In the aftermath of an intense earthquake, the earth as a whole "rings" with a period of 54 minutes.
What is the frequency of this oscillation?
Express your answer in hertz.

The first step is to find the frequency heard by each aircraft as they approach each other. Let's call the frequency heard by each aircraft.

According to the Doppler effect formula for sound, the frequency heard by an observer moving towards a stationary source is given by:

f' = (v + vs) / (v + vd) * f

where f is the emitted frequency, v is the speed of sound, vs is the speed of the source (aircraft in this case), and vd is the speed of the observer (also an aircraft in this case).

Since both aircraft are approaching each other at the same speed, we can assume that their speeds are equal and call it v_a. Therefore, we have:

f' = (v + v_a) / (v - v_a) * f

We are given that the frequency heard by each aircraft is 2 times the emitted frequency, so we can write:

2f = (v + v_a) / (v - v_a) * f

Simplifying this equation, we get:

2 = (v + v_a) / (v - v_a)

2(v - v_a) = v + v_a

v = 3v_a

Now we can substitute this value of v into the speed of sound formula to get the speed of each aircraft:

343 m/s = (3v_a + v_a)

v_a = 343 / 4 = 85.75 m/s

Finally, we can convert this speed to km/hr:

85.75 m/s * 60 s/min * 60 min/hr / 1000 m/km = 308.7 km/hr

Therefore, each aircraft must have a speed of approximately 308.7 km/hr in order for the pitch they both hear to be 2 times the emitted frequency.

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For someone with a negative Weber slope for weight detection, it would be easier to tell the difference between 20 pounds and 21 pounds.

The Weber's Law states that the just noticeable difference (JND) between two stimuli is proportional to the magnitude of the stimuli. A negative Weber slope indicates that the JND decreases as the magnitude of the stimuli increases. In this case, as the weight increases, the person's ability to discriminate between the weights becomes easier.

Therefore, option C, telling the difference between 20 pounds and 21 pounds, would be easier for someone with a negative Weber slope for weight detection.

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A. The average drift speed of the electrons in the wire is  1.19 x \(10^{-3}\)cm/s.

B. The time it would take an electron to travel 8.84 m is 7.43 x \(10^{5}\)sec

(A) To find the average drift speed of electrons in a wire, we can use the equation:

I = nAvq

Where:
I is the current in Amperes
n is the electron density in electrons per \(cm^{3}\)
A is the cross-sectional area of the wire in \(cm^{2}\)
v is the average drift velocity of electrons in cm/s
q is the charge of an electron, which is 1.6 x \(10^{-19}\) Coulombs

First, we need to find the cross-sectional area of the wire. The formula for the area of a circle is:

A = π\(r^{2}\)

Where:
A is the area of the circle
r is the radius of the circle

Given that the wire diameter is 1.63 mm, we can find the radius by dividing it by 2:

r = 1.63 mm / 2 = 0.815 mm = 0.0815 cm

Now, we can calculate the area:

A = \(π(0.0815 cm)^{2}\) = 0.0209 \(cm^{2}\)

Next, we can rearrange the equation to solve for v:

v = I / (nAq)

Given that the current is 20 A and the electron density is 8.47 x \(10^{24}\)electrons per \(cm^{3}\), we can substitute these values into the equation:

v = 20 A / (8.47 x \(10^{24}\) electrons per cm^3 * 0.0209 cm^2 * 1.6 x \(10^{-19}\) C)

Simplifying the expression:

v = 1.19 x \(10^{-3}\) cm/s

Therefore, the average drift speed of electrons in the 14 gauge wire carrying a maximum current of 20 A is approximately 1.19 x \(10^{-3}\) cm/s.

(B) To calculate the time it would take for an electron to travel a distance of 8.84 m, we can use the formula:

t = d / v

Where:
t is the time in seconds
d is the distance in meters
v is the average drift velocity of electrons in meters per second

Given that the distance is 8.84 m and the average drift velocity is 1.19 x 10^-3 cm/s, we need to convert the velocity to meters per second:

v = 1.19 x \(10^{-3}\) cm/s * 0.01 m/cm = 1.19 x \(10^{-5}\) m/s

Now, we can substitute the values into the formula:

t = 8.84 m / 1.19 x \(10^{-5}\)m/s

Simplifying the expression:

t = 7.43 x \(10^{5}\)s

Therefore, it would take approximately 7.43 x \(10^{5}\) seconds for an electron to travel a distance of 8.84 m.

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Answer:

2+ charge

Explanation:  The alkaline earth metals have two valence electrons in their highest-energy orbitals (ns2). They are smaller than the alkali metals of the same period, and therefore have higher ionization energies. In most cases, the alkaline earth metals are ionized to form a 2+ charge

Hope this helps, have a great day :)

Answer:

2N

Explanation:

Given parameters:

Mass of the balloon = 1kg

Acceleration  = 2m/s²

Unknown:

Applied force = ?

Solution

According to Newton's second law of motion:

 Force   =  mass x acceleration

 Now insert the given parameters and solve;

   Force  = 1 x 2  = 2N

Answer:

asdadsadada

Explanation:

Explanation:

To solve this problem, we can use the formula:

ΔL = αLΔT

where ΔL is the change in length, α is the linear expansivity coefficient of brass, L is the original length of the brass rod, and ΔT is the change in temperature.

Given:

α = 2.0 × 10^-5 K^-1 (linear expansivity coefficient of brass)

L = 10.0 m (original length of the brass rod)

ΔT = 41°C - 30°C = 11°C (change in temperature)

Using the formula:

ΔL = αLΔT

ΔL = (2.0 × 10^-5 K^-1) × (10.0 m) × (11°C)

ΔL = 0.0022 m

Therefore, the new length of the brass rod at 30°C will be:

L' = L + ΔL

L' = 10.0 m + 0.0022 m

L' = 10.0022 m

So, the new length of the brass rod at 30°C will be approximately 10.0022 meters.

Answer:

sowi d ko po knows hehe need ko lang po ng points

Explanation:

hope u understand

Answer:

40 kW

Explanation:

A railcar has a continuous 1000 N decelerating force any time it is in motion. If no braking occurs, how much power would be required to keep the railcar moving at 40 m/s

Solution:

Power in Physics is the rate of doing work and the work can be mechanical, electrical, etc. The S.I unit of power is the watts (W).

The power required to keep the car moving must match the work done by the friction force (decelerating force) that tends to slow down the railcar.

Work done = Force * displacement

Power = Work done / time = (Force * displacement) / time

Power = Force * (displacement / time)

Power = force * velocity = 1000 N * 40 m/s = 40000 W

Power = 40 kW

Covalent bond interactions and/or bonds are overcome when hydrogen at 30 k is heated to 6000 k.

Even though atomic nitrogen, is the most prevalent gas in the atmosphere, living organisms have a tough time getting nitrogen to use in the construction of nitrogenous compounds due to the strength of several degrees of covalent bonding. Two nitrogen atoms are triple linked to one another to form molecular nitrogen. Because of the resulting robust triple bond, it is challenging for biological systems to disassemble this nitrogen so that it may be used as a component of biomolecules like proteins, DNA, and RNA.

Covalent bond can be seen in the birth of water molecules. Covalent bonds hold the hydrogen and oxygen atoms that make up water molecules together.

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Answer:

teleportation (artificial or natural over wormholes )

The range of wavelengths of visible light over which zinc telluride is transparent is 550.99 nm to 700 nm.

Zinc telluride has a band gap of 2.26 eV, while the minimum photon energy given by the visible light is 1.8 eV.

It is required to determine the range of wavelengths of visible light over which zinc telluride is transparent.

It is given that the Planck's constant is 4.13 x 10^-15 eV s and that the full range of wavelength of visible light is 400-700 nm.

The formula to calculate wavelength from energy is given by;

E= hc/λ

where; E = energy, h = Planck's constant, c = speed of light, and λ = wavelength.

Rearranging the formula, we get;

λ = hc/E

Using the above formula, we can find the wavelengths of visible light as follows:

For E = 1.8 eV,λ

= hc/E = (4.13 x 10^-15 J s x 2.998 x 10^8 m/s) / (1.8 eV x 1.602 x 10^-19 J/eV)

= 688.67 nm

For E = 2.26 eV,

λ = hc/E

= (4.13 x 10^-15 J s x 2.998 x 10^8 m/s) / (2.26 eV x 1.602 x 10^-19 J/eV) = 550.99 nm

Therefore, the range of wavelengths of visible light over which zinc telluride is transparent is 550.99 nm to 700 nm.

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Red shirt appears red because:

a. The shirt reflects red light

A red shirt appears red because the shirt reflects red light.

Thus, An important topic for astronomers is "red shift." The phrase can be taken literally; when the light's wavelength is extended, the light is perceived as having "shifted" toward the red portion of the spectrum.

When a source of sound moves in relation to an observer, sound waves experience a similar phenomenon.

The frequency of sound waves varies if the source of the sound and the observer are moving relative to one another, according to Austrian mathematician Christian Andreas Doppler, who made this discovery.

The observer hears a frequency that is higher when the two are moving closer together and lower when they are moving farther apart and red shift.

Thus, A red shirt appears red because the shirt reflects red light.

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In the given problem, the wheel starts from rest and experiences a constant angular acceleration of 0.8 rad/s^2. We are asked to determine the time elapsed before a 1.6-second interval, during which the wheel rotates through an angle of 117 radians.

we can use the basic kinematic equation for rotational motion:

θ = ω₀t + (1/2)αt²

where:

θ is the angular displacement,

ω₀ is the initial angular velocity,

α is the angular acceleration,

t is the time.

Since the wheel starts from rest (ω₀ = 0), the equation simplifies to:

θ = (1/2)αt²

We are given that the wheel rotates through an angle of 117 radians in a 1.6-second interval. Plugging in these values, we can solve for t:

117 = (1/2) * 0.8 * t²

234 = 0.8 * t²

t² = 234 / 0.8

t ≈ √292.5

t ≈ 17.1 s

Therefore, at the start of the 1.6-second interval, the wheel has been in motion for approximately 17.1 seconds.

we can use the relationship between angular displacement, initial angular velocity, angular acceleration, and time. The equation for rotational motion is:

θ = ω₀t + (1/2)αt²

Since the wheel starts from rest (ω₀ = 0), the equation simplifies to:

θ = (1/2)αt²

We are given that the wheel rotates through an angle of 117 radians in a 1.6-second interval. Plugging in these values, we can solve for t:

117 = (1/2) * 0.8 * t²

234 = 0.8 * t²

t² = 234 / 0.8

t ≈ √292.5

t ≈ 17.1 s

This means that the time elapsed before the 1.6-second interval is approximately 17.1 seconds. In other words, the wheel has been in motion for about 17.1 seconds at the start of the 1.6-second interval.

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Answer:

c, 25,100 J

Explanation:

edge2o2o

The smallest component of a digital picture or graphic that can be shown on a digital display device is a pixel.

Thus, The fundamental logical unit in digital graphics is the pixel. A whole image, movie, piece of text, or other visible object on a computer monitor is made up of pixels.

The terms "pixel" and "picture element" both refer to the same thing. A dot or square on a computer monitor's display screen serves as the representation of a pixel. Geometric coordinates are used to construct the fundamental building pieces of a digital image or display, known as pixels.

The amount, size, and color mix of pixels varies and is measured in terms of the display depending on the graphics card and display monitor.

Thus, The smallest component of a digital picture or graphic that can be shown on a digital display device is a pixel.

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Answer:

Does the brass make the water get hotter or does the water make the brass get colder?

Velocity can fluctuate in magnitude, direction, or both because it is a vector. Therefore, acceleration is a change in either direction or speed, or both.

Cosmic rays are subatomic particles that have been accelerated to extremely high energies in active galactic nuclei and supernovas, which are massive stars that explode.

Understanding the mechanisms that accelerate cosmic rays is crucial because these rays contain extremely invasive radiation that can harm spacecraft electronics.

The same direction as the change in velocity is the one in which acceleration is a vector. Velocity can fluctuate in magnitude, direction, or both because it is a vector.

Therefore, Velocity can fluctuate in magnitude, direction, or both because it is a vector. Therefore, acceleration is a change in either direction or speed, or both.

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Answer:

its  A. because since heat energy means thermal i think it is A and also When friction acts between two surfaces that are moving over each other, some kinetic energy is transformed into heat energy.

Explanation: your welcome and i hope its right

Answer:

When the Sun's energy moves through space, it reaches Earth's atmosphere and finally the surface. This radiant solar energy warms the atmosphere and becomes heat energy. This heat energy is transferred throughout the planet's systems in three ways: by radiation, conduction, and convection.

Answer:

Quantity of charge = 8.5 Coulombs

Explanation:

Given the following data;

Current = 0.5 A

Time = 17 seconds

To find the charge flowing through the wire;

Mathematically, the quantity of charge passing through a conductor is given by the formula;

Quantity of charge = current * time

Substituting into the formula, we have;

Quantity of charge = 0.5 * 17

Quantity of charge = 8.5 Coulombs

Answer:

using Newton's second law answer would be 3 m/s²

Answer:

c.................................

Porter's Five Forces is a framework used to analyze the competitive intensity and attractiveness of an industry. The five forces are: Threat of New Entrants, Bargaining Power of Suppliers, Bargaining Power of Buyers, Threat of Substitute Products or Services and Intensity of Competitive Rivalry.

Threat of New Entrants: This force considers the ease or difficulty for new competitors to enter an industry. It includes barriers to entry such as high capital requirements, economies of scale, brand loyalty, and government regulations.

Example: The airline industry is known for its high barriers to entry due to the significant capital required to purchase aircraft, establish routes, and secure necessary licenses and permits. Additionally, established airlines often have loyal customer bases and strong brand recognition, making it challenging for new entrants to compete effectively.

Bargaining Power of Suppliers: This force assesses the power suppliers have over the industry in terms of pricing, quality, and availability of inputs. It considers factors such as the concentration of suppliers, uniqueness of their products, and their ability to forward integrate.

Example: In the smartphone industry, major suppliers of components like microchips and display screens hold significant bargaining power. These suppliers provide essential inputs, and their products may have limited alternatives or require specialized manufacturing processes. As a result, smartphone manufacturers must negotiate favorable terms with these suppliers to ensure a reliable supply chain and competitive pricing.

Bargaining Power of Buyers: This force examines the power customers have in influencing prices, demanding better quality or service, and potentially switching to alternative products or suppliers. It considers factors such as buyer concentration, product differentiation, and switching costs.

Example: The retail industry experiences strong buyer power, particularly in highly competitive markets. Customers have access to various options, and their ability to compare prices and products easily through online platforms empowers them to demand competitive pricing, promotions, and high-quality products and services.

Threat of Substitute Products or Services: This force looks at the availability of alternative products or services that can satisfy customer needs. It considers factors such as price-performance trade-offs, switching costs, and customer loyalty.

Example: The rise of streaming services such as Netflix, Amazon Prime Video, and Hulu posed a significant threat to traditional cable and satellite TV providers. These streaming platforms offer a wide range of content at competitive prices, allowing customers to switch from traditional TV services to streaming options, resulting in a decline in subscriber numbers for traditional providers.

Intensity of Competitive Rivalry: This force evaluates the level of competition among existing firms in the industry. It considers factors such as the number and size of competitors, industry growth rate, product differentiation, and exit barriers.

Example: The soft drink industry, dominated by major players like Coca-Cola and PepsiCo, experiences intense competitive rivalry. These companies fiercely compete for market share through advertising campaigns, new product launches, pricing strategies, and distribution channels. The rivalry is further intensified by the high market saturation and the limited scope for differentiation among similar products.

The interconnection of these forces lies in their collective influence on the competitive dynamics and profitability of an industry. Changes in one force can trigger a chain reaction that impacts the others. For instance, a high threat of new entrants may lead to increased competitive rivalry as existing firms strive to defend their market share. Similarly, a strong bargaining power of buyers can limit the pricing power of suppliers and impact their profitability. Understanding these interconnections helps businesses assess the overall attractiveness and competitive landscape of an industry and develop appropriate strategies to thrive within it.

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The order of magnitude describes a relative larger or smaller quantity. Find out what a molecule means by orders of magnitude and how they are determined.

In different situations, the term "order of magnitude" is also employed more loosely. Simply said, the phrase can refer to something that is much larger or smaller, a very huge or little number, a small or large volume of something, etc.

A number pf powers of 10 or even the numbers of power of 0.1 inside a negative number determines the order of magnitude. Ordinarily, an order of magnitude was expressed as 10 to a nth power. The order in magnitude is represented.

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