In relation to the reactants of a chemical reaction, the products are

Answer:

Temperate Deciduous Forest

Explanation:

Explanation:

(a) The mass of an object remains the same always. It is independent of its location. In this case, an iron nail is ground into powder. It means that its mass will remain unchanged. Hence, (a) is the correct option.

(b) Whenever there is a change of color of an object, a chemical reaction occurs. It shows that a reaction happens there. In this problem, a paper turns yellow-brown upon exposure to sunlight. A chemical reaction takes place there. Hence, (b) is the correct option.

1) The mass of any substance remains the same irrespective of the state.

Thus, an iron nail ground into powder should have the same mass unless parts of it got lost during grinding.

2) A paper that turns yellow-brown upon exposure to sunlight is likely undergoing a chemical change. It could be that the light oxidizes the atoms of the paper.

Chemical changes occur when the atoms of a substance combine with another substance to form new products. New products are not formed in physical changes and the original product can be retrieved by physical means.

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Answer:

The middle Hydrogen atom is bonded to two instead of one atom

Oxygen is bonded to one instead of two atoms

Oxygen has three instead of two lone pairs of electron.

Explanation:

If we look at the structure, we will notice that it does not satisfy the basic principles of valency.

Hydrogen has a valency of 1. However, the middle hydrogen atom is bonded to two atoms instead of only one atom - the other atom of hydrogen and an atom of oxygen.

Secondly, oxygen has three lone pairs instead of two lone pairs, hence it is bonded to only one instead of two atoms. This does not correspond to the known valency of oxygen.

The structure does not obey the valence rule. From the structure, it is impossible for the hydrogen atom to bond to more than one atom.

The valence rule posits that an atomic element has the ability to gain or lose the maximum number of electrons in its outermost shell.

From the information, the hydrogen is bonded to a hydrogen atom and singly bonded to another oxygen atom.

This does not conform to the rule of valence electrons and therefore affects the stability of the hydrogen atom because the hydrogen has the ability to bond to only one atom and not two different atoms.

Therefore, we can conclude that the structure does not obey the valence rule and hydrogen can only bond to one atom at a time.

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Answer:

120 moles of Mg

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

3Mg + 2H₃PO₄ —> Mg₃(PO₄)₂ + 3H₂

From the balanced equation above,

3 moles of Mg reacted to produce 3 moles of H₂.

Finally, we shall determine the number of mole of Mg needed to produce 120 moles of H₂. This can be obtained as follow:

From the balanced equation above,

3 moles of Mg reacted to produce 3 moles of H₂.

Therefore, 120 moles of Mg will also react to produce 120 moles of H₂.

Thus, 120 moles of Mg is needed for the reaction.

Agarose gel electrophoresis differs from SDS-PAGE in all of the following ways except  loading buffer which generally gives the sample a uniform negative charge. As a result, choice A is the best one.

By determining their size and charge, small molecules (DNA, RNA, protein, etc.) or their fragments can be separated and analysed using the gel electrophoresis technique. Biochemistry as well as molecular biology use it to distinguish between a mixture of fragments of DNA and RNA by length, to determine the size of DNA as well as RNA fragments, or to separate amino acids by charge. Clinical chemistry uses it to separate amino acids by charge and size (IEF agarose, basically size independent). Its loading buffer typically imparts a homogeneous negative charge to the sample.

Therefore, the correct option is option A.

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Answer:

2.05g

Explanation:

The weight of butane gas present in the system with the specified temperature and pressure is 2.05 g. We can use ideal gas law here.

Ideal gas law states the relation between temperature, pressure and volume  and mathematically written as below:

PV = nRT

Here, P and V be the pressure and volume and n be the no.of moles and R be the universal  gas constant. T is the absolute temperature in kelvin.

The system have a volume of 3000 mL or 3 L and pressure of 760 torr and temperature of 1000 K. The no. of moles n is the ratio of taken weight to the molar mass. R has the value 62.36 L torr/(K mol)

Apply these values into ideal gas law as given below:

(3 L × 760 torr)  = (w/56.1 g/mol) × 62.36 L torr/(K mol) × 1000 K. From this,

\(2280 \textup{ torr L} = \frac{w}{56.1 g/mol} \times 62360 \textup{ L torr/mol}\)

\(w = \frac{2280\textup{ torr L}\times 56.1\textup{ g/mol}}{62360 \textup{ L torr/mol}} =2.05 g\)

Therefore, the amount of butane gas for the given system is 2.05 g.

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The final temperature of the gas, after absorbing 1300 J of heat and doing 2200 J of work, is approximately 375.45 K.

To find the final temperature (T_final) of the gas, we can use the first law of thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat added (Q) minus the work done (W) by the system:

ΔU = Q - W

Since the gas is ideal and monatomic, the change in internal energy is related to the temperature change (ΔT) through the equation:

ΔU = nC_vΔT

where n is the number of moles and C_v is the molar heat capacity at constant volume.

Rearranging the equations and substituting the given values:

nC_vΔT = Q - W

(5.00 mol)(3/2R)ΔT = 1300 J - 2200 J

(5.00 mol)(3/2)(8.3145 J/(mol⋅K))ΔT = -900 J

Simplifying:

(37.9725 J/K)ΔT = -900 J

ΔT = -900 J / (37.9725 J/K)

ΔT ≈ -23.70 K

Since the initial temperature is 126 °C, we convert it to Kelvin:

T_initial = 126 °C + 273.15 = 399.15 K

Now we can find the final temperature:

T_final = T_initial + ΔT

T_final = 399.15 K - 23.70 K

T_final ≈ 375.45 K

Therefore, the final temperature of the gas is approximately 375.45 K.

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The number of moles of N2 produced in the reaction is 3.69 moles. To calculate the number of moles of N2 produced in a reaction, we need to use the ideal gas law equation, PV = nRT.

In this equation, P represents pressure, V represents volume, n represents the number of moles, R represents the gas constant, and T represents temperature.
First, we need to convert the temperature to Kelvin by adding 273.15 to 21.5, which gives us 294.65 K.
Next, we need to convert the volume to litres by dividing 110.0 mL by 1000, which gives us 0.110 L.
Now we can plug in the values we have into the ideal gas law equation:
(2.75 atm)(0.110 L) = n(0.0821 L atm/K mol)(294.65 K)
Simplifying this equation, we get:
0.3025 = 0.0821n
To solve for n, we divide both sides by 0.0821:
n = 3.69 moles of N2

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For the rusting of an iron bar, a chemical change occurs; while for the freezing of a substance , a physical change occurs.

When an iron bar rusts, a chemical change occurs. Rusting is a chemical reaction that involves the oxidation of iron in the presence of oxygen and water. The iron undergoes a chemical transformation and forms a new compound, iron oxide, which gives the rusty appearance. This change is irreversible and involves a rearrangement of atoms at the molecular level.

On the other hand, when a substance freezes, a physical change takes place. Freezing is a phase transition from a liquid to a solid state. During freezing, the substance undergoes a change in its physical state without any alteration in its chemical composition. The arrangement of molecules or atoms becomes more ordered as they transition from a disordered liquid state to a more structured solid state. This change is reversible, and the substance can return to its liquid state by melting.

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Answer:

It is difficult to prove the law of conservation of mass when a gas is produced because the gas molecules move quickly into the outside space and away

Answer:

0.600 is yourr answer and if wrong sorry  

Explanation:

0.600 mol of potassium contain \(3.6 * 10^{23}\) atoms of potassium.

C. 0.600 mol

A mole is the amount (10) of material containing  \(6.022*10^{23}\) particles . This number is also called Avogadro's number.

Given:

Atoms of potassium = \(3.3*10^{23} atoms\)

To find:

Moles of potassium =?

As we know,

\(1 mole = 6.022*10^{23} atoms\\\\1 atom = 1 / 6.022*10^{23} mole\\\\3.3*10^{23} atoms = 1 / 6.022*10^{23} mole * 3.3*10^{23} atoms\\\\3.3*10^{23} atoms=0.600 mol\\\\\)

Thus, 0.600 mol of potassium contain  \(3.6 * 10^{23}\) atoms of potassium.

Therefore, option C is correct.

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Answer:

B. Food can be produced in larger amounts for more people to eat.

Explanation:

Commercial farming mechanizes operations controls diseases and pests, enabling farms to produce more

Answer:

food can be produced in larger amounts for more people to eat.

Explanation:

you're welcome

Answer:

1039.482

Explanation:

\(~~~~~\text{pH} + \text{pOH} = 14\\\\\implies \text{pOH} = 14- \text{pH}\\\\\implies \text{pOH} = 14 - 11.8\\\\\implies \text{pOH} = 2.2\\\\\text{Now,}\\\\~~~~~~~\text{pOH}= -\log\left[\text{OH}^{-1}\right]\\\\\implies \left[\text{OH}^{-1} \right] = 10^{-\text{pOH}} = 10^{-2.2}~ = 0.006309~M\\\\\text{Hence the concentration of OG}^{-1}~ \text{is 0.006309~M}\)

Answer:

im solving now

Explanation:

Answer:

B A B  sorry if its wrong

Explanation:

Circuits can be connected in series or parallel but the maximum voltage is obtained in series connection, thus, light bulbs shine brightest in series connection.

A parallel circuit connection is one in which the terminals of all the components in th circuit meet at two points.

The components are parallel to each other and current flows in multiple directions.

A series connection in a circuit is one in which the terminals of the component parts in a circuit are joined end to end. Current flows in one direction.

The voltage in a series connection is the sum of all the individual cells, therefore, the light bulb in series connection shines brightest.

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Answer:

7

Explanation:

To make 2 moles of C6H12O6, we would need 12 moles CO2

Mole can be defined as the unit of amount of substance in the International System of Units. The quantity amount of substance is a measure of how many elementary entities of a given substance are in an object.

According to the balanced chemical equation:

6CO2 + 6H2O → C6H12O6 + 6O2

The molar ratio between CO2 and C6H12O6 is 6:1. This means that for every 6 moles of CO2 used, 1 mole of C6H12O6 is produced.

Therefore, to make 2 moles of C6H12O6, we would need:

6 moles CO2/1 mole C6H12O6 × 2 moles C6H12O6 = 12 moles CO2

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Answer:

here is my answerrrrrrr

Answer:

NO2

Explanation:

N = Nitrogen

O = Oxygen

Answer:

NO. 2.

is the answer

hopes this helps

Answer & Explanation:

For the water to H2 and O2 problem:

1) Reactant is H20, it is to the left of the arrow.

2) Products are H2 (gas) and O2 (gas) because it is to the right and what is created.

For the CO2 + water -> Glucose + Oxygen problem:

1) Reactant is CO2 and H2O, it is to the left of the arrow and what is being changed.

2) Products are C6H12O6 (glucose) and O2 (gas) because it is to the right and what is created.

Answer:

Virus is living due to reproduction and non-living due to crystal appearance.

Explanation:

Characteristics that viruses display is the ability of reproduction in which they increase in population which is a living character and have DNA or RNA which help them to make exact copies of itself. Virus is parasitic in nature because it causes harm to the living host such as humans, animals and plants. Some characteristics that viruses don't display are that they are not like living cells, have no membrane around them, no organelles such as mitochondria, golgi bodies, endoplasmic reticulum and lysosomes etc. Viruses are present in crystal form outside the cell.

The density of the coin, given the data from the question is 21.33 g/mL.

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

From the question given above, the following data were obtained:

Density = mass / volume

Density = 48000 / 2250

Density = 21.33 g/mL

The density of the coin obtained, given the data from the question is 21.33 g/mL

Considering the options given, the density of the metal is not specified.

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Explanation:

At 4th point the slump block is located

hope this helps you

have a great day :)

It is point 2, for anyone who sees this is the future

The citric acid cycle, where acetyl CoA is modified inside the mitochondria to produce energy precursors in preparation for the next step.

Generating ATP, the citric acid cycle, where acetyl CoA is modified inside the mitochondria to produce energy precursors in preparation for the next step. Oxidative phosphorylation, the process where the electron transport from the energy precursors from the citric acid cycle (step 3) results in to the phosphorylation of ADP, generating ATP. A biogeochemical cycle refers to the processes through which an element—or combination like water—moves between its different living or nonliving forms and places in the biosphere. The biogeochemical cycles of water, carbon dioxide, nitrogen, phosphorus, plus sulphur are crucial to living things.

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In solution 4 of part b, both the hydronium concentration and hydroxide concentration are 1 M due to the neutralization reaction between HCl and NaOH. The initial concentrations of H₃O⁺ and OH⁻ were 0.1 M, but they reacted to form water and resulted in equal final concentrations of 1 M for both ions.

To calculate the hydronium and hydroxide concentrations for solution 4 in part b, we need to first understand the equation for the reaction that occurred.

The equation given is: HCl + NaOH -> NaCl + H₂O

This tells us that one mole of HCl reacts with one mole of NaOH to produce one mole of NaCl and one mole of water.

Based on this equation, we know that the initial concentration of hydroxide ions (OH-) in solution 4 is equal to the initial concentration of sodium hydroxide (NaOH), which was given as 0.1 M.

Next, we need to determine the concentration of hydronium ions (H₃O⁺). Since HCl is a strong acid, it completely dissociates in water to produce H₃O⁺ and Cl⁻ ions. Therefore, we can assume that the initial concentration of H₃O⁺ is equal to the initial concentration of HCl, which was also given as 0.1 M.

Now, let's consider what happens when the HCl and NaOH are mixed together. They react to form NaCl and water, which means that the concentrations of H₃O⁺ and OH⁻ will change.

From the equation, we can see that the reaction consumes one mole of HCl and one mole of NaOH. This means that the final concentration of HCl and NaOH will both be zero.

To determine the final concentration of OH-, we need to use the fact that the reaction produces one mole of water for every mole of NaOH that reacts. Therefore, the final concentration of OH⁻ will be equal to the initial concentration of NaOH (0.1 M) divided by the volume of the solution.

If we assume that the volume of the solution is 100 mL (as stated in the question), then the final concentration of OH- will be:

[OH⁻] = 0.1 M / 0.1 L = 1 M

Finally, we can use the fact that the concentration of H₃O⁺ and OH⁻ must be equal in a neutral solution to determine the final concentration of H₃O⁺.

Since the final concentration of OH⁻ is 1 M, we know that the final concentration of H₃O⁺ must also be 1 M.

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For an FCC crystal: calculate the density of atoms (atoms/a² where a is the lattice constant) for the (100), (110) and (111) planesThe unit cell of a FCC crystal is shown below:Here, each corner atom contributes 1 atom, and each face atom contributes 1/2 atoms.

For (100) plane:Length of unit cell along (100) plane direction = a Density of atoms = No. of atoms / Area of the plane Area of the plane = a²Density of atoms for (100) plane = 4 / a²For (110) plane:Length of unit cell along (110) plane direction = a√2Density of atoms = No. of atoms / Area of the plane Area of the plane = a x a√2Density of atoms for (110) plane = 2 x 2 / (a x a√2) = 4√2 / a²

For (111) plane:Length of unit cell along (111) plane direction = a√3Density of atoms = No. of atoms / Area of the plane Area of the plane = a²√3/2 Density of atoms for (111) plane = 3 x 4 / (a²√3) = 4√3 / a²Hence, the density of atoms for the (100), (110) and (111) planes in an FCC crystal are as follows:For (100) plane: 4 / a²For (110) plane: 4√2 / a²For (111) plane: 4√3 / a².

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