Large stars can explode as they finish burning their nuclear fuel, causing a supernova. The explosion blows away the outer layers of the star. According to Newton’s third law, the forces that push the outer layers away have reaction forces that are inwardly directed on the core of the star. These forces compress the core and can cause the core to undergo a gravitational collapse. The gravitational forces keep pulling all the matter together tighter and tighter, crushing atoms out of existence. Under these extreme conditions, a proton and an electron can be squeezed together to form a neutron. If the collapse is halted when the neutrons all come into contact with each other, the result is an object called a neutron star, an entire star consisting of solid nuclear matter. Many neutron stars rotate about their axis with a period of ≈1s and, as they do so, send out a pulse of electromagnetic waves once a second. These stars were discovered in the 1960s and are called pulsars. A) Consider a neutron star with a mass equal to the sun, a radius of 19 km , and a rotation period of 1.0 s. What is the speed of a point on the equator of the star? Express your answer to two significant figures and include the appropriate units. B) What is g at the surface of this neutron star? Express your answer to three significant figures and include the appropriate units. C) A stationary 1.0 kg mass has a weight on earth of 9.8 N. What would be its weight on the star? Express your answer to three significant figures and include the appropriate units. D) How many revolutions per minute are made by a satellite orbiting 1.0 km above the surface? Express your answer to two significant figures and include the appropriate units. E) What is the radius of a geosynchronous orbit about the neutron star? Express your answer to three significant figures and include the appropriate units

Answer:

7 Seconds

Explanation:

P=W/t

t=W/P

t=875,000/125,000

t=7 seconds

Answer:

Potential energy refers to the stored up energy within an object, that builds up and can potentially be used to propel that object.

Explanation:

A famous example, would be water behind a dam. The rushing water fills up behind the dam, and since it's being held in one place, it will build up until of course the dam is either moved or lifted, and then all the water will be forced (due to all the energy that was being stored) down the rest of the stream.

I hope the explanation makes sense. If it doesn't, please let me know and I'll try to find another one for you :)

Answer:

(a). The speed is 115.28 m/s.

(b). The time is 94 min.

(c). The International Space Station travels 43202.400 km.

(d). Speed is scalar quantity.

Velocity is vector quantity.

Explanation:

Given that,

Top speed = 415 km/h

1 miles = 1609 m

(a). We need to calculate the speed in m/s

Using conversion of km/h to m/s

\(v=415\ km/h\)

\(v=415\times\dfrac{5}{18}\)

\(v=115.28\ m/s\)

(b). We need to calculate the distance from London to Edinburgh in km

Using conversion for distance

\(d=403\ miles\)

Distance in meter,

\(d=403\times1609\)

\(d=648427\ m\)

\(d=648.427\ km\)

We need to calculate the time

Using formula of time

\(t=\dfrac{d}{v}\)

Put the value into the formula

\(t=\dfrac{648.427}{415}\)

\(t=1.56\ h\)

\(t=1\ hours 34\ min\)

\(t= 94\ min\)

(c). Speed v' =7.66 km/s

v'=7660 m/s

In the time it takes the car to travel from London to Edinburgh,

We need to calculate the distance

Using formula of distance

\(d'=v'\times t\)

Put the value into the formula

\(d'=7660\times94\times60\)

\(d'=43202400\ m\)

\(d'=43202.400\ km\)

(d). Speed :

Speed is equal to the distance divided by time.

It is scalar quantity.

Velocity :

Velocity is equal to the displacement divided by time.

It is vector quantity.

Hence, (a). The speed is 115.28 m/s.

(b). The time is 94 min.

(c). The International Space Station travels 43202.400 km.

(d). Speed is scalar quantity.

Velocity is vector quantity.

Answer:

i) O m/s² as velocity is constant

ii) 20m/s

iii)Hint:Calculate the area of the graph,that is;below the line, for the first 15 seconds only

Hope this helps.

Answer:

Explanation:

An x-ray emits radiation to see through the outer part of your body.

Hope this helps! <3

An X-ray is a type of radiation which is a type of electromagnetic radiation in the electromagnetic spectrum.

The  electromagnetic spectrum consists of electromagnetic radiation consists of waves made up of electromagnetic field which are capable of propogating through space and carry the radiant electromagnetic energy.

The radiation are composed of electromagnetic waves which are synchronized oscillations of electric and magnetic fields . They are created due to change which is periodic in electric as well as magnetic fields.

In vacuum ,all the electromagnetic waves travel at the same speed that is with the speed of air.There are 7 types of electromagnetic radiation in the electromagnetic spectrum.Gamma rays have the highest energy while radio waves have least energy.

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Answer:

Hmm wheres the choices?

Explanation:

The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.

In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.

The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.

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Right now the ball only has potential energy but when the ball falls that will be converted into kinetic energy because it is moving. BTW Im 14 in 9th grade ya'll should know this.

Answer:

potential; kinetic

Explanation:

The event that marks the end of a star's evolutionary life before becoming a white dwarf is a planetary nebula. So, option E is correct.

A planetary nebula is characterized by cosmic rays of gas and dust surrounding a dying star. This dying star becomes a white dwarf after the complete depletion of hydrogen in the core.

It gets its name from a scientist who described the gases to be looking like two planets around a dying star. Thus, it's called planetary nebulae. This marks the final stage of a dying star that becomes a white dwarf. It consists of the outer layers of the star.

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A) The temperature of the 6.5g iron meteor will increase by approximately 92.0°C if all of its kinetic energy, calculated to be 284.6J, is converted to heat.

To solve this problem, we can use the equation:

ΔT = (KE * 1 cal/g°C) / (mass * specific heat * 4.186 J/cal)

First, we need to convert the mass of the meteor from grams to kilograms:

Mass = 6.5 g = 0.0065 kg

Next, we need to convert the kinetic energy from meters per second to joules:

KE = (1/2) * mass * velocity^2

KE = (1/2) * 0.0065 kg * (295 m/s)^2

KE = 284.6 J

Now we can substitute the values into the equation and solve for ΔT:

ΔT = (284.6 J * 1 cal/g°C) / (0.0065 kg * 113 cal/kg°C * 4.186 J/cal)

ΔT = 92.0°C

Therefore, the temperature of the iron meteor will rise by approximately 92.0°C if its kinetic energy is entirely converted to heat. The answer is (A) 92.0°C.

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Divide the square of the velocity by the sum of the acceleration caused by gravity multiplied by two times the friction coefficient. a = 2.5 m/s2. = 2500 N.

The observation distance, reaction distance, and braking distance are added up to form the total stopping distance. Shortly after the driver decides to slow down or stop, some time has passed. The response distance is the length of time it takes too respond and enter the proper braking position.

For every 10 meters, taking an level path along a road encircling the mountain is substantially less expensive (in terms of both effort and time), but the overall cost increases over a much greater distance. The frictional of distance is measured in each case by the time and/or effort needed to go ten meters.

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At equal pressure, less lp(liquefied petroleum) gas will flow through an orifice than natural gas. False.

At equal pressure, LP (liquefied petroleum) gas will generally flow through an orifice more easily than natural gas. This is due to the differences in the physical properties of the two gases.

LP gas, such as propane or butane, is stored in a liquid state under pressure. When the pressure is released, it vaporizes and becomes a gas. As a result, LP gas has a higher energy content and a higher vapor pressure compared to natural gas.

On the other hand, natural gas primarily consists of methane and is typically supplied through pipelines. It is in a gaseous state at normal atmospheric conditions.

When an orifice or a restricted opening is present, the flow rate of gas is determined by several factors, including the pressure difference across the orifice, the size of the orifice, and the properties of the gas.

Given equal pressure conditions, LP gas will tend to flow more readily through an orifice compared to natural gas. This is because LP gas has a higher vapor pressure, which means it has a greater tendency to expand and fill the available space. The higher energy content of LP gas also contributes to its ability to flow more easily through the orifice.

Therefore, the statement that less LP gas will flow through an orifice than natural gas at equal pressure is false. LP gas is expected to flow more readily through the orifice compared to natural gas.

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The harmonic frequencies would be 880 Hz, 1320 Hz, 1760 Hz, and 2200 Hz if the fundamental frequency was 440 Hz.

The sound waves have a wavelength of 2m and travel at a speed of 440 m/s. Hence, the sound wave has a 2 m wavelength.

340 m/s x 340 Hz x 1 m = 340 m/s, the formula for wavelength. A 34,000 hertz wave has a wavelength of 340 m/s, and its frequency is 0.01 m, or 1 cm.

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Answer:

How does the wavelength at which the maximum intensity occurs change when you increase the temperature? The wavelength decreases.

Explanation:

...

Answer:

Option (a) is correct.

Explanation:

Let the magnitude of the positive charge = \(q_1\) and the magnitude of the negative charge = \(q_2\)

Earlier, the distance between both the charge, d = 1m

By using Coulomb's law, the magnitude of the force between two charge

\(F=k\frac {q_1 q_2}{d^2}\), where k is a constant.

So, the magnitude of the force in the initial configuration,

\(F_i = k\frac {q_1 q_2}{1^2}= k q_1q_2\cdots(i)\)

The nature of the force is attractive, as both the charges are opposite in nature.

On replacing the positive charge from 1m left to 1 m right side of the negative charge, the distance between the charges remains the same, i.e d=1m.

Moreover, the magnitude, and nature of each charge, \(q_1\) as well as \(q_2\), are remain the same.

So, the magnitude of the force in the final configuration,

\(F_f = k\frac {q_1 q_2}{1^2}= k q_1q_2\)

From equation (i), \(F_f=F_i\)

The nature of the force is attractive, as both the charges are opposite in nature.

So, the electrostatic force remains attractive, and the magnitude does not change.

Hence, option (a) is correct.

When the electrostatic force lies between the charges so here the force should remain attractive, also the magnitude should remain the same.

Here we assume the magnitude of the positive charge should be q1 and the magnitude of the negative charge should be q2

Also, the distance between the charge should be d = 1 m

So here we use the columb law

F = kq1q2/d2

here k should be constant

Here the nature of the force should be attractive since the both the charges should be opposite.

Hence, the first option is correct.

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Answer:

It's d

Explanation:

Answer: D

Explanation:

Force of gravity

When the crest of one wave passes through the trough of another wave, destructive interference takes place.

The crest and trough of a wave, respectively, are its highest and lowest surface portions. The wave height is the vertical distance between the peak and trough. The wavelength is the horizontal separation between two consecutive crests or troughs.

When the crest of one wave passes through the trough of another wave, interference takes place.

This interference can be constructive, where the amplitudes of the waves add up, resulting in a larger wave, or destructive, where the amplitudes of the waves cancel out, resulting in a smaller wave or no wave at all.

The type of interference that occurs depends on the relative amplitudes, wavelengths, and phases of the two waves.

Therefore, destructive interference takes place when the crest of one wave passes through the trough of another wave.

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Answer:

Potential energy

Explanation:

Answer:

carbon dioxide

Explanation:

Answer:

carbon dioxide

Explanation:

trust

The kinetic energy and the speed of the electrons ejected by light of wavelength is

To find the Kinetic energy and speed of the electron, the given values are,

Work function of metallic Caesium - 2.14 ev.

The phenomenon in which electrically charged particles are released from or within a material when it absorbs electromagnetic radiation is called Photoelectric effect. When the electrons on the metal plate gets ejected when the light beam passed on the metal plate.

From the basic equation of photoelectric effect we have

hν = Φ + ½ mv²      

where,

hν - hc/ λ ,is the energy of the incident radiation

Φ - work function of the metal

½ mv² - kinetic energy of the emitted electrons

Thus applying values,

1) For wavelength of 580 nanometers, we have

The energy of incident radiation equals,

6.636× 10⁻³⁴× ((3× 10⁸)/(580× 10⁻⁹× 1.6 × 10 ⁻¹⁹)

=2.14 ev

Since the energy of incident radiation is lesser than or equal to the work function of the metal hence no electron's will be emitted.

2. The Kinetic energy can be,

K.E = 6.636× 10⁻³⁴× ((3× 10⁸)/(580× 10⁻⁹) - 2.14 × 1.6 × 10 ⁻¹⁹)

=2.837 ev.

Thus kinetic energy for the wavelength is 2.837 ev.

Speed of the energy  can be calculated as,

υ = √2E/m = √2×2.837×1.6×10⁻¹⁹/(9.8 × 10⁻³¹)

  = 0.9988×10⁶ m/s.

So, the speed of the energy is 0.9988×10⁶ m/s.

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Answer:

The velocity is always tangent to the line of a circle .

Explanation:

When an object moves in a circular path, its motion is called the circular motion. The speed of the object is constant at each and every point in such motion while the velocity changes due to change in direction.

In a circular motion, the direction of velocity is always tangent to the circle. At  each and every point, its direction is found tangentially.

Answer:

Please find the answer in the explanation.

Explanation:

The variable/s you can manipulate in the simulation to make all the items get the same proximate values for their acceleration will be the variable final velocity. Since all of them have zero initial velocity, the acceleration will tend to zero if they have a constant velocity.

If the final velocity is also zero or approximately equal to zero, that means the velocity is constant. And whenever there is constant velocity, the acceleration will be equal to zero.

Also, if the final velocity of all the parameters are very closed, they will surely have approximately same acceleration.

The variable which can be manipulated in the simulation will be the final

velocity.

The table shows all of them having the same initial velocity which is zero,

then the final velocity will have to be varied in order to get the same

proximate values for their acceleration.

Acceleration is the rate of change of velocity with time and when the velocity

is constant or equal to zero, the acceleration will be equal to zero.If the final

velocity of all the parameters are very close in value , then they will have

proximate values for acceleration.

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In relation to line locators, conductive refers to a direct connection between the pipe and transmitter. Conductive locating involves connecting a transmitter to a metallic pipe or cable and then using a receiver to detect the signal transmitted through the pipe or cable.

The transmitter sends an electrical signal through the conductive material, which is then picked up by the receiver. This technique is particularly useful when locating pipes or cables that are buried underground or hidden behind walls. By using conductive locating, line locators can accurately determine the location, depth, and direction of the pipe or cable. In contrast, an indirect connection with radio waves, as in option B, is referred to as inductive locating, which involves detecting the electromagnetic field around the pipe or cable. While inductive locating can be useful in some situations, such as locating non-conductive pipes or cables, it is less accurate than conductive locating. Overall, conductive locating is a key technique used by line locators to accurately and efficiently locate buried or hidden pipes and cables.

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Answer: The part of the microscope that is the circular area is the APERTURE

I hope this helped!

Answer:

22400 Joules

Explanation:

Apply the formula:

KE = 1/2 . 40 . 1120

KE = 20 . 1120

KE = 22400 Joules

The speed of the wind is 17 mph and the speed of the plane in still air is 119 mph.

Let the speed of the plane be x and the speed of the wind be y. Then, the speed of the plane with the wind becomes x + y, while the speed of the plane against the wind is x - y.

The distance traveled with the wind in 3 hours is 408 miles.

Therefore, we can write the equation as:

3(x + y) = 408

Divide both sides by 3:

x + y = 136  .... (1)

The distance traveled against the wind in 4 hours is also 408 miles.

Therefore, the equation can be written as:

4(x - y) = 408

Divide both sides by 4:

x - y = 102  .... (2)

Now we can solve these two equations using the elimination method.

Add equations (1) and (2):

x + y + x - y = 136 + 1022x = 238x = 119 mph

Therefore, the speed of the plane in still air is 119 mph.

Now, substitute this value of x in equation (1):

119 + y = 136y = 17 mph

Therefore, the speed of the wind is 17 mph.

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The correct question is:

A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air?