Answer:
$15.39
Step-by-step explanation:
You just subract
$64.25 - $48.86
Answer:
15.39
Step-by-step explanation:
$64.25
- 48.86
-------------
$15.39
How many 1/9's in 31
There are a total of 279 1/9s in 31.
What is simplification?Simplifying procedures is one way to achieve uniformity in job efforts, expenses, and time. It reduces diversity and variation that is pointless, harmful, or unneeded. Parenthesis, exponents, multiplication, division, addition, and subtraction are all referred to as PEMDAS. The order of the letters in PEMDAS informs you what to calculate first, second, third, and so on, until the computation is finished, given two or more operations in a single statement.
To find out how many 1/9's are in 31, you can divide 31 by 1/9.
This can be simplified by converting the division of a fraction to multiplication with its reciprocal:
31 ÷ (1/9) = 31 × (9/1)
Simplifying the expression on the right side gives:
31 × 9 = 279
So there are 279, 1/9's in 31.
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Help asap if you get it right ill give 30 points no cap. Zach created a blueprint using only similar parallelograms.
Which statement about the parallelograms must be true?
The parallelograms have corresponding angles that are not congruent.
The parallelograms have corresponding sides that are congruent.
The parallelograms have proportional corresponding sides.
The parallelograms all have congruent sides and angles.
Answer: Hello!
Step-by-step explanation:
Your answer would be D :)
James wants to have earned $6,180 amount of interest in 28 years. Currently he finds
that his annual interest rate is 6.12%. Calculate how much money James needs to invest
as his principal in order to achieve this goal.
Answer:
$3606.44
Step-by-step explanation:
The question asks us to calculate the principal amount that needs to be invested in order to earn an interest of $6180 in 28 years at an annual interest rate of 6.12%.
To do this, we need to use the formula for simple interest:
\(\boxed{I = \frac{P \times R \times T}{100}}\),
where:
I = interest earned
P = principal invested
R = annual interest rate
T = time
By substituting the known values into the formula above and then solving for P, we can calculate the amount that James needs to invest:
\(6180 = \frac{P \times 6.12 \times 28}{100}\)
⇒ \(6180 \times 100 = P \times 171.36\) [Multiplying both sides by 100]
⇒ \(P = \frac{6180 \times 100}{171.36}\) [Dividing both sides of the equation by 171.36]
⇒ \(P = \bf 3606.44\)
Therefore, James needs to invest $3606.44.
Billy took 5 tests in his math class. He scored an 89,88,93,90 and 81. What is the variance of his grades in these test? If necessary, round to the nearest hundredth.
The variance of Billy's grades obtained from his test scores is 15.76
What is variance?The variance is a measure of variability or spread a dataset. The variance can be calculated from the sum of the square of the differences of the data points from the mean divided by the number or count of the data points.
The variance of Billy's test scores can be calculated by finding the mean or the average of the scores, then finding the sum of the squares of the differences of each score from the mean as follows;
The mean score = (89 + 88 + 93 + 90 + 81)/5 = 88.2
The square of the differences of the values from the mean can be calculated as follows;
(89 - 88.2)² = 0.64, (88 - 88.2)² = 0.04, (93 - 88.2)² = 23.04, (90 - 88.2)² = 3.24, and (81 - 88.2)² = 51.84
The sum of the square of the differences is therefore;
0.64 + 0.04 + 23.04 + 3.24 + 51.84 = 78.8
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As the CAPS document outlines, the Content Specification and Content Clarification for Patterns, Functions, and Algebra shows sequenced mathematics content topics and a content area spread. In the Intermediate Phase, select one topic and report on the topic sequence and content area spread. Your report should demonstrate mathematics concepts and procedures’ hierarchical and logical progression.
Answer:
Step-by-step explanation:
In the Intermediate Phase of mathematics education, one topic that demonstrates a hierarchical and logical progression in patterns, functions, and algebra is the concept of "Linear Equations."
The topic of Linear Equations in the Intermediate Phase builds upon the foundation laid in earlier grades and serves as a stepping stone towards more advanced algebraic concepts. Here is an overview of the topic sequence and content area spread for Linear Equations:
Introduction to Variables and Expressions:
Students are introduced to the concept of variables and expressions, learning to represent unknown quantities using letters or symbols. They understand the difference between constants and variables and learn to evaluate expressions.
Solving One-Step Equations:
Students learn how to solve simple one-step equations involving addition, subtraction, multiplication, and division. They develop the skills to isolate the variable and find its value.
Solving Two-Step Equations:
Building upon the previous knowledge, students progress to solving two-step equations. They learn to perform multiple operations to isolate the variable and find its value.
Writing and Graphing Linear Equations:
Students explore the relationship between variables and learn to write linear equations in slope-intercept form (y = mx + b). They understand the meaning of slope and y-intercept and how they relate to the graph of a line.
Systems of Linear Equations:
Students are introduced to the concept of systems of linear equations, where multiple equations are solved simultaneously. They learn various methods such as substitution, elimination, and graphing to find the solution to the system.
Word Problems and Applications:
Students apply their understanding of linear equations to solve real-life word problems and situations. They learn to translate verbal descriptions into algebraic equations and solve them to find the unknown quantities.
The content area spread for Linear Equations includes concepts such as variables, expressions, equations, operations, graphing, slope, y-intercept, systems, and real-world applications. The progression from simple one-step equations to more complex systems of equations reflects a logical sequence that builds upon prior knowledge and skills.
By following this hierarchical progression, students develop a solid foundation in algebraic thinking and problem-solving skills. They learn to apply mathematical concepts and procedures in a systematic and logical manner, paving the way for further exploration of patterns, functions, and advanced algebraic topics in later phases of mathematics education.
Use the commutative property to write an expression 8c-1.5
Answer:
Step-by-step explanation:
i need help on that too
the cost of a new car is $32,000 it depreciates at a rate of 15% per year . this means that it loses 15% of each value each year
The mathematical function describing the cost of car the next year is →
C{n + 1} = C{n} (1 - 3/20).
What is depreciation rate?The depreciation rate is a rate at which the price of a quantity decreases every year.
Given is that the cost of a new car is $32,000 it depreciates at a rate of 15% per year.
We can understand it as follows.
After one year the cost would be -
{x} = 32000 - {15% of 32000}
{x} = 32000 - 4800
{x} = $27200
After second year the cost would be -
{x} = 27200 - {15% of 27200}
{x} = 27200 - 4080
{x} = $23120
This means that after every year, the value decrease by 15% of what it was a year before. We can write -
C{n + 1} = C{n} - (15/100) C{n}
C{n + 1} = C{n} (1 - 3/20)
Therefore, the mathematical function describing the cost of car the next year is →
C{n + 1} = C{n} (1 - 3/20).
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4x10 26 [87.96 x 10 6]
Answer:
remember that you start in the [ ] and work your way out
Step-by-step explanation:
All the fourth-graders in a certain elementary school took a standardized test. A total of 82% of the students were found to be proficient in reading, 74% were found to be proficient in mathematics, and 65% were found to be proficient in both reading and mathematics.A student is chosen at random. What is the probability that the student is proficient in neither reading nor mathematics
Answer:
0.09 = 9% probability that the student is proficient in neither reading nor mathematics
Step-by-step explanation:
We solve this question treating the events as Venn probabilities.
I am going to say that:
Event A: A student is proficient in reading.
Event B: A student is proficient in mathematics.
A total of 82% of the students were found to be proficient in reading
This means that \(P(A) = 0.82\)
74% were found to be proficient in mathematics
This means that \(P(B) = 0.74\)
65% were found to be proficient in both reading and mathematics.
This means that \(P(A \cap B) = 0.65\)
What is the probability that the student is proficient in neither reading nor mathematics?
This is:
\(P = 1 - P(A \cup B)\)
In which
\(P(A \cup B) = P(A) + P(B) - P(A \cap B)\)
With the values that we have:
\(P(A \cup B) = 0.82 + 0.74 - 0.65 = 0.91\)
Then
\(P = 1 - P(A \cup B) = 1 - 0.91 = 0.09\)
0.09 = 9% probability that the student is proficient in neither reading nor mathematics
2x + 2 = 5x -8 simplify
Two car services charge different rates. A charges .60 per mile plus 3.00initial charge B charges .75 per mile mile traveled . the situation is modeled bu this system where x is the number of miles traveled and y is the charge for that distance ,in cents. How many miles must each car travel for the charges to be equal and ehat is the charge for that distance
The charges will be equal when each car travels 2000 miles. To find the charge for that distance, we substitute x = 2000 into either equation.
To determine the number of miles at which the charges for the two car services, A and B, are equal, we can set up an equation based on the given information.
Let's represent the charge for car service A as y_A and the charge for car service B as y_B. We can set up the following equations:
For car service A: y_A = 0.60x + 300 (in cents)
For car service B: y_B = 0.75x (in cents)
To find the number of miles at which the charges are equal, we set y_A equal to y_B and solve for x:
0.60x + 300 = 0.75x
Subtracting 0.60x from both sides:
300 = 0.15x
Dividing both sides by 0.15:
x = 300 / 0.15
x = 2000
Therefore, the charges will be equal when each car travels 2000 miles. To find the charge for that distance, we substitute x = 2000 into either equation. Let's use the equation for car service A:
y_A = 0.60(2000) + 300
y_A = 1200 + 300
y_A = 1500 cents or $15.00
So, when each car travels 2000 miles, the charges will be equal at $15.00.
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A pizza shop delivered 17 pepperoni pizzas to a college on the first night of final exams. The total cost of the pizzas was $189.
A small pizza costs $3 and contains 2 ounces of pepperoni. A medium pizza costs $11 and contains 6 ounces of pepperoni. A large pizza costs $13 and contains 12 ounces of pepperoni.
The owner of the pizza shop used 9 pounds 4 ounces of pepperoni in making the 17 pizzas. How many pizzas of each size were delivered to the coll
6 small sizes, 3 medium sizes, and 7 large size pizzas were delivered.
What is a system of equations?
A system of linear equations is a set of two or more linear equations involving the same variables. The variables represent unknown quantities that we want to find, and the linear equations are mathematical statements that describe the relationships between these variables.
Let a = number of small pizzas delivered
Let b = number of medium pizzas delivered
Let c= number of large pizzas delivered
(1) a + b + c = 16
(2) 4a + 9b + 11c = 128
(3) 3a + 5b + 10c = 6 * 16 + 7
--------------------------------------------
(3) 3a + 5b + 10c = 103
Multiply both sides of (1) by 3
and subtract (1) from (3)
(3) 3a + 5b + 10c = 103
(1) - 3a - 3b - 3c = - 48
--------------------------------------------
2b + 7c = 55
---------------------------------------
Multiply both sides of (1) by 4
and subtract (1) from (2)
(2) 4a + 9b + 11c = 128
(1) - 4a - 4b - 4c = - 64
5b + 7c = 64
Subtract:
5b + 7c = 64
- 2b - 7c = - 55
3b = 9
b = 3
and,
5 * 3 + 7c = 64
7c = 64 - 15
7c = 49
c = 7
(1) a + b + c = 16
(1) a + 3 + 7 = 16
(1) a = 6
Hence, 6 small sizes, 3 medium sizes, and 7 large size pizzas were delivered.
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Does 17 divide each of these numbers?
a)68 b) 84 c) 357 d) 1001
Hello !
68/17 = 4
=> yes for 68
84/17 = 4.941...
=> no for 84
357/17 = 21
=> yes for 357
1001/17 = 58.882...
=> no for 1001
The lifespan of a car battery averages six years. Suppose the batterylifespan follows an exponential distribution.(a) Find the probability that a randomly selected car battery will lastmore than four years.(b) Find the variance and the 95th percentile of the battery lifespan.(c) Suppose a three-year-old battery is still going strong. (i) Find theprobability the battery will last an additional five years. (ii) Howmuch longer is this battery expected to last
Answer:
Step-by-step explanation:
Let X denote the life span of a car battery and it follows and exponential distribution with average of 6 years.
Thus , the parameter of the exponential distribution is calculated as,
μ = 6
\(\frac{1}{\lambda} =6\)
\(\lambda = \frac{1}{6}\)
a) The required probability is
\(P(X>4)=1-P(X\leq 4)\\\\=1-F(4)\\\\1-(1-e^{- \lambda x})\\\\=e^{-\frac{4}{6}\)
= 0.513
Hence, the probability that a randomly selected car battery will last more than four years is 0.513
b) The variance of the battery span is calculated as
\(\sigma ^2=\frac{1}{(\frac{1}{\lambda})^2 }\\\\\sigma ^2=\frac{1}{(\frac{1}{6})^2 } \\\\=6^2=36\)
The 95% percentile \(x_{a=0.05}\) (α = 5%) of the battery span is calculated
\(x_{0.05}=-\frac{log(\alpha) }{\lambda} \\\\=-\frac{log(0.05)}{1/6} \\\\=-6log(0.05)\\\\=17.97 \ years\)
c)
Let \(X_r\) denote the remaining life time of a car battery
i)the probability the battery will last an additional five years is calculated below
\(P(X_r>5)=e^{-5\lambda}\\\\=e^{-\frac{5}{6} }\\\\=0.4346\)
ii) The average time that the battery is expected to last is calculated
\(E(X_r)=\frac{1}{\lambda} \\\\=6\)
En cierto laboratorio se cultiva la cepa de una bacteria, causal de múltiples problemas. Con fin de determinar la rapidez de reproducción de dicha bacteria, esta se coloca en un medio de crecimiento y condiciones favorables. La población existente es de 250 bacterias y se observa que cada hora se duplica la cantidad
The exponential function giving the number of bacteria after x hours is given as follows:
\(y = 250(2)^x\)
How to define an exponential function?An exponential function has the definition presented according to the equation as follows:
\(y = ab^x\)
In which the parameters are given as follows:
a is the value of y when x = 0.b is the rate of change.The parameter values for this problem are given as follows:
a = 250, b = 2.
Hence the function is given as follows:
\(y = 250(2)^x\)
Missing InformationThe problem asks for the exponential function giving the number of bacteria after x hours is given as follows:
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Samantha makes $8.00 an hour babysitting. With the money Samantha earns babysitting, she plans to buy herself a MP3 player that costs $154.00.
Which inequality represents the number of hours Samantha would have to babysit in order to have enough money to buy the MP3 player?
A youth group takes a bus to the movie theater. The cost of a drink is $2.25, the cost of popcorn is $3.45, and the cost of a ticket is $7.00. Each student gets a ticket, a drink, and popcorn. The bus rental costs $100.
If the total cost of the trip is $252.40, how many people went?
Sandra surveyed 15 of her friends to find the number of badges and stickers they owned.
Based on the distribution of data, which observation is correct?
The mean number of stickers is about 1.3 times the mean number of badges.
The mean number of stickers is about 1.3 times the mean number of badges.
The mean number of stickers is about 0.78 times the mean number of badges.
The mean number of stickers is about 0.78 times the mean number of badges.
The mean number of badges is greater than the mean number of stickers because the tallest column is farther right.
The mean number of badges is greater than the mean number of stickers because the tallest column is farther right.
The median number of badges is greater than the median number of stickers because the tallest column is farther right.
The median number of badges is greater than the median number of stickers because the tallest column is farther right.
Answer:
8h ≥ 154
Step-by-step explanation:
Mark me Brainllest
Solve for angles x and y in the triangle below. Round your angle to the nearest whole degree.
Solve for both x and y
\(\tan(y )=\cfrac{\stackrel{opposite}{6}}{\underset{adjacent}{4}} \implies \tan( y )= \cfrac{3}{2} \implies \tan^{-1}(~~\tan( y )~~) =\tan^{-1}\left( \cfrac{3}{2} \right) \\\\\\ y =\tan^{-1}\left( \cfrac{3}{2} \right)\implies y \approx 56.31^o \\\\[-0.35em] ~\dotfill\\\\ \tan(x )=\cfrac{\stackrel{opposite}{4}}{\underset{adjacent}{6}} \implies \tan( x )= \cfrac{2}{3} \implies \tan^{-1}(~~\tan( x )~~) =\tan^{-1}\left( \cfrac{2}{3} \right) \\\\\\ x =\tan^{-1}\left( \cfrac{2}{3} \right)\implies x \approx 33.69^o\)
Make sure your calculator is in Degree mode.
Misty wants to save money to purchase a new bicycle that costs $279. She
opens a savings account and deposits $7 per week. How many weeks will it
take for her to save enough money to buy the bicycle?
Answer: Hmm, I want to say it will be about 40 weeks before she can get the bike, hope this helps!
Step-by-step explanation:
Answer:
40 weeks
Step-by-step explanation:
Grade level and gender Describing the sampling distribution of ħi - Pz PROBLEM: In a very large high school, the junior class has 800 students, 54% of whom are female. The senior class has 700 students, 49% of whom are female. The student council selects a random sample of 40 juniors and a separate random sample of 35 seniors. Let P, - ., be the difference in the sample proportions of females. (a) What is the shape of the sampling distribution of p,, - P..? Why? (b) Find the mean of the sampling distribution. (c) Calculate and interpret the standard deviation of the sampling distribution.
The size of sample are both large enough 40 and 35. The mean and standard deviation of given data is 0.05 and 0.105 respectively.
The shape of the sampling distribution of \(\hat{p}_j - \hat{p}_s\)is approximately normal, according to the Central Limit Theorem. This is because the sample sizes are both large enough (40 and 35, respectively) and the population proportions are unknown but assumed to be independent.
The mean of the sampling distribution is the difference in the population proportions of females, which is 0.54 - 0.49 = 0.05.
The standard deviation of the sampling distribution can be calculated as:
\($\sqrt{\frac{\hat{p}_j(1 - \hat{p}_j)}{n_j} + \frac{\hat{p}_s(1 - \hat{p}_s)}{n_s}}$\)
where \(\hat{p}_j = 0.54$, $n_j = 40$, $\hat{p}_s = 0.49$, and $n_s = 35$.\)Plugging in these values, we get:
\($\sqrt{\frac{0.54(1 - 0.54)}{40} + \frac{0.49(1 - 0.49)}{35}} \approx 0.105$\)
Interpretation: The standard deviation of the sampling distribution tells us how much we can expect the sample proportion difference to vary across different random samples. In this case, we can expect the difference between the sample proportions of females in the junior and senior classes to vary by about 0.105 on average across different samples.
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jaci welk is paid $11.95 an hour with time-and-a-half pay for all hours she works over 40 hours a week. last week she worked 45 1/2 hours.
how many over time hours did jaci worked?
what was her overtime rate?
what was her overtime pay?
Answer:
Number of hours worked overtime = 5.5 hours
overtime rate = $17.925 per hour
overtime pay = $98.59
Step-by-step explanation:
a. Her overtime hours are the number of hours worked over 40 hours, and we are told that she worked 45 1/2 hours last week.
Therefore, her overtime hours = 45.5 - 40 = 5.5 hours
b. overtime rate:
for her overtime rate, we are given that she has a time-and-a-half pay for her overtime hours. This means that she is paid 1.5 times the normal rate for working overtime.
∴ overtime rate = 1.5 × normal rate
overtime rate = 1.5 × 11.95/hour
overtime rate = $17.925/hour
c. overtime pay:
overtime pay = overtime rate × overtime hours worked
overtime pay = 17.925 × 5.5
overtime pay = $98.59
What is the measure of AEB?
For a géometric sequence, if a1=9 and a5
=2304, what is the value of r?
The value of common ration r is 4.
Given that,
a₁ = 9
a₅ = 2304
We know that,
A geometric sequence is a sequence in which each term (except from the first term) is multiplied by a fixed amount to obtain the following term.
The following term in the geometric sequence must be obtained by multiplying it by a set term (referred to as the common ratio), and the previous term in the sequence can be obtained by dividing it by the same common ratio.
Since we know that nth term of GP is,
\(a_{n}\) = a₁ \(r^{n-1}\)
Therefore,
a₅ = a₁ \(r^{4}\) = 2304
⇒ 9 x \(r^{4}\) = 2304
⇒ \(r^{4}\) = 256
⇒ r = 4
Hence, r = 4
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What is the answer to this please????
Answer:
your answer will be
y=40 x +20
Step-by-step explanation:
have a nice day/night ^_^
A bag has 4 blue marbles, 3 green marbles, and 5 red
marbles. You select 2 marbles one at a time without
replacement.
Determine the probability the first marble is blue and
the second marble is green Round your answer to
the hundredths place.
The probability of selecting a blue marble on the first draw and a green marble on the second draw is 0.09.
What is probability?
Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain to happen.
There are 12 marbles in total in the bag, so the probability of selecting a blue marble on the first draw is 4/12.
After the first marble is drawn, there are 11 marbles left in the bag, so the probability of selecting a green marble on the second draw, given that the first marble was blue and has already been removed, is 3/11.
To determine the probability of both events occurring together, we multiply the probabilities. Therefore, the probability of selecting a blue marble on the first draw and a green marble on the second draw is:
(4/12) * (3/11) = 0.0909
Rounding to the hundredth place, the probability is approximately 0.09.
Therefore, the probability of selecting a blue marble on the first draw and a green marble on the second draw is 0.09.
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is the $4,250 his total he started with or how do we find what he started with!!
Answer:
To find net worth, add all assets seperately. Then add the liabilities. Subtract the assests and liabilities to get your net worth.
It says he has $4,250 in his savings, so that's an assest. Due to the savings.
He already had that much, so you could say he started with it.
Step-by-step explanation:
Good luck! <3
Hoped that helped.
What is 25% of 50= please help
Answer:
answer 12.5
Step-by-step explanation:
25% of 50 is 12.5 because 50 ÷ 4 = 12.5 Hope that helps!
find perimeter of the figure.
Answer:
I don't know if you want to be a good
What is the test statistic for a hypothesis test where H0: μ=12.5, x¯¯¯=14.1, s=2.7, and n=12? Responses
The test statistic for the hypothesis test using the parameters is 2.05
A test statistic is used to access how consistent sample data are with the null hypothesis in a hypothesis test.
How to calculate test hypothesis of given parameters?
Using the parameters
Hₙ: ц=12.5, x=14.1, s=2.7, and n=12
The test statistic (t) is given by the formula
t=\(\frac{x-U}{s/\sqrt{n} }\)
Substituting the given parameters;
t=\(\frac{14.1-12.5}{2.7/\sqrt{12} }\)
t=\(\frac{1.6}{2.7/3.46}\)
t=\(\frac{1.6}{0.78}\)
t=2.05
This figure is round up to 2 decimal places
The test statistic using the parameters is 2.05
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Natalie's grandmother gave her $50 for her birthday. She also received gifts of $45,
$25,
and $30 from her three aunts. How much did she get for her birthday?
Tina's Beauty Salon charges $10 per haircut. If the salon has 52 visitors seeking haircuts per day, estimate
how much Tina would make in 5 days by rounding the number of visitors to the nearest ten.
Group of answer choices
$50
$2500
$500
$250
Answer:
2500
Step-by-step explanation:
$10 times 52 is $520 a day so multiply 520 times 5 and you get $2600 so round that and it is $2500