In the measurement 365 cL the “c” stands for the___ And the “ L”stands for the___

Answers
A.base unit and prefix
B.suffix and prefix
C.prefix and suffix
D.prefix and base unit

Answer:

When speed reduces, acceleration decreases

Explanation:

From first equation of motion;

\({ \tt{v = u + at}}\)

When time is constant:

\({ \tt{v = 0 + kt}} \\ { \tt{v = kt}} \\{ \tt{v \: \alpha \: \: a}}\)

When speed is decreasing, velocity and acceleration are in opposite directions.

After time t, the position function of the ball is determined as \(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

The given parameters;

The position function of the ball after time t, is calculated as follows;

\(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

The negative sign of acceleration of due to gravity is because the ball is moving upward against gravity.

Thus, after time t, the position function of the ball is determined as \(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

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The volume of the gas at 101.3 kPa would be approximately 651.25 cm³.

To calculate the change in volume of a gas from an initial pressure to a final pressure, we can use Boyle's law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's law can be expressed as:

P1 * V1 = P2 * V2

Where:

P1 = Initial pressure (80.8 kPa)

V1 = Initial volume (817 cm³)

P2 = Final pressure (101.3 kPa)

V2 = Final volume (to be calculated)

Let's plug in the values into the equation and solve for V2:

80.8 kPa * 817 cm³ = 101.3 kPa * V2

V2 = (80.8 kPa * 817 cm³) / 101.3 kPa

V2 ≈ 651.25 cm³

Therefore, the volume of the gas at 101.3 kPa would be approximately 651.25 cm³.

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Answer:

The depth of the diver is 28.01 m

Explanation:

Given;

density of the seawater, ρ = 1,015 kg/m³

standard sea level pressure, P₀ = 1.0 atm = 101,325 Pa

the final reading of her pressure, P₁ = 3.75 atm = 379968.75 Pa

acceleration due to gravity, g = 9.8 m/s²

Let the depth she was diving at the final pressure = h

This depth is calculated as;

P₁ = P₀  +  ρgh

P₁ - P₀ =  ρgh

\(h = \frac{ P_1 \ - \ P_o}{\rho g} = \frac{379968.75 \ - \ 101325}{1015 \ \times \ 9.8} = 28.01 \ m\)

Therefore, the depth of the diver is 28.01 m

As thermal energy is added to a sample of water, the potential energy of its molecules increases, and then the kinetic energy of its molecules increases.

The sections of the heating curve illustrate this process  is B followed by D

Therefore option A is correct.

Thermal energy (also called heat energy) is described as being produced when a rise in temperature causes atoms and molecules to move faster and collide with each other.

some factors of thermal energy include:

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Answer:

The Great Pyramid of Giza (also known as the Pyramid of Khufu or the Pyramid of Cheops) is the oldest and largest of the pyramids in the Giza pyramid complex bordering present-day Giza in Greater Cairo, Egypt.It is the oldest of the Seven Wonders of the Ancient World, and the only one to remain largely intact.

Explanation:

Answer:

0.0119502868 kilocalorie

Explanation:

Answer:

increases by 50

Explanation:

Answer:

The energy of the system and total momentum are both conserved in an elastic head-on collision. The atomic nucleus receives 1.87 percent of the neutron's kinetic energy and final kinetic energy is 12.3×10-13J.

Explanation:

In elastic head-on collision, the energy of the system and total momentum is conserved.

For the neutron,

m - mass, - initial velocity,  - final velocity

For the atom,

M- mass , - initial velocity, - final velocity

Conserved momentum on the head-on collision

mv_i=mv_f+MV_f

v_i-v_f=MmV_f

v_i-v_f=14.9V_f.........(I)

The kinetic energy

v_i^2-v_f^2=14.9V_f^2............(II)

From equation (I) and (II)

(v_i-v_f)/(v_i^2-v_f^2 )=(12v_f^2)/(12v_f^2 )

v_i+v_f=V_f.........(III)

Solve equation (I) and (III) for  

v_i=7.9v_f

Now, the fraction of the neutron's kinetic energy transferred to the atomic nucleus,

(1/2 MV_f^2)/(1/2 mv_i^2 )=14.9/7.95=1.87

K2=1.87×6.58×10-13J=12.3×10-13J

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The maximum width of the gorge that the secret agent can clear is 33.2 m.

Gorge is a steep-sided valley that is typically formed when a river or stream cuts through a landscape. Gorges can occur in a variety of landscapes and can range greatly in size. They are often found in areas of limestone or sandstone, and are often filled with spectacular scenery, including waterfalls, rapids, and cliffs. Gorges can also be formed by ice, erosion, and glacial activity.

The maximum width of the gorge that the secret agent can clear is given by the equation:

W = 2v0^2 * sin(2θ) / g

Where W is the maximum width of the gorge, v0 is the initial speed of the agent, θ is the angle of the slope, and g is the acceleration due to gravity.

Substituting the given values into the equation, we get:

W = 2 * (12.9 m/s)^2 * sin(2 * 28°) / 9.81 m/s^2

W = 33.2 m

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Since Two stars M1 and M2 of equal mass make up a binary star system.  their orbital speed is  2.69E4 m/s.

The orbital period of a binary star system is given by the equation:

T = 2 * pi * sqrt(a³ / (G * (M1 + M2)))

where T is the orbital period, a is the semi-major axis of the orbit (half of the distance between the two stars at their closest approach), G is the gravitational constant, and M1 and M2 are the masses of the two stars.

Substituting the given values into this equation, we get:

3.20 days = 2 * pi * sqrt(a³ / (6.67E-11 m³ kg^⁻¹ s^⁻² * (5.45 sm * 1.99E30 kg/sm + 5.45 sm * 1.99E30 kg/sm)))

Solving for the semi-major axis, we find that a = 2.11E11 m.

The speed of each star in the orbit can be found using the equation:

v = sqrt(G * (M1 + M2) / a)

Substituting the values we have calculated, we find that v = 2.69E4 m/s. This is the speed of each star in the orbit.

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Answer:hope this helps you

Explanation:.

When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.

How do sound waves and earthquakes compare?

The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.

In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.

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Answer: i think it is for 16,  Infectious diseases commonly spread through the direct transfer of bacteria. for 17 i think In biology, immunity is the capability of multicellular organisms to resist harmful microorganisms. i dont have a clue about the others but i hope this is right or atleast helps

Explanation:

For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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s[3] is an expression whose value is the character at index 3 of the str associated with s.

What string method can be used to check whether the text variable's string only contains letters?

Checking whether a string only contains alphabetical characters requires the use of the Python isalpha() string method. I.e., isalpha() determines whether a string is composed entirely of letters.

The indexOf() method searches the entire calling string for the specified substring with such a single argument of a substring to look for and returns the index of the first occurrence.

Therefore, The value of the expression s[3] is the character found at index 3 of the str linked to s.

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Answer:

the 2nd one is the right one

Explanation:

wave length is on top

The figure 2 correctly shows the part of the wave that represents the wavelength.

A wave is a dynamic disturbance that propagates and causes a change in equilibrium of one or more parameters in physics, mathematics, and related subjects. Quantities may oscillate regularly around an equilibrium (resting) value at certain frequency if a wave is periodic.

A travelling wave is one in which the entire waveform moves in one direction; in contrast, a standing wave is one in which two periodic waves are overlaid and move in the opposing directions.

In a standing wave, there are some points where the wave amplitude seems reduced or even zero, and these positions have null vibration amplitudes. A wave equation (standing wave field comprising two opposing waves) or a one-way wave equation (for single wave propagation in a certain direction) is frequently used to describe waves.

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Answer:5

Explanation:

You do change in y over change in X

Answer:

a. 1.56 × 10¹⁸ electrons per second

b. The electrons in wire 3 flow into the junction.

Explanation:

Here is the complete question

Three wires meet at a junction. Wire 1 has a current of 0.40 A into the junction. The current of wire 2 is 0.65 A out of the junction. (a) How many electrons per second move past a point in wire 3? (b) In which direction do the electrons move in wire 3 -- into or out of the junction?

Solution

(a) How many electrons per second move past a point in wire 3?

Using Kirchhoff's current law, at the junction, i₁ + i₂ + i₃ = 0 where i₁ = current in wire 1 = 0.40 A, i₂ = current in wire 2 = 0.65 A and  i₃ = = current in wire 3,

So, i₃ = -(i₁ + i₂)

taking current flowing into the junction as positive and those leaving as negative, i₁ = + 0.40 A and i₂ = -0.65 A

So, i₃ = -(i₁ + i₂)

i₃ = -(0.40 A + (-0.65 A))

i₃ = -(0.40 A - 0.65 A)

i₃ = -(-0.25 A)

i₃ = 0.25 A

Since i₃ = 0.25 C/s and we have e = 1.602 × 10⁻¹⁹ C per electron, then the number of electrons flowing in wire 3 per second is i₃/e = 0.25 C/s ÷ 1.602 × 10⁻¹⁹ C per electron = 0.1561  × 10¹⁹ electrons per second = 1.561  × 10¹⁸ electrons per second ≅ 1.56 × 10¹⁸ electrons per second

(b) In which direction do the electrons move -- into or out of the junction?

Given that i₃ = + 0.25 A and that positive flows into the junction, thus, the electrons in wire 3 flow into the junction.

Answer: i don’t know the answer but

Explanation:

Divide the distance by the speed. That gives the travel time.

t = d/v = (4200 km) / (800 km/hr) = ? hrs

Answer:

The first harmonic

Explanation:

fundamental harmonic = 1st harmonic = 1st sound

all other sounds after are higher-pitched and quieter

lowest frequency & highest amplitude

but they are all related to that first sound.

integer multiples of the fundamental frequency

chatgpt

Answer:

The fundamental harmonic is the same as the first harmonic, and it is represented by option E. The fundamental harmonic is the lowest frequency standing wave pattern produced by a vibrating object, and it determines the overall pitch or frequency of the sound produced by the object. The fundamental harmonic has the highest amplitude, and all other harmonics are integer multiples of it.

Answer:

The angular displacement of the blade is 576,871.2 radians

Explanation:

Given;

angular speed of the Helicopters rotor blades, ω = 510 rpm (revolution per minute)

time of motion, t = 3 hours

The angular speed of the Helicopters rotor blades in radian per second is given as;

\(\omega = \frac{510 \ rev}{mins} *\frac{2 \pi \ rad}{1 \ rev} *\frac{1 \ min}{60 \ s}\\\\\omega = 53.414 \ rad/s\)

The angular displacement in radian is given as;

θ = ωt

where;

t is time in seconds

θ = (53.414)(3 x 60 x 60)\\

θ = 576,871.2 radians

Therefore, the angular displacement of the blade is 576,871.2 radians

Answer:

\( \boxed{ \sf{see \: below}}\)

Explanation:

The unit of speed is metre per second or m / s. It clearly depends on two fundamental units ; unit of length ( metre ) and unit of time ( second ). Hence , m/s is a derived unit.

Hope I helped!

Best regards! :D

The unit of speed is m/s. The two terms metre and second are fundamental quantities.

As,m/s is derived from these two fundamental quantities. Therefore, Unit of speed is a derived unit.

Answer:

-48cm

Explanation:

For a convex lens f is +ve and V is +ve

Using the formula 1/f=1/v+1/u

u=12cm and f=16cm

1/16-1/12=1/v

1/v=-1/48

v=-48cm

Newton's third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction. The third law is also known as the law of action and reaction.

You are pushing the Earth away from yourself with the same force.

The answer would be:

the force you exert on the ground beneath you.

The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.

Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.

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The coefficient of thermal conductivity (k) is related to the rate of heat flow (Q), the cross-sectional area (A), the length (L), the temperature difference (ΔT), and the thermal resistance (Rth) by the following equation:

k = Q / (A * ΔT * L) = Rth * (A * ΔT)

Reorganizing this equation gives:

Rth = k / (A * ΔT)

The given information in the problem is:

Rate of heat flow (Q) = 14.0 watts

Thermal resistance (Rth) = (350 mm × 350 mm × 15 mm) / (14.0 watts) = 31.5 mm⁴/C

Temperature difference (ΔT) = 28°C

Substituting these values into the equation, we have:

k = Q / (A * ΔT) = 14.0 W / (0.35 m² * 28°C) = 1.94 W/mK

So the coefficient of thermal conductivity (k) for this wood is approximately 1.94 W/mK.