17) Find sine and cot

Answer:  approximately 3.57 seconds

========================================================

Work Shown:

x = number of seconds

distance = speed*time

250 meters = (70 m/s)*(x seconds)

250 = 70x

70x = 250

x = 250/70

x = 3.57142857142858

x = 3.57

It takes approximately 3.57 seconds for the car to travel 250 meters, when it travels a constant speed of 70 meters per second.

Answer:

The single decimal multiplier is 26%.

Step-by-step explanation:

Since we have given that

You use to increase by 5% followed by 20% increase.

So, the single decimal multiplier would be

Hence, the single decimal multiplier is 26%.

Answer:

thats not a proper equation-

Step-by-step explanation:

None of the given answer options (-10, 10, 16, ¾/1) correspond to the correct slope of -1/2.

To find the slope of the red line given that it is perpendicular to the green line with a slope of 2, we can use the property that perpendicular lines have slopes that are negative reciprocals of each other.

The slope of the green line is 2. To find the slope of the red line, we take the negative reciprocal of 2. The negative reciprocal is obtained by taking the reciprocal (flipping the fraction) and changing the sign.

Reciprocal of 2: 1/2

Negative reciprocal: -1/2

Therefore, the slope of the red line is -1/2.

However, none of the given answer options (-10, 10, 16, ¾/1) correspond to the correct slope of -1/2.

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Answer:

\(274\,\text{in}^3\)

Step-by-step explanation:

\(V=\pi r^2h=\pi(3.75)^2(6.21)\approx274\,\text{in}^3\)

Answer:

She has capped 4 correctly and broke 22.

Look at the paper for solution.

She needs a new job.

Given that;

To find;

Original coordinates of the points:

A (8,15)

B (12,13) and

C (8,10)

Dilated scale factor of 3.

A ⇒ 3x = 3(8)

            = 24 ;

       3y = 3(15)

            = 45 ⇒ A' (24,45)

B ⇒ 3x = 3(12)

            = 36 ;

       3y = 3(13)

            = 39 ⇒ B' (36, 39)

C ⇒ 3x = 3(8)

            = 24 ;

       3y = 3(10)

            = 30 ⇒ C' (24, 30)

Right triangle is formed by the given image. I will therefore use the right triangle's short and long legs to solve for the hypotenuse, or length of CB.

Short leg: B and C's y values

39 - 30 = 9

Long leg: B and C's x values

36 - 24 = 12

a² + b² = c²

9² + 12² = c²

81 + 144 = c²

225 = c²

√225 = √c²

15 = c

The length (distance of point C and B) of CB is 15 units.

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Answer:

10 hours

Step-by-step explanation:

It is given that,

Standard working day is 8 hours

If you were to work 125% of a normal day, then it means that,

\(125\%\ \text{of}\ 8\ \text{hours}\\\\=\dfrac{125}{100}\times 8\\\\=10\ \text{hours}\)

Hence, you will work for 10 hours.

With placing positive integers around the circle. Yes, there exist three integers in consecutive locations around the circle that have a sum greater than or equal to 17.

What exactly is a circle?

A circle is a kind of ellipse with zero eccentricity and two foci that are coincident. A circle is also known as the locus of points drawn at equal distances from the center. The radius of a circle is the distance from its center to its outside line. The diameter of a circle is the line that divides it into two equal sections and is equal to twice the radius.

The equation for a circle in the plane is:

(x-h)^²+ (y-k)² = r²

When the coordinate points are (x, y)

(h, k) is the coordinate of a circle's center.

where r is the circumference of a circle.

where circle area = πr²

Circle circumference=2πr

Now,

First 10 positive integers

that are 1,2,3,4,5,6,7,8,9,10

after putting these in circle 1 and 10 will be adjacent

and

To prove :-there exist three integers in consecutive locations around the circle that have a sum greater than or equal to 17 .

Now as sum of =5+6+7=18

6+7+8=21

7+8+9=24

Hence,

           There exist three integers in consecutive locations around the circle that have a sum greater than or equal to 17.

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Answer:

4x +2

Step-by-step explanation:

4( x + 2)

= 4*x +4*2

= 4x +2

Answer:

Horizontal compression

Step-by-step explanation:

Just took a test

Answer: horizontal compression

Step-by-step explanation:

Edge

Answer:

We need to remember that the Z value comes froma normal standard distribution given by:

\( Z\sim N(\mu=0,\sigma=1)\)

So then the mean is 0 and all the values in the left are negative. So then if we want to analyze that if A is negative then  value of Z indicates that :

B. the number of standard deviations of an observation is to the left of the mean

Step-by-step explanation:

We need to remember that the Z value comes froma normal standard distribution given by:

\( Z\sim N(\mu=0,\sigma=1)\)

And the z score formula is given by:

\(z=\frac{X -\mu}{\sigma}\)

So then the mean is 0 and all the values in the left are negative. So then if we want to analyze that if A is negative then  value of Z indicates that :

B. the number of standard deviations of an observation is to the left of the mean

B. the number of standard deviations of an observation is to the left of the mean

A \(Z\) score is a numerical measurement that describes a value's relationship to the mean of a group of values. The value of the \(Z\) score tells you how many standard deviations you are away from the mean. A negative \(Z\) score reveals the raw score is below the mean average. Also, a negative value of Z indicates that B. the number of standard deviations of an observation is to the left of the mean

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Answer:

C

Step-by-step explanation:

We want to find ratio of the area of the shaded region to the total area of the square.

First, we can find the total area of the square. Since QR = 7, each side of the square measures 7. Therefore, its area is:

\(A=(7)^2=49\text{ units}^2\)

Instead of finding the shaded area, we can find the areas that are not shaded. Subtracting that into the total area will then give us the shaded area.

QRP is a triangle. Since PQRS is a square, QR = 7 = RS = SP = PQ.

So, the area of ΔQRP is:

\(\displaystyle A_{\Delta QRP}=\frac{1}{2}(7)(7)=24.5\)

UTS is also a triangle. We are given that RU = US and PT = TS. So, Points U and T bisect RS and SP, respectively. Since RS = SP = 7, RU = US = PT = TS = 3.5. So, the area of ΔUTS is:

\(\displaystyle A_{\Delta UTS}=\frac{1}{2}(3.5)(3.5)=6.125\)

Therefore, the total area of the white region is:

\(A_{\text{white}}=6.125+24.5=30.625\)

Thus, the shaded region is:

\(A_{\text{shaded}}=49-30.625=18.375\)

Then the ratio of the shaded region to the total area of the square will be:

\(\displaystyle R_{\text{shaded:total}}=\frac{18.375}{49}=\frac{3}{8}\)

Our answer is C.

The rate (in km/h) at which the distance from the plane to the radar station is increasing a minute later is 0 km/h (rounded to the nearest whole number).

To solve this problem, we can use the concepts of trigonometry and related rates.

Let's denote the distance from the plane to the radar station as D(t), where t represents time. We want to find the rate at which D is changing with respect to time (dD/dt) one minute later.

Given:

The plane is flying with a constant speed of 360 km/h.

The plane passes over the radar station at an altitude of 1 km.

The plane is climbing at an angle of 30°.

We can visualize the situation as a right triangle, with the ground radar station at one vertex, the plane at another vertex, and the distance between them (D) as the hypotenuse. The altitude of the plane forms a vertical side, and the horizontal distance between the plane and the radar station forms the other side.

We can use the trigonometric relationship of sine to relate the altitude, angle, and hypotenuse:

sin(30°) = 1/D.

To find dD/dt, we can differentiate both sides of this equation with respect to time:

cos(30°) * d(30°)/dt = -1/D^2 * dD/dt.

Since the plane is flying with a constant speed, the rate of change of the angle (d(30°)/dt) is zero. Thus, the equation simplifies to:

cos(30°) * 0 = -1/D^2 * dD/dt.

We can substitute the known values:

cos(30°) = √3/2,

D = 1 km.

Therefore, we have:

√3/2 * 0 = -1/(1^2) * dD/dt.

Simplifying further:

0 = -1 * dD/dt.

This implies that the rate at which the distance from the plane to the radar station is changing is zero. In other words, the distance remains constant.

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It would take 18 days for 4 workers to complete the job.

Step-by-step explanation:

As d goes up, w goes down by the same amount.

X = 9*8 = 72

18*4 = 72

likewise, 2*36 = 72

3*24 = 72

6*12 = 72

And so on....

Given :

Center of sphere , C( 1 , -1 , 6 ) .

To Find :

Find equations of the spheres with center (1, −1, 6) that touch the following planes.a) xy-plane b) yz-plane c) xz-plane .

Solution :

a)

Distance of the point from xy-plane is :

d = 6 units .

So , equation of circle with center C and radius 6 units is :

\((x-1)^2+(y-(-1))^2+(z-6)^2=6^2\\\\(x-1)^2+(y+1)^2+(z-6)^2=36\)

b)

Distance of point from yz-plane is :

d = 1 unit .

So , equation of circle with center C and radius 1 units is :

\((x-1)^2+(x+1)^2+(z-6)^2=1^2\\\\(x-1)^2+(x+1)^2+(z-6)^2=1\)

c)

Distance of point from xz-plane is :

d = 1 unit .

So , equation of circle with center C and radius 1 units is :

\((x-1)^2+(x+1)^2+(z-6)^2=1^2\\\\(x-1)^2+(x+1)^2+(z-6)^2=1\)

Hence , this is the required solution .

Answer:

yeah it is b

acute and scalene

Step-by-step explanation:

scalene means none of the sides equal

and also all sides are acute angles

Answer:

yep you are correct it would be answer b

Step-by-step explanation:

hope this helped you

The length of the hypotenuse is 7m.

Let the side opposite to 30° be the shortest leg.

The side opposite to 60° is the longest leg.

So, the side opposite to 90° is hypotenuse.

Length of the shortest side is x.

Length of longest side is \(\sqrt{3}x\)

Length of the hypotenuse is 2x.

We know x = 7

So, \(\sqrt{3}(x)=\sqrt{3}(7)\)

Thus, the length of the longer leg is \(\sqrt{3}(7)\) m

Length of hypotenuse = 2x = 2(7) = 14m

\(x^{2} +(\sqrt{3} x)^2 =(2x)^2\\\\(7)^2+(\sqrt{3} (7))^2=(2x)^2\\\\49 + (3(49)) = (2x)^2\\\\49 + 147= (2x)^2\\\\(2x)^2=196\)

Taking square root on both sides:

\(2x = \sqrt{196}\)

2x = 14

x = 7

Therefore, the length of the hypotenuse is 7m.

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Answer:

95.4%

Step-by-step explanation:

Z(low)=-2 0.022750132

Z(upper)=2 0.977249868

Using the it's formula, the total opportunity cost of three unit(s) of tanks is of 350 autos.

The opportunity cost formula is given by:

C = F - A.

In which:

For this problem, we have that:

Thus:

F = 1000 - 650 = 350.

The total opportunity cost of three unit(s) of tanks is of 350 autos.

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Let's start by calculating the probability of winning no prize with one eligible purchase, which is:

P(no prize) = 1 - 0.117 = 0.883

a) The probability of winning at least three prizes in 29 purchases can be calculated using the binomial distribution:

P(X ≥ 3) = 1 - P(X < 3) = 1 - [P(X = 0) + P(X = 1) + P(X = 2)]

where X is the number of prizes won in 29 purchases. We can use the binomial probability formula to calculate each of these individual probabilities:

P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)

where n = 29 is the number of purchases, p = 0.117 is the probability of winning a prize, and C(n, k) is the number of ways to choose k prizes out of n purchases. Using a calculator or software, we can find:

P(X = 0) ≈ 0.183

P(X = 1) ≈ 0.315

P(X = 2) ≈ 0.267

Therefore,

P(X ≥ 3) ≈ 1 - (0.183 + 0.315 + 0.267) ≈ 0.234

So the probability of winning at least three prizes in 29 purchases is approximately 0.234.

b) The probability of winning more than six prizes can be calculated using a similar method:

P(X > 6) = 1 - P(X ≤ 6) = 1 - [P(X = 0) + P(X = 1) + ... + P(X = 6)]

Using a calculator or software, we can find:

P(X > 6) ≈ 1 - 0.996 ≈ 0.004

So the probability of winning more than six prizes in 29 purchases is approximately 0.004.

c) The probability of winning one prize or fewer can be calculated as:

P(X ≤ 1) = P(X = 0) + P(X = 1)

Using the binomial probability formula, we can find:

P(X = 0) ≈ 0.183

P(X = 1) ≈ 0.315

Therefore,

P(X ≤ 1) ≈ 0.183 + 0.315 ≈ 0.498

So the probability of winning one prize or fewer in 29 purchases is approximately 0.498.

Answer: We can use the binomial distribution to solve this problem. Let X be the number of prizes won in 29 purchases, and p be the probability of winning a prize with any eligible purchase, which is 0.117.

a) The probability of winning at least three prizes is:

P(X ≥ 3) = 1 - P(X < 3)

To find P(X < 3), we can use the binomial cumulative distribution function with n = 29, p = 0.117, and x = 2:

P(X < 3) = F(2; 29, 0.117) = 0.906

Therefore, P(X ≥ 3) = 1 - 0.906 = 0.094 (rounded to three decimal places).

b) The probability of winning more than six prizes is:

P(X > 6) = 1 - P(X ≤ 6)

To find P(X ≤ 6), we can use the binomial cumulative distribution function with n = 29, p = 0.117, and x = 6:

P(X ≤ 6) = F(6; 29, 0.117) = 0.985

Therefore, P(X > 6) = 1 - 0.985 = 0.015 (rounded to three decimal places).

c) The probability of winning one prize or fewer is:

P(X ≤ 1) = F(1; 29, 0.117) = 0.698 (rounded to three decimal places).

Therefore, the answer is 0.698 (rounded to three decimal places).

Step-by-step explanation:

Answer:

The answer is X

Step-by-step explanation:

Sike, I aint finna help you. What you thoguht this was? A cheating website, get yo lil ah off this shi

Answer:

D. 10 units

Step-by-step explanation:

Answer:

Step-by-step Solution:

Hence, Option B is correct.

Answer: 0.166666667 yards OR 0.1524 meters OR 0.5 feet

Step-by-step explanation:

1 / 6 = 0.166666667 yards

1 yard = 0.9144 meters

0.9144 / 6 = 0.1524 meters

1 yard = 3 feet

3 / 6 = 0.5 feet

The annual sales is 322,511.6 in 4 years.

A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.

Given that;

Record sales are increasing by 6% each year.

And, 260,090 records were sold this year.

Now, We have;

Record sales are increasing by 6% each year.

Hence, After 4 years;

The annual sales = 260,090 + 4 × 6% of 260,090

                           = 260,090 + 4 × 6/100 × 260,090

                           = 260,090 + 62,421.6

                           = 322,511.6

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Answer:328,358

Step-by-step explanation:

Answer:

y = 5.25x + 4

Step-by-step explanation:

(hours, money)

(6, 34.50)

(8, 46.00)

Slope: change in y/change in x

11.5/2

5.25

Y - intercept: b

46 = 5.25(8) + b

46 = 42 + b

4 = b

Put it all together

A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(x^{4}\)+ c\(x^{3}\). The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set.

Part A: A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(x^{4}\)+ c\(x^{3}\). The coefficient of the highest degree term (x^5) must be non-zero and all the terms must be written in descending order of the degree. This is the definition of standard form for polynomials.

Part B: The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set. In this case, the set is polynomials and the operation is subtraction. An example of this property can be seen by subtracting two polynomials, such as 4\(x^{2}\) + 3x - 5 and \(x^{2}\) + 2. The result of this subtraction would be 3\(x^{2}\) + 3x - 5, which is also a polynomial and therefore an element of the set, demonstrating the closure property.

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A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(y^{2}\)+ c. The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set.

Part A: A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(y^{2}\)+ c. The coefficient of the highest degree term (\(x^{5}\)) must be non-zero and all the terms must be written in descending order of the degree. This is the definition of standard form for polynomials.

Part B: The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set. In this case, the set is polynomials and the operation is subtraction. An example of this property can be seen by subtracting two polynomials, such as 4\(x^{2}\) + 3x - 5 and  + 2. The result of this subtraction would be 3\(x^{2}\) + 3x - 5, which is also a polynomial and therefore an element of the set, demonstrating the closure property.

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