If 1 cm on the globe represents 555 km in the real world, how many kilometers would you have traveled in 16.8 cm? (round)
9324 km

Answer:

19.5

Explanation:

momentum = mass * velocity

momentum = 6.5 * 3

momentum = 19.5

Answer:

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 30 × 10 × 15

We have the final answer as

Hope this helps you

Answer:

F=w=ma                                                                                                                                                       OR by using equations of motions                                                                               vf=vi-at                    : a=vf-vi/t                                                              eq 1                         s=vit+1/2at squre                                                                                 eq 2                     2as=vf squre - vi squre                                                                        eq 3                                                                                                                                                                                  

Explanation:

where m is the mass of falling body , f is the weight is the force acting down ward , vf is the final velocity, vi is the inetial velocity , t is the time and s is the distance covered by a body.

Answer:

P.E = 1764 Joules

Explanation:

Given the following data;

Mass = 6kg

Height = 30m

We know that acceleration due to gravity is equal to 9.8m/s²

To find the potential energy;

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

\( P.E = mgh\)

Where,

P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Substituting into the equation, we have;

P.E = 6 * 9.8 * 30

P.E = 1764 Joules

Explanation:

We know that, like charges repel and unlike charges attract each other.

IF one of the charge is four times that of the other and both charges are positive, the field lines is shown in figure (1).

Two negative charges attract each other, the field lines is shown in figure (2).

The net force between charges is given by :

\(F=\dfrac{kq_1q_2}{r^2}\)

Whre

k is the electrostatic constant

r is the distance between charges

According to Myers-Briggs, a charcteristic that is common to judging is  liking things settled and organized.

The term judging has to do with the quest for order and organization. It is one of the personality traits as outlined by Myers-Briggs.

The characteristic that is common among the people that exhibit the judging personality trait is liking things settled and organized.

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Answer:likes to have things settled and organized

Explanation:

bc I just took the test so ik it’s right

Answer:

C. Heat will flow from Object A to Object B

Thanks!

The candidate's speed (m/s), given that the candidate experiences a centripetal acceleration that is 2.8 times the acceleration due to gravity is 17.4 m/s

We understood that the centripetal acceleration is related to speed and radius according to the following formula:

a = v² / r

Cross multiply

v² = ar

Take the square root of both sides

v = √ar

Where

Withe the above formula, we can determin the speed of the candidate. Details below:

v = √ar

v = √(27.44 × 11.05)

v = 17.4 m/s

Thus, the speed of the candidate is 17.4 m/s

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The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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One degree of longitude at the equator is 111.32 kilometers (69.17 miles), one minute of longitude is 1.855 kilometers (1.153 miles), and one second of longitude is 0.031 kilometers (0.019 miles).

At the equator, one degree of longitude corresponds to 1/360th of the circumference of the Earth, which can be calculated as:

C = 2*π*r where C is the circumference, r is the radius of the Earth.

The radius of the Earth is half of its diameter, so:

r = 12,756 km / 2 = 6,378 km

Thus, the circumference of the Earth at the equator is:

C = 2*π*(6,378 km) ≈ 40,075 km

So, one degree of longitude at the equator is:

40,075 km / 360 ≈ 111.32 km

Or in miles:

24,901 miles / 360 ≈ 69.17 miles

To find the distance in one minute of longitude, we need to divide by 60:

111.32 km / 60 ≈ 1.855 km/min

69.17 miles / 60 ≈ 1.153 miles/min

To find the distance in one second of longitude, we need to divide by 60 again:

1.855 km/min / 60 ≈ 0.031 km/sec

1.153 miles/min / 60 ≈ 0.019 miles/sec

Therefore, one degree of longitude at the equator corresponds to approximately 111.32 kilometers (69.17 miles), one minute of longitude corresponds to approximately 1.855 kilometers (1.153 miles), and one second of longitude corresponds to approximately 0.031 kilometers (0.019 miles).

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Answer:

Hello! Your answer would be, O False

Explanation:

Hope I helped! Brainiest plz!♥ Have a nice morning! Hope you make a 100%! -Abby

Answer:

False is the correct answer.

Explanation:

plz mark me as brainliest.

The specific heat capacity of the metal, given that 27.777 g of water at 22.1 °C was mixed with the metal is 9.7×10⁻² Cal/gºC

Step 1: Obtain the heat absorbed by the water. This is shown below:

Q = MCΔT

= 27.777 × 1 × 7.2

= 199.9944 Cal

Step 2: Determine the specific heat capacity of the metal using the heat absorbed by the water. Details below:

Q = MCΔT

-199.9944 = 29.292 × C × -70.6

-199.9944 = -2068.0152 × C

Divide both sides by -2068.0152

C = -199.9944 / -2068.0152

= 9.7×10⁻² Cal/gºC

Thus, the specific heat capacity of the metal is 9.7×10⁻² Cal/gºC. None of the options are correct.

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The reason we perceive the moon to be bigger when its a full moon is because it is farther away, making our brains think it is larger. One interpretation is that the horizon might appear more distant than the sky, making space of the moon look more flattened and dome like instead of a round sphere.

Nuclear fusion may be used to create new elements using a particle accelerator. Niels Bohr's atomic model informed Henry Moseley's discovery of the atomic number. Transuranium elements have a wide range of industrial uses. Transmutation reactions allow for the synthesis of new elements. Advanced particle accelerators are still utilized to create new elements.

1. Nuclear fusion is a process that may be used to synthesize new elements using a particle accelerator.

Two lighter atomic nuclei are brought together at high speeds and temperatures in this process, forcing them to combine and produce a heavier nucleus.

The nucleus formed will have a higher atomic number and maybe a new element. The particle accelerator provides the required energy to overcome the electrostatic resistance between the positively charged nuclei, allowing them to reach near enough to be bound together by the strong nuclear force.

2. Henry Moseley's discovery of atoms was inspired by Niels Bohr's work on the structure of the atom, which provided a theoretical foundation for comprehending the link between the number of protons in an atom's nucleus and its position in the periodic table.

Bohr's atomic model postulated that electrons circle the nucleus in discrete energy levels, and Moseley's tests demonstrated that the energy levels of electrons in various elements were proportional to the number of protons in the nucleus.

This resulted in the discovery of the atomic number, which is the number of protons in the nucleus of an atom and is used to rank the elements in the periodic table.

3. Transuranium elements, which have atomic numbers larger than 92, offer a wide range of industrial uses.

Americium-241 is utilized in smoke detectors, curium-244 powers spacecraft and satellites, and plutonium-238 provides power for deep space missions.

These elements might also be used in nuclear medicine and energy generation.

4. Transmutation reactions provide an important contribution by allowing the formation of new elements by altering the number of protons in an atom's nucleus.

This method has resulted in the discovery of multiple elements and has contributed to our knowledge of matter's fundamental features.

5. Although complex and energy-intensive, it is nevertheless feasible to synthesize new elements using powerful particle accelerators.

Ernest Rutherford and other early nuclear physicists devised procedures that have been refined and improved through time, allowing scientists to synthesize and analyze ever heavier elements.

However, as the atomic number of the elements grows, so does their stability, making them more difficult to synthesize and analyse. As a result, new element synthesis is still an active area of study and discovery in nuclear physics.

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The given statement about “The nucleus was discovered by Rutherford when this occurred to the alpha particles shot at gold foil in his laboratory.” is true, because in his famous experiment, alpha particles were seen to scatter away from a gold foil in the reverse direction.

In the Rutherford model, the atom is described as having a small, dense, positively charged core known as a nucleus, in which nearly all of the mass is concentrated, and around which the light, negative constituents known as electrons circulate at some distance, similar to how planets revolve around the sun at a certain distance. Under the guidance of Rutherford and German physicist Hans Geiger in 1909, Ernest Marsden, conducted a series of experiments that revealed the scattering of alpha particles from thin gold foil. This resulted in the hypothesis that the nucleus was small and dense.

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Answer:

131.2 kg, to have the same precision as 58.2 kg

Explanation:

Answer:

The answer is B

Explanation:

keep it up

Answer:

The fields are at right angles to each other and to the direction of the wave.

Explanation:

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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La conservación de la energía mecanica permite encontrar los resultados para las preguntas son:

La energía mecánica es la energía total del cuerpo, esta formada por la suma de la energía cinética y la energía potencial, este energía es constante en un sistema sin roce.

         Em = K + U

Donde Em es la energía mecánica, K la energía cinéticas y U las energizas potenciales.

En el adjunto tenemos un esquema del movimiento, busquemos la energía mecánica en dos puntos:

Punto inicial. En la  parte mas baja.

          \(Em_o = K\) = ½ m v²  

Donde m es la masa y v la velocidad del cuerpo.

Punto final.  En la parte mas alta de la trayectoria.

          \(Em_f =U\) = m g y

La energía mecánica se conserva.

          \(Em_o = Em_f\)

          ½ m v² = m g y

         v= \(\sqrt{2 g y}\)

Calculamos

         v =  \(\sqrt{2 \ 9.8 \ 83}\)

         v =  40,3 m/s

Como en el sistema no hay roce la energía mecánica se mantiene constante en toda la trayectoria.

        Em = m g y

        Em =  46 9,8 83

        Em = 3,8 10⁴ J

En conclusión usando la conservación de la energía podemos encontrar los resultados para las preguntas son:

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Answer:

1. No, it is a colloid

2. Yes

Explanation:

Answer:

A = 21 î + 28 ĵ

B = 12 î + 5 ĵ

Explanation:

a.

To write A and B in terms of î and ĵ, we need to use the trigonometric ratios and the vector notation

According to the diagram, we have:

tan a = 4/3 tan ß = 5/12

Using the identity tan θ = opposite/adjacent, we can find the x and y components of A and B.

For A, we have:

x component = 35 cos a y component = 35 sin a

Using tan a = 4/3, we can find cos a and sin a by using Pythagoras’ theorem:

cos a = 3/5 sin a = 4/5

Therefore, the x and y components of A are:

x component = 35 cos a = 35 (3/5) = 21 y component = 35 sin a = 35 (4/5) = 28

Using the vector notation, we can write A as:

A = 21 î + 28 ĵ

Similarly, for B, we have:

x component = 13 cos ß y component = 13 sin ß

Using tan ß = 5/12, we can find cos ß and sin ß by using Pythagoras’ theorem:

cos ß = 12/13 sin ß = 5/13

Therefore, the x and y components of B are:

x component = 13 cos ß = 13 (12/13) = 12 y component = 13 sin ß = 13 (5/13) = 5

Using the vector notation, we can write B as:

B = 12 î + 5 ĵ

b.

To show that A + B makes an angle of 45° to the x-axis, we need to find the resultant vector R and its angle θ with the x-axis.

To find R, we can use the vector addition rule :

R = A + B R = (21 î + 28 ĵ) + (12 î + 5 ĵ) R = (21 + 12) î + (28 + 5) ĵ R = 33 î + 33 ĵ

To find θ, we can use the inverse tangent function :

tan θ = y component / x component tan θ = 33 / 33 tan θ = 1

θ = tan^-1(1) θ = 45°

Therefore, A + B makes an angle of 45° to the x-axis.

Explanation:

To determine the effort needed to lift a load of 200N, given a velocity ratio of 5 and an efficiency of 80%, we can use the formula:

Efficiency = (Output Work / Input Work) * 100

Efficiency can also be calculated as the ratio of the output force to the input force. In this case, the output force is the load being lifted (200N), and the input force is the effort required.

Given that the velocity ratio is 5, it means that for every 5 units of distance the effort moves, the load moves 1 unit of distance. This implies that the effort is exerted over a greater distance than the load.

Let's denote the effort force as "E" and the distance moved by the effort as "dE." Similarly, the load force is "L," and the distance moved by the load is "dL."

Using the velocity ratio, we have the following relationship:

dE / dL = 5

Now, we can calculate the input work (Wi) and the output work (Wo):

Input Work (Wi) = Effort (E) * Distance moved by the effort (dE)

Output Work (Wo) = Load (L) * Distance moved by the load (dL)

Given that the efficiency is 80%, we can rewrite the formula for efficiency as:

0.80 = (Wo / Wi) * 100

Now, let's solve for the effort (E) using the given values:

Load (L) = 200N

Efficiency = 0.80

Velocity Ratio = 5

First, calculate the output work (Wo):

Wo = Load (L) * Distance moved by the load (dL)

Since the velocity ratio is 5, the distance moved by the load (dL) will be 1/5 of the distance moved by the effort (dE):

dL = (1/5) * dE

Wo = L * (1/5) * dE

Wo = 200N * (1/5) * dE

Wo = 40N * dE

Next, calculate the input work (Wi):

Wi = Effort (E) * Distance moved by the effort (dE)

Wi = E * dE

Now, substitute the values into the efficiency formula:

0.80 = (Wo / Wi) * 100

0.80 = (40N * dE) / (E * dE) * 100

0.80 = 40 / E * 100

0.80 * E = 40

E = 40 / 0.80

E = 50N

Therefore, the effort needed to lift a load of 200N with a velocity ratio of 5 and an efficiency of 80% is 50N.

a 150-dB sound is approximately 10 million times louder than an 80-dB sound.

Provide instances of the differences between the audible, ultrasonic, and infrasonic frequency ranges. Three sorts of sound waves, each covering a distinct frequency range, are used. These are what they are:

The difference in decibels between two sounds is related to the ratio of their intensities (or power) by the following formula:

dB₂ - dB₁ = 10 log10(I₂ / I₁)

where dB₁ and dB₂ are the decibel levels of the two sounds, and I₁ and I₂ are their intensities (or power).

Using this formula, we can find the ratio of the intensity of a 150-dB sound to that of an 80-dB sound:

150 dB - 80 dB = 10 log10(I₁₅₀ / I₈₀)

70 = 10 log10(I₁₅₀ / I₈₀)

7 = log10(I₁₅₀ / I₈₀)

10^7 = I₁₅₀ / I₈₀

I₁₅₀  = 10^7 * I₈₀

This shows that the intensity of a 150-dB sound is 10 million times greater than that of an 80-dB sound.

Therefore, a 150-dB sound is approximately 10 million times louder than an 80-dB sound.

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The magnitude of the vector is approximately 35.85 m.

The angle that this vector makes with the positive x-axis is approximately 32 degrees.

To find the magnitude of the vector with components Ax=29 m and Ay=18 m, we use the Pythagorean theorem:

|A| = √(Ax^2 + Ay^2)

|A| = √(29^2 + 18^2)

|A| = √(841 + 324)

|A| = √1165

|A| =  34.13 m

To find the angle that this vector makes with the positive x-axis, we can use the inverse tangent function:

θ = tan^-1(Ay/Ax)

θ = tan^-1(18/29)

θ = 31.82 degrees

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The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.

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Answer:

D. Hydrogen

Explanation:

The sun is a big ball of gas and plasma. Most of the gas — 91 percent — is hydrogen.

Answer:

D. Hydrogen

Explanation:

Hydrogen makes up most of the Sun. It is nearly 91 percent.