Neglecting drag, the cannonball's initial height, and its horizontal motion, the maximum height rise is 110.45 metres, the time it takes for the ball to rise is 4.7 seconds, and the overall flight duration is 9.4 seconds.
Equation:
A pupil propels a cannonball 47.0 metres per second vertically upward.
assuming that the acceleration brought on by gravity is 10 m/s2.
Using the equation U2 = 2gH, the cannonball's highest point will be determined.
where H is the height the cannonball reaches.
When all the figures are put together, 47*47 = 2*10*H
H = 110.45 metres.
The cannonball's ascent time would be given by t=(2H/g).
When all the values are put together, t = (2*110.45/10)t = 4.7 seconds.
The cannonball's total flight time, T, is equal to the sum of its rise and descent times.
The ratio of ascent to descent is time.
Time of ascension = 4.7 Seconds since there is no other acceleration present and it is motion under gravity.
T = 2×(time of ascent) (time of ascent)
9.4 seconds are equal to T = 2*4.7.
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which can occur in a physical change
Answer:
A physical change involves a change in physical properties. Examples of physical properties include melting, transition to a gas, change of strength, change of durability, changes to crystal form, textural change, shape, size, color, volume and density.
Explanation:
A carousel is (more or less) a disk of mass, 15,000 kg, with a radius of 6.14. What torque must be applied to create an angular acceleration of 0.0500 rad/s^2?round to 3 significant figures
(Plssss help me im suffering from severe brainrot)
To calculate the torque required to create an angular acceleration, we can use the formula:
Torque = Moment of Inertia × Angular Acceleration
The moment of inertia of a disk can be calculated using the formula:
Moment of Inertia = (1/2) × Mass × Radius^2
Given:
Mass = 15,000 kg
Radius = 6.14 m
Angular Acceleration = 0.0500 rad/s^2
First, calculate the moment of inertia:
Moment of Inertia = (1/2) × Mass × Radius^2
Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2
Next, calculate the torque:
Torque = Moment of Inertia × Angular Acceleration
Torque = Moment of Inertia × 0.0500 rad/s^2
Now, let's plug in the values and calculate:
Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2
Moment of Inertia ≈ 283,594.13 kg·m^2
Torque = 283,594.13 kg·m^2 × 0.0500 rad/s^2
Torque ≈ 14,179.71 N·m
Rounding to three significant figures, the torque required to create an angular acceleration of 0.0500 rad/s^2 is approximately 14,180 N·m.
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Select the correct answer. What is the electron configuration of an element with atomic number 15? A. B. O C. O D. OE. 15² 25² 2p6 1s² 2s² 2p 3s² 3p5 1s² 25² 2p 3s² 3p³ 1s² 25² 2p 3s² 1s² 2s² 2p 3p³ 3s² 3p¹
The electron configuration of an element with atomic number 15 is 3s² 3p⁵.
What is electronic configuration?The electron configuration of an element with atomic number 15 (which corresponds to the element phosphorus) can be determined by following the Aufbau principle and the Pauli exclusion principle. The Aufbau principle states that electrons occupy the lowest energy levels available, while the Pauli exclusion principle states that each orbital can hold at most two electrons with opposite spins.
What is energy level of phosphorus?Starting with the first energy level, we fill in the electrons for each subsequent energy level until we reach the 15 electrons of phosphorus: 1s² 2s² 2p⁶ 3s² 3p⁵
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12.
A hiker walks for 5km on a bearing of 053" true (North 53° East). She then turns and
walks for another 3km on a bearing of 107° true (East 17° South).
(a)
Find the distance that the hiker travels North/South and the distance that she travels
East/West on the first part of her hike.
The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.
This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.
Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.
The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.
Angles will always be expressed in degrees in the solution.
The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.
The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.
Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.
The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.
The angle between the two is (180 - 53 - 17) = 110 degrees.
The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.
Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.
Distance Travelled East/WestThe hiker walked East for the second part of the hike.
To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.
The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.
Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.
To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.
The angle between the second vector and the Eastern direction is 17 degrees.
Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.
The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.
Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
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Which feature is created when a block of rock dropped down in relation to the block of rock beside it?
Answer:
Which feature is created when a block of rock dropped down in relation to the block of rock beside it?
Explanation:
Grabens drop down relative to adjacent blocks and create valleys. Horsts rise up relative to adjacent down-dropped blocks and become areas of higher topography.
Draw and label a diagram of a pulley system with a velocity ratio of 5
Why is the weight of earth is 1 by 6 of the weight of moon?; How do you calculate your weight on the moon and earth?; What is the mass of a 6 kg object when it is brought to the moon that has a gravity that is 1/8 of that on earth?; What is the weight of a 30 kg object on earth?
Answer:
Below
Explanation:
weight = mass * g <==g is less on the moon, so your weight is less on the moon
to calculate weight, you have to use the g of the planet you are on
The MASS does not change....it will be 6kg on the moon or earth
Weight of 30 kg on earth = 30 * g = 30 * 9.81 = 294 N
Please I need help with this :(
three charged particals are located at the corners of an equil triangle shown in the figure showing let (q 2.20 Uc) and L 0.650
Problem 2 More Basketballs Use these values of initial position and initial velocity in the following questions.
Initial position: ___1.0___ m above ground
Initial velocity: ___6.3 __ m/s, up
Problem Try to answer the following questions:
(a) What is the maximum height above ground reached by the ball?
(b) What are the magnitude and the direction of the velocity of the ball just before it hits the ground?
Show Your Problem Solving
Steps: Show these below:
1) Draw a Sketch
2) Choose origin, coordinate direction
3) Inventory List – What is known?
4) Write the kinematics equation(s) and solution of Part (a):
5) Write the kinematics equation(s) and solution of Part (b):
We have that the the maximum height and magnitude and the direction of the velocity is mathematically given as
a)V=5.42m/s
b)
Magnitude=9.8m/s^2Direction =DownFrom the question we are told
Problem 2 More Basketballs Use these values of initial position and initial velocity in the following questions.
Initial position: ___1.0___ m above ground
Initial velocity: ___6.3 __ m/s, up
Motiona)Generally the equation for Motion is mathematically given as
\(S=ut+\frac{1}{2}at^2\\\\Therefore\\\\-1.5=0+0.5+\frac{1}{2}*9.8t^2\\\\t=0.55sec\\\\Therefore\\\\V^2=u^2+2as\\\\V^2=0^2+2*-9.8*(-1.5)\)
V=5.42m/sb)
Since whilst in air the gravitational force can only act on it
therefore
Acting in downward direction
its specs are
Magnitude=9.8m/s^2Direction =DownFor more information on Motion visit
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3. How did the light wave interact with the water? | I
Answer:
Refraction is another way that waves interact with matter. ... Waves bend as they enter a new medium because they start traveling at a different speed in the new medium. For example, light travels more slowly in water than in air. This causes it to refract when it passes from air to water or from water to air.
Explanation:
i hope this helps but if it doesnt im rlly srry :p
(A) Calculate the one temperature at which Fahrenheit and Celsius thermometers agree with each other.
(B) Calculate the one temperature at which Fahrenheit and Kelvin thermometers agree with each other.
Answer:
A) -40° C and -40° F
B) 574.25° K and 574.25° F
Explanation:
see attachment for calculation and explanation
that we odels, we 2. his type entists base tand somet of the real ents, we five elect period nd at particles a) Copy the table below into your books. b) In the first column, write down the names of the first 20 elements. c) Use the Periodic Table at the back of this book to complete the table. Element Symbol Number of Number of Number of protons electrons protons and neutrons Na V Number of neutrons The diagrams below show models of certain elements. a) Write down the number of protons, electrons and neutrons for each element. b) Identify each element. ents have number. Symbol for the Figure 11 Atomic information a Mass number and neutrons
The difference between an atom's mass number (A) and atomic number (Z) is equal to the number of neutrons.
1) H – Hydrogen - 1 proton, 1 electron, 0 neutrons
2) He – Helium - 2 protons, 2 electrons, 2 neutrons
3) Li – Lithium - 3 protons, 3 electrons, 4 neutrons
4) Be – Beryllium - 4 protons, 4 electrons, 5 neutrons
5) B – Boron - 5 protons, 5 electrons, 6 neutrons
6) C – Carbon - 6 protons, 6 electrons, 6 neutrons
7) N – Nitrogen - 7 protons, 7 electrons, 8 neutrons
8) O – Oxygen - 8 protons, 8 electrons, 8 neutrons
9) F – Fluorine - 9 protons, 9 electrons, 10 neutrons
10)Ne – Neon - 10 protons, 10 electrons, 10 neutrons
11) Na – Sodium - 11 protons, 11 electrons, 12 neutrons
12) Mg – Magnesium - 12 protons, 12 electrons, 12 neutrons
13) Al – Aluminium - 13 protons, 13 electrons, 14 neutrons
14) Si – Silicon - 14 protons, 14 electrons, 14 neutrons
15) P – Phosphorus - 15 protons, 15 electrons, 17 neutrons
16) S – Sulphur - 16 protons, 16 electrons, 16 neutrons
17) Cl – Chlorine - 17 protons, 17 electrons, 18 neutrons
18) Ar – Argon - 18 protons, 18 electrons, 22 neutrons
19) K – Potassium - 19 protons, 19 electrons, 20 neutrons
20) Ca – Calcium - 20 protons, 20 electrons, 28 neutrons
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You drop a ball from a window located on an upper floor of a building. It strikes the ground with speed v. You now repeat the drop, but you ask a friend down on the ground to throw another ball upward at speed v. Your friend throws the ball upward at the same moment that you drop yours from the window. At some location, the balls pass each other. Is this location.
Answer:
y = y₀ (1 - ½ g y₀ / v²)
Explanation:
This is a free fall problem. Let's start with the ball that is released from the window, with initial velocity vo = 0 and a height of the window i
y = y₀ + v₀ t - ½ g t²
y = y₀ - ½ g t²
for the ball thrown from the ground with initial velocity v₀₂ = v
y₂ = y₀₂ + v₀₂ t - ½ g t²
in this case y₀ = 0
y₂2 = v t - ½ g t²
at the point where the two balls meet, they have the same height
y = y₂
y₀ - ½ g t² = vt - ½ g t²
y₀i = v t
t = y₀ / v
since we have the time it takes to reach the point, we can substitute in either of the two equations to find the height
y = y₀ - ½ g t²
y = y₀ - ½ g (y₀ / v)²
y = y₀ - ½ g y₀² / v²
y = y₀ (1 - ½ g y₀ / v²)
with this expression we can find the meeting point of the two balls
plz solve 90-(3+9)∙7
Answer:
The answer is 6.
90 - (3+9) • 7
90 - (12) • 7
90 - 12 • 7
90 - 84
6
A boat is cruising in a straight line at a constant speed of 2.5 m/s when it is shifted into neutral. After coasting 14 mm the engine is engaged again, and the boat resumes cruising at the reduced constant speed of 1.5 m/s. Assuming constant acceleration while coasting,
a. How much time did it take for the boat to coast the 12 m?
b. What was the boat’s acceleration while it was coasting?
c. What was the speed of the boat when it had coasted for 6.0 m? Explain.
Answer:
Explanation:
a ) distance s = 12 m .
constant speed = 1.5 m/s
time taken to coast 12 m
= distance / speed
= 12 / 1.5 = 8 s
b ) initial velocity u = 2.5 m /s
final velocity v = 1.5 m /s
displacement s = 14 m
acceleration a = ?
v² = u² + 2 as
1.5² = 2.5² + 2 a x 14
a = - .1428 m /s²
= - 14.28 cm / s²
c )
v = ?
u = 2.5 m /s
s = 6 m
a = - .1428 m /s²
v² = u² - 2 as
= 2.5² - 2 x 6 x .1428
= 6.25 - 1.71
= 4.54
v = 2.13 m /s .
Determine the velocity of the bullet and block moving together after colloision.
The velocity of the bullet and block moving together after the collision is approximately 1.18 m/s.
We can use the principle of conservation of momentum to find the velocity of the bullet and block moving together after the collision. The principle of conservation of momentum states that the total momentum of a closed system is conserved before and after the collision, as long as there are no external forces acting on the system. In this case, the bullet and the block form a closed system, and we can assume that there are no external forces acting on them during the collision.
Before the contact, the bullet's momentum is:
p1 = m1 x v1 = 2 kg x 60 m/s = 120 kg m/s
where m1 is the mass of the bullet and v1 is its velocity before the collision.
The momentum of the block before the collision is:
p2 = m2 x v2 = 100 kg x 0 m/s = 0 kg m/s
where m2 is the mass of the block and v2 is its velocity before the collision.
Before the impact, the system's entire momentum is:
p = p1 + p2 = 120 kg m/s + 0 kg m/s = 120 kg m/s
Following the contact, the bullet and block move at the same speed, v. After the collision, the system has the following mass:
m = m1 + m2 = 2 kg + 100 kg = 102 kg
Following the collision, the system's overall momentum is:
p' = m x v
The total momentum prior to and following the impact is the same, in accordance with the conservation of momentum concept. As a result, we may set p = p' and find v:
p = p'
=> 120 kg m/s = 102 kg x v
=> v = 120 kg m/s / 102 kg
=> v ≈ 1.18 m/s
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An object is (starting at rest) begins to plummet towards the earth. Assuming it is in a vacuum, how fast is the object traveling after 5s?
Answer:
–50.96
Explanation:
The following data were obtained from the question:
Initial velocity (Vᵢ) = 0 m/s
Acceleration (a) = – 9.8 m/s²
Time (t) = 5.2 s
Final velocity (Vբ) =.?
Acceleration is simply defined as the change of velocity with time. Mathematically, it is expressed as:
Acceleration (a) = Final velocity (Vբ) – Initial velocity (Vᵢ) /Time (t) =
a = (Vբ – Vᵢ) / t
With the above formula, we can determine how fast the object is traveling after 5 s as follow:
Initial velocity (Vᵢ) = 0 m/s
Acceleration (a) = – 9.8 m/s²
Time (t) = 5.2 s
Final velocity (Vբ) =.?
a = (Vբ – Vᵢ) / t
– 9.8 = (Vբ – 0) / 5.2
– 9.8 = Vբ / 5.2
Cross multiply
Vբ = –9.8 × 5.2
Vբ = –50.96 m/s
Therefore, the object is traveling at
–50.96 m/s
Three packing crates of masses, M1 = 6 kg, M2 = 2 kg and M3 = 8 kg are connected by a light string of negligible mass that passes over the pulley as shown. Masses M1 and M3 lies on a 30o incline plane which slides down the plane. The coefficient of kinetic friction on the incline plane is 0.28. A. Draw a free body diagram of all the forces acting in the masses M1 and M2. B. Determine the tension in the string that connects M2 and M3.
Answer:
39.81 N
Explanation:
I attached an image of the free body diagrams I drew of crate #1 and #2.
Using these diagram, we can set up a system of equations for the sum of forces in the x and y direction.
∑Fₓ = maₓ
∑Fᵧ = maᵧ
Let's start with the free body diagram for crate #2. Let's set the positive direction on top and the negative direction on the bottom. We can see that the forces acting on crate #2 are in the y-direction, so let's use Newton's 2nd Law to write this equation:
∑Fᵧ = maᵧ T₁ - m₂g = m₂aᵧNote that the tension and acceleration are constant throughout the system since the string has a negligible mass. Therefore, we don't really need to write the subscripts under T and a, but I am doing so just so there is no confusion.
Let's solve for T in the equation...
T₁ = m₂aᵧ + m₂gT₁ = m₂(a + g)We'll come back to this equation later. Now let's go to the free body diagram for crate #1.
We want to solve for the forces in the x-direction now. Let's set the leftwards direction to be positive and the rightwards direction to be negative.
∑Fₓ = maₓ F_f - F_g sinΘ = maₓThe normal force is equal to the x-component of the force of gravity.
(F_n · μ_k) - m₁g sinΘ = m₁aₓ (F_g cosΘ · μ_k) - m₁g sinΘ = m₁aₓ [m₁g cos(30) · 0.28] - [m₁g sin(30)] = m₁aₓ [(6)(9.8)cos(30) · 0.28] - [(6)(9.8)sin(30)] = (6)aₓ [2.539595871] - [-58.0962595] = 6aₓ 60.63585537 = 6aₓ aₓ = 10.1059759 m/s²Now let's go back to this equation:
T₁ = m₂(a + g)We have 3 known variables and we can solve for the tension force.
T = 2(10.1059759 + 9.8)T = 2(19.9059759)T = 39.8119518 NThe tension force is the same throughout the string, therefore, the tension in the string connecting M2 and M3 is 39.81 N.
“Which of the following are scientific facts?”
E Many diseases are caused primarily by microorganisms too small to be seen with the naked eye.
All objects in the universe are attracted to one another through the force of gravity.
Species evolve through the process of natural selection.
The air we breath on Earth is mostly nitrogen
Tin expands as it is heated.
Water boils at 100°C.
1 nts
Answer:
Disease are caused by micro organisms
All objects in the universe are attracted to one another
species evolved through natural selection
The scientific facts from the given list are,
Microorganisms that are too tiny to be seen with the bare eye are the primary cause of many illnesses.
The force of gravity draws all objects in the cosmos toward one another.
Natural selection is the process through which species change.
What is science?Science is the methodical, empirically-based pursuit and application of knowledge and understanding of the natural and social worlds.
Microorganisms that are too tiny to be seen with the bare eye are the primary cause of many illnesses.
The force of gravity draws all objects in the cosmos toward one another.
Natural selection is the process through which species change.
Therefore options A, B, and C are scientific facts.
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What is the rms speed of oxygen molecule at a pressure of 3.9x104
Pa if it has a
density of 1.3kg/m3
The root-mean-square speed of an oxygen molecule at a pressure of 3.9 x 10^4 Pa and a density of 1.3 kg/m^3 is approximately 6.13 x 10^-9 m/s.
What is the rms speed?The root-mean-square (rms) speed of an oxygen molecule can be calculated using the ideal gas law and the definition of density.
The ideal gas law states:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
Rearranging the ideal gas law to solve for the rms speed (v) gives:
v = sqrt(3 * P / (density * N))
where P is the pressure, density is the density of the gas, and N is Avogadro's number (6.022 x 10^23 molecules/mol).
Given:
Pressure (P) = 3.9 x 10^4 Pa
Density = 1.3 kg/m^3
We can substitute these values into the formula to calculate the rms speed of an oxygen molecule.
v = sqrt(3 * (3.9 x 10^4) / (1.3 * (6.022 x 10^23)))
v = sqrt(3.77 x 10^-18 m^2/s^2)
v ≈ 6.13 x 10^-9 m/s
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Calculate the pressure exerted by a 4000N camel on the sand. The camel’s feet have a
surface area of 2m2
.
Answer:
The pressure exerted by camel feet is 2000 N/m².
Step-by-step explanation:
Solution :Here, we have given that ;
Force applied on camel feet = 4000 NTotal area of camel feet = 2 m²We need to find the pressure exerted by camel feet.
As we know that :
\({\longrightarrow{\pmb{\sf{Pressure= \dfrac{Area}{Force}}}}}\)
Substituting all the given values in the formula to find the pressure exerted by camel feet.
\( \begin{gathered} \begin{array}{l} {\longrightarrow{\sf{Pressure= \dfrac{Area}{Force}}}} \\ \\ {\longrightarrow{\sf{Pressure= \dfrac{4000}{2}}}} \\ \\ {\longrightarrow{\sf{Pressure= \cancel{\dfrac{4000}{2}}}}} \\ \\ {\longrightarrow{\sf{Pressure= 2000 \: N/{m}^{2}}}} \\ \\\star \: \small\underline{\boxed{\sf{\purple{Pressure= 2000 \: N/{m}^{2}}}}} \end{array}\end{gathered}\)
Hence, the pressure exerted by camel feet is 2000 N/m².
\(\rule{300}{2.5}\)
Where do daughter cells obtain their dna
Answer:
The parent cell
Explanation:
Answer
Mitosis phase - The DNA in the parent cell nucleus makes a copy of itself and is then split between the two daughter cells during mitosis
Explanation
This is biology, not really physics.
An object falls freely from rest on a planet
where the acceleration due to gravity is
29 m/s ^2
After 3.8 s, what will be its speed?
Answer in units of m/s.
Answer:
v=u+gt , initially u=0 and g acting in the direction of movement of body.
v=0+9.8×2
v=19.6m/s
Explanation:
sorry i dont have exact answer but hope this above equation will help you ....♡
Animals conduct_______.
A. cellular respiration
B. photosynthesis
C. both cellular respiration and photosynthesis
QUESTION 1 Linear Motion
(a) A small coin is dropped from the height of the Spire in Dublin's city centre, a height of 120 metres.
(i) Calculate the speed of the coin just bạfore it hits the ground. Be sure to show all your work.
(ii) Is your calculated speed realistic? Explain your answer.
Explain the answer please
Answer:
48.51ms / 174.6 km/h
Explanation:
y = 1/2 x g x t^2 v = g x t
when y = 120m
120 = 1/2 x 9.8 x t^2
t^2 = 24.49
t = 4.95s
when t = 4.95s
v = 9.8 x 4.95
v = 48.51 m/s = 174.6 km/h
I'd say its realistic. But I don't really know that sry
Based on the diagram, why does the lightbulb light when the loop rotates, and what is the energy change involved?
When the wire moves in an electric field, electrons in the wire move and become mechanical energy. The mechanical energy causes the light to glow. Electrical energy used to rotate the loop is converted to light energy.
When the wire moves in an electric field, electrons in the wire move and become mechanical energy. The mechanical energy causes the light to glow. Electrical energy used to rotate the loop is converted to light energy.
When the wire moves in a magnetic field, electrons in the wire move and become an electric current. The current causes the light to glow. Mechanical energy used to rotate the loop is converted to electrical energy.
When the wire moves in a magnetic field, electrons in the wire move and become an electric current. The current causes the light to glow. Mechanical energy used to rotate the loop is converted to electrical energy.
When the wire moves in an electric field, electrons in the wire move and become mechanical energy. The mechanical energy causes the light to glow. Mechanical energy used to rotate the loop is converted to electrical energy.
When the wire moves in an electric field, electrons in the wire move and become mechanical energy. The mechanical energy causes the light to glow. Mechanical energy used to rotate the loop is converted to electrical energy.
When the wire moves in a magnetic field, electrons in the wire move and become an electric current. The current causes the light to glow. Mechanical energy used to rotate the loop is converted to light energy.
Answer:
Based on the information provided, the lightbulb lights when the loop rotates because the movement of the wire in an electric or magnetic field causes electrons in the wire to move and become either mechanical energy or an electric current. This energy causes the light to glow. The energy change involved is the conversion of electrical or mechanical energy used to rotate the loop into either light or electrical energy
Explanation:
The setup time of a clocked flip-flop is:
A) The minimum amount of time that an input must remain stable after an active clock
transition.
B) The maximum amount of time that an output must remain stable after an active clock
transition.
C) The minimum amount of time that an output must remain stable before an active clock
transition.
D) The minimum amount of time that an input must remain stable before an active clock
transition.
The setup time of a clocked flip-flop is:
The minimum amount of time that an output must remain stable before an active clock transition.
What is a Flip flop ?A flip-flop is a device that can hold a single bit of data (a binary digit); one of its two states corresponds to a "one," and the other to a "zero." Such data storage can be used to store state, and in electronics, such a circuit is known as sequential logic.
The output state changes of a timed flip-flop can be synced to a clock pulse thanks to an additional input.
Data must be at a valid logic level at setup time (tS), which is defined as the time before the DAC clock shift.
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About the four terrestrial planets (Earth, Mars, Mercury, and Venus), which of the following statements is NOT correct?A. The orbital periods of the four planets in order from shortest to longest are: Mercury, Venus, Earth, and MarsB. The distances from the Sun for the four planets in order from closet to farthest are: Mercury, Venus, Earth, and MarsC. The four planets all have mantle, core, and stable atmospheric layersD. The four planets in order from smallest to biggest are: Mercury, Mars, Venus, and Earth
All four planets contain stable atmospheric layers, a mantle, and a core. One of the following is FALSE regarding the four terrestrial planets (Earth, Mars, Mercury, and Venus).
Which of the following traits do the four terrestrial planets share?Terrestrial planets include Mercury, Venus, Earth, and Mars because of their compact, stony surfaces that resemble terra firma on Earth. The four innermost planets in the solar system are the four terrestrial planets.
What are the four features of planets that are terrestrial?The four innermost planets are known to as terrestrial planets and feature a moon or moons, valleys, volcanoes, and craters. They also have a liquid heavy-metal core.
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13. How much work do you need to do if you use a force of 5 Newtons to move a table 10 meters?
O 0.5 N-m
O 50 N-m
O 2 N-m
O 500 N-m
Answer:
50 N-m
Explanation:
5 N-m x 10 N-m = 50 N-m
Answer:
50 n-m
Explanation:
If the rest mass of a proton is 1.67 x 10^-27 kg, what is its mass when
traveling at 0.85 c?
The mass of the proton at the given speed is 2.78 x 10⁻²⁷ kg.
What is the mass of the proton at the given speed?The mass of the proton at the given speed of is calculated by applying the following equation.
Mathematically, the equation relating the mass of the proton and the rest mass is calculated as follows;
m = ( M₀ ) / (√ ( 1 - v² / c² )
where;
M₀ is the rest mass of the protonm is the mass of the protonv is the speed of the protonc is the speed of lightThe given parameters include;
rest mass of the proton = 1.67 x 10⁻²⁷ kgthe speed of light = cthe speed of the proton, v = 0.8cThe mass of the proton at the given speed is calculated as follows;
m = ( M₀ ) / (√ ( 1 - v² / c² )
m = ( M₀ ) / (√ ( 1 - (0.8c)² / c² )
m = M₀ / 0.6
m = 1.67 x 10⁻²⁷ kg / 0.6
m = 2.78 x 10⁻²⁷ kg
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