please help!!! im being timed!! urgeent!!!

Answer:

Explanation:

The gravitational force acting on the ball, F = 10 N (down) The air resistance acting on the ball, f = 1 N (up) We need to find the magnitude of net force acting on the ball. The net force is given by : F' = 9 N. So, the net force acting on the ball is 9 N in downward direction. Hence, this is the required solution

Answer:

Your correct answer is shown down below so that you know...

Explanation:

If you didn't know, a hypothesis is known as an educated guess that can be tested with observations and falsified if it really is false. You cannot prove conclusively that most hypotheses are true because it's generally impossible to examine all possible cases for exceptions that would disprove them.

Answer:

You cannot prove a hypothesis to be true

Explanation:

Answer:

Option C is correct

Explanation:

A supersaturated solution is one that has more solute dissolved than the solution should hold at that temperature.

Examples include carbonated water, sugar syrup, honey.

A solution of a chemical compound can be dissolved in heated water to prepare a supersaturated solution. A solution becomes supersaturated as its temperature is changed.

Answer:

Its A

Explanation:

Answer:

you will be my girl my my girl myyyyy girllll you will be my girl my girl myyyy worldddddd you will be my. smokin ciggarets on teh roof you look so pretty and i love this view we fell inlove in october and thats why i love fall

Explanation:

Answer:

A) x4

Explanation:

Magnification is equal to image size divided by the actual size, or M = I/A.

The image size is the student's drawing, which is 28.8 cm, and the actual size is 7.2 cm. Divide them, and cancel out the units, and you should get:

28.8 cm/7.2 cm = 4

Answer:

In order for sugar to dissolve, there must be an attraction between the two substances.

Explanation:

Water and sugar are both attracted to each other, which is why sugar is able to dissolve in water.

Hope this helps! :)

Answer:

the water was stirred

Explanation:

it’s need as a type of attraction

The angular frequency (w) of the oscillator described by A 1 2 3 4 5 6 7 8 9 10 11 12 t (sec) is 2.0 rad/s (option B).

The angular frequency (w) is given by the formula w = 2πf, where f is the frequency. In this case, the given data points represent the amplitude (A) of the oscillator at different time intervals (t). The time intervals are evenly spaced, so we can assume that the frequency is constant. By observing the data, we can see that the oscillator completes one full oscillation (from 1 to 12) in 6 seconds. Therefore, the frequency is 1 oscillation/6 seconds = 1/6 Hz. Using the formula, we can calculate the angular frequency as w = 2π(1/6) ≈ 2.0 rad/s.

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Answer:

the answer is the concentric sperical shells

Answer:

Gravity

Explanation:

Weight is dependent on the objects mass and the gravitational pull on it.

The period of a physical pendulum depends on its mass distribution and can be calculated using the moment of inertia. The equation for the period takes into account the mass, length, radius, and distance between the pivot and center of mass.

A physical pendulum is a type of pendulum in which the mass is distributed along the length of the pendulum, and its period depends on the distribution of the mass.

To find the period of the physical pendulum, we need to consider the moment of inertia of the system, which is given by the sum of the moment of inertia of the rod and the moment of inertia of the sphere about the pivot.

Assuming that the length of the rod is much greater than the radius of the sphere, we can approximate the moment of inertia of the rod as \((1/3)ml^2\), where m is the mass of the rod and l is its length. The moment of inertia of the sphere about the pivot is \((2/5)mR^2\), where R is the radius of the sphere.

Using the parallel axis theorem, we can find the moment of inertia of the system about the pivot as \((1/3)ml^2 + (2/5)mR^2 + md^2\), where d is the distance between the pivot and the center of mass of the system.

The period of the physical pendulum is given by \(T = 2\pi \sqrt{(I/mgd)}\), where g is the acceleration due to gravity.

Thus, the period of the physical pendulum depends on the distribution of the mass, and it cannot be determined without knowing the values of m, l, R, and d.

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Answer:

3.6 N

Explanation:

The magnitude of centripetal force in this case is equal to the magnitude of tension in the spring.

The formula is :

T= mv²/r ------where T is tension

m= mass of object =0.8 kg

v= velocity of object {tangential velocity} = 3.0 m/s

r= length of string = 2m

Applying the formula with real values;

T= mv²/r

T= {0.8 * 3²} / 2

T= { 7.2}/2 = 3.6 N

The minimum current through R1 will be 10mA.

Using Ohm's Law (V = IR), we can find the minimum current through R1 as follows:

Vr1 = Vz5 + Vz6

where Vr1 is the voltage across resistor R1.

Therefore, the minimum current through R1 is:

Ir1 = Vr1 / R1

Assuming that R1 is a standard value resistor (e.g., 1kΩ), and the Zener voltages are each 5V, the voltage across R1 will be:

Vr1 = Vz5 + Vz6 = 5V + 5V = 10V

Therefore, the minimum current through R1 will be:

Ir1 = Vr1 / R1 = 10V / 1kΩ = 10mA

Current is the flow of electric charge through a conductor or material. It is defined as the rate of flow of electric charge, measured in units of amperes (A). One ampere is equivalent to the flow of one coulomb of electric charge per second.

Electric current is caused by the movement of charged particles, typically electrons, in a circuit. When a voltage is applied to a conductor, it creates an electric field that causes electrons to move through the conductor. This flow of electrons constitutes an electric current.

The direction of electric current is defined as the direction of flow of positive charges, even though the actual charges that move are electrons, which are negatively charged. Electric current can be direct current (DC), where the flow of charge is in one direction, or alternating current (AC), where the direction of flow periodically changes.

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The CRO (Cathode Ray Oscilloscope) will display a triangular wave that is vertically stretched and horizontally compressed.

The vertical deflection plates will cause the triangular wave to be displayed with a peak-to-peak amplitude of\(100 cm (50 V * 0.1 cm/V)\), while the horizontal deflection plates will cause  sawtooth wave to be displayed with a peak-to-peak amplitude of \(5000 cm (100 V * 0.02 cm/V).\) The synchronization of the two inputs will ensure that the triangular wave and the sawtooth wave are displayed in a coordinated manner, with each cycle of the sawtooth wave corresponding to five cycles of the triangular wave. The resulting display will show a pattern of diagonal lines that gradually rise and then quickly drop back to the starting position, with each line representing a cycle of the sawtooth wave.

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Answer:

the average speed of the blocks is 0.36 m/s

Spectral classification is a system that categorizes stars based on their spectral characteristics, specifically the absorption lines in their spectra. These lines are the result of various elements and compounds present in the star's outer layers absorbing specific wavelengths of light.

By examining a star's spectrum, we can identify its temperature, as well as other properties such as chemical composition and luminosity.

The primary classification system used by astronomers is the Harvard Spectral Classification, which organizes stars into seven main classes: O, B, A, F, G, K, and M. These classes are ordered by descending surface temperature, with O being the hottest and M being the coolest. Each class is further divided into subcategories numbered from 0 to 9, which also indicate temperature variations within the class.

To determine the surface temperature of a nearby star, astronomers examine its spectrum and identify the absorption lines corresponding to specific elements. The strength and position of these lines can reveal the star's temperature. For example, a star with strong hydrogen lines would be classified as an A-type star, which has a surface temperature of about 7,500 to 10,000 Kelvin.

In conclusion, the surface temperature of a nearby star can best be determined from spectral classification by examining the absorption lines in its spectrum. By identifying the star's spectral class and subtype, astronomers can infer its surface temperature with relative accuracy. This method plays a crucial role in understanding the properties and evolution of stars in our universe.

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Complete Question:

The surface temperature of a nearby star can best be determined from spectral classification by examining?

Answer:

Given that

speed u=4*10^6 m/s

electric field E=4*10^3 N/c

distance b/w the plates d=2 cm

basing on the concept of the electrostatices

now we find the acceleration b/w the plates  to find the horizontal distance traveled by the electron when it hits the plate.

acceleration a=qE/m=\(1.6*10^{-19}*4*10^3/9.1*10^{-31} =0.7*10^{15}\)=\(7*10^{14}\) m/s

now we find the horizontal distance traveled by electrons hit the plates

horizontal distance

\(X=u[2y/a]^{1/2}\)

=\(4*10^6[2*2*10^{-2}/7*10^{14}]^{1/2}\)

=\(3*10^{-2}\)= 3 cm

Answer:

See the answers below.

Explanation:

The magnitude can be easily found by means of the Pythagorean theorem.

\(C = \sqrt{(C_{x})^{2} +(C_{y})^{2}} \\C=\sqrt{(105)^{2} +(88.2)^{2} } \\C=\sqrt{18804.24}\\C = 137.13 [m]\)

We know that the coordinates in x and in y are negative, therefore the vector should be located in the fourth quadrant, see attached image.

And the angle with respect to the horizontal can be determined by means of the tangent of the angle.

\(tan(\alpha )=\frac{88.2}{105}\\tan(\alpha ) =0.84\\\alpha =tan^{-1} (0.84)\\\alpha =40\)

These are 40 degrees below the X-positive horizontal axis.

Answer:

137.13

Explanation:

I got it right on Acellus

Work is required to accelerate it from rest to a rotation rate of 1.00 revolution per 7.00s is 12,640 Joules

The following equation is used to calculate the net work necessary to accelerate a merry-go-round from resting to a rotational speeds with one rotation every 7.00 secs:

Work is calculated as (mass x radius x angular acceleration) / 2.

In which: 1440 kg in mass

R = 7.50 meters

Angle acceleration is equal to 2/7.00s times 0.89 rad/s2.

Hence, this mathematical methodology is used to compute the net work needed:

Work is equal to (1440 kg x 7.50m2 x 0.89 rad/s2) / (2 x 7.50m x 1440 kg x 1 revolution/7.00s) / 2 = 5,524,000 J or 5.52 MJ.

Acceleration was its term for the variation in velocity. Generally speaking, and sometimes not, acceleration denotes a shift in speed. Regardless of whether an object is moving in a circle, its velocity route is still changing, therefore it keeps gaining speed.

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Answer:

chickens

Explanation:

Answer:

The force that is “left over” after all of the forces acting on an object are cancelled and/or combined is called the net force. A 3 N force and a 7 N force act in the same direction on a box. A 3 N force and a 7 N force act in opposite directions on a box.

The aeronautical beacon for a lighted heliport flashes alternating white and green flashes. A heliport is a dedicated facility for landing and taking off helicopters. The term heliport is used to describe a small airport that is only used for helicopters.

A heliport, like an airport, typically has a landing and takeoff area, a maintenance and fueling area, and a control tower.

An aeronautical beacon is a light placed on top of a structure to make it visible from a distance to pilots flying aircraft. These beacons are intended to assist pilots in locating airports, heliports, and other navigational landmarks. The flash of light from an aeronautical beacon is seen from far away and is quite noticeable.

Aeronautical beacons flash alternating white and green flashes. When pilots are looking for airports and other navigation landmarks, these two colours are easier to see from the air than any other colour combination.

As a result, all aeronautical beacons flash alternating white and green flashes.

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Answer:

Please give options

Explanation:

mark me as brainlist

Answer:

the reaction force is to the left and of the same magnitude

Explanation:

To analyze this collision we see that when the bowling ball collides with the pin it exerts a force on it and by the law of action and reaction the pin exerts a force of equal magnitude and opposite direction on the ball.

Due to the high difference in mass, the speed and direction of the bowling ball is little altered, instead the speed and direction of the pin change significantly.

In summary the reaction force is to the left and of the same magnitude

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\\)

m is the mass

v is the velocity

From the question we have

\(k = \frac{1}{2} \times 1000 \times {26}^{2} \\ = 500 \times 676 \\ = 338000\)

We have the final answer as

Hope this helps you

Answer:

answer is (c) density is not a characteristics of vibration.

hope it is right answer for it!!

Given:

• Length of beam = 7 m

• Mass of beam = 50 kg

• Mass of person = 60 kg

• Distance of the person from the left = 3.6 m

Let's find the tensions, T1 and T2.

First make a free body sketch:

Here, the net torque = 0.

To find the tension, T1, we have:

Where:

l = 7 m

mp = 60 kg

g is acceleration due to gravity = 9.8 m/s²

l1 = 3.6 m

mb = 50 kg

Thus, we have:

Therefore, the tension T1 = 530.6 N.

To find the tension T2, we have:

Thererfore the tension T2 = 547.5 N

• ANSWER:

T1 = 530.6 N

T2 = 547.4 N

The energy eigenfunction oscillates at the same frequency as the oscillator's motion and describes the probability density of locating the oscillator at a specific location x.

The energy eigenfunction for a simple harmonic oscillator with energy eigenvalue \(3hw/2 and a = mw2h\) is given by:

\(ψ(x) = NHe(n)(sqrt(mw/h)) * exp(-1/2(mw/h)x^2)\)

where N is a normalization constant, He(n) is the nth Hermite polynomial, and x is the position of the oscillator. The energy eigenvalue of a simple harmonic oscillator is proportional to its frequency and the amplitude of its motion. In this case, the energy eigenvalue is \(3hw/2\), where h is Planck's constant, w is the angular frequency of the oscillator, and m is its mass.

The parameter\(a = mw2h\) is related to the spring constant of the oscillator. The energy eigenfunction describes the probability density of finding the oscillator at a particular position x, and it oscillates with the same frequency as the oscillator's motion.

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The time taken for the train to reach a speed of 74 km/h from rest is approximately 5.81 minutes.

The force exerted by the locomotive engine is 7.7 × 10⁵N. To determine the time taken for the train to reach a speed of 74 km/h from rest, we can use the equation:

Force = mass × acceleration

Rearranging the equation, we have:

Acceleration = Force / mass

Given that the mass of the train is 1.3 × 10⁷ kg, we can substitute these values into the equation to find the acceleration.

Acceleration = 7.7 × 10⁵ N / 1.3 × 10⁷kg

Now, we can use another equation to find the time taken for the train to reach the desired speed:

Final speed = Initial speed + acceleration × time

The initial speed is 0 since the train is starting from rest, and the final speed is 74 km/h. We need to convert the final speed to m/s by dividing it by 3.6.

74 km/h ÷ 3.6 = 20.6 m/s

Now, we can substitute the values into the equation:

20.6 m/s = 0 + (7.7 × 10⁵ N / 1.3 × 10⁷ kg) × time

Simplifying the equation, we get:

20.6 m/s = (7.7 × 10⁵ N / 1.3 × 10⁷ kg) × time

To solve for time, we can rearrange the equation:

time = (20.6 m/s) / (7.7 × 10⁵ N / 1.3 × 10⁷ kg)

Calculating the values, we find:

time = (20.6 m/s) / (5.92 × 10⁻² m/s²)

time = 348.31 seconds

To convert seconds to minutes, we divide by 60:

time = 348.31 seconds ÷ 60

time = 5.81 minutes

Therefore, it takes approximately 5.81 minutes for the train to reach a speed of 74 km/h from rest.

In conclusion, the time taken for the train to reach a speed of 74 km/h from rest is approximately 5.81 minutes.

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