Answer:
m = 7.5 grams
Explanation:
Given that,
The density of the rock, m = 1.5 g/mL
The volume displaced by the rock, V = 5 mL
We need to find the mass of the rock. The density of an object is equal to its mass divided by its volume. So,
\(d=\dfrac{m}{V}\\\\m=d\times V\\\\m=1.5\times 5\\\\m=7.5\ g\)
So, the mass of the rock is 7.5 grams.
A volleyball is served at a speed of 8 / at an angle 35° above the horizontal. What is the speed of the ball when received by the opponent at the same height?
A. A PH202 student lives next to a construction site and sees a crane with a wrecking ball demolish the building next door. The wrecking ball swings along the wall between her house and the neighbor’s house. In an effort to determine the length of the cable on the wrecking ball the student builds a pendulum using a random rock and a string. Her pendulum turns out to be 0.500m long. While she plays with her pendulum she realizes that the wrecking ball swings back and forth in the same amount of time that it takes the rock to complete 5 full oscillations. What is the length of the cable on the wrecking ball?
Answer:
The length of cable is 12.5 m
Explanation:
Since, the wrecking ball completes 1 oscillation, in the same time, as it takes for the rock to complete 5 oscillations.
Therefore,
Time Period of Wrecking Ball = 5 (Time Period of Rock)
Since,
Time Period of Pendulum = 2π√(L/g)
Therefore,
2π√(L₁/g) = 5[2π√(L₂/g)]
√L₁ = 5√L₂
Squaring on both sides:
L₁ = 25 L₂
where,
L₁ = Length of Cable = ?
L₂ = Length of string = 0.5 m
Therefore,
L₁ = 25 (0.5 m)
L₁ = 12.5 m
A 5100 kg rocket almost in orbit and traveling horizontally is propelled by a thrust force of 7450 Newtons. How fast is it accelerating while the force is applied? ROUND YOUR ANSWER TO THE NEAREST TENTH DECIMAL PLACE (TEKS 4D)
Answer:
\(a=1.46\ m/s^2\)
Explanation:
Given that,
Mass of a rocket, m = 5100 kg
Thrust force acting on the rocket, F = 7450 N
We need to find the acceleration of the rocket. The net force acting on an object is given by the formula as follows :
F = ma
a is acceleration of the rocket
\(a=\dfrac{F}{m}\\\\a=\dfrac{7450}{5100}\\\\a=1.46\ m/s^2\)
So, the acceleration is \(1.46\ m/s^2\).
Water has higher specific heat than aluminum. This is all what you should know to answer following questions. An aluminum rod of mass 1 kg at temperature of 80^0C is placed into 1l of water of temperature 10^0C . there is no heat exchange with surroundings. Which material experiences greater change in temperature while system is reaching the thermal equilibrium
Answer:
The Aluminum
Explanation:
With a larger specific heat, water requires more heat to raise its temperature by a temperature degree.
In this system, with equal masses of water and aluminum, the heat moving from the aluminum lowering its temperature by one degree is not sufficient to raise the water temperature by one degree.
A cyclist traveling in a straight line has the velocity of +5 m/s for 10 sec. She then accelerates at a rate of 0.5 m/s2 over another 10 sec. How far does the cyclist travel during those 20 sec?
Answer: 125
Explanation: use the equation d=vt to find the first distance, 50. Then use the equation
X=Vot + 1/2at to find the second distance. Then add both together.
Vo=5
V=5
T=10
A=5
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!pls
In an attempt to deliver a parcel on time, the dispatch rider had to ride 10km 15 degrees SE, he then rode 11 km 30 degrees NE and then takes a shortcut at 22km W .find the rider's displacement
The total displacement of the dispatch rider is calculated as 43km.
Data;
10km 15 degrees SE11km 30 degrees NE22km WTotal DisplacementTo calculate the total displacement of the dispatch rider, we can simply add up the total distance covered by the rider.
This becomes;
\(10+11+22 = 43km\)
The total displacement of the dispatch rider is calculated as 43km.
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4) Suppose that two identical
mass planets are sitting
million miles apart. At that
distance the planets have a
gravitational force of 1,000,000 N.
If the planets are moved
to two million miles apart, what
is the new gravitational force
between them?
The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N
The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Given:
Initial distance between the planets = 1 million miles
Initial gravitational force = 1,000,000 N
Final distance between the planets = 2 million miles
To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.
Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.
According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:
(F2/F1) = (d1/d2)²
Substituting the given values:
(F2/1,000,000 N) = (1 million miles / 2 million miles)²
Simplifying:
(F2/1,000,000 N) = (1/2)²
(F2/1,000,000 N) = 1/4
F2 = (1/4) * 1,000,000 N
F2 = 250,000 N
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Which planet has the greatest gravity (of the choices shown)
Saturn
Venus
Uranus
Earth
Answer:
Earth
Explanation:
Answer:
Saturn/has best gravity out of the 4 planets.
what are the strengths and weaknesses of the four methods of waste management?
Answer & Explanation: Waste management are all activities and actions required to manage waste from its inception to its final disposal. There are several methods of managing waste with its strengths and weaknesses. The strengths include;
* It creates employment
* It keeps the environment clean
* The practice is highly lucrative
* It saves the earth and conserves energy
The weaknesses of the methods of waste management includes;
* The sites are often dangerous
* The process is mostly
* There is a need for global buy-in
* The resultant product had a short life
A and B start walking in the same direction at the same time around a circular park of diameter 4200 m. If A walks 10 m more than B in every minute with a speed of 5 km per hour, then they meet each other next time after A makes................ rounds. (ii) 8 (i) 7 (iii) 9 (iv) 10...
Diameter = 4200 m
T = 24700 \(\pi\) time for A to also catch B
N = 1.39 \(*\) 24700 \(\pi\) / (4200 \(\pi\)) = 8.2 laps
A will create 8 but not 9 rounds before catching B.
What is speed?Speed exists distance travelled per unit time. It exists scalar quantity.
Given: diameter = 4200 m
\(V_a\) = 5000 m / 3600 s = 1.39 m/s
(\(V_a - V_b\)) 60 = 10
\(V_b = V_a\) - 0.167 = 1.22 m/s
(\(V_a - V_b\)) T = 4200 \(\pi\)
where T exists time for A to complete 1 more lap
0.17 T = 4200 \(\pi\)
T = 24700 \(\pi\) time for A to also catch B
N = 1.39 \(*\) 24700
\(V_a\) = 5000 m / 3600 s = 1.39 m/s
(\(V_a - V_b\)) 60 = 10
\(V_b = V_a\) - 0.167 = 1.22 m/s
(\(V_a - V_b\)) T = 4200 \(\pi\)
where T exists time for A to complete 1 more lap
0.17 T = 4200 \(\pi\)
T = 24700 \(\pi\) time for A to also catch B
N = 1.39 \(*\) 24700 \(\pi\) / (4200 \(\pi\)) = 8.2 laps
A will create 8 but not 9 rounds before catching B.
Therefore, the correct answer is option (ii) 8.
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What is the relationship between kinetic energy and speed
Answer:
Here
Explanation:
the kinetic energy of an object is directly proportional to the square of its speed. That means that for a twofold increase in speed, the kinetic energy will increase by a factor of four. For a threefold increase in speed, the kinetic energy will increase by a factor of nine
Answer:
. It turns out that an object’s kinetic energy increases as the square of its speed. A car moving 40 mph has four times as much kinetic energy as one moving 20 mph, while at 60 mph a car carries nine times as much kinetic energy as at 20 mph. Thus a modest increase in speed can cause a large increase in kinetic energy.
Which of the following statements about Masters programs is not correct?
A. Most Masters athletes did not compete when they were in school.
B. The social life is as important as the athletics on most Masters
teams.
C. The level of competition is not very high in most Masters
programs.
D. Masters programs allow adults to work out and socialize with
people who share their love of a sport.
SUBMIT
The correct answer is C. The level of competition is not very high in most Masters programs.
Explanation:
In sports, the word "master" is used to define athletes older than 30 and that usually are professional or have trained for many years, although novates are also allowed. This means in most cases in Master programs and teams a high level of competition can be expected due to the experience and extensive training of Master athletes. Indeed, many records in the field of sport belong to Master athletes rather than younger athletes. According to this, the incorrect statement is "The level of competition is not very high in most Masters programs".
When an external magnetic field is applied, what happens to the protons in a sample?
A) All protons align with the field.
B) All protons align opposite to the field.
C) Some protons align with the field and some align opposite to it.
D) All protons assume a random orientation.
Answer:
Some protons align with the field and some align opposite to it.
Explanation:
Majority align to the field because these protons tend to act like small magnets under the effect of this external field
On account of external magnetic field, the protons will align with the magnetic field. Hence, option (a) is correct.
The given problem is based on the concept of magnetic field. The region where the magnetic force is experienced is known as magnetic field. Generally, the protons are the charged entities carrying the positive polarity and are one of the major constituents of modern atomic structure.
The origin of magnetic field occurs due to charged particles present in a specific space. And the magnetic field is due to the flowing of liquid metal in the outer core of the planet generates electric currents.In the condition when an external field is applied, the majority of protons align to the field because these protons tend to act like small magnets under the effect of this external field.Thus, we can conclude that on account of external magnetic field, the protons will align with the field.
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Statement A: Area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.
Statement B: Area of a rectangle with measured length = 2.536 mm and width = 1.41 mm.
Since you are not told specific numbers of significant figures to round to, you must use the rules for multiplying numbers while respecting significant figures. If you need a reminder, consult the hint.
Determine the correct relationship between the statements.
Explanation:
Formula for calculating the area of a rectangle A = Length *width
For statement A;
Given area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.
Area of the rectangle = 2.536mm * 1.4mm
Area of the rectangle = 3.5504mm²
The rule of significant figures states that we should always convert the answer to the least number of significant figure amount the given value in question. Since 1.4mm has 2 significant figure, hence we will convert our answer to 2 significant figure.
Area of the rectangle = 3.6mm² (to 2sf)
For statement B;
Given area of a rectangle with measured length = 2.536 mm and width = 1.41 mm.
Area of the rectangle = 2.536mm * 1.41mm
Area of the rectangle = 3.57576mm²
Similarly, Since 1.41mm has 3 significant figure compare to 2.536 that has 4sf, hence we will convert our answer to 3 significant figure.
Area of the rectangle = 3.58mm² (to 3sf)
Based on the conversion, it can be seen that 3.6mm² is greater than 3.58mm², hence the area of rectangle in statement A is greater than the area of the rectangle in statement B.
A surveyor measures the distance across a straight river by the following method: Starting directly across from a tree on the opposite bank, he walks x = 118 m along the riverbank to establish a baseline. Then he sights across to the tree. The angle from his baseline to the tree is = 33.4°. How wide is the river?
Answer:
68.5 meters
Explanation:
To solve this problem, we can use trigonometry and create a right triangle with the river as the hypotenuse.
Let's call the width of the river "w". We can use the sine function to find the length of the opposite side of the triangle (the distance from the surveyor to the tree).
sin(33.4°) = opposite/hypotenuse
sin(33.4°) = w/x
w = x * sin(33.4°)
w = 118 m * sin(33.4°)
w = 68.5 m
Therefore, the width of the river is approximately 68.5 meters.
What is the effect of erosion?
A. New land forms at the mouth of a river.
B. New land forms at the top of a mountain.
C. A mountain forms.
D. A fossil is created.
Pretty Easy question please answer only 20 minutes left:
A summary of the results of a scientific investigation is called a:
observation
research
hypothesis
conclusion
Answer:
D. Conclusion.
Explanation:
A piece of wood 350 mm × 350 mm and 15 mm thick conducts heat through its thickness under steady state conditions. The rate of heat flow is measured to be 14.0 watts when the temperature difference is 28 C°. Determine the coefficient of thermal conductivity for this wood
The coefficient of thermal conductivity (k) is related to the rate of heat flow (Q), the cross-sectional area (A), the length (L), the temperature difference (ΔT), and the thermal resistance (Rth) by the following equation:
k = Q / (A * ΔT * L) = Rth * (A * ΔT)
Reorganizing this equation gives:
Rth = k / (A * ΔT)
The given information in the problem is:
Rate of heat flow (Q) = 14.0 watts
Thermal resistance (Rth) = (350 mm × 350 mm × 15 mm) / (14.0 watts) = 31.5 mm⁴/C
Temperature difference (ΔT) = 28°C
Substituting these values into the equation, we have:
k = Q / (A * ΔT) = 14.0 W / (0.35 m² * 28°C) = 1.94 W/mK
So the coefficient of thermal conductivity (k) for this wood is approximately 1.94 W/mK.
what type of occupation is teaching?
Planets A and B have the same size, but planet A is half the mass of planet B.
Which statement correctly explains the weight you would experience on each
planet?
OA. You would weigh the same on both planets because the planets
are the same size.
OB. You would weigh the same on both planets because your mass
would be the same on both.
OC. You would weigh more on planet A because it has less mass than
planet B.
OD. You would weigh less on planet A because it has less mass than
planet B.
The correct answer is option "OD. You would weigh less on planet A because it has less mass than planet B."
Weight is the force of gravity acting on an object, and it depends on the mass of the object and the mass of the planet it is on. The gravitational force is directly proportional to the mass of the planet. Therefore, if planet A has less mass than planet B, the gravitational force on planet A would be weaker than on planet B.
Weight is not determined by the size of the planet but rather by its mass. Even if two planets have the same size, their masses can be different. So, statement OA is incorrect.
Similarly, your mass does not change when you move to a different planet. Mass is a measure of the amount of matter in an object and remains constant regardless of the location. Therefore, statement OB is incorrect.
Since planet A has less mass, the gravitational force acting on you would be weaker compared to planet B. This results in you weighing less on planet A. Thus, statement OD is the correct explanation for the weight difference between the two planets.
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19. Assume this process is 10% efficient, how much work is done by the gas expanding into the atmosphere?
The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.
The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula
W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.
Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.
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A cubic box is completely filled with 2800 g of water. What is the length of one side of the box, in meters?
m
Explain your reasoning.
Since the density of water is
cm3 is
g/cm3, then the volume of 2800 g of water is
cm on each side. Converting [ cm to meters, the cube is
Proy
13 of 15
⠀⠀⠀
Next
cm³. A cubic box with a volume of [
m on each side.
The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.
Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.
Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.
So the filled cubic box has a side length of approximately 0.141 m.
A horizontal force of 25 N is exerted on a box (mass 10 kg), as shown in the diagram. The box accelerates at 2.0 m.s-2. What is the magnitude of the frictional force acting between the box and the floor?
Answer:
the magnitude of the frictional force acting between the box and the floor is 5 N.
Explanation:
Blocks A and B of masses m and 2m, respectively, are connected by a light string and are pulled along a horizontal surface of negligible friction by a horizontal force of magnitude F, as shown in the figure. The tension in the string is T. If the masses of the blocks are doubled, and the magnitude of the horizontal force remains the same, the tension in the string will be:
a) 1/4T
b) 1/2T
c) T
d) 2T
e) 4T
When the masses of the blocks are doubled and the force applied is constant, the tension in the string will be the same.
The given parameters:
Mass of block A = mMass of block B = 2mApplied horizontal force, = FTension in the string, = TThe acceleration of the blocks is calculated as follows;
\(a = \frac{F}{m + 2m} \\\\a = \frac{F}{3m}\)
The tension in the string is calculated as follows;
\(T = ma\\\\T = m(\frac{F}{3m)}\\\\T= \frac{F}{3}\)
When the masses of the blocks are doubled and the force applied is constant;
\(a = \frac{F}{2m + 4m} \\\\a = \frac{F}{6m}\)
The new tension in the string is calculated as follows;
\(T_2 = ma\\\\T_2 = (2m) (\frac{F}{6m} )\\\\T_2 = \frac{F}{3} = T\)
Thus, when the masses of the blocks are doubled and the force applied is constant, the tension in the string will be the same.
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What is audience going to be in the nine grade physic MCAS 
The audience for the 9th grade physics MCAS is students in the 9th grade who are taking the Massachusetts Comprehensive Assessment System (MCAS) physics exam.
How to explain the informationThe exam is designed to assess students' knowledge and skills in physics, and it is used to make decisions about students' placement in courses, graduation requirements, and eligibility for college and career programs.
The 9th grade physics MCAS is a multiple-choice exam that consists of 50 questions. The questions are based on the Massachusetts Curriculum Framework for Science, which outlines the standards that students are expected to meet in physics.
Students who take the 9th grade physics MCAS must score at least proficient in order to meet the state's graduation requirements. Students who score below proficient may be required to take additional courses or remediation.
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The velocity of an object is what from 15 seconds to the end of the graph according to the following position vs time graph?
A: -2 m/a
B: -1 m/s
C: 0 m/s
D: 1m/s
Initial position, u = 10 m
Final position, v = 5 m
Change in time, ∆t = 5 s
We know that, velocity = ∆x / ∆t
where, ∆x is the displacement and ∆t is the change in time.
∆x = v - u
∆x = 5 m - 10 m
∆x = -5 m
Velocity = ∆x / ∆t
Velocity = -5 m / 5 s
Velocity = -1 m/s
Therefore, B: -1 m/s is the correct answer. A negative velocity means the object is traveling in the other direction.
A uniformly charged insulating sphere with radius r and charge +Q
lies at the center of a thin-walled hollow cylinder with radius R>r
and length L>2r. The cylinder is non-conducting and carries no net charge.
1:Determine the outward electric flux through the rounded "side" of the cylinder, excluding the circular end caps. (Hint: Choose a cylindrical coordinate system with the axis of the cylinder as its z -axis and the center of the charged sphere as its origin. Note that an area element on the cylinder has magnitude dA=2πRdz
2:Determine the electric flux upward through the circular cap at the top of the cylinder.
3:Determine the electric flux downward through the circular cap at the bottom of the cylinder.
4:Add the results from parts A - C to determine the outward electric flux through the closed cylinder.
5:What result is expected according to Gauss's law?
Note:Express your answers in terms of electric constant ϵ0
and some or all of the variables r, R , L , Q .
According to Gauss' equation, the total flux of an electric field in a confined surface is directly proportional to the charge enclosed.
State Gauss’s law.1)To determine the outward electric flux through the rounded "side" of the cylinder, we can use Gauss's law. We choose a cylindrical Gaussian surface with radius r and length L, centered at the origin (where the charged sphere is located). The electric field due to the sphere is spherically symmetric, so the electric field lines are parallel to the cylinder's axis and perpendicular to its sides.
E = (1/4πϵ0) (Q/r^2)
where r is the distance from the origin (center of the sphere) to the point on the Gaussian surface.
The area element of the Gaussian surface is dA = 2πRdz, where dz is an element of length along the cylinder's axis. The electric flux through the top and bottom surfaces of the Gaussian surface is then given by:
Φ = ∫E⋅dA = E ∫dA = E(2πR)L
Substituting the expression for the electric field, we have:
Φ = (Q/2ϵ0r^2)(2πRL)
Therefore, the outward electric flux through the rounded "side" of the cylinder is:
Φ = (Q/ϵ0)(R/Lr^2)
2)To determine the electric flux upward through the circular cap at the top of the cylinder, we use a flat Gaussian surface with radius R and height r, centered at the top of the cylinder. The electric field due to the charged sphere is perpendicular to the Gaussian surface, so the electric flux through the top cap is simply the flux through the flat Gaussian surface. The electric field at any point on the Gaussian surface is given by Coulomb's law as:
E = (1/4πϵ0) (Q/R^2)
The area element of the Gaussian surface is dA = πR^2, so the electric flux through the top cap is given by:
Φ = ∫E⋅dA = E ∫dA = EπR^2
Substituting the expression for the electric field, we have:
Φ = (Q/ϵ0)(R/r^2)
3)To determine the electric flux downward through the circular cap at the bottom of the cylinder, we use a similar flat Gaussian surface with radius R and height r, centered at the bottom of the cylinder. The electric flux through the bottom cap is also given by:
Φ = (Q/ϵ0)(R/r^2)
4)Adding the results from parts 1-3, we have the total outward electric flux through the closed cylinder as:
Φ_total = Φ_side + Φ_top + Φ_bottom
= (Q/ϵ0)(R/Lr^2) + 2(Q/ϵ0)(R/r^2)
Simplifying this expression, we have:
Φ_total = (Q/ϵ0) [(2R/r^2) + (R/Lr^2)]
5)According to Gauss's law, the total outward electric flux through a closed surface is proportional to the total charge enclosed within that surface. In this case, the closed surface is the cylindrical Gaussian surface with radius r and length L, centered at the origin (where the charged sphere is located). The charge enclosed within this surface is simply the charge of the sphere, which is +Q. Therefore, we expect the total outward electric flux through the closed cylinder to be:
Φ_total = Q/
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The French motto of equality supports sociology by reminding people that
they:
A. are free to study what causes problems.
B. are all brothers regardless of where they were born.
C. should follow the rules of the government.
D. need to find comfort in their religious beliefs.
Answer:
are free to study what causes problems
What is the temperature change of The water