Please help me with this. If a rock is thrown upward on an exoplanet of a nearby star with initial velocity of 20 m/s its height in meters t seconds later is given by y = 20t - 1.87t².

Answer:

7.125 miles

Step-by-step explanation:

Using the triangle midsegment theorem:

Distance of pineapple street = 1/2(distance of kiwi street) = 0.5 * 1.4 = 0. 7 miles

Distance of plum Street = (2 * distance of P to Pineapple street) = 2 * 1.3 = 2.6 miles

Distance from Kiwi to pineapple = 1/2 * distance of apple Street = 0.5 * 2.25 = 1.125 miles

1.3 + 1.3 + 1.4 + 1.125 + 0.7 + 1.3

Step-by-step explanation:

remember, the sum of all angles in a triangle is always 180°.

1. you mean find the angle at A, yes ?

180 = angle A + angle B + angle C =

= angle A + 38 + 90

angle A = 180 - 38 - 90 = 90 - 38 = 52°

2. Pythagoras

AB² = 11² + 8.5² = 121 + 72.25 = 193.25

AB = 13.90143877... in

3. sine/cosine ratio is tangent.

sin(38) × AB = 8.5 in

cos(38) × AB = 11 in

sin(38)/cos(38) = tan(38) = 8.5/11 = 0.772727272...

sin(52) × AB = 11 in

cos(52) × AB = 8.5 in

sin(52)/cos(52) = tan(52) = 11/8.5 = 1.294117647...

4. they are equal. as sin(x) = cos(90-x).

5. they are equal. as cos(x) = sin(90-x).

6. 90°. again, the sum of all angles must be 180°. so, when one angle is all by itself already 90°, then there are only 90° left for the other 2 angles.

7. not sure what you mean by "kissing angles" but

a. sin(40°) = cos(90-40) = cos(50°) = 0.64278761...

b. cos(27°) = sin(90-27) = sin(63°) = 0.891006524...

c. sin(90°) = cos(90-90) = cos(0°) = 1

d. cos(65°) = sin(90 - 65) = sin(25°) = 0.422618262...

Answer:

2

Step-by-step explanation:

Multiply 2/3 by 3 to get 2.

3 1/2 cups can be expressed as the multiplication expression: 3 + 1/2.

To express 3 1/2 cups as a multiplication expression using the unit "1 cup" as a factor, you can write it as:

3 1/2 cups = (3 + 1/2) cups = 3 cups + 1/2 cup

Since there are 1 cup in each term, we can rewrite it as:

3 cups + (1/2) cup

Now, we can express each term as a multiplication expression:

3 cups = 3 * 1 cup = 3

(1/2) cup = (1/2) * 1 cup = 1/2

Putting it all together, the multiplication expression is:

3 * 1 cup + (1/2) * 1 cup = 3 + 1/2

Therefore, 3 1/2 cups can be expressed as the multiplication expression: 3 + 1/2.

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The solution to the system of equations is x = -3 and y = -4.

To solve the system of equations:

Equation 1: 2x - y = -10

Equation 2: 3x + 2y = -1

We can use the method of substitution or elimination to find the values of x and y.

Let's use the method of elimination:

Multiply Equation 1 by 2 to make the coefficients of y in both equations equal:

2(2x - y) = 2(-10)

4x - 2y = -20

Now, we can eliminate y by adding Equation 2 and the modified Equation 1:

(3x + 2y) + (4x - 2y) = -1 + (-20)

7x = -21

x = -3

Substitute the value of x into Equation 1 to solve for y:

2(-3) - y = -10

-6 - y = -10

y = -10 + 6

y = -4

Therefore, the solution to the system of equations is x = -3 and y = -4.

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ORDER FROM LEAST TO GREATEST:

-10, -9, -8, -7,-6, -5, -4, 0, 2, 9, 10.

Hey there!

When we have negative numbers, we might count like this: ....-5,-4,-3,-2,-1,0,1,2,3....

As you can see, the negative number is known as greater if it is closer to zero, so -1 is greater than -100.

With this information, let's order these numbers! :)

-10,-9,-8,-7,-6,-5,-4,0,2,9,10

I hope that this helps!

The value of x is 18.4 and the value of y is 22.5 in the cube

From the question, we have the following parameters that can be used in our computation:

The diagram of a cube.

Each edge of the cube = 13 units.

The diagonal of each face is x units long

So, we have

x^2 = 13^2 + 13^2

Evaluate

x = 18.4

The diagonal of the cube is y units long.

So, we have

y^2 = 13^2 + 13^2 + 13^2

Evaluate

y = 22.5

Hence, the value of x is 18.4 and the value of y is 22.5

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The number of extra tables that you need to double the original seating capacity will be 7.

The allocation of weights to the important variables that produce the calculation's optimum is referred to as a direct consequence.

The seating capacity y for a banquet hall is represented by y = 8x + 56, where x is the number of extra tables you need.

If the no extra table is there. Then the value of 'y' will be

y = 8 (0) + 56

y = 56

Then the number of extra tables do you need to double the original seating capacity will be

8x + 56 = 2 × 56

8x = 56

x = 7

Then the number of extra tables that you need to double the original seating capacity will be 7.

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Answer:

a triangle that may not have the same dimensions as the bases

Step-by-step explanation:

The cross section of the figure that is perpendicular to the triangular bases and passes through a vertex of the triangular bases would be a triangle that may not have the same dimensions as the bases.

Answer:

-5

Step-by-step explanation:

yw

Answer:

-5

Step-by-step explanation:

the two minus signs next to each other make it a plus sign so the equation would become

-10 + 5

which is -5

The equation of the ellipse that has the center at (0, 0) the vertex at (-8, 0), and the covertex at (0, 4) is; \(\frac{x^2}{64} + \frac{y^2}{16} = 1\)

The standard form of the equation of an ellipse is as follows;

\(\frac{x^2}{a^2} + \frac{y^2}{b^2}=1\)

Where;

a = The semi major axis

b = The semi minor axis

The semi major axis is the distance from the center of the ellipse to the vertex, and the semi minor axis is the distance from the center to the co-vertex.

The coordinate of the center of the ellipse = (0, 0)

The coordinates of the vertex = (-8, 0)

The coordinates of the co-vertex = (0, -4)

The ellipse has an horizontal major axis, therefore;

a = |0 - (-8)| = 8, and b = |0 - 4| = 4

The equation of the ellipse is therefore;

\(\frac{x^2}{8^2} + \frac{y^2}{4^2}=\frac{x^2}{64} + \frac{y^2}{16} = 1\)

\(\frac{x^2}{64} + \frac{y^2}{16} = 1\)

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Answer:

892

Step-by-step explanation:

she could have scored the 10 points in 302400 ways.

The given parameters are

n= total points =10

r1 =one-point free throw = 1

r2 = two-point field goals = 2

r3 =  three-point field goals = 3

The number of ways (k) she could have scored the points is:

k=(n!)/(r1!×r2!×r3!)

The factorial function is a mathematical formula represented by an exclamation mark "!".

k= 10!/(1!×2!×3!)

k= 3628800/(1×2×6)

k= 302400

so.. she could have scored the 10 points in 302400 ways.

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The statement "the Y value of function I would ask equals -2 is greater than the Y value function be when I ask equals negative to the Y value function a 1X equals -2 is less than the Y value a function be one x was -2" is true.

Given, two functions  y = -2f(x) = 1/x

To determine whether the statement "the Y value of function I would ask equals -2 is greater than the Y value function be when I ask equals negative to the Y value function a 1X equals -2 is less than the Y value a function be one x was -2" is true or false, we need to find the value of Y for both functions when x = -2.

Substituting x = -2 in the functions we get:I would ask y = -2(-2) = 4f(-2) = 1/(-2) = -1/2Therefore, the Y value of the function I would ask is greater than the Y value function be when I ask equals negative to the Y value function a 1X equals -2 is less than the Y value a function be one x was -2. Hence, the given statement is true.

Therefore, the statement "the Y value of function I would ask equals -2 is greater than the Y value function be when I ask equals negative to the Y value function a 1X equals -2 is less than the Y value a function be one x was -2" is true.

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Answer:

5(10-3)=8 is False

Step-by-step explanation:

5(10-3)=35

The required frequency distribution table is below in the solution part.

The relative frequency of the data is the ratio of the given frequency to the total frequency in the observation.

To create a frequency distribution with 5 classes, we first need to find the range of the data, which is the difference between the largest and smallest values:

Range = 10

Next, we divide the range by the number of classes we want (5) to get the class width:

Class width = Range / Number of classes

Class width = 10 / 5

Class width = 2

Now, we can create the frequency distribution table:

Class      Frequency

0-1                5

2-3                29

4-5                16

6-7                14

8-9                 2

10-11               2

___________________

Total             73

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If the certain truck traveled 7,605 miles in 15 days. The average number of miles traveled per day will be 507.

It is defined as the single number that represents the mean value for the given set of data or the closed value for each entry given in the set of data.

It is given that, a certain truck traveled 7,605 miles in 15 days.

The average number of miles traveled per day is obtained by dividing the total distance traveled by the total time taken as,

Suppose the average number of miles traveled per day is x,

x=76015 / 15

x=507 miles per day.

Thus, if the certain truck traveled 7,605 miles in 15 days. The average number of miles traveled per day will be 507.

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Answer:

Step-by-step explanation:

Perimeter = 32

length = x - 3

width = 2x + 7

Perimeter = 2* Length + 2* width

Perimeter = 2*(x-3) + 2(2x + 7) = 32         Remove the brackets.

2x - 6 + 4x + 14 = 32                                  Combine

6x + 8 = 32                                                 Subtract 1 from both sides

6x = 32 - 8

6x = 24                                                       Divide by 6

x = 24/6

x = 4

So the base = x - 3 = 4 - 3 = 1

The height  = 2*4 + 7 = 8 + 7 = 15

The slope intercept form of the given equation is,

y = 5x - 1/4

Given an equation of a line as,

5x - y = 1/4

We have to write the equation of the line in slope intercept form.

Equation of the line in slope intercept form is,

y = mx + c

Here m is the slope and c is the y intercept.

Rearranging the given equation,

5x = y + 1/4

5x - 1/4 = y

or,

y = 5x - 1/4

Hence the slope intercept form is y = 5x - 1/4.

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Answer:

(3) Median

Step-by-step explanation:

I would say median because it most likely wouldn't be any of the others. Mean would be thrown off with the outlier 0.80. Mode wouldn't really work for this. I don't think standard deviation would work because this isn't coninuous data.

Hope it helps and is correct!

Answer:

c(3a) = 2(3a)^2 - 4(3a) + 3 = 18a^2 - 12a + 3.

Step-by-step explanation:

c(3a) = 18a^2 - 12a + 3

Note: this is the simplified form of the expression.

Answer:

the Inverse of the matrix is; A⁻¹

\(= \left[\begin{array}{ccc}\frac{-3}{(2k)} &\frac{1}{k}&\frac{15}{(2k)}\\\frac{-3k+15}{(10k)}&\frac{-1}{k}&\frac{-75+13k}{(10k)}\\\frac{1}{2}&0&\frac{-5}{2}\end{array}\right]\)

Step-by-step explanation:

Given the data in the question;

Matrix A = \(\left[\begin{array}{ccc}-25&-25&-13\\k&0&3\\-5&-5&-3\end{array}\right]\)

To find the Inverse of matrix A

A⁻¹ = Adj.A / det.A

so

Determinant of the matrix A will be

|A| = -25( 0 + 15) + 25( -3K + 15 ) - 13( -15K + 0 )

= -375 - 75K + 375 + 65K

= -10K

Now, the adjoin of matrix A will be

Adj.A = \(\left[\begin{array}{ccc}15&-10&-75\\3k-15&10&75-13k\\-5k&0&25k\end{array}\right]\)

The Inverse of the matrix is;

A⁻¹ = Adj.A / det.A

\(= \frac{1}{-10k} \left[\begin{array}{ccc}15&-10&-75\\3k-15&10&75-13k\\-5k&0&25k\end{array}\right]\)

\(= \left[\begin{array}{ccc}\frac{15}{-10k} &\frac{-10}{-10k}&\frac{-75}{-10k}\\\frac{3k-15}{-10k}&\frac{10}{-10k}&\frac{75-13k}{-10k}\\\frac{-5k}{-10k}&\frac{0}{-10k}&\frac{25k}{-10k}\end{array}\right]\)

\(= \left[\begin{array}{ccc}\frac{-3}{2k} &\frac{1}{k}&\frac{15}{2k}\\\frac{-3k+15}{10k}&\frac{-1}{k}&\frac{-75+13k}{10k}\\\frac{1}{2}&0&\frac{-5}{2}\end{array}\right]\)

\(= \left[\begin{array}{ccc}\frac{-3}{(2k)} &\frac{1}{k}&\frac{15}{(2k)}\\\frac{-3k+15}{(10k)}&\frac{-1}{k}&\frac{-75+13k}{(10k)}\\\frac{1}{2}&0&\frac{-5}{2}\end{array}\right]\)

Therefore the Inverse of the matrix is; A⁻¹

\(= \left[\begin{array}{ccc}\frac{-3}{(2k)} &\frac{1}{k}&\frac{15}{(2k)}\\\frac{-3k+15}{(10k)}&\frac{-1}{k}&\frac{-75+13k}{(10k)}\\\frac{1}{2}&0&\frac{-5}{2}\end{array}\right]\)

Since the mass of diamond is 481.3 g, the volume of diamond is 137.12 cm³

Volume is the capacity of an object

Since large diamond with a mass of 481.3 grams was recently discovered in a mine. If the density of the diamond is 3.51 grams over centimeters cubed, to determine the volume of the diamond, we proceed as follow.

We know that density, ρ = m/v where

Now, since we desire the volume of the object, we make the volume subject of the formula, so, we have that

v = m/ρ

Given that

Substituting the values of the variables into the equation, we have that

v = m/ρ

= 481.3 g/3.51 g/cm³

= 137.123 cm³

≅ 137.12 cm³

So, the volume is 137.12 cm³

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Answer:

dividing by 1000

Step-by-step explanation:

False.  No, extraneous variables should not be included as independent variables in the context of dependent sample designs.

In the context of dependent sample designs, extraneous variables should be controlled or accounted for in the study, but they should not be included as independent variables. This is because these extraneous variables are likely to be correlated with the dependent variable and including them would create an issue of multicollinearity that would affect the statistical analysis and interpretation of the results.

For example, when studying the effect of a new treatment on a group of patients, age, gender, and pre-existing health conditions may be considered as extraneous variables that should be controlled for, but not included as independent variables in the study. In this example, the formula for the regression analysis would be Y = β0 + β1X1 + β2X2 + e, where Y is the dependent variable, X1 and X2 are the independent variables, β0, β1, and β2 are coefficients, and e is the error term.

No, extraneous variables should not be included as independent variables in the context of dependent sample designs.

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Answer:

x=4

Step-by-step explanation:

4(5x+2)=14x+32

20x+8 = 14x+32

20x-14x+8=14x-14x +32 (Both side +14x)

6x+8=32 (cancel 14x -14x)

6x+8-8=32 -8(both side -8)

6x=24 (both side divide 6)

6x/6=24/6

x=4

Answer:

34x+34

Step-by-step

20x+2=14x+32

20x+14x=2+32

34x+2+32

2+32=34

34x=34

The solution for the following are as given below:(fog)(x) = x^2 - 2

(gof)(x) = x^2 - 2x

(fg)(x) = x^2 - 2

(gf)(x) = x^2 - 2x

To compute the composition of two functions, we need to apply one function to the input, and then apply the second function to the output of the first function. For example, to compute (fog)(x), we first evaluate g(x), which gives us x^2 - 1, and then evaluate f(x^2 - 1), which gives us (x^2 - 1) - 1 = x^2 - 2. Similarly, we can compute (gof)(x) by evaluating f(x) = x - 1 first and then evaluating g(x - 1) = (x - 1)^2 - 1.

To compute the product of two functions, we simply multiply them together. For example, (fg)(x) = f(x) * g(x) = (x - 1) * (x^2 - 1) = x^3 - x^2 - x + 1. Similarly, we can compute (gf)(x) = g(x) * f(x) = (x^2 - 1) * (x - 1) = x^3 - 2x^2 + x + 1.

It's worth noting that the order of composition matters in general, which is why (fog)(x) and (gof)(x) give different results. However, in this particular case, since f and g are both quadratic polynomials, they happen to commute, meaning that (fog)(x) = (gof)(x) and (fg)(x) = (gf)(x).

We have:

(fog)(x) = f(g(x)) = f(x^2 - 1) = (x^2 - 1) - 1 = x^2 - 2

(gof)(x) = g(f(x)) = g(x - 1) = (x - 1)^2 - 1 = x^2 - 2x

(fg)(x) = f(g(x)) = f(x^2 - 1) = (x^2 - 1) - 1 = x^2 - 2

(gf)(x) = g(f(x)) = g(x - 1) = (x - 1)^2 - 1 = x^2 - 2x

Therefore:

(fog)(x) = x^2 - 2

(gof)(x) = x^2 - 2x

(fg)(x) = x^2 - 2

(gf)(x) = x^2 - 2x

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The sum of the geometric sequence in this problem is given as follows:

5.77.

A geometric sequence is a sequence of numbers where each term is obtained by multiplying the previous term by a fixed number, which is called the common ratio q.

The first term, the common ratio and the number of terms for this problem are given as follows:

\(a_1 = 10, q = -\frac{2}{3}, k = 8\)

The formula for the sum of the first n terms is given as follows:

\(S_n = a_1\frac{1 - r^n}{1 - r}\)

Hence the sum for this problem is given as follows:

\(S_8 = 10 \times \frac{1 - \left(-\frac{2}{3}\right)^8}{1 + \frac{2}{3}}\)

\(S_8 = 5.77\)

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After calculating the average of numbers here, the average of the four odd numbers from \(8 \ to \ 15\) is greater than the average of the four even numbers.

The step-by-step solution to this is given below:

To determine which average is greater, let's calculate the averages of the even and odd numbers separately.

The four even numbers from \(8 \ to \ 15 \ are \ 8, 10, 12, and \ 14\). To find their average, we sum them up and divide by \(4\):

\(\[\text{Average of even numbers} = \frac{8 + 10 + 12 + 14}{4} = \frac{44}{4} = 11\]\)

The four odd numbers from \(8 \ to \ 15 \ are \ 9, 11, 13, and \ 15.\) Similarly, we calculate their average:

\(\[\text{Average of odd numbers} = \frac{9 + 11 + 13 + 15}{4} = \frac{48}{4} = 12\]\)

Now, the next step will be comparing the two averages, we find that the average of the four odd numbers, \(12\), is greater than the average of the four even numbers, \(11\).

Therefore, the average of the four odd numbers from \(8 \ to \ 15\) is greater than the average of the four even numbers.

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Answer:

Wait

Step-by-step explanation:

Is a equation or polynomial

Answer:

0, +/- 1. +/- 2

Step-by-step explanation:

\(x^{5} -5x^{3} +4x=0\) Write the equation in the form of P(x) = 0.

\(x(x^{4} - 5x^{2} + 4) = 0\) Factor out the GCF, x.

\(x(x^{2})^{2} - 5x^{2} + 4 = 0\) Factor \((x^{2})^{2}- 5x^{2} + 4 = 0\).

\(x = 0,\) \((x^{2})^{2} - 5x^{2} + 4 = 0\) Let a = \(x^{2}\) and substitute.

\(a^{2} - 5a + 4 = 0\) Factor.

\((a - 4)(a - 1) = 0\) Replace a with \(x^{2}\).

\((x^{2} - 4)(x^{2} -1) = 0\) Factor \((x^{2} - 4)\) as a difference of squares.

\((x -2)(x+2)(x^{2} -1) = 0\) Use the Zero Product Property

\(x = 2, x = -2, x^{2} = -1\)

\(x = 0, 1, -1, 2, -2\)