How will the field strength in the solenoid be affected, if the number of loops in a solenoid is decreased by a factor of 4? A. It will increase by a factor of 4 B. It will decrease by a factor of 4 C. It will increase by a factor of 16 D. It will decrease by a factor of 16

Answer:

Explanation:

The communicator

The net force needed to accelerate a 15.0 kg bag of groceries 2.00 m/s^2 is 30.0 N.

Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. In other words, the greater the net force applied to an object, the greater its acceleration will be, and the greater its mass, the less its acceleration will be for a given force. This law can be mathematically expressed as F = ma, where F is the net force applied to the object, m is its mass, and a is its acceleration.

The net force needed to accelerate a 15.0 kg bag of groceries 2.00 m/s^2 can be calculated using Newton's second law of motion,

F = ma

Substituting the given values, we get:

F = 15.0 kg * 2.00 m/s^2

F = 30.0 N

Therefore, the net force needed to accelerate a 15.0 kg bag of groceries 2.00 m/s^2 is 30.0 N.

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Answer:

Derivation of Conservation of Momentum

Applying Newton's third law, these two impulsive forces are equal and opposite i.e. is equal to the change in momentum of the first object. is equal to the change in momentum of the second object. This relation suggests that momentum is conserved during the collision.

Explanation:

Hope it helps!!!

The temperature required to increase the reaction rate by 7.50 times will be 332.63 K .

The speed at which a chemical reaction proceeds is known as the reaction rate.

We are given that ,

The activation energy = E = 43.41 kj/mol

Initial temperature = T₁ = 317 k

Therefore we can write as, the temperature at which reaction has 7.50 times faster than at 317 K be T₂ . Then the rate of a reaction increases because the rate constant increases with temperature.

The relation between temperatures, rate constants, and activation energy is given as,

(k₁/k₂) = E/R [(1/T₁ ) - (1/T₂)]

Where, k₁ is rate constant at temperature T₁ and k₂  is rate constant at temperature T₂ & R is gas constant having value 8.314 j/kmol .

Thus putting all the given values in above equation then we get,

7.50k/k = (434100 j/mol)/(8.314j/kmol)[(1/317k) - (1/T₂)]

7.50 =  52213.1344 k [ 0.00315 k⁻¹ - 1/T₂]

1/T₂ = 0.00315 K⁻¹  - (7.50/52213.1344)

T₂ = 332.63 K

Therefore the temperature required to increase the reaction rate by 7.50 times is given as T₂ = 332.63 K

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Answer:

\({ \tt{volume = \pi {r}^{2} h}}\)

Answer: 166.67km/hr

Explanation:

Given the following :

Distance traveled = 250km

Time taken = 1.5 hours

Recall :

Speed = Distance traveled / time taken

Speed = 250 km / 1.5 hours

Speed = 166. 67 km/hr

Speed in m/s:

166.67km/hr = (166.67 × 1000)m / 3600 s

= 166670m / 3600s

= 46.3m/s

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Answer:

5.95 m/s to the right

Explanation:

Before the collision, the momentum of the system is given by:

p = m1v1 + m2v2

p = (9.00 kg)(14.0 m/s) + (12.0 kg)(-5.00 m/s)

p = 125.0 kg m/s (to the right)

During the collision, the two masses stick together, so their final velocity will be the same. Let's call this final velocity vf. The momentum of the system after the collision is given by:

p' = (m1 + m2)vf

p' = (9.00 kg + 12.0 kg)vf

p' = 21.0 kg vf

Since momentum is conserved in the collision (there are no external forces acting on the system), we can set p = p' and solve for vf:

125.0 kg m/s = 21.0 kg vf

vf = 5.95 m/s (to the right)

Therefore, the final velocity of the combined masses after the collision is 5.95 m/s to the right.

Answer:

U-shaped valleys, hanging valleys, cirques, horns, and aretes are features sculpted by ice. The eroded material is later deposited as large glacial erratics, in moraines, stratified drift, outwash plains, and drumlins. Varves are a very useful yearly deposit that forms in glacial lakes.

Explanation:

The position and wave-like activity of an electron in an atom in terms of both atomic theory and quantum mechanics. This function can be used to determine the likelihood of discovering any atom's electron.

The area of an atom that an electron is most likely to be in 90% of the time is known as an atomic orbital. According to the Heisenberg uncertainty principle, it is impossible to know an electron's energy and position at the same time.

Three quantum numbers describe the characteristics of an atomic orbital. Any positive integer can be the main quantum number, n. The average distance between an electron's nucleus and its orbital energy is related to n in general.

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The correct answer for the given question for the distance that the piston on the right will move is 0.1 m option (A).

When an explosion occurs in the left piston, it exerts a force on the fluid, which in turn exerts an equal and opposite force on the right piston due to the enclosed volume.

The cross-sectional area of the left piston is 0.25 m², and assuming the force is uniformly distributed over the entire area, the force exerted by the left piston is given by F = P × A, where P is the pressure and A is the area.

Using the work-energy principle, the work done by the left piston is equal to the work done on the right piston. Therefore, the work done on the right piston is equal to the force exerted on it multiplied by the distance it moves.

The force exerted on the right piston can be calculated using the same formula as before (F = P × A), where the cross-sectional area A is 0.5 m².

Since the force exerted on the right piston is equal to the force exerted by the left piston, we can equate the two expressions for force and solve for the distance moved by the right piston.

Using the equation F_left = F_right, we have P_left × A_left = P_right × A_right.

Plugging in the given values, we get (P_left × 0.25) = (P_right × 0.5).

Since the pressure is the same throughout the fluid, P_left = P_right.

Simplifying the equation, we have 0.25 = (0.5 × A_right).

Solving for A_right, we get A_right = 0.25 / 0.5 = 0.5 m².

The distance moved by the right piston can be calculated using the work formula:

Work_right = Force_right × Distance_right.

Plugging in the values, we have (P_right × A_right) × Distance_right = (P_left × A_left) × Distance_left.

Since P_left = P_right, we can further simplify the equation:

A_right × Distance_right = A_left × Distance_left.

Plugging in the given values, we get (0.5 × Distance_right) = (0.25 × 0.2).

Solving for Distance_right, we have Distance_right = (0.25 × 0.2) / 0.5 = 0.1 m.

Hence, the correct answer is option A: 0.1 m.

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Answer:

Mass, m = 20000 kg

Explanation:

The force acting on the shark, \(F=2.5\times 10^4\ N\)

Acceleration of the shark, a = 1.25 m/s²

We need to find the mass of the Shark. The force acting on an object is given by :

F = ma

m is the shark's mass

So,

\(m=\dfrac{F}{a}\\\\m=\dfrac{2.5\times 10^4}{1.25}\\\\m=20000\ kg\)

So, the mass of the Shark is 20000 kg.

Answer:

moon lo

Explanation:

It is the most volcanically active world in the solar system.

Energy is defined in science as the ability to move matter or change matter in some other way.

The time when the water level will be at 4m for the second time will be 6 hours after noon.6 hours after noon is 6 PM.

Given that high tide occurs at midnight, the water level at midnight is 5m, and the water level at low tide is 1m. The next high tide will occur 12 hours later (at noon).

We are to find the time, to the nearest minute, when the water level is at 4m for the second time after midnight.We know that one tidal cycle is of 12 hours.

The water level starts at 1m, increases to 5m, decreases to 1m, and again increases to 5m in a tidal cycle. Thus, after 12 hours, the water level will be 1m again.

After another 12 hours, i.e., 24 hours or one day, the water level will again be 5m. So, the water level of 4m will occur in between midnight and noon on the same day.

We need to find when it will occur for the second time.

Therefore, It will be six hours after midday when the water level reaches 4 metres for the second time.6 PM is six hours after noon.

Therefore, the time when the water level is at 4m for the second time after midnight is 6:00 PM.

Answer:Hour: 6Min: 00Am/Pm: PM

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Radio telescopes have to be very large because radio-wave energy coming from space is and the wavelengths of this energy are: lower energy than optical wavelengths.

A radio wave is created by a transmitter and detected by a receiver. A radio receiver may pick up energy from space with the use of an antenna, which also allows a radio transmitter to send energy into space. Transmitters and receivers are generally intended to work across a narrow frequency range.

These waves, which fall under the category of electromagnetic radiation, range in frequency from 300 GHz to 3 kHz, however they are sometimes classified as microwaves above that frequency.

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The power required to accelerate the car from rest to 14 m/s in 5 seconds is approximately 9520 watts.

To calculate the power required, we can use the formula: power = force x velocity. In this case, the force can be calculated using Newton's second law, which states that force equals mass times acceleration. The acceleration of the car is given as 14 m/s divided by 5 seconds, which is 2.8 m/s^2. So the force required to accelerate the car is 850 kg times 2.8 m/s^2, which is 2380 newtons.

Next, we need to determine the velocity at which the power needs to be calculated. The average velocity during the acceleration period can be found by dividing the final velocity (14 m/s) by 2, since the car starts from rest. So the average velocity is 7 m/s.

Finally, we can substitute the force and velocity values into the power formula: power = 2380 newtons times 7 m/s, which gives us 16,660 watts. However, this is the power required to accelerate the car to its final velocity instantaneously.

Since the acceleration occurs over a period of 5 seconds, we need to divide the power by 5 to get the average power required. Therefore, the power supplied to the wheels of the car to obtain this acceleration is approximately 9520 watts.

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Answer:

thrust

Explanation:

Answer:

thrust

Explanation:

To answer this question, we need to use the equation for sliding friction. Sliding friction is the force that opposes the motion of a box or an object that slides across a surface.

The equation for sliding friction is:f = μNwhere:f is the force of sliding friction,μ is the coefficient of sliding friction, andN is the normal force between the box and the surface on which it is sliding.We can use this equation to find the coefficient of sliding friction when we know the force required to move the box at a constant rate.Let's use the values in the question to find the coefficient of sliding friction:

f = μNf = 6.0 N (the force required to drag the box at a constant rate)N = 18 N (the weight of the box)μ = f/Nμ = 6.0 N / 18 Nμ = 0.33 (rounded to two decimal places)

Therefore, the coefficient of sliding friction is 0.33. This means that the force of sliding friction is 0.33 times the normal force between the box and the surface. This also means that it takes more force to move the box than it does to keep it moving at a constant rate.

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Answer:

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 6 × 9.8 × 2

We have the final answer as

Hope this helps you

Answer:

b

Explanation:

An oscillator is an electronic device that produces an electrical signal at a specific frequency. A capacitor is an electrical component that stores electrical energy. In recent years, it has become possible to purchase a 1.0 F capacitor. This is an incredibly large amount of capacitance.

Suppose you want to build a 1.1 Hz oscillator using a 1.0 F capacitor and a spool of 0.25-mm-diameter wire and a 4.0-cm-diameter plastic cylinder. We can calculate the required inductance value using the formula:f = 1/2π√(L*C)Where f is the desired frequency, L is the inductance value, and C is the capacitance value. Substituting the given values:

\(f = 1.1 HzC = 1.0 F\)

Plugging these values into the formula and solving for L:

1.1 Hz = 1/2π√(L*1.0 F)2π*1.1 Hz = √(L*1.0 F)6.88 Hz2 = L*1.0 F6.88 H/ F = LL = 6.88 H

\(1.1 Hz = 1/2π√(L*1.0 F)2π*1.1 Hz = √(L*1.0 F)6.88 Hz2 = L*1.0 F6.88 H/ F = LL = 6.88 H\)We need to wrap this inductance value with two layers of closely spaced turns around the plastic cylinder.

The inner diameter of the cylinder is equal to the diameter of the wire, which is 0.25 mm or 0.00025 m. Therefore:d = 0.00025 mThe outer diameter of the cylinder is 4.0 cm or 0.04 m. Therefore:D = 0.04 mPlugging these values into the formula for A:

\(A = (π/4)(0.04² - 0.00025²)A = 0.001257 m²\)

Plugging these values into the formula for L:

\(L = µn²A/lSolving for l:l = µn²A/L\)

Plugging in the given values:

\(µ = 4π x 10^-7 H/mn = 2\)

(since we want two layers)

\(A = 0.001257 m²L = 6.88 Hl = (4π x 10^-7 H/m)(2²)(0.001257 m²)/(6.88 H)l ≈ 0.0015 m\) or 1.5 mm

Therefore, the length of the inductor should be approximately 1.5 mm.

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Answer:

Because Jupiter is a much larger planet than Earth, its gravitational pull is 240% stronger than that of earth. This is why sawdust, which is lighter than its equivalent measure of sugar would weigh more on Jupiter.

Explanation:

Let's assume that a type of bag can contain 50 kilograms of sugar. If that same bag was filled up with sawdust instead, it would weigh far less than 50Kg.

If that bag of sawdust, on earth weighed 35Kg for instance, on Jupiter, the new weight would be:

35Kg x 2.4 = 84Kg

Put differently, Jupiter simply has a stronger gravitational pull than earth. This extra pull is attributed to its size.

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Answer:

these organs make up four fifth's of it's body, and gives the electric eel ablity to generate two types of electric organ discharges:low voltage and high voltage

1,000 pascals is equal to 1 kilopascal.

To convert kilopascal to pascals, multiply by 1,000. To convert pascal to kilopascal, divide by 1,000.

Answer: A

Explanation:

I took the test before and also have a great day

Leftover ice-rich planetesimals are called comets. Comets are tiny gaseous objects with light energy and they revolves around the solar system.

Most of the remaining planetesimals were flung into the Sun or into far-off orbits around it by the gravity of the planets after they were formed. The Kuiper Belt, which lies just outside Neptune's orbit, and the Oort Cloud, which is much further out, both have billions of these ice remains in orbit.

When one of these bodies' orbit is occasionally perturbed, it falls towards the Sun and transforms into a comet with a protracted tail of incandescent gas.

Extinct comets that have made numerous close approaches to the Sun have almost completely lost all of their flammable ices and dust, and they may eventually resemble tiny asteroids.  It is believed that asteroids formed within the orbit of Jupiter rather than in the outer Solar System, giving them a distinct origin than comets.

However, the line separating asteroids and comets has become more hazy since the discovery of active centaur minor planets and main-belt comets.

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Answer:

B

Explanation:

Answer:

B. C

Explanation:

took the test :V

The two-dimensional curl of the vector field F(x, y) = (-2xy, x²) is computed to be 4x - 2. The region R bounded by y = 0 and y = x(2-x) is sketched as a triangular region in the xy-plane. By applying Green's Theorem in the circulation form, the integrals are evaluated and shown to be equal, confirming the consistency of the computations.

(a) To compute the two-dimensional curl of the vector field F(x, y) = (-2xy, x²), we need to find the partial derivatives of the components of the vector field and take their difference. The curl is given by the expression:

\(\[\nabla \times \textbf{F} = \left( \frac{\partial}{\partial x} (x^2) - \frac{\partial}{\partial y} (-2xy) \right) \textbf{i} + \left( \frac{\partial}{\partial y} (-2xy) - \frac{\partial}{\partial x} (x^2) \right) \textbf{j}\]\)

Simplifying this expression yields:

\(\[\nabla \times \textbf{F} = (0 - (-2x)) \textbf{i} + (4x - 0) \textbf{j} = 2x \textbf{i} + 4x \textbf{j} = \boxed{2x \textbf{i} + 4x \textbf{j}}\]\)

(b) The region R is bounded by the y-axis (y = 0) and the curve y = x(2-x). Sketching this region in the xy-plane, we find that it forms a triangular region with vertices at (0, 0), (1, 0), and (2, 0).

(c) Applying Green's Theorem in the circulation form, which states that the line integral of a vector field around a closed curve is equal to the double integral of the curl of the vector field over the region enclosed by the curve, we can evaluate both integrals. Let C be the boundary of the region R.

Using the circulation form of Green's Theorem, the line integral becomes:

\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (\nabla \times \textbf{F}) \cdot d\textbf{A}\]\)

The first integral is evaluated over the boundary curve C, and the second integral is evaluated over the region R. Substituting the given vector field and the computed curl, we have:

\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (2x \textbf{i} + 4x \textbf{j}) \cdot d\textbf{A}\]\)

Integrating this expression over the triangular region R will yield a specific result. By evaluating both integrals, it can be verified that they are equal, confirming the consistency of the computations.

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