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The encryption method that combines a random value with the plain text to produce the cipher text is: One-time pad.

The one-time pad encryption technique is a form of symmetric encryption where a random key, known as the one-time pad, is combined with the plain text using a bitwise XOR operation. The one-time pad should be at least as long as the plain text and should never be reused.

In this method, each character of the plain text is combined with a corresponding character from the one-time pad, resulting in the cipher text. The one-time pad acts as a random key stream, making the encryption extremely secure if implemented correctly.

Steganography is a different technique that involves hiding information within other seemingly innocuous data, such as images or audio files, without necessarily encrypting it.

Transposition is a method of encryption where the characters of the plain text are rearranged or shuffled without changing the actual characters themselves.

Elliptic Curve is not an encryption method but rather a mathematical framework used in public-key cryptography systems, such as Elliptic Curve Cryptography (ECC), which provide secure communication channels but do not involve combining random values with the plain text to produce the cipher text.

Therefore, the correct answer is: One-time pad.

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In 1 minute, bison runs 3520 feet

In 60 minutes, the bison would run

3520*60 feet

211200 feet per hour.

These are equivalent to;

40 miles per hour since 1 mile is equivalent to 5280 feet.

The bison is faster by 10 miles per hour

Answer:

b. 14

Step-by-step explanation:

The probability that the randomly selected sample will have less than 97.5% of the units that can hold at least 400 lbs of weight before breaking is 2.4249.

What is the binomial distribution?

In probability theory and statistics, the discrete probability distribution of the number of successes in a series of n separate experiments, each asking a yes-or-no question and each with its own Boolean-valued outcome: success or failure, is known as the binomial distribution with parameters n and p.

Here, we have

Given: For one product, 98% of all the units made at a particular factory can hold at least 400 lbs. of weight before breaking to check the product, quality control selects a random sample of 300 units made at the factory and determines whether or not the product can hold at least 400 lbs.

p = 0.98

q = 1 - p = 1 - 0.98 = 0.02

n = 300

Using the binomial distribution,

Standard deviation = σ = √npq = √300 × 0.98 × 0.02 = 2.4249

Standard deviation = σ = 2.4249

Hence, the probability that the randomly selected sample will have less than 97.5% of the units that can hold at least 400 lbs of weight before breaking is 2.4249.

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Step-by-step explanation: it 6

Answer: 252m^2 (squared)

Step-by-step explanation: 2×(6×3 + 6×12 + 3×12) = 252m^2

The probability that a student who has an A is a male is 60%.

To find the probability that a student who has an A is a male, we need to calculate the ratio of the number of male students with an A to the total number of students with an A.

Given that there are 19 students in total, and 6 of them are female, we can determine that there are 19 - 6 = 13 male students. Out of these male students, 7 do not have an A. Therefore, the number of male students with an A is 13 - 7 = 6.

Now, we know that there are 10 students in total who have an A. Therefore, the probability that a student with an A is a male can be calculated as the ratio of the number of male students with an A to the total number of students with an A:

Probability = Number of male students with an A / Total number of students with an A

Probability = 6 / 10

Probability = 0.6 or 60%

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SOLUTION

We want to solve the equation

cross multiplying, we have

Hence the answer is x = 2, the first option

The value of "p" will be "0.002".

According to the question,

By subtracting "0.25p" from both sides, we get

→ \(100+0.05p-0.25p=0.25p-0.25p\)

                 \(100-0.2p=0\)

                            \(100=0.2p\)

                               \(p = \frac{0.2}{100}\)

                                  \(= 0.002\)

Thus the above approach is right.

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To determine if a data point is considered an outlier for a data set, we need to calculate the interquartile range (IQR) and use it to define the outlier boundaries. The IQR is the difference between the third quartile (Q3) and the first quartile (Q1). The correct option is (B).

We have that Q1 = 9 and Q3 = 17, we can calculate the IQR as follows:

IQR = Q3 - Q1 = 17 - 9 = 8

To identify outliers, we can use the following rule:

- Any data point that is less than Q1 - 1.5 * IQR or greater than Q3 + 1.5 * IQR is considered an outlier.

Using this rule, we can evaluate each data point:

A. 27: This data point is greater than Q3 + 1.5 * IQR = 17 + 1.5 * 8 = 29. It is considered an outlier.

B. 17: This data point is not an outlier because it is equal to the third quartile (Q3).

C. 3: This data point is less than Q1 - 1.5 * IQR = 9 - 1.5 * 8 = -3. It is considered an outlier.

D. 41: This data point is greater than Q3 + 1.5 * IQR = 17 + 1.5 * 8 = 29. It is considered an outlier.

Therefore, the outliers in the data set are A (27) and D (41).

As for when to use the mean, it is generally recommended to use the mean as a measure of central tendency when the data is symmetric and does not have extreme values.

Therefore, the correct option would be B. When the data is symmetric.

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Answer:

x=4

Step-by-step explanation:

We are given that the triangles are congruent.

Specifically, the order of the letters gives that the angles ∠DAB and ∠CBA are corresponding parts of the two congruent triangles.  Since corresponding parts of congruent triangles are themselves congruent, ∠DAB ≅ ∠CBA.  Thus, m∠DAB = m∠CBA.

Given the expressions for the two angles, we can substitute into the equation, and solve for the requested variable.

\(m\angle DAB=m\angle CBA\\(35)=(8x+3)\\(35)-3=(8x+3\!\!\!\!\!\!\!\!\!\!{--})-3 \!\!\!\!\!\!\!\!\!\! {--}\\32=8x\\\dfrac {32}{8}=\dfrac {8x\!\!\!\!\!\!\! {-}}{8\!\!\!\! {-}}\\4=x\)

It would take the two painters together eight hours to paint the house

Step-by-step explanation: Given that, One painter can paint the entire house in twelve hours. The second painter takes eight hours to paint a similarly-sized house. To find, How long would it take the two painters together to paint the house? Suppose one painter takes x hours to paint the house.

Therefore, the other painter will take x-4 hours to paint the same house. According to the question, \(1/x+1/(x-4)=1/12+1/8\) Multiply by LCM, \(8(x-4)=12x+12(x-4)8x-32=6x+484x=80x=20\)Therefore, the first painter will take 20 hours to paint the house. The second painter will take 16 hours (20-4). Together they will take, \(1/20+1/16=0.1+0.0625=0.1625\) Thus, they will take 6.1538 hours which can be rounded to 4.8 hours.

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Considering the forecasted demand of 30,000 units, the best site would be Comilla as it yields the highest profit among all locations for that particular volume.

To determine the best site for the new manufacturing plant based on volume and pricing factors, we need to calculate the total costs and revenues for each location. The location with the highest profit will be considered the best site. Let's calculate the profits for each location based on the given information:

Location: Rajshahi

Fixed cost per year: $30,000

Variable cost per product: $45

Price per product: $150

Forecast demand per year: 20,000

Total Cost = Fixed Cost + (Variable Cost per Product * Forecast Demand per Year)

Total Revenue = Price per Product * Forecast Demand per Year

Profit = Total Revenue - Total Cost

Total Cost = $30,000 + ($45 * 20,000) = $1,050,000

Total Revenue = $150 * 20,000 = $3,000,000

Profit = $3,000,000 - $1,050,000 = $1,950,000

Performing similar calculations for the other locations, we get:

Location: Dhaka

Total Cost = $100,000 + ($75 * 50,000) = $4,850,000

Total Revenue = $120 * 50,000 = $6,000,000

Profit = $6,000,000 - $4,850,000 = $1,150,000

Location: Comilla

Total Cost = $60,000 + ($35 * 30,000) = $1,110,000

Total Revenue = $100 * 30,000 = $3,000,000

Profit = $3,000,000 - $1,110,000 = $1,890,000

Location: Chittagong

Total Cost = $110,000 + ($60 * 40,000) = $2,510,000

Total Revenue = $90 * 40,000 = $3,600,000

Profit = $3,600,000 - $2,510,000 = $1,090,000

Based on the calculated profits, we can determine the range in volume over which each location would be best:

Rajshahi: The best site for a volume range up to 20,000 units.

Dhaka: The best site for a volume range between 20,001 and 50,000 units.

Comilla: The best site for a volume range between 50,001 and 30,000 units.

Chittagong: The best site for a volume range above 30,000 units.

Therefore, considering the forecasted demand of 30,000 units, the best site would be Comilla as it yields the highest profit among all locations for that particular volume.

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The correct formula for the expression is,

⇒ f (x)  = - 6 cos (π/4.5x - 2π) + 2

Since, Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.

We have a function:

f(x) = a cos(bx + c) + d

Here a is the amplitude:

Since, The value of d is the average of maximum and minimum.

Hence,  d = (9 - 5)/2 = 4/2 = 2

And, The value of 'a' is the difference between the maximum value and d.

Hence,  a = -4 -(2) = - 6

Here, the half-period is,

= π - 3π/4) = π/4

=  b = 2π/9 = π/4.5

The value of c is the value makes the cosine zero at x= 9

⇒  (π/4.5)(9) +c = 0

⇒  c = -2π

Hence, Function is,

f (x) = - 6 cos (π/4.5x - 2π) + 2

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Answer:

The correct answer would be:

f (x) = - 6 cos (π/4.5x - 2π) + 2

Therefore, the ∠1 in the triangle is 35 degrees and ∠2 is 35 degrees.

A triangle is a geometric shape that consists of three straight sides and three angles. The sum of the interior angles of a triangle is always 180 degrees. Triangles are classified based on the length of their sides and the measure of their angles. Some common types of triangles include equilateral triangles, which have three equal sides and three equal angles of 60 degrees each; isosceles triangles, which have two equal sides and two equal angles; and scalene triangles, which have three unequal sides and three unequal angles. Triangles have a wide range of applications in mathematics, science, engineering, and other fields.

line 1,2,4 is a Stright line then ∠4+∠2 is a 180 degree.

∠4+∠2 = 180 degrees

145 +∠2 = 180

∠2 = 180-145

∠2 = 35 degrees

The sum of the angles in a triangle is always 180 degrees. Therefore, we can find the ∠1 by subtracting the sum of the two given angles from 180 degrees:

∠1 = 180 degrees - (110 degrees + 35 degrees)

∠1 = 180 degrees - 145 degrees

∠1 = 35 degrees

Therefore, the ∠1 in the triangle is 35 degrees.

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The volume of the solid generated by revolving the region is 30395.33 cubic units

To find the volume of the solid generated by revolving the region bounded by the curves y = 5√x and y = x^2/6 about the line x = 5, we can use the method of cylindrical shells.

First, let's determine the limits of integration. The region is bounded by the curves y = 5√x and y = x^2/6. To find the intersection points, we set the two equations equal to each other:

5√x = x^2/6

Simplifying, we have:

30√x = x^2

Dividing both sides by x, we get:

30 = x

So, the intersection point is x = 30.

The region is bounded by x = 0 (the y-axis) and x = 30.

Now, let's set up the integral to calculate the volume. The volume can be expressed as:

V = ∫(2πrh) dx

where r is the distance from the axis of revolution (x = 5) to the curve, and h is the height of the shell.

The radius r can be determined by subtracting the x-coordinate (5) from the x-value of the curve at each point x.

r = x - 5

The height h of each shell is the difference between the y-values of the two curves:

h = (x^2/6) - 5√x

Now, we can set up the integral:

V = ∫[0,30] (2π(x-5)((x^2/6) - 5√x)) dx

Simplifying the integrand, we have:

V = ∫[0,30] (2π/6)(x^3 - 5x√x - 5x^2 + 25√x) dx

V = (π/3)∫[0,30] (x^3 - 5x√x - 5x^2 + 25√x) dx

Now, we can integrate each term separately:

V = (π/3)[(x^4/4) - (10/7)(x^(3/2)) - (5/3)(x^3) + (50/3)(x^(1/2))] |[0,30]

Evaluating the integral at the upper and lower limits, we get:

V = (π/3)[(30^4/4) - (10/7)(30^(3/2)) - (5/3)(30^3) + (50/3)(30^(1/2))] - (π/3)[(0^4/4) - (10/7)(0^(3/2)) - (5/3)(0^3) + (50/3)(0^(1/2))]

Simplifying further:

V = (π/3)[(81000/4) - (300/7) - (45000) + (1500/3)] - (π/3)(0)

V = (π/3)[(202500/4) - (300/7) - (45000) + (500)] - (π/3)(0)

V = (π/3)[(202500 - 85714 - 45000 + 500)] - (π/3)(0)

V = (π/3)[91186]

Finally, we can box the final answer:

V = 30395.33 cubic units

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Answer:

The cost to rent each chair is $1.25 and the cost to rent each table is $8.50

Step by step:

A party rental company has chairs and tables for rent. The total cost to rent

A party rental company has chairs and tables for rent. The total cost to rent 4

chairs and 8

tables is $73

. The total cost to rent 2

chairs and 3

tables is $28

. What is the cost to rent each chair and each table?

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1 Expert Answer

By:

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Edward C. answered • 02/10/15

TUTOR 5.0 (377)

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Let C = cost to rent each chair

Let T = cost to rent each table

4C + 8T = 73

2C + 3T = 28

Multiply the 2nd equation by (-2) and then add the equations together

4C + 8T = 73

-4C - 6T = -56

2T = 17

T = 17/2 = 8.5

Plug this in to the 1st equation to solve for C

4C + 8(17/2) = 73

4C + 68 = 73

4C = 5

C = 5/4 = 1.25

So the cost to rent each chair is $1.25 and the cost to rent each table is $8.50

The cost to rent each chair and each table are $1 and $8.5 respectively.

Suppose the price of one chair =x

The price of one table =y

Any equation of the form ax+by+c=0 is called a linear equation where a, b, c∈ R.

According to the question, the total cost to rent 5 chairs and 2 tables is $22.

5x+2y=22

Multiplying it by 4 on both sides

20x+8y=88.......(1)

The total cost to rent 3 chairs and 8 tables is $71.

3x+8y=71.........(2)

Subtracting (2) from (1)

17x=17

x=1

So, y=8.5

So, the price of 1 chair =$1

the price of 1 table =$8.5

Hence, the cost to rent each chair and each table are $1 and $8.5 respectively.

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The system of equations has infinite solutions, both equations represent the same line.

Here we have the following system of equations:

-3x+6y=12

2y=x+4

And we want to solve this by substitution, first, we can rewrite the first equation as:

-3x + 3*(2y) = 12

Now we can substitute the second equation 2y = x + 4 in the parenthesis, we will get:

-3x + 3*(x + 4) = 12

Now we can solve this for x.

-3x + 3x + 12 = 12

12 = 12

So this is true for any value of x, which means that both equations represent the same line (thus the system has infinite solutions).

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y approaches 5.

As x approaches infinity, -4^(-x) approaches 0.

0 + 5 = 5

Answer:

Step-by-step explanation:

40.8-10²

40.8-10×10

40.8-100

320-100

Answer:

B

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (- 2, 10) and (x₂, y₂ ) = (8, - 10) ← 2 ordered pairs from the table

m = \(\frac{-10-10}{8-(-2)}\) = \(\frac{-20}{8+2}\) = \(\frac{-20}{10}\) = - 2 → B

Answer:

the second one I think, as it is clearer and makes more sense

The jump will be from 0 to 0.8, and the other jump from 0.8 to 1.1 in the right direction. Then the correct option is B.

A number line refers to a straight line in mathematics that has numbers arranged at regular intervals or portions along its width. A number line is often shown horizontally and can be postponed in any direction.

The expression is given below.

⇒ 0.8 + 0.3

The sign of both terms are similar that is positive.

If the sign of the number is positive, then we move rightward. Similarly, if the sign of the number is negative, then we move leftward.

First, the jump will be from 0 to 0.8, and the other jump from 0.8 to 1.1 in the right direction. Then the correct option is B.

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Answer: We can solve this problem using the standard normal distribution and standardizing the variable X.

Let Z be a standard normal variable, which is obtained by standardizing X as:

Z = (X - μ) / σ

where μ is the mean of X and σ is the standard deviation of X.

In this case, X is normal with mean μ = 3.6 and variance σ^2 = 0.01, so its standard deviation is σ = 0.1.

Then, we have:

Z = (X - 3.6) / 0.1

To find C such that P(X <= c) = 5%, we need to find the value of Z for which the cumulative distribution function (CDF) of the standard normal distribution equals 0.05. Using a standard normal table or calculator, we find that:

P(Z <= -1.645) = 0.05

Therefore:

(X - 3.6) / 0.1 = -1.645

X = -0.1645 * 0.1 + 3.6 = 3.58355

So C is approximately 3.5836.

To find C such that P(X > c) = 10%, we need to find the value of Z for which the CDF of the standard normal distribution equals 0.9. Using the same table or calculator, we find that:

P(Z > 1.28) = 0.1

Therefore:

(X - 3.6) / 0.1 = 1.28

X = 1.28 * 0.1 + 3.6 = 3.728

So C is approximately 3.728.

To find C such that P(-c < X < c) = 95%, we need to find the values of Z for which the CDF of the standard normal distribution equals 0.025 and 0.975, respectively. Using the same table or calculator, we find that:

P(Z < -1.96) = 0.025 and P(Z < 1.96) = 0.975

Therefore:

(X - 3.6) / 0.1 = -1.96 and (X - 3.6) / 0.1 = 1.96

Solving for X in each equation, we get:

X = -0.196 * 0.1 + 3.6 = 3.5804 and X = 1.96 * 0.1 + 3.6 = 3.836

So the interval (-c, c) is approximately (-0.216, 3.836).

Answer:

This is not possible, since probabilities cannot be negative. Therefore, there is no value of e that satisfies the given condition

Step-by-step explanation:

We can use the standard normal distribution to solve this problem by standardizing X to Z as follows:

Z = (X - μ) / σ = (X - 3.6) / 0.1

Then, we can use the standard normal distribution table or calculator to find the values of Z that correspond to the given probabilities.

P(X <= c) = P(Z <= (c - 3.6) / 0.1) = 0.05

Using a standard normal distribution table or calculator, we can find that the Z-score corresponding to the 5th percentile is -1.645. Therefore, we have:

(c - 3.6) / 0.1 = -1.645

Solving for c, we get:

c = 3.6 - 1.645 * 0.1 = 3.4355

So, the value of c such that P(X <= c) = 5% is approximately 3.4355.

Similarly, we can find the value of d such that P(X > d) = 10%. This is equivalent to finding the value of c such that P(X <= c) = 90%. Using the same approach as above, we have:

(d - 3.6) / 0.1 = 1.28 (the Z-score corresponding to the 90th percentile)

Solving for d, we get:

d = 3.6 + 1.28 * 0.1 = 3.728

So, the value of d such that P(X > d) = 10% is approximately 3.728.

Finally, we can find the value of e such that P(-e < X < e) = 90%. This is equivalent to finding the values of c and d such that P(X <= c) - P(X <= d) = 0.9. Using the values we found above, we have:

P(X <= c) - P(X <= d) = 0.05 - 0.1 = -0.05

This is not possible, since probabilities cannot be negative. Therefore, there is no value of e that satisfies the given condition

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In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

1. 9x² + 3x - 4 = 0

Step 02:

Discriminant:

D = b² - 4ac

9x² + 3x - 4 = 0

a = 9

b = 3

c = - 4

D = (3)² - 4(9)(-4) = 9 + 144 = 153

The answer is:

D = 153

Therefore ,a result, the answer to the variable problem (B) is incorrect because, even though the adjusted R-square has a lower value .

A variable is a quality that may be measured and take on several values. A few examples of variables are height, age, salary, province of birth, school grades, and kind of dwelling.

Here,

Given : The adjusted r-squared number is always lower than the s n value The added variable always causes the modified r-squared value to fall.

If a new variable is included to the regression, the r-squared result cannot drop.

. When comparing several regression models, the adjusted r-squared is more helpful than the r-squared.

Therefore ,a result, the answer to the variable problem (B) is incorrect because, even though the adjusted R-square has a lower value than the R-square, it might not drop as you add more variables.

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The quotient when 0.03 is divided by 0.148 after rounding it off is 0.2.

According to the question,

We have the following information:

0.03 is divided by 0.148

Now, we have the quotient as:

0.2027

Now, when rounding off the numbers we know that the digits from where we are rounding off we look at the right next to that digit and when that digit is greater than 5 then the digit should be increased by 1 and when that digit is less than 5 then the digit should be the same.

So, we will round it off by taking the underlined digit to be next to first 2:

So, the digit is 0.

Then, we have:

0.2

Hence, the quotient when 0.03 is divided by 0.148 after rounding it off is 0.2.

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Answer:

L = 32 cm

W = 8 cm

A = 256cm square

Step-by-step explanation:

Answer:

aprils second number was 8

Step-by-step explanation:

Answer:

i think the other one is F

Step-by-step explanation:

Answer:

Step-by-step explanation:

Conclusion:

Hoped this helped.