Part C
A blockbuster movie makes about $247,000,000 in the United States during its
opening weekend. That same weekend another movie opens but only makes
about $5,200,000.
Part C
How much more did the blockbuster movie make? Write your answer in
scientific notation.
Show your work.

The value of x for which (f - g)(x) = 0 is x = 12.

To find the value of x for which (f - g)(x) = 0, we need to subtract g(x) from f(x) and set the resulting expression equal to zero. Let's perform the subtraction:

(f - g)(x) = f(x) - g(x)

= (16x - 30) - (14x - 6)

= 16x - 30 - 14x + 6

= 2x - 24

Now, we can set the expression equal to zero and solve for x:

2x - 24 = 0

Adding 24 to both sides:

2x = 24

Dividing both sides by 2:

x = 12

Therefore, the value of x for which (f - g)(x) = 0 is x = 12.

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To find a vector perpendicular to both u = 〈-1, -5, 2, -3〉 and v = 〈-4, -5, 4, -5〉, we can take their cross product. The cross product of two vectors in R⁴ can be obtained by using the determinant of a 4x4 matrix:

Let's calculate the cross product:

u x v = 〈u₁, u₂, u₃, u₄〉 x 〈v₁, v₂, v₃, v₄〉

         = 〈(-5)(4) - (2)(-5), (2)(-5) - (-1)(4), (-1)(-5) - (-5)(-4), (-5)(-5) - (-1)(-5)〉

         = 〈-10, -14, -25, -20〉

So, a vector perpendicular to both u and v is 〈-10, -14, -25, -20〉.

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Answer:

  10.8 feet

Step-by-step explanation:

You want the length of the shadow of a 27 ft tree if a 5 ft post casts a 2 ft shadow.

The shadow length is proportional to the object height, so you have ...

  (tree shadow)/(tree height) = (post shadow)/(post height)

  x/(27 ft) = (2 ft)/(5 ft)

  x = (27 ft)(2/5) = 10.8 ft

The length of the tree's shadow is 10.8 feet.

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To decide the length of the tree's shadow, we can utilize the idea of comparable triangles. Length of the Tree = 10.8 feet..

Since the wall post and the tree are both creating shaded areas simultaneously, we can set up an proportion between their heights and the lengths of their shadows.

We should indicate the length of the tree's shadow as x. We have the following proportion: (height of tree)/(length of tree's shadow) = (height of wall post)/(length of wall post's shadow).

Substituting the given qualities, we have: 27 ft/x = 5 ft/2 ft.

We can cross-multiply to solve for x: 27 ft * 2 ft = 5 ft * x.

Working on the equation gives us: 54 ft = 5 ft * x.

Simplifying the two sides by 5 ft provides us with the length of the tree's shadow: x = 54 ft/5 ft , x = 10.8 feet.

Calculating the expression offers us the last response, which is the length of the tree's shadow in feet.

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Answer:

0.0175 is correct answer. Please Mark it as brainlist answer.

Answer:

Below

Step-by-step explanation:

There are 13 spades    13 hearts     13 diamonds and 13 clubs in the full 52 deck

1st card  spade    13 / 52

 now there are only 51 cards lefts  13 are hearts  

      second card  hearts    13 / 51

     now there are 50 cards left    13 are diamonds

           third card diamond   13/50

        similarly for the fourth card = 13 / 49

Final prob =   13/52  * 13/51  * 13/50  * 13/49

Answer:

I believe it's 15 feet in 5 yards and 18 yards in 54 feet

Step-by-step explanation:

1. There is a total of 15 feet in 5 yards.

2. There is a total of 18 yards in 54 feet.

Answer:

28.5 united squared

Answer:

Check pdf

Step-by-step explanation:

The equation for the translated function is:

g(x)  =-3x + 1

Remember that a vertical translation of N units can be written as:

g(x) = f(x) + N

If N > 0, the translation is up.

if N < 0, the translation is down.

Here the translation is of 9 units up, then we need to write:

g(x) = f(x) + 9

Replacing f(x) we will get:

g(x) = -3x - 8 + 9

g(x)  =-3x + 1

That is the translated function.

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Answer:

1

Step-by-step explanation:

To translate f(x) = -3x - 8, 9 units up, we simply add 9 to the function: g(x) = -3x - 8 + 9 = -3x + 1. Therefore, g(x) is equal to -3x plus one. The slope of g(x) is -3 and the y-intercept is 1.

Answer: 65%

Step-by-step explanation:

The petty cash transactions can be recorded as follows:

1. April 15:

  Dr. Petty Cash (Asset)                  $250

     Cr. Cash (Asset)                           $250

  (To establish the petty cash fund with a balance of $250)

2. April 27:

  Dr. Delivery Expenses (Expense)   $180

     Cr. Petty Cash Tickets (Asset)        $180

  (To record courier receipts as delivery expenses)

  Dr. Maintenance Expenses (Expense)   $50

     Cr. Petty Cash Tickets (Asset)              $50

  (To record RONA receipts as maintenance expenses)

  Dr. Cash (Asset)                             $20

     Cr. Petty Cash Tickets (Asset)              $20

  (To replenish the petty cash fund with $20 in cash)

3. May 1:

  Dr. Petty Cash (Asset)                   $100

     Cr. Cash (Asset)                            $100

  (To increase the petty cash fund to a $350 balance)

The initial establishment of the petty cash fund on April 15 involves transferring $250 from the cash account to the petty cash account.

On April 27, the petty cash tickets are used to record the expenses. The courier receipts of $180 are recorded as delivery expenses, and the RONA receipts of $50 are recorded as maintenance expenses. Additionally, the petty cash fund is replenished with $20 in cash, representing the remaining cash on hand.

On May 1, the company decides to increase the balance of the petty cash fund to $350 by transferring an additional $100 from the cash account to the petty cash account. This adjustment reflects the decision to have a larger amount available in petty cash for day-to-day expenses.

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The Marginal Rate of Substitution (MRS) for the given function is equal to -2/sqrt(x). To find the Marginal Rate of Substitution (MRS), we need to take the derivative of the given function with respect to x.

Given: y = 24 - 4(sqrt(x))

Step 1: Differentiate the function y with respect to x.

dy/dx = d/dx(24 - 4(sqrt(x)))

Step 2: Differentiate each term separately using the power rule and chain rule.

dy/dx = 0 - 4(1/2)(x^(-1/2))(1)

Step 3: Simplify the derivative.

dy/dx = -2(x^(-1/2))

Step 4: Rewrite the derivative in terms of MRS.

MRS = dy/dx = -2/sqrt(x)

Therefore, the Marginal Rate of Substitution (MRS) for the given function y = 24 - 4(sqrt(x)) is -2/sqrt(x).

The negative sign indicates that the MRS is inversely related to x, which means as x increases, the MRS decreases. The value of MRS represents the rate at which a consumer is willing to substitute y (the dependent variable) for an incremental change in x (the independent variable). In this case, as x increases, the consumer is willing to substitute less y for the additional units of x.

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The endpoints of the translated segment A'B' after undergoing the given translation is; A'(3, 3) and B'(5, 0)

In transformation in mathematics, there are different types such as dilation, reflection, rotation, translation e.t.c

Now, in this case what we are dealing with is translation which simply means moving an object or figure from one point to the other without changing the shape or dimensions.

To translate the point AB(x, y) , 2 units down and 2 units right, we will use the translation rule;

A'B'(x + 2, y − 2) .

We are given the coordinates of AB as A(1,5) and B(3,2)

Thus;

A'(1 + 2, 5 - 2) = A'(3, 3)

B'(3 + 2, 2 - 2) = B'(5, 0)

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The solution to dy/dx=1y is y=eˣ+C, where C is a constant.

This is found by separating the variables, integrating both sides, and solving for y. The constant C is determined by initial conditions or additional information about the problem.

This differential equation is a first-order linear homogeneous equation, meaning it can be solved using separation of variables. The solution shows that the rate of change of y is proportional to y itself, leading to exponential growth or decay depending on the sign of C.

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complete question:

The solution to  differential equation dy/dx=1y   is ?

Answer:

x^4/64y^10

Step-by-step explanation:

Answer:

=4

Step-by-step explanation:

823 can be written as

3√82

=3√64

=3√(4)(4)(4)

=4

Answer:

bkrjrjjrkrkrkririirkr

Answer:

commission = 15800

Step-by-step explanation:

920000 - 400000 = 520000

400000 x .02 = 8000

520000 x .015 = 7800

8000 + 7800 = 15800

If alpha is greater than 90 degrees but beta and gamma are less than 90 degrees, the vector resides in the second octant.


The octant is a three-dimensional coordinate system that is divided into eight parts. Each octant contains vectors with different signs of x, y, and z coordinates. In this scenario, since alpha is greater than 90 degrees, it means that the vector extends from the negative x-axis. Also, beta and gamma are less than 90 degrees, so the vector is pointing upwards in the y and z directions. Therefore, the vector is in the second octant, which includes all vectors with a positive y-coordinate and a negative x and z-coordinate.


If the values of alpha, beta, and gamma are known, it is possible to locate a vector in the octant system. The second octant is defined as a space where the x-coordinate is negative, the y-coordinate is positive, and the z-coordinate is negative.

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Answer:

x = 14

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Answer:

The answer is 274

Step-by-step explanation:

Now,

Definition of Variance:

So,

\( \frac{ {(87 - 78)}^{2} + ( {46 - 78)}^{2} + (90 - 78) {}^{2} + ({78 - 78)}^{2} + ( {89 - 78)}^{2} } {5} \)

\(Var(X) \: = \frac{1370}{5} = 274 \\ \)

Thus, The variance of the sequence is 274.

Answer:

I believe its A

Step-by-step explanation:

Sorry if im wrong

a) The forecast is approximately miles. b) the Mean Absolute Deviation (MAD) based on the forecast is approximately miles. c) The forecast for year 6 is approximately miles. d) the last forecast is 3,468 miles.

a) To calculate the forecast for year 6 using a 2-year moving average, we take the average of the mileage for years 5 and 4. This provides us with the forecasted value for year 6.

b) The Mean Absolute Deviation (MAD) for the 2-year moving average forecast is calculated by taking the absolute difference between the actual mileage for year 6 and the forecasted value and then finding the average of these differences.

c) When using a weighted 2-year moving average, we assign weights to the most recent and previous periods. The forecast for year 6 is calculated by multiplying the mileage for year 5 by 0.40 and the mileage for year 4 by 0.60, and summing these weighted values.

The MAD for the weighted 2-year moving average forecast is calculated in the same way as in part b, by taking the absolute difference between the actual mileage for year 6 and the weighted forecasted value and finding the average of these differences.

d) Exponential smoothing involves assigning a weight (α) to the most recent forecasted value and adjusting it with the previous actual value. The forecast for year 6 is calculated by adding α times the difference between the actual mileage for year 5 and the previous forecasted value, to the previous forecasted value.

In this case, with α=0.20 and a forecast of 3,100 miles for year 1, we perform this exponential smoothing calculation iteratively for each year until we reach year 6, resulting in the forecasted value of approximately 3,468 miles.

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The value of the union of sets A and B is, P(A ∪ B) is 0.64.

The union of two sets means the total elements in both the sets combined.

Given: sets P(A) = 0.38, P(B) = 0.83, and  intersection P(A ∩ B) = 0.57

We need to find the union of P(A ∪ B).

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

Let us substitute the given values in the formula.

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

=0.38+0.83-0.57

=1.21-0.57

=0.64

Therefore, the value of union of sets P(A ∪ B) is 0.64.

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Answer:

\(x = 0 \: \text{or} \: x = - 4.\)

Step-by-step explanation:

\(6 {x}^{2} + 24x = 0 \\ \text{then} \: 6x(x + 4) = 0 \\ \text{hence} \: x = 0 \: \text{or} \: x + 4 = 0 \\\text{therefore} \: x = 0 \: \text{or} \: x = - 4.\)

The arc length of the curve c(t) = (√2t, 1/2 t^2, ln(t)), where 1 ≤ t, is given by (1/3)b^3 + b - 1/b + 4/3.

To find the arc length of the curve defined by c(t) = (√2t, 1/2 t^2, ln(t)), where 1 ≤ t, we can use the arc length formula:

L = ∫[a,b] √[dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2 dt

Let's calculate the derivatives first:

dx/dt = (√2)'t = √2

dy/dt = (1/2 t^2)' = t

dz/dt = (ln(t))' = 1/t

Now we can substitute these derivatives into the arc length formula:

L = ∫[1,b] √(√2)^2 + t^2 + (1/t)^2 dt

L = ∫[1,b] 2 + t^2 + 1/t^2 dt

L = ∫[1,b] (2t^2 + t^4 + 1) / t^2 dt

Now, we can simplify the integrand:

L = ∫[1,b] (t^2 + 1 + 1/t^2) dt

L = ∫[1,b] (t^2 + 1) dt + ∫[1,b] 1/t^2 dt

Integrating each term separately:

∫(t^2 + 1) dt = (1/3)t^3 + t + C1

∫1/t^2 dt = -1/t + C2

Now, we can evaluate the definite integral from t = 1 to t = b:

L = [(1/3)b^3 + b] - [(1/3)(1)^3 + 1] - [-1/1 + 1/b]

L = (1/3)b^3 + b - 4/3 + 1 + 1 - 1/b

Simplifying further:

L = (1/3)b^3 + b - 1/b + 4/3

Therefore, the arc length of the curve c(t) = (√2t, 1/2 t^2, ln(t)), where 1 ≤ t, is given by (1/3)b^3 + b - 1/b + 4/3.

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Answer:

  ₹168 per hour

Step-by-step explanation:

The hourly rate at which Tamara is paid can be found by dividing her ₹1050 pay by the 6:15 hours that she worked.

We know there are 60 minutes in an hour, so the fraction of an hour represented by 15 minutes is ...

  (15 min)/(60 min/h) = (15/60) h = 1/4 h = 0.25 h

Added to the 6 whole hours Tamara worked, her pay is for 6.25 hours.

The pay per hour is found by dividing pay by hours.

  ₹1050/(6.25 h) = ₹168/h

Tamara's hourly rate of pay is ₹168 per hour.

good luck buddy rip if you dont get the question

The given statement "The median of a quantitative data set is always one of the individual data values" is false.

When a given data set is arranged in ascending order the observation which at the between of the data is the median of that data set. It is a value in the set whose left and right both have the same number of observations.

The given statement is not true, this is because the median is the mid-value of any data set.

Hence, the given statement "The median of a quantitative data set is always one of the individual data values" is false.

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