PLEASE HELP!!!!!!!!
Given 2 and one-eighth times negative 7 times five tenths, determine the product.

negative fourteen and five eightieths
negative 7 and seven sixteenths
fourteen and five fortieths
7 and one eighth

Step-by-step explanation:

1.) Combine multiplied terms into a single fraction

−1/2

Answer:

1, 2 and 3  (I, II and III)

Step-by-step explanation:

Since the slope is positive (3) in the equation y = 3x + 1, it means that the graph has a positive slope, meaning the line slopes up from left to right.

The y intercept is 1

the x intercept is:  

0 = 3x + 1

x = 1/3

Therefore, the graph of y = 3x + 1 lies in quadrants I, II and III.  Graph the equation to prove this.  

Answer:

-0.19

a correlation coefficient is a measure of how...

By fractions, 9/20 quarts of lemonade concentrate is needed to make lemonade for 24 people.

What are the names of fractions  numerical expression in mathematics known as a quotient, where a numerator and a denominator are split in half. Both are integers in a simple fraction. Whether it is in the numerator or denominator, a complex fraction contains a fraction. The numerator of a proper fraction is less than the denominator.

Let x= the number of quarts of lemonade concentrate needed for 24 people. In this question " 20/3 quarts of water" was unnecessary information.

40x=24*(3/4)​

Cross products

x=24⋅ (3/4) ⋅ (1/40)= 9/20

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Answer:

0.5

Step-by-step explanation:

ggggggggsgsgsgsgsgsgsgsgsgsgsgsgs

Answer:

0.5

Step-by-step explanation:

\(\sqrt{0.25}=\sqrt{\dfrac{25}{100}}\\\\\\=\sqrt{\dfrac{5*5}{10*10}}\\\\\\=\dfrac{5}{10}\\\\\\=0.5\)

Answer: 29-12_< c

Step-by-step explanation:

Answer:

Step-by-step explanation:

so the problem is 7 cookies in 1 minutes which is 7 x1 but if we want to know how many we have in 2 minutes we would have to multiply by 2 not 1. so we do 7x2 which is 14. 14 cookies in 2 minutes

To find the average value of x^2 in the one-dimensional infinite potential energy well, we need to use the wave function for the particle in the well, which is given by:

ψn(x) = sqrt(2/L) * sin(nπx/L)

where n is a positive integer and L is the width of the well.

The probability density of finding the particle at a position x is given by:

|ψn(x)|^2 = (2/L) * sin^2(nπx/L)

Using this probability density, we can find the average value of x^2 by integrating x^2 multiplied by the probability density over the entire well:

= ∫(x^2)(2/L) * sin^2(nπx/L) dx from 0 to L

Using the trigonometric identity sin^2θ = (1/2) - (1/2)cos(2θ), we can simplify the integral as follows:

= (1/L) * ∫(x^2) dx from 0 to L - (1/L) * ∫(x^2)cos(2nπx/L) dx from 0 to L

The first integral is simply the average value of x^2 over the entire well, which is L^2/3. The second integral can be evaluated using integration by parts, resulting in:

(1/L) * ∫(x^2)cos(2nπx/L) dx = (L^2/2nπ)^2 * [sin(2nπx/L) - (2nπx/L)cos(2nπx/L)] from 0 to L

Plugging this into our original equation, we get:

= L^2/3 - (L^2/2nπ)^2 * [sin(2nπ) - 2nπcos(2nπ)] + (L^2/2nπ)^2 * [sin(0) - 0]

Since sin(0) = 0 and sin(2nπ) = 0, the equation simplifies to:

= L^2/3 - (L^2/2nπ)^2 * (-2nπ) = L^2/3 + (L^2/2) * n^2π^2

Finally, we can substitute L^2/4π^2 for 1/2 in the expression above to get:

= L^2/3 + L^2/4 * n^2π^2 - L^2/4π^2 * n^2π^2

Simplifying further, we get:

= L^2/3 - L^2/4π^2 * n^2π^2

which is the desired result.
To show that the average value of x^2 in a one-dimensional infinite potential energy well is L^2(1/3 - 1/2n^2 π^2), we need to follow these steps:

Step 1: Define the wave function.
For an infinite potential energy well of width L, the wave function Ψ_n(x) is given by:
Ψ_n(x) = √(2/L) sin(nπx/L)

Step 2: Compute the probability density function.
The probability density function, ρ(x), is given by the square of the wave function, |Ψ_n(x)|^2:
ρ(x) = (2/L) sin^2(nπx/L)

Step 3: Calculate the expectation value of x^2.
The expectation value (average value) of x^2, denoted as , is given by the integral of the product of x^2 and the probability density function over the width of the well (0 to L):
= ∫[x^2 ρ(x)] dx from 0 to L

Step 4: Perform the integral.
= ∫[x^2 (2/L) sin^2(nπx/L)] dx from 0 to L

After solving this integral, you will find that:

= L^2(1/3 - 1/2n^2 π^2)

This confirms that the average value of x^2 in the one-dimensional infinite potential energy well is indeed L^2(1/3 - 1/2n^2 π^2).

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Answer:

22.31 minutes

Step-by-step explanation:

First simplify the numbers to decimals to make it easy : 2 1/3 = 2.30( estimated) ,  11 2/3 = 11.67 ( estimated ), and 4 2/5 = 4.4

The we divide how many miles by the total amount of minutes to get 5.07( estimated )

We then multiply it by 4.4 to get 22.308 to be exact.

So it will take him 22.31 minutes

P.S : Correct me if I am wrong. Apologizes.

If the length of a rectangle is 19 feet longer than the width. If the perimeter is 46 feet, The equation for this scenario where "x" represents the width is 2x + 2 (x +19 ) = 46  and the width is 2 feet.

Given data :

Length of a rectangle = 19 feet

Perimeter = 46 feet

Perimeter formula: 2l+2w=P

Let x represent the width

Hence,

2x + 2 (x +19 ) = 46

2x + 2 x +38 = 46

Collect like terms

4x  = 46 -38

4x = 8

Divide both side by 4x

x = 8/4

x = 2 feet

Therefore the equation that was used to find the width  is  2x + 2 (x +19 ) = 46  while the width is 2 feet.

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Answer:D)AP is not congruent to PB

whats the question....?

Part A. When we have two chords that intercept at one of the exterme points of a circle, like this:

Then the relationship between the minor arc and the interior angle of the chords is:

therefore, if we substitute according to the given circle we have:

Therefore, angle a is 85°.

Part B. The angle formed by a tangent and a chord of a circle is half the the arc that is formed:

We have that:

Now, we substitute:

Therefore, "b" is 105°.

Part C. Given the following configuration:

The following relationship holds:

Now, we substitute the values according to the given circle:

Now, we divide both sides by "c":

Therefore, the value of "c" is 13.5

Part D. In the following configuration:

The following relationship holds:

Now, we substitute the values:

Solving the operations:

therefore, the angle "d" is 80 degrees.

The rate of change of h(x) with respect to x when x=2 is -3. To find d/dx, we need to take the derivative of the function h(x) and evaluate it at x=2.

h(2) tells us that when x=2, h(x)=4.

h'(2) tells us that the slope of the tangent line to the graph of h(x) at x=2 is -3.

So, we can use this information to find d/dx as follows:

h(x) = y

dy/dx = h'(x)

We know that when x=2, y=h(2)=4.

We also know that the slope of the tangent line to the graph of h(x) at x=2 is h'(2)=-3.

So, we can write the equation of the tangent line at x=2 as:

y - 4 = (-3)(x - 2)

y = -3x + 10

Now we can take the derivative of y with respect to x to find d/dx:

d/dx (y) = d/dx (-3x + 10)

d/dx (y) = -3

Therefore, d/dx = -3.

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Different RAID levels offer varying levels of performance, effective storage use, disk failure tolerance, and minimum drive requirements.

RAID (Redundant Array of Independent Disks) is a technology that combines multiple physical drives into a single logical unit to improve performance, data redundancy, and fault tolerance. Here's a breakdown of the different RAID levels in terms of performance, effective storage use, disk failure tolerance, and minimum drive requirements:

In summary, different RAID levels offer a trade-off between performance, effective storage use, fault tolerance, and minimum drive requirements. It is important to carefully consider the specific needs of your system to choose the appropriate RAID level.

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From the given results, we found that the relative frequency of rolling a 3 is 9/40.

What is the relative frequency?

The relative frequency is calculated as the ratio of the number of occurrences of a given value of the data in the set of all outcomes to the total number of outcomes. Frequency is a measure of how frequently an event happens. While not a theoretical concept, relative frequency is one that is currently being tested. The fact that it is experimental means that if we repeat the trials, we might get different relative frequencies. In order to compare the frequency of a specific event to all other occurrences, relative frequency is used.

The complete question is given below.

Number of times Danielle rolled a number cube = 40

We are asked to find the relative frequency of rolling a 3.

Relative frequency = frequency/ Total frequency

From the table,

Frequency of 3 = 9

Total frequency = 5 + 5+ 9 + 6 + 7 + 8 = 40

Then the relative frequency of 3 = 9/40

Therefore from the given results, we found that the relative frequency of rolling a 3 is 9/40.

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Answer:

m=7

Step-by-step explanation:

15m−13m=69.96−55.96

Step 1: Simplify both sides of the equation.

15m−13m=69.96−55.96

15m+−13m=69.96+−55.96

(15m+−13m)=(69.96+−55.96)(Combine Like Terms)

2m=14

2m=14

Step 2: Divide both sides by 2.

2m

2

=

14

2

(a) The statement f(13)=550 means that on day 13, the rate at which pollution is being removed from the lake is 550 kg/day.

(b) The units of the 5 are "days."

The units of the 16 are also "days."

The units of the 3400 are "kg" (kilograms).

(c) The statement \(\int_5^16 f(t)dt=3400\) means that during the time period from day 5 to day 16, the total amount of pollution removed from the lake is 3400 kg.

An integral is a mathematical concept that represents the area under a curve or the accumulation of a quantity over a given interval. It is a fundamental concept in calculus and is used to compute various quantities such as areas, volumes, and total amounts

(a) The statement f(13)=550 indicates that at a specific point in time, which is day 13 in this case, the rate at which pollution is being removed from the lake is 550 kg/day. This means that on day 13, the system or process in place is actively reducing the pollution in the lake at a rate of 550 kilograms per day.

(b) In the expression \(∫_5^16 f(t)dt=3400\), the integral symbol (∫) represents the mathematical operation of finding the area under the curve of the function f(t) over the interval from 5 to 16. The value of 3400 represents the numerical result of that integral, indicating the total amount or quantity associated with the given function and interval.

The units of the 5 and 16 are "days" because they represent the limits of the time interval over which the integration is performed. The integration is carried out with respect to the variable t, which represents time.

The units of the 3400 are "kg" (kilograms) because it represents the total amount of pollution removed from the lake over the specified time interval.

(c) The statement \(\int_5^16 f(t)dt=3400\)provides the meaning that during the time period from day 5 to day 16, a total of 3400 kilograms of pollution were removed from the lake. The integral represents the accumulation or sum of the rate of pollution removal (f(t)) over the specified time interval. The result of 3400 indicates the total amount of pollution removed from the lake during that time period.

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The solution for the system is (0,3) as line a meets the y-axis at (0, -3) and the Intersection point of a and b is (3,0). This makes it obvious that the solution for x will be 0 when the solution for y is 3

Given that the number graph ranges from negative eight to eight on the x-axis and negative eight to eight on the y-axis.

Two lines that are perpendicular to each other intersect at (three, zero). The line with a positive slope is labeled a, and the line with a negative slope is labeled b.

The system is given byx – y = 3 (line a)x + y = 3 (line b)We know that both the lines a and b pass through (3,0).

Let's first find the points of intersection of the line a with the x-axis and the y-axis.

To find the point of intersection of the line a with the x-axis, put y = 0 in the equation x - y = 3x - 0 = 3x = 3So, the point of intersection of line a with the x-axis is (3,0).

To find the point of intersection of the line a with the y-axis, put x = 0 in the equation x - y = 3 0 - y = 3y = -3So, the point of intersection of line a with the y-axis is (0,-3).

Similarly, let's find the points of intersection of the line b with the x-axis and the y-axis.

To find the point of intersection of the line b with the x-axis, put y = 0 in the equation x + y = 3x + 0 = 3x = -3So, the point of intersection of line b with the x-axis is (-3,0).

To find the point of intersection of the line b with the y-axis, put x = 0 in the equation x + y = 3 0 + y = 3y = 3So, the point of intersection of line b with the y-axis is (0,3).

Now, we can plot the graph of the two lines a and b and then find the points of intersection as follows:

Therefore, the solution for the system is (0,3) as line a meets the y-axis at (0, -3) and the intersection point of a and b is (3,0). This makes it obvious that the solution for x will be 0 when the solution for y is 3.

Hence, the answer is (0, 3).Option B. (0, 3)

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Answer:

pepperoni pizzas = 8

cheese pizzas = 4

Step-by-step explanation:

let x = cheese pizza

2x + x + 1 = 13

3x = 13 -1

3x = 12

x = 4

pepperoni = 2x4 = 8

Answer:

57 dollar

Step-by-step explanation:

The total surface area of cylinder is 112π units².

The surface area of cylinder is -

A = 2πr(h + r)

Given is a cylinder as shown in the image attached.

We can write the total surface area of cylinder as -

A = 2πr(h + r)

A = 2π x 4 x (10 + 4)

A = 8π x 14

A = 112π

Therefore, the total surface area of cylinder is 112π units².

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If the sand falls at a rate of 16 cubic millimeters per second, a player would have approximately 6.25 seconds for their turn.

The rate of sand falling from the hourglass is given as 16 cubic millimeters per second. We need to find out the time available for a turn. Let's assume that the hourglass is filled with 'x' cubic millimeters of sand.

We can use the formula:

Volume = Rate x Time

Here, the volume of sand is 'x' cubic millimeters, the rate is 16 cubic millimeters per second, and we need to find the time available for a turn, which we can represent as 't' seconds.

So,

x = 16t

We can rearrange this equation to find 't':

t = x/16

This means that the time available for a turn is equal to the volume of sand in the hourglass divided by the rate at which the sand falls.

We don't know the exact volume of sand in the hourglass, but let's assume it's 100 cubic millimeters.

Then,

t = 100/16

t = 6.25 seconds

So, in this case, a player would have approximately 6.25 seconds for their turn before all of the sand falls to the bottom of the hourglass.

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Both the mean and the median would increase.

What is Mean?

The mean of a set is defined as the sum of the all the numbers divided by the total number of sets.

Given that;

The model data set is,

$42, $38, $26, $32, $40, $34, $28, $32

Now,

We arrange the set into ascending order as;

$26, $28, $32, $32, $34, $38, $40, $42

Mean of data set is;

Mean = $26 + $28 + $32 + $32 + $34 + $38 + $40 + $42 / 8

         = $272 / 8

         = $34

And, Median of data set is;

Since, There are 8 (even) numbers, so there are two median.

So, Median = 8/2 = 4th number

                          = $32

And, Median = 8/2 + 1 = 5th number

                                  = $34

Thus, There are two medians $32 and $34.

Now, When we delete the least amount, we get;

The model data set;

$28, $32, $32, $34, $38, $40, $42

Thus, Mean = $28+$32+$32+$34+$38+ $40+$42 / 7

                  = $246 / 7

                  = $35.14

And, Median = (n+1)/2

                    = (7+1)/2

                    = 4th number

                    = $34

Thus, Both the mean and the median would increase.

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The following equations are organized for P as a function of Q

1) P = 20-8Q

2) p = \(\dfrac{12-Q}{3}\)

3) p = 9 - 4Q

A function in mathematics is, technically speaking, a relation between a set of inputs and a set of potential outputs, where each input is related to exactly one output. Examples of functions in mathematics typically range from integers to integers or from real numbers to real numbers.

Additionally, it is a relation or a process that links each element x of a set X to the codomain of the function and to a single element y of a different set Y (typically the same set).

1) Q = 20-P

Q + P = 20

P = 20-Q

2) Q=12-3P

Q +3P = 12

3P = 12-Q

p = \(\dfrac{12-Q}{3}\)

P = 4 - 1/3Q

3) 8Q = 18 -2p

8Q + 2p = 18

2p = 18 - 8Q

p =  \(\dfrac{18-8Q}{2}\)

p = 9 - 4Q

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Complete question:

Gaussian Random variable with a PDF of form: fx​(x)=2πσ2​1​exp(2σ2−(x−μ)2​    Pr(x < 0) = 1 - Q(11/7)  and Pr(x > 15) = Q(4.5)

To find the probability Pr(x < 0) for a Gaussian random variable with parameters N = 11 and σ = 7, we need to integrate the given PDF from negative infinity to 0:

Pr(x < 0) = ∫[-∞, 0] fx(x) dx

However, the given PDF seems to be incorrect. The Gaussian PDF should have the form:

fx(x) = (1/√(2πσ^2)) * exp(-(x-μ)^2 / (2σ^2))

Assuming the correct form of the PDF, we can proceed with the calculations.

a) Find Pr(x < 0) if N = 11 and σ = 7:

Pr(x < 0) = ∫[-∞, 0] (1/√(2πσ^2)) * exp(-(x-μ)^2 / (2σ^2)) dx

Since the given PDF is not in the correct form, we cannot directly calculate the integral. However, we can use the Q-function, which is the complementary cumulative distribution function of the standard normal distribution, to express the probability in terms of the Q-function.

The Q-function is defined as:

Q(x) = 1 - Φ(x)

where Φ(x) is the cumulative distribution function (CDF) of the standard normal distribution.

By standardizing the variable x, we can express Pr(x < 0) in terms of the Q-function:

Pr(x < 0) = Pr((x-μ)/σ < (0-μ)/σ)

          = Pr(z < -μ/σ)

          = Φ(-μ/σ)

          = 1 - Q(μ/σ)

Substituting the given values μ = 11 and σ = 7, we can calculate the probability as:

Pr(x < 0) = 1 - Q(11/7)

b) Find Pr(x > 15) if μ = -3 and σ = 4:

Following the same approach as above, we standardize the variable x and express Pr(x > 15) in terms of the Q-function:

Pr(x > 15) = Pr((x-μ)/σ > (15-μ)/σ)

          = Pr(z > (15-(-3))/4)

          = Pr(z > 18/4)

          = Pr(z > 4.5)

          = Q(4.5)

Hence, Pr(x > 15) = Q(4.5)

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Answer:

x = -9

Step-by-step explanation:

x - 7 = 4(x + 5)

x - 7 = 4x + 20

-27 = 3x

x = -9

Answer:

x = -9

Step-by-step explanation:

x-7=4(x+5)

Distribute

x-7 = 4x+20

Subtract x from each side

x-7-x =4x-x+20

-7 = 3x+20

Subtract 20 from each side

-7-20 = 3x+20-20

-27 = 3x

Divide by 3

-27/3 = 3x/3

-9 =x

Answer:

Step-by-step explanation:

Let M(x,y) be the median of ΔABC through A to BC.M will be the midpoint of BC.x1​=5,y1​=3x2​=3,y2​=−1By midpoint formula, x=(x1​+x2​)/2∴x=(5+3)/2=8/2=4By midpoint formula, y=(y1​+y2​)/2∴y=(3+(−2))/2=2/2=1Hence the co-ordinates of M are (4,1).By diatnce formula, d(AM)=[(x2​−x1​)2+(y2​−y1​)2]​x1​=7,y1​=−3x2​=4,y2​=1