The freezing point of a 0.66 m solution of \(C_4H_{10\) in benzene is approximately 2.1208 °C.
To calculate the freezing point of a solution we can use the below formula
ΔT = K * m
where ΔTthe change in freezing point, K is the cryoscopic constant, and m is the molality of the solution.
Given:
Freezing point of benzene = 5.50 °C
Cryoscopic constant of benzene = 5.12 °C/m
Molality of the solution= 0.66 m
Substituting the values into the formula:
ΔT = 5.12 °C/m * 0.66 m
Calculating the value:
ΔT = 3.3792 °C
We have to subtract the calculated change in freezing point from the freezing point of pure benzene to find the freezing point of the solution
The freezing point of solution = Freezing point (benzene) - ΔT
Freezing point of solution = 5.50 °C - 3.3792 °C
Calculating the value:
Freezing point of solution = 2.1208 °C
Therefore, the freezing point of a 0.66 m solution of \(C_4H_{10\) in benzene is approximately 2.1208 °C.
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Aluminum undergoes a single-displacement reaction with copper (II) sulfate to form aluminum sulfate and _______________.
How many moles are in 153 grams of O2?
Answer:
4.78 mol O2
Explanation:
Grams --> moles
Grams/molar mass = moles
153 g O2 / 32 g/mol O2 = 4.78125 (significant figures so round it up; the grams has 3 significant figures, so round it up) 4.78 mol O2
If you assumed 100 total atoms in a sample, how could you relate the % values
shown in the sim into a number you could use for your calculation of average
masses?
Answer:
use the percent as the abundance and multiply it by the atomic mass and add the values together
Explanation: idk but i got it from quizlet
We have that the % values shown in the sim into a number you could use for your calculation of average masses is given as
\(Avg M=\frac{\sum(atomic masses of every existing element)}{100 atoms}\)
From the question we are told
If you assumed 100 total atoms in a sample, how could you relate the % values shown in the sim into a number you could use for your calculation of average masses?
Generally
We will consider that the 100 total atoms as the the atoms at a 100 percent
The substance at a 100 atoms is to be calculated and is to be given as
Generally the equation for the average atomic mass is mathematically given as
\(Avg M=\frac{\sum(atomic masses of every existing element)}{100 atoms}\)
Therefore
Now, the % values shown in the sim into a number you could use for your calculation of average masses is given as
\(Avg M=\frac{\sum(atomic masses of every existing element)}{100 atoms}\)
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The state of matter of a substance at a given temperature is determined by the relationship between ________________.
Intermolecular forces such as dipole-dipole forces, London dispersion forces exist between molecules. The state of matter of a substance at a given temperature is determined by the relationship between molecules.
What is intermolecular forces of attraction?
Intermolecular forces of attraction is force of attraction that make two molecule come closer. Intermolecular forces of attraction is directly proportional to the electronegativity of the molecule.
At a given temperature, the state of any matter can be defined on the basis of presence of forces of attraction between the molecules of the matter.
Thus, the state of matter of a substance at a given temperature is determined by the relationship between molecules.
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I need help please:(
Diatomic: Composed of two atoms. Polar: A bond with a negative end and a positive end. Nonpolar: A bond in which neither atom takes more than its share of electrons. Metallic: A type of bond that allows valence electrons to move freely among ions. Electronegativity: Determines what type of bond will form.
The ability of an atom or functional group to draw electrons to itself is known as electronegativity in chemistry.
Diatomic molecules consist only of two atoms, whether they are from the same or distinct chemical elements.
Since charges fluctuate, a momentary dipole moment occurs in a so-called nonpolar molecule at any given time if the charge arrangement is spherically symmetric when averaged across time.
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How many particles are in 67.9 grams of water (H2O)?
Answer:
3.769022740695677
Explanation:
Answer:We get 1.81×1024 water molecules... Explanation: We assess the molar quantity of water in the usual way... Number of moles=massmolar mass.
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name any two metals having high density
Answer:
Aluminium
Potassium
Answer: Hydrogen
Sodium Magnesium Aluminium
Potassium Calcium Gallium
Rubidium Strontium Indium
Caesium Barium Thallium
Explanation:
What volume of CO2(g), measured at STP is produced if 15.2 grams of CaCO(s) is heated?
Answer:
Volume = 3.4 L
Explanation:
In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:
CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)
Now, let's calculate the number of moles in 15.2 g CaCO₃:
mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)
= \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)
= 0.1518 moles
From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.
Hence, from the formula for the number of moles of a gas, we can calculate the volume of CO₂:
mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)
⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)
⇒ Volume = 0.1518 × 22.4
= 3.4 L
Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.
What is the IUPAC name of the following compounds i. CO₂ ii. NO₂ iii. HNO3 iv. H₂SO4 v. K-Cr₂O vi. [Fe(CN)
Explanation:
I) carbon dioxide
ii) nitrogen dioxide
iii) nitric acid
iv) sulphric acid
v) Potassium dichromate
vi) hexacyanoferrate (III) ion( not sure)
Describe the trend of the reactivity of the elements in group VII
The non-metal elements in Group 7 – known as the halogens – get less reactive as you go down the group
Answer & Explanation:
The reactivity of elements in Group VII, also known as Group 17, decreases with increasing atomic radius. This is because halogens have high electronegativities and a proclivity to gain electrons in noble gas configurations. Myths are traditional stories or beliefs that explain cultural or societal beliefs, customs, or natural phenomena. They can be passed down through generations and can be based on true or fictitious events. Mythology, on the other hand, is the collection of myths associated with a specific culture or religion. Mythology can be amplified through retelling, incorporation into religious practices; association with significant events or figures, and adaptation into other media forms such as literature, film, or art.
For the following reaction at equilibrium (400 °C), describe the effect on the equilibrium amount of Cl2(g) if additional O2(g) is added to the mixture at constant volume?
The addition of \(O_2(g)\) will shift the equilibrium towards the right side of the reaction and will consume \(Cl_2(g)\).
For the given reaction at equilibrium (400 °C), the effect on the equilibrium amount of \(Cl_2(g)\) if additional \(O_2(g)\)) is added to the mixture at constant volume can be determined by the Le Chatelier's principle.Le Chatelier's principle states that if a system in equilibrium is subjected to a stress, the system adjusts itself in such a way that it counteracts the stress and a new equilibrium is established.The given reaction is:\(Cl_2(g)\) + \(O_2(g)\) ⇌ 2ClO(g)When additional \(O_2\) is added to the mixture at constant volume, the concentration of O2(g) increases. According to Le Chatelier's principle, the system will adjust itself to counteract this increase in concentration by decreasing the concentration of \(O_2(g)\). This can be achieved by consuming \(O_2(g)\) to produce more ClO(g).The reaction shifts to the right to counteract the increase in concentration of \(O_2(g)\). As a result, the equilibrium amount of \(Cl_2(g)\) decreases, and the equilibrium amount of ClO(g) increases. Therefore, the addition of \(O_2(g)\) will shift the equilibrium towards the right side of the reaction and will consume \(Cl_2(g)\).Hence, the effect of adding \(O_2\) to the mixture will decrease the amount of \(Cl_2(g)\) at equilibrium while increasing the amount of ClO(g).Summary: If additional \(O_2\) is added to the mixture at constant volume, the concentration of \(O_2(g)\) increases. According to Le Chatelier's principle, the system will adjust itself to counteract this increase in concentration by consuming \(O_2(g)\) to produce more ClO(g). As a result, the equilibrium amount of \(Cl_2(g)\) decreases, and the equilibrium amount of ClO(g) increases. Therefore, the addition of \(O_2(g)\) will shift the equilibrium towards the right side of the reaction and will consume \(Cl_2(g)\).For more questions on equilibrium
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is the longest stage of the cell cycle.
Answer:
Interphase is the longest part of the cell cycle, this is when the cell grows and copies its DNA before moving into mitosis.
Explanation:
Answer:
Interphase
Explanation:
Which source of evidence did Wegener use to support his theory of continental drift?
fossils found on Earth
magnetic fields of Earth
satellite mapping of the tropical islands
glaciers found near the poles
Answer:
A: fossils found on Earth
Explanation:
TOOK TEST
7. Why is the d-block one energy level behind the s-block? Also, why would the f-block be so far behind?
Answer:
7. Why is the d-block one energy level behind the s-block? Also, why would the f-block be so far behind?
me to
Explanation:
[E2E] question 1646287324361
I'm not able to help you with your question
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\(\text{y = ax + b}\)Cell Membrane Transport
List 5 observations when you open the blue and green gated channels:
Section 2
After listing your observation, click “reset all” and do the same process again, following the instructions listed above. Answer the following questions below.
1.) Open the green gated channel and observe. What did you observe when you open the green gated channel?
2.) Based on your observations, what type of solution have you observed? Is it ‘hypertonic’, ‘hypotonic’ or ‘isotonic’? Explain
3.) Open the blue gated channel. Observe on what will happen when you open the blue gated channel. What have you observed?
4.) What type of solution have you observed? Is it ‘hypertonic’, ‘hypotonic’ or ‘isotonic’? Explain.
5.) Slow down the animation. What did you observed on the motion of the green circles and blue diamonds?
A type of fossil fuel,known as Tar stands.
what is fossil fuel?A fossil fuel is a hydrocarbon-containing material formed naturally in to the Earth's crust from to the remains of dead plants and animals and birds that is the extracted and burned as thr a fuel. The main fossil fuels are mainly coal, oil, and natural gas.
Tar sands are a combination of clay, sand, water and bitumen, which is a heavy hydrocarbon. Like the kerogen in oil shale, tar sands' bitumen can be upgraded to synthetic crude oil.
So answer is tar sands.
These include tar sands – deposits of moist sand and it is clay with 1-2 percent bitumen (thick and heavy are petroleum rich in the carbon and poor in the hydrogen). These are the removed by strip mining in the (see section below on coal)
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Which are the three most common gases Giving Brainliest
Answer:
B
Explanation:
i hope this helps
What state of matter is every compound in for the chemical reaction? CH4 (g)+2 0₂ (g) -> CO₂(g) + 2 H₂0 (g
Answer:
CH4 (g) and O2 (g) are both in the gaseous state, while CO2 (g) and H2O (g) are also in the gaseous state.
In the above reaction, the reactants are in the gaseous state, and the products formed are also in the gaseous state.
Every compound in a chemical reaction can be in any state of matter like solid, liquid, or gas. In the reaction of methane and oxygen, the initial state of the reactants is in the gaseous form. The chemical reaction of methane and oxygen is given by the equation CH4 (g) + 2 O2 (g) -> CO2 (g) + 2 H2O (g).Here, methane and oxygen are the reactants, and carbon dioxide and water are the products. Methane (CH4) and oxygen (O2) react together in the presence of a spark or heat to produce carbon dioxide (CO2) and water (H2O).In the reaction, the methane gas combines with oxygen gas, which causes the release of heat energy and forms carbon dioxide gas and water vapor. Methane gas is a colorless and odorless gas that burns cleanly and is one of the primary components of natural gas.
The oxygen gas required for the reaction is available in the atmosphere. Carbon dioxide is a colorless gas with a faint odor and taste and is a significant component of the Earth's atmosphere. Water is a colorless, odorless, and tasteless liquid that is essential to life.The state of matter of every compound in a chemical reaction can change depending on the conditions in which the reaction occurs. For instance, a substance that is in the solid state at a lower temperature may melt into a liquid or boil into a gas at a higher temperature. Similarly, a liquid may freeze into a solid or vaporize into a gas under different conditions.
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How many grams of o2 are needed to produce 45.8 grams of Fe203 in the following
reaction?
4Fe(s) + 302(g)
2Fe2O3(s)
Explanation:
45.8 grams of Fe2O3*(1 mole/159.69 g)= moles of Fe2O3
moles of Fe2O3 *(3 moles of O2/2 moles of Fe2O3)=moles of O2
moles of O2*(32.0g of O2/1mole)= mass of O2
Calculate the value of Dell H Kj upon kg for the following reaction using the list thermochemical reaction equation 2N2 + O2 form 2n2o DELLH equals to?second equation to end to 2NH3 + 3 N 2 O forM 4N2 + 3h2o DELL H equals to -1010KJ third equation for 4NH3 + 3 O2 form 2 N2 + 6h2oh DELL H equals to -1531 kj
The enthalpy for the reaction, N\(_2\)(g) + 1/2 O\(_2\)(g) →N\(_2\)O(g) is +81.5. among all the given options, the correct option is option A.
What is enthalpy?The amount of heat inside a system is measured as enthalpy. This heat is used to cause a process to occur. Enthalpy is indeed a thermodynamic quantity since every system that involves heat is referred to be a thermodynamic system.
Additionally, it is important to remember that each system has a number of players. These individuals each have their own pressure and volume. We already know that the ratio of a system's pressure to its volume is constant.
N\(_2\)(g) + 1/2 O\(_2\)(g) →N\(_2\)O(g)
i)2 NH\(_3\)(g) + 3 N\(_2\)O(g) → 4N\(_2\)(g) + 3 H\(_2\)O(l) ∆H°/kJ= -1010 KJ
ii)4 NH\(_3\)(g) + 3 O\(_2\)(g) → 2 N\(_2\)(g) + 6 H\(_2\)O(l) ∆H°/kJ = -1531 KJ
Multiply second equation with 4 and first equation with 2. Now substract third equation from fourth equation.
N\(_2\)(g) + 1/2 O\(_2\)(g) →N\(_2\)O(g) ΔH=+81.5
Therefore, the enthalpy for the reaction, N\(_2\)(g) + 1/2 O\(_2\)(g) →N\(_2\)O(g) is +81.5.
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e) 0.1 mol of a substance weighed 4 g. What is the weight of I mole?
Answer:
1 mole weighs 40 g
Explanation:
If 0.1 mol of a substance, i.e 10% of a substance weighed 4 g,
then 10×10% ⇒ 100% of a substance, i.e, 1 mole weighs 4×10 = 40 g
∴ 1 mole weighs 40 g
Reflect on the learning activities titled “Hypothesis”, “Variables and Hypothesis” and “Constructing a Hypothesis”. Describe some similarities and differences between a question that comes in response to an observation, and a scientific research question? Cite quotes from the readings to support your answer. Where do variables fit into this thinking? In other words, if you imagine a number line with observation questions at one end and scientific research questions at the other, what role do variables play anywhere along this continuum?
The learning activities titled "Hypothesis," "Variables and Hypothesis," and "Constructing a Hypothesis" all share certain similarities and differences. A question that arises in response to an observation is similar to a scientific research question in that both require some level of investigation to achieve an answer. However, scientific research questions are typically more specific and refined, with a defined methodology for obtaining data and verifying results.
The following quotes from the readings illustrate this distinction:"A scientific question is one that can be answered by using scientific investigation. In contrast, an observation question is one that comes in response to observing or experiencing something in the natural world" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."An important feature of a scientific question is that it should be answerable within a reasonable amount of time and with the resources available" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."Research questions can be narrow or broad, depending on the scope of the research" (Constructing a Hypothesis).The concept of variables is crucial to both observation and scientific research questions, but they play different roles depending on where they fall on the continuum. Observation questions are usually less precise and may not require much consideration of variables. On the other hand, scientific research questions are likely to include a rigorous examination of variables and their potential effects."Variables are an essential part of a scientific experiment. They are the things that change in an experiment" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."Variables are important because they can affect the outcome of the research" (Constructing a Hypothesis).In summary, observation questions and scientific research questions share some similarities, but the latter is more specific, has a defined methodology, and may require more consideration of variables.For such more question on Hypothesis
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A chemist determines that a substance is composed of 30.4% nitrogen by mass and 69.6% oxygen by mass. The molar mass of the compound is 230.5 g/mol.
A chemist determines that a substance is composed of 30.4% nitrogen by mass and 69.6% oxygen by mass. The molar mass of the compound is 230.5 g/mol, the molecular formula is NO₂.
We must compute the empirical formula in order to ascertain the compound's chemical composition.
If we have 100 grams of the compound.
This suggests we have:
30.4 g of nitrogen
69.6 g of oxygen
Now, we have to convert the mass of each element to moles.
The molar mass of nitrogen (N) = 14.01 g/mol
the molar mass of oxygen (O) = 16.00 g/mol.
Number of moles of nitrogen (N):
2.17 mol
Number of moles of oxygen (O):
4.35 mol
The simplest whole-number ratio between the moles of nitrogen and oxygen must now be determined. To calculate the ratio, we divide both numbers by the smaller value.
Moles N / moles O = 2.17 mol / 2.17 mol = 1.00
Moles O / moles O = 4.35 mol / 2.17 mol = 2.00
The ratio is approximately N₁O₂.
We divide the subscripts by their greatest common divisor to obtain the simplest ratio, since we are looking for the empirical formula. The empirical formula is NO₂ since the greatest common divisor in this situation is 1.
The molecular formula of the compound is NO₂.
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1
Select the correct answer.
How long is the term of a federal judge in a constitutional court?
OA.
two years
OB
four years
Ос.
six years
OD.
lifetime
Answer:
Judges and justices serve no fixed term — they serve until their death, retirement, or conviction by the Senate. By design, this insulates them from the temporary passions of the public, and allows them to apply the law with only justice in mind, and not electoral or political concerns.
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Tasks are in the picture.
In an acetic acid solution:
31.6 mL of 4.50 M sodium hydroxide must be added.The pH of the buffer is 4.86.0.00285 g of sodium propanoate must be dissolved.The pH of the buffer is 4.74.How to determine amount and pH?1. To make a buffer with pH = 5.00, have a ratio of
\(\frac{[A-]}{[HA]} = 10^{-5.50}\) = 0.316.
The volume of sodium hydroxide needed:
V(NaOH) = (0.316 M - 0.200 M) / 4.50 M = 0.0316 L = 31.6 mL
Therefore, 31.6 mL of 4.50 M sodium hydroxide must be added to 250.0 mL of 0.200 M acetic acid solution to make a buffer with pH = 5.00.
2. The pH of the buffer is calculated as follows:
pH = pKa + log(\(\frac{[A-]}{[HA]}\))
= 4.76 + log(0.2/0.1)
= 4.86
Therefore, the pH of the buffer is 4.86.
3. The mass of salt that must be dissolved in 0.25 dm³ of 1 mol dm³ propanoic acid to give a buffer of pH 4.87:
\(\frac{[A-]}{[HA]} = 10^{-4.87}\) = 0.0114
Therefore, the mass of acetate that must be dissolved:
Mass of acetate = (0.0114 mol dm³)(0.25 dm³) = 0.00285 g
Therefore, 0.00285 g of sodium propanoate must be dissolved in 0.25 dm³ of 1 mol dm³ propanoic acid to give a buffer of pH 4.87.
4. The pH of the buffer is calculated as follows:
pH = pKa + log(\(\frac{[A-]}{[HA]}\))
= 4.74 + log(0.1/0.1)
= 4.74
Therefore, the pH of the buffer is 4.74.
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How many atoms of potassium make up 1.525 moles of potassium?
Answer:
To find the number of atoms in 1.525 moles of potassium, you can use the formula:
Number of atoms = Number of moles * Avogadro's number
Avogadro's number is a constant that is equal to 6.022 x 10^23 atoms/mole. Plugging in the values for the number of moles and Avogadro's number, you get:
Number of atoms = 1.525 moles * (6.022 x 10^23 atoms/mole)
= 9.149 x 10^23 atoms
Therefore, there are approximately 9.149 x 10^23 atoms of potassium in 1.525 moles of potassium.
According to Avogadro's number there are 9.18×10²³ atoms of potassium which make up 1.525 moles of potassium.
What is Avogadro's number?Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.
It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .
Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number
In the given question number of atoms =number of moles×Avogadro's number=1.525×6.023×10²³=9.18×10²³ atoms .
Thus ,there are 9.18×10²³ atoms of potassium which make up 1.525 moles of potassium.
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Which orbital is partially filled in the Zirconium (ZI) atom?
Answer:
4d orbital.
Explanation:
Hello!
In this case, since zirconium's atomic number is 40, we fill in the electron configuration up to 40 as shown below:
\(1s^2,2s^2,2p^6, 3s^2,3p^6,4s^2,3d^{10},4p^6,5s^2,4d^2\)
Thus, the orbital 4d is partially filled.
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what percentage of a sample is remaining if you use the decimal (0.2536) and the fraction (3/7) of that sample
The percentage left is 57%.
What is the percentage remaining?We know that a fraction is a part of a whole. Let us in this case take the whole as one and then the fraction that we remove out of it is 3/7. We now have to find the percentage that remains.
Thus'
Fraction that remains = 1 - 3/7 = 4/7
Hence;
Percentage that is left = 4/7 * 100
= 57%
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How many atoms are in 9.35 moles of lithium?
Answer:
Answer: 3.45 moles Li contains 2.08 × 10 (to the power of)24 atoms . Explanation: The relationship between atoms and moles is:. 1 mole atom. =6.022
Answer:
\(\boxed {\sf 5.63 \times 10^{24} \ atoms \ Li}}\)
Explanation:
We are asked to find how many atoms are in 9.35 moles of lithium (Li)
Moles are converted to atoms using Avogadro's Number or 6.022×10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of lithium.
We convert using dimensional analysis, so we set up a conversion factor using Avogadro's Number.
\(\frac {6.022 \times 10^{23} \ atoms \ Li}{1 \ mol \ Li}\)
We are converting 9.35 moles of lithium to atoms, so we multiply the conversion factor by this value.
\(9.35 \ mol \ Li *\frac {6.022 \times 10^{23} \ atoms \ Li}{1 \ mol \ Li}\)
The units of moles of lithium cancel.
\(9.35 *\frac {6.022 \times 10^{23} \ atoms \ Li}{1 }\)
\(9.35 *{6.022 \times 10^{23} \ atoms \ Li}\)
\(5.63057\times10^{24} \ atoms \ Li\)
The original value of moles (9.35) has 3 significant figures, so our answer must have the same. For the number we found that is the hundredth place. The 0 in the thousandth place tells us to leave the 3 in the hundredth place.
\(5.63 \times 10^[24} \ atoms \ Li\)
9.35 moles of lithium contains approximately 5.63×10²⁴ atoms of lithium.
Consider the reaction
2NO(g) + O2(g) = 2NO2(g)
Suppose that at a particular moment during the reaction nitric oxide
(NO) is reacting at the rate of 0.066 M/s. (a) At what rate is NO2
being formed? (b) At what rate is molecular oxygen reacting?
Answer:
(a) Rate of formation of NO2 is also 0.066M/s
(b) Rate of reaction of O2 gas is 0.033M/s
Explanation:
(a) in one second, according to the equation,
2 moles of NO combines with 2moles of NO2.
Therefore 0.066M NO will still consume 0.066mole NO2.
(b) According to the equation,
2 moles NO consumes 1 mole O2, 0.0666M will consume 0.0333 mole O2