does this curved graph show a function explain how you know
Answers
Answer:
No; the graph fails the vertical line test.
The vertical line test is a tool used to determine if we have a function. If we can draw a single straight vertical line through more than one point on the red curve, then the graph is said to have failed the vertical line test. Consequently, this leads to the relation not being a function.
For this circle graph, we can draw a vertical line through more than one point, which is why we don't have a function here.
Put another way, there are inputs (x) that produce more than one output (y), so that's why we don't have a function.
-BBBM
Related Questions
Trial # Mass 1
(x 10^9 Kg) Mass 2
(x 10^9 Kg) Distance
( x 10^3m) Force
(N) Gravitation Constant, G
(Nm2/kg2)
1 2 4 4.4 27.4
2
3
4
5
6
Average value of G ________________
Published Value of G: 6.67 x 10 -11 Nm2/kg2
How do the values compare?
Answers
The gravitational constant (G) is a physical constant that is used to quantify the strength of the gravitational force between two objects. The value of G is approximately 6.6743 × 10−11 N m2 kg−2.
The average value of G can be calculated by adding up all the values in the table and dividing by the number of trials. The average value of G in this case would be 27.4 Nm2/kg22.
The published value of G is 6.67 × 10−11 Nm2/kg2.
Comparing the average value of G obtained from the experiment with the published value of G, we can see that there is a significant difference between the two values. The average value of G obtained from the experiment is much larger than the published value of G. This could be due to experimental error or other factors that were not taken into account during the experiment.
I hope this helps! Let me know if you have any other questions.
avs 1235 what happens to the pressure and velocity of air as it passes through a venturi
Answers
As air passes through a venturi, the pressure decreases in the throat where the velocity is highest and increases again as the air moves away from the constriction.
As air passes through a venturi, both the pressure and velocity of the air undergo changes. The venturi effect, named after the Italian physicist Giovanni Venturi, describes the relationship between the velocity and pressure of a fluid as it flows through a constricted section of a pipe.
In a venturi, the cross-sectional area of the pipe decreases in the narrowest region, known as the throat, and then expands again to its original size. This change in cross-sectional area leads to changes in pressure and velocity.
Pressure: According to Bernoulli's principle, as the air flows through the narrower region of the venturi, the velocity of the air increases. According to the principle, an increase in fluid velocity leads to a decrease in pressure. Therefore, the pressure of the air decreases in the throat of the venturi where the velocity is the highest. As the air moves away from the throat and returns to a wider cross-sectional area, the velocity decreases, and the pressure increases again, returning to its original value.
Velocity: As the air passes through the narrower region of the venturi, the cross-sectional area decreases. According to the principle of conservation of mass, the mass flow rate remains constant for an incompressible fluid like air. Since the cross-sectional area decreases in the throat, the velocity of the air must increase to maintain the same mass flow rate. As the air moves away from the throat and enters the wider section of the venturi, the cross-sectional area increases, causing the velocity to decrease and return to its original value.
In summary, as air passes through a venturi, the pressure decreases in the throat where the velocity is highest and increases again as the air moves away from the constriction. Simultaneously, the velocity of the air increases in the narrower region and decreases as the air returns to a wider cross-sectional area. This phenomenon allows venturis to be used in various applications, such as flow measurement, fluid mixing, and atomization.
Learn more about velocity here
https://brainly.com/question/80295
#SPJ11
a ball is thrown vertically upward with a velocity of 20m/s from the top of a multistory building. the height of the point where the ball is thrown is 25 m from the ground. then find a. how height will the ball rise?
B how long will it be before the ball hip the ground?
Answers
A ball is thrown vertically upward with a velocity of 20m/s from the top of a multistory building. The height of the point where the ball is thrown is 25 m from the ground. The height will the ball rise is 20m. 5s long will it be before the ball hip the ground.
What is velocity ?The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.
A. for solving how high will ball go , velocity at the top point will be 0 this gives ,
s = v² - u² / 2a
= 0 - 20² / -2 × 10
= 20m
B. Time to reach maximum height can be obtained from v = u + at
0 = 20 + ( − 10 ) t
t = 2s
s = ut + 0.5at²
= 20 ( 2 ) + 0.5 ( −10 ) ( 2 )²
= 20m
Therefore, the total distance for maximum height is 45 m
s = ut + 0.5at²
45 = 0 + 0.5 ( 10 ) ( t )²
t = 3s
Then,
Total time = 3+2
= 5s
Thus, A ball is thrown vertically upward with a velocity of 20m/s from the top of a multistory building.The height will the ball rise is 20m. 5s long will it be before the ball hip the ground.
To learn more about velocity, follow the link;
https://brainly.com/question/18084516
#SPJ1
Pls help with all questions dew in 10 minutes!
Answers
When we look at Jupiter, we're actually seeing the outermost layer of its clouds.
The Great Red Spot is a storm in Jupiter's southern hemisphere with crimson-colored clouds that spin counterclockwise at wind speeds
8. 58,232 km
The second largest planet in the solar system
Surface. As a gas giant, Saturn doesn't have a true surface. The planet is mostly swirling gases and liquids deeper down.
Saturn's rings are thought to be pieces of comets, asteroids or shattered moons that broke up before they reached the planet,
9. Unlike the other planets of the solar system, Uranus is tilted so far that it essentially orbits the sun on its side, with the axis of its spin nearly pointing at the star.
Uranus' atmosphere is mostly hydrogen and helium, with a small amount of methane and traces of water and ammonia.
As an ice giant, Uranus doesn't have a true surface. The planet is mostly swirling fluids. While a spacecraft would have nowhere to land on Uranus, it wouldn't be able to fly through its atmosphere unscathed either. The extreme pressures and temperatures would destroy a metal spacecraft.
10. 24,622 km
Neptune has an average temperature of -353 Fahrenheit (-214 Celsius).
Neptune's atmosphere is made up mostly of hydrogen and helium with just a little bit of methane.
On the court in the picture below, the X's represent the defense (team that does not have the birdie) and the O's represent the offense (team that does
have the birdie). What type of shot should the offense make to try to score? Hint: Look at the position of the X players. What part of the court is open? O Drop Shot
O Serve
O Clear
Answers
The offense should aim for an Drop Shot to try to score.
What is a drop shot?A drop shot is a soft shot that lands just over the net and falls quickly, making it difficult for the defense to reach and return. In this situation, the drop shot can be effective because it would require the X players to quickly move forward from the backcourt, putting them out of position and giving the offense an opportunity to score.
Based on the position of the X players, it looks like the back of the court is more crowded compared to the front. Therefore, the offense should aim for an Drop Shot to try to score.
Thus, the part of the court that is open is drop shot.
Learn more about drop shot here: https://brainly.com/question/21398403
#SPJ1
what is the center of mass formula
Answers
The center of mass formula is COM = (Σmi * ri) / (Σmi) and it is used to calculate average position of an object's mass.
We can define center of mass as weighted average of the positions of all the individual masses in an object.
The center of mass is an important concept in physics and engineering because it determines the object's overall behavior when acted upon by external forces.
Formula:
COM = (Σmi * ri) / (Σmi), where
COM = Center of Mass
mi = mass of individual particle i
ri = position vector of individual particle i
Σ = sum over all particles in the object
For example:
The center of mass of a rigid body remains at rest if no external forces are acting on it, and the object rotates about its center of mass under the influence of a torque. Understanding the center of mass is crucial for analyzing and designing a wide range of systems, from planetary motions to the design of buildings and bridges.
Learn more about center of mass here:
https://brainly.com/question/8662931
#SPJ4
A particle moves along x-axis and its acceleration at any time t is a=2sin(πt), where t is in seconds and a is in m/s2. The initial velocity of particle (at time t=0) is u=0. Then the distance travelled (in meters) by the particle from time t=0 to t=t will be
Answers
The distance traveled by the particle from time t = 0 to t = t is given by 2/πsin(πt) meters.
To find the distance traveled by the particle from time t = 0 to t = t, we need to integrate the velocity function. Since the acceleration is given as a = 2sin(πt), we can find the velocity function v(t) by integrating the acceleration with respect to time: v(t) = ∫ a dt = ∫ 2sin(πt) dt
Integrating sin(πt) with respect to t gives us: v(t) = -2/πcos(πt) + C. Given that the initial velocity u = 0, we can determine the constant C as 0: v(t) = -2/πcos(πt)
Now, to find the distance traveled, we integrate the absolute value of the velocity function: s(t) = ∫ |v(t)| dt = ∫ |-2/πcos(πt)| dt. Integrating |-2/πcos(πt)| with respect to t yields: s(t) = 2/π∫cos(πt) dt = 2/πsin(πt) + D
Since we are considering the distance traveled from t = 0 to t = t, the constant D is 0: s(t) = 2/πsin(πt)
Therefore, the distance traveled by the particle from time t = 0 to t = t is given by 2/πsin(πt) meters.
To know more about velocity, refer here:
https://brainly.com/question/30559316#
#SPJ11
A tugboat is pulling a barge into a harbor. The barge is exerting a force of 3000 N against the tugboat.
Answers
Available options are:
A. –4500 N
B. –2500 N
C. 2500 N
D. 4500 N
Answer:
-4500 N
Explanation:
Given that we have F₁ = 3000N? (force of the barge)
the force of the tugboat is F '
To pull the barge, the force of the tugboat must be greater than or equal to the force of the barge.
Hence, according to Newton's third law which states that for every action or force in nature, there is an opposite reaction.
Therefore considering the available option the correct answer is "- 4500N, " this is because it is greater than the force of the barge and it's in opposition to the force exerted.
Answer:
The answer is -4500 N
Explanation:
a cable hangs between two poles 12 yards apart. the cable forms a catenary that can be modeled by the equation y = 12 cosh ( x 12 ) − 7 between x = − 6 and x = 6 . find the area under the catenary.
Round your answer to four decimal places. Arc Length ≈ yards Question Help: □ Message instructor
Answers
The area under the catenary of the cable is approximately 24.0316 square yards.
We can use the formula:∫a^b f(x) dxwhere f(x) is the equation of the function and a and b are the limits of integration.
Substituting the given equation for f(x) and limits a = -6 and b = 6, we get:∫-6^6 (12cosh(x/12) - 7) dxNow, we know that the integral of cosh(x) is sinh(x). Therefore, we can integrate
the given function using the substitution u = x/12:∫-6^6 (12cosh(x/12) - 7) dx= ∫-6^6 12cosh(x/12) dx - ∫-6^6 7 dx= 12∫-6^6 cosh(x/12) dx - [7x] from -6 to 6= 12[sinh(x/12)] from -6 to 6 - 14Putting in the limits, we get:12[sinh(6/12) - sinh(-6/12)] - 14= 24.0316 (rounded to 4 decimal places)Therefore, the area under the catenary of the cable is approximately 24.0316 square yards.
Learn more about cable here:
https://brainly.com/question/30424450
#SPJ11
A 0.061 kg golf ball is struck by a golf club with a force of 299.4 N. The change in velocity of the ball is 54.3 m/s. How much time is the ball in contact with the club?
Answers
Answer:
The time the ball is in contact with the club is approximately 0.011063 seconds
Explanation:
The question is with regards to Newton's second law of motion which states that a force is equal to the rate of change of momentum produced
The given parameters are;
The mass of the ball, m = 0.061 kg
The force with which the ball is struck with the golf club, F = 299.4 N
The change in velocity of the ball, Δv = 54.3 m/s
By Newton's second law, we have;
\(F_{net} = \dfrac{\Delta P}{\Delta t} = \dfrac{m \times \Delta v}{\Delta t}\)
Where;
Δt = The time it takes the momentum of the object to change = The time the ball is in contact with the club
Substituting the known values, we get;
\(F_{net} = F =299.4 = \dfrac{0.061 \times 54.3}{\Delta t}\)
\(\therefore \Delta t = \dfrac{0.061 \times 54.3}{299.4} \approx 0.011063\)
The time the ball is in contact with the club = Δt ≈ 0.011063 seconds.
i need to speak with zuka
Answers
Answer:
DMs are not accessible anymore. I assume Zuka is a staff member? the only way to talk to a staff member anymore is to report something, but even then, the probably won't even look at what they're deleting :/
May I have brainliest please? :)
50 POINTS & RLLY EASY
Which planet has the features that best describe Mars?
Select one:
A.
-has a lower density than liquid water
- circled by many rings, which are made of light and dust that reflect light easily
- second largest planet in the solar system made of gas and rock
b. has landforms made by flowing liquid water
- has many huge on its surface
- gets its red color from iron oxide present in soil and rocks on surface
- reflects light from sun
c.
- largest and most massive planet in the solar system
-has a huge permanent storm that looks like a red spot in images
- has at least 61 moons orbiting it, some of which are very large
- located closer to the sun than Kuiper Belt
d.
- methane in the atmosphere gives planet a blue-green color
- poles are oriented almost parallel to the planet's orbit
- poles experience constant daylight or darkness for 48 years at a time
- located in our solar system
Answers
Answer:
b. has landforms made by flowing liquid water
- has many huge on its surface
- gets its red color from iron oxide present in soil and rocks on surface
- reflects light from sun
Explanation:
An African Bush Elephant can weigh up to 13,000 lbs, how many grams is that?
(Hint - 11b. = .54kg)
Final Answer:
Answers
the lowest point in death valley is 85.0 m below sea level. the summit of nearby mr. whitney has an elevation of 4420 m above sea level. what is the change in gravitational potential energy of an energetic 65.0 kg hiker who makes it from the floor of death valley to the top of mr. whitney? (answer: 2.87 x 106 j)
Answers
Answer:
ΔPE = 2.87 x 10^6 J
Explanation:
We can use the formula for the change in gravitational potential energy:
ΔPE = mgh
where m is the mass of the hiker, g is the acceleration due to gravity, and h is the change in height. We can use the given elevations to find the change in height:
h = 4420 m - (-85.0 m) = 4505 m
Note that we add the two elevations because the elevation of Death Valley is negative.
We can now substitute the values into the formula:
ΔPE = (65.0 kg)(9.81 m/s^2)(4505 m)
ΔPE = 2.87 x 10^6 J
Therefore, the change in gravitational potential energy of the hiker is approximately 2.87 x 10^6 J.
The change in gravitational potential energy of the hiker can be calculated using the formula:
ΔPE = mgh
where m is the mass of the hiker, g is the acceleration due to gravity, and h is the change in height (altitude).
To use this formula, we need to first determine the change in height that the hiker experiences. This can be found by taking the difference between the altitude of the summit of Mt. Whitney and the altitude of the lowest point in Death Valley, and then adding them together to get the total change in altitude:
h = 4420 m + 85.0 m = 4505.0 m
Next, we can substitute the given values into the formula to find the change in gravitational potential energy:
ΔPE = \((65.0 kg) * (9.81 m/s^2) * (4505.0 m)\)
ΔPE = \(2.87 \times 10^6 J\)
Therefore, the change in gravitational potential energy of the hiker is \(2.87 \times 10^6 J\).
Learn more about gravitational potential energy:
https://brainly.com/question/15896499
#SPJ11
I need help with this question it's science
Answers
Alex participates in an aerobics class five times per week at 50% of his maximum heart rate for 20 minutes. If Alex wants to improve his cardiorespiratory endurance, what does he need to increase
Answers
To improve his cardiorespiratory endurance, Alex needs to increase either the intensity, duration, or frequency of his aerobic exercise.
Cardiorespiratory endurance refers to the ability of the cardiovascular and respiratory systems to efficiently deliver oxygen to the working muscles during sustained physical activity. To improve this endurance, it is important to challenge and gradually increase the demands placed on these systems through aerobic exercise.
In Alex's case, he participates in an aerobics class five times per week at 50% of his maximum heart rate for 20 minutes. To further improve his cardiorespiratory endurance, he has several options:
Increase Intensity: Alex can aim to exercise at a higher intensity by increasing his heart rate closer to his maximum heart rate. This can be achieved by increasing the difficulty level of the aerobics exercises, incorporating high-intensity interval training (HIIT), or engaging in more vigorous forms of aerobic exercise.
Increase Duration: Alex can extend the duration of his aerobic workouts. Instead of exercising for 20 minutes, he can gradually increase the time to 30, 40, or 60 minutes. This challenges his cardiovascular and respiratory systems for a longer period, leading to improvements in endurance.
Increase Frequency: Alex can add more sessions of aerobic exercise per week. Instead of exercising five times a week, he can aim for six or seven sessions. This increases the overall training volume and provides more opportunities for the body to adapt and improve its cardiorespiratory endurance.
To enhance his cardiorespiratory endurance, Alex can make adjustments in the intensity, duration, or frequency of his aerobic exercise. By gradually increasing one or more of these factors, he can progressively challenge his cardiovascular and respiratory systems, leading to improvements in his endurance capacity. It is important for Alex to listen to his body, gradually progress his exercise routine, and seek guidance from a qualified fitness professional for personalized recommendations.
To know more about aerobic exercise, visit
https://brainly.com/question/29776375
#SPJ11
A boat takes 2.5 hr to go 25 mi upstream against the current. It can go 55 mi downstream with the current in the same amount of time. Find the speed of the current and the speed of the boat in still w
Answers
Part 1 of 2 The speed of the boat in still water is 16 mph.
Part 2 of 2 The speed of the current is 6 mph.
Given that, the boat takes 2.5 hr to go 25 mi upstream against the current. It can go 55 mi downstream with the current in the same amount of time. Let the speed of the boat in still water be B and the speed of the current be C.
As we know,Speed = Distance/Time
Speed of the boat while going upstream = (B - C) mph
Time taken to travel upstream = 2.5 hours
Distance travelled upstream = 25 miles
Therefore, B - C = 25/2.5
B - C = 10 equation (1)
Speed of the boat while going downstream = (B + C) mph
Time taken to travel downstream = 2.5 hours
Distance travelled downstream = 55 miles
Therefore, B + C = 55/2.5
B + C = 22 equation (2)
On solving the equations (1) and (2), we get the value of B and C.
2B = 32B = 16 mph
Substituting the value of B in equation (1)
B - C = 10=> 16 - C = 10=> C = 16 - 10=> C = 6 mph
The speed of the current is 6 mph and the speed of the boat in still water is 16 mph.
Learn more about the speed at
#SPJ11
The complete question is:
A boat takes 2.5 hr to go 25 mi upstream against the current. It can go 55 mi downstream with the current in the same amount of time. Find the speed of the current and the speed of the boat in still water.
Part 1 of 2 The speed of the boat in still water is ______ mph.
Part 2 of 2 The speed of the current is __________ mph.
How much heat energy must be absorbed by 300 g of liquid water to raise its temperature by 30 degree straight C?
Answers
Answer: To calculate the heat energy required to raise the temperature of a substance, we use the formula:
Q = m * c * ΔT
where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
For liquid water, the specific heat capacity is approximately 4.18 J/g°C.
So, for 300 g of liquid water to be raised by 30°C, we have:
Q = 300 g * 4.18 J/g°C * 30°C
Q = 37,620 J
Therefore, 37,620 Joules of heat energy must be absorbed by 300 g of liquid water to raise its temperature by 30 degrees Celsius.
ice core samples are used to measure…
A. Past climates
B. Future climates
C. Future weather
D. Current weather
Answers
the answer is A
Which color of visible light has a LOWER FREQUENCY than orange light?
A. Green
B. Red
O C. Blue
D. Violet
Answers
Answer:
B. Red
Step by step explanation:
Answer:
Explanation:
Green Blue and Violet are all above Orange.
Only red is below it.
Here are the colors and their frequencies.
Color Frequency * 10^14
Red 4.62
Orange 5.00
Green 5.45
Blue 6.66
Violet 7.50
Can someone help me with this?
Answers
Answer:
1- origin
2- y coordinate
3- y axis
4- x axis
5- x coordinate
Explanation:
Find the work done by a weightlifter lifting a 20kg barbell 2.2 m upward at a constant speed.
Answers
Answer:
440J
Explanation:
First, let us find the weight of the barbell.
The formula to find the weight is :
W = m × g
Here,
m ⇒ mass ⇒ 20 kg
g ⇒ acceleration of gravity
Let us find it now.
W = m × g
W = 20 kg × 10 ms⁻²
W = 200N
And now let us find the work done by this weight lifter.
Work = Force × Displacement
Let us find it now.
Work = Force × Displacement
= 200N × 2.2m
= 440J
A spring oscillates with a period of
0.228 S. What is its frequency?
(Unit = Hz)
Answers
Answer:4.39
Explanation:For acellus students the answer is 4.39
A change of position is called
o distance
O velocity
O speed
O displacement
Answers
State whether these questions are true or false.
Q1) Distance formula is displacement/time T/F?
Q2)velocity formula is = displacement/time T/F?
Answers
\(▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)
The given statements are :
Q1) Distance formula is displacement/time T/F?
- False
Q2)velocity formula is = displacement/time T/F?
- True
Compare and Contrast the two main branches of physical science. How are they the same? How are they different?
Answers
Chemistry
Physical science is science which studies non-living things.This covers things on earth to the universe.The main branches are physics and chemistry.The other sub-branches are Astronomy, meteorology and Geology.Physics is concerned with the basic principals of matter and energy.It covers concepts in motion, energy, force, pressure , light and many other areas we encounter in our day to day life.Chemistry is concerned with composition of matter and how it reacts.Material in chemistry is understood through observing molecules, atoms, elements and their interaction in nature including their properties.Chemistry is further divided into organic chemistry and natural chemistry sub-branches.
Hope this helps you!!!
3. An electric motor is used to lift a 6.0 kg of mass through a height of 1 metre. The energy it uses is measure on an energy meter is 10 joules.
a) Calculate the work done in lifting the mass
Answers
Answer:
Climbing stairs and lifting objects is work in both the scientific and everyday sense—it is work done against the gravitational force. When there is work, there is a transformation of energy. The work done against the gravitational force goes into an important form of stored energy that we will explore in this section.

Figure 1. (a) The work done to lift the weight is stored in the mass-Earth system as gravitational potential energy. (b) As the weight moves downward, this gravitational potential energy is transferred to the cuckoo clock.
Let us calculate the work done in lifting an object of mass m through a height h, such as in Figure 1. If the object is lifted straight up at constant speed, then the force needed to lift it is equal to its weight mg. The work done on the mass is then W = Fd = mgh. We define this to be the gravitational potential energy (PEg) put into (or gained by) the object-Earth system. This energy is associated with the state of separation between two objects that attract each other by the gravitational force. For convenience, we refer to this as the PEg gained by the object, recognizing that this is energy stored in the gravitational field of Earth. Why do we use the word “system”? Potential energy is a property of a system rather than of a single object—due to its physical position. An object’s gravitational potential is due to its position relative to the surroundings within the Earth-object system. The force applied to the object is an external force, from outside the system. When it does positive work it increases the gravitational potential energy of the system. Because gravitational potential energy depends on relative position, we need a reference level at which to set the potential energy equal to 0. We usually choose this point to be Earth’s surface, but this point is arbitrary; what is important is the difference in gravitational potential energy, because this difference is what relates to the work done. The difference in gravitational potential energy of an object (in the Earth-object system) between two rungs of a ladder will be the same for the first two rungs as for the last two rungs.
Converting Between Potential Energy and Kinetic Energy
Gravitational potential energy may be converted to other forms of energy, such as kinetic energy. If we release the mass, gravitational force will do an amount of work equal to mgh on it, thereby increasing its kinetic energy by that same amount (by the work-energy theorem). We will find it more useful to consider just the conversion of PEg to KE without explicitly considering the intermediate step of work. (See Example 2.) This shortcut makes it is easier to solve problems using energy (if possible) rather than explicitly using forces.
More precisely, we define the change in gravitational potential energy ΔPEg to be ΔPEg = mgh, where, for simplicity, we denote the change in height by h rather than the usual Δh. Note that h is positive when the final height is greater than the initial height, and vice versa. For example, if a 0.500-kg mass hung from a cuckoo clock is raised 1.00 m, then its change in gravitational potential energy is
mgh=(0.500 kg)(9.80 m/s2)(1.00 m) =4.90 kg⋅m2/s2=4.90 Jmgh=(0.500 kg)(9.80 m/s2)(1.00 m) =4.90 kg⋅m2/s2=4.90 J
Note that the units of gravitational potential energy turn out to be joules, the same as for work and other forms of energy. As the clock runs, the mass is lowered. We can think of the mass as gradually giving up its 4.90 J of gravitational potential energy, without directly considering the force of gravity that does the
provide 2 important pitching tips you can tell someone else. softball
Answers
Tip 1 - throwing a fastball. Use two points to keep your arm properly aligned your biceps brush your ear at the top of the backswing, and your pitching hand brushes your hip at release.
Tip 2 - throwing a curveball. Pictures should know that in order to maximize your curves, you should visualize a series of dots from the mound to the outside corner of the plate. Pitch along those dots.
Tip 3 - throwing a fast pitch rise. It’s possible that your wrist snap may be sideways. Play with different grips or finger pressures and try to relax them.
Tip 4 - throwing a change-up. Don’t always throw the change-up in a given situation. Make sure to change your pitch selection.
Tip 5 - throwing a drop-ball. Keep your pitching arm close to your body to avoid injury.
Please help!!!!! I will give brainliest. Describe four examples of acceleration you see during your day. Choose an object that is slowing down, one that is speeding up, one that is moving at a constant speed but changing direction, and one that is moving at a constant velocity with zero acceleration.
Answers
When the brake is applied to the car and comes to rest after some time is an example of an object that is slowing down.
What is acceleration?The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.
1. When the brake is applied to the body and comes to rest after some time is an example of an object that is slowing down.
2. When a person accelerates the car and the velocity is increasing is an example of speeding up.
3. An object moves in a circular motion moving at a constant speed but changing direction,
4. Acceleration is the rate of change of velocity. If the change in the velocity is constant the acceleration is zero is an example of moving at a constant velocity with zero acceleration.
To learn more about acceleration, refer to the link;
https://brainly.com/question/2437624
#SPJ1
PLEASE HELP ME! IM TIMED
Answers
Answer:
it b
Explanation:
just try