Imagine a flat circular plate with an area of 15 m2, thickness 0.4 m, and an area moment of inertia about the x-axis of 27 m4. If the density of this plate is 4 kg/m3, the mass moment of inertia about the x-axis is: _________
Answers
The mass moment of inertia about the x-axis is 33.95 m⁴.
Given,
Area of the circular plate = 15 m²
Thickness of the plate = 0.4 m
Area moment of inertia about the x-axis = 27 m⁴
Density of the plate = 4 kg/m³
The mass moment of inertia about the x-axis is given by the formula:
Ixx = (ρ×A/12)×(h² + b²)
where, ρ is the density of the plate
A is the area of the plate
h is the thickness of the plate
b is the area moment of inertia about the x-axis
Substituting the given values in the formula, we get
Ixx = (ρ×A/12)×(h² + b²)
Ixx = (4×15/12)×(0.4² + 27)
Ixx = 1.25×(0.16 + 27)
Ixx = 1.25×27.16
Ixx = 33.95
Therefore, the answer is 33.95 m⁴.
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Related Questions
a capacitor is connected to a 15 khz oscillator. the peak current is 65 ma when the rms voltage is 6.0 v.
Answers
Answer:
here is the answer
Explanation:
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If you walk 10.0 m horizontally forward at a constant velocity carrying a 20 N object, the amount of work you do is A) more than 200 J. B) equal to 200J C) less than 200 J, but more than 0J D) zero.
Answers
If you walk 10.0 m horizontally forward at a constant velocity carrying a 20 N object, the amount of work you do is equal to 200J. Therefore, the correct option is B.
The work done by an object is given by the equation W = Fd cos θ. In this case, a person walks 10.0 m horizontally forward at a constant velocity while carrying a 20 N object. The amount of work they do can be calculated by using the above equation.
The work done can be found by multiplying force and displacement. However, the direction of the force and the displacement matters. The force and displacement should be in the same direction. This is known as the dot product of the force and displacement.
W = F.d cos θ
Where, W = Work done, F = force in the direction of displacement, d = displacement, and θ = angle between force and displacement
The force exerted by the person is 20 N, which is acting horizontally in the direction of displacement. Therefore, θ = 0°.
Cos 0° = 1
W = F.d.1
W = 20 N.10 m
W = 200 J
Therefore, the work done by the person is 200 J. So, the correct option is B) equal to 200 J.
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A rocket is launched from the surface of the earth with a speed of 9.0x103 m/s. What is the maximum altitude reached by the rocket? (MEarth=5.98x1024 kg, REarth=6.37x106 m)
Answers
From the Law of conservation of energy, we know that the sum of the kinetic and potential energy of the rocket is the same at the surface of the Earth and at the maximum altitude. Nevertheless, the kinetic energy of the rocket when it is at the maximum altitude is 0:
\(\begin{gathered} K_1+U_1=K_2+U_2 \\ K_2=0 \\ \Rightarrow K_1+U_1=U_2 \end{gathered}\)The kinetic energy is given by:
\(K=\frac{1}{2}mv^2\)On the other hand, the gravitational potential energy for big changes in altitude (comparable to the radius of the Earth) is given by the expression:
\(U=-\frac{GMm}{r}\)Where M is the mass of the Earth, m is the mass of the rocket, r is the distance from the center of the Earth to the rocket and G is the gravitational constant:
\(G=6.67\times10^{-11}N\cdot\frac{m^2}{\operatorname{kg}}\)At the beggining of the movement, the value of r corresponds to the radius of the Earth:
\(U_1=-\frac{GMm}{R_E}\)At the end of the movement, the value of r corresponds to the radius of the Earth plus the maximum altitude h:
\(U_2=-\frac{GMm}{R_E+h_{}}\)Substitute the expressions for U_1, K_1 and U_2 and simplify the equation by eliminating the factor m:
\(\begin{gathered} \frac{1}{2}mv^2-\frac{GMm}{R_E}=-\frac{GMm}{R_E+h} \\ \Rightarrow\frac{1}{2}v^2-\frac{GM}{R_E}=-\frac{GM}{R_E+h} \end{gathered}\)Isolate the term GM/(R_E+h):
\(\Rightarrow\frac{GM}{R_E+h}=\frac{GM}{R_E_{}}-\frac{1}{2}v^2\)Divide both sides by the factor GM:
\(\Rightarrow\frac{1}{R_E+h}=\frac{1}{R_E}-\frac{v^2}{2GM}\)Take the reciprocal to both sides of the equation:
\(\Rightarrow R_E+h=\frac{1}{\frac{1}{R_E}-\frac{v^2}{2GM}}\)Isolate h:
\(h=\frac{1}{\frac{1}{R_E}-\frac{v^2}{2GM}}-R_E\)Substitute the values of each variable: R_E=6.37x10^6m, M=5.98x10^24kg, G=6.67x10^-11 N*m^2/kg^2, and v=9.0x10^-3 m/s:
\(\begin{gathered} h=\frac{1}{\frac{1}{6.37\times10^6m}-\frac{(9.0\times10^3\cdot\frac{m}{s})^2}{2(6.67\times10^{-11}N\cdot\frac{m^2}{kg^2})(5.98\times10^{24}kg)}}-6.37\times10^6m \\ =18.03\times10^6m-6.37\times10^6m \\ =11.7\times10^6m \end{gathered}\)Therefore, the maximum altitude reached by a rocket with an initial speed of 9.0x10^3m is:
\(11.7\times10^6m\)A Saturn V Moon rocket has a mass at lift-
off of 3.0 x 106 kg. The thrust at lift-off is
3.3 × 107 N. Find:
a) the weight of the rocket on Earth
b) the resultant (unbalanced) force at lift-off
c) the acceleration at lift-off
d) the apparent weight of the rocket in orbit.
Answers
Explanation:
a) weight = m * g = 3 x 10^6 kg * 10 m/s^2 = 3.0 x 10^7 N
b) Thrust - weight = 3.3 x 10^7 N - 3.0 x 10^7 N = 3 x 10^6 N
c) F = ma 3. x 10^6 = 3 X 10^6 * a solve for 'a' = 1 m/s^2
d) weightless (but not massless)
While underway in fog, you hear a vessel sound one prolonged blast followed by two short blasts.What does this signal indicate
Answers
Given what we know, we can confirm that while underway in fog, the sound of one prolonged blast followed by two short blasts can indicate a vessel towing.
Why is this important?These signals can be of vital importance for the safety of the crew of both ships involved. With visibility diminished in fog, these sounds allow the ships to know the approximate position of other nearby ships. Signaling that a towing is taking place will also indicate a limited range of movement for the towing ship, making it extra important to not be on a collision course.
Therefore, we can confirm that while underway in fog, the sound of one prolonged blast followed by two short blasts can indicate a vessel towing.
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A) make a claim on how humans impact the distribution of resources by...
B) what evidence have you discovered to explain how humans impact mineral distributions?
C) what evidence have you discovered to explain how humans impact fuel reserves
Answers
(A) Humans impact the distribution of resources by altering the natural processes that govern the distribution of resources such as minerals, fuel reserves, and water.
(B) Mining is one way in which humans impact mineral distributions.
(C) Humans impact fuel reserves through the extraction and consumption of fossil fuels.
What is the humans impact the distribution of resources?Human activities such as mining, drilling, and deforestation, humans disrupt the natural balance of resources, which can lead to resource depletion or an uneven distribution of resources.
By extracting minerals from the earth, humans can deplete or alter the natural distribution of these resources.
Additionally, mining can result in the release of toxic chemicals and heavy metals into the environment, which can have detrimental effects on ecosystems and human health.
The burning of fossil fuels releases greenhouse gases, which contribute to climate change. Additionally, the extraction of fossil fuels can have negative impacts on ecosystems, including habitat destruction and water pollution.
The use of fossil fuels also contributes to geopolitical tensions and conflicts, as countries compete for access to these resources. In recent years, there has been a growing recognition of the need to transition to cleaner, renewable energy sources in order to mitigate the negative impacts of human activities on fuel reserves and the environment.
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A particle is constrained to travel along the path (Figure 2). If X = (4t4)m, where t is in seconds, determine the magnitude of the particle's velocity and acceleration when 0.5 s. The ball is thrown off the top of the building
Answers
The magnitude of the particle's velocity at t = 0.5 s is 2 m/s and the magnitude of its acceleration is 12 m/s^2.
The magnitude of the particle's velocity and acceleration can be found by taking the first and second derivative of the position equation, respectively.
First, let's find the velocity:
v = dX/dt = d(4t^4)/dt = 16t^3
At t = 0.5 s, the velocity is:
v = 16(0.5)^3 = 2 m/s
Now, let's find the acceleration:
a = dv/dt = d(16t^3)/dt = 48t^2
At t = 0.5 s, the acceleration is:
a = 48(0.5)^2 = 12 m/s^2
Therefore, the magnitude of the particle's velocity at t = 0.5 s is 2 m/s and the magnitude of its acceleration is 12 m/s^2.
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The periodic table includes
_____ periods.
Answers
There are currently seven complete periods in the periodic table
Answer:
The periodic table includes
Seven periods and Eighteen groups
4. If the circuit below draws a current of 0.195 A, what is the equivalentresistance? Hint: Use Ohm’s law.
Answers
62.53 ohms
Explanation
Ohm's law states that the voltage or potential difference between two points is directly proportional to the current or electricity passing through the resistance, and directly proportional to the resistance of the circuit.
\(\begin{gathered} V=IR \\ so \\ R=\frac{V}{I} \end{gathered}\)then
Step 1
a)let
\(\begin{gathered} V=12.0\text{ v} \\ I=0.195\text{ A} \end{gathered}\)now, replace in the formula
\(\begin{gathered} R=\frac{V}{I} \\ R=\frac{12.0\text{ v}}{0.195\text{ A}} \\ R=62.53\text{ }\Omega \end{gathered}\)therefore, the answer is
62.53 ohms
I hope this helps you
Select the definition that best describes the term “ultimate tensile strength.”
Answers
Ultimate tensile strength is the maximum stress that a material can withstand just before fracture.
What is stress?
Stress is defined as the force acting per unit area. It is denoted by Sigma(σ)
When a body is undergoing stretch by applying a pull force, it stretches more and more until it reaches its elastic limit. A point comes when the body no more stretches and breaks or fractures at bottle neck formation. This strength of any material is known as Ultimate breaking Stress or Ultimate tensile strength.
Thus, Ultimate tensile strength is the maximum stress that a material can withstand just before fracture.
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34. Why is it that an object can accelerate while
traveling at constant speed, but not at con-
stant velocity?
Answers
Answer:
The direction in which this object travels might be changing.
Explanation:
Velocity is a vector quantity. In addition to the rate at which this object moves, velocity also measures the direction of the motion.
In contrast, speed is a scalar quantity. The speed of an object also measure the rate at which this object moves. However, unlike velocity, speed does not account for the direction of the motion.
Hence, even if speed is constant, velocity of this object might not be constant as long as the direction of the motion is changing.
For example, consider an object moving around a circle at a constant rate. The speed of this object will be constant since the rate of the motion is constant. However, the velocity of this object will not be constant since the object needs to keep changing its direction to stay on the track.
The stratigraphy in a site from top to bottom are (1) 4.5 m thick sand; (2) 4.5 m thick clay; (3) impermeable shale. The water table is at a depth of 2 m below ground. The sand above the water table has a void ratio of 0.52 and a saturation degree of 37%. The clay has a moisture content of 42%. The specific gravity of both the sand and clay is 2.65 . After constructing a foundation whose bottom is at a depth of 3 m, the extra stress at the top and the bottom of the clay layer is 100kPa and 40kPa, respectively. According to the consolidation test, the void ratio of the clay corresponding to 50,100 and 200kPa are 1.02,0.922 and 0.828 , respectively. The settlement of the clay layer will be (mm). (One-dimensional settlement is applicable. The density of water is 1000 kg/m 3
)
Answers
The settlement of the clay layer will be determined by the consolidation characteristics of the soil.
Given the stratigraphy and soil properties provided, the settlement can be calculated using the one-dimensional consolidation theory. The settlement of the clay layer is expected to be 12.34 mm.
To calculate the settlement of the clay layer, we can utilize the one-dimensional consolidation theory. The extra stress at the top and bottom of the clay layer (100 kPa and 40 kPa, respectively) and the void ratio of the clay corresponding to different pressure levels (50 kPa, 100 kPa, and 200 kPa) are provided.
First, we need to calculate the initial void ratio (e0) of the clay layer. The initial void ratio is obtained from the moisture content of the clay, which is given as 42%. Using the equation e0 = (moisture content)/(1 - moisture content), we find that e0 = 0.72.
Next, we calculate the average effective stress (σ') applied to the clay layer. The average effective stress is given by σ' = (extra stress at the top + extra stress at the bottom)/2. Plugging in the values, σ' = (100 kPa + 40 kPa)/2 = 70 kPa.
Using the relationship between void ratio and applied pressure (e vs. log σ' curve), we can determine the corresponding void ratio (e') at the average effective stress. From the given data, we interpolate the values to find that e' = 0.916.
Now, we can calculate the compression index (Cc) of the clay layer. Cc is the slope of the e vs. log σ' curve, and it is determined by subtracting the void ratio at a higher pressure level from the void ratio at a lower pressure level and dividing it by the logarithm of the ratio of the two pressure levels. From the provided data, Cc = (0.922 - 0.828)/log(200 kPa/100 kPa) = 0.055.
Finally, we can calculate the settlement (S) of the clay layer using the equation S = (Cc * Δσ') / (1 + e0). Plugging in the values, S = (0.055 * 70 kPa) / (1 + 0.72) = 12.34 mm.
Therefore, the settlement of the clay layer is estimated to be 12.34 mm.
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How many calories you need per day to maintain your current weight.
Answers
20 POINTS…
If the particles within two objects have the same kinetic energy, are the two objects at the same temperature? Explain?
Please someone answer this
Answers
The rate of molecular motion will increase as the temperature rises. At the same temperature, an object with less massive molecules will have a faster molecular speed. Two objects with the same average kinetic energy will have the same temperature when kinetic temperature is applied.
Which example shows an endothermic reaction?
reactants + thermal energy --> products
products + thermal energy --> reactants
products --> reactants + thermal energy
reactants --> products + thermal energy
please help
Answers
Answer:
reactants --> products + thermal energy
Explanation:
Heat is absorbed in endothermic reaction.
Which statement accurately describes how the acceleration of an object in free fall changes?
O A. It accelerates downward at a constant rate.
O
B. It accelerates downward at an increasing rate.
C. It accelerates downward at an irregular rate.
D. It accelerates downward at a decreasing rate.
Answers
Answer: A
Explanation: An object in free fall only is affected by gravity, so the acceleration is 9.8 m/s²
It takes 77.4 N to push a 43.8 kg
crate at a constant speed across
flat ground. What is the
coefficient of kinetic friction?
(No unit)
Answers
Answer:
0.180
Explanation:
(Applied Force) / (Weight) = Coefficient of kinetic friction
(77.4 N) / (43.8 kg * 9.81 m/s/s) = 0.180
.180 is indeed the correct answer for acellus
a truck moves with a speed of 90 km/h for 45 mins and 120 km/h for next 20 mins find average speed
Answers
Average speed a truck moves with a speed of 90 km/h for 45 mins and 120 km/h for next 20 mins is 40.72km/h.
Average speed = Total distance / Total time
S = 73.3/ 1.8
S = 40.72km/h
Given:
90 km/h is the speed.
Time = 0.75 hours * 45 minutes
To calculate the distance travelled, substitute the following values into the distance formula:
Distance (D) is equal to the product of speed and time, hence D = 90 * 0.75 = 33.75 km.
Given:
120 km/hr speed
Time = 20 minutes = 0.3333 hours
To calculate the distance travelled, substitute the following values into the distance formula:
Consequently, the distance travelled overall is:
Distance equals speed times time, so D = 120*0.33 D = 39.6 km.
Distance is a measurement of how far apart two things or points are, either numerically or occasionally qualitatively. Distance can refer to a physical length in physics or to an estimate based on other factors in common usage.
Use the formula d = st, or distance equals speed times time, to find the distance.
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A 70.0 kg person leaps from a bridge in with a bungee cord attached and falls 120 meters. If the bungee cord stretches 2.5 meters during the stopping process, what’s its force constant (k)?
Answers
The force constant of the bungee cord when a person of mass 70 kg leaps on a bridge with it is 219.52 N/m.
What is force constant?The force constant or spring constant is a measure of the stiffness of a spring. It is the force per unit deformation of the spring. Its SI unit is N/m.
To calculate the force constant of the bungee cord, we use the formula below.
Formula:
K = 2mgh/e²............. Equation 1Where:
K = Force contant of the bungee cordm = Mass of the persong = Acceleration due to gravityh = Height at which the person falle = extensionFrom the question,
Given:
m = 70 kgg = 9.8 m/s²h = 120 me = 2.5 mSubstitute these values into equation 1
K = (2×70×9.8/2.5²)K = 219.52 N/mHence, the force constant of the bungee cord is 219.52 N/m.
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A pendulum makes 50 complete swings in 2 min 40 s.
What is the time period for 1 complete swing?
Answers
Answer:
50 swings = 2 mins 40 secs
=> 50 swings = 160 secs
=> 1 swing = 160 / 50 secs
=> 1 swing -= 3.2 secs
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Thank You!!
The time period to complete 1 swing is 3.2 seconds
The calculation can be done as follows;
50 complete swings are completed in 2 minutes 40 seconds
2 minutes 40 seconds to seconds is
= 2mins to seconds is 120 seconds
= 120 seconds + 40 seconds
= 160 seconds
50 complete swings= 160 seconds
1 complete swing= 160/50
1 complete swing= 3.2
Hence the time period for 1 complete swing is 3.2 seconds
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Energy that is stored is called...
Answers
Answer:
Potential energy
Explanation:
Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy. Electrical Energy is the movement of electrical charges. Everything is made of tiny particles called atoms.
- Scientific Forms of Energy_ Stored Energy, Kinetic Energy ...ei.lehigh.edu › learners › energy › readings › energy_basics
Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy. Electrical Energy is the movement of electrical charges.
A soccer ball is kicked from the top of a cliff in such a manner that its x and y components are given by x = (20.5 m/s) and y = 36.5 m + (30.0 m/s) - (4.90 m/s?)e?, where x and y will be in meters when t is in seconds. Determine the following. (Express your answer in vector form.) (a) displacement of the ball during the time interval At = 0 - 3.00 S Ar = m (b) average velocity of the ball during the time interval At = 0 - 3.00 s m/s Vavg - (c) acceleration of the ball during the time interval At = 0 -- 3.00 s m/s2
Answers
The acceleration of the ball during the time interval At = 0 - 3.00 s is;a = (6.83 i - 10 j) m/s².
The given components of the soccer ball, x and y are given by; x = (20.5 m/s)y = 36.5 m + (30.0 m/s) - (4.90 m/s²)eᵣ where x and y will be in meters when t is in seconds.
(a) The displacement of the ball during the time interval At = 0 - 3.00 S = (x + y)tAr = m
The vertical component of the displacement of the ball is given by; y = uᵢt + ½at²; where, uᵢ = 30 m/s, a = -9.8 m/s² and t = 3 s.
Substituting values, we get; y = 30(3) + ½(-9.8)(3)²= 45.6 m
The horizontal component of the displacement is given by; x = vt; where v = 20.5 m/s and t = 3 s.
Substituting values, we get; x = 20.5(3)= 61.5 m
Therefore, the displacement of the ball during the time interval At = 0 - 3.00 S is; r = (61.5 i + 45.6 j) m
(b) The average velocity of the ball during the time interval At = 0 - 3.00 s is given by; vavg = Δr/Δt where, Δr = displacement during the time interval At = 0 - 3.00 s= (61.5 i + 45.6 j) mand, Δt = 3 s
Substituting values, we get; vavg = (61.5 i + 45.6 j)/3= (20.5 i + 15.2 j) m/s
Therefore, the average velocity of the ball during the time interval At = 0 - 3.00 s is; vavg = (20.5 i + 15.2 j) m/s
(c) The acceleration of the ball during the time interval At = 0 - 3.00 s is given by;a = Δv/Δtwhere, Δv = change in velocity during the time interval At = 0 - 3.00 s.
Substituting values of Δv in horizontal and vertical directions, we get; Δvₓ = 20.5 - 0= 20.5 m/sΔvᵧ = 0 - 30= -30 m/s
Therefore, Δv = (20.5 i - 30 j) m/s
And, Δt = 3 s
Substituting values, we get;a = (20.5 i - 30 j)/3= (6.83 i - 10 j) m/s²
Therefore, the acceleration of the ball during the time interval At = 0 - 3.00 s is;a = (6.83 i - 10 j) m/s².
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Which of the following is an application where heat from electricity is a desired outcome?
I. Electric clothes dryer
II. Iron
III. Space heater
IV. Toaster
V. Water pump
Answers
Space heaters are the only application on the list where heat from electricity is the desired outcome. They are a convenient and efficient way to warm up a specific area or room, especially during cold weather.
The application where heat from electricity is a desired outcome is Space heater. Space heaters are designed to generate heat from electricity and warm up a specific area or room. They work by passing an electrical current through a resistive element, such as a coil of wire, which converts electrical energy into heat energy. The heat is then transferred to the surrounding air, warming up the room.
Electric clothes dryers, irons, toasters, and water pumps all use electricity to perform their respective functions, but heat is not the desired outcome. Electric clothes dryers use electricity to rotate a drum and create hot air to dry clothes. Irons use electricity to heat up a metal plate and smooth out wrinkles in clothes. Toasters use electricity to heat up metal wires and toast bread. Water pumps use electricity to circulate water through pipes or hoses.
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80 POINTS!!! How do I find the strength of the drag? I have tried inputting 3957, 7509, 60146.4 and theyre all wrong. Please show work!!
Answers
Answer:
The strength of drag can be found by using the drag equation:
Drag = 1/2 * air density * velocity^2 * drag coefficient * reference area
where air density is the density of the fluid (air, water, etc.), velocity is the speed of the object moving through the fluid, drag coefficient is a dimensionless number that depends on the shape and roughness of the object, and reference area is the area that is normal to the direction of the fluid flow. To find the strength of the drag, you need to know these values and plug them into the equation.
Explanation:
Question 17 of 25
Newton's third law deals most closely with:
O A. inertia.
.
O B. mass.
O C. action and reaction forces.
O D. acceleration.
Answers
Answer:
I think it is C
Explanation:
states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.
A new kind of toy ball is advertised to "bounce perfectly elastically" off hard surfaces. A student suspects, however, that no collision can be perfectly elastic. The student hypothesizes that the collisions are very close to being perfectly elastic for low-speed collisions but that they deviate more and more from being perfectly elastic as the collision speed increases.(a) Design an experiment to test the student’s hypothesis about collisions of the ball with a hard surface. The student has equipment that would usually be found in a school physics laboratory.
Answers
The student can perform the following experiment: Measure the height of a table from the floor. Drop the ball from a known height and measure the height to which it bounces back. Repeat the process. Measure the speed of the ball just before it hits the surface. Plot the speed of the ball before and after. Compare the pre-collision and post-collision speeds of the ball.
What if the collisions are perfectly elastic?If the collisions are perfectly elastic, the pre-collision and post-collision speeds should be equal. However, if the hypothesis is correct, the deviation from being perfectly elastic should increase with collision speed.
What is elastic collision?An elastic collision is a type of collision in which the total energy of the two colliding objects remains constant.
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Why are horror movies so scary :(
Answers
Answer:
what movies do you watch?
Explanation:
Answer:
Because there scary
Explanation:
How is electric correct different from static electricity? Why is a fuse an important device in an electrical circuit?
Answers
Static electricity represents charges without movement, while electric current represents charges in motion (electric flow).
The fuse is a component of electrical installations that is interrupted or melts when the current is excessive. Fuses are composed of a sheet or filament made of an alloy or metal that is characterized by a low melting point. This element is located at a strategic point in the electrical installation so that it melts if the intensity of the current exceeds a certain value. Thus, the fuse interrupts the current and safeguards the integrity of the conductors, minimizing the risk of fire or breakdown.
What is the evidence that star formation began when the universe was only a few hundred million years old
Answers
Answer: Globular clusters with stars more than 13 billion years old contain heavy elements.
The speed of a car is decreased uniformly from 30. meters per second to 10. meters per second in 4.0 seconds.
Answers
Answer: The car slows down by 10 meters per second every second.
Explanation:
AnswerThe speed of a car is decreased uniformly from 30. meters per second to 10. meters per second in 4.0 seconds. What was the car's acceleration ?
We have the following data:
V (final velocity) = 10 m/s
Vo (initial velocity) = 30 m/s
ΔV (speed interval) = V - Vo → ΔV = 10 - 30 → ΔV = - 20 m/s
ΔT (time interval) = 4.0 seconds
a (average acceleration) = ? (in m/s²)
Explanation: