is phosphorus a pure substance or mixture kid friendly

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Answer:

Francium (Fr), heaviest chemical element of Group 1 (Ia) in the periodic table, the alkali metal group. It exists only in short-lived radioactive forms.

There are various kind of elements that are present in periodic table. Some elements are harmful, some are radioactive, some are noble gases. Francium  belongs to alkali metals group.

Periodic table is a table in which we find elements with properties like metals, non metals, metalloids and radioactive element arranges in increasing atomic number.

Periodic table help a scientist to know what are the different types of elements are present in periodic table so that they can discover the new elements that are not being discovered yet.

Francium is a radioactive element, the electronic configuration of Francium is [ R n] 7s¹. The number of electron in outermost shell s is 1. This shows that francium belongs to group 1 of periodic table that is alkali metals.

Therefore, Francium  belongs to alkali metals group.

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These pollutants consist of dusts, mists, fumes, vapors, and gas, a chemical can enter the body most frequently through inhalation.

What is chemical exposure?

Exposure happens when someone comes into contact with a chemical, either directly or through another substance that has come into contact with the chemical. Visit the ToxFAQs website of the Agency for Toxic Substances and Disease Registry for more details on specific chemicals, such as their potential health effects.

What is hazardous?

Any substance that has the potential to endanger life or health is considered to be a chemical hazard. In the home and in many other places, chemicals are frequently used. Chemical exposure can have negative effects on your health that can be immediate or long-lasting.

These pollutants consist of dusts, mists, fumes, vapors, and gas. A chemical can enter the body most frequently through inhalation.

A respirator or mask that is appropriate for the particular contaminant is part of personal protective equipment (PPE) that offers protection against contaminants that are airborne.

Therefore, these pollutants consist of dusts, mists, fumes, vapors, and gas, a chemical can enter the body most frequently through inhalation.

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The three major categories of energy for electricity generation are fossil fuels (coal, natural gas, and petroleum), nuclear energy, and renewable energy sources.

Answer:

b

Explanation:

Hydrocarbons provide 84% of the world's energy, but they are non-renewable. Hydrocarbons are the most economic form of energy.

The boiling points of HF, H2O and NH3 increase in the order of  NH3 < HF < H2O. Therefore, option D is correct.

​

The melting points and boiling points increase down the group because of the van der Waals forces. The size of the molecules changes down the group. This increase in size intends an increase in the property of the van der Waals forces.

Water can produce more hydrogen bond in comparison to the Hydrogen fluoride and Ammonia . If we see the bond polarity then must be HF > H2O > NH3. But in this condition major finding factor is Hydrogen bond so, the order is NH3 < HF < H2O.

Thus, option D is correct.

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For the first question, we can use the Arrhenius equation: the reaction will proceed 5.50 times faster at 439 K or 166°C than it did at 363 K. the rate constant for the reaction at 71.0°C is 2.10×\(10^3 s^{-1}\)

\(k2/k1 = exp[(Ea/R)((1/T1)-(1/T2))]\)

where k1 and T1 are the rate constant and temperature at which the reaction proceeds at a certain rate, k2 is the desired rate constant, Ea is the activation energy, R is the gas constant, and T2 is the temperature at which we want the reaction to proceed faster.

Let's plug in the given values and solve for T2:

\(5.50 = exp[(61.25 kJ/mol)/(8.314 J/(molK))((1/363 K)-(1/T2))]\)

T2 = 439 K or 166°C

Therefore, the reaction will proceed 5.50 times faster at 439 K or 166°C than it did at 363 K.

For the second question, we can use the Arrhenius equation to calculate the rate constant, k:  the rate constant for the reaction at

   71.0°C is 2.10×\(10^3 s^{-1}\)

\(k = A*exp(-Ea/RT)\)

where A is the frequency factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin.

Let's plug in the given values:

T = (71.0 + 273.15) K = 344.15 K

Ea = 87.7 kJ/mol = 87,700 J/mol

A = 9.18×\(10^1 s^{-1}\)

R = 8.314 J/(mol*K)

k = (9.18×\(10^11 s^{-1}\))exp(-((87,700 J/mol)/(8.314 J/(molK)*344.15 K)))\\k = 2.10×\(10^3 s^{-1}\)

Therefore, the rate constant for the reaction at 71.0°C is 2.10×\(10^3 s^{-1}\).

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The percentage yield of the reaction is equal to 51.27 %.

The yield can be described as a measure of the amount of the product formed in relation to the reactant consumed, formed in a chemical reaction, generally expressed as a percentage.

The percent yield can be defined as a comparison between the actual yield and the theoretical yield based on the chemical equation.

\({\displaystyle {\mbox{percent yield}}={\frac {\mbox{actual yield}}{\mbox{theoretical yield}}}\times 100}\)

Given the theoretical yield of the chemical reaction, = 263 g

The actual yield of the reaction = 121 g

The percentage yield of the reaction can be calculated as:

Percent yield = (121/263) ×100

Percent yield = 51.27 %

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Answer:

A, B & C form the vertices of a triangle.

∠ CAB = 90°, ∠ ABC = 73° and AB = 9.4.

Calculate the length of BC rounded to 3 SF

Answer:

The mass of H2SO4 collected is 92.0g assuming the theoretical yield of H2SO4 is 100g

Explanation:

Assuming the theoretical yield of the sulfuric acid, H2SO4, is 100g.

To solve this question we must use the equation of percent yield:

Percent yield = Actual yield / Theoretical yield * 100

Where percent yield = 92.0%, actual yield is the mass of H2SO4 produced and theoretical yield is 100g, the mass we are assuming

Replacing:

92.0% = Actual yield / 100g * 100

92.0g = Actual Yield

Answer:

C

Explanation:

Measurements are always specific numerical values that you observe. Taking your temperature results in a number. Reading your watch results in a specific time that you get. Weighing a cantaloupe results in a specific measurement in kilograms or pounds. Asking the weather will result in an answer, like sunny or rainy, which aren't specific numerical values.

The following is not an example of making a measurement is asking for weather as it depends on weather reports. option C is correct.

A  weather report is what  tells you about the high and low temperatures for the past day o weather the rain is going to happen or not which can be predict only.

Weather report also tells you the present temperature of the day and may  tell you the average temperature for the day which can only be predict cannot be measured in any aspect.

Therefore, following is not an example of making a measurement is asking for weather as it depends on weather reports. option C is correct.

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Answer:

191.11 grams of oxygen gas should be produced.

Explanation:

The balanced reaction is:

2 Al₂O₃ → 4 Al + 3 O₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Being the molar mass of each compound:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Then you can apply the following rule of three: if by stoichiometry 108 grams of aluminum are produced along with 96 grams of oxygen, 215 grams of aluminum are produced along with how much mass of oxygen?

\(mass of oxygen=\frac{215 grams of aluminum*96 grams of oxygen}{108grams of aluminum}\)

mass of oxygen= 191.11 grams

191.11 grams of oxygen gas should be produced.

The gas under standard temperature and pressure that occupies a volume of 22.4 L when 44.0 grams of the gas is present is carbon dioxide (CO₂). Option 1 is correct.

Under standard temperature and pressure (STP), which is defined as 0 degrees Celsius (273.15 Kelvin) and 1 atmosphere of pressure, 1 mole of any ideal gas occupies a volume of 22.4 liters. In this case, we have 44.0 grams of a gas occupying a volume of 22.4 liters under STP conditions.

To determine the identity of the gas, we need to consider the molar mass. The molar mass of a substance represents the mass of one mole of that substance. In this case, if we have 44.0 grams of a gas, and this mass is equal to the molar mass of the gas, it suggests that we have exactly one mole of the gas.

The molar mass of carbon dioxide (CO₂) is approximately 44.01 grams per mole, which is very close to the given mass of 44.0 grams. Therefore, the gas in question is most likely carbon dioxide (CO₂), as its molar mass matches the given mass, and it satisfies the conditions of occupying a volume of 22.4 liters under STP.

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Complete question:

A gas is held under cοnditiοns οf standard temperature and pressure. It is fοund that 44.0 grams οf the gas οccupies a vοlume οf 22.4 L under these cοnditiοns. What is the gas?  

Selecting resources with reliable credentials and expertise is important for any information you look up on any topic.

There are several factors to consider when selecting resources:

Credentials: The credentials of the author or organization providing the information are important to consider. Look for information from reputable sources such as academic institutions, government agencies, and well-established organizations.

Expertise: The expertise of the author or organization is also important. Look for information from experts in the field who have relevant education and experience.

Date: The date of the information is also important. Look for the most recent information on a topic as older information may be outdated or inaccurate.

Reliability: The reliability of the source should also be considered, look for sources that are peer-reviewed, or have been validated by reputable organization

Bias: Consider the potential bias of the source and how it might affect the information presented.

Purpose: The purpose of the source should also be considered, whether it is for academic, commercial or personal use.

Accessibility: The resource should be available easily, whether is free to access or paid, and it should be in the appropriate format and language.

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The percent composition of boron in diborane (b2h6) is 78% because the mass of boron is higher than hydrogen atom.

Diborane is a poisonous, reactive gas that is produced by the action of acids on borides. Diborane is used as a reducing agent for making other chemicals and also act as a catalyst.

So we can conclude that The percent composition of boron in diborane (b2h6) is 78% because the mass of boron is higher than hydrogen atom.

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The compound diborane can be used as a rocket propellant. the percentage composition of boron in diborane (B2H6) is 75%. Option D. This is further explained below.

Generally, Diborane is simply defined as a compound having the molecular formula B2H6, Diborane is more often known as diborane.

In conclusion, As a rocket fuel, diborane is a useful chemical. Diborane (B2H6) contains 75 percent boron by weight.

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If carbonite existed,  its likely chemical formula will be CO₂²⁻.

The carbonite is liquid substance that is made from the carbon and the oxygen. the carbonite could change in the solid form through rapid freezing. carbonite is used to freeze the good for preservation is called as the carbon freezing. the carbonite is the blasting explosive. so, the carbon freezing is the process in which the liquid carbonite is frozen into the solid state.

Thus, in the movie star wars episode v: the empire strikes back, the character han solo is frozen in the fictional material, carbonite. if carbonite existed,  its likely chemical formula will be CO₂²⁻.

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Answer:

The pressure exerted by a gas is due to the random motion of particles in the gas. Gases have weak intermolecular forces and the particles are in continuous random motion and these particles collide with the walls of the container. These collisions with the walls of the container exert pressure on the gas.

Explanation: Hope this helps!!

Answer:

motion

Explanation:

i just know things

Answer: 19 grams

Explanation:

percent by mass = (mass of part)/(mass of whole) * 100

this means that in this question, 12 = x/160 * 100, where x is the amount of NaCl.

this means 12/100 = x/160, and thus x = (160)(12/100)=19.2 grams

The closest option is B.

Answer:

Second Option: 19 grams

Explanation:

Total solution weight: 160 grams

percent of NaCl in the solution: 12%

You take these two numbers and multiply them with 12 being over 100:

160 * \(\frac{12}{100}\) = 19.2 grams

and then just round to the nearest whole number: 19 grams

Answer:

75240J

Explanation:

Given parameters:

Mass of water  = 300g

Initial temperature of the water  = 85°C

Final temperature  = 25°C

Unknown:

Amount of heat released = ?

Solution:

The amount of heat released in this cooling process can be calculated using the expression below;

     H  = m x c x (t₂  - t₁)

m is the mass

c is the specific heat capacity of water  = 4.18J/g°C

t is the temperature

  Insert the parameters and solve;

 H = 300 x 4.18 x (25  - 85) = -75240J

The negative symbol denotes heat loss.

Matter is the material from which all known physical objects are made. True. Everything in the universe is made of matter

Matter is anything that has mass and occupies space in the universe, both living and non-living things. Matter can be elements, compounds or mixtures and can be changed from one form of matter to another. Matter can be grouped into 3 different states of being namely, solid, liquid, and gas. Examples are water, trees, air, book, and soil.

Each material has certain properties that make it easy to distinguish it from other substances. Material properties can are grouped into two, namely physical properties that can be measured directly and chemical properties related to the ability of a substance to react or change into another substance.

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The density of borosilicate glass is different from the weighted average of the densities of its components because the density of a glass is influenced by its molecular structure and the way its atoms are arranged, rather than a simple weighted average of its components.

Borosilicate glass is a type of glass that contains boron trioxide, which makes it more resistant to thermal expansion and chemical corrosion. When the glass is formed, the components (such as silicon dioxide, boron trioxide, and other metal oxides) are combined at high temperatures, causing them to form a new amorphous material with a unique atomic structure.
The arrangement of atoms and bonding in borosilicate glass is not linear or consistent, and it can differ from the atomic arrangements found in the individual components. This irregular structure results in the overall density of the glass being different from a simple weighted average of the densities of its individual components.
In summary, the density of borosilicate glass is different from the weighted average of the densities of its components due to the unique molecular structure and atomic arrangements that occur when the glass is formed.

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The frequency of a photon with an energy of 4.91 x 10⁻¹⁷ J is approximately 7.41 x 10¹⁶ Hz.

The energy (E) of a photon is given by the equation E = hf, where h is Planck's constant (6.63 x 10⁻³⁴ J·s) and f is the frequency of the photon. To find the frequency, we rearrange the equation to f = E/h.

Substituting the given values, we have f = (4.91 x 10⁻¹⁷ J) / (6.63 x 10⁻³⁴ J·s) ≈ 7.41 x 10¹⁶ Hz.

Therefore, the frequency of the photon is approximately 7.41 x 10¹⁶ Hz (option b).

For the second question, we need to use the Rydberg formula to determine the final level of the electron. The formula is given by 1/λ = R(1/n₁² - 1/n₂²), where λ is the wavelength of the photon emitted, R is the Rydberg constant (2.179 x 10¹⁸ J), and n₁ and n₂ are the initial and final energy levels, respectively.

Rearranging the formula, we have 1/n₂² = 1/λR + 1/n₁². Substituting the given values, we have 1/n₂² = 1/(3745 nm)(2.179 x 10¹⁸ J) + 1/(n₁)².

Simplifying the equation, we find 1/n₂² = 0.0002679 + 1/n₁². Comparing the equation with the given answer choices, we find that the final level of the electron is 5 (option a).

Therefore, the final level of the electron is 5 (option a).

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The concentration of conjugate base in the buffer change after the addition of a small amount of strong base The concentration of conjugate base will increase. HA+BOH ⇒ H2O +AB

Buffer capacity refers to the amount of added acid or base that can be neutralized by a buffer. This is determined by the concentration of the conjugate acid and conjugate base. As these concentrations increase, the buffering capacity increases. A buffer is a solution that can withstand changes in pH due to the addition of acidic or basic components.

Can neutralize small amounts of added acids or bases and keep the pH of the solution relatively stable. When a strong base is added to a buffer the hydroxide ions are consumed by the weak acid, forming water, and consumed by the weak conjugate base of the acid. The number of weak acids decreases and the number of conjugate bases increases.

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Answer:

Option c.

Explanation:

According to Newton's law, formula to solve this problem is:

F = m . a

Mass → 1000 kg

a → 3 m/s²

F = 1000 kg . 3m/s² →  3000 N

1 N = 1 kg .  m/s²  according to SI, Internation System of units.

Answer:  3597 kJ of heat

Explanation:

According to ideal gas equation:

\(PV=nRT\)

P = pressure of gas = 5.00 atm

V = Volume of gas = 8.00 L

n = number of moles = ?

R = gas constant =\(0.0821Latm/Kmol\)

T =temperature =\(25.0^0C=(25.0+273)K=298K\)

\(n=\frac{PV}{RT}\)

\(n=\frac{5.00atm\times 8.00L}{0.0821 L atm/K mol\times 298K}=1.63moles\)

As it is given :

1 mole of propane produces = 2220 kJ of heat

Thus 1.63 moles of propane produces = \(\frac{2200}{1}\times 1.63=3597kJ\)

Thus 3597 kJ of heat is produced

To increase the quantity of HF(g) in the equilibrium mixture for the given reaction, either we increase the temperature or decrease the pressure (option C).

I. Adding H2(g): Adding more H2(g) will shift the equilibrium position to the right according to Le Chatelier's principle. This will increase the quantity of HF(g) in the equilibrium mixture. Therefore, this change will increase the quantity of HF(g).

II. Increasing the temperature: The given reaction is exothermic (ΔH > 0), meaning it releases heat when it proceeds in the forward direction. According to Le Chatelier's principle, increasing the temperature will favor the endothermic direction to absorb the additional heat. In this case, increasing the temperature will shift the equilibrium position to the left, reducing the quantity of HF(g). Therefore, this change will not increase the quantity of HF(g).

III. Decreasing the pressure: The reaction involves gaseous species. According to Le Chatelier's principle, decreasing the pressure will favor the side with more moles of gas. In this case, the reaction produces two moles of HF(g) from one mole each of H2(g) and F2(g). Decreasing the pressure will favor the formation of more moles of gas, which is HF(g). Therefore, this change will increase the quantity of HF(g).

Based on the above analysis, the changes that will increase the quantity of HF(g) are I and III. Therefore, the correct answer is option c. I and II only.

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The reason why Group A elements and Group B elements are different is that they belong to different categories in the periodic table. Group A elements, also known as the representative elements, are found in the s and p-blocks of the periodic table.

These elements have valence electrons in either the s or p orbitals, which makes them highly reactive and able to form a wide range of chemical compounds.

On the other hand, Group B elements, also known as the transition elements, are found in the d-block of the periodic table. These elements have valence electrons in the d orbitals, which gives them unique chemical and physical properties.

The main difference between Group A elements and Group B elements is that they belong to different categories in the periodic table. Group A elements are representative elements found in the s and p-blocks of the periodic table, while Group B elements are transition elements found in the d-block. The valence electrons of Group A elements are in the s and p orbitals, making them highly reactive and able to form a wide range of chemical compounds. Meanwhile, Group B elements have valence electrons in the d orbitals, giving them unique chemical and physical properties. The difference in their electron configurations gives rise to their distinctive characteristics.

In conclusion, the difference between Group A and Group B elements can be attributed to their location and electron configurations in the periodic table. Group A elements are representative elements found in the s and p-blocks, while Group B elements are transition elements found in the d-block. Their electron configurations give rise to their unique chemical and physical properties. Understanding these differences is important in chemistry as it allows scientists to predict the behavior and reactivity of different elements in chemical reactions.

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