please help! What is the relationship between velocity and acceleration?

Answer:

Explanation:

The horizontal velocity is 1.61.

Answer:

the glove could be heavy so slowing down his power

Explanation:

JUST GUESSED

Answer:

c

Explanation:

units c mark me brainless k

Answer:

e

Explanation:

Answer:

For a thermodynamic system to be in equilibrium, all intensive (temperature, pressure) and extensive thermodynamic properties (U, G, A, H, S, etc) must be constants. Hence, the total change in any of those properties (dℑ ) must be zero at equilibrium.

Explanation:

hope it helps :)

Answer: For a thermodynamic system to be in equilibrium, all intensive (temperature, pressure) and extensive thermodynamic properties (U, G, A, H, S, etc) must be constants. Hence, the total change in any of those properties (dℑ ) must be zero at equilibrium.

Explanation:

8.27 x 1013 meres is the orbital radius.

Jupiter's mass, 1.9 x 1027 kg, and the time interval, 16.9 days, are equal to 1.46 x 106 seconds. The radius is needed, thus r. Solution

The moon must be held in its orbit by a gravitational force equal to the centripetal force between Jupiter and the moon.

6.67 x 10⁻¹¹ N/m²kg

2 x 1.9 x 10/27 x 1.46 x 10'6 / 4 r = 6.85 x 102'7 G = 6.67 x 10'11 N/m2kg2 r = 8.27 x 10'7

The second-largest moon in Jupiter's orbit and the third-largest moon in the solar system is called Callisto. Of all the objects in our solar system, its surface has the most craters.

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Answer:

The net force required to bring the car to rest is 11,900 N. Since the car is slowing down, the direction of the net force must be opposite to the initial velocity. Therefore, the direction of the net force is opposite to the initial direction of the car's motion.

Explanation:

First, we need to convert the speed from km/h to m/s:

100 km/h * (1000 m/km) / (3600 s/h) = 27.78 m/s

The initial kinetic energy of the car is:

KE = (1/2) * m * v^2

KE = (1/2) * 1350 kg * (27.78 m/s)^2

KE = 535,500 J

To bring the car to a stop, the net force applied over the distance traveled must equal the initial kinetic energy. So:

work done = force * distance = KE

Rearranging this equation, we get:

force = KE / distance

Substituting the values we have, we get:

force = 535,500 J / 45 m

force = 11,900 N

The net force required to bring the car to rest is 11,900 N. Since the car is slowing down, the direction of the net force must be opposite to the initial velocity. Therefore, the direction of the net force is opposite to the initial direction of the car's motion.

Answer:

\(a=-0.001388\ m/s^2\)

Explanation:

Given that,

Initial speed of a train, u = 2.5 m/s

Finally, it reaches the station, v = 0 (at rest)

Time, t = 30 minutes = 1800 s

Acceleration is equal to the rate of change of velocity. So,

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{0-2.5}{1800}\\\\a=-0.001388\ m/s^2\)

So, its acceleration is \(0.001388\ m/s^2\).

Answer:

no se pregúntale a otro gracias cuidate :)

The impact will last for 3.3 milliseconds, the average force applied to the nail will be [m (v² - u²)]/2s, and the average force applied to the nail will be 883.2 N, respectively.

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

Given data;

Average force,F = ?

Mass,m = 0.46 kg

Acceleration,a

Final velocity,v = 0 m/sec

Initial velocity,u = 6.5 m/sec

The duration of the impact, assuming the acceleration is constant is found with the help of Newton's third equation of motion as;

v²=u²+2as

0  = (6.5)² + 2 ×a × 1.1 × 10⁻²

- 42.25 = 2 × a × 1.1 × 10⁻²

a = - 1920 m/s²

a = (v-u)/t

-1920 = (0-6.5)/t

t = 3 × 10⁻³ sec

t = 3.3 milli second

From Newton's third equation of motion;

v² = u² +2as

a = (v² - u² ) /2s

The average force exerted on the nail, in terms of the mass, initial velocity, and distance traveled is;

F = ma

F = [m (v² - u² )] /2s

The average force, in newtons, exerted on the nail is;

F = [m (v² - u² )] /2s

F= ma

Substitute the given value;

F = 0.469 × 1920

F = 883.2 N

Hence the duration of the impact, the average force exerted on the nail and the average force, in newtons, exerted on the nail will be 3.3 milliseconds, F = [m (v² - u² )] /2s and 883.2 N respectively.

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One of the major effects of heat transfer is temperature change: heating increases the temperature while cooling decreases it. We assume that there is no phase change and that no work is done on or by the system. Experiments show that the transferred heat depends on three factors—the change in temperature, the mass of the system, and the substance and phase of the substance.

Figure a shows a copper-colored cylinder of mass m and temperature change delta T. The heat Q, shown as a wavy rightward horizontal arrow, is transferred to the cylinder from the left. To the right of this image is a similar image, except that the heat transferred Q prime is twice the heat Q. The temperature change of this second cylinder, which is also labeled m, is two delta T. This cylinder is surrounded by small black wavy lines radiating outward. Figure b shows the same two cylinders as in Figure a. The left cylinder is labeled m and delta T and has a wavy heat arrow pointing at it from the left that is labeled Q. The right cylinder is labeled two m and delta T and has a wavy heat arrow pointing to it from the left labeled Q prime equals two Q. Figure c shows the same copper cylinder of mass m and with temperature change delta T, with heat Q being transferred to it. To the right of this cylinder, Q prime equals ten point eight times Q is being transferred to another cylinder filled with water whose mass and change in temperature are the same as that of the copper cylinder.

Answer:

τ = 5 s

Explanation:

When a vibrating body is damped. Its amplitude starts to decrease. This decrement is exponential. And it is given as follows:

\(X = X_{0}e^{-\frac{t}{2\tau}\)

where,

τ = Time Constant = ?

X = Instantaneous value of amplitude

X₀ = Initial Value of amplitude

t = time interval = 10 s

The ratio of decrement is given as:

\(\frac{X}{X_0} = 36.8\% = 0.368\)

therefore, using these values, we get:

\(\frac{X}{X_{0}} = 0.368 = e^{\frac{10\ s}{2\tau}}\)

Taking natural log (ln) on both sides, we get:

\(ln(0.368) = \frac{10\ s}{2\tau}\\\\\tau = \frac{10\ s}{2ln(0.368)}\)

τ = 5 s

The value of the time constant for the decrease in the amplitude of this oscillator is 5.

Given the following data:

To determine the value of the time constant:

Mathematically, the amplitude for damped harmonic motion is given by the formula:

\(X = X_o e^\frac{t}{2 \tau}\)

Where:

Rearranging the formula, we have:

\(\frac{X}{X_o} = e^{-\frac{t}{2 \tau}}\)

Substituting the given parameters into the formula, we have;

\(0.368 = e^\frac{-10}{2 \tau}\\\\ln(0.368) = \frac{-10}{2 \tau}\\\\-0.9997 = \frac{-10}{2 \tau}\\\\2 \tau \times -0.9997 = 10\\\\-1.9994\tau=-10\\\\\tau =\frac{-10}{-1.9994} \\\\\tau = 5.0\)

Time constant = 5

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What is common among all the graphs is that they all show an object that is moving.

In the distance time graph, we have the distance on the vertical axis and we have the time on the horizontal axis and the shape of the plots may differ depending on the nature of the motion of the objects.

Graphs of distance vs time help us to examine motion by showing how an object has moved over time. All objects shown on a distance vs. time graph are shifting positions over time, regardless of the graph's specific shape or slope, and the graph reveals information about the direction and speed of their motion.

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The total distance traveled by the skier is  160 m.

option C.

Distance is a measure of how far apart two objects or points are. It can be defined as the numerical value of the physical space between two objects or points.

Distance can be measured in a variety of units, such as meters, feet, miles, or kilometers, depending on the system of measurement used.

Distance can also refer to the length of a path between two points, which can be a straight line or a curved line.

The total distance traveled by the skier is calculated as follows;

total distance = distance ( 0 min) + distance (1 min) + distance (2 min) + distance ( 3 mins)

total distance = 0 m + (120 m - 0 m) + ( 160 m - 120 m )

total distance = 0 m + 120 m + 40 m = 160 m

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Answer:

D. Impulse

Explanation: Hope this helps

A Torque is a twisting force, or turning moment, it is a vector quantity with both magnitude and direction e.g Turning the handle of a cork-screw clockwise and then counterclockwise will advance the screw first inward and then outward By convention, counterclockwise torques are positive and clockwise torques are negative.

The direction is perpendicular to both the radius from the axis and to the force. It is conventional to choose it in the right hand rule direction along the axis of rotation.

Counterclockwise is the positive rotation direction and clockwise is the negative direction.

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The magnitude of the resultant vector, representing the actual path of the boat, is approximately 1.42 m/s.

To find the magnitude of the resultant vector, we need to consider the boat's velocity and the velocity of the river. The boat's velocity is given as 0.75 m/s, and the river's velocity is given as 1.2 m/s.

Since the boat is moving in a river, we can think of the boat's velocity as a combination of two velocities: its own velocity and the velocity of the river. The resultant vector represents the actual path of the boat, considering both velocities.

To calculate the resultant vector, we can use vector addition. The magnitude of the resultant vector can be found by taking the square root of the sum of the squares of the boat's velocity and the river's velocity. Mathematically, we have:

Resultant magnitude = √(boat velocity^2 + river velocity^2)

Plugging in the given values, we have:

Resultant magnitude = √(0.75^2 + 1.2^2)

= √(0.5625 + 1.44)

= √2.0025

≈ 1.42 m/s

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Answer:

True

Explanation:

It definetly is because, if we are biased it sets us up to fail on some things.

Answer:

The relative uncertainty gives the uncertainty as a percentage of the original value. Work this out with: Relative uncertainty = (absolute uncertainty ÷ best estimate) × 100%. So in the example above: Relative uncertainty = (0.2 cm ÷ 3.4 cm) × 100% = 5.9%. The value can therefore be quoted as 3.4 cm ± 5.9%.

Explanation:

hope it helps :)

If one ball is dropped at rest from a height of h = 65 m.  The acceleration of the two balls is: -9.8 m/s^2 for both balls.

Let's start by finding the time it takes for the two balls to meet. We know that the ball thrown upward starts from rest, so its initial velocity is 0 m/s. We can use the following kinematic equation:

y = v_i*t + (1/2)at^2

where y is the displacement (in this case, it is the distance between the two balls), v_i is the initial velocity, a is the acceleration, and t is the time. We can set y equal to the initial height of the dropped ball, which is h = 65 m. For the ball thrown upward, the initial position is y = 0.

For the dropped ball:

y = h = 65 m

v_i = 0 m/s

For the ball thrown upward:

y = 0

v_i = 0 m/s

Using the given information, we can solve for t:

h = (1/2)at^2

65 m = (1/2)*(-9.8 m/s^2)t^2

t = sqrt(65 m / (1/2(-9.8 m/s^2))) ≈ 3.64 s

So it takes about 3.64 seconds for the two balls to meet.

Now, we can find the acceleration of the two balls. For the dropped ball, the acceleration is simply the acceleration due to gravity, which is -9.8 m/s^2. For the ball thrown upward, the acceleration is also the acceleration due to gravity, but with a negative sign since it is moving in the opposite direction of gravity. Therefore, the acceleration of the two balls is:

a = -9.8 m/s^2 for both balls

This means that both balls experience the same acceleration due to gravity, regardless of their initial velocities.

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Answer:

independent” variable goes on the x-axis (the bottom, horizontal one) and the “dependent” variable goes on the y-axis (the left side, vertical one).

Explanation:

this is the answer I don't know if it's right

Answer:

gpe gained = 60J

Explanation:

gravitational potential energy  =  mass * gravity * height

gpe =  2 kg * 10 N * 3 m

gpe = 60J

the angle between vectors is 1

let,  vector A,B and |A| =5 , |B| =12

According to dot product,

A.B = |A| |B| cos∝

-6 = 5x12cos∝

cos∝ = 0.99

nearly equal to 1

hence the angle between A and B is 1

Answer:

ΔS = 3.5 m

Explanation:

First, apply the 2º Newton's Law to find the resulting acceleration.

∑F = m × a

F = m × a

14 = 32 × a

a = 14 /32 = 7/16

a = 0.4375 m/s²

Then, we must apply the equation of accelerated movement:

ΔS = V₀*t + (1/2)*a*t²

Starting from the rest and using the value of acceleration:

ΔS = 0*4 + (1/2)*(0.4375)*(4)²

ΔS = (1/2)*(0.4375)*(16)

ΔS = 3.5 m

Time = t = 6.62 s

Explanation:

Given data:

Height = h = 215 m

Initial velocity =  = 0 m/s

gravitational acceleration = g = 9.8 m/s²

Time = t = ?

According to the second equation of motion

As the initial velocity is zero, the first term of right-hand side of the above equation is equal to zero.

                                       t² = 2h/g

                                        t = square root 2h/g

                                        t = square root 2x215/9.8

                                        t = 6.62 s

The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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The work done, by the force of friction on the box as the box moves a distance is 13.12 J.

The work done by force of friction is calculated from the product of force of friction and distance through which the object travelled and it is given as;

W = Fₙd

where;

W = μmg x d

Where;

W = 0.431 x 6.25 x 9.8 x 0.497

W = 13.12 J

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Answer:

Explanation:

A scientist adds different amounts of salt to 5 bottles of water. She then measures how long it takes for the water to boil. What is the responding variable in this experiment? A. The time it takes for the water to boil B. The amount of salt added to the water C. The kind of bottles used D. The brand of salt used

The tax rate you will pay is displayed in tax brackets for each category of taxable income.

Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.

Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.

As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.

Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.

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The magnitude of the velocity of the third particle is \(7.065 * 10^-^2^0\) m/s, and its direction is 0° counterclockwise from the +x-axis.

Mass of the unstable nucleus (m1) =\(1.9 * 10^-^2^6\) kg

Mass of the first particle (my) = \(5.5 * 10^-^2^7\)kg

Mass of the second particle (m2) = \(8.0 * 10^-^2^7\) kg

Velocity of the first particle (vi) = \(6.3 * 10^6\)  m/s in the positive y-direction

Velocity of the second particle (v2) =\(4.5 * 10^6\) m/s in the positive x-direction

velocity of the third particle = \(V_3\)and  mass =  \(M_3\)

We apply  the principle of conservation of momentum:

Total momentum before disintegration = Total momentum after disintegration

Initial momentum = Final momentum

The initial momentum= 0  because the unstable nucleus is initially at rest.

Final momentum = (Mass of the first particle * Velocity of the first particle) + (Mass of the second particle * Velocity of the second particle) + (Mass of the third particle * Velocity of the third particle)

0 = (my * vi) + (m2 * v2) + (m3 * v3)

\(3 * v_3 = -[(m_y * v_i) + (m_2 * v_2)]\\m_3 * v_3 = -[(5.5 * 10^-^2^7 kg * 6.3 * 10^6 m/s) + (8.0 * 10^-^2^7 kg * 4.5 * 10^6 m/s)]\\m_3 * v_3 = -[3.465 * 10^-^2^0 kgm/s + 3.6 * 10^-^2^0 kgm/s]\\m_3 * v_3 = -7.065 * 10^-^2^0 kg*m/s\)

\(|v_3| = 7.065 * 10^-^2^0 kgm/s\)

\(θ = tan^(^-^1^)(v_3_y/v_3_x)θ = tan^(^-^1^)(v_3_y/-v_3_x)θ = tan^(^-^1^)(0/7.065 * 10^-^2^0 kg*m/s)θ = tan^(^-^1^)(0)\)

θ = 0°

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