i have 100% in the class, but the cumulative final is next week. what if i fall on the final, how many percent will i have after the final. example for that

The desired expression for f(x) in terms of a contour integral and a sum over the poles is (1/πx) ∑ (-1)^n f(t).

The integral can be closed in the complex k-plane by considering a semicircle in the upper half-plane, and evaluating the residues of the integrand at the poles inside the contour. The resulting expression for f(x) involves a contour integral and a sum over the poles.

The Fourier inversion formula is given by:

f(x) = (1/(2π)) ∫₋∞₊∞ e^(ikx) F(k) dk

where F(k) is the Fourier transform of f(x).

To evaluate the integral for x > 0, we can close the contour in the upper half-plane by adding a semicircle at infinity. This is because the integrand decays rapidly as |k| → ∞, so the contribution from the semicircle is zero.

Then, the integral becomes a sum over the residues of the integrand at the poles inside the contour:

f(x) = (1/(2π)) ∑ Res(e^(ikx) F(k), poles inside contour)

To find the residues, we need to factorize the integrand:

e^(ikx) F(k) = e^(ikx) ∫₋∞₊∞ f(t) e^(-ikt) dt

= ∫₋∞₊∞ f(t) e^(i(kx-t)) dt

The poles occur when kx - t = nπi for some integer n. Solving for k, we get:

k = (nπi + t)/x

The residues at these poles are given by:

Res(e^(ikx) F(k), k = (nπi + t)/x) = e^(inπi) f(t)/x

Substituting these expressions back into the formula for f(x), we get:

f(x) = (1/(2π)) ∑ e^(inπi) f(t)/x

= (1/πx) ∑ (-1)^n f(t)

where the sum is over all integers n and the factor (-1)^n comes from the alternating signs of the exponentials.

This is the desired expression for f(x) in terms of a contour integral and a sum over the poles.The integral can be closed in the complex k-plane by considering a semicircle in the upper half-plane, and evaluating the residues of the integrand at the poles inside the contour. The resulting expression for f(x) involves a contour integral and a sum over the poles.

The Fourier inversion formula is given by:

f(x) = (1/(2π)) ∫₋∞₊∞ e^(ikx) F(k) dk

where F(k) is the Fourier transform of f(x).

To evaluate the integral for x > 0, we can close the contour in the upper half-plane by adding a semicircle at infinity. This is because the integrand decays rapidly as |k| → ∞, so the contribution from the semicircle is zero.

Then, the integral becomes a sum over the residues of the integrand at the poles inside the contour:

f(x) = (1/(2π)) ∑ Res(e^(ikx) F(k), poles inside contour)

To find the residues, we need to factorize the integrand:

e^(ikx) F(k) = e^(ikx) ∫₋∞₊∞ f(t) e^(-ikt) dt

= ∫₋∞₊∞ f(t) e^(i(kx-t)) dt

The poles occur when kx - t = nπi for some integer n. Solving for k, we get:

k = (nπi + t)/x

The residues at these poles are given by:

Res(e^(ikx) F(k), k = (nπi + t)/x) = e^(inπi) f(t)/x

Substituting these expressions back into the formula for f(x), we get:

f(x) = (1/(2π)) ∑ e^(inπi) f(t)/x

= (1/πx) ∑ (-1)^n f(t)

where the sum is over all integers n and the factor (-1)^n comes from the alternating signs of the exponentials.

This is the desired expression for f(x) in terms of a contour integral and a sum over the poles.

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If x is the largest of the three consecutive integers, then the three consecutive integers can be represented as x-1, x, and x+1.

The sum of these three consecutive integers is:

(x-1) + x + (x+1)

Simplifying the expression, we get:

3x

Therefore, the expression in terms of the given variables that represents the sum of three consecutive integers when x is the largest is 3x.

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The private spilled 0.35 litres of fuel

The first step is to convert 6.5 hectolitres to litres

= 6.5 × 100

= 650 litres

Next is to convert millilitres to litres

= 350/1000

= 0.35 litres

Hence the number of litres spilled is 0.35 litres

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The work done by the gas during the isothermal expansion is 331.32 J.

Isothermal Expansion refers to a process in which the temperature of a system stays constant while the volume increases. In this process, an ideal gas expands from 1.1 m³ to 1.8 m³, and the gas constant is R = 8.314 J/(mol K).

The work done by the gas during the isothermal expansion can be calculated as follows:Answer:During an isothermal process, the change in internal energy of the system is zero since the temperature remains constant.

Therefore,ΔU = 0The first law of thermodynamics is given by:ΔU = q + w

where q is the heat absorbed by the system, and w is the work done on the system.Since ΔU = 0 for an isothermal process, the above equation reduces to:w = -q

During an isothermal process, the heat absorbed by the system is given by the equation:q = nRTln(V₂/V₁)Where, n is the number of moles, R is the gas constant, T is the temperature, V₁ is the initial volume, and V₂ is the final volume.

Substituting the given values, we have:q = (1 mol) × (8.314 J/(mol K)) × (293 K) × ln(1.8 m³ / 1.1 m³)q = 331.32 J

Therefore, the work done by the gas during the isothermal expansion is given by:w = -qw = -(-331.32 J)w = 331.32 J

Thus, the work done by the gas during the isothermal expansion is 331.32 J.

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the Jacobian determinant for the transformation \(x = 6u\sin(5v), y = 6u\cos(5v)\) is \(J = -180u\).

To find the Jacobian determinant of the transformation \((x, y) \rightarrow (u, v)\) for the given equations, we need to compute the partial derivatives of x and y with respect to u and v, respectively, and then calculate the determinant.

Transformation 1: \(x = 6u\cos(5v), y = 6u\sin(5v)\)

We start by finding the partial derivatives:

\[\frac{\partial x}{\partial u} = 6\cos(5v)\]

\[\frac{\partial x}{\partial v} = -30u\sin(5v)\]

\[\frac{\partial y}{\partial u} = 6\sin(5v)\]

\[\frac{\partial y}{\partial v} = 30u\cos(5v)\]

Now, we can calculate the Jacobian determinant:

\[J = \frac{\partial (x, y)}{\partial (u, v)} = \begin{vmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{vmatrix} = \begin{vmatrix} 6\cos(5v) & -30u\sin(5v) \\ 6\sin(5v) & 30u\cos(5v) \end{vmatrix}\]

Simplifying the determinant:

\[J = (6\cos(5v))(30u\cos(5v)) - (-30u\sin(5v))(6\sin(5v))\]

\[J = 180u\cos^2(5v) + 180u\sin^2(5v)\]

\[J = 180u(\cos^2(5v) + \sin^2(5v))\]

\[J = 180u\]

Therefore, the Jacobian determinant for the transformation \(x = 6u\cos(5v), y = 6u\sin(5v)\) is \(J = 180u\).

Transformation 2: \(x = 6u\sin(5v), y = 6u\cos(5v)\)

We repeat the same process for the second transformation:

\[\frac{\partial x}{\partial u} = 6\sin(5v)\]

\[\frac{\partial x}{\partial v} = 30u\cos(5v)\]

\[\frac{\partial y}{\partial u} = 6\cos(5v)\]

\[\frac{\partial y}{\partial v} = -30u\sin(5v)\]

The Jacobian determinant:

\[J = \begin{vmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{vmatrix} = \begin{vmatrix} 6\sin(5v) & 30u\cos(5v) \\ 6\cos(5v) & -30u\sin(5v) \end{vmatrix}\]

Simplifying the determinant:

\[J = (6\sin(5v))(-30u\sin(5v)) - (30u\cos(5v))(6\cos(5v))\]

\[J = -180u\sin^2(5v) - 180u\cos^2(5v)\

]

\[J = -180u(\sin^2(5v) + \cos^2(5v))\]

\[J = -180u\]

Therefore, the Jacobian determinant for the transformation \(x = 6u\sin(5v), y = 6u\cos(5v)\) is \(J = -180u\).

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Answer:

It would take 1097 days for the costs in Canada to be equal (up to) the cost in China

Step-by-step explanation:

The information given in the question includes;

1) China initial fee = $1,000,000

Number of people = 10

Payment per person per day = $1

Payment for the 10 people per day = $10

Canada initial fee = $50,370

Number of people = 10

Payment per person per day = $90

Payment for the 10 people per day = $900

Step 1: Define the variables to represent unknown quantities

Let the number of days at which the cost would be equal be X

Step 2: The equations relating the variables are;

$1,000,000 + X-days × $10/day = $50,370 + X-days × $900/day

Step 3: To solve the equation we have;

$1,000,000 - $50,370 =  X-days × $900/day - X-days × $10/day

$949,360 = X-days × $890/day

X-days = $949,360 ÷ $890/day = 1067 days

Step 4: Conclusion: It would take 1097 days for the costs in Canada to be equal (up to) the cost in China

5) The difference in wages can be explained by the following;

1) Low cost of living in China compared to Canada

2) Higher unemployment figures in China

3) Government policies

6) Companies that outsource their manufacturing includes;

1) Apple 2) Cisco 3) Nike

7) Advantages of outsourcing

a) Acquire skilled labor

b) Reduce the distraction of manufacturing and focus on fundamental pursuits

c) Reduce risks

d) Improve efficiency

e) 24 hours up time business  

f) Improved workforce flexibility

g) Service improvement

h) Cost savings

8) Disadvantages of outsourcing

a) Hidden costs of production

b) Potential loss of focus

c) Increased security risks

d) Reduced central control

e) Partake in financial cost of other companies

I dunn know wut you mean but herez..

Simplify the parenthesis

Simplify all exponents

Simplify all multiplication and division, left to right

Simplify all addition and subtraction, left to right

Hava gud day :P

iii,v,iv,i, and ii

can I get brainlyest?

Answer:

the third one, the 6 one, and the last one

Step-by-step explanation:

i hope it help because it like asking you for the number who will give you positive, and if you know negative + negative = positive

The procedure which is deemed to be the type of sample in discuss is; representative sample are free of bias.

Representative sampling and random sampling are two techniques used to help ensure data is free of bias. A representative sample on the other hand is a group or set chosen from a larger statistical population according to specified characteristics. A random sample is a group or set chosen in a random manner from a larger population.

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By using Disk Method, the integral that gives the volume of the solid formed by revolving the region about the y-axis of y = x^(11/12) y=1, x=0 is V = π∫(0 to 1) y^(24/11) dy = 11π/35. The option is D) is correct.

To use the Disk Method to find the volume of the solid formed by revolving the region about the y-axis, we can imagine slicing the solid into thin disks perpendicular to the y-axis, with each disk having thickness dy. The total volume of the solid can be found by summing up the volumes of all such disks from y=0 to y=1.

The equation of the curve is y = x^(11/12), so we can solve for x as x = y^(12/11). The region is bounded by y=0, y=1 and x=0.

Now, consider a thin disk located at a distance y from the y-axis. The radius of the disk is given by the distance between the y-axis and the curve at y, which is simply x = y^(12/11). Thus, the radius of the disk is r(y) = y^(12/11). The thickness of the disk is dy.

The volume of the disk is given by the formula for the volume of a cylinder, which is V = πr^2h, where r is the radius of the disk and h is its thickness. Substituting in the values we have for r(y) and dy, we get:

dV = π(y^(12/11))^2 dy

Integrating this expression over the range of y from y=0 to y=1 gives us the total volume of the solid:

V = ∫(0 to 1) π(y^(12/11))^2 dy

Simplifying the integrand, we have:

V = π∫(0 to 1) y^(24/11) dy

Using the power rule of integration, we have:

V = π[(11/35) y^(35/11)](0 to 1)

Evaluating this expression at the limits of integration, we get:

V = π[(11/35) - 0] = π(11/35) = 11π/35

Therefore, the volume of the solid formed by revolving the region about the y-axis is 11π/35 cubic units. The correct answer is D).

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_____The given question is incomplete, the complete question is given below:

Use the Disk Method to set up and evaluate the integral that gives the volume of the solid formed by revolving the region about the y-axis. y = x^(11/12) y=1, x=0

A)  V = π∫(0 to 1) y^(11/12) dy =  11π/70

B)  V = π∫(0 to 1) y^(24/11) dy =  11π/70

C)  V = π∫(0 to 1) y^(12/11) dy =  11π/35

D) V = π∫(0 to 1) y^(24/11) dy = 11π/35

A-B is equivalent to 5x2 + 11x - 13 as a result as \(A = 3x^2 + 5x - 6\) and  \(B = -2x^2 - 6x + 7\) .

A mathematical expression is a grouping of digits, variables, operators, and symbols that denotes a mathematical amount or relationship. It can be analyzed or condensed using mathematical operations and rules, and it can be a single word or a group of terms. Numerous mathematical ideas, including equations, variables, functions, and formulas, can be represented by expressions. Standard form, factored form, extended form, and polynomial form are just a few of the different ways they can be expressed in writing.

given

We must deduct the expression B from the expression A in order to obtain A-B. To accomplish this, we subtract the appropriate coefficients from terms of the same degree. Here are the facts:

\(A = 3x^2 + 5x - 6\\B = -2x^2 - 6x + 7\)

A - B =\((3x^2 + 5x - 6) (-2x^2 - 6x + 7)\)

= 3x2 + (5x - 6) + (2x2 - 6) + (7x - 5x2 + 11x - 13 (distributing the negative sign)

A-B is equivalent to 5x2 + 11x - 13 as a result as \(A = 3x^2 + 5x - 6\) and  \(B = -2x^2 - 6x + 7\) .

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A toy passed the strength test then the probability that is without finishing defects is 0.938

Given that Factory of wooden toys checks the quality of production before its commercial date.

F: is the toy is w/o finishing defects

S: the toy passes the strength test

P(S(bar)/F(bar)) = P(S(bar)∩F(bar)) / P(F(bar))

= P(F(bar)/S(bar)) × P(S(bar)) / P(F(bar)/S(bar)) × P(S(bar)) + P(F(bar)/S)×P(S)

= (1-0.95) ×0.08 / (1-0.95)× 0.08 + (1-0.92) × 0.92

= 0.02 / 0.098

= 1/4

P(S) = P(S/F)× P(F) + P(S/F') × P(F')

= 0.95 × 0.92 + 0.08 × 0.08

= 0.934

b) P(F/S) = P(S/F)× P(F) / P(S)

= 0.95 × 0.92 / 0.934

= 0.938

Hence, a toy passed the strength test then the probability that is without finishing defects is 0.938

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Answer:

1. 3.2 x 10^4

2. 6 x 10^4

3. 1.04 x 10^5

4. 1.82 x 10^7

5. 9.23 x 10^6

6. 4.05 x 10^5

7. 2.019 x 10^3

8. 3.02 x 10^4

Step-by-step explanation:

Next time don't randomly comment on other people's questions to get points without putting in the effort. Spread credibility, not liability. Do the rest by yourself; there are multiple resources online that you can learn from!

Answer:

1. 3.2 x 10^4

2. 6 x 10^4

3. 1.04 x 10^5

4. 1.82 x 10^7

5. 9.23 x 10^6

6. 4.05 x 10^5

7. 2.019 x 10^3

8. 3.02 x 10^4

Step-by-step explanation:

I really hoped this helped

The missing coefficients in the equation y = mx + b are m = 0.841 and b = 18.813. The final equation that fits the given data is y = 0.841x + 18.813

To find the missing coefficients in the equation y = mx + b, we need to use the given data in the table to determine the values of m and b.

We can start by using two of the data points to set up a system of equations:

Using (5, 23.018) and (6, 23.859):

m(5) + b = 23.018

m(6) + b = 23.859

Subtracting the first equation from the second equation gives:

m(6) - m(5) = 0.841

Simplifying this expression:

m = 0.841 / (6 - 5) = 0.841

Now we can substitute the value of m into one of the original equations to solve for b:

m(5) + b = 23.018

0.841(5) + b = 23.018

b = 23.018 - 4.205

b = 18.813

Therefore, the missing coefficients are:

m = 0.841

b = 18.813

The equation y = 0.841x + 18.813 fits the given data.

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The given question is incomplete, the complete question is:

Use the data in the given table to fill in the missing coefficients. Round your answers to 3 decimal places. X y 5 23.018 5.5 23.438 6 23.859 6.5 24.035 7 25.449 7.5 24.868 8 26.058 I Enter an integer or decimal number [more..] y = I+

According to Descartes' Rule of Signs, there is 1 positive real zero and 2 or 0 negative real zeroes of the polynomial.

Descarte's Rule of Signs determines the number of real zeros in polynomial functions.

This indicates that -

The number of positive real zeros in the polynomial function f(x) is less than or equal to an even number depending on the sign change of the coefficients.

The number of negative real zeros in f(x) is an even number equal to or less than the number of sign changes of the coefficients of f(-x) terms.

Here, the polynomial function is given as -

\(P(x)=x^{3}-x^{2} -x-5\) ----- (1)

We have to find out the number of positive and negative real zeros that  the given polynomial can have.

The given polynomial already has its variables in the descending powers. So, we can easily determine the number of sign changes in the coefficients of P(x).

So, the coefficients of the variables in P(x) are -

1, -1, -1, -5

From above, we see that -

There is a sign change in the first and second variable coefficients

There is no sign change in the second and third variable coefficients

There is no sign change in the third and fourth variable coefficients

According to Descartes' Rule of Signs, there can be exactly three positive real zeros or less than three but an odd number of zeros.

So, we can determine that the number of positive real zeroes of the given polynomial can be 1.

To find out the negative real zeroes of the given polynomial, we have to find out P(-x) and determine the sign changes in the variable coefficients of P(-x).

From equation (1), we can write P(-x) as -

\(P(x)=x^{3}-x^{2} -x-5\\= > P(-x)=(-x)^{3}-(-x)^{2} -(-x)-5\\= > P(-x)=-x^{3}-x^{2} +x-5\)----- (2)

So, the coefficients of the variables in P(-x) are -

-1, -1, +1, -5

From above, we see that -

There is no sign change in the first and second variable coefficients

There is a sign change in the second and third variable coefficients

There is a sign change in the third and fourth variable coefficients

According to Descartes' Rule of Signs, since there are two sign changes of the coefficient variables, there can be two negative real zeros or less than two but an even number of zeros.

So, we can determine that the number of negative real zeroes of the given polynomial can be 2 or 0.

Thus, according to Descartes' Rule of Signs, there is 1 positive real zero and 2 or 0 negative real zeroes of the polynomial.

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The vector a = ⎝⎛−311⎠⎞ such that aT​Y​=2Y1​−3Y2​+Y3​. The distribution of Z= 2Y1​−3Y2​+Y3​ is N(μZ,ΣZ), where μZ = 1 and ΣZ = 12. The matrix A = ⎝⎛110​012​101⎠⎞ such that AY​=(Y1​+Y2​+Y3​Y1​−Y2​+2Y3​​). The joint distribution of W​=(W1​W2​​), where W1​=Y1​+Y2​+Y3​ and W2​=Y1​−Y2​+2Y3​ is N2(μW,ΣW), where μW = 5 and ΣW = 14. The joint distribution of V​=(Y1​Y3​​) is N2(μV,ΣV), where μV = (3, 1) and ΣV = ⎝⎛61−2​143​⎠⎞​. The joint distribution of Z​=⎝⎛​Y1​Y3​21​(Y1​+Y2​)​⎠⎞​ is N3(μZ,ΣZ), where μZ = ⎝⎛311⎠⎞​ and ΣZ = ⎝⎛61−2​143​−2312​⎠⎞​.

(a) The vector a = ⎝⎛−311⎠⎞ such that aT​Y​=2Y1​−3Y2​+Y3​ can be found by solving the equation aT​Σ​a = Σ​b, where b = ⎝⎛2−31⎠⎞​. The solution is a = ⎝⎛−311⎠⎞​.

(b) The matrix A = ⎝⎛110​012​101⎠⎞ such that AY​=(Y1​+Y2​+Y3​Y1​−Y2​+2Y3​​) can be found by solving the equation AY = b, where b = ⎝⎛51⎠⎞​. The solution is A = ⎝⎛110​012​101⎠⎞​.

(c) The joint distribution of V​=(Y1​Y3​​) is N2(μV,ΣV), where μV = (3, 1) and ΣV = ⎝⎛61−2​143​⎠⎞​. This can be found by using the fact that the distribution of Y1​ and Y3​ are independent, since they are not correlated.

(d) The joint distribution of Z​=⎝⎛​Y1​Y3​21​(Y1​+Y2​)​⎠⎞​ is N3(μZ,ΣZ), where μZ = ⎝⎛311⎠⎞​ and ΣZ = ⎝⎛61−2​143​−2312​⎠⎞​. This can be found by using the fact that Y1​, Y2​, and Y3​ are jointly normal.

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Answer: A

Step-by-step explanation: I would say A because the angle is greater than 90 degrees

Answer:

We have supplementary angles.

76 + 3x + 2 = 180

3x + 78 = 180

3x = 102

x = 34

The correct option of the given statement "The present value of $5,325 to be received in one period at a rate of 6.5%" is d. 5,000.

it can be found using the formula:

PV = FV/(1 + r),

where

PV is the present value,

FV is the future value,

and r is the interest rate expressed as a decimal.

Here, FV = $5,325 and r = 0.065 (6.5% expressed as a decimal).

Substituting these values into the formula gives:

PV = $5,325/(1 + 0.065)PV

    = $5,325/1.065PV

     ≈ $5,000

Therefore, the present value of $5,325 to be received in one period if the rate is 6.5% is approximately $5,000.

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Given

Solving, step-by-step

Answer:

B

Step-by-step explanation:

A has a change of 20 Fahrenheit.

C has an overall change of 21 kilometres.

D has a total distance of 6.2 kilometres.

PLS GIVE BRAINLIEST

Answer:

B.

Step-by-step explanation:

Buys item = -2.25

Sells item = +2.25

-2.25 + 2.25 = 0

A) The difference between -10 and 10 is 20.

C) sea level = 0, 0 + 21 = 21

D) 3.1 + 3.1 = 6.2

Answer:

I believe the answer is Kelvin

Answer:

8x - 3

General Formulas and Concepts:

Step-by-step explanation:

Step 1: Define expression

6x + 2x - 3

Step 2: Simplify

Answer:

64%

Step-by-step explanation:

"Percent" means per hundred. So Lamar has completed 32 out of 50 deliveries.

32/50 is the same as 64/100.

64/100 is 64%

Without mental math, if you can use a calculator, divide

32÷50

You'll get 0.64, times by 100 (or move the decimal point two places to the right) to get 64%

Answer:

68°+47°+ x = 180°

115°+ x = 180°

115°-115°+x = 180°-115°

x = 65°

hope it's helpful ❤❤❤❤

THANK YOU.

Answer:

Yes, Logan's pay rates are proportional for those 2 days.

Step-by-step explanation:

First, we have to figure out what 6 divided by 3 is.

6 ÷ 3 = 2

So, now we have to divide 90 by 45.

90 ÷ 45 = 2.

So, yes it is proportional because 6 ÷ 3 = 2 and 90 ÷ 45 is also 2 so yes it is proportional.

Hope this helps! :)

Answer:

\( m\angle A = 79\degree\)

\( m\angle B = 112\degree\)

Step-by-step explanation:

ABCD is a cyclic Quadrilateral.

Opposite angles of a cyclic quadrilateral are supplementary.

Therefore,

\( m\angle A + m\angle C = 180\degree\)

\( m\angle A + 101\degree = 180\degree\)

\( m\angle A = 180\degree-101\degree\)

\( \red{\bold {m\angle A = 79\degree}} \)

\( m\angle B + m\angle D = 180\degree\)

\( m\angle B + 68\degree = 180\degree\)

\( m\angle B = 180\degree-68\degree\)

\( \purple {\bold {m\angle B = 112\degree}} \)

Answer:

(x-3)^2 + (y+2)^2 = 25

Step-by-step explanation:

Center is (3,-2) Radius is 5

3=h -2=k r=5

Formula (x-h)^2 + (y-k)^2 = r^2

Plug it in and switch the signs inside the ( )

(x-3)^2 + (y+2)^2 = 25

Answer:

186 degree

Step-by-step explanation:

136' - (-50')

a negative times a negative equals a positive

136' + 50' = 186'