Answer:
B) Aerosol
The particles from the pigeon droppings are likely to be transmitted from the air vents directly into Martyn's respiratory system
Answer:
aerosol
Explanation:
22. A rock is thrown straight up with an initial velocity of 24.5 m/s. What maximum height will the rock reach before starting to fall downward? (Take acceleration due to gravity as 9.80 m/s².)
a. 9.80 m
b. 19.6 m
c. 24.5 m
d. 30.6 m
A river flows with a uniform velocity vr. A person in a motorboat travels 1.22 km upstream, at which time she passes a log floating by. Always with the same engine throttle setting, the boater continues to travel upstream for another 1.45 km, which takes her 69.1 min. She then turns the boat around and returns downstream to her starting point, which she reaches at the same time as the same log does. How much time does the boater spend traveling back downstream
Answer:
t ’= \(\frac{1450}{0.6499 + 2 v_r}\), v_r = 1 m/s t ’= 547.19 s
Explanation:
This is a relative velocity exercise in a dimesion, since the river and the boat are going in the same direction.
By the time the boat goes up the river
v_b - v_r = d / t
By the time the boat goes down the river
v_b + v_r = d '/ t'
let's subtract the equations
2 v_r = d ’/ t’ - d / t
d ’/ t’ = 2v_r + d / t
\(t' = \frac{d'}{ \frac{d}{t}+ 2 v_r }\)
In the exercise they tell us
d = 1.22 +1.45 = 2.67 km= 2.67 10³ m
d ’= 1.45 km= 1.45 1.³ m
at time t = 69.1 min (60 s / 1min) = 4146 s
the speed of river is v_r
t ’= \(\frac{1.45 \ 10^3}{ \frac{ 2670}{4146} \ + 2 \ v_r}\)
t ’= \(\frac{1450}{0.6499 + 2 v_r}\)
In order to complete the calculation, we must assume a river speed
v_r = 1 m / s
let's calculate
t ’= \(\frac{ 1450}{ 0.6499 + 2 \ 1}\)
t ’= 547.19 s
These ethical theories could endorse something like genocide under the right conditions: (Choose as many as you think are correct) Utilitarianism Cultural Relativism Egoism Natural Rights Theory Kantian Deontology
According to the utilitarian ethical theory, morality is decided by emphasising results.
This kind of consequentialism exists here. According to utilitarianism, a decision should be made if it would result in the greatest amount of benefit for the largest number of people. The utilitarian perspective holds that you should select the ice cream flavour that would make you feel the happiest if you are making a decision for yourself.
A variation of consequentialism known as utilitarianism holds that actions' results are the only criteria for what is right and bad. Utilitarianism takes into account the interests of every sentient being equally, unlike other consequentialist ideologies like egoism and altruism.
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convert -40⁰ c to Fahrenheit scale
Answer:
104f
Explanation:
(40°C × 9/5) + 32 = 104°F
The diagram below shows the velocity vectors for two cars that are moving
relative to each other.
45 m/s west
25 m/s east
Car 1
Car 2
From the frame of reference of car 1, what is the velocity of car 2?
OA. 20 m/s west
OB. 70 m/s east
C. 70 m/s west
D. 20 m/s east
The relative velocity of the car 2 with respect to car 1 is 70 m/s west. So, the correct option is C.
Velocity of the car 1 with respect to the ground, v₁ = 45 m/s west
Velocity of the car 2 with respect to the ground, v₂ = 25 m/s east
Let the direction towards the east be positive and the opposite direction towards the west be negative.
The expression for the relative velocity of the car 2 with respect to car 1 is given by,
v₂₁ = v₂ - v₁
v₂₁ = 25 - (-45)
Therefore, the relative velocity,
v₂₁ = 70 m/s west
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Attaching the image file here.
A car with a mass of 2,000 kg travels at 20 m/s. Which one has the greatest impulse?
Answer:2000kg
Explanation:
Convert it
The mass of an object is 10 kg and it is pushed with an acceleration of 4 m/s² ! calculate the force with which the object was pushed ~
\( \\ \)
Explanation:
Force=mass×acceleration
mass=10kg, acceleration=4m/s²
force=10×4=40N.
Find the velocity of a 1000kg car with 50,000J of KE.
Answer:
10 m/2²
Explanation:
v=t/d
blah blah blah
Answer:
10 m/s
Explanation:
Kinetic Energy = 1/2 m v^2
KE / ( 1/2 m) = v^2
then v = sqrt ( KE / (1/2 m ) = 10 m/s
three equal charges each of charge q is placed at the vertex of an equilateral triangle.Find the force exerted on any of them due the others.Take the length of sides of triangle to be equal to 1
The net force on the top charge due to the other two charges is zero, and the charge will remain in equilibrium.
What is net electric force?
We can use Coulomb's law to calculate the force exerted by one charge on another. Coulomb's law states that the magnitude of the electrostatic force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them.
Mathematically, it can be expressed as:
F = (kq1q2)/r^2
where;
F is the magnitude of the electrostatic force, q1 and q2 are the charges of the two point charges, r is the distance between them, and k is Coulomb's constant.In this case, we have three charges of equal magnitude q placed at the vertices of an equilateral triangle of side length 1. We can calculate the distance between any two charges using the geometry of the equilateral triangle. The distance between any two adjacent charges is 1, and the distance between any two opposite charges is √3.
Let's consider the force exerted on one of the charges, say the one at the top of the triangle, due to the other two charges at the bottom left and bottom right vertices. The distance between the top and bottom left charges is 1, and the distance between the top and bottom right charges is also 1.
Therefore, the magnitude of the force exerted by the bottom left charge on the top charge is:
F1 = (kqq)/1^2 = k*q^2
Similarly, the magnitude of the force exerted by the bottom right charge on the top charge is also k*q^2. Since the two forces are acting in opposite directions along the same line, we can simply subtract them to find the net force:
F_net = F1 - F2 = kq^2 - kq^2
F_net = 0
Therefore, the net force on the top charge due to the other two charges is zero, and the charge will remain in equilibrium.
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A sound wave is traveling with a frequency of 880Hz. It has a wavelength of 0.75. What is the speed of the sound wave
The speed of the sound wave is 660 meters per second.
To calculate the speed of the sound wave, we need to use the formula:
Speed = Frequency x Wavelength
Here, the frequency of the sound wave is given as 880Hz, and the wavelength is given as 0.75. To get the answer, we just need to plug these values into the formula and solve for the speed:
Speed = 880 x 0.75
Speed = 660 meters per second
It's important to note that the speed of sound depends on the medium through which it is traveling. In air, the speed of sound is approximately 343 meters per second at standard temperature and pressure. However, this value can change depending on factors such as temperature, humidity, and altitude.
Understanding the speed of sound is important in various fields, such as music, engineering, and physics. For example, in music, the speed of sound determines the pitch of a note, while in engineering, it can be used to design and optimize acoustic systems. In physics, it's used to study the properties of waves and to explain phenomena such as Doppler effect and sonic booms.
Therefore, the speed of the sound wave is 660 meters per second.
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Nora notices water droplets on the grass in the morning. It did not rain during the night. Which statement is true about this change of state?
Mass was added to the water particles, resulting in deposition.
Energy was added to the water particles, resulting in evaporation.
Mass was removed from the water particles, resulting in sublimation.
Energy was removed from the water particles, resulting in condensation.
Answer:
Mass was added to the water particles, resulting in deposition.
Explanation:
Answer: The energy was removed from the water particles resulting in condensation
Explanation Think about when you leave a cup of ice of and after a while you see water droplets thats what happened to the grass in the morning and thats called condensation.
Blue light (450 nm) and orange light
(625 nm) pass through a diffraction
grating with d = 2.88 x 10-6 m. What is
the angular separation between them
for m = 1?
Answer:
3.54
Explanation:
some nerd thing I found it on Yahoo answers
Answer:
3.54º
Explanation:
Find the blue θ first
sin⁻¹(540x10⁻⁹/2.88x10⁻⁶)=8.99°
Then find the orange θ
sin⁻¹(625x10⁻⁹/2.88x10⁻⁶)=12.53°
Take the differences and subtract
12.53°-8.99°=3.54°
At time t = 0 s, a puck is sliding on a horizontal table with a velocity 3.60 m/s, 35.0° above the +x axis. As the puck slides, a constant acceleration acts on it that has the following components: a = - 2 0.360 m/s and da, = -0.980 m/s. What is the velocity of the puck at time t = 1.50 s? 2 0
The velocity of the punk at time t = 1.5 s is equal to 2.47 m/s.
What are the components of velocity?The object will have two velocities during the projectile motion, one is horizontal velocity and the other is vertical velocity. The horizontal velocity of the object is constant throughout the projectile motion but the vertical velocity is changed in the projectile motion.
Given that the velocity vector is making an angle θ with a horizontal table, θ = 35°
The vertical component of the velocity of the puck can be determined as:\(u_x = u Sin 35^o = 3.60 \times 0.573 =2.06 m/s\)
The horizontal component of the velocity of the puck can be determined as:
\(u_y = u cos 35^o = 3.60 \times 0.82=2.95 m/s\)
Given the acceleration aₓ = -0.360 m/s² and a y = -0.980 m/s²
The final vertical components of the velocity of the punk are:
\(v_x = u_x + a_xt\)
\(v_x = 2.95 - (0.360) (1.5)\\v_x = 2.41 m/s\)
and, the horizontal velocity of the punk is:
\(v_y = u_y +a_yt\\v_y = 2.06 - (0.980) (1.5)\\v_y = 0.59 m/s\)
The velocity of the punk can be determined as:
\(v = \sqrt{v_x^2 + v_y ^2}\\ v =\sqrt{(5.80)^2 + (0.35)^2}\\ v = 2.47 m/s\)
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Problem B.2: Escaping a Star (6 Points) It takes many years for a photon produced in a star's centre to reach its surface and escape into space. This is due to its constant interaction with other particles. To estimate the time it takes for a photon to escape a star's interior, we assume that the photon is deflected in equal time intervals into a random direction in a two-dimensional space (i.e., a random walk): At each step i, the photon moves a constant distance in an angle, thus changing its position: cos(4) sin(y) Ai, - c (a) Determine the distance R(n) from the centre (0,0) after n steps.
Answer:
This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.
The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.
The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).
The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:
R(n) = √(X² + Y²)
Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.
However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:
<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2
<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2
Because <X²> = <Y²>, we can write:
<R²> = <X²> + <Y²> = n A²
So, the root mean square distance (the square root of the mean square displacement) after n steps is:
R(n) = √(<R²>) = √(n) * A
Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.
reviews the general principles in this problem. A projectile is launched from ground level at an angle of 13.0 ° above the horizontal. It returns to ground level. To what value should the launch angle be adjusted, without changing the launch speed, so that the range doubles?
Answer: θ would equal approximately 28.7°
This is a kinematics problem, where one is only given the theta value 13.0° in regards to the range; thus, the problem is testing one's understanding of the relationships between the variables.
Range (aka x) = (v₀ sin (2θ₀))/g, where θ₀ = 13.0°
Now if we multiply the range by 2, we get:
2x = 2((v₀ sin (2θ₀))/g) → to verbalize, if range equates to (v₀ sin (2θ₀))/g, and doubling the range equals twice the product value, then:
2θ = sin⁻¹(2sin(2(13.0° )) = sin⁻¹(2(0.76255845048)) = sin⁻¹ (1.52511690096) = 57.35560850015109°/2 = θ
Thus, θ = 28.67780425
It's been awhile since I did this; though I hope it helped!
If a body travelled a distance 's' in 't'.
What is the distance travelled in 't'
Answer: Distance traveled in time t is s
Explanation: Self Explanatory
A man is standing away from the School
Building at a distance of
300m . He claps his hands and hears an echo calculate the time interval of him hearing his echo
The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.
What do you mean by echo?An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.
The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.
To calculate the time interval, we can use the following formula:
time = distance / speed
where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.
distance = 2 x 300m = 600m
speed = 343 m/s
time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)
Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.
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Determine the force in members KD ( in kN) of the Pratt truss . State if the members are in tension (+) or compression (-). Take that P1 = 21 kN , P2 = 33 kN and P3 = 45 kN .
The force in member KD is 19.04 kN in tension.
Determine the reactions at the support points. Since the truss is statically determinate, we can easily solve for these reactions. Assuming the supports are pinned, we can determine the vertical reaction at support A to be 54 kN and the horizontal reaction at support D to be 33 kN.
Analyze the forces at each joint of the truss. Starting at joint A, we can solve for the forces in members AB and AC using the equations of equilibrium:
ΣFy = 0: 54 - P1 - 10sin(60) - ABsin(60) = 0
ΣFx = 0: AC - 10cos(60) - ABcos(60) = 0
Solving these equations simultaneously, we get AB = 16.21 kN (compression) and AC = 5.00 kN (tension).
Move on to joint B and solve for the forces in members BD and BE:
ΣFy = 0: ABsin(60) - BDsin(45) - 10sin(60) = 0
ΣFx = 0: -BE - ABcos(60) + BDcos(45) = 0
Solving these equations, we get BD = 15.17 kN (compression) and BE = 8.21 kN (tension).
Continue analyzing the forces at each joint until we reach joint D. Solving for the forces in members CD and KD:
ΣFy = 0: -P3 - CDsin(30) - BE - BDsin(45) = 0
ΣFx = 0: CDcos(30) + BDcos(45) - KD = 33
Solving these equations, we get CD = 18.41 kN (compression) and KD = -19.04 kN (tension).
Therefore, the force in member KD would be 19.04 kN in tension.
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Two people stand a distance L apart along an east-west road. They both clap their hands at precisely noon in the ground frame. You are driving eastward down this road at speed 4c/5. You notice that you encounter the western person at the same instant (as measured in your frame) that the eastern person claps. Where are you along the road at the instant (as measured in your frame) that the western person claps?
Answer:
Location along the road = 9/15 L
Explanation:
speed eastward = 4c/5
distance between people standing = L
Location along the road at the instant the western person claps =
= 5/3 L - 16/5 L = 9/ 15 L
attached below is a detailed solution
What is the car’s average velocity (in m/s) in interval between t=1.0s to t=1.5s?
Answer:
This question is incomplete
Explanation:
This question is incomplete. However, the formula for velocity is;
Velocity (in m/s) = distance/time
The distance the car covered in the completed question is divided by the difference in the time interval
The difference in the time interval will be = 1.5s - 1.0s = 0.5s
NOTE: the distance must be in meters or be converted to meters
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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a force is represented by a ____ the choice of a ____ is necessary
Answer:
a force is represented by a vector the choice of a reference frame is necessary
Explanation:
I only need question 12 answered
A vector's length is considered to be its magnitude. A is used to represent the vector's magnitude.
A vector's magnitude can be determined in what ways?|v| =(x2 + y2) is the formula to calculate a vector's magnitude in two dimensions, where v = (x, y). From the Pythagorean theorem, this formula was obtained. In three-dimensional space, the formula to calculate a vector's magnitude is V = (x, y, z).A vector's length is considered to be its magnitude. A is used to represent the vector's magnitude. For more details on a vector's magnitude, see to its introduction. On this page, formulas for the magnitude of vectors in two and three dimensions in terms of their coordinates are developed.To learn more about vector's length refer to:
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The angle measured anticlockwise from the +x axis can be used to find vector components as well. In that instance, the x-component and y-component, respectively, will always be cos and sin.
How do you find the x and y components of a vector given velocity?The components of velocity v x=v cos and v y=v sin, where v is the magnitude of the velocity and is its direction in relation to the horizontal, have magnitudes of v x=v cos and v y=v respectively.Fill in a and b in the formula \(|v|=a_2+b_2 | v |=a_2 + b_2\) for a vector with the values a and b. Step 2: Underly the square root first, and then simplify the square root as much as you can, to simplify the magnitude\(|v|=a_2+b_2 | v |=a_2 + b_2\). Finding the horizontal component requires multiplying the vector's magnitude by the cosine of the vector's angle, and finding the vertical component requires multiplying the vector's magnitude by the sine of the vector's angle.To learn more about vector refer to :
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You can keep a 1kg apple from falling to the ground by placing it on a table. What reaction force is resisting the force of the apple on the table?
1. Air resistance
2. Friction
3. Normal force
4. Tension
5. Gravity
The equilibrium condition allows finding the correct answer for the force that is resisting the weight of the apple is:
3. Normal force
Newton's second law gives the relationship between force, mass and acceleration of bodies, in the special case that the acceleration is is called the equilibrium condition.
∑ F = 0
Where F is the external force.
The free body diagram is a diagram of the forces on bodies without the details of the shape of the body, in the attached we can see a scheme of the forces.
Let's write the equilibrium condition for the apple
N - W = 0
N = W
.
We can see that the only forces acting on the apple are its weights and reaction from the table called Normal.
Let's analyze the different answers:
1. False. The apple is not moving therefore the resistance is zero
2. False. The apple is not moving so friction it with the table is
3. True. The free-body diagram shows that the normal and the weight are equal
4. False. There is nothing to pull the apple so there is no tension
5. False. Gravity is the weight of the apple that is applied to the table, not from the table to the apple.
In conclusion using the equilibrium condition we can find the correct result for the force that is resisting the weight of the apple is:
3. Normal force
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different days have different gravity
Explanation:
I NEED ASAP
Heat energy in the atmosphere always moves _____.
A.
from cloudy to clear regions
B.
from low pressure to high pressure regions
C.
from high temperature to low temperature areas
D.
from low temperature to high temperature areas
Answer:
from high temperature to low temperature areas
Explanation:
If it is correct, could you please give me brainliest? I would really appreciate it! Thank you!
what is compressibility?
Hi! Compressibility is the capacity of something to be flattened or reduced in size by pressure. I hope this helps you! Good luck and have a great day. ❤️
The work done is a vector quantity and SI base unit is J
Answer:
Is this your question? Also I think work done is a scalar quantity.
Explanation:
Breifly describe how traits are passed down from human parents to their offspring. In your description, be sure to include the terms gene, chromosome, and meiosis.
Answer:
Parents pass on traits or characteristics, such as eye colour and blood type, to their children through their genes
Explanation:
Including reaction time, the stopping distance is more than 20 feet at 10 miles per hour, at 20 miles per hour it will be about:
30 feet
63 feet
40 feet
75 feet
Answer:
A. 30 feet
Explanation:
Including reaction time, the stopping distance is more than 20 feet at 10 miles per hour, at 20 miles per hour it will be about 63 feet. Option B is correct.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity.
Given conditions;
10 miles per hour ⇒ 20 feet
1 mile per hour ⇒ 2 feet
20 miles per hour ⇒ 20 × 2 feet
20 miles per hour ⇒ 20 × 2 feet
20 miles per hour ⇒40 feet
If the stopping distance is more than 20 feet at 10 miles per hour at 20 miles per hour it must be more than 40 feet.So that the correct answer is 63 feet.
Hence option B is correct.
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3. What is the acceleration of a cart with a F = 80 N and m = 32 kg? *
2.0 m/s^2
O 2.5 m/s^2
2.8 m/s^2
2.7 m/s^2
Answer:
2.5 m/s^2
Explanation:
Given the following data;
Force = 80N
Mass = 32kg
To find acceleration;
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
\( F = ma\)
Where;
F represents force.
m represents the mass of an object.
a represents acceleration.
Making acceleration (a) the subject, we have;
\(Acceleration (a) = \frac{F}{m}\)
Substituting into the equation;
\(Acceleration (a) = \frac{80}{32}\)
Acceleration = 2.5m/s²