a manometer connected to a pipe in which a fluid flowing indicate a negative pressure head of 60mmHg.what are the absolute pressure in the pipe in paschal density of mercury is 13600kg/mm3

Answers

Answer 1

Around 101.404 kPa of absolute pressure are present inside the pipe.

How can you tell whether a manometer is reading positive or negative pressure?

Measured in relation to atmospheric pressure, gauge pressure changes depending on the barometer reading. When the unknown pressure exceeds atmospheric pressure (A), the gauge pressure reading is positive; when it is below atmospheric pressure (A), it is negative (B).

We know that the pressure inside the pipe is lower than atmospheric pressure since the manometer reading shows a negative pressure head. Assume that the atmosphere has a pressure of 1 atm (101.325 kPa), or around 760 mmHg.

First, we need to convert the pressure head reading from mmHg to meters:

60 mmHg * (1 m/1000 mm) = 0.06 m

The pressure difference between the pipe and the atmosphere is then:

ΔP = ρgh = (13600 kg/m³)(9.81 m/s²)(0.06 m) = 79.416 Pa

To find the absolute pressure in the pipe, we add this pressure difference to atmospheric pressure:

P_abs = P_atm + ΔP = 101.325 kPa + 79.416 Pa = 101.404 kPa

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Related Questions

(4x)。
(2x+6)。
I need to solve x for these angles

(4x)(2x+6)I need to solve x for these angles

Answers

Answer: x=14

Explanation:

there is 90° in a right angle so

(4x)+(2x+6) =90

collect like terms

6x+6=90

 -6 from both sides

6x=84

 ÷6

x=14

Mark and Nancy both take three measurements of the length of a pencil that is 15.1 cm. Mark records 15.0, 15.0, and 15.1 cm. Nancy records 15.1, 15.2, and 15.2 cm. Which of the following statements is true about Mark and Nancy's measurements?
A. Mark's measurement is more precise.
B. Nancy's measurement is more accurate.
C. Mark's measurement is more accurate.
D. Both sets of measurements are equally accurate and precise.​

Answers

It’s A trust me thank you………….

Seismic waves are the waves that transport energy away from the focus of an
earthquake. Seismometers, such as the one shown here, measure the
shaking of the Earth as a result of earthquakes. The black arrows show the
relative motion of the sensor on the seismometer. What characteristic of a
seismic wave is this motion showing?
OA. The period of the seismic wave
OB. The amplitude of the seismic wave
4

Answers

The characteristic of a seismic wave that the motion shown by the sensor on the seismometer represents is the amplitude of the seismic wave.

Seismic waves are waves that transport energy away from the focus of an earthquake, and they cause the ground to shake. Seismometers are instruments that measure the shaking of the Earth caused by seismic waves. The black arrows in the picture show the relative motion of the sensor on the seismometer. The sensor moves back and forth as the ground shakes, and the amplitude of this motion represents the intensity of the seismic wave.The amplitude of a seismic wave is a measure of the strength or energy of the wave. It is the maximum displacement of the ground from its resting position during the passage of the wave. The greater the amplitude of the seismic wave, the stronger the shaking of the ground and the more damage it can cause. The amplitude of a seismic wave is usually measured in millimeters or centimeters.In summary, the motion shown by the sensor on the seismometer represents the amplitude of the seismic wave. This is an important characteristic of a seismic wave as it determines the intensity of the shaking and the potential damage that the earthquake can cause. Seismologists use this information to study earthquakes and to understand their effects on the Earth.

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What is the average velocity of the object?

______ m/s

What is the average velocity of the object?______ m/s

Answers

Answer:

0.1 m/s (or 100 cm/s)

Explanation:

At the first point on the graph’s faded grid, the object has traveled 1 meter in 10 seconds. At the next point, the object traveled 2 meters in 20 seconds. This is a 1 to 10 ratio, or 1/10, which is 0.1 in decimal format.

A 175,000 kg space probe is landing on an alien planet with a gravitational acceleration of 8.25. If its fuel is ejected from the rocket motor at 35,000 m/s what must the mass rate of change of the space ship (delta m)/(delta t) be to achieve at upward acceleration of 2.00 m/s^2? Remember to use the generalized form of Newton's Second Law.

answer with correct units​

Answers

The mass rate of change of the space probe is approximately 28.49 kg/s .

What is the mass rate of the space probe?

To solve this problem, we can use the generalized form of Newton's Second Law, which states that the force acting on an object is equal to its mass times its acceleration:

F = ma

In this case, the force acting on the space probe is the thrust force generated by the rocket motor, which is equal to the rate of change of momentum of the ejected fuel:

F = (Δ m /Δt) * v

where;

Δ m /Δt t is the mass rate of change of the space ship, and v is the velocity of the ejected fuel, which is given as 35,000 m/s.

Since the space probe is landing on the planet, the net force acting on it should be equal to the force of gravity pulling it down minus the upward thrust force generated by the rocket motor. So we can write:

F_net = m * g - (Δ m /Δt) * v

Plugging in the values and solving for delta m / delta t, we get:

2.00 m/s² = (175,000 kg * 8.25 m/s²) - (Δ m / Δt) * 35,000 m/s

Δ m / Δt = (175,000 kg * 8.25 m/s² - 2.00 m/s² * 35,000 m/s) / 35,000 m/s

Δm / Δt ≈ 28.49 kg/s

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What are the magnitude and the direction of the electric field that will allow an electron to fall with an acceleration of 4.3 m/s2?

Answers

Answer:

Explanation:

The acceleration of an electron in an electric field is given by the equation:

a = qE/m

where a is the acceleration, q is the charge of the electron, E is the electric field, and m is the mass of the electron.

Given that the acceleration of the electron is 4.3 m/s^2, and the mass of the electron is 9.11 × 10^-31 kg, and the charge of the electron is -1.6 × 10^-19 C, we can solve for the electric field E:

E = ma/q

E = (4.3 m/s^2) × (9.11 × 10^-31 kg) / (-1.6 × 10^-19 C)

E = -2.44 × 10^4 N/C

The negative sign indicates that the direction of the electric field is opposite to the direction of the electron's motion. Therefore, the magnitude of the electric field required to accelerate an electron with an acceleration of 4.3 m/s^2 is 2.44 × 10^4 N/C and the direction is opposite to the direction of motion of the electron.

Calculate the surface density of atoms in the (111) plane of the body centered cubic lattice. Assume the lattice constant a=5 angstroms. Assume the atoms to be hard spheres, with closest atoms touching each other.

Answers

The surface density of atoms in the (1,1,1) plane of the BCC lattice is 0.16 atoms/angstrom².

To calculate the surface density of atoms in the (1,1,1) plane, we first need to determine how many atoms are in the plane. Since the plane passes through the center of the unit cell, it intersects one-eighth of each of the corner atoms and the full central atom. Therefore, the total number of atoms in the (1,1,1) plane is:

N_atoms = 1 + 8*(1/8) = 2

Next, we need to calculate the area of the (1,1,1) plane. To do this, we can consider the lengths of the sides of the unit cell. Since the BCC lattice has a cubic unit cell, all sides have length a=5 angstroms. The (1,1,1) plane passes through the center of the unit cell and intersects the sides at a 45-degree angle. The distance from the center of the unit cell to the midpoint of one of the sides is a/sqrt(2), so the length of the diagonal of the square face of the unit cell is 2a/√(2) = a√(2). The area of the square face is then (a√(2))² = 2a².

The (1,1,1) plane intersects the square face at a 45-degree angle, so its area is 2*a²/2 = a².

The surface density of atoms is the number of atoms per unit area. Dividing the number of atoms in the (1,1,1) plane by the area of the plane gives:

surface density = N_atoms / area

= 2 / a² = 2 / (5 angstroms)² = 0.16 atoms/angstrom²

Therefore, the surface density of atoms in the (1,1,1) plane of the BCC lattice is 0.16 atoms/angstrom².

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7. What is the velocity of an object with a distance of 90m south and a time of
5s?

Answers

Answer:

Explanation:

v= s/t

V =90m/5s

V = 8m/s

If you have a concave mirror whose focal length is 100.0 cm, and you want an image that is upright and 10.0 times as tall as the object, where should you place the object?

Answers

given

\(\begin{gathered} focal\text{ length=100 cm} \\ let\text{ object distance is u form the pole of mirror } \\ so\text{ u=-u} \\ and\text{ v=?} \\ here\text{ v is the distance of image from the pole of mirror } \\ let\text{ height of the object h} \\ so\text{ h=+h} \\ according\text{ to the question image of the object is } \\ \text{ h}^{^{\prime}}=+10h \\ \end{gathered}\)

since the image is in the upright direction so the image is virtual.

and in the case of the mirror, an image can be virtual if and only if

the image is placed between the pole and the focus. so the object

must be placed between the pole and the focus.

\(\begin{gathered} the\text{ formula for magnification is given by;} \\ m=-\frac{v}{u}=\text{ }\frac{h^{^{\prime}}}{h} \\ and\text{ the mirror formula is given by the following} \\ \frac{1}{f}=\frac{1}{u}+\frac{1}{v} \end{gathered}\)\(\begin{gathered} -\frac{v}{u}=\frac{h^{^{\prime}}}{h} \\ by\text{ putting all the values} \\ -\frac{v}{u}=\frac{10h}{h} \\ v=-10u \end{gathered}\)\(undefined\)

Single Stage 0.0/3.0 points (graded) Consider a rocket carrying 100,000 kg of propellant, 10,000 kg of structure, and 5000 kg of payload. What is the propellant fraction of this rocket? Round your answer to at least 2 decimal places (i.e., enter 0.25 to represent 25%) incorrect 1.100 What is the payload fraction of this rocket? Round your answer to at least 2 decimal places. incorrect 0.05 Recall that the relationship between specific impulse and exhaust velocity is: Vex=g0Isp . Assuming that Isp=450s and g0=9.81m/s2 , what is the value of ΔV in m/s that this rocket will produce if all the propellant is consumed in one stage? incorrect 4414

Answers

Answer: The Propellant fraction is 0.87.

The payload fraction is 0.04.

Δv = 8991.81 m/s

Explanation: To determine the fractions, first, calculate the total mass of the rocket:

\(m_{t} = m_{prop} + m_{str} + m_{pay}\)

\(m_{t} = 100,000 + 10,000 + 5,000\)

\(m_{t} = 115,000\)

The Propellant Fraction will be

\(m_{prop} = \frac{m_{prop}}{m_{t}}\)

\(m_{prop} = \frac{100,000}{115,000}\)

\(m_{prop} =\) 0.87

The Payload Fraction is:

\(m_{pay} = \frac{m_{pay}}{m_{t}}\)

\(m_{pay} = \frac{5,000}{115,000}\)

\(m_{pay} =\) 0.04

The value of Δv is calculated by the formula:

Δv = \(-V_{e}. ln(\frac{m_{final}}{m_{initial}} )\)

The exhaust velocity (\(V_{e}\)) is:

\(V_{e} = g_{0}.Isp\)

\(V_{e} =\) 9.81*450

\(V_{e} =\) 4414.5

\(m_{final}\) is the total mass after the rocket consume all the propellant and \(m_{initial}\) is the total mass before the action.

Δv = \(-V_{e}. ln(\frac{m_{final}}{m_{initial}} )\)

Δv = \(-4414.5.ln(\frac{15,000}{115,000} )\)

Δv = - 4414.5.ln(0.13)

Δv = 8991.81

Δv will be 8991.81 m/s.

A proton, which is the nucleus of a hydrogen atom, can be modeled as a sphere with a diameter of 2.4 fm and a mass of 1.67*10^-27 kg. (a) Determine the density of the proton.(Please provide numerical answer in kg/m^3).

Answers

The density of the proton is 3.97 x 10^17 kg/m^3.

The proton, the nucleus of a hydrogen atom, is a fundamental building block of matter and plays a crucial role in many physical and chemical processes. It can be modeled as a sphere with a diameter of 2.4 femtometers (fm) and a mass of 1.67 x 10^-27 kilograms. In order to determine its density, we need to calculate its volume and then divide its mass by its volume.

The volume of a sphere with diameter 2.4 fm (1 fm = 10^-15 m) is given by:

V = (4/3) * π * (d/2)^3

= (4/3) * π * (2.4 x 10^-15 m / 2)^3

= 4.18 x 10^-45 m^3

The density of the proton is given by:

density = mass/volume

= 1.67 x 10^-27 kg / 4.18 x 10^-45 m^3

= 3.97 x 10^17 kg/m^3

So, the density of the proton is 3.97 x 10^17 kg/m^3.

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A 24.4kg dog is running northward at 2.14m/s, while a 5.53kg cat is running eastward at 3.56m/s. Their 78.5kg owner has the same momentum as the two pets taken together. Find the direction of the owner's velocity. Find the magnitude of the owner's velocity.

Answers

The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.

To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.

Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).

According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.

The total momentum before the interaction is given by:

Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)

Mass of the dog (m1) = 24.4 kg

Velocity of the dog (v1) = 2.14 m/s

Mass of the cat (m2) = 5.53 kg

Velocity of the cat (v2) = 3.56 m/s

Mass of the owner (m3) = 78.5 kg

Velocity of the owner (v) = unknown

Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)

The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.

Total momentum after = 0

Equating the two expressions:

(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0

Simplifying the equation:

(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0

71.8648 kg·m/s + (78.5 kg * v) = 0

Solving for v:

78.5 kg * v = -71.8648 kg·m/s

v = -71.8648 kg·m/s / 78.5 kg

v ≈ -0.916 m/s

Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.

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A person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a
height of 52 m and it lands a distance of 35 m from the base of the cliff. What is the speed at
which the rock was initially kicked?

Answers

The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s

What is Speed ?

Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s

Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.

The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.

Let us first calculate the time by using the formula

h = ut + 1/2gt²

Where

h = 52 mu = 0Range R = 35 mg = 9.8 m/s²

Substitute all the necessary parameters into the formula

52 = 0 + 1/2 × 9.8 × t²

52 = 4.9t²

t² = 52/4.9

t² = 10.6

t = √10.6

t = 3.26 s

The speed at which the rock was initially kicked can be found by

R = Ut

35 = U × 3.26

U = 35/3.26

U = 10.7 m/s

Therefore, rock was initially kicked at a speed of 10.7 m/s

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State the hamilton's equation of
motion and derive each of them

Answers

Hamilton's equations of motion are a set of equations that describe the dynamics of a classical mechanical system in terms of a generalized coordinate and its conjugate momentum.

How to explain the equation

The equations are derived from the Hamiltonian formalism. Hamilton's equations can be derived from the Hamilton's principle, which is a variational principle that states that the action of a dynamical system is stationary.

To derive these equations, we start with the Hamiltonian function H(p, q) and use the principle of least action. The action S is defined as the integral of the Lagrangian L(q, q', t) over time:

S = ∫[L(q, q', t)] dt

To find dp/dt, we differentiate the Lagrangian with respect to q:

∂L/∂q = ∂(p * q' - H)/∂q

= -∂H/∂q

Using the chain rule, we find:

dL/dt = (∂L/∂q) * dq/dt + (∂L/∂q') * dq'/dt

= -∂H/∂q * dq/dt + p * d(q')/dt

= -∂H/∂q * dq/dt + p * d^2q/dt^2

= -∂H/∂q * dq/dt + dp/dt

Since the Lagrangian is equal to p * dq' - H, we can write:

dL/dt = -∂H/∂q * dq/dt + dp/dt

From the principle of least action, we know that the action S is stationary, so dL/dt = 0. Thus, we have:

-∂H/∂q * dq/dt + dp/dt = 0

Rearranging the equation, we obtain the first equation of motion:

dp/dt = -∂H/∂q

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Hello I could use some help answering this question I don’t quite understand ! :)

Hello I could use some help answering this question I dont quite understand ! :)

Answers

ANSWER

C. The rate of heat transfer for both walls is the same

EXPLANATION

The rate of heat transfer for a material is given by:

\(R=\frac{kA\Delta T}{d}\)

where k = thermal conductivity

A = surface area of the material

ΔT = change in temperature

d = thickness of the material

Wall A has 4 timesthe area of Wall B and is also twice as thicjk as wall B. This implies that:

\(\begin{gathered} A_A=4A_B \\ d_A=2d_B \end{gathered}\)

We also have that the thermal conductivity of Wall A is half that of Wall B:

\(k_A=\frac{1}{2}k_B\)

Therefore, the rate of heat trnsfer for Wall ABis:

\(R_B=\frac{k_BA_B\Delta T}{d_B}\)

and for Wall A is:

\(\begin{gathered} R_A=\frac{k_AA_A\Delta T}{d_A} \\ R_A=\frac{(\frac{1}{2}k_B)(4A_B)\Delta T}{2d_B}=\frac{4k_BA_B\Delta T}{4d_B} \\ R_A=\frac{k_BA_B\Delta T}{d_B} \end{gathered}\)

Note: ΔT is the same for both walls

Hence, we see that the rate ofheat rtransfer for both walls is the same.

The correct option is option C.

Which of the following is accurate when discussing specific heat? Question 2 options: A) The specific heat of a gas can be measured at constant pressure. B) The specific heat of a gas can be measured at constant volume only. C) Specific heat values for liquids will never vary for different ranges of temperature. D) Specific heat values for solids will never vary for different ranges of temperature.

Answers

The accurate statement when discussing specific heat is  option A) The specific heat of a gas can be measured at constant pressure.

This is because specific heat is the amount of heat energy required to raise the temperature of a substance by a certain amount. For gases, the specific heat can be measured at either constant pressure or constant volume. However, when discussing specific heat in general, it is more commonly measured at constant pressure.

Option B is incorrect because the specific heat of a gas can also be measured at constant volume, not just constant volume only.

Option C is incorrect because specific heat values for liquids can vary for different ranges of temperature. The specific heat of a substance may change with temperature due to variations in molecular interactions and other factors.

Option D is incorrect because specific heat values for solids can also vary for different ranges of temperature. The specific heat of a solid can depend on factors such as crystal structure, impurities, and temperature range.

Therefore, the accurate statement is option A, which states that the specific heat of a gas can be measured at constant pressure.

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What does this picture show?

What does this picture show?

Answers

Answer:

d poor accuracy,poor precision

The diagram represents how much accurate and precise the result data is. It is clear from the image that, the data points have poor accuracy and good precision.

What is accuracy ?

Accuracy of a result is the measure of the closeness of the experimental or calculated value to the true value or absolute value of a measurement.  For a reproducible experiment, the results for each trials can be differ or close.

The closeness between values of a set of experiments is called precision of the results. Not all accurate value be can be precise. Similarly precision of values does not need to meet accuracy.

Here, the central dot indicates the true value. The green points are a set of experimental values. They are not so close to the true value and hence it is less accurate. However, all the points and closer together. Hence, they are precise. Therefore, option B is correct.

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Why does the plant produce more pollen need for fertilization?

The pollen is used as to attract bees and other insects to help fertilize the egg.
Many of the pollen produced never reach eggs cells due to environmental factors.
The plant stores the excess pollen for its next reproduction cycle.
There are many animals that would eat pollen from flowers.

Answers

Answer: The main reason the  pollen and the extension the process of pollination  is so that important is because it means the plants don't have to rely on water to transport the biological components necessary for the fertilization.  Inside it and they contain the male portion of DNA needed for the plant reproduction.

Explanation:

The pollen is used as to attract bees and other insects to help fertilize the egg.

2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m

Answers

For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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bob's car ran out of gas 3.4 km from the nearest gas station. if it requires a 500 n force to push his car, how much work will bob do to get his car to the gas station? (1.7 MJ or 1.7 10 j)

Answers

The mileage of the car is calculated by dividing the number of miles traveled by the amount of gas used. Car's Gas Mileage is 147.0

How do you calculate how far you can go on a tank of gas?Gas Run Out.Turn on your hazard lights and safely pull your car over to the right shoulder.If you have emergency gear, such as a reflective triangle, set it up as needed.Go for a stroll to the closest gas station.Place a roadside assistance call.How to Calculate Your Car's Gas MileageThe outcome is your car's normal miles per gallon, which you can calculate by dividing the distance traveled by the number of petrol tanks you filled up.For instance, your car would average 25 miles per gallon if you traveled 200 miles on 8 gallons of gas.

 Car's Gas Mileage = 500/3.4

=147.0

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In the experiment, “Rolling Along”, which ball had the greater mass?
Question 2 options:


Ping-pong ball


Golf ball


The masses are the same


Neither ball had mass

Answers

Answer:

b

Explanation:

In a physics lab, Ray Zuvlite arranges two mirrors with a right angle orientation as shown. Ray then directs a laser line at one of the mirrors. The light reflects off both mirrors as shown. If angle A is 38°, determine the what is the angle measure of angles B, C, and D?

Answers

The angle measure of angle B = 25° and angle C = 65° and angle D = 25°.

What is meant by measure?Through the use of a protractor, angles are measured in degrees (°). In order to calculate or draw angles in terms of degrees, a protractor is a measuring tool that is utilized. Using a protractor, for instance, we can observe that the black arrow in the image below crosses the 90° line at 100°. Thus, the angle has a 100° measurement. A degree is a unit of measurement for a plane angle in which one complete rotation equals 360 degrees, generally indicated by the symbol °. It is included in the SI brochure as an acceptable unit even though it is not a SI unit—the radian is the SI unit of angular measure.

The given parameters are;

The orientation of the two mirrors = At right angle to each other

The laser light is directed at one of the mirror

The measure of angle, A = 25°

The measures of angle B, C, and D are found as follows;

We have;

∠A = ∠B = 25°, by angle of incidence equals angle of reflection

∠B = 25°

∠B + ∠C = 90° by sum of the acute angles of a right triangle

25° + ∠C = 90°

∴ ∠C = 90° - 25° = 65°

∠C = 65°

∠E = ∠C = 65° by angle of incidence equals angle of reflection

∴ ∠E = 65°

Line 'L' is perpendicular to the second mirror, therefore, the angle between line 'L' and the second mirror = 90° = ∠E + ∠D

∠E + ∠D = 90°,  by angle sum property

Therefore;

65° + ∠D = 90°

∴ ∠D = 90° - 65° = 25°

∠D = 25°

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You have been managing your time for years so you probably already have some ideas about what works for you. What are some effective time management strategies you have used at home at school or in the workplace? Why were they successful?

Answers

One of the most effective time management strategies that I have used is creating a to-do list. They are successful because they help me to prioritize tasks, remain organized, increase productivity, and reduce stress.

One of the most effective time management strategies that I have used is creating a to-do list.

Creating a to-do list helps me to prioritize tasks and ensures that I do not forget any important tasks.

When creating a to-do list, I ensure that I put the most important tasks at the top of the list and then work my way down.

The to-do list has helped me to organize my work, manage my time effectively and reduce stress.

Another effective strategy that I have used is breaking large tasks into smaller manageable tasks.

When dealing with complex tasks, I break them down into smaller, more manageable chunks.

This helps me to focus on the individual parts of the task, which are easier to handle and manage.

When I focus on smaller tasks, I find it easier to get started, and I gain momentum as I make progress on each small task.

This method has helped me to increase my productivity and reduce the stress that comes with handling large tasks.

In conclusion, the above time management strategies have helped me to manage my time effectively at home, school, and in the workplace.

They are successful because they help me to prioritize tasks, remain organized, increase productivity, and reduce stress.

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Females are theoretically more prone to anxiety disorders due to __________. A. their habit of overreacting to physiological changes B. the high levels of serotonin causing hormone imbalance C. increased levels of norepinephrine causing anxiety sensitivity D. stress levels, life experiences, and friends’ stresses Please select the best answer from the choices provided A B C D

Answers

Answer:

fluctuations in the levels of female reproductive hormones

Explanation:

Women are more prone to anxiety due to a variety of biological, psychological, and cultural factors. Although the exact cause is unknown, recent research suggests that fluctuations in the levels of female reproductive hormones and cycles play an important role in women's enhanced vulnerability to anxiety.

Answer: D. stress levels, life experiences, and friends’ stresses

Explanation:

Females are theoretically more prone to anxiety disorders due to __________. A. their habit of overreacting

What observations can the geologist make by working outdoors instead of in a lab?

Answers

Answer:

Geology is the study of the Earth that involves the process at Earth, materials of which it is made, and its history.

Geologists combine both laboratory and field data to illustrate the results of their research. Some observations that can the geologist make by working outdoors instead of in a lab are as follows:

Understanding and exploring the earth's surface closely using geophysical tools.Collecting samples by own and make some interpretations at the same time.Observation of the  landscapesClose observation of outcrops

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The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons

Answers

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

Why the electron number cannot be used instead?

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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Part A What will be the equilibrium temperature when a 227 g block of copper at 283 °C is placed in a 155 g aluminum calorimeter cup containing 844 g of water at 14.6°C? ​

Answers

Answer:

T = 20.84°C

Explanation:

From the law of conservation of energy:

Heat Lost by Copper Block = Heat Gained by Aluminum Calorimeter + Heat Gained by Water

\(m_cC_c\Delta T_c = m_wC_w\Delta T_w + m_aC_a\Delta T_a\)

where,

\(m_c\) = mass of copper = 227 g

\(m_w\) = mass of water = 844 g

\(m_a\) = mass of aluminum = 155 g

\(C_c\) = specific heat capacity of calorimeter = 385 J/kg.°C

\(C_w\) = specific heat capacity of water = 4200 J/kg.°C

\(C_a\) = specific heat capacity of aluminum = 890 J/kg.°C

\(\Delta T_c\) = change in temperature of copper = 283°C - T

\(\Delta T_w\) = change in temperature of water = T - 14.6°C

\(\Delta T_a\) = change in temperature of aluminum = T - 14.6°C

T = equilibrium temperature = ?

Therefore,

\((227\ g)(385\ J/kg.^oC)(283^oC-T)=(844\ g)(4200\ J/kg.^oC)(T-14.6^oC)+(155\ g)(890\ J/kg.^oC)(T-14.6^oC)\\\\24732785\ J - (87395\ J/^oC) T = (3544800\ J/^oC) T - 51754080\ J+ (137950\ J/^oC) T-2014070\ J\\\\24732785\ J +51754080\ J+2014070\ J = (3544800\ J/^oC) T+(137950\ J/^oC+(87395\ J/^oC) T\\\\78560935\ J = (3770145\ J/^oC) T\\\\T = \frac{78560935\ J}{3770145\ J/^oC}\)

T = 20.84°C

Three point charges
q1, q2, and q3
are situated at three corners of a rectangle. Here, q1 = +7.00 µC, q2 = −7.00 µC, q3 = +8.00 µC. Length is 5.00 cm, height is 2.50 cm.

What is the electric potential at the free corner where there is no charge?

Answers

The formula gives the electric potential resulting from a charged object q experienced at the a point P that is r distances away.

What exactly does "electric" mean?

powered by, by, or involving electricity. an electric flow. An electric heater that feels electric shock-like. a performance with energy.

How come it's called "electric"?

Its name, "elektron," which meaning amber, is derived from this word. In tree sap, you can find amber, a golden fossilized rock. The Greeks discovered that when they rubbed silver against wool, light materials (like straw or feathers) stuck to it. The term "static" electricity refers to this type of electricity.

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A ball thrown with an initial velocity of u(10i+15j)m/s when it reaches the top of it trajectly neglucating air resistance what is avelocity & acceleration ?

Answers

At the apex of the trajectory, the ball's velocity and acceleration are u (10i+15j) m/s and zero

The initial velocity of the ball is u (10i+15j) m/s.

Velocity at the top of the trajectory: Since the ball is thrown with an initial velocity, it will reach the top of its trajectory with the same velocity, since there is no air resistance. Therefore, the velocity of the ball at the top of the trajectory is u (10i+15j) m/s.

Acceleration: The acceleration of the ball at the top of the trajectory is zero, since the ball is not accelerating (there is no acceleration due to air resistance).

Therefore, the velocity and acceleration of the ball at the top of the trajectory are u (10i+15j) m/s and zero, respectively.

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What is a wave and that’s Carrie’s from one place to another?

What is a wave and thats Carries from one place to another?

Answers

To find:

What a wave is? and what does it do?

Explanation:

A wave is the di

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