indicate whether each statement about the nucleus of an atom is true or false.you are currently in a labeling module. turn off browse mode or quick nav, tab to items, space or enter to pick up, tab to move, space or enter to drop.true/falsestatementthe nucleus of an atom is neutral.the nucleus of an atom contains only neutrons.the number of nucleons present in the nucleus is equal to the number of electrons present outside the nucleus.the nucleus accounts for almost all the volume of an atom.the nucleus accounts for almost all the mass of an atom.the nucleus can be positively or negatively charged depending on the identity of the atom. answer bank

The hand that holds the broomstick's top when you sweep is its fulcrum. The hand in the top of the broom serves as the pivot point, making it a lever.

The majority of brooms have the fulcrum inserted into the bristles at the base of the brush. The user can apply a reasonable amount of force without the broom tipping over or becoming unstable because this location has a good balance of leverage and stability.

A lever is a straightforward device with a rigid bar or board that rotates around the fulcrum, a fixed point.

Lever, Pulley, Wheel and Axle, Inclined Plane, Wedge, and Screw are the six classical simple machines.

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Answer:

.

The common velocity of the two bodies after the collision is 2.7 m/s.

This can be calculated using the equation of conservation of momentum:

m1v1 + m2v2 = (m1 + m2)v

where m1 is the mass of the first body (12 kg), v1 is the velocity of the first body (4.2 m/s), m2 is the mass of the second body (18 kg), v2 is the velocity of the second body (0 m/s), and v is the common velocity of the two bodies after the collision.

Substituting the given values into the equation, we get:

12(4.2) + 18(0) = (12 + 18)v

Solving for v, we get:

v = 2.7 m/s

The sentences that describe examples of acceleration are: B. A batter swings a bat to hit a ball.D. A runner slows down after finishing a race.

In both cases, there is a change in velocity, which indicates acceleration. In sentence B, the batter is exerting force to change the direction and speed of the bat. In sentence D, the runner is decelerating or slowing down after crossing the finish line. "Finishing" typically refers to the completion or conclusion of an activity or task. It implies reaching the end or final stage of something. In different contexts, "finishing" can have various meanings. For example: Finishing a race: This refers to crossing the finish line or completing a race, such as a running race, swimming race, or cycling race. Finishing a project: This implies completing all the required tasks and reaching the end goal of a project, whether it's a work-related project, school assignment, or personal endeavor.

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The expression to be simplified is, A + BC + ABCD. Using De Morgan's theorem, we can convert complementation bars extending over multiple variables into complementation bars over single variables. The De Morgan's theorem states that the complement of a product is equal to the sum of complements. De Morgan's Theorem:

 1.   (AB) = A + B2.  (A + B) = A B The steps to simplify the given expression using De Morgan's theorem are as follows: A + BC + ABCD = A + (BC + ABCD) = A + (BC). (ABCD) = A + (B + C) (A + B + C + D) = A + AB + AC + BC + BD = A + AC + BC + BD.

Hence, the simplified expression is A + AC + BC + BD. Thus, using DeMorgan's Theorem and other applicable rules of Boolean algebra, the given expression is simplified to A + AC + BC + BD.

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The mass concentration is 0.2 kg/m³. Mass is an intrinsic property of a body. It was traditionally believed to be related to the quantity of matter in a physical body, until the discovery of the atom and particle physics.

To convert particle concentration from particles per cubic centimeter (particle/cm³) to kilograms per cubic meter (kg/m³), you need to know the density and the mass of each particle.

The conversion involves two steps:

Step 1: Convert particles/cm³ to particles/m³:

To convert from particles/cm³ to particles/m³, you need to multiply the concentration by 1,000,000 since there are 1,000,000 cubic centimeters in a cubic meter.

200 particles/cm³ * 1,000,000 = 200,000,000 particles/m³

Step 2: Convert particles/m³ to kg/m³:

To convert from particles to mass, you need to know the mass of each particle. Once you have the mass of a single particle, you can multiply it by the particle concentration to obtain the mass concentration.

For example, if you know the mass of each particle is 1 nanogram (1 ng = 1 x 10^-9 kg), you can calculate the mass concentration:

Mass concentration (kg/m³) = Particle concentration (particles/m³) * Mass of each particle (kg/particle)

Mass concentration = 200,000,000 particles/m³ * 1 x 10^-9 kg/particle = 0.2 kg/m³

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So her speed at the bottom of the hill is approximately 10.0 m/s.To find the girl's speed at the bottom of the hill, we can use the principle of conservation of mechanical energy.

At the top of the hill, the total mechanical energy is equal to the sum of kinetic energy and potential energy:

E_top = E_kinetic + E_potential

The kinetic energy of the girl and her bicycle is given by:

E_kinetic = (1/2) * m * v_top^2

where m is the total mass (40 kg) and v_top is the speed at the top of the hill (5.0 m/s).

The potential energy at the top of the hill is:

E_potential = m * g * h

where g is the acceleration due to gravity (approximately 9.8 m/s^2) and h is the height of the hill (10 m).

Since there is no other energy input or output besides the force of friction, the total mechanical energy is conserved, and we can equate the mechanical energy at the top to the mechanical energy at the bottom of the hill:

E_top = E_bottom

(1/2) * m * v_top^2 + m * g * h = (1/2) * m * v_bottom^2

We need to solve for v_bottom, which is the speed at the bottom of the hill.

Now, we can rearrange the equation and solve for v_bottom:

(1/2) * m * v_top^2 + m * g * h = (1/2) * m * v_bottom^2

Substituting the given values:

(1/2) * 40 kg * (5.0 m/s)^2 + 40 kg * 9.8 m/s^2 * 10 m = (1/2) * 40 kg * v_bottom^2

100 J + 3920 J = 20 J + 20 J + v_bottom^2

3920 J + 100 J = 40 kg * v_bottom^2

4020 J = 40 kg * v_bottom^2

Dividing both sides by 40 kg:

v_bottom^2 = 4020 J / 40 kg

v_bottom^2 = 100.5 m^2/s^2

Taking the square root of both sides:

v_bottom = √(100.5 m^2/s^2)

v_bottom ≈ 10.0 m/s

Therefore, her speed at the bottom of the hill is approximately 10.0 m/s.

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Answer:

Fossil Fuels are natural fuels like coal or gas that were formed millions of years ago and take millions of years to form. They are formed from the remains of past living organisms.

Explanation:

Well you do no really need an explanation for this one...

Given that the angular speed of the 27-inch-diameter tire is 5π radians per second. We need to find out the speed at which the cyclist is traveling.

The formula that relates angular speed, linear speed and radius of rotation is given as:v = rωwhere,v is the linear speed,ω is the angular speed andr is the radius of rotation.Since the diameter of the tire is 27 inches, the radius is 27/2 = 13.5 inches = 1.125 feet.Substituting the values in the above formula,v = rωv = (1.125) × (5π)v = 5.625π

The speed at which the cyclist is traveling when his 27-inch-diameter tires are rotating at an angular speed of 5π radians per second is 5.625π feet per second.

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hydrolysis.

Explanation:

Chemical weathering is what happens when rocks are broken down and chemically altered. Learn about the different types of chemical weathering, including hydrolysis, oxidation, carbonation, acid rain and acids produced by lichens.

The task is to compare the tangential acceleration of a tall baseball player's ball, which is thrown at a distance r from their elbow, with the tangential acceleration of a shorter baseball player's ball, which is thrown at a distance r/2 from their elbow, both having the same angular acceleration α.

The tangential acceleration of an object moving in circular motion can be calculated using the equation a_t = rα, where a_t is the tangential acceleration, r is the distance from the center of rotation, and α is the angular acceleration.

For the tall player's ball, the distance from the elbow is r, so its tangential acceleration is given by \(a_tall = r * α\).

For the shorter player's ball, the distance from the elbow is r/2, so its tangential acceleration is given by \(a_short = (r/2) * α\).

Comparing the two tangential accelerations, we can see that a_tall is twice as large as a_short. This is because the tangential acceleration is directly proportional to the radius of rotation.

Therefore, the tangential acceleration of the tall player's ball is twice the magnitude of the tangential acceleration of the shorter player's ball, given that both balls have the same angular acceleration α.

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The Centre of gravity is the point on an object where the force of gravity is considered to act.

Every object that exists on the earth has weight and because of that weight, certain gravity acts on it. When we calculate the total weight of the object, mainly center is taken as the point where the whole weight of the object is accumulated.

for instance, in the seesaw, the middle portion of it acts as a center of gravity which balances out both sides.

It plays a very important role in calculating big and complex problems of gravitation. It simplifies calculations to treat the mass of an object as if it is concentrated at one point only. It is an imaginary point that stable the object.

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Answer:

D is the answer

Explanation:

But do u know if im right test it out then surprise

The electromagnetic waves described in the reading are different in two ways, and that is Frequency and velocity. Hence, option D is correct.

A magnetic field and an electric field vibrate together to produce electromagnetic waves, often known as EM waves. In other terms, magnetic and electric fields that are oscillating make up electromagnetic waves (EM).

When a magnetic field and an electric field interact, electromagnetic waves are created. The term "electromagnetic waves" is used to describe them. An electromagnetic wave has an electric field and a magnetic field that are perpendicular to one another. They are likewise perpendicular to the EM wave's direction.

The wavelength and frequency of electromagnetic waves vary. Electromagnetic waves with longer wavelengths have lower frequencies, whereas those with shorter wavelengths have higher frequencies. Waves at higher frequencies carry more power. A wave's wavelength and frequency together determine its speed.

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Answer:

Answer is option 3 or

Explanation:

Diagram 2 best represents the charge distribution on the smaller sphere. Therefore, the correct option is option 2.

Charge is a physical attribute that causes matter in such an electromagnetic field to experience a force. Electric charges can be either positive or negative.

If there is no net electric charge, the substance is termed neutral or uncharged. Like charges repel each other (for example, two positive charges repelling two negative charges). Charges with opposing charges (positively and negatively) attract each other. Diagram 2 best represents the charge distribution on the smaller sphere.

Therefore, the correct option is option 2.

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Answer:

392.4

Explanation:

40*9.81=392.4

Insulators are often defined as materials that do not allow electricity to flow through them. Option A is correct. Electrons in an insulator do not move readily.

Insulators are commonly employed in physics. Insulators are often defined as materials that do not allow electricity to flow through them.

Insulators are also referred to as poor electrical conductors. We may discover various instances of these insulators in our daily lives. Insulators include materials such as paper, glass, rubber, and plastic.

Insulators are often defined as materials that do not allow electricity to flow through them. Electrons in an insulator do not move readily

Hence option A is correct. Electrons in an insulator do not move readily

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Answer:

D. 4Al + 3O2 → 2Al2O3

Explanation:

Chemical reactions involves the chemical combination of two or more substances called REACTANTS to yield other substances called PRODUCTS. However, in accordance with the LAW OF CONSERVATION OF MASS, the amount of reactants must be equal to that of the products.

To accomplish this, the reaction must be BALANCED. A balanced equation is an equation in which the number of atoms of each element in the reactant side equals the number of atoms in the product side. In this reaction involving Aluminum and Oxygen to give Aluminum oxide as follows:

Al + 02 → Al2O3

A coefficient is used to balance the number of atoms on both sides of the equation as follows:

4Al + 3O2 → 2Al2O3

Answer:

here for points

3u3784y297y4ui3t7

Explanation:

Answer:

The ball hit with 12N

Explanation:

Just took the quiz and got it right

The objective of this lab is to find the resonance in air column.

The apparatus of this experiment are a long cylindrical plastic tube attached to a water reservoir. The length of the water column can be changed by raising or lowering the water level while the tuning fork is held over the open end of the tube.

Resonance is indicated by a sudden increase in the intensity of the sound when the column is adjusted to a proper length.

The resonance is nothing but a standing wave phenomenon in the air column and occurs when the column length is λ/4, 3λ/4, 5λ/4.

Second resonance is occurred at third harmonic and third resonance is occurred at fifth harmonic.

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Answer:true

Explanation:

Answer: False

Explanation: An easy way to think of independent and dependent variables is, when you're conducting an experiment, the independent variable is what you change, and the dependent variable is what changes because of that.

Explanation: Research highlights the individuals with ASDS are nutritionally vulnerable because they exhibit a selective or pick eating pattern and sensory sensitivity that predisposes them to restricted intakes.

I hope this helps!

Answer:

b

Explanation:

ANSWER:

1.757 mm

STEP-BY-STEP EXPLANATION:

The coefficient of linear expansion is given by the following formula:

Where α = coefficiente of linear expasion, ΔL = change in lenght, ΔT = change in tempetature

Solving for ΔL:

Replacing and we calculate the change in lenght:

The change in length is 1.757 mm

The image of the print on the retina when the book is held 30.0 cm from the eye is about - 0.11 mm high, even though the print size is much larger than the photoreceptor cells, the eye-brain system can still perceive the letters with high detail.

(a) The lens-to-retina distance is given as 2.00 cm. When the book is held 30.0 cm away from the eye, the image height can be calculated using the thin lens equation.

We know that the distance of the book from the eye (object distance) is 30.0 cm and the lens-to-retina distance (image distance) is 2.00 cm.

Thus, 1/f = 1/do + 1/di

where,

Using the above formula, the focal length of the lens can be calculated as follows:

1/f = 1/do + 1/di= 1/30 + 1/2.00= 0.03333 + 0.500= 0.53333f = 1/0.53333= 1.875 cm

The height of the image can be calculated using the magnification formula:

m = - di/do

The negative sign indicates that the image is inverted. Using the above formula, m = - di/do= - (f/2) / do= - (1.875/2) / 30.0= - 0.03125

The height of the image can be calculated as follows: h' = m × h

where,

In this case, h is given as 3.50 mm.h' = m × h= - 0.03125 × 3.50= - 0.109375 mm= - 0.11 mm

The image of the print on the retina when the book is held 30.0 cm from the eye is about - 0.11 mm high.

(b) The size of the print can be compared to the sizes of rods and cones in the fovea. The rods and cones are the photoreceptor cells that convert light into electrical signals in the retina.

The fovea is a small, central region of the retina that contains a high density of cones and is responsible for high-acuity vision. The size of the print (3.50 mm) is much larger than the size of a single cone (about 0.002 mm) or rod (about 0.005 mm) in the fovea.

This means that multiple cones and rods would be activated by each letter in the print, allowing for better resolution and detail. The interconnections and higher order image processing of the eye-brain system would also allow for the brain to fill in missing information and make sense of the letters.

Therefore, even though the print size is much larger than the photoreceptor cells, the eye-brain system can still perceive the letters with high detail.

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Testable hypotheses are the theoretical problems that operational definitions have converted into.

Scientific observation is an empirical research designed to systematically address issues about the world. Through the use of operational definitions, theoretical questions are converted into. a provable theory. The measurement process for measuring external, observable behaviour is specified in Operational Definitions. The measurements that are obtained are utilised to define and quantify the construct. A measurement process (a collection of operations) is specified in an operational definition for the purpose of measuring an external, observable behaviour, and the definition and measurement of the hypothetical construct are then based on the results of the measurement procedure. No matter how solid your conceptual definition may be, you cannot measure anything without an operational definition.

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Both carts experience the same force but Cart A has a greater speed after the recoil.

The given parameters;

Apply the principle of conservation of linear momentum to determine the velocity of the carts after collision;

\(m_Av_0_A\ + m_Bv_0_B = m_Av_f_A \ + m_Bv_f_B\\\\the \ initial \ velocity \ of \ both \ carts = 0\\\\0.4(0) + 0.8(0) = 0.4v_f_A + 0.8v_f_B\\\\0 = 0.4v_f_A + 0.8v_f_B\\\\0.4v_f_A = -0.8v_f_B\\\\v_f_A= \frac{-0.8 v_f_B}{0.4} \\\\v_f_A = - 2 \ v_f_B \ \ m/s\)

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart A is equal to the force exerted on cart B but in opposite direction.

\(F_A = -F_B\)

Thus, the correct statement that compares the motion and forces acting on the two carts is "Both carts experience the same force but Cart A has a greater speed after the recoil."

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Answer:

compress

Explanation:

According to Bekesy's place theory of hearing, the frequency of a sound correlates to the area along the organ of Corti where the greatest number of nerve cells are activated.

By using a circular window to transmit sound vibrations to the cochlear fluid, von Békésy found that the traveling wave was generated along the length of the basilar membrane, and that the point of maximum amplitude varied depending on the fundamental frequency of the vibration.

According to the place theory of hearing, the location along the basilar membrane where each frequency of a sound produces vibrations affects how we hear it.

A sound of 6,000 hertz, for instance, would excite the area of the basilar membrane that has a 6,000 hertz characteristic frequency.

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When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

Let Va is the velocity of the airplane

Va is the velocity of the wind

When flying against the wind then

(Va+Vw)*(3.2 hours) = 640

3.2Va + 3.2Vw = 640

3.2Vw = 640 - 3.2Va

Vw = 200 - Va----------------(1)

When flying with the wind:

(Va-V)*(2 hours) = 640km

2Va - 2Vw = 640

Va - Vw = 320 ----------------(2)

Putting the value of VW in equation (2) we get

Va - (200-Va) = 320

2Va = 320 +200

2Va = 520

Va = 260

Putting this value in equation (2)

Vw =Va - 360

Vw = 100

Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

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The speed of the particle after 10 seconds is, 25.88m/s.

To find the answer, we have to know more about the equations of motion.

                          \(m=16kg\\u=10m/s\\t=10s\\f=25N\)

                        \(ma=f\\a=\frac{f}{m} =\frac{25}{16}=1.6m/s^2\)

           \(S=ut+\frac{1}{2}at^2=(10*10)+(\frac{1.6*10^2}{2})=178.13m\)

                \(v=\sqrt{u^2+2aS} =\sqrt{10^2+(2*1.6*178.13)} =25.88m/s\)

Thus, we can conclude that, the speed of the particle after 10 seconds is, 25.88m/s.

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