If 5 moles of nitrogen are used how many moles NH3(g) are produced

Answer:

The following data were obtained from the question:

Specific heat capacity (C) = 0.386 J/gºC

Mass (m) = 156 g

Initial temperature (T1) = 96.0ºC

Final temperature (T2) = 28.0ºC

Change in temperature (ΔT) = T1 – T2 = 96 – 28 = 68°C

Heat (Q) =..?

The heat released can be obtained as follow:

Q = m * c * ΔT

= 156 g * 0.386 J/g °C * 68.0 °C

≈ Q = m * c * ΔT

= 156 g * 0.386 J/g °C * 68.0 °C

≈ 3977.568 J

Therefore, the heat released is 3977.568 J

Explanation:

Answer:

\(The \: metric \: system \: uses \: one \: unit \: for \: each \: \\ category \: of \: measurement. \)

Answer:

i don’t understand what you are saying?

Explanation:

Answer:

The TV signal.

Explanation: Hope this is right! :)

I uploaded the answer to a file hosting. Here's link:

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Answer:

B.

near the equator

Explanation:

Tropical rainforests are found in Central and South America, western and central Africa, western India, Southeast Asia, the island of New Guinea, and Australia. Sunlight strikes the tropics almost straight on, producing intense solar energy that keeps temperatures high, between 21° and 30°C (70° and 85°F). Tropical rainforests are found closer to the equator where it is warm. Temperate rainforests are found near the cooler coastal areas further north or south of the equator. The tropical rainforest is a hot, moist biome where it rains all year long.

Explanation:

The periodic table brings order to information about the chemical elements. It helps chemists to understand why elements react as they do. Elements in the same group have similar chemical properties. This is because they have the same number of outer electrons and the same valency

Binding pocket consists of aspartic acid and two glycine and serine. Binding pocket is relatively small: chymotrypsin.
Binding pocket contains two glycine residues so that only small aromatic amino acids can be accommodated: chymotrypsin.

Binding pocket is relatively large: elastase.
Binding pocket contains an aspartic acid residue: elastase.
Binding pocket can positively enter the pocket: trypsin.
The classification of the statements for the binding pockets of chymotrypsin, trypsin, and elastase:
Chymotrypsin:
1. Binding pocket contains threonine, valine, and a serine residue.
2. Binding pocket is relatively large so that aromatic amino acids can be accommodated.
Trypsin:
1. Binding pocket contains two glycine residues and a serine.
2. Binding pocket is positively charged due to the negatively charged aspartic acid residue, allowing positively charged amino acids to enter the pocket.
Elastase:
1. Binding pocket contains an aspartic acid and two glycine residues.
2. Binding pocket is relatively small so that only small amino acids can be accommodated.

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Yes, the molecule formaldehyde (CH₂O) is polar. In order to determine the polarity of a molecule, we look at the electronegativity difference between the atoms involved. In the case of formaldehyde, there is a significant difference in electronegativity between carbon (C) and oxygen (O) atoms.

Oxygen is more electronegative than carbon, which means it attracts the shared electrons more strongly. As a result, the oxygen atom in formaldehyde gains a partial negative charge (δ-) while the carbon atom gains a partial positive charge (δ+). Additionally, the geometry of formaldehyde, which has a bent structure, also contributes to its polarity. The presence of a polar bond and the asymmetric distribution of charge in the molecule make formaldehyde polar overall. This polarity has implications for its chemical properties and reactivity.

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the freezing point of the solution is 4.85 C and the molar mass of sucrose is 191.7 g/mol, can be calculated using the equation: ΔT = iK_f, where ΔT is the change in freezing point, i is the van’t Hoff factor, and K_f is the freezing point depression constant.

The van’t Hoff factor for the solution is 2, since methyl salicylate is a nonelectrolyte. Thus, ΔT = 2(5.10 C/m)(20.0 g/800 g) = 0.650 C. Thus, the freezing point of the solution is 5.50 - 0.650 = 4.85 C.

The molar mass of sucrose can be calculated using the equation: pi = MRT, where pi is the osmotic pressure, M is the molar concentration of the solution, R is the gas constant, and T is the temperature.

The molar concentration of the solution is 0.822 g/300 mL = 0.00274 mol/L. Thus, MRT = 149 mm Hg, so the molar mass of sucrose is (149 mm Hg)(0.08206 L. atm/K. mol)/(0.00274 mol/L)(298 K) = 191.7 g/mol. Thus, the molar mass of sucrose is 191.7 g/mol.

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The half-life of the radioactive sample is T₁/₂ = (t / 7.22) s where t is the time taken for the number of atoms to reduce from N₀ to 0.5 N₀.

Given that the number of atoms present in a radioactive sample is 1.40 x 10¹⁵ atoms and it has an activity of 5.90 x 10¹¹ Bq.

To determine the half-life (in s) of a radioactive sample, we can use the formula:

N = N₀ / 2^(t/T₁/₂)

Where, N₀ is the initial number of atoms,N is the final number of atoms,t is the time elapsed,T₁/₂ is the half-life time

In this case, as we want to find T₁/₂, we can manipulate the formula and write:T₁/₂ = t / log₂(N₀ / N)

We know that T₁/₂ is the time required for half of the radioactive atoms to decay.

Hence, we can say that when N = 0.5 N₀, then t = T₁/₂

Substituting the given values,N₀ = 1.40 x 10¹⁵ atoms

N = 0.5 N₀ = 0.5 x 1.40 x 10¹⁵ atoms = 7.00 x 10¹⁴ atoms

And, t = T₁/₂

Hence,T₁/₂ = t / log₂(N₀ / N)= T₁/₂ = t / log₂(1.40 x 10¹⁵ / 7.00 x 10¹⁴)= T₁/₂ = t / log₂(150)= T₁/₂ = t / 7.22

Therefore, the half-life of the radioactive sample is T₁/₂ = (t / 7.22) s where t is the time taken for the number of atoms to reduce from N₀ to 0.5 N₀.

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The mass of Tin in alloy = 50 g

Given

10% tin, 16% antimony, and 74% lead.

mass of alloy = 500 g

Required

grams of tin

Solution

The mass percent of each component of the mixture shows the mass ratio of each component

%tin in alloy = 10%, so mass of tin :

\($10 \% \times 500 \mathrm{~g}=50 \mathrm{~g}$\)

The mass percent indicates the proportion of each element in a chemical composition. The amount of grams necessary to form a solution or the molar mass of the elements in the compound in grams/mole are needed to calculate the mass percent.

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When the products of the dissolution reaction are allowed to diffuse away from the mineral surface, both Le Châtelier's Principle and Fick's Law suggest that the mineral will dissolve more rapidly.

When a mineral dissolves, it undergoes a dissolution reaction that can be represented by the equation:

Mineral (solid) → Ions (in solution)

According to Le Châtelier's Principle, the equilibrium of a reaction is influenced by changes in concentration, temperature, and pressure. In the case of mineral dissolution, the concentration of dissolved ions affects the equilibrium. By removing the products of the dissolution reaction from the mineral surface through diffusion, the concentration of the ions in the immediate vicinity of the mineral decreases, shifting the equilibrium towards further dissolution. This promotes a faster dissolution rate.

Fick's Law describes the diffusion of species in a solution, stating that the rate of diffusion is proportional to the concentration gradient. When the products of the dissolution reaction diffuse away from the mineral surface, the concentration gradient between the mineral and the surrounding solution increases, facilitating faster diffusion of the dissolved ions away from the mineral. This leads to a more rapid dissolution process.

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Answer:

Electrons are the smallest of the particles that make up an atom, and they carry a negative charge. The number of protons and electrons is equal in a neutral atom. The hydrogen atom, for example, has just one electron and one proton. The uranium atom, on the other hand, has 92 protons, and therefore, 92 electrons.

Answer:

Hello! Your answer is : Double replacement

The chemical formula of 4- ethyl is C19H40.   This  patch is composed of an ethyl group( C2H5) attached to the fourth carbon  snippet( counting from one end) of a direct carbon chain.

It also has a propyl group( C3H7) attached to the fifth carbon  snippet of the same chain. The chain itself has 12 carbon  tittles and three methyl groups(- CH3) attached to the 3rd, 4th, and 7th carbon  tittles. thus, the complete name of the  emulsion is 4- ethyl, where" dodecane" refers to the 12- carbon chain.

This  patch belongs to the class of alkanes, which are hydrocarbons that only contain single bonds between carbon  tittles. The presence of the ethyl and propyl groups creates branching in the carbon chain, which can affect its physical and chemical  parcels compared to a direct alkane with the same number of carbon  tittles. The three methyl groups contribute to the  patch's overall shape and may also affect its reactivity.

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The question in english language is as follows:

What is the formula of 4-ethyl-5-propyl-3,4,7-trimethyldecane?

Radiocarbon dating, also known as carbon-14 dating, is a method used to determine the age of organic materials. It is based on the radioactive decay of the isotope carbon-14 (14C).

Living organisms constantly absorb carbon, including a small amount of carbon-14, from the atmosphere. When an organism dies, it no longer takes in carbon-14, and the existing carbon-14 begins to decay at a known rate. By measuring the ratio of carbon-14 to stable carbon isotopes (carbon-12 and carbon-13) in a sample, scientists can estimate the time that has elapsed since the organism's death. Radiocarbon dating is effective for dating materials up to about 50,000 years old.

Therefore, both radiocarbon dating and radiopotassium dating rely on the principles of radioactive decay. The decay rates of the isotopes used in these methods are well-established and constant, allowing for accurate age determinations.

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You create a graph that shows temperature as a function of time, with the temperature expressed in degrees Celsius and the time expressed in minutes.

Because the temperature difference between the substance and its surroundings reduces as it cools, the lines are curved. As a result, the pace of cooling is slowed down since less heat is being transmitted out of the substance. For the majority of pure substances, phase transitions take place at particular temperatures.

In a graph, the available heating curves appear as curved lines. The heating supply is indicated on the vertical axis, and the outside temperature is marked on the horizontal axis.

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The percent yield of H₂O, if 87.0 g of H₂O is produced by combining 95.0 g of O₂ and 11.0 g of H₂ is 87.87%.

Mass of any substance will be calculated by using their moles as:

n = W/M, where

W = given or required mass

M = molar mass

Moles of 95g of Oxygen (O₂) = 95g / 32g/mol = 2.96 moles

Moles of 11g of hydrogen (H₂) = 11g / 2g/mol = 5.5 moles

Given chemical reaction is:
2H₂ + O₂ → 2H₂O

From the stoichiometry of the reaction, it is clear that:

1 moles of O₂ = reacts with 2 moles of H₂

2.96 moles of O₂ = reacts with 2×2.96=5.92 moles of H₂

Here hydrogen is the limiting reagent as it has lower moles and formation of water depends on this only.

2 moles of H₂ = produces 2 moles of water

5.5 moles of H₂ = produces 5.5 moles of water

Mass of 5.5 moles of water will be calculated as:

W = (5.5mol)(18g/mol) = 99g

Given theoretical yield of water = 87g

% yield of water will be calculated as:
% yield = (87 / 99)×100 = 87.87%

Hence required value is 87.87%.

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Answer:

D

Explanation:

Answer:

big ablsolty long pp

Explanation:

dong

Answer:

Commensalism is a relationship between two organisms in which one organism benefits, and the other one is left unaffected.

Examples:

1. Barnacles on a sea turtle

2. Tree frogs and plants (they use them as protection)

1. Barnacles on a sea turtle

2. Tree frogs and plants (they use them as protection)

hope this helps

The origin of the Columbia River Basalt (CRB) has been a subject of scientific debate. There are two main hypotheses regarding its formation: the passive rise of shallow mantle and the active rise of a deep-mantle plume.

The origin of the Columbia River Basalt, a large igneous province in the northwestern United States, has been a subject of debate. Two main hypotheses propose different mechanisms for its formation. The passive rise of shallow mantle suggests that the basaltic magma resulted from decompression melting due to lithospheric extension and thinning.

On the other hand, the active rise of a deep-mantle plume theory proposes that the basaltic magma was generated by a deep-seated mantle plume. Determining the exact mechanism requires extensive geological and geochemical studies, including analyzing the composition and isotopic signatures of the basaltic rocks, to provide evidence supporting either the passive rise or active rise hypothesis.

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The collapse of a cloud of gas that leads to the formation of stars and planets depends on a number of factors. However, one of the most important factors that play a major role in this process is gravity. The force of gravity, which is generated by the gas molecules in the cloud, causes the molecules to pull towards the center of the cloud.

As a result of this gravitational pull, the gas molecules in the center of the cloud become more densely packed. This, in turn, leads to an increase in temperature and pressure at the center of the cloud. The increase in temperature and pressure triggers nuclear reactions that eventually result in the formation of a star.

Once the star is formed, it continues to exert a gravitational pull on the surrounding gas molecules. This leads to the formation of planets that orbit the star. In addition to gravity, other factors such as temperature, pressure, and the composition of the gas cloud can also influence the process of star and planet formation.

In conclusion, gravity is the most important factor that causes a cloud of gas to collapse and form a star and planets. This process can take millions of years and is influenced by a number of factors that interact with one another.

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Answer:

mechanical energy

Answer:

sea water

Explanation:

a sea water can match the following

Answer:

option d. 56/26 Fe is the correct answer.

The pH of a saturated solution of Ba(OH)2 tells us that there is an excess of OH- ions present in the solution. This means that the concentration of Ba2+ ions in the solution is equal to the solubility of Ba(OH)2.

The solubility product (Ksp) expression for Ba(OH)2 is:

Ksp = [Ba2+][OH-]^2

Since the pH of the saturated solution is 12, we know that the concentration of OH- ions is 10^-2 M. Therefore, the concentration of Ba2+ ions in the solution is also 10^-2 M.

Plugging these values into the Ksp expression, we get:

Ksp = (10^-2)(10^-2)^2 = 10^-6

Therefore, the value of Ksp for Ba(OH)2 is 1.0 x 10^-6, which is closest to option a. 4.0 x 10^-6.

A saturated solution is one in which the maximum amount of solute has dissolved in the solvent, and any additional solute will not dissolve. Solubility refers to the maximum amount of solute that can dissolve in a solvent under specific conditions.

For a saturated solution of Ba(OH)₂ with a pH of 12, the concentration of OH⁻ ions can be calculated using the relationship:

pOH = 14 - pH

pOH = 14 - 12 = 2

The concentration of OH⁻ ions is 10⁻² M. Since Ba(OH)₂ dissociates into one Ba²⁺ ion and two OH⁻ ions, the concentration of Ba²⁺ ions will be half that of OH⁻ ions (i.e., 10⁻²/2 M).

The solubility product (Ksp) for Ba(OH)₂ can be calculated using the expression:

Ksp = [Ba²⁺] * [OH⁻]²

Ksp = (10⁻²/2) * (10⁻²)² = 5.0 x 10⁻⁷

Therefore, the value of the solubility product (Ksp) of Ba(OH)₂ is 5.0 x 10⁻⁷, which corresponds to option d.

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Answer:

atoms of the same element that have different masses due to their

varying numbers of neutrons

Explanation:

The mass number of an atom is the  sum of number of protons and number of neutrons. Whereas, charge is acquired by the lose or gain of electrons.

The atomic mass describes how much an atom weighs. The mass of an atom is usually take as relative mass where the mass of an atom is determined relative to the mass of carbon -12.

Mass number describes the sum of number of protons  and neutrons.  The mass of an atom is mainly contributed by the nucleus thats why take the ,mass number as its mass.

An atom gains positive charge when it loses one or more electron. For example hydrogen with 1 proton and no neutrons will lose its one electron and acquire a positive charge.

When an atom gains an electron it acquire a negative charge. Consider oxygen where 8 neutron and 8 electrons  (6 valence electrons) are there with a mass of 16 g/mol. It acquires 2 units of negative charge by gaining two electron. Since it needs two ore electron to attain octet.

Similarly a nitrogen atom with mass of 14 g/mol and 5 valence electrons acquire a -3 charge since it need 3 more electron to attain octet.

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