If a horse travels 20 meters in 5 seconds what is the horses speed

HAZWOPER training and certification recognize:

The correct option is both A and C

HAZWOPER (Hazardous Waste Operations and Emergency Response) training and certification recognize that a large number of victims (as much as 80%) in hazardous waste incidents or emergencies will self-present or be self-referred for medical treatment.

Additionally, HAZWOPER training acknowledges that victims may use any entrance they can access at a hospital, not just the emergency department entrance.

This is because individuals affected by hazardous materials may arrive at different areas of the hospital seeking medical assistance.

Therefore, option d. Both A and C are correct statements regarding the recognition of HAZWOPER training and certification.

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Hydrated ionic compounds have water molecules incorporated into their structure. Heating removed the volatile component, water, from the Epsom salt sample, which is magnesium sulfate.

Hydrated ionic compounds have water molecules incorporated into their structure. In the case of Epsom salt, it is magnesium sulfate heptahydrate which means there are seven water molecules incorporated in it. On heating the Epsom salt sample, the volatile component that is removed from it is water.

An example of a hydrated ionic compound is magnesium sulfate heptahydrate (\(MgSO_{4} 7H_{2} O\)). Heating the Epsom salt sample will remove the water molecules from the hydrated compound, resulting in the formation of an anhydrous ionic compound, \(MgSO_{4}\).

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Answer:

H₂O

Explanation:

Chemical equation:

C₅H₁₂ + O₂      →     CO₂ + H₂O

Balanced chemical equation:

C₅H₁₂ + 8O₂      →     5CO₂ + 6H₂O

The given reaction is combustion reaction. The balance equation shows  that there are equal number of moles of carbon, hydrogen and oxygen on both side of equation thus it follows the law of conservation of mass.

Combustion reaction:

The reaction in which substance react with oxygen and produced carbon dioxide and water.

Mostly hydrocarbons burns in the presence of oxygen and form carbon dioxide and water.

Answer:

8.0 × 10⁴ J

Explanation:

Step 1: Given data

Step 2: Calculate the change in the temperature

ΔT = 39 °C - 23 °C = 16 °C

Step 3: Calculate the heat required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 4,186 J/kg.°C × 1.2 kg × 16 °C

Q = 8.0 × 10⁴ J

Answer:

b. 0.47 moles Ca.

Explanation:

Hello there!

In this case, since 1 mole of any element contains 6.022x10²³ atoms of the same, it is possible for us to compute the moles in 2.8x10²³ atoms of calcium via the Avogadro's number:

\(2.8x10^{23}atomsCa*\frac{1molCa}{6.022x10^{23}atomsCa}\\\\=0.47molCa\)

Therefore, the answer would be b. 0.47 moles Ca.

Best regards!

Answer:

Primary alcohols can be oxidized to form aldehydes and carboxylic acids; secondary alcohols can be oxidized to give ketones. Tertiary alcohols, in contrast, cannot be oxidized without breaking the molecule's C–C bonds.

How does the type of paper of a paper airplane affect the distance it travels?

The experiment was performed with different types of paper, all paper have different quality, chemical composition,density & all this properties of paper will affect the distance travelled by the paper airplane. hence the motive of experiment was to check how different paper affect the distance travelled by the paper airplane.

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Answer:

0.75 liters

Explanation:

Answer:

C. precipitate formation.

Explanation:

options C is correct answer.

Answer:

C. precipitate formation.

Explanation:

Answer:

The answer is:

\(speed(\frac{m}{s}) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (number)\\\\ 100 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 23 \\\\ 200 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 42 \\\\ 300 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 26 \\\\ 400 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 8 \\\\ 500 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1 \\\\\)

Explanation:

Its total kinetic energy of a gas colloquial atom colloction is equal to absolute temperature alone, according to the programs that directly gas Theory.

Average speed for 1st option:

\(= \frac{(200 \times 23)+(400 \times 42)+(600 \times 26)+(800 \times 8) +1000}{100} \\\\= 444\ \frac{m}{s} \ \ \ \ \ \ \ \ \ \text{average speed of gas}\)

 Average speed for 2nd option:

 \(= \frac{(200 \times 11) +(400 \times 21)+ (600 \times 13)+ (800 \times 4)}{11+21+13+4} \\\\= 440 \ \frac{m}{s}\)

 Average speed for 3rd option:

\(= \frac{(200 \times 43) +(400 \times 50)+ (600 \times 7)}{100} \\\\ =328 \ \frac{m}{s}\)

 Average speed for 4th option:

 \(= \frac{(200 \times 50) +(400 \times 25)+ (600 \times 13)+(800\times 8)+(1000 \times 4)}{100}\\\\ =382\ \frac{m}{s}\)

  Average speed for 5th option:

\(= \frac{(100 \times 23) +(200 \times 42)+ (300 \times 26)+(400\times 8)+500}{100}\\\\ =222 \ \frac{m}{s}\)

The average speed also increased by half because the temperatures had kinetic energy.\(\to 444 \ \frac{m}{s}\ to \ 222 \ \frac{m}{s}\)

31.7 g of water formation in the given reaction releases 783.02 kJ of heat energy.

The change in heat in the given equation is -890.8 kJ/mol. This means that when one mole of CH4 reacts with 2 moles of O2, it produces one mole of CO2 and 2 moles of H2O while releasing 890.8 kJ of heat energy.Now, we have to find out how much heat energy will be released when 31.7 g of water is formed. To do this, we need to first calculate the number of moles of water formed from 31.7 g of H2O.Molar mass of H2O = 2 × 1.008 + 15.999 = 18.015 g/molNumber of moles of H2O = 31.7 g / 18.015 g/mol = 1.759 molNow we know that 2 moles of H2O are formed when 1 mole of CH4 reacts. Therefore, the number of moles of CH4 required to produce 1.759 mol of H2O will be:1 mole of CH4 : 2 moles of H2Ox moles of CH4 : 1.759 moles of H2Ox = 1.759/2 = 0.8795 molSo, 0.8795 moles of CH4 are required to produce 1.759 moles of H2O. And the heat released during the reaction of 0.8795 mol CH4 can be calculated using the given change in heat.ΔH = -890.8 kJ/molHeat released during the reaction of 0.8795 mol CH4= ΔH × number of moles= -890.8 kJ/mol × 0.8795 mol= -783.02 kJ.

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Answer:

MARK AS BRAINLIEST

Explanation:

Boron trifluoride only has six valence electrons and is one of the relatively rare second period covalent molecules that disobeys the octet rule. There are three bonded groups and so no lone pairs. Six electrons implies three electron pairs and therefore a trigonal geometry.

3 bonding and 0 non-bonding electron pairs are found in the BF3 molecule.

Chemical Bonding refers to the formation of a chemical bond between two or more atoms, molecules, or ions to give rise to a chemical compound.

Boron trifluoride only has six valence electrons and is one of the relatively rare second-period covalent molecules that disobeys the octet rule.

There are three bonded groups and so no lone pairs. Six electrons imply three electron pairs and therefore a trigonal geometry.

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This problem is providing us with the rate law for the reaction between nitrogen dioxide and carbon monoxide to produce nitrogen monoxide and carbon dioxide. Thus, the required rate constant turns out to be C: 2.08 × 10-4 M-1 s-1 as show below:

In chemistry, chemical kinetics is used to study the changes in the amount of a substance that undergoes consumption or production in a chemical reaction with respect to the time.

In this case, considering the attached picture wherein the data is presented, one can write the following version of the rate law:

\(\frac{d[NO_2]}{dt}=-k[NO_2]^2\)

Which can be integrated by parts:

\(\int{\frac{1}{[NO_2]^2 } } \, d[NO_2]=-k\int{}\, dt\\\\\frac{1}{[NO_2]}=kt\)

Which resembles y=mx+b; this means we need to prepare a 1/[NO₂] vs t graph with a trendline, task that can be done on Excel as shown on the second attached file.

Hence, we see the trendline as y = 0.000208x + 1.977, where the slope, 0.000208, is equal to k (rate constant) and with the appropriate units, it will be:

C: 2.08 × 10-4 M-1 s-1

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Answer: okay, girl I got you . Chemical.

Nuclear.

Thermal.

Electromagnetic. The Electromagnetic Spectrum. The electromagnetic (EM) spectrum is the range of all types of EM radiation. Radiation is energy that travels and spreads out as it goes – the visible light that comes from a lamp in your house and the radio waves that come from a radio station are two types of electromagnetic radiation. This lesson will introduce electricity as the flow of electrons. In some cases, electricity can be the flow of positive charges or both positive and negative charges. This lesson will focus on the more typically defined flow of electrical current as that of electrons. Students should have some basic knowledge of atoms and their structure. However, as part of their online readings, students will investigate the basics of atomic structure (nucleus, protons, neutrons, electrons). Thus, this lesson provides a good opportunity to clarify misconceptions about atoms and to ensure that all students understand basic atomic structure. According to the Benchmarks for Science Literacy, students of all ages show a wide range of beliefs about the nature and behavior of particles. They lack an appreciation of the very small size of particles; attribute macroscopic properties to particles; believe there must be something in the space between particles; have difficulty in appreciating the intrinsic motion of particles in solids, liquids, and gases; and have problems in conceptualizing forces between particles. This misconception is important to keep in mind when talking about electricity as the flow of electrons. Students may think that the electrons are in the copper wire and not the copper atoms that make up the wire. It is important to stress this point with students so that they develop an understanding that substances are composed of atoms, rather than atoms residing as a separate entity within substances.

Explanation: hope this helped and please mark me brainiest.

The other compound that makes up most of the other gases in the table is water vapor.

Water vapor is not listed in the table because it is not a pollutant. However, it is a significant component of exhaust gas, and it can contribute to smog formation. Water vapor is formed when the fuel in a petrol engine is burned. The combustion process produces water as a byproduct.

The amount of water vapor in the exhaust gas depends on the temperature of the combustion process. At higher temperatures, more water vapor is produced. Water vapor is not a pollutant in itself, but it can contribute to smog formation.

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Complete question:

this table shows the percentages of some gases in the exhaust from a petrol engine

nitrogen 68

carbon dioxide 15

carbon monoxide 1

oxygen 0.75

nitrogen oxides 0.24

hydrocarbons 0.005

sulphur dioxide 0.005

other gases

what is the name of the other compound that makes up most of the other gases in the table?

The compound that is formed by the combination of the boron and oxygen is boron oxide.

The term periodic table has to do with the arrangement of the elements in such a way that they can be easily studied. We know that the compound boron oxide.

The boron atom is a member of group three while oxygen is a member of group six. We know that the compound is ionic thus the boron ion would combine with the oxygen ion in order to form the boron oxide. the boron is positive and oxygen is negative.

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Answer:

because theres a force called gravity

Explanation:

Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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Answer:

The concentration increases because the solution becomes more pure because the solvent leaves the solution.

Explanation:

With the aid of a reagent that precipitates one or more ions while leaving others in solution, ions in an aqueous solution can be separated using the selective precipitation technique.

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Answer:

1.52 g of NaCl

Explanation:

We'll begin by calculating the number of mole of chlorine gas (Cl₂) that occupied 0.3 L at STP. This can be obtained as follow:

Recall: 1 mole of any gas occupy 22.4 L at STP.

1 mole of Cl₂ occupy 22.4 L at STP.

Therefore, Xmol of Cl₂ will occupy 0.3 L at STP i.e

Xmol of Cl₂ = 0.3 / 22.4

Xmol of Cl₂ = 0.013 mole

Thus, 0.013 mole of Cl₂ occupied 0.3 L at STP.

Next, we shall determine the number of mole of NaCl produced from the reaction.

Cl₂ + 2Na —> 2NaCl

From the balanced equation above,

1 mole of Cl₂ reacted to produce 2 moles of NaCl.

Therefore, 0.013 mole of Cl₂ will react to produce = 0.013 × 2 = 0.026 mole of NaCl.

Thus, 0.026 mole of NaCl is produced.

Finally, we shall determine the mass of the NaCl. This can be obtained as follow:

Mole of NaCl = 0.026 mol

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =?

Mole = mass /Molar mass

0.026 = mass of NaCl / 58.5

Cross multiply

Mass of NaCl = 0.026 × 58.5

Mass of NaCl = 1.52 g

Therefore, 1.52 g of NaCl were produced from the reaction

Answer:

25°C + 273.15 = 298.15K , so D.) is the Answer

Explanation:

Answer:

i want to help but  i   d   k. the answer :( sorry i couldnt help

Explanation:

Answer:

Example 1

palladium(II) nitrate,

Example 2

Metal catalysts such as Fe, Ni, Mo, and Co are routinely used in the manufacture of CNMs.

Explanation

The three metals used in catalytic converters — rhodium, platinum and palladium — are part of a category known as platinum group metals, or PGMs, which are known for their catalytic properties.

Answer: :)

The temperature of a gas is directly proportional to the average kinetic energy of the particles of the gas. But the total kinetic energy of the molecules of a gas is a measure of the internal energy or thermal energy of the gas.

Explanation:

30.9 grams of dichloromethane (CH2Cl2) will be formed upon the complete reaction of 30.9 grams of carbon tetrachloride with excess methane.

The balanced equation for the reaction is: CH4(g) + CCl4(g) -> CH2Cl2(g) + HCl(g). To determine the amount of dichloromethane (CH2Cl2) that will be formed upon the complete reaction of 30.9 grams of carbon tetrachloride with excess methane, we can use the concept of stoichiometry. Stoichiometry is the branch of chemistry that deals with the quantitative aspects of chemical reactions, including the mass relationships between reactants and products.From the balanced equation, we can see that the reaction has a 1:1 ratio between the carbon tetrachloride and the dichloromethane. Therefore, if we know the amount of one substance, we can calculate the amount of the other substance by using the stoichiometric ratio. 30.9 grams of CCl4 will react with an excess of methane to form 30.9 grams of CH2Cl2. So the answer is 30.9 grams of dichloromethane (CH2Cl2) will be formed upon the complete reaction of 30.9 grams of carbon tetrachloride with excess methane.

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The complete question is :

according to the following reaction, how many grams of dichloromethane () will be formed upon the complete reaction of 30.9 grams of carbon tetrachloride with excess methane ()?methane (CH4)(g) + carbon tetrachloride(g)  dichloromethane (CH2Cl2)(g)

In order to find the percent yield of a reaction, we need to use the following formula:

%yield = (actual yield/theoretical yield)*100

The actual yield is 7.59 grams

The theoretical yield is the mass you found on letter C, 8.0 grams

Now we can use the formula:

%yield = (7.59/8)100

%yield = 0.9487 * 100

The percent yield will be 94.87 %

Answer:

1.80 g (grams) of glucose.

Explanation:

First, we dissolve 20.0 g of glucose in a volume of water of 100 mL (0.1 L), so let's calculate the concentration of glucose in g/L, like this:

Now, we take 45 mL (0.045 L) of this solution that contains a concentration of glucose of 200 g/L to create a new solution with 0.500 L.

From this new solution, we have to find the mass of glucose if we took 100 mL (0.1 L) of this solution, so we have to use the following equation:

Where C is concentration, V is volume, and subindex 1 and 2 indicate the initial solution, which in this case, is C1 = 200 g/L, V1 = 0.045 L, and the final solution with unknown concentration (C2) and a volume of V2 = 0.500 L.

Let's solve for C2 and replace the given data to obtain the new concentration (final concentration) of the new solution of 0.500 L, like this:

The final concentration of glucose in 0.500 L would be 18.0 g/L.

The next and final step is to calculate the total mass using the volume that we took from the 0.500 L solution, which is 100.0 mL (0.1 L). To do this, we have to do a dimensional analysis to obtain the answer in units of grams, so the calculation will look like this:

The answer would be that we have 1.80 g (grams) of glucose in 100 mL from the 0.500 L solution.

Answer:

NaBr

Explanation:

Bromine's symbol is Br, not B, for B is for Boron

Answer:

Chemical Energy is stored in food molecules

Answer:

chemical energy

Explanation:

because none of the other make sense