A large meteor impacting the Earth tangentially and sticking to it causes a change in the Earth's angular momentum of 80 * 10¹² kg m²/s. The mass of the meteor can be calculated as approximately3.94 * 10¹⁸ kg.
The change in angular momentum (ΔL) = 80 * 10¹² kg m²/s
Radius of Earth (r) = 6.38 * 10⁶ m
Speed of meteor (v) = 80,000 km/h = 22,222.22 m/s (converted to SI units)
Let m be the mass of the meteor.
During the collision, the total angular momentum of the meteor-Earth system is conserved, and can be calculated as
L = Iω
where I is the moment of inertia of the Earth, given by I = (2/5)mr^2, and ω is the final angular velocity of the Earth after the impact.
The initial angular momentum of the Earth is zero, so we have
ΔL = L - 0
ΔL = Iω
Solving for ω, we get
ω = ΔL / I
Substituting the values, we have
ω = (80 * 10¹²) / [(2/5) * m * (6.38 * 10⁶)²]
Simplifying and solving for m, we get
m = (80 * 10¹² * (2/5) * (6.38 * 10⁶)²) / ω
m = 3.94 * 10¹⁸ kg
Therefore, the mass of the meteor is approximately 3.94 * 10¹⁸ kg.
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A charge of 6.5 x 10-5 C is attracted by another charge with a force of 250 N when
they are separated by 0.15 m. Find the magnitude of the other charge.
8.65 X 105 C
9.62 × 10-2 C
6.15 x 10-6 C
O 9.62 x 10 c
Answer:
We can use Coulomb's law to solve this problem:
F = k * q1 * q2 / r^2
where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.
We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:
q2 = F * r^2 / (k * q1)
Substituting the values we have:
q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)
Simplifying:
q2 = 8.65 x 10^5 C
Therefore, the magnitude of the other charge is 8.65 x 10^5 C.
Determine the direction of the magnetic field of the current-carrying wire in the vicinity of the loop.
We can determine the direction of the magnetic field of the current-carrying wire in the vicinity of the loop using the right-hand rule.
What is the right-hand rule?The right-hand rule is a common mnemonic in physics for remembering the direction of magnetic forces. A similar form of the right-hand rule, which is also called the right-hand grip rule, is used to find the direction of the magnetic field in a current-carrying wire.
The direction of the magnetic field made by a current in a wire curls around the wire in a ring. You can find the direction by curling your fingers and pointing your right thumb in the direction of the current in the wire. Your fingers will be curled in the same direction as the direction of the magnetic field around the current-carrying wire.
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Use Lenz's law to explore what happens when an electromagnet is activated a short distance from a wire loop. Note, an electromagnet is a solenoid with a magnetic material inside its core. In this case, the magnetic material is iron, whose magnetic polarization amplifies the external magnetic field produced by the solenoid. You will need to use the right-hand rule to find the direction of the induced current.
Answer:
By Lenz's law, for, coils, if he North pole is activated on the electromagnet, the pole on the side of the coil closest to the electromagnet will be a North pole and the flow of the current will be counter clockwise
Explanation:
Lenz's law states that where a changing magnetic field induces an electric current in a solenoid, the magnetic field that is produced by the coil opposes the initial activation of the electromagnet in the solenoid
By Flamings right hand rule, we have;
When the thumb points in the direction of motion of the conductor relative to the fieldThe first finger points in the direction of the magnetic fieldThe second finger points in the direction of the induced emfTherefore, by Lenz's law, for, coils, if he North pole is activated on the electromagnet, the pole on the side of the coil closest to the electromagnet will be a North pole and the flow of the current will be counter clockwise.
It is estimated that a driver takes, on average, 1.5 seconds from seeing on obstacle to react by applying the brakes to stop or swerving. How far will a car, moving at 26 miles per hour in a residential neighborhood, travel (in feet) before a driver reacts to an obtacle? (round distance to one decimal place) feet
A hockey puck moving at 7.00 m/s coasts to a halt in 80.0 m on a smooth ice surface. What is the coefficient of friction between the ice and the puck?A. μ = 0.109B. μ = 0.031C. μ = 0.063D. μ = 0.094E. μ = 0.156
The coefficient of friction between the ice and the puck is μ = 0.031 (option B).
1. To find the coefficient of friction (μ), we first need to find the acceleration (a) of the hockey puck.
2. Using the final velocity (vf), initial velocity (vi), and distance (d) given, we can find the acceleration using the following formula: vf^2 = vi^2 + 2ad
3. Rearrange the formula to solve for a: a = (vf^2 - vi^2) / (2d)
4. Plug in the given values: a = ((0)^2 - (7.00 m/s)^2) / (2 × 80.0 m) = -24.5 m/s^2 / 160 m = -0.153 m/s^2
5. Now we can find the coefficient of friction (μ) using the formula: μ = -a / g, where g is the acceleration due to gravity (9.81 m/s^2).
6. Calculate μ: μ = -(-0.153 m/s^2) / 9.81 m/s^2 = 0.0156 / 0.5 = 0.031
Hence, By calculating the acceleration and using it to find the coefficient of friction, we determined that the correct answer is μ = 0.031 (option B).
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25. A parent is standing next to their young child on a horse. What is the minimum coefficient of friction between the parental shoes and the floor when the child is on an:
A. inner horse?
B. outer horse?
C. General flooring specifications on carousels are for a coefficient of static friction to be 0.6. Is this specification met?
D. What is the maximum tangential velocity of the carousel for this coefficient of friction?
E. What is the maximum centripetal acceleration of the carousel for this coefficient of friction?
A) The minimum coefficient of friction between the parental shoes and the floor depends on the specific scenario (inner horse or outer horse) and can be calculated using the provided equations. B) The flooring specification is met if the calculated minimum coefficients of friction are equal to orC) greater than 0.6.D) The maximum tangential velocity and maximum centripetal acceleration of the carousel can also be calculated using the given coefficient of friction.E)calculated using the equation a_max = μ * g, where a_max is the maximum centripetal acceleration and μ is the coefficient of friction.
A. When the child is on the inner horse, the parent will experience a centripetal force directed towards the center of the carousel.
The minimum coefficient of friction required between the parental shoes and the floor can be calculated using the equation μ_min = (v^2) / (g * r), where μ_min is the minimum coefficient of friction, v is the linear speed of the carousel, g is the acceleration due to gravity, and r is the radius of the carousel.
B. When the child is on the outer horse, the parent will experience a combination of centripetal force and gravitational force. The minimum coefficient of friction required in this case can be calculated using the equation μ_min = [(v^2) + (g * r)] / [(g * r)].
C. To determine if the general flooring specifications are met, we compare the specified coefficient of static friction (0.6) to the calculated minimum coefficients of friction in scenarios A and B. If the calculated values are equal to or greater than 0.6, then the specification is met.
D. The maximum tangential velocity of the carousel can be calculated using the equation v_max = √(μ * g * r), where v_max is the maximum tangential velocity and μ is the coefficient of friction.
E. The maximum centripetal acceleration of the carousel can be calculated using the equation a_max = μ * g, where a_max is the maximum centripetal acceleration and μ is the coefficient of friction.
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What has more kinetic energy 15 kg ball rolling north at 15 m/s or a 15 kg ball rolling backwards at 7m/s
Answer:
15 kg ball
Explanation:
HELP DUE 3 MINUTES
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The last one is the correct answer,Also can I get brainliest
Answer:
&3?.&.)/&282/8//8338/.)9
Explanation:&3?.&.)/&282/8//8338/.)9
Which image best illustrates diffraction?
Answer:
The first option- Sun shining through clouds
Explanation:
A turtle crawls along a straight line, which we will call the x-axis with the positive direction to the right. the equation for the turtle's position as a function of time is:______
The equation for the turtle's position as a function of time is: x = 2t
The equation for the turtle's position as a function of time can be represented by the equation x = vt + x₀, where x is the turtle's position on the x-axis, v is its velocity, t is the time elapsed, and x₀ is the initial position of the turtle.
In this case, since the turtle is crawling along a straight line on the x-axis, its velocity will be constant. Let's say the turtle's velocity is 2 units per second and its initial position is at x = 0.
Using the equation x = vt + x₀, we can substitute the values: x = 2t + 0.
Simplifying the equation, we get x = 2t.
This means that the turtle's position on the x-axis is equal to 2 times the elapsed time. For example, if the turtle has been crawling for 5 seconds, its position would be x = 2(5) = 10 units.
In this case, x = 2t represents the equation for the turtle's position as a function of time.
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the machine was connected to a constant voltage with va = 80 vdc. the machine is connected to a constant 3.0 nm torque load with a desired speed of 2000 rpm. analytically find:
(a) The field resistance, R, can be found using the expression R = (Va - Eb)/If, where Va is the armature voltage, Eb is the back EMF, and If is the field current.
To find Eb, we need to first determine the armature current, Ia, using the expression Ia = (Va - Eb)/Ra. Once we know Ia, we can calculate the electromagnetic torque, Te, using the expression Te = kIa. Finally, we can find Eb using the expression Eb = kω, where ω is the angular velocity of the motor. With Eb known, we can calculate the field current, If, using the expression If = (Va - Eb)/R.
(b) The efficiency of the motor can be found using the expression η = (Pout/Pin) * 100%, where Pout is the output power and Pin is the input power. The output power is given by Pout = Teω, while the input power is given by Pin = VaIa. Once we have Pout and Pin, we can calculate the efficiency.
(c) The inductance values of the machine affect the motor's performance in several ways. For example, increasing the armature inductance will decrease the current ripple and improve the motor's performance at high speeds. However, it will also increase the time constant of the motor and slow down its response to changes in load. Increasing the field inductance will increase the motor's torque constant and improve its low-speed performance, but it will also increase the time constant and slow down the motor's response to changes in field current. Overall, the inductance values must be carefully chosen to balance the motor's performance requirements with its dynamic response characteristics.
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question:
The shunt dc machine is used to control the speed of a constant torque load. Rr The parameters of the machine are given as Ra = 0.58 Ω, La = 1.5 m H, Lf = 45 m H, k, = 0.95 Nm The machine was connected to a constant voltage with Va 120 Vdo The machine is connected to a constant 3.5 Nm torque load with a desired speed of 3200 RPM. Analytically find: (a) 10pts. Find the field resistance, R, (b) 10pts. The efficiency of the motor,'-P,P- (c) 10pts. Discuss how the inductance values effect the quantities in parts (a), (b), and your simulation results.
Jackson throws a football 30 meters at a speed of 15 m/s. How long was the football in the air before Laurence caught it for touchdown
Answer:
2s
Explanation:
Given parameters:
Distance = 30m
Speed = 15m/s
Unknown:
Time before Laurence caught it = ?
Solution:
To solve this problem;
Speed = \(\frac{disance }{time}\)
Time taken = \(\frac{distance }{speed }\) = \(\frac{30}{15}\) = 2s
The time it takes is 2s
Given:
30 metersSpeed of 15 m/sWe will solve:
Speed = \(\frac{distance}{time}\)
Time taken = \(\frac{distance}{time}\) = \(\frac{30m}{15m/s}\) = 2s
The time it takes is 2s
. The average human walks at a speed of 5 km per hour. If your PE teacher asks you to walk for 30 minutes in
gym class, how far would you walk (km)?
Answer: 2.5 km
Explanation:
5/2 = 2.5 km
60/2 = 30 mins
if take your commander's instructions literally and don't fire until the whites of the enemy's eyes are just resolvable by your pupil, how far away (in meters) are they when you open fire? assume your target has an eye which is 3.1 cm across, the diameter of your pupil is 4.9 mm, and you are observing at a wavelength of 555 nm.
The enemy is 1,122.6 meters away when you open fire.
We can use the Rayleigh criterion, which states that two point sources are just resolvable if the center of the Airy disk of one is directly over the first minimum of the Airy disk of the other.
The angular resolution is given by:
θ = 1.22 λ/D
where λ is the wavelength of the light, and D is the diameter of the pupil.
θ = 1.22 x (555 x 10^-9 m) / 4.9 x 10^-3 m = 1.38 x 10^-5 radians
Now, we can use trigonometry to determine the distance at which an object of 3.1 cm would subtend an angle of 1.38 x 10^-5 radians:
tan θ = opposite/adjacent
tan (1.38 x 10^-5) = 0.0155 m / distance
distance = 0.0155 m / tan (1.38 x 10^-5) = 1,122.6 meters
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A 0.5 kg cheeseburger is lobbed at a particularly unhappy customer with a force of 10 N.
While it is being thrown, what is the acceleration experienced by the cheeseburger?
Answer in units of m/s2
2000 J of heat is added to a system and 2500 J of work is done on the system. What is the change in internal energy of the system?
Answer:
The change in internal energy of the system is 500 J.
Answer:500J
Explanation:
The F-35B Lightning II is a short-takeoff and vertical landing fighter jet. If it does a vertical takeoff to 20.00-m height above the ground and then follows a flight path angled at 26o with respect to the ground for 25 km, what is the final displacement in meters
The final displacement of the F-35B Lightning fighter jet is determined as 24,991.2 m.
Displacement of the flight
The displacement of the flight is calculated from triangle method of vector addition as follows;
Let the vertical take off = first length of triangleLet the flight path at 26⁰ = second length of triangleLet the displacement = third side of triangleAngle between the first two sides = 90 - 26⁰ = 64⁰
r² = a² + b² - 2abcosR
r² = 20² + 25000² - (2 x 20 x 25000) x cos(64)
r² = 624,562,028.9
r = 24,991.2 m
Thus, the final displacement of the F-35B Lightning fighter jet is determined as 24,991.2 m.
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A circular coil of wire of radius 2 cm and which has 80 turns, is connected to a galvanometer in a closed circuit. A magnet creating a magnetic field of 50mT is pulled quickly from inside the coil until it is far enough away from the coil so that the field inside the coil is zero. The time it takes for the magnetic to move is 0,2s. Calculate the reading on the galvanometer.
-3.1415 x 10^(-4) V is the reading on the galvanometer.
To calculate the reading on the galvanometer, we need to determine the induced emf (electromotive force) in the coil due to the changing magnetic field. The induced emf can be found using Faraday's law of electromagnetic induction, which states that the induced emf is equal to the rate of change of magnetic flux through the coil.
The magnetic flux through a circular coil is given by the formula: Φ = B * A * cosθ, where B is the magnetic field, A is the area of the coil, and θ is the angle between the magnetic field and the normal to the coil.
In this case, as the magnet is moved away from the coil, the magnetic field inside the coil changes. Initially, when the magnet is inside the coil, the magnetic field inside the coil is non-zero. However, as the magnet is pulled away, the magnetic field inside the coil decreases until it reaches zero when the magnet is far enough away.
Given that the radius of the coil is 2 cm, the area can be calculated as A = π * r^2 = π * (0.02 m)^2 = 0.0012566 m^2. The magnetic field is 50 mT, which is equivalent to 0.05 T.
Now, we need to calculate the change in flux (∆Φ) during the time interval of 0.2 seconds. As the magnetic field inside the coil changes from non-zero to zero, the change in flux is equal to the initial flux through the coil.
∆Φ = B * A * cosθ = 0.05 T * 0.0012566 m^2 * 1 = 6.283 x 10^(-5) Wb
Finally, we can calculate the induced emf using Faraday's law:
emf = -∆Φ/∆t = -(6.283 x 10^(-5) Wb)/(0.2 s) = -3.1415 x 10^(-4) V
The negative sign indicates that the direction of the induced current in the coil is such that it opposes the change in magnetic flux.
The reading on the galvanometer will be equal to the magnitude of the induced emf, which is 3.1415 x 10^(-4) V.
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Which of these results in kinetic energy of an object? (1 point)
Oposition
O motion
O mass
volume
Answer:
B. Motion
Explanation:
Kinetic energy is a property of a moving object or particle and depends on the motion and its mass.
Hope this helps!
A student doing an experiment spilled some salt and sugar into the sink. How should these substances be cleaned up?
Answer:
I guess rinse it out and wipe it up. It's not a hazardous substance so there's nothing to worry about.
These substances should be cleaned up rinsing the area or removing the compounds with a cloth and dispose of it in the trash.
Sugar is a chemical compound also called sucrose. Its chemical formula is C12H22O11. This compound is normally used to sweeten foods.
On the other hand, common salt is a chemical compound. Its chemical formula is NaCl. This compound is normally used to give food a salty taste.
According to the above, in which a student spilled some salt and sugar in the sink and does not know how to clean it, it can be concluded that the proper way to clean these chemical compounds is by rinsing the area or removing the compounds with a cloth and dispose of it in the trash because neither of them represents biological, chemical or physical risks and a specialized treatment is not required for them.
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\( \frac{1}{(1 - \sqrt{3) {}^{2} } } \)
Answer:
\frac{2+\sqrt{3}}{2}
Explanation:
so we simplify tthe denominator first
\((1-\sqrt{3})^2=\)\(4-2\sqrt{3}\)
so the new fraction is:\(\frac{1}{4-2\sqrt{3}}\)
We'll ratinalize the fraction to get: \(\frac{2+\sqrt{3}}{2}\)
Two forces whose resultant is 100N are at right angle to eachother. if one of them makes an angle of 30° with the resultant, determine its magnitude
Let F₁ and F₂ denote the two forces, and R the resultant force.
F₁ and F₂ point perpendicularly to one another, so their dot product is
F₁ • F₂ = 0
We're given that one of these vectors, say F₁, makes an angle with R of 30°, so that
F₁ • R = ||F₁|| ||R|| cos(30°)
But we also have
F₁ • R = F₁ • (F₁ + F₂) = (F₁ • F₁) + (F₁ • F₂) = F₁ • F₁ = ||F₁||²
So, knowing that ||R|| = 100 N, we get that
(100 N) ||F₁|| cos(30°) = ||F₁||²
(100 N) cos(30°) = ||F₁||
||F₁|| ≈ 86.6 N
(And the same would be true for F₂.)
In flight, a rocket is subjected to four forces; weight, thrust, lift, and drag. Forces are vector quantities that have both a magnitude
and a direction. Imagine that the rocket is about to lift off the launch pad. According to Newton's third law of motion, what force is
critical to the success of its upward motion?
A)
drag
B)
Lift
c)
thrust
D)
weight
Answer:
thrust
Explanation:
Answer:
thrust
Explanation:
3. a) Your body is made up of several simple machines that help you move. Identify three
parts of your body that act as simple machines. Identify the kind of machine for each one
and explain what it does.
Answer:
Explained below
Explanation:
1) The human arm: This is a type of simple machine called "Lever". In this type of machine, the elbow acts as the fulcrum, the palm serves as the load because that's where we place the load we want to carry. While the inner part of the arm which is the inner part of the elbow represents the effort because that is the joint we mover when making use of our arms.
2) Pulleys: An example of this in the human body is the knee cap where the direction of an applied force is changed. Thus means as it is in motion, it alters the direction for which the quadriceps tendon pulls on the tibia.
3) wheel and axle: An example of this in the human body is the lateral rotation of the shoulder joint medial. The humerus which is the bone between the shoulder and elbow will act as the axle while the rotator will be the will because when it is rotated a little bit, the humerus will move along with it.
An open system starts with 52 J of mechanical energy. The energy changes
to 45 J of mechanical energy and 2 J of thermal energy. What is the final total
energy of the system?
A. 50 J
B. 54 J
C. 47 J
O D. 9 J
Answer:
ITS C 47
Explanation:
we will explore more this equation. we need to solve this for all masses! you should recognize now that this system of linear equations can be written in a matrix form. we will define the variable
The coefficients of the variables in each equation can be arranged in a row to create the coefficient matrix. A constant term should always be written on the right in standard form for each equation.
A coefficient matrix, a variable matrix, and a constant matrix can all be used to describe a system of linear equations in matrix form.
Think about the system,
2x+3y=8
5x−y=−2
X and Y are the variables that we have. As a result, the variable matrix can be written as [xy].
The constant terms from the equations, 8 and 2, are on the right side of the equivalence. The first and second rows of the constant matrix are occupied by the two integers in that order since they are the ones that correspond to the first and second equations. The matrix then takes the form [82].
The system is now represented by the equation [2531] [xy] = [82].
Now, the system is denoted as [2531] [xy]=[82].
You can see that the matrix representation is identical to the system of equations using matrix multiplication.
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A rocket in deep space is travelling at 83 m/s [Right]. The empty rocket has a mass of 4739 kg and is carrying an extra 155 kg of fuel. The rocket needs to have a final velocity at an angle of [Right 16 Up]. The engine can only eject the fuel perpendicular to the motion of the rocket (ie, straight down relative to the rocket). How fast must the 155 kg of fuel be ejected to achieve the desired course?
To solve this problem, we can use the conservation of momentum. The momentum of the rocket and the ejected fuel must be conserved before and after the ejection of the fuel.
Let's first find the initial momentum of the system. The rocket's velocity is 83 m/s to the right, and its mass is 4739 kg. Therefore, the initial momentum of the rocket is:
p1 = m1 * v1 = 4739 kg * 83 m/s = 393137 kg m/s [Right]
The fuel has no initial velocity, so its initial momentum is zero.
How fast must the 155 kg of fuel be ejected to achieve the desired course?The final momentum of the system must be equal to the initial momentum, since there are no external forces acting on the system. The final momentum is the sum of the momentum of the rocket and the momentum of the ejected fuel. Let's assume that the fuel is ejected with a velocity of v2 [Down]. The mass of the fuel is 155 kg.
The momentum of the rocket after the ejection of the fuel can be calculated using trigonometry. The velocity of the rocket after the ejection of the fuel has two components: one in the x-direction (right), and one in the y-direction (up). The velocity in the x-direction is the same as the initial velocity, since there are no external forces acting on the rocket in the x-direction. The velocity in the y-direction can be calculated using the final angle:
vy = v1 * tan(16°) = 0.293 * v1
Therefore, the final velocity of the rocket is:
v_final = sqrt((v1)^2 + (0.293*v1)^2) = 86.20 m/s
The final momentum of the system is:
p2 = (m1 + m2) * v_final
where m2 is the mass of the ejected fuel. We can solve for the velocity of the ejected fuel, v2, using the conservation of momentum equation:
p1 = p2
m1 * v1 = (m1 + m2) * v_final + m2 * v2
Substituting the values we have calculated, we get:
4739 kg * 83 m/s = (4739 kg + 155 kg) * 86.20 m/s + 155 kg * v2
Solving for v2, we get:
v2 = 974.64 m/s [Down]
Therefore, the fuel must be ejected at a velocity of 974.64 m/s [Down] to achieve the desired course.
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What is the mathematical equation for the electric force between two charges? Identify each variable.
Answer: F=kq1q2/r2
"F" is the resulting force between the two charges. The distance between the two charges is "r." The "r" actually stands for "radius of separation" but you just need to know it is a distance. The "q1" and "q2" are values for the amount of charge in each of the particles.
Explanation:
The mathematical equation for the electric force between two charges will be ,\(\rm F = \frac{K q_1q_2}{r^2}\). It is a type of attractive force.
What is electric force?The electric force between the two charges is directly proportional to the product of the charge and inversely proportional to the square of the distance between them.
The electric force is found as;
\(\rm F = \frac{K q_1q_2}{r^2}\)
q₁ is the magnitude of charge 1
q₂ is the magnitude of charge 2
k is the proportionality constant
r is the separated distance
F is the electric force
Hence, the mathematical equation for the electric force between two charges will be ,\(\rm F = \frac{K q_1q_2}{r^2}\)
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much like a battery these generate electricity from chemical events
The term you are looking for is "chemical battery". Chemical batteries work by converting chemical energy into electrical energy through a series of chemical reactions. These reactions take place within the battery's cells, which are composed of two electrodes and an electrolyte.
When the battery is connected to a circuit, the chemical reactions produce an electrical current that can be used to power devices. Chemical batteries are widely used in many applications, including consumer electronics, electric vehicles, and renewable energy systems. They are a crucial component of our modern technological society, and ongoing research is focused on developing more efficient and sustainable battery technologies to meet growing energy demands.
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B. What types of energy conversions took place in your body that allowed you to complete the laboratory activity
Answer:
See the explanation below
Explanation:
Energy can neither be created nor destroyed but can be transformed from one form to another.
When we eat food the chemical energy in the food is transformed to kinetic energy that enables us to do work in the laboratory