remaining since we cannot repeat the letter used in the first position. Similarly, for the third letter, we have 24 choices remaining since we cannot repeat either of the previous letters.
Therefore, the total number of three-letter initials with none of the letters repeated can be found by multiplying the number of choices for each position: 26 * 25 * 24 = 15,600. Hence, there are 15,600 different three-letter initials that people can have if none of the letters are repeated.
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Let ABCD be an isosceles trapezoid (AB//CD). Draw AE, BF perpendicular to CD (E, F belong to CD), Let AB = 8cm, CD = 18cm, AD = 13cm.
a) Prove that triangle ADE = triangle BCF
b) Calculate DE, CF.
c) Calculate AE.
Thanks for solving the homework
A trapezoid is a plane figure bounded by four sides. Therefore, the required answers are given below;
a) ΔADE = ΔBCF (Side-Angle-Side congruent property)
b) DE = 5 cm and CF = 5 cm
c) AE = 12 cm
Plane figures are shapes that are formed by straight boundaries referred to as sides. Examples include; square, rectangle, trapezium, etc.
A trapezoid is a family of quadrilaterals., these are figures that have four straight sides.
In the given question, the required answers are:
a) To prove that ΔADE = ΔBCF
Thus,
AE ⊥ DC (given)
BC ⊥ DC (given)
<AED = <BFC = \(90^{o}\)
AE = BF (height of the trapozoid)
<ADE ≅ <BCF (congruent property of two triangles)
Therefore, it can be concluded that;
ΔADE = ΔBCF (Side-Angle-Side congruent property)
b) Given that AB = 8 cm, and DC = 18 cm.
Then,
CD = DE + EF + FC
18 = DE + 8 + FC (since EF = AB)
18 - 8 = 2 DE (since DE = FC)
DE = 5 cm
Thus, DE = 5 cm and CF = 5 cm
c) To determine the value of AE, we have to apply the Pythagoras theorem. So that;
\(/Hyp/^{2}\) = \(/Adj 1/^{2}\) + \(/Adj 2/^{2}\)
\(13^{2}\) = \(AE^{2}\) + \(5^{2}\)
169 - 25 = \(AE^{2}\)
\(AE^{2}\) = 144
AE = \(\sqrt{144}\)
= 12
AE = 12 cm
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Write the simplest polynomial function for each set of zeros
Zeros = 8,-10, 1,
PLEASEEEEE HELPPPPPPPPPP
9514 1404 393
Answer:
p(x) = x^3 +x^2 -82x +80
Step-by-step explanation:
If a polynomial function has a zero at x=a, then (x -a) is a factor. Your list of zeros means the factors are ...
p(x) = (x -8)(x +10)(x -1) . . . . . . . . factored form
When this is multiplied out, it becomes ...
p(x) = x^3 +x^2 -82x +80 . . . . . . standard form
_____
The factored form can be multiplied out using the distributive property.
= ((x(x +10) -8(x +10))(x -1)
= (x^2 +10x -8x -80)(x -1)
= (x^2 +2x -80)x -(x^2 +2x -80)
= x^3 +2x^2 -80x -x^2 -2x +80
= x^3 +x^2 -82x +80
during the worst periods of hyperinflation in a certain country the price of food increased at a rate of 30% per month.if your food bill was $120 in one month during this period,what was it three months later ?
The rate of inflating is r=30% per month.
The bill of food after three months can be determined as,
\(\begin{gathered} C=120(1+\frac{30}{100})^3 \\ C=263.64 \end{gathered}\)Thus, the bill after three months will be $263.64.
X-y=3 slope intercept
Can someone please help me on this question!!!
Answer:
3(b/150)
I think I got it right, where's my second supporter?
find the inequalities represented by the graph?
Answer:
,
Step-by-step explanation:
,...
SOMEONE HELP ME PLSSSS
simplify (pic below)
Answer:
10^11
Step-by-step explanation:
This question helps you practice some exponent rules. To "fix" a negative exponent you push it across the fraction bar. The 10^-3 on the bottom becomes a 10^3 on the top. See image.
Then, when you have 10^8 • 10^3, that is when you are multiplying, you add the exponents.
10 ^ (8+3)
= 10^11
see image
At the school football game, there are 42 adults
sitting in the bleachers. the ratio of adults to
students in the bleachers is 7 to 9. how many
students are sitting in the bleachers?
Answer:
54 students
Step-by-step explanation:
42 / 7 = 6
9 x 6 = 54
42 : 54 = 7 : 9
If \(x = 9 - 4\sqrt{5}\), find the value of \(\sqrt{x} - \frac{1}{\sqrt{x} }\).
Observe that
\(\left(\sqrt x - \dfrac1{\sqrt x}\right)^2 = \left(\sqrt x\right)^2 - 2\sqrt x\dfrac1{\sqrt x} + \left(\dfrac1{\sqrt x}\right)^2 = x - 2 + \dfrac1x\)
Now,
\(x = 9 - 4\sqrt5 \implies \dfrac1x = \dfrac1{9-4\sqrt5} = \dfrac{9 + 4\sqrt5}{9^2 - \left(4\sqrt5\right)^2} = 9 + 4\sqrt5\)
so that
\(\left(\sqrt x - \dfrac1{\sqrt x}\right)^2 = (9 - 4\sqrt5) - 2 + (9 + 4\sqrt5) = 16\)
\(\implies \sqrt x - \dfrac1{\sqrt x} = \pm\sqrt{16} = \pm 4\)
To decide which is the correct value, we need to examine the sign of \(\sqrt x - \frac1{\sqrt x}\). It evaluates to 0 if
\(\sqrt x = \dfrac1{\sqrt x} \implies x = 1\)
We have
\(9 - 4\sqrt5 = \sqrt{81} - \sqrt{16\cdot5} = \sqrt{81} - \sqrt{80} > 0\)
Also,
\(\sqrt{81} - \sqrt{64} = 9 - 8 = 1\)
and \(\sqrt x\) increases as \(x\) increases, which means
\(0 < 9 - 4\sqrt5 < 1\)
Therefore for all \(0 < x < 1\),
\(\sqrt x - \dfrac1{\sqrt x} < 0\)
For example, when \(x=\frac14\), we get
\(\sqrt{\dfrac14} - \dfrac1{\sqrt{\frac14}} = \dfrac1{\sqrt4} - \sqrt4 = \dfrac12 - 2 = -\dfrac32 < 0\)
Then the target expression has a negative sign at the given value of \(x\) :
\(x = 9-4\sqrt5 \implies \sqrt x - \dfrac1{\sqrt x} = \boxed{-4}\)
Alternatively, we can try simplifying \(\sqrt x\) by denesting the radical. Let \(a,b,c\) be non-zero integers (\(c>0\)) such that
\(\sqrt{9 - 4\sqrt5} = a + b\sqrt c\)
Note that the left side must be positive.
Taking squares on both sides gives
\(9 - 4\sqrt5 = a^2 + 2ab\sqrt c + b^2c\)
Let \(c=5\) and \(ab=-2\). Then
\(a^2+5b^2=9 \implies a^2 + 5\left(-\dfrac2a\right)^2 = 9 \\\\ \implies a^2 + \dfrac{20}{a^2} = 9 \\\\ \implies a^4 + 20 = 9a^2 \\\\ \implies a^4 - 9a^2 + 20 = 0 \\\\ \implies (a^2 - 4) (a^2 - 5) = 0 \\\\ \implies a^2 = 4 \text{ or } a^2 = 5\)
\(a^2 = 4 \implies 5b^2 = 5 \implies b^2 = 1\)
\(a^2 = 5 \implies 5b^2 = 4 \implies b^2 = \dfrac45\)
Only the first case leads to integer coefficients. Since \(ab=-2\), one of \(a\) or \(b\) must be negative. We have
\(a^2 = 4 \implies a = 2 \text{ or } a = -2\)
Now if \(a=2\), then \(b=-1\), and
\(\sqrt{9 - 4\sqrt5} = 2 - \sqrt5\)
However, \(\sqrt5 > \sqrt4 = 2\), so \(2-\sqrt5\) is negative, so we don't want this.
Instead, if \(a=-2\), then \(b=1\), and thus
\(\sqrt{9 - 4\sqrt5} = -2 + \sqrt5\)
Then our target expression evaluates to
\(\sqrt x - \dfrac1{\sqrt x} = -2 + \sqrt5 - \dfrac1{-2 + \sqrt5} \\\\ ~~~~~~~~~~~~ = -2 + \sqrt5 - \dfrac{-2 - \sqrt5}{(-2)^2 - \left(\sqrt5\right)^2} \\\\ ~~~~~~~~~~~~ = -2 + \sqrt5 + \dfrac{2 + \sqrt5}{4 - 5} \\\\ ~~~~~~~~~~~~ = -2 + \sqrt5 - (2 + \sqrt5) = \boxed{-4}\)
solve the problem. if the null space of a 7 × 9 matrix is 3-dimensional, find rank a, dim row a, and dim col a.
If the null space of a 7 × 9 matrix is 3-dimensional, we can determine the rank of matrix A, the dimension of the row space of A, and the dimension of the column space of A.
The rank of a matrix is equal to the number of linearly independent columns or rows in the matrix. Since the null space is 3-dimensional, the rank of A would be 9 - 3 = 6.
The dimension of the row space, also known as the row rank, is equal to the dimension of the column space, or the column rank. Therefore, the dimension of the row space and the dimension of the column space of A would also be 6.
The rank of matrix A would be 6, and both the dimension of the row space and the dimension of the column space of A would also be 6.
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