The amount of worth of machine Larry needs to sell to recieve 15,000 dollars is 125, 000 dollars.
How to find the worth of machine he can sell to earn a particular amount?Larry thinks the big money is in rowing machines. If Larry switches jobs,
he will earn a 12% commission on all the machines he sells. For Larry to
receive $15,000 in commissions, the worth of dollars of machines he must
sell can be computed as follows:
Therefore,
let
x = amount he will earn
Hence,
15, 000 = 12% of x
15,000 = 12 / 100 × x
15000 = 12x / 100
cross multiply
1500000 = 12x
divide both sides by 12
x = 1,500,000 / 12
x = 125,000
Therefore, he needs to sell $125, 000 worth of machine.
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The figure below is a net for a right rectangular prism. Its surface area is 416 m² and the area of some of the faces are filled in below. Find the area of the missing faces, and the missing dimension.
The area of each of the missing faces is 40 m².
The length of each of the missing faces is 10 m.
The missing dimension is 10 m by 4 m.
What is area?Area is the region bounded by a plane shape.
To calculate the area of each missing face, we use the formula below.
Formula:
a = [A-2(48+120)]/2.............. Equation 1Where:
a = Area of each missing facesA = Total surface area of the rectangular prismFrom the question,
Given:
A = 416 m²Substitute these values into equation 1
a = [416-2(48+120)]/2a = (416-336)/2a = 40 m²And the length of each of the missing edge can be calculated using the formula below
Formula:
l = a/w.................Equation 2Where:
l = Length of each of the missing edgew = width of each of the missing edgeFrom the diagram in the question,
Given:
w = 4 ma = 40 m²Substitute into equation 2
l = 40/4l = 10 mHence, the length is 10 m.
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Question 3 of 10
Classify the following triangle. Check all that apply.
11.9 , 7,6,11.9
A.Scalere
B. Right
C. Isosceles
D. Equilateral
E. Obtuse
F .Acute
Answer:
Step-by-step explanation:
An isosceles triangle is a one that has two of its sides equal. Hence option (c) is correct because here two sides have length of 11.9.
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Please actually help me and dont type something irrelevant. Its rude and annoying. Im just trying to bring my grade up.
Answer:
D. The speed of light
Step-by-step explanation:
The speed of light is extremely fast at 299,792,458 m / s. This would be better to look at in scientific notation:
3.00 x 108 m/s.
Define a function in Scheme that
returns True if a matrix (list of lists) is symmetric and returns
False otherwise.
Here's a Scheme function that checks whether a matrix is symmetric or not:
```scheme
(define (is-symmetric-matrix matrix)
(define (get-element matrix i j)
(if (null? matrix)
#f
(if (= i 0)
(if (null? (car matrix))
#f
(if (= j 0)
(car (car matrix))
(get-element (cdr matrix) i (- j 1))))
(get-element (cdr matrix) (- i 1) j))))
(define (is-matrix-symmetric-helper matrix i j)
(if (null? matrix)
#t
(if (equal? (get-element matrix i j)
(get-element matrix j i))
(is-matrix-symmetric-helper matrix i (+ j 1))
#f)))
(if (null? matrix)
#t
(is-matrix-symmetric-helper matrix 0 0)))
```
The function `is-symmetric-matrix` takes a matrix as an input, which is represented as a list of lists. It uses a helper function called `is-matrix-symmetric-helper` to compare each element of the matrix with its corresponding element in the transposed position. The `get-element` function is used to retrieve the element at position `(i, j)` in the matrix.
The `is-matrix-symmetric-helper` function recursively iterates over the matrix, comparing each element with its transposed element. If any pair of corresponding elements is found to be different, it immediately returns `#f` (False), indicating that the matrix is not symmetric. If it reaches the end of the matrix without finding any differences, it returns `#t` (True), indicating that the matrix is symmetric.
Finally, the main `is-symmetric-matrix` function first checks if the matrix is empty. If it is, it immediately returns `#t` since an empty matrix is considered symmetric. Otherwise, it calls the helper function with the initial indices `(0, 0)` and returns its result.
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Find the missing length indicated. Pls show ur work. Thank you
Step-by-step explanation:
please mark me brainlest to all questions
___________
\( \: \)
\(\boxed{ \rm{answer \: by \: { \boxed{ \rm{☆HayabusaBrainly}}}}}\)
Step by step :Solution in picture!
in 2012, gallup asked participants if they had exercised more than 30 minutes a day for three days out of the week. suppose that random samples of 100 respondents were selected from both vermont and hawaii. from the survey, vermont had 65.3% who said yes and hawaii had 62.2% who said yes. what is the value of the sample proportion of people from vermont who exercised for at least 30 minutes a day 3 days a week? group of answer choices unknown 0.6375 0.653 0.622
The value of the sample proportion of people from Vermont who exercised for at least 30 minutes a day, 3 days a week is 0.653.
We have,
Vermont had 65.3% of respondents who said yes to exercising for at least 30 minutes a day, 3 days a week.
To find the sample proportion, you can convert the percentage to a decimal by dividing the percentage by 100.
Step 1:
Convert the percentage to a decimal.
65.3 / 100 = 0.653
Thus,
The value of the sample proportion of people from Vermont who exercised for at least 30 minutes a day, 3 days a week is 0.653.
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Mrs. Huffman is buying a dog for her daughter, Anna. The dog can be male or female. It can be a Goldendoodle, Collie, or Retriever. The dog can be small, medium, or large. What is the probability that Anna randomly chooses a male Goldendoodle of any size?
Answer:
1/2
Step-by-step explanation:
there ARE ONLY TWO GENDERS
THE dog can be male or female =
sum genders = 2
probability of been a male = 1/2
If 10400 dollars is invested at an interest rate of 8 percent per year, find the value of the investment at the
end of 5 years for the following compounding methods, to the nearest cent.
(a) Annual: $
(b) Semiannual: $
(c) Monthly: $
(d) Daily: $
The interest estimated by compounding methods are-
(a) Annual: n = 1; CI = $860
(b) Semiannual: n = 2; CI = $862.
(c) Monthly: n = 12; CI = $865
(d) Daily: n = 365; CI = $855
Explain the term compound interest?When you add the interest you have already earned back into the principal balance, you are earning compound interest, which increases your profits.The formula for computing the compound interest is -
CI = A - P
A = P(1 + r/100nt)∧rt
In which,
CI = compound interestP = principal ($10,400)n = number of times compoundedr = rate of interest (8%)t = time (5 year)(a) Annual: n = 1
A = 10,400(1 + 8/500)∧5
A = 10,400 x 1.08
A = 11,260
CI = 11,260 - 10,400
CI = $860
(b) Semiannual: n = 2
A = 10,400(1 + 8/1000)∧10
A = 10,400 x 1.089
A = 11,262
CI = $862.
(c) Monthly: n = 12
A = 10,400(1 + 8/6000)∧60
A = 10,400 x 1.083
A = 11,265
CI = $865
(d) Daily: n = 365
A = 10,400(1 + 8/182500)∧1825
A = 10,400 x 1.0832
A = 11,255
CI = $855
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what is the common factor of 2x^3-4x^2-15x
Answer:
kbsishodhohror keviegieh
Answer:
\(2 {x}^{3} - 4 {x}^{2} - 15x \\ = x( {2x}^{2} - 4x - 15) \\ \)
please help me im gonna have to do this over again if i get it wrong
\(1\frac{1}{2}\) \(batches\)
➛➛➛➛➛
\(\frac{1/2}{1} =\frac{3/4}{x}\)
\(\frac{1}{2} =\frac{3}{4x}\)
\(cross~multiply\)
\(4x=2(3)\)
\(\frac{4x}{4} =\frac{6}{4}\)
\(x=\frac{3}{2} =1\frac{1}{2}\)
✂----------------hope it helps...have a great day!!Line AB and line BC form a right angle at point B. If A = (2, 5) and B = (4, 4), what is the equation of line BC?
Answer:
y = 2x - 4
Step-by-step explanation:
To solve this problem, we must first calculate the slope of the line AB using the formula:
\(\boxed{m = \frac{y_2 - y_1}{x_2 - x_1}}\)
where:
m ⇒ slope of the line
(x₁, y₁), (x₂, y₂) ⇒ coordinates of two points on the line
Therefore, for line AB with points A = (2, 5) and B = (4, 4) :
\(m_{AB} = \frac{5 - 4}{2 - 4}\)
⇒ \(m_{AB} = \frac{1}{-2}\)
⇒ \(m_{AB} = -\frac{1}{2}\)
Next, we have to calculate the slope of the line BC.
We know that the product of the slopes of two perpendicular lines is -1.
Therefore:
\(m_{BC} \times m_{AB} = -1\) [Since BC and AB are at right angles to each other]
⇒ \(m_{BC} \times -\frac{1}{2} = -1\)
⇒ \(m_{BC} = -1 \div -\frac{1}{2}\) [Dividing both sides of the equation by -1/2]
⇒ \(m_{BC} = \bf 2\)
Next, we have to use the following formula to find the equation of line BC:
\(\boxed{y - y_1 = m(x - x_1)}\)
where (x₁, y₁) are the coordinates of a point on the line.
Point B = (4, 4) is on line BC, and its slope is 2. Therefore:
\(y - 4 =2 (x - 4)\)
⇒ \(y - 4 = 2x - 8\) [Distributing 2 into the brackets]
⇒ \(y = 2x-4\)
Therefore, the equation of line BC is y = 2x - 4.
What is a concave hexagon with 2 pairs of congruent sides?
A concave hexagon with 2 pairs of congruent sides is a shape that has six sides and two pairs of sides that are of equal length, but the shape curves inward at one or more angles, creating a concave indentation.
A hexagon is a six-sided polygon, and when two pairs of its sides are congruent,
it means that four of its sides have the same length, if the shape curves inward at one or more angles,
it creates a concave hexagon, which means that the indentation on the shape is facing inward, rather than outward, a concave hexagon with 2 pairs of congruent sides is a six-sided polygon with four sides of equal length, but with a curvature that creates an inward indentation.
Hence, a concave hexagon with 2 pairs of congruent sides is a six-sided figure with an indentation and two sets of sides with equal lengths.
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An interior designer is planning a room but needs to first figure out the dimensions. The length of the room is 17 inches on the architect’s plan. What is the actual length of the room in feet if the scale of the plan is 1.25 inches to 3 feet?
If the length of the room is 17 inches one the architect's plan, the actual length of the room in feet if the scale of the plan is 1.25 inches to 3 feet is
40.8 feet
The length of the room on the architect's plan = 17 inches
The scale of the plan = 1.25 inches to 3 feet
That means
The length on the plan/ The actual length = 1.25 inches / 3 feet
Substitute the value of the length on the plan in the equation
17 / The actual length = 1.25/3
The actual length of the room = 17/0.42
= 40.8 feet
Hence, if the length of the room is 17 inches one the architect's plan, the actual length of the room in feet if the scale of the plan is 1.25 inches to 3 feet is 40.8 feet
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Suppose that 5 J of work is needed to stretch a spring from its natural length of 36 cm to a length of 51 cm. (a) How much work is needed to stretch the spring from 41 cm to 46 cm? (Round your answer to two decimal places.) 5 Incorrect: Your answer is incorrect. J (b) How far beyond its natural length will a force of 25 N keep the spring stretched? (Round your answer one decimal place.) cm
Answer:
a) 0.6 joules of work are needed to stretch the spring from 41 centimeters to 46 centimeters.
b) The spring must be 5.6 centimeters far from its natural length.
Step-by-step explanation:
a) The work done to stretch the ideal spring from its natural length is defined by the following definition:
\(W = \frac{1}{2}\cdot k\cdot (x_{f}-x_{o})^{2}\) (1)
Where:
\(k\) - Spring constant, measured in newtons.
\(x_{o}\), \(x_{f}\) - Initial and final lengths of the spring, measured in meters.
\(W\) - Work, measured in joules.
The spring constant is: (\(W = 5\,J\), \(x_{o} = 0.36\,m\), \(x_{f} = 0.51\,m\))
\(k = \frac{2\cdot W}{(x_{f}-x_{o})^{2}}\)
\(k = \frac{2\cdot (5\,J)}{(0.51\,m-0.36\,m)^{2}}\)
\(k = 444.44\,\frac{N}{m}\)
If we know that \(k = 444.44\,\frac{N}{m}\), \(x_{o} = 0.41\,m\) and \(x_{f} = 0.46\,m\), then the work needed is:
\(W = \frac{1}{2}\cdot \left(444.44\,\frac{N}{m} \right)\cdot (0.46\,m-0.41\,m)^{2}\)
\(W = 0.555\,J\)
0.6 joules of work are needed to stretch the spring from 41 centimeters to 46 centimeters.
b) The elastic force of the ideal spring (\(F\)), measured in newtons, is defined by the following formula:
\(F = k\cdot \Delta x\) (2)
Where \(\Delta x\) is the linear difference from natural length, measured in meters.
If we know that \(k = 444.44\,\frac{N}{m}\) and \(F = 25\,N\), then the linear difference is:
\(\Delta x = \frac{F}{k}\)
\(\Delta x = \frac{25\,N}{444.44\,\frac{N}{m} }\)
\(\Delta x = 0.056\,m\)
The spring must be 5.6 centimeters far from its natural length.
A rectangle is 4 cm longer than it is wide. If the length and width are both
decreased by 2 cm, the area is decreased by 24 cm². Find the dimensions
of the original rectangle.
Q3 make c the subject
i do not understand this one but please explain it in steps so i understand i will mark brainliest
Answer:
c=(ay-2)/m
Step-by-step explanation:
Isolate c
First I would multiply both sides by y
mc+2=ay
Then I would subtract 2
mc=ay-2
Then I can divide my m to get c alone
c=(ay-2)/m
true or false: if you are given a graph with two shiftable lines, the correct answer will always require you to move both lines.
False. if you are given a graph with two shif table lines, the correct answer will always require you to move both lines.
In a graph with two shiftable lines, the correct answer may or may not require moving both lines. It depends on the specific scenario and the desired outcome or conditions that need to be met.
When working with shiftable lines, shifting refers to changing the position of the lines on the graph by adjusting their slope or intercept. The purpose of shifting the lines is often to satisfy certain criteria or align them with specific points or patterns on the graph.
In some cases, achieving the desired outcome may only require shifting one of the lines. This can happen when one line already aligns with the desired points or pattern, and the other line can remain fixed. Moving both lines may not be necessary or could result in an undesired configuration.
However, there are also situations where both lines need to be shifted to achieve the desired result. This can occur when the relationship between the lines or the positioning of the lines relative to the graph requires adjustments to both lines.
Ultimately, the key is to carefully analyze the graph, understand the relationship between the lines, and identify the specific criteria or conditions that need to be met. This analysis will guide the decision of whether one or both lines should be shifted to obtain the correct answer.
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20 POINTS ANSWER FAST PLEASE
Amanda has an envelope that is 2 1/4 inches tall. The envelope is 4 1/3 times as long as it is tall. How long is her envelope?
Answer:
8 1/12
Step-by-step explanation:
4 1/3 × 2 1/4
= 8 1/12
If $5x-7=13x+17$, what is $6(x-4)$?
Answer:
0(x-4)
Step-by-step explanation:
in my working system i mean just when i try on the place of 4 any number can be inserted
$5x-7=13x+17$,here both gives -22 as a result so
$6(x-4)$=6x-24 and to give the same result or 0
$6(x-4)$=0(x-any number )
If Sarah has $6453 Dallors of food and has $135 Dollars on her. How much will she need to pay for her food?
A. 6318
B. 233
C. 4555
D None of the Above
Answer:
It will be A
Step-by-step explanation:
6453
- 135
--------
6318 dollars needed for Sarah's food.
Hope this helps!
In a certain triangle, two of the sides have measures of 8 and 10. If the triangle is isosceles, then which of the following could be the measure of the third side?
A. 18
B. 2
C. 20
D. 8
Answer:
C. 20 could be the third side of the isosceles triangle
pls help i am speedrunning overdues rn
The amount of soil needed to fill the garden box is given as follows:
1728 ft³.
How to obtain the volume of a rectangular prism?The volume of a rectangular prism, with dimensions defined as length, width and height, is given by the multiplication of these three defined dimensions, according to the equation presented as follows:
Volume = length x width x height.
The figure in this problem is composed by two prisms, with dimensions given as follows:
19 ft, 12 ft and 6 ft.10 ft, 3 ft and 12 ft.Hence the volume is given as follows:
V = 19 x 12 x 6 + 10 x 3 x 12
V = 1728 ft³.
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one third of the sum of a number and four
Answer:
\(\frac{1}{3} (n+4)\)
That is what the expression would be
Please help. I'm stuck on this.
Answer:
2
Step-by-step explanation:
Triangle TUV, with vertices T(2,-8), U(9,-6), and V(6,-3), is drawn on the coordinate
grid below. what is the area. in square units, of triangle TUV
The area of the triangle TUV, with vertices T(2,-8), U(9,-6), and V(6,-3), is 13.58
How did we arrive at the above?First using distance calculator we derived the length of TV and the length of VU.
Since TV = Height; and
VU = Base
and the triangle is a right triangle,
Then, area is given by 1/2 base x Height
Length of TV usign distance calculator is 6.40312
Lenght of VU using distance calculator is 4.24264
So area = 1/2 * 6.40312 * 4.24264
Area = 13.58
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Consider the differential equation Y = C. What is the magnitude of the error in the two Euler approximations you found? Magnitude of error in Euler with 2 steps = Magnitude of error in Euler with 4 steps = D. By what factor should the error in these approximations change (that is, the error with two steps should be what number times the error with four)? factor = (How close to this is the result you obtained above?) y(1) (Be sure not to round your calculations at each step!) B. What is the solution to this differential equation (with the given initial condition)? (Be sure not to round your calculations at each step!) Now use four steps: : when . A. Use Euler's method with two steps to estimate with initial condition
To estimate the solution to the differential equation Y' = C using Euler's method with two steps, we need to divide the interval [0, 1] into two subintervals.
Let's denote the step size as h, where h = (1 - 0) / 2 = 0.5.
Using Euler's method, the general formula for the next approximation Y(i+1) is given by:
Y(i+1) = Y(i) + h * C
Given the initial condition Y(0) = 0, we can calculate the two approximations:
First step:
Y(1) = Y(0) + h * C
= 0 + 0.5 * C
= 0.5C
Second step:
Y(2) = Y(1) + h * C
= 0.5C + 0.5 * C
= C
So, the two Euler approximations with two steps are:
Y(1) = 0.5C
Y(2) = C
Now, let's calculate the magnitude of the error in these approximations compared to the exact solution.
The exact solution to the differential equation Y' = C is given by integrating both sides:
Y = C * t + K
Using the initial condition Y(0) = 0, we find that K = 0.
Therefore, the exact solution to the differential equation is Y = C * t.
Now, we can compare the Euler approximations with the exact solution.
Magnitude of error in Euler with 2 steps:
Error_2 = |Y_exact(1) - Y(1)|
= |C * 1 - 0.5C|
= 0.5C
Magnitude of error in Euler with 4 steps:
To calculate the error in the Euler approximation with four steps, we need to divide the interval [0, 1] into four subintervals. The step size would be h = (1 - 0) / 4 = 0.25.
Using the same formula as before, we can calculate the Euler approximation with four steps:
Y(1) = Y(0) + h * C
= 0 + 0.25 * C
= 0.25C
Y(2) = Y(1) + h * C
= 0.25C + 0.25 * C
= 0.5C
Y(3) = Y(2) + h * C
= 0.5C + 0.25 * C
= 0.75C
Y(4) = Y(3) + h * C
= 0.75C + 0.25 * C
= C
So, the Euler approximation with four steps is:
Y(1) = 0.25C
Y(2) = 0.5C
Y(3) = 0.75C
Y(4) = C
Magnitude of error in Euler with 4 steps:
Error_4 = |Y_exact(1) - Y(4)|
= |C * 1 - C|
= 0
Therefore, the magnitude of the error in the Euler approximation with 2 steps is 0.5C, and the magnitude of the error in the Euler approximation with 4 steps is 0.
The factor by which the error in the approximations with two steps should change compared to the error with four steps is given by:
Factor = Error_2 / Error_4
= (0.5C) / 0
= undefined
Since the error in the Euler approximation with four steps is 0, the factor is undefined.
The solution to the differential equation Y' = C with the given initial condition Y(0) = 0 is Y = Ct.
Using the exact solution, we can evaluate Y(1):
Y(1) = C * 1
= C
So, the solution to the differential equation with the given initial condition is Y = Ct, and Y(1) = C.
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Two different tests to write k/4 +16
Step-by-step explanation:
\begin{gathered}6x - 2y = 6 \\ 6x = 6 + 2y \\ x = \frac{6 + 2y}{6} \end{gathered}
6x−2y=6
6x=6+2y
x=
6
6+2y
write the perimeter of the triangle as a simplified expression y+64y-22yt1
Given the triangle;
The perimeter of a shape is the sum of the sides or outer parts of the shape.
Thus, the perimeter of the triangle is;
\(y+6+4y-2+2y+1\)Then, we simplify further by collect like terms, we have;
\(\begin{gathered} y+4y+2y+6-2+1 \\ =7y+5 \end{gathered}\)Repeat the above problem corresponding to y(x,t=5)=0.5cos(0.1x)+0.4sin(0.1x+π/3) wavelength ratige? [Aas: 16.5 m>λ>0.0165 m ] Calculate the speced of Jongitudial waves at NTP in Ans: y(x,t)=aexp[ σ 2
(x−b−b(f−2)if
] Consider a wave propagating in the -x-direction whose 40.4f−0.004(x−10) for a wave, the displacement of waich is given by frequency is 100sec −1
. At r=5 sec the displacement as- Whete r.y and − ars mearured in centimeter and f in secooss. sociated with the wave is given by the following cruabog; Whar wif be the wavetengst and the frequency of the wave? M(x,t−5)=0.5cos(0,1x) What is the w the wave? { Ans: y(x,0)=0.5cos{0.1x+200π(t−5)}
The wavelength range of the longitudinal waves is between 16.5 m and 0.0165 m.
Longitudinal waves are characterized by the displacement of particles occurring parallel to the direction of wave propagation. In the given problem, the equation of the wave is provided as y(x,t=5) = 0.5cos(0.1x) + 0.4sin(0.1x+π/3).
To determine the wavelength range, we can analyze the wave equation. The general form of a sinusoidal wave is given by y(x,t) = a * sin(kx - ωt + φ), where a represents the amplitude, k is the wave number (related to the wavelength), ω is the angular frequency, t is time, and φ is the phase constant.
Comparing this with the given equation, we can observe that the wave number k is 0.1 (since k = 2π/λ, where λ is the wavelength). Therefore, the wavelength λ can be calculated as λ = 2π/k = 2π/0.1 = 20π.
Given that the wavelength range is specified as 16.5 m > λ > 0.0165 m, we can convert this into the range for π: 16.5 m > 20π > 0.0165 m.
Thus, the wavelength range for the longitudinal waves in this problem is between 16.5 m and 0.0165 m.
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Tire manufacturers are required to provide performance information on tire sidewalls to help prospective buyers make their purchasing decisions. One important piece of isformation is the tread wear index, which indicates the tire's resistance to tread wear. A tire with a grade of 200 should last twice as long, on average, as a tire with a grade of 100 . A consumer organization wants to test the actual tread wear index of a brand name of tires that claims "graded 200 " on the sidewall of the tire. A random sample of n=18 indicates a sample mean tread wear index of 198.8 and a sample standard deviation of 21.4. Is there evidence that the population mean tread wear index is different from 200 ? a. Formulate the null and alternative hypotheses. b. Compute the value of the test statistic. c. At alpha =0.05, what is your conclusion? d. Construct a 95% confidence interval for the population mean life of the LEDs. Does it support your conclusion?
a. Null hypothesis (H0): The population mean tread wear index is equal to 200. Alternative hypothesis (Ha): The population mean tread wear index is different from 200.
b. The test statistic (t) is calculated using the formula t = (198.8 - 200) / (21.4 / sqrt(18)).
c. At alpha = 0.05, if the absolute value of the test statistic (|t|) is greater than the critical value (±2.101), we reject the null hypothesis.
d. The 95% confidence interval for the population mean tread wear index is constructed using the formula 198.8 ± (2.101 * (21.4 / sqrt(18))). If the interval includes 200, it supports the conclusion that there is no evidence of a difference in the population mean.
a. The null hypothesis (H0): The population mean tread wear index is equal to 200.
The alternative hypothesis (Ha): The population mean tread wear index is different from 200.
b. To determine the test statistic, we can use the t-test since the population standard deviation is unknown. The formula for the t-test statistic is given by:
t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))
Plugging in the values:
Sample mean (\(\bar{x}\)) = 198.8
Hypothesized mean (μ) = 200
Sample standard deviation (s) = 21.4
Sample size (n) = 18
t = (198.8 - 200) / (21.4 / √(18))
c. To determine the conclusion, we need to compare the computed test statistic (t) with the critical value from the t-distribution table. Since the alternative hypothesis is two-sided (population mean can be greater or less than 200), we need to consider the critical values for a two-tailed test.
Using the t-distribution table or statistical software, we find that with a sample size of 18 and a significance level of 0.05, the critical values for a two-tailed test are approximately ±2.101.
If the absolute value of the computed test statistic (|t|) is greater than the critical value, we reject the null hypothesis. Otherwise, we fail to reject the null hypothesis.
d. To construct a 95% confidence interval, we can use the formula:
Confidence Interval = sample mean ± (critical value * (sample standard deviation / √(sample size)))
Plugging in the values:
Sample mean (\(\bar{x}\)) = 198.8
Sample standard deviation (s) = 21.4
Sample size (n) = 18
Critical value for a 95% confidence level = ±2.101
Confidence Interval = 198.8 ± (2.101 * (21.4 / √(18)))
If the confidence interval contains the hypothesized mean of 200, it supports the conclusion that there is no evidence to suggest that the population mean tread wear index is different from 200. If the confidence interval does not include 200, it contradicts the conclusion and suggests that the population mean is different from 200.
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