If a particle of mass m= 0.3 kg and q= 1.4 c was released from rest at point c what would be the particle's velocity when it reached point d? (answer should be in units m/s)

Depending on the asteroid's velocity, a launch speed greater than 6 m/s is necessary relative to you.

The needed launch speed is more than 6 m/s with respect to you. This is due to the fact that the rock will have a certain velocity relative to the asteroid if it is launched at a speed of 6 m/s relative to you. When the rock is very distant from the asteroid, this velocity, along with the asteroid's velocity, will cause it to have a velocity greater than 6 m/s.

We can use the relative velocity equation to determine the necessary launch speed:

Relative Velocity = Asteroid Velocity - Launch Velocity

Therefore, we can get the launch velocity by solving for the following equation: If we want the rock to have a relative velocity of 6 m/s when it is very distant from the asteroid:

Launch Velocity = Asteroid Velocity + Relative Velocity

= 6 m/s + Asteroid Velocity

Therefore, Based on the asteroid's velocity, the necessary launch speed (relative to you) is therefore larger than 6 m/s.

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Answer:

F = I L B     describes the perpendicular force on a wire of length L in a uniform field B

B = F / (I L) = 1.2 / (9 * 2.5) = .053 Tesla

Option C: 0.115 is the correct option.

The correct error between the thread plug gauge pitch diameter and the micrometer measurement is 0.115 mm.

Explanation:

In order to determine the correct error between the thread plug gauge pitch diameter and the micrometer measurement, we first need to calculate the difference between the two.

This will give us the error.

The formula we will use is:

Error = |Pitch Diameter - Micrometer Measurement|

Given that:

             Pitch Diameter = 22.35 mm

             Micrometer Measurement = 22.235 mm

Substituting the values, we get:

              Error = |22.35 - 22.235|

              Error = 0.115 mm

Therefore, the correct error is 0.115 mm.

Option C: 0.115 is the correct option. The correct error between the thread plug gauge pitch diameter and the micrometer measurement is 0.115 mm.

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If a sheet of aluminum foil is held in front of a radioactive source. Two types of radiation are detected on the other side. The alpha particle radiation will not be detected.

The ability of some unstable atoms to emit nuclear radiation spontaneously, typically in the form of alpha or beta particles frequently accompanied by gamma rays, is known as radioactivity.

As given in the problem statement, if a sheet of aluminum foil is held in front of a radioactive source. Two types of radiation are detected on the other side, then we have to find which type of radiation will not be detected on the other side.

When a radioactive source is in front of a sheet of aluminum foil. On the opposite side, radiation of two different sorts is seen. There won't be any indication of alpha particle radiation.

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The time needed to generate an energy of 456 J using a power of 76 W is 6.0 seconds.

Power is the quantity of energy transferred per unit time. It can be expressed as;

Power = energy / time

Given the data in the question;

To determine the required time, plug the given values into the formula above and solve for t.

Power = energy / time

Time = energy / power

Time = 456kgm²/s² / 76kgm²/s³

Time = 6.0s

Therefore, the required time is 6.0 seconds.

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The electric potential due to the charge at a distance r = 0.280 cm from the charge is V = 1.03 x 10^6 V.

The electric potential due to a charge at a distance r from the charge can be determined using the formula V = kq/r, where k is the Coulomb's constant, q is the charge, and r is the distance from the charge.

Given that the charge is q = 2e, where e is the charge on an electron, and the distance is r = 0.280 cm, we can plug these values into the formula to find the electric potential:

V = kq/r
V = (8.99 x 10^9 Nm^2/C^2)(2e)/(0.280 cm)

Since the charge on an electron is e = 1.6 x 10^-19 C, we can substitute this value into the formula:

V = (8.99 x 10^9 Nm^2/C^2)(2)(1.6 x 10^-19 C)/(0.280 cm)

Next, we need to convert the distance from cm to m, since the units in the formula are in meters:

V = (8.99 x 10^9 Nm^2/C^2)(2)(1.6 x 10^-19 C)/(0.280 x 10^-2 m)

Simplifying the equation gives:

V = (8.99 x 10^9 Nm^2/C^2)(2)(1.6 x 10^-19 C)/(2.8 x 10^-3 m)

V = 1.03 x 10^6 V

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The solution to the problems in correct significant figures are;

a. 10.8 g - 8.264 g = 2.536 g

b. 4.75 m - 0.4168 m = 4.3332 g

c. 139 cm x 2.3 cm = 319.7 cm²

d. 13.78 g/11.3 mL = 1.22 g/ml

e. 1.6 km + 1.62 m + 1200 cm =  1,613.62 m

Significant figures are used to establish the number which is presented in the form of digits.

a. 10.8 g - 8.264 g = 2.536 g

b. 4.75 m - 0.4168 m = 4.3332 g

c. 139 cm x 2.3 cm = 319.7 cm²

d. 13.78 g/11.3 mL = 1.22 g/ml

e. 1.6 km + 1.62 m + 1200 cm = 1,600 m + 1.62 m + 12 m = 1,613.62 m

Thus, the solution to the problems in correct significant figures are;

a. 10.8 g - 8.264 g = 2.536 g

b. 4.75 m - 0.4168 m = 4.3332 g

c. 139 cm x 2.3 cm = 319.7 cm²

d. 13.78 g/11.3 mL = 1.22 g/ml

e. 1.6 km + 1.62 m + 1200 cm =  1,613.62 m

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Answer:

-0.018 m/s

Explanation:

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Both masses start at rest, so u₁ = u₂ = 0 m/s.

0 = m₁v₁ + m₂v₂

0 = (20 kg) (0.060 m/s) + (65 kg) v₂

v₂ ≈ -0.018 m/s

The final velocity of the student can be determined using momentum conservation equation. The velocity after interaction will be 0.018 m/s.

Momentum of a body is the product of its velocity and mass. Momentum of a moving body conserved in collision. Hence, the sum of initial momentum of the two colliding bodies is equal to the sum of their final momentum.

Both the student and bag were at rest initially and the initial momentum is zero.

The mass of the student = 20 kg

mass of bag + chair = 65 kg

velocity = 0.06 m/s

then, m1v1 + m2v2  = 0

(65 kg) v1 + (0.06 m/s  × 20 kg ) = 0

v1 = 0.018 m/s

The momentum exerted on the bag is returned to the student with an equal and opposite magnitude. The velocity of the girl after interaction will be 0.018 m/s.

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Answer:

Anything that isn't in the sky like a book or a chicken

Explanation:

The group that will make the car travel closest to 5 m/s when it is at the bottom of the first will is of:

Group C.

The velocity that each car will assume at the bottom of the hill is given by the equation presented as follows:

v = square root (2gh + kx²/m).

The parameters are given as follows:

The parameters are given by the table in this problem, hence the velocities of each car are given as follows:

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Answer: group C

Explanation:

(a)The critical value for a 95% confidence level is approximately 1.96. (b) A higher confidence level requires a wider interval to capture the true population mean with greater certainty.

(a) To construct a 95% two-sided confidence interval on the mean life of the light bulbs, we can use the formula:

CI = X ± z × (σ ÷√n)

where X is the sample mean, σ is the population standard deviation, n is the sample size, and z is the critical value corresponding to the desired confidence level.

In this case, X= 1014 hours, σ = 25 hours, and n = 20. The critical value for a 95% confidence level can be found using a standard normal distribution table or a calculator. For a two-sided confidence interval, we divide the desired confidence level by 2 and find the corresponding z-value.

The critical value for a 95% confidence level is approximately 1.96. Substituting the values into the formula, we have:

CI = 1014 ± 1.96 × (25 ÷ √20)

the confidence interval on the mean life.

(b) To construct a 95% lower-confidence bound on the mean life, we can use the formula:

Lower bound = X - z × (σ ÷ √n)

Using the same values as in part (a), the lower bound can be calculated.

The lower bound from part (a) is the lower confidence bound for the mean life.

For the second part of the question, we have two confidence intervals: (38.02, 61.98) and (39.95, 60.05).

(a) To find the value of the sample mean, we take the average of the lower and upper bounds of each confidence interval. The sample mean is the midpoint of the confidence interval.

Sample mean = (38.02 + 61.98) ÷ 2 = 50

(b) One of the intervals is a 95% confidence interval, and the other is a 90% confidence interval. The interval (38.02, 61.98) is the 95% confidence interval because it is wider. A higher confidence level requires a wider interval to capture the true population mean with greater certainty.

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A subpanel in an older house that is wired with non-metallic sheathed cable (nm) has one circuit with a grounding wire. the grounding wire should be connected to a separate grounded buss bar.

Brass, Aluminum or Copper Bus bars are metal strips or rods. They come in a variety of shapes and sizes that determine the maximum current (ampacity) they can carry safely and reliably. This also means that it is important to install the best one for a particular application.

Its job is to receive power from the delivery point and distribute it to the output circuits. However, unlike cables, no insulation is usually required. Busbars are often arranged in separate housings. Bus bars are used as nodes or nodes in power distribution applications and can be housed in switchgear or control cabinets and bus bar enclosures.

The grounding bar is used in environments where a common grounding point or grounding point is required or required in the distribution network. One of the main advantages of brass, aluminum, or copper grounding bars is that they can be placed anywhere on the chassis or rack.

This makes installation faster and more efficient than cables. A grounded (or neutral) bus reduces the need for regular maintenance and reduces the risk of downtime. This is very important in industries where uninterrupted power distribution is essential. Telecom and power supplies are two prominent examples.

However, it is not uncommon for some neutral bus bars to have insulation.

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Answer:

The direction of motion of the ball is approximately 68.199º below the +x semiaxis.

Explanation:

The ball has a two-dimension motion, to be exact, a parabolical motion, that is, a motion at constant velocity in the x-direction and free fall motion in the y-motion. Hence, the horizontal velocity of the basketball is 12 meters per second and its direction (\(\theta\)), in sexagesimal degrees, is calculated by this trigonometrical expression:

\(\theta = \tan^{-1} \frac{v_{y}}{v_{x}}\) (1)

Where:

\(v_{x}\) - Horizontal velocity, in meters per second.

\(v_{y}\) - Vertical velocity, in meters per second.

If we know that \(v_{x} = 12\,\frac{m}{s}\) and \(v_{y} = -30\,\frac{m}{s}\), then the direction of motion of the ball is:

\(\theta \approx 68.199^{\circ}\) (below the +x semiaxis)

The direction of motion of the ball is approximately 68.199º below the +x semiaxis.

-- burn it   (it combines with Oxygen and makes new substances)

-- chew it   (it combines with your saliva and makes new substances)

-- swallow it   (your stomach juices dissolve it and make new substances)

I think that's as far as I should go with it.

Answer:

his feet feel warmer because of friction. when friction takes place then an object will warm up because friction is a universal law that always takes place. if you rub your hands together, you also experience the heat of frictional I hope that helped.

Answer:

84% efficiency

Explanation:

21000/25000*100

The distance to the bending mark when fabricating a 90°-bend is equal to the stub-up minus the take-up. Therefore, the correct answer is option b.

When bending a conduit or pipe to create a 90° angle, the bending mark represents the point at which the bend starts. The stub-up is the length of the conduit that extends vertically from the bottom of the bend to the end of the conduit. The take-up is a measurement that accounts for the additional length of the conduit that is consumed during the bending process.

To find the distance to the bending mark, you need to subtract the take-up from the desired stub-up length. This will give you the correct position to mark on the conduit before starting the bending process. Following this guideline will help ensure that your 90°-bend will be accurate and meet the required specifications.

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Answer:

explain this

Explanation:

The speed of the missile, relative to ship B, can be determined using the concept of relative velocity. To solve this problem, we need to consider the lengths of the missiles and their relative velocities.

The length of the first missile is given as 0.872 m, while the length of the missiles used by ship A is 2 m. This means that the missile has contracted in length due to its high speed.

To find the speed of the missile, we can use the formula for length contraction, which is given by:

L = L0 * sqrt(1 - (v^2 / c^2))

Where:
L0 = Length of the object at rest
L = Length of the object in motion
v = Velocity of the object
c = Speed of light

We know that L0 (length of the missile at rest) is 2 m and L (length of the missile in motion) is 0.872 m. We need to solve for v (velocity of the missile).

Rearranging the formula, we get:

(v^2 / c^2) = 1 - (L^2 / L0^2)

Substituting the known values, we have:

(v^2 / c^2) = 1 - (0.872^2 / 2^2)

Simplifying, we find:

(v^2 / c^2) = 1 - (0.760384 / 4)

(v^2 / c^2) = 1 - 0.190096

(v^2 / c^2) = 0.809904

Taking the square root of both sides, we have:

v / c = sqrt(0.809904)

v / c = 0.89999

Multiplying both sides by c, we get:

v = 0.89999 * c

Now, to find the speed u of the missile relative to ship B, we need to subtract the velocity of ship B from the velocity of the missile.

So, the speed u of the missile, relative to ship B, is given by:

u = v - uB

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The speed u of the missile, relative to ship B, is approximately 2.702 × 10^8 m/s.

Explanation :

The length of the missile measured by the captain of ship B, which is 0.872 m, is shorter than the 2-m-long missiles used by ship A. This indicates that the missile has experienced length contraction due to its high speed relative to ship B.

To find the speed u of the missile relative to ship B, we can use the concept of length contraction. The formula for length contraction is given by L' = L / γ, where L' is the contracted length, L is the rest length, and γ is the Lorentz factor.

In this case, the contracted length L' is 0.872 m and the rest length L is 2 m. We can rearrange the formula to solve for γ: γ = L / L'.

Substituting the given values, we have γ = 2 m / 0.872 m = 2.29.

The Lorentz factor is related to the velocity v of the missile relative to ship B by the equation γ = 1 / √(1 - (v/c)^2), where c is the speed of light.

We can rearrange this equation to solve for v: v = c * √(1 - 1/γ^2).

Substituting the Lorentz factor γ = 2.29 and the speed of light c = 3 × 10^8 m/s, we can calculate the speed v:

v = (3 × 10^8 m/s) * √(1 - 1/2.29^2)
v = (3 × 10^8 m/s) * √(1 - 1/5.2441)
v ≈ (3 × 10^8 m/s) * √(1 - 0.1907)
v ≈ (3 × 10^8 m/s) * √(0.8093)
v ≈ (3 × 10^8 m/s) * 0.9006
v ≈ 2.702 × 10^8 m/s

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Answer:

6.58×10⁻¹⁸ J

Explanation:

Applying

E = kq²/r.................. Equation 1

Where E = potential energy, q = charge on each electron, r = distance between the electron, k = coulomb's constant.

From the question,

Given: r = 3.5×10⁻¹¹ m,

Constant: q = 1.6×10⁻¹⁹ C, k = 8.99×10⁹ Nm²/C²

Substitute these values into equation 1

E = (1.6×10⁻¹⁹)²(8.99×10⁹)/(3.5×10⁻¹¹)

E = 6.58×10⁻¹⁸ J

Answer:

law of conservation of mass

Explanation:

hope that helped :)

The correct answer is B. 2 statement is correct,  Lowering the power consumption helps reducing the heat generation.

Statement (2) is correct: Lowering the power consumption helps reduce heat generation. When a device or system consumes less power, it generates less heat as a byproduct. This is beneficial for thermal management, as excessive heat generation can lead to performance issues, reduced efficiency, and potential damage to components.

Statements (1) and (3) are incorrect:

- Lowering the power consumption does not directly extend battery life.

- Lowering the energy consumption does not directly reduce the electricity bill. However, lowering energy consumption can indirectly contribute to reducing the electricity bill by reducing the total energy usage.

Statement (4) is incorrect:

- A CPU with 10% utilization does not necessarily consume 33% of the peak power. Power consumption is not directly proportional to CPU utilization. In summary, only statement (2) is correct, so the answer is B.

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The force corresponds to the question mark in the given figure is known as Gravity. Hence, option (C) is correct.

The given problem is based on the concept of equilibrium of forces. The forces that causes the net motion of an object to be zero, is known as equilibrium of force.

Thus, we can conclude that the force corresponds to the question mark in the given figure is known as Gravity. Hence, option (C) is correct.

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The net force is (40 Newtons) (down the road).

But 40 Newtons is not going to move a piano very enthusiastically.

Horizontal component = 75 · cosine(65°)  =  31.7 N  

Vertical component = 75 · sine(65°)  =  68.0 N

From the that astronomers categorize galaxies into a handful of basic shapes, it can be concluded that the all galaxies are made from the same forces.

Astronomers have categorized galaxies into three main categories,

Elliptical Galaxies:

These galaxies have smooth ellipsoidal shape. They are most abundant type. For example- Messier 49

Spiral galaxies:

These galaxies have a spiral shapes with many hand like structures. For example- Milky way.

Irregular Galaxies:

They do not have any specific shape.

Therefore, from the that astronomers categorize galaxies into a handful of basic shapes, it can be concluded that the all galaxies are made from the same forces.

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Newton's third law states that any action will have a(n) equal and opposite reaction.

The distance travelled by the car after the first four hours of the trip is 370 km and the average speed for the first four hours of the trip is 92.5 kmph

v ( t ) = d ( t ) / t

v ( t ) = Velocity with respect to time

d ( t ) = Distance with respect to time

t = Time

For the first four hours, the following details are taken from the graph shown.

d ( 4 ) = 370 km

t = 4 hr

v ( 4 ) = 370 / 4

v ( 4 ) = 92.5 kmph

Average velocity can also be calculated using the formula V = ( u + v ) / 2 if the initial and final velocities are given. u represents initial velocity and v represents the final velocity.

Therefore,

Distance travelled in first 4 hours = 370 km

Average speed in first four hours = 92.5 kmph

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Answer:

A

Explanation:

You did not list the options. However, knowing the possible options from having seen the material myself - I can infer that the answer option is A. I apologize sincerely if this is wrong.

Answer:

the first one is c and the second is b