In an ideal form, action research is a collaborative process in which the researcher is actively engaged with those experiencing the problem, rather than conducting research on them.
Action research is an approach that involves actively working with individuals or communities to identify and address problems or challenges they face. It emphasizes collaboration, participation, and empowerment. The researcher, in this case, acts as a facilitator, working alongside the individuals or communities to co-create knowledge, implement interventions, and evaluate the outcomes. The goal of action research is not solely to gather information or conduct research on the participants, but rather to involve them as active partners in the research process. The researcher and the participants collaborate to understand the problem, develop solutions, and make meaningful changes that address the issue at hand. This approach aims to foster mutual learning, engagement, and transformation for all involved parties.
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i need help with this question asap
The reaction with zinc is; Zn + 2HCl → ZnCl2 + H2
The reaction with ZnO is; ZnO + 2HCl → ZnCl2 + H2O
What is the reaction of HCl with Zn and ZnO?Hydrochloric acid (HCl) reacts with both zinc (Zn) and zinc oxide (ZnO) to produce different products.
Reaction of HCl with Zinc (Zn):
When hydrochloric acid is added to zinc, a single replacement reaction takes place, and the products are zinc chloride (ZnCl2) and hydrogen gas (H2). The chemical equation for this reaction is:
Zn + 2HCl → ZnCl2 + H2
Reaction of HCl with Zinc oxide (ZnO):
When hydrochloric acid is added to zinc oxide, a double replacement reaction takes place, and the products are zinc chloride (ZnCl2) and water (H2O). The chemical equation for this reaction is:
ZnO + 2HCl → ZnCl2 + H2O
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would a cloud or a rock be more dense? PLSSSSSS HELP PLSSS I WILL MARK BRAINLIEST AND ANSWER SOME OF YOUR QUESTIONS
Which of the following statements on HPLC modes is true? A. Increasing the polarity of the mobile phase decreases the elution time of polar compounds in normal-phase HPLC B. A non-polar stationary phase is used in normal-phase HPLC C. Compounds have a lower attraction to the mobile phase than to the stationary phase in displacement development D. A polar stationary phase is used in reversed-phase HPLC E. More polar compounds elute first in normal-phase HPLC
The following statements on HPLC modes are true is more polar compounds elute first in normal-phase HPLC (Option E).
The liquid chromatography (HPLC) is a technique in analytical chemistry employed for the separation, identification, and quantification of elements. It is considered a highly sensitive method, and it works by separating the components in a mixture with the assistance of a solvent under high pressure.
There are two modes of HPLC: Reversed-Phase HPLC (RP-HPLC) and Normal-Phase HPLC (NP-HPLC). In RP-HPLC, a nonpolar stationary phase, such as C18, is used, and polar solvents, such as water, are used as mobile phases. Polar stationary phases, such as silica gel, are used in NP-HPLC, while nonpolar solvents, such as hexane, are used as mobile phases.
More polar compounds have a greater affinity for the polar stationary phase than less polar compounds, which have a higher affinity for the nonpolar mobile phase in NP-HPLC. As a result, less polar compounds elute first in normal-phase HPLC.
Thus, the correct option is E.
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Can someone help me please ?
Answer:
B
Graph 1 is An endothermic reaction and graph 2 is an exothermic reaction
How many molecules are contained in 5.78 moles of H2O? Once you have the answer, determine the log (base 10) of it and enter that value with three decimal places into the answer box. Do not add units.
The result is 25.017, which when rounded to three decimal places is 25.017. Therefore, the final answer is 25.017.
To determine the number of molecules in 5.78 moles of H2O, we need to use Avogadro's number. Avogadro's number is a constant that represents the number of particles (atoms, molecules, or ions) in one mole of a substance. It is equal to 6.022 x 10^23.
To find the number of molecules in 5.78 moles of H2O, we first need to determine the number of moles of H2O molecules present in 5.78 moles of H2O. Since each mole of H2O contains 2 hydrogen atoms and 1 oxygen atom, we need to multiply the number of moles of H2O by Avogadro's number and then multiply that result by 3 (to account for the 3 atoms in each H2O molecule).
So, the calculation would be:
5.78 moles H2O x 6.022 x 10^23 molecules/mole x 3 atoms/molecule = 1.04 x 10^25 molecules of H2O
To find the log (base 10) of this value, we can use the log function on a calculator or in Excel. The result is 25.017, which when rounded to three decimal places is 25.017. Therefore, the final answer is 25.017.
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PLS HELP - How many moles are present in 3.01 x 1023 atoms of N2 (nitrogen gas) ?
A.
0.8 moles N2
B.
0.5 moles N2
C.
1.5 moles N2
D.
2.5 moles N2
Answer:
0.5 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
\(n = \frac{N}{L} \\\)
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
\(n = \frac{3.01 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{3.01}{6.02} = 0.5 \\ \)
We have the final answer as
0.5 molesHope this helps you
how many moles are in 16.00 g of sulfur
Answer:
32.065
Hope this helps
What overall effect does adding a catalyst have on a chemical reaction? It increases pressure on the system. It increases reactant surface area. It lowers the activation energy that is needed. It lowers the concentration of reactants.
Answer:
it lowers the activation energy
Answer:
c
Explanation:
2. (**) modern vacuum pumps make it easy to attain pressures of the order of 10-13 atm in the laboratory. consider a volume of air and treat the air as an ideal gas. a. at a pressure of 9.00 * 10-14 atm and an ordinary temperature of 300.0 k, how many molecules are present in a volume of 1.00 cm3 ? b. how many molecules would be present at the same temperature but at 1.00 atm instead?
The number of air molecules in a volume of 1.00 cm3 under the conditions of the vacuum pump is 3.65 * 10-15 moles and those that would be present at the same temperature but at 1.00 atm would be 0, 04 moles
The vacuum pump is a device that extracts gas molecules from a sealed volume, to create a partial vacuum, and is frequently used in industry, especially food.
To perform both calculations considering air as an ideal gas, the equation PV = nrt is used, in which
P = Pressure
V = Volume
n = number of moles
R = Gas constant
t = temperature
Calculation of the number of air molecules in a volume of 1.00 cm3 under the conditions of the vacuum pumpData
t = 300K
V = 1L
P = 9.00 * 10-14 atm
R = 0.082 L Atm / mol °K .
n = ?
PV = nrt
n = PV/rt
n = 9.00 * 10-14. 1 / 0.082 . 300
n = 9.00 * 10-14 / 24.6
n = 3.65 * 10-15 moles
Calculation of the number of molecules present at the same temperature but at 1.00 atmData
t = 300K
V = 1L
P = 1 atm
R = 0.082 L Atm / mol °K .
n = ?
PV = nrt
n = PV/rt
n=1. 1 / 0.082 . 300
n = 1 / 24.6
n = 0.04 mole
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10) given: h2o(l) → h2o(s) and δh° = −6.02 kj at 273k calculate the entropy change of the surroundings (δssurr) when one mole of water freezes at 0°c and a pressure of one atmosphere. 10) ______
The given reaction is:h2o(l) → h2o(s)The enthalpy change (ΔH) is given as -6.02 kJ/mol at 273 K.
We have to calculate the entropy change of the surroundings (ΔSsurr) when one mole of water freezes at 0 °C and a pressure of one atmosphere.The process of freezing of water is an exothermic process as heat is released. The temperature remains constant until all the water has been converted to ice. At the freezing point of water, the entropy of the system decreases as the solid phase is more ordered than the liquid phase.
During the freezing of water, the surrounding will gain heat from the system and its temperature will rise by some amount. Therefore,ΔSsurr = -ΔH / T ΔSsurr
= -(-6.02 kJ/mol) / (273 K) ΔSsurr
= + 0.022 J/K
The entropy of the surroundings increases by 0.022 J/K when one mole of water freezes at 0 °C and a pressure of one atmosphere.
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Which of the alkene shown groups produces the strongest signal in an IR spectrum? F CI Br 11 III IV 11 III IV
The halogen group that produces the strongest signal in an IR spectrum is chlorine (CI).
The term "infrared (IR) spectrum" refers to the range of frequencies of light that is absorbed by a molecule's bonds when a particular kind of energy (IR radiation) is applied to it. Infrared spectroscopy is a technique that detects these light frequencies, allowing us to determine the functional groups and bonding in a molecule.Infrared Spectroscopy is used to identify the presence or absence of functional groups in a molecule. It also indicates what type of functional group is present in the compound. It is a useful analytical tool for determining molecular structures, identifying unknown substances, and monitoring reaction progress.
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Which items are fuel for physical activity.
Select 2 correct answer(s)
options:
A)Specialized sports drinks
B)Food Intake
C)Supplementation
D)Water Intake
Answer:
Water Intake,Food Intake
Explanation:
If you have 3 moles of CO₂, how many atoms of Oxygen (0) do you have
if the percent yield is equal to 100%, then
Answer:
If the percent yield is 100%, the actual yield will be equal to the theoretical yield
Explanation:
percent yield = actual yield divided by theoretical yield
percent yield = actual yield / theoretical yield
If you can run 6km in 24 minutes, how many cm can you run in 5 hours?
Answer:
7500000cm/hr
Explanation:
6km=600000cm
24min=24/60hr=0.4hr
so, according to the question
6k/24km=600000cm÷0.4hr
=1500000cm/hr
therefore in 5 hours we can run:
5×1500000cm/Hr
=7500000cm/hr
A person can run "7,500,000 cm" in 5 hours.
According to the question,
A person can run 6 km in 24 minutes, i.e.,
= \(\frac{6}{24} \ km/min\)
and,
5 hours = 300 minutes
then,
→ A person can run in 5 hours:
= \(\frac{6}{24}\times 300\)
= \(\frac{1800}{24}\)
= \(75 \ km\)
By converting km into cm, we get
= \(7500000 \ cm\)
So the above is the right answer.
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Which has the most thermal energy?
Answer:
Explanation:
If all other conditions are the same, substances in gas form have the most thermal energy, followed by liquids, then solids. Temperature can be measured with a thermometer. The matter inside a thermometer expands as its particles gain thermal energy and move.
What is the volume at STP of 3.44 x 1023 molecules of CO2
gas?
a 25.1L
b 39.2 L
С
12.8 L
d 15.7 L
Answer:
C. 12.8 liters.
Explanation:
The Standard Temperature and Pressure (STP) of a gas are 273.15 K and 100 kilopascals. From Avogadro's Law, a mole of carbon dioxide contains \(6.022 \times 10^{23}\) molecules. If we suppose that carbon dioxide behaves ideally, then the equation of state for ideal gas is:
\(P\cdot V = n\cdot R_{u}\cdot T\) (1)
\(P\cdot V = \frac{r\cdot R_{u}\cdot T}{N_{A}}\) (1b)
Where:
\(P\) - Pressure, measured in pascals.
\(V\) - Volume, measured in liters.
\(r\) - Amount of molecules, no unit.
\(N_{A}\) - Avogadro's number, no unit.
\(R_{u}\) - Ideal gas constant, measured in pascal-liters per mole-Kelvin.
\(T\) - Temperature, measured in Kelvin.
If we know that \(P = 100000\,Pa\), \(r = 3.44\times 10^{23}\), \(N_{A} = 6.022\times 10^{23}\), \(T = 273.15\,K\) and \(R_{u} = 8.314\times 10^{3}\,\frac{L\cdot Pa}{mol\cdot K}\), then the volume of carbon dioxide at STP is:
\(V = \frac{r\cdot R_{u}\cdot T}{N_{A}\cdot P}\)
\(V = \frac{(3.44\times 10^{23})\cdot \left(8.314\times 10^{3}\,\frac{L\cdot Pa}{mol\cdot K} \right)\cdot (273.15\,K)}{(6.022\times 10^{23})\cdot (100000\,Pa)}\)
\(V = 12.972\,L\)
Therefore, the correct answer is C.
which of these molecules best corresponds to the IR spectrum of an unknown compound with the molecular formula C4H8O2? 24 Which of these molecules best corresponds to the IR spectrum of an unknown compound with the molecular formula C4HaOz? HOOCH X 0.8 CHO2 0.6 0.4 0.2 0.0 3000 2000 Wavenumber(cm-1 1000
CHO2 is the molecule that best corresponds to the IR spectrum of the unknown compound with the molecular formula C4H8O2.
To determine which molecule best corresponds to the IR spectrum of an unknown compound with the molecular formula C4H8O2, we need to analyze the functional groups present in the compound and compare them to the given options.
The molecular formula C4H8O2 suggests that the compound contains 4 carbon atoms, 8 hydrogen atoms, and 2 oxygen atoms.
Looking at the given options, we have:
1. HOOCH
2. CHO2
To identify the functional groups present, we need to consider the characteristic absorption peaks in the IR spectrum. Some important absorption regions to consider are:
- Around 3000 cm-1: Associated with C-H stretching vibrations of alkanes and alkenes.
- Around 1700 cm-1: Associated with C=O stretching vibrations of carbonyl groups.
From the given options, only CHO2 contains a carbonyl group (C=O), which corresponds to the molecular formula C4H8O2. This indicates that CHO2 is the molecule that best corresponds to the IR spectrum of the unknown compound with the molecular formula C4H8O2.
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what is the solubility (in mol/l) of silver chromate in 1.50 m potassium chromate aqueous solution?
The solubility of silver chromate in a 1.50 M potassium chromate aqueous solution is 4.3 x 10^-7 mol/L.
To determine the solubility of silver chromate (Ag₂CrO₄) in a 1.50 M potassium chromate (K₂CrO₄) solution, we can use the solubility product constant (Ksp) and the common ion effect.
The solubility product constant for Ag₂CrO₄ is given as 1.1 x 10^-12.
Let's assume the solubility of Ag₂CrO₄ in the potassium chromate solution is 's' mol/L.
According to the solubility product expression for Ag₂CrO₄:
Ksp = [Ag⁺]²[CrO₄²⁻]
We know that the concentration of chromate ions, [CrO₄²⁻], is 1.50 M.
Since Ag₂CrO₄ dissociates into two Ag⁺ ions and one CrO₄²⁻ ion:
[Ag⁺] = 2s
[CrO₄²⁻] = 1.50 M
Substituting these values into the solubility product expression:
Ksp = (2s)² * (1.50)
1.1 x 10^-12 = 4s^2 * 1.50
Dividing both sides by 6, we get:
1.83 x 10^-13 = s²
Taking the square root of both sides, we find:
s ≈ 4.3 x 10^-7 mol/L
Therefore, the solubility of silver chromate in the 1.50 M potassium chromate solution is approximately 4.3 x 10^-7 mol/L. This solubility is about 100 times less than the solubility of silver chromate in pure water.
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1. s orbital(s) and p orbital(s) form sp3 orbital(s).target 1 of 9target 2 of 9target 3 of 9 2. s orbital(s) and p orbital(s) form sp2 orbital(s).target 4 of 9target 5 of 9target 6 of 9 3. s orbital(s) and p orbital(s) form sp orbital(s).
A sphere surrounds the atomic nucleus called the s orbital. There are shells within the sphere where an electron is more likely to be discovered right now. 1s is the smallest sphere. Greater than the 1s orbital are the 2s and 3s orbitals.
Each p orbital has two lobes, that are located on either side of the plane of the nucleus. The three p orbitals are equal in terms of size, shape, and energy, but they differ in how the lobes are orientated. These three orbitals are referred to as 2px, 2py, and 2pz because the lobes are located along one of the x, y, or z-axis. Similar to s orbitals, p orbitals grow in size and energy as the primary quantum number rises (4p > 3p > 2p).
sp3 orbital: One of a group of hybrid orbitals that result from mathematically combining one s orbital and three p orbitals to create four new equivalent orbitals that are directed toward the corners of a regular tetrahedron.
One of the hybrid orbitals created when one s orbital and one p orbital are mathematically merged to create two new equivalent, perpendicular orbitals is the sp orbital. With the exception of being closer to the nucleus, sp orbitals resemble p orbitals in appearance.
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Identifying Parts of a Chemical Reaction
Given chemical reaction,
Glucose + Oxygen → carbon dioxide + water
Reactants : Glucose and oxygen.
Products : carbon dioxide and water.
Parts of chemical reaction:Each chemical reaction is made up of three main components: the reactants (located on the left side of the reaction equation), the products (located on the right side of the reaction equation), and the particular reaction conditions, which are listed above or below the arrows in the middle of the reaction equation.
Combustion is one of the five fundamental types of chemical reactions, along with combination, decomposition, single-replacement, and double-replacement. You can classify a reaction into one of these groups by looking at the reactants and products of the reaction in question. It is possible for some reactions to fall into more than one category.
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1-calculate the mass of 4 moles of Na
2-what is the mass of 0.3 moles of water H2o H:1 O:16
3-compute the number of moles found in 10g of ethanol C2H5OH C:12 O:16
please help me as fast you can
1. 92 g
2. 5.4 g
3. 0.217 moles
Further explanationThe mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
Moles can also be determined from the amount of substance mass and its molar mass
\(\tt n=\dfrac{m}{MW}\)
1. the mass of 4 moles of Na(MW= 23 g/mol)
\(\tt mass=mol\times MW\\\\mass=4\times 23\\\\mass=92~g\)
2. the mass of 0.3 moles of water(MW=18 g/mol)
\(\tt mass=mol\times MW\\\\mass=0.3\times 18\\\\mass=5.4~g\)
3. the number of moles found in 10g of ethanol C2H5OH(MW=46 g/mol) :
\(\tt mol=\dfrac{10}{46}\\\\mol=0.217\)
someone please help we with this. I’m genuinely not in the mood to do anything rn. Plus my teacher did a horrible job at explaining what I’m supposed to do.
Associating numbers with physical quantities and events is the process of measuring. The sciences, engineering, building, and other technological professions, as well as practically all daily activities, all depend on measurement. The calculated answers to the questions from measurement are as follows.
a. represents mass concentration
b. represents time
c. represents energy
d. represents mass
e, represents volume
f, represents speed
g. represents volume
h. represents capacity
i. represents mass
j. represents capacity
By definition, unit conversion refers to the division or multiplication operation used to convert measurements of the same quantity between various units. The act of converting something from one form to another in mathematics, such as from inches to millimeters or from liters to gallons, is known as conversion.
conversions-
a. 0.015 kg
b. 1570 m
c. 3.54 x 10⁻⁶
d. 3.5 x 10⁶
e.1200 ml
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step 4: if a chiral center is formed from grignard addition, a mixture of enantiomers will be formed. the grignard reagent can attack at either the top face or bottom face of the carbonyl to give an equal mixture of chiral products. which carbonyls will give an achiral product after a grignard reaction with ch3mgbr ?
The carbonyls that will give an achiral product after a Grignard reaction with ch3mgbr is option E diagram in the image attached.
What is the Grignard reaction about?Alkyl or aryl-magnesium halides (the Grignard reagent) are applied to a carbonyl group in an aldehyde or ketone to produce the Grignard reaction (French: [ia]). The creation of carbon-carbon bonds depends on this process.
A symmetrical ketone will not produce a mixture of isomers since the Grignard reagent will react with it to produce a product with a plane of symmetry.
Asymmetrical ketones include cyclopentanone and 3-pentanone (pentan-3-one). Additionally, because the end product is a tertiary alcohol bound to two methyl groups and an ethyl group, 2 butanone (butan 2 ol) will likewise produce an achiral compound.
Therefore, The result will contain at least one chiral center formed by the remaining substances, which are all asymmetric ketones or an aldehyde.
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Objects with potential energy got that energy:
A. Entirely from their height above the earth.
B. After work was performed on them.
C. When kinetic energy was released from fossil fuels.
D. Through electromagnetic discharges.
Answer:
D. Through electromagnetic discharges.
Explanation:
What is the role of the primary standard in an acid-base titration?.
The role of the primary standard in an acid-base titration is to serve as a reference to which the volume of the solution being analyzed can be compared. It should have high purity, a high molecular weight, and a composition that is chemically pure. The standard acid and standard base must be stable, water-soluble, and easily obtainable.
In an acid-base titration, a primary standard is a highly purified solid material that can be dissolved in water to produce a clear solution with a specific concentration. The solution is used to determine the concentration of an unknown solution, such as an acid or a base.The role of the primary standard is to establish the equivalence point of the titration, which is when the acid and base have reacted in a 1:1 ratio. The standard acid and base must be stable, water-soluble, and easily obtainable. In addition, they should have high purity, a high molecular weight, and a composition that is chemically pure.
In conclusion, the primary standard is essential in an acid-base titration because it serves as a reference to which the volume of the solution being analyzed can be compared. It should have high purity, a high molecular weight, and a composition that is chemically pure. The standard acid and base must be stable, water-soluble, and easily obtainable.
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the smoke inhaled from a burning cigarette contains a mix of over how many chemicals?
The smoke inhaled from a burning cigarette contains a mix of over 7,000 chemicals, including nicotine, tar, and carbon monoxide, many of which are toxic and carcinogenic.
How does smoking affect the body?Smoking can cause a wide range of health problems, including lung cancer, heart disease, stroke, respiratory infections, and chronic obstructive pulmonary disease (COPD). It can also affect the reproductive system, increase the risk of osteoporosis, and damage the skin and teeth.
What are some strategies for quitting smoking?There are several strategies that can be effective in quitting smoking, including nicotine replacement therapy, medication, counseling, and support groups. Quitting smoking can be challenging, but it can significantly improve overall health and reduce the risk of serious health problems.
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What volume of HCl must be used to prepare 350mL of 2.0M HCl solution using a stock solution containing 5L of 12.0M HCl?
Answer:
~58.3 mL
Explanation:
m1*v1=m2*v2 --> (12.0 M HCL) * v1 = 350mL * 2.0M HCL
--> 350*2.0 = 700
--> 700/12.0 M HCL = 58.3 mL repeating
The pH of the ocean is around 8.1, is the ocean considered a
buffer? Why or Why not?
Yes, the sea is considered a buffer.
A buffer is a solution that resists pH changes when acids or bases are added. The buffering capacity of the ocean allows it to maintain a relatively stable pH even when acids and bases are added.
The ocean's buffering capacity is primarily due to the presence of dissolved compounds such as bicarbonate (HCO3-) and carbonate (CO32-). These compounds act as both weak acids and bases, accepting and releasing hydrogen ions (H+) to maintain pH balance. When carbon dioxide (CO2) in the atmosphere dissolves in seawater, carbonic acid (H2CO3) is produced and decomposed into bicarbonate ions and hydrogen ions.
This transformation helps prevent a rapid drop in pH as excess hydrogen ions combine with carbonate ions to form bicarbonate ions, which can reduce overall acidity.
When alkali such as hydroxide ions (OH-) is added to the ocean, excess hydroxide ions combine with hydrogen ions to form water molecules, reducing alkalinity.
The presence of these dissolved compounds and their interconversion reactions stabilize the pH of the ocean, making it less susceptible to rapid changes in acidity or alkalinity. This buffering capacity is essential for the survival and maintenance of marine life, as many organisms are sensitive to changes in pH.
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2. Predict the shift in the reaction with each stress shift rt, shift left, or no
HEAT + Ti(s) + 2C1 (g)
a. CI, (g) is added to the system.
b. TiCk (g) is removed from the system.
TiCI (g)
c. The temperature of the container is decreased.
d. The pressure of the container is increased.,
e. Ti(s) is added to the system.