Just answer it, dont have to show work, will mark brainly

The no. of ways to select the 3 blue balls and 5 orange balls from the urn is 0.424

No. of Blue balls in the urn = 5

No. of Orange balls in the urn = 7

Total no. of balls in the urn = No. of blue balls + No. of orange balls

                                             = 5 + 7

                                            = 12 balls

No. of blue balls to be selected = 3

No. of orange balls to be selected = 5

No. of balls to be selected = 8

The total. no of ways 8 balls can be selected = 12C₈

The No. of ways 3 blue balls can be selected = 5C₃

The No. of ways 5 orange balls can be selected = 7C₅

Therefore, No. of ways to select 3 blue balls and 5 orange balls from the urn

                       =  5C₃ x  7C₅ / 12C₈

[ Probability = No. of ways to select blue balls x No. of ways to select orange balls / Total no. of ways to select balls]

                P = 10 x 21 / 495

                   = 210 / 495

                P = 0.424

Therefore,  the no. of ways to select blue and orange balls is 0.424

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Answer:

0.7

I hope this helps!

The given statement "In performing a lower-tailed z-test for one mean, the value of the test statistic was z=0.51, which would yield a p-value of 0.695." is true because we perform null hypothesis.

In a lower-tailed z-test for one mean, we test a null hypothesis that the population mean (μ) is greater than or equal to a certain value, against an alternative hypothesis that the population mean is less than that value.

To perform the test, we calculate the z-test statistic using the sample mean, sample standard deviation, sample size, and the hypothesized population mean. If the calculated z-test statistic falls in the rejection region (below the critical value), we reject the null hypothesis and conclude that the population mean is less than the hypothesized value.

In this case, the calculated z-test statistic is 0.51, which falls in the non-rejection region (above the critical value) for a lower-tailed test with a significance level of 0.05. Therefore, the p-value is greater than 0.05, and we do not reject the null hypothesis. The statement that the p-value is 0.695 is consistent with this conclusion.

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The probability that the coin was heads is 27/50 and the probability that the number cube was 5 is 16/50.

To find the probability that the coin was heads, we need to calculate the number of times the coin landed heads and divide it by the total number of trials (50 in this case).

From the table, we can see that the coin landed heads a total of 5 + 3 + 5 + 3 + 5 + 6 = 27 times out of 50 trials.

Therefore, the probability that the coin was heads is 27/50.

To find the probability that the number cube landed on 5, we need to calculate the number of times the number cube landed on 5 and divide it by the total number of trials (50 in this case).

From the table, we can see that the number cube landed on 5 a total of 5 + 5 + 6 = 16 times out of 50 trials.

Therefore, the probability that the number cube was 5 is 16/50.

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The missing terms in the given factorized expression are:

3x²y + 12xy² + 9xy = 3xy ( x + 4y + 3 )

An expression in math is a sentence with a minimum of two numbers or variables and at least one math operation.

We have,

_ x²y + _ y² + 9 _ = 3x _ ( _ + 4y + _ )

We need to fill the boxes and make sure that both sides are equal.

We will remove the bracket on the right side.

i.e 3x _ _ + 12xy_ + 3x_ _

Now,

_ x²y + _ y² + 9 _ = 3x _ _ + 12xy_ + 3x_ _

We will make,

_ x²y  and 3x _ _ equal.

_ y²  and 12xy_ equal.

9 _  and + 3x_ _ equal.

So,

(3)x²y = 3x (x)(y)

(12x)y² = 12xy(y)

9 (xy) = 3x(y)(3)

Thus the missing terms in the given factorized expression are:

3x²y + 12xy² + 9xy = 3xy ( x + 4y + 3 )

3x²y + 12xy² + 9xy = 3x²y + 12xy² + 9xy

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To find the variance of the coefficient on x1 given SSR (sum of squared residuals), total variation in x1, and correlation between x1 and x2, we can use the following formula:

Var(b1) = (SSR / (n-2)) / [Sxx(1 - r^2)]

where b1 is the coefficient on x1, n is the sample size, SSR is the sum of squared residuals, Sxx is the total variation in x1, and r is the correlation between x1 and x2.

To calculate the total variation in x1 (Sxx), we need to subtract the square of the mean of x1 from the sum of squares of x1 values.

Sxx = Σ(x1 - \(\.x1_{mean}\))^2

Once we have calculated Sxx and SSR, we can use the formula above to find the variance of the coefficient on x1. This tells us how much the coefficient on x1 is likely to vary in different samples taken from the population.

In summary, the variance of the coefficient on x1 can be calculated using the formula Var(b1) = (SSR / (n-2)) / [Sxx(1 - r^2)], where Sxx is the total variation in x1, SSR is the sum of squared residuals, n is the sample size, and r is the correlation between x1 and x2.

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It is given that:

1) f(g(x)) will be:

2)The domain will be all real numbers except x=-4.

3)g(f(x)) will be:

4) The domain of g(f(x)) is:

5) f(f(x)) is given by:

6)The domain of f(f(x)) is:

7) g(g(x)) is calculated as:

8)The domain of g(g(x)) is:

The new mean of the given data is 47, and the new standard deviation for the same data is 10.

When each score in a set of data is multiplied by 5 and then 7 is added to the result, the transformation can be described as follows:

New Score = (Original Score * 5) + 7

To find the new mean, we need to apply this transformation to the original mean. Since the original mean is 8, the new mean can be calculated as:

New Mean = (Original Mean * 5) + 7

= (8 * 5) + 7

= 40 + 7

= 47

Next, to find the new standard deviation, we need to consider the effect of the transformation on the original standard deviation. Since multiplying the data by a constant (5 in this case) scales the standard deviation, the new standard deviation can be calculated as:

New Standard Deviation = Original Standard Deviation * 5

= 2 * 5

= 10

Therefore, the new mean of the data is 47, and the new standard deviation is 10.

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32 - 7 = 25/5 = 5

so, we have 5 products being purchased, since the 7 sec check-out doesn't count as product time.

hope it helps :)

Answer:

5 items

Step-by-step explanation:

32 - 7 = 25

25 / 5 = 5

This means that 5 items are being purchased.

Hope it helps c:

There is a 50% chance that the person selected is female.

Let's assume that there are 50 students in the class and of them, 25 are female and 25 are male.

The probability that the person selected is female will be calculated by the formula P(Female) = 25/50 = 0.5

Therefore, the probability that the person selected is female is 0.5 or 50%. This means that if a person is randomly selected from the front, middle portion of the class, there is a 50% chance that the person selected is female.

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Complete question:

What is the gender ratio of the people in the class?

Answer:

b

Step-by-step explanation:

rude people delete meh answers

rude the answer is b

thank u very much now i must b on my way

Answer:

Its B

Step-by-step explanation:

Because the first one is correct give the credit to her.

The length of the line drawn between points (3, 10) and (7, 7) is 13.454 unit length.

The length of the line is described by the distance formula which is described as below:

d = √ ( x₂ - x₁ )² + ( y₂ - y₁ )²

where x is the x coordinates of the points

y is the y coordinates of the points

Coordinates of first point = (3, 10)

Coordinates of second point = (7, 7)

x₁ = 3

x₂ = 7

y₁ = 10

y₂ = 7

d = √ (3 - 7)² + (10 - 7)²

d = √ 16 + 9

d = √ 25

d = 5 unit length

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a. The class width for all intervals in this frequency distribution is 3.

b. Calculating the class midpoints for all intervals, we get:

32-35: 33.5

36-39: 37.5

40-43: 41.5

44-47: 45.5

48-51: 49.5

52-55: 53.5

56-59: 57.5

c. Calculating the class boundaries for all intervals, we get:

32-35: 30.5-36.5

36-39: 34.5-39.5

40-43: 38.5-43.5

44-47: 42.5-47.5

48-51: 46.5-51.5

52-55: 50.5-55.5

56-59: 54.5-59.5

The number of full oscillations that any wave element performs in one unit of time is how we determine the frequency of a sinusoidal wave.

To find the class width, class midpoints, and class boundaries for the given frequency distribution, let's analyze the temperature intervals and frequencies:

Temperature (°F)    Frequency

32-35                      1

36-39                      3

40-43                      5

44-47                      11

48-51                      7

52-55                      7

56-59                      1

(a) Class width:

The class width is the difference between the upper and lower boundaries of each temperature interval. In this case, all the intervals have the same width.

Class width = Upper boundary - Lower boundary

For example, in the first interval (32-35), the lower boundary is 32 and the upper boundary is 35.

Class width = 35 - 32 = 3

The class width for all intervals in this frequency distribution is 3.

(b) Class midpoints:

The class midpoint is the average value of the upper and lower boundaries of each interval. It represents the central value of the interval.

Class midpoint = (Upper boundary + Lower boundary) / 2

For example, in the first interval (32-35), the lower boundary is 32 and the upper boundary is 35.

Class midpoint = (35 + 32) / 2 = 33.5

Calculating the class midpoints for all intervals, we get:

32-35: 33.5

36-39: 37.5

40-43: 41.5

44-47: 45.5

48-51: 49.5

52-55: 53.5

56-59: 57.5

(c) Class boundaries:

The class boundaries are the values that separate each interval. They are calculated by adding or subtracting half of the class width from the upper and lower boundaries.

For example, in the first interval (32-35), the lower boundary is 32 and the upper boundary is 35, and the class width is 3.

Lower class boundary = Lower boundary - (0.5 * class width) = 32 - (0.5 * 3) = 32 - 1.5 = 30.5

Upper class boundary = Upper boundary + (0.5 * class width) = 35 + (0.5 * 3) = 35 + 1.5 = 36.5

Calculating the class boundaries for all intervals, we get:

32-35: 30.5-36.5

36-39: 34.5-39.5

40-43: 38.5-43.5

44-47: 42.5-47.5

48-51: 46.5-51.5

52-55: 50.5-55.5

56-59: 54.5-59.5

Note: The class boundaries are inclusive of the lower boundary and exclusive of the upper boundary.

These are the calculations for the class width, class midpoints, and class boundaries for the given frequency distribution.

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To find the class width, subtract the lower class limit from the upper class limit. To find the class midpoints, add the lower and upper class limits and divide by 2. To find the class boundaries, subtract 0.5 from the lower class limit and add 0.5 to the upper class limit.

(a) Class width:

To find the class width, we subtract the lower class limit from the upper class limit. For example, the class width for the first class interval (32-35) is 35 - 32 = 3.

(b) Class midpoints:

To find the class midpoints, we add the lower class limit and the upper class limit and divide the sum by 2. For example, the class midpoint for the first class interval (32-35) is (32 + 35) / 2 = 33.5.

(c) Class boundaries:

To find the class boundaries, we subtract 0.5 from the lower class limit and add 0.5 to the upper class limit. For example, the class boundaries for the first class interval (32-35) are (32 - 0.5) and (35 + 0.5).

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Answer:

Step-by-step explanation:

2x + 12 + x + 1 + x+ 4

2x + x + x = 4x

12 + 1 + 4 = 17

Answer:

118.3

Step-by-step explanation:

The formula for the area is a triangle is base*height/2

Area = 18.2*13/2 = 118.3

Answer:

118.3

1/2b×h

1/2(13)x18.2

6.5×18.2

118.3m^2

Answer:

y = 6x + 10

Isaiah makes $34.00 after working for 4 hours.

Step-by-step explanation:

Slope intercept form is y=mx+b

In this situation the equation would look like so, x = amount of hours:

y = 6x + 10

To solve for how much Isaiah earns after 4 hours plug in 4 instead of x.

y = 6(4) + 10

y = 24 + 10

y = 34

Isaiah makes $34.00 after working for 4 hours.

Hope that helps and have a great day!

The total cost of power generation for a specific load demand can be calculated by optimally allocating the load demand to each unit based on their power output limits. The allocation is done in a way that minimizes the overall cost while meeting the load demand.

In the given power system depicted in Figure 1, there are three units that are always running. Each unit has specific characteristics regarding their minimum power output (Pmin), maximum power output (Pmax), and incremental cost (Ci). Let's discuss the characteristics of each unit and calculate the total cost of power generation for a given load demand.

Unit 1:

Pmin = 200 MW

Pmax = 500 MW

Ci = $50/MWh

Unit 2:

Pmin = 150 MW

Pmax = 400 MW

Ci = $40/MWh

Unit 3:

Pmin = 100 MW

Pmax = 300 MW

Ci = $30/MWh

To calculate the total cost of power generation for a given load demand, we need to determine the optimal power output for each unit. We start by considering the units with the lowest incremental cost first.

Suppose the load demand is D MW. We allocate the load demand to the units as follows:

Step 1: Check if Unit 1 can meet the load demand within its power range. If yes, allocate the load demand to Unit 1 and calculate the cost:

Cost1 = Ci * P1, where P1 is the power output of Unit 1.

Step 2: If there is still remaining load demand, allocate it to Unit 2:

Cost2 = Ci * P2, where P2 is the power output of Unit 2.

Step 3: If there is still remaining load demand, allocate it to Unit 3:

Cost3 = Ci * P3, where P3 is the power output of Unit 3.

Finally, the total cost of power generation, Cost_total, is the sum of Cost1, Cost2, and Cost3:

Cost_total = Cost1 + Cost2 + Cost3

To find the optimal power output for each unit, we consider the load demand and compare it to the minimum and maximum power output limits for each unit. The power allocation is based on meeting the load demand while minimizing the overall cost of power generation.

In summary, given the characteristics of the three units in the power system (Pmin, Pmax, and Ci), the total cost of power generation for a specific load demand can be calculated by optimally allocating the load demand to each unit based on their power output limits. The allocation is done in a way that minimizes the overall cost while meeting the load demand.

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\((20341)_5\\\\=(2 \times 5^4 + 0 \times 5^3 + 3 \times 5^2 +4 \times 5^1 +1\times 5^0)_{10}\\\\=(2 \times 625+0+3 \times 25 +20 +1)_{10}\\\\=(1250+75+21)_{10}\\\\=(1346)_{10}\)

Answer:

x= (5,0) y= (0,1)

Step-by-step explanation:

Answer:

15πcm

Step-by-step explanation:

2πr = circumference

radius = 0.075m = 7.5cm

Circumference = 7.5X2π

15π cm

Answer:

7(2)-2

=14-2

Which makes it

=12

Answer:

  0

Step-by-step explanation:

Multiplying the first equation by xy, we have ...

  x^2 +y^2 = -xy

Factoring the expression of interest, we have ...

  x^3 -y^3 = (x -y)(x^2 +xy +y^2)

Substituting for xy using the first expression we found, this is ...

  x^3 -y^3 = (x -y)(x^2 -(x^2 +y^2) +y^2) = (x -y)(0) = 0

The value of x^3 -y^3 is 0.

A translatiοn tο hοrizοntal right οf 5 units and vertical up 3 units.

A sequence is a grοuping οf numbers, variable οr "terms". Term examples include 2, 5, but instead 8. Sοme stοry lines can be extended indefinitely by deciding tο take advantage οf a certain pattern that they exhibit.

Use the pattern 2, 5, 8, and then add 3 tο make it lοnger. Fοrmulas exist that shοw where tο glance fοr wοrds in a sequence. In mathematics.

Frοm the graph given we can easily cοnclude that

A translatiοn tο hοrizοntal right οf 5 units and vertical up 3 units

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Answer:

2 (x + 4)(3x - 25)

Step-by-step explanation:

\(6 {x}^{2} - 26x - 200\)

\(3 {x}^{2} - 13x - 100\)

\(2 (x + 4)(3x - 25)\)

Solution

We are given

Distance = 5/2 miles

Time = 1/4 hours

Answer:

The speed would \(10~\text{mph}\).

Step-by-step explanation:

Step 1: State the formulas required

The formula for speed is:

\(\text{Speed}=\frac{\text{Distance}}{\text{Time}}\)

Step 2: Substitute the values into the formula

The distance is \(\frac{5}{2}~\text{miles}\) and the time is \(\frac{1}{4}~\text{hours}\).

Substitute these values into the formula:

\(\text{Speed}=\frac{\text{Distance}}{\text{Time}}\\\text{Speed}=\frac{\frac{5}{2}}{\frac{1}{4}}\\\)

Step 3: Calculate

\(\text{Speed}=\frac{\frac{5}{2}}{\frac{1}{4}}\\\\\text{Speed}={\frac{5}{2}}\div {\frac{1}{4}}\\\\\text{Speed}={\frac{5}{2}}\times 4\\\\\text{Speed}={\frac{20}{2}}\\\\\text{Speed}=10\)

So, the speed is  \(10~\text{miles per hour}\)  or  \(10~\text{mph}\).

1. Instantaneous velocity: The derivative of the height function s(t) with respect to time t gives the instantaneous velocity v(t) = ds/dt = -9.8t.

2. Average velocity: Calculate the average velocity by dividing the change in height by the change in time.
Average velocity = (s(9) - s(0)) / (9 - 0) = (178.2 - 300) / 9 = -13.53 m/s

3. Find the time t when instantaneous velocity equals average velocity:
t = 13.53 / 9.8 ≈ 1.38 seconds
Thus, the instantaneous velocity equals the average velocity at approximately 1.38 seconds during the first 9 seconds of the fall.

To find the time during the first 9 seconds of fall at which the instantaneous velocity equals the average velocity, we need to first find the average velocity.

The average velocity of the object during the first 9 seconds can be found by calculating the displacement (change in height) divided by the time taken:

Average velocity = (s(9) - s(0)) / 9
                = (-4.912(9)^2 + 300 - (-4.912(0)^2 + 300)) / 9
                = (-393.768 + 300) / 9
                = -11.9747 m/s (rounded to 4 decimal places)

Now we need to find the time during the first 9 seconds at which the instantaneous velocity equals -11.9747 m/s.

The instantaneous velocity of the object at any time t can be found by taking the derivative of s(t):

v(t) = s'(t) = -9.824t

We want to find the time t during the first 9 seconds at which v(t) = -11.9747 m/s.

-9.824t = -11.9747
t = 1.2195 seconds (rounded to 4 decimal places)

Therefore, the time during the first 9 seconds of fall at which the instantaneous velocity equals the average velocity is 1.2195 seconds.

Answer: 1.2195 seconds.

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