I am the life cycle that contains tiny undeveloped plants,
but I still have enough food for growth. Who am I?


Please help PLEASE

Answer:

CO2: Carbon Dioxide

CS2: Cardon Disulfide

PBr3: Phosphorus Tribromide

P2S5: Phosphorus Pentasulfide

N2S: Monosulfur Dinitride

SiS2: Silicon Disulfide

NBr3: Nitrogen Tribromide

N2CI4: Sorry don't know this one.

Atoms of two distinct elements are bound together by covalent bonds to form binary covalent compounds. They typically contain nonmetal elements, such as laughing gas NO, a gas that causes acid rain SO₂, etc. Binary covalent compounds are those that consist of just two components.

The definition of a covalent compound is one in which the atoms are joined by a covalent connection. Compounds with just two elements are referred to as binary covalent compounds.

The name of the given compounds are:

CO₂: Carbon Dioxide

CS₂: Cardon Disulfide

PBr₃: Phosphorus Tribromide

P₂S₅: Phosphorus Pentasulfide

N₂S: Monosulfur Dinitride

SiS₂: Silicon Disulfide

NBr₃: Nitrogen Tribromide

N₂CI₄: Dinitrogen Tetra chloride

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Answer:

true hope that helps

Explanation:

Answer: (a) 6.57 g of methanol (CH3OH) in 1.50 × 102 mL of solution. It is known that ... 32.042 g/mol. In order to calculate the molarity, 1st we have to find out the number of moles, ... 34P: Balance the following equations and write the corresponding ionic a. ... 38P: (a) Without referring to Figure 4.11. give the oxidation numbers of.

Explanation:

Answer:

A,C and E

Explanation:

options A,C and E are true

Answer:                                                                                                                   The tendency of the halogen elements to form salt like (i.e., highly ionic) compounds increases in the following order: astatine < iodine < bromine < chlorine < fluorine. ... The oxidizing strength of the halogens increases in the same order—i.e., from astatine to fluorine.

Explanation:

Answer:

\(50\; \rm mL\) of the stock solution would be required.

Explanation:

Assume that a solution of volume \(V\) contains a solute with a concentration of \(c\). The quantity \(n\) of that solute in this solution would be:

\(n = c \cdot V\).

For the solution that needs to be prepared, \(c = 0.20\; \rm M = 0.20\; \rm mol \cdot L^{-1}\). The volume of this solution is \(V = 250.0\; \rm mL\). Calculate the quantity of the solute (magnesium chloride) in the required solution:

\(\begin{aligned}n &= c \cdot V \\ &= 0.20\; \rm mol \cdot L^{-1} \times 250.0\; \rm mL \\ &= 0.20\; \rm mol \cdot L^{-1} \times 0.2500\; \rm L \\ &= 0.050\; \rm mol\end{aligned}\).

Rearrange the equation \(n = c \cdot V\) to find an expression of volume \(V\), given the concentration \(c\) and quantity \(n\) of the solute:

\(\displaystyle V= \frac{n}{c}\).

Concentration of the solute in the stock solution: \(c(\text{stock}) = 1.00\; \rm M = 1.00\; \rm mol \cdot L^{-1}\).

Quantity of the solute required: \(n = 0.050\; \rm mol\).

Calculate the volume of the stock solution that would contain the required \(n = 0.050\; \rm mol\) of the magnesium chloride solute:

\(\begin{aligned}& V(\text{stock}) \\ &= \frac{n}{c(\text{stock})} \\ &= \frac{0.050\; \rm mol}{1.00\; \rm mol \cdot L^{-1}} \\ &= 0.050\; \rm L \\ &= 50\; \rm mL\end{aligned}\).

Combustion can be defined as the reaction of a compound with oxygen. The enthalpy of combustion of octane is \(\Delta H_{\rm rxn}\) for \(\rm C_8H_{18}\;+\;25\;O_2\;\rightarrow 8\;CO_2\;+\;9\;H_2O\).

The enthalpy of reaction is the amount of heat energy absorbed or lost by the molecules in the chemical reaction.

The enthalpy of combustion is the amount of heat energy released by the compound in the reaction with oxygen.

The reaction in which heat is liberated with the reaction of a compound with oxygen has an enthalpy of combustion, equivalent to the enthalpy of reaction.

The combustion of octane can be given as:

\(\rm C_8H_{18}\;+\;25\;O_2\;\rightarrow 8\;CO_2\;+\;9\;H_2O\)

Thus, the reaction has combustion energy equivalent to the enthalpy of the reaction is \(\rm C_8H_{18}\;+\;25\;O_2\;\rightarrow 8\;CO_2\;+\;9\;H_2O\). Thus, option B is correct.

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Attraction is described as feelings of elation and euphoria produced by neurochemicals, according to anthropologist Helen Fisher and other scientists.

Anthropologist Helen Fisher and other scientists have conducted extensive research on the subject of attraction and its underlying mechanisms. They propose that attraction is not solely a result of external factors or conscious decision-making but is rooted in our biology and neurochemistry.

According to Fisher's research, attraction involves the release of specific neurochemicals in the brain, which contribute to the experience of elation and euphoria. These neurochemicals include dopamine, norepinephrine, and serotonin, among others. When we feel attracted to someone, these chemicals are released, leading to heightened emotional states and positive feelings.

Dopamine, in particular, plays a crucial role in the brain's reward system and is associated with feelings of pleasure and motivation. It is released in response to stimuli that we find rewarding, such as the presence or interaction with someone we are attracted to. This surge of dopamine can result in the feelings of elation and euphoria commonly associated with attraction.

Furthermore, other neurochemicals like norepinephrine and serotonin contribute to the intense emotions experienced during attraction. Norepinephrine is involved in regulating arousal and attention, while serotonin influences mood and emotional well-being.

In summary, attraction involves complex neurochemical processes in the brain that give rise to feelings of elation and euphoria. Understanding these underlying mechanisms can provide valuable insights into the nature of human attraction and interpersonal relationships.

basis of attraction and the research conducted by anthropologist Helen Fisher and other scientists in unraveling the complexities of human emotions and relationships.

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Answer:

magnesium(s) + silver nitrate(aq) → magnesium nitrate(aq) + silver(s). The reducing agent in this reaction is the Mg as it will donate electrons to the silver ions .

Explanation:

225.0 g of water releases -33,646.125 J of heat energy when it cools from 85.5°C to 50.0°C.

To calculate the amount of heat released when water cools, we can use the formula:

Q = m * c * ΔT

Where:

Q is the heat energy in joules,

m is the mass of the water in grams,

c is the specific heat of water in J/g•°C,

ΔT is the change in temperature in °C.

Given:

m = 225.0 g

c = 4.18 J/g•°C

ΔT = (50.0°C - 85.5°C) = -35.5°C (negative because the water is cooling)

Substituting these values into the formula, we have:

Q = 225.0 g * 4.18 J/g•°C * (-35.5°C)Q = -33,646.125 J

The negative sign indicates that heat is being released by the water as it cools. Therefore, 225.0 g of water releases -33,646.125 J of heat energy when it cools from 85.5°C to 50.0°C.

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The Ka of nitrous acid is approximately 4.608 × 10⁻5.

To find the Ka of nitrous acid (\(HNO_{2}\)), we'll use the equilibrium concentrations given in the question. The reaction for nitrous acid dissociation is:

\(HNO_{2}\) ⇌ \(H_{3} O\)+\(NO_{2}\)-

At equilibrium, the concentrations are:
[\(HNO_{2}\)] = 0.050 M
[\(H_{3} O\)+] = [\(NO_{2}\)-] = 4.8 × 10⁻³ M

The Ka expression for nitrous acid is:
Ka = (\(H_{3} O\)+][\(NO_{2}\)-]) / [\(HNO_{2}\)]

Substitute the equilibrium concentrations into the Ka expression:
Ka = (4.8 × 10⁻³)(4.8 × 10⁻³) / 0.050

Now, calculate the Ka value:
Ka ≈ 4.608 ×\(10^{-5}\)

So, the Ka of nitrous acid is approximately 4.608 × \(10^{-5}\)

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While ethanol being an alcohol does have a direct O−H connection. Hence, ethanol has intermolecular hydrogen bonds. Therefore, more stroger physical bonds have to be destroyed in ethanol, than in acetone. Hence, acetone evaporates faster than ethanol inspite of having higher surface tension.

The pressure that a vapour exerts on the condensed phases (solid or liquid) in a closed system when they are in thermodynamic equilibrium with one another is known as vapour pressure (or equilibrium vapour pressure).

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Hydrogen bonds are the intermolecular forces responsible for the production of water dimers.

Between molecules, intermolecular forces are at work. In contrast, molecules themselves exert intramolecular pressures. In comparison to intramolecular forces, intermolecular forces are weaker. The London dispersion forces, dipole-dipole interactions, ion-dipole interaction, & van der Waals forces are a few examples of intermolecular forces.

The equilibrium between the intermolecular interactions and a kinetic energy of a specific particles (atoms or molecules) determines the state of a material. The kinetic energy, which is dependent on the substance's temperature, maintains the molecules separated and in motion.

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The active ingredient in a common treatment for upset stomachs is sodium bicarbonate, Then the percent, by mass, of sodium in sodium bicarbonate is approximately 27.38%.

To calculate the percent by mass of sodium (Na) in sodium bicarbonate (NaHCO3), follow these steps:

1. Determine the molar mass of sodium (Na) and sodium bicarbonate (NaHCO3).
- Molar mass of Na = 22.99 g/mol
- Molar mass of NaHCO3 = (22.99 g/mol for Na) + (1.01 g/mol for H) + (12.01 g/mol for C) + (3 × 16.00 g/mol for O) = 22.99 + 1.01 + 12.01 + 48.00 = 84.01 g/mol

2. Calculate the mass percentage of sodium in sodium bicarbonate.
- Mass percentage of Na = (Molar mass of Na / Molar mass of NaHCO3) × 100
- Mass percentage of Na = (22.99 g/mol / 84.01 g/mol) × 100 = 27.37%

The percent by mass of sodium in sodium bicarbonate is 27.37%.

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1. The enthalpy of reactant is 80 KJ

2. The enthalpy of product is 160 KJ

3. The activaition energy for the reaction is 160 KJ

4. The heat of reaction is 80 KJ

5. The forward reaction is endothermic

6. The addition of catalyst will lower the activation energy

7. The enthalpy of reactant is less than the enthalpy of product

8. False

9. False

10. False

The enthalpy of reactants defines the energy of the reactants while the enthalpy of products defines the energy of product.

From the diagram given, we obtained the following

The activation energy for the reaction can be obtain as follow:

Activation energy = Peak energy - Energy of reactant

Activation energy = 240 - 80

Activation energy = 160 KJ

The heat of reaction can be obtain as follow:

Heat of reaction = Enthalpy of products - Enthalpy of reactants

Heat of reaction = 160 - 80

Heat of reaction = 80 KJ

The heat of reaction obtained above is positive (i.e 80 KJ).

Thus, we can conclude that the forward reaction is endothermic reaction.

A catalyst is a substance which alters the rate of a reaction. Catalyst tends to lower the activation energy of a reaction, thereby enhacing the reaction rate.

However, we must take note of the following:

From the diagram above, we obtain:

We can see that the enthalpy of the reactant is less than that of the products.

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The concentration of hydroxide ions (OH-) in a solution is related to the pH, a measure of acidity or alkalinity. The pH scale ranges from 0 to 14, with a pH of 7 indicating a neutral solution. Higher pH values indicate increasing alkalinity, while lower pH values indicate increasing acidity.

For the solutions with the highest pH studied, the concentration of hydroxide ions would be the highest, as an increase in OH- ions contributes to a more alkaline solution. To find the concentration of OH- ions, we can use the relationship between pH and pOH, where:

pH + pOH = 14

The highest pH studied is not provided, we can consider the maximum pH value of 14. In this case, the pOH would be 0 (since pH + pOH = 14). The concentration of OH- ions can be determined using the equation:

[OH-] = 10^(-pOH)

The pOH value of 0, we find the concentration of hydroxide ions in the solution:

[OH-] = 10^(-0) = 10^0 = 1 mol/L

The solution with the highest pH studied (assuming pH = 14), the concentration of hydroxide ions is 1 mol/L.

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In the hydrogenation of alcohol, Ethanol is the reducing agent and it loses electron.

Alcohol hydrogenase transform ethanol to Acetaldehyde. This known as carcinogen. In this Acetaldehyde is more toxic compound. Alcohol dehydrogenases catalyze the oxidation of primary and secondary alcohols to the corresponding aldehyde or ketone by the transfer of a hydride anion to NAD+ with release of a proton.

Ethanol + NAD^+ ---> acetaldehyde + NADH + H^+

The half reactions are:

Ethanol --------->Acetaldehyde + 2H^+ + 2e (oxidation)

NAD+ + 2H+ + 2e- ------->NADH + H^+ (Reduction)

Ethanol is oxidized to acetaldehyde, because it loses e- .NAD+ is reduced to NADH, because it gain of e− . NAD is the oxidizing agent. Oxidizing agent gains e− and therefore reduced during reaction. Ethanol is the reducing agent. Reducing agent loses e−and therefore oxidized during reaction . Alcohol dehydrogenase is also involved in the toxicity of other types of alcohol.

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All of the given oxides would produce bases when added to water. The correct answer is option D)

When added to water, all of the given oxides would produce bases. Magnesium oxide (MgO), calcium oxide (CaO), and barium oxide (BaO) are all basic oxides since they react with water to form a base. When calcium oxide is added to water, it reacts vigorously to produce calcium hydroxide, a strong base, and heat.

When magnesium oxide reacts with water, it produces magnesium hydroxide, a weak base, and heat. When barium oxide is added to water, it also reacts vigorously to produce barium hydroxide, a strong base, and heat.

Thus, All of the given oxides would produce bases when added to water. The correct answer is option D)

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answer:

the reason is to ensure more solute is dissolving as it cools down. it is important to do it slowly because water will be sucked into buchner flask by a partial vaccum through the rubber tubing and be able to arrange molecules.

the mass defect of Li-7 is -0.035279 u and the nuclear binding energy per nucleon is 5.60553 × 10⁻¹² J/nuclide.

Given data:

Atomic mass of Li-7, A = 7.016003

The atomic mass of Li-7 is the sum of the number of protons and neutrons in it. Therefore, the number of neutrons in Li-7 is:

Neutrons = Atomic mass - Protons= 7.016003 - 3= 4.016003The mass of 3 protons and 4.016003 neutrons in Li-7 is: Mass of protons + Mass of neutrons = (3 x 1.007276) + (4.016003 x 1.008665) = 3.021828 + 4.029454 = 7.051282 u

Therefore, the mass defect in Li-7 is:

Mass defect = Actual mass - Calculated mass

= Atomic mass - Mass of protons and neutrons

= 7.016003 - 7.051282

= -0.035279 u

Nuclear Binding Energy per nucleon (BE/A) can be calculated using the formula:

BE/A = [Δm.c² / A]

where Δm is the mass defect and c is the speed of light which is 2.998 × 10⁸ m/s.

Substituting the values in the above formula:

BE/A = [(-0.035279) × (2.998 × 10⁸)² / 7]= 5.60553 × 10⁻¹² J/nuclide

Therefore, the mass defect of Li-7 is -0.035279 u and the nuclear binding energy per nucleon is 5.60553 × 10⁻¹² J/nuclide.

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Answer:

can you show us question 3 pls

Explanation:

Taking into account the reaction stoichiometry, the mass of Zn required to generate 0.15 mol of H₂ is 9.807 grams.

In first place, the balanced reaction is:

Zn + 2 HCl  → ZnCl₂ + H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: If by reaction stoichiometry 1 mole of H₂ is generated by 65.38 grams of Zn, 0.15 mole of H₂ is generated by how much mass of Zn?

mass of Zn= (0.15 mole of H₂× 65.38 grams of Zn)÷ 1 mole of H₂

mass of Zn= 9.807 grams

Finally, a mass of 9.807 grams of Zn are required.

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The chemist has added approximately 19.71 millimoles of potassium permanganate (KMnO₄) to the flask, calculated by multiplying the volume of the solution (0.45 L) by the molarity of the solution (0.0438 mol/L) and converting to millimoles.

To calculate the millimoles of potassium permanganate (KMnO₄) added to the flask, we need to multiply the volume of the solution (in liters) by the molarity of the solution (in moles per liter).

To calculate the millimoles, we can use the following conversion factor:

1 mole = 1000 millimoles

Millimoles of KMnO₄ = Volume (L) × Molarity (mol/L) × 1000 (mmol/mol)

Plugging in the values:

Millimoles of KMnO₄ = 0.45 L × 0.0438 mol/L × 1000 mmol/mol

Millimoles of KMnO₄ = 19.71 mmol (rounded to two decimal places)

Therefore, the chemist has added approximately 19.71 millimoles of potassium permanganate (KMnO₄) to the flask.

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Answer:

18.73× 10²³ formula units

Explanation:

Given data:

Number of moles of Ca(NO₃)₂ = 3.11 mol

Number of formula units = ?

Solution:

Avogadro number:  

"It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance"  

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

Number of formula units of Ca(NO₃)₂:

1 mole contain 6.022 × 10²³ formula units

3.11 mol ×  6.022 × 10²³ formula units / 1 mol

18.73× 10²³ formula units

Thank you lord lord please thank you lord lord for that you lor

Answer:

Molar mass of gas = 160 g/mol

Explanation:

Given data:

Mass of sample gas = 1.28 g

Temperature of sample gas = 127°C (127+273 = 400K)

Pressure of sample gas = 1 atm

Volume of sample gas = 0.250 L

Molar mass of gas = ?

Solution:

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K

Now we will put the values in formula.

1 atm × 0.250 L = n × 0.0821 atm.L/ mol.K ×400K

0.250 L.atm   = n ×32.84atm.L/ mol

n = 0.250 L.atm/32.84atm.L/ mol

n = 0.008 mol

Molar mass of gas:

Number of moles = Mass/molar mass

0.008 mol = 1.28 g / molar mass

Molar mass = 1.28 g / 0.008 mol

Molar mass = 160 g/mol

Answer:

A and C

Explanation: Don't worry, I gotchu