how to lower the intensity of the Bunsen burner

Answer:This pressure is transmitted throughout the liquid and makes it more difficult for bubbles to form and for boiling to take place. If the pressure is reduced, the liquid requires less energy to change to a gaseous phase, and boiling occurs at a lower temperature

Explanation:

Atmospheric Pressure and Boiling

The pressure of gas above a liquid affects the boiling point. ... If the pressure is reduced, the liquid requires less energy to change to a gaseous phase, and boiling occurs at a lower temperature

B

The sodium hydroxide (NaOH) solution is a basic solution, so the pH of that solution should be close to 14

then when adding hydrochloric acid (HCl) we start to neutralice the solution, meaning the pH must sift slowly to lower pH.

Assuming both solutions have similar concentration the pH shall shift form basic (above 7) to acid pH (below 7). Until now both B and D images agreed with the explanation given. To chose between them we need to remember that HCl is a very strong acid, which means that in solution will get to very acid solutions (very low pH values) which leaves only B as possible answer

Answer:

b. source

Explanation:

The source is where something comes from. i.e. The source of sunlight is the sun.

Answer:

PLZ HELP ME. This is my second time posting my question because the first time a person put a random answer. If you do not know the question please do not answer it and leave it to someone else. Thank you, and my question is on the attached image below

Explanation:

PLZ HELP ME. This is my second time posting my question because the first time a person put a random answer. If you do not know the question please do not answer it and leave it to someone else. Thank you, and my question is on the attached image below.

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The atom is neutral as the number of electrons and neutrons is the same.

Mathematically,

Charge

= +40 + (-40)

= +40 - 40

=0

Note: Neurons have no charge

Answer:

Explanation:

i think c

Answer:

False

Bouyant force = volume of displaced fluid * density of fluid

The most important mineral for making the drywall used for the residential home construction is gypsum.

The soft sulfate mineral gypsum has the chemical formula CaSO4.2H2O and is made up of calcium sulfate dihydrate. It is widely mined, used as fertilizer, and the primary component of numerous plaster, sidewalk or blackboard chalk, and drywall products.

Gypsum may be found as beautiful crystals and as thick layers within shale. Gypsum deposits are never entirely pure. It is typically discovered in deposits that contain a mixture of limestone, sand, shale, anhydrite, and occasionally rock salt.

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The reaction for the formation of HI, at the given time, has a reaction quotient of 613.

What is the reaction quotient?

Reaction quotient is the ratio of the concentration of product and reactant raised to the stoichiometric power at a given time interval.

The chemical reaction for the formation of HI is given as:

\(\rm H_2\;+\;I_2\;\rightarrow\;2\;HI\)

The reaction quotient is given as:

\(\rm Q=\dfrac{[HI]^2}{[H_2]\;[I_2]}\)

The concentration of system at the time, t has been:

Hydrogen = 0.1 M

Iodine = 0.2 M

HI = 3.5 M

Substituting the values for reaction quotient:

\(\rm Q=\dfrac{(3.5)^2}{(0.1)(0.2)}\\ Q=613\)

The reaction quotient for the reaction is 613. Thus, option D is correct.

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Answer:

di ko maintindihan anggulo ng isinulat

The mass of oxygen gas produced, given that 15.8 g of potassium permanganate is heated until no more oxygen gas is given off is 1.6 g

From the question given, the following data were obtained:

The mass of oxygen gas produced from the reaction can be obtained as follow:

Mass of potassium permanganate = Mass of remaining substance + mass of oxygen

Inputting the given parameters, we have:

15.8 = 14.2 + mass of oxygen

Collect like terms,

Mass of oxygen = 15.8 - 14.2

= 1.6 g

Thus, we can conclude that the mass of oxygen gas produced from the reaction is 1.6 g

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No approximations or assumptions need to be made in the calculation of the pH and the tartrate ion 1C4H4O6 2-2 concentration for a 0.250 M solution of tartaric acid.

The pH and the tartrate ion 1C4H4O6 2-2 concentration of a 0.250 M solution of tartaric acid can be calculated using the acid-dissociation constants and the Henderson-Hasselbalch equation. The acid-dissociation constants (Ka1 and Ka2) of tartaric acid are 1.14x10-2 and 5.01x10-5, respectively.

The pH of the solution can be calculated using the Henderson-Hasselbalch equation: pH = pKa + log([base]/[acid]) where [base] is the concentration of the conjugate base (the tartrate ion) and [acid] is the concentration of the acid (tartaric acid). Since the solution is 0.250 M in tartaric acid, [acid] = 0.250 M and [base] = 0.250 M - [tartrate ion], which can be calculated using the Ka1 and Ka2 values.

For Ka1, the tartrate ion 1C4H4O6 2-2 concentration can be calculated as 0.250 M - 0.250 * 1.14x10-2 = 0.249 M. For Ka2, the tartrate ion 1C4H4O6 2-2 concentration can be calculated as 0.250 M - 0.250 * 5.01x10-5 = 0.249 M.

Using the Henderson-Hasselbalch equation, the pH of the solution can be calculated as pH = pKa + log([base]/[acid]). The pKa values of tartaric acid are 3.92 and 5.63 respectively. Therefore, for Ka1, the pH of the solution can be calculated as pH = 3.92 + log(0.249/0.250) = 3.91, and for Ka2, the pH of the solution can be calculated as pH = 5.63 + log(0.249/0.250) = 5.63.

No approximations or assumptions need to be made in the calculation of the pH and the tartrate ion 1C4H4O6 2-2 concentration for a 0.250 M solution of tartaric acid, as the Henderson-Hasselbalch equation and the acid-dissociation constants of tartaric acid can be used.

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P-aminobenzoic acid is an organic compound with the chemical formula C₇H₇NO₂. When sulfuric acid (H₂SO₄) is added to a solution of p-aminobenzoic acid, it can cause the precipitation of the compound.

This is due to a chemical reaction that occurs between the acid and the amino group (-NH₂) on the benzene ring of the p-aminobenzoic acid. Sulfuric acid is a strong acid that can donate protons (H⁺) to other molecules, such as p-aminobenzoic acid.  When it is added to a solution of p-aminobenzoic acid, the sulfuric acid reacts with the amino group to form an ammonium sulfate salt, which is not soluble in water.

The ammonium sulfate salt then precipitates out of solution as a solid, causing the p-aminobenzoic acid to also precipitate out.The reaction between p-aminobenzoic acid and sulfuric acid is an example of a salt formation reaction.  This type of reaction involves the combination of an acid and a base to form a salt and water. In this case, the amino group on the p-aminobenzoic acid acts as the base, while the sulfuric acid acts as the acid.

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Answer:

calcium oxide CaO

hope it helps

Answer:

.75 Tons

Explanation:

1 Ton is equal to 2,000 pounds

Answer

-52.2 Joules

Explanation

Given that;

Mass of krypton, m = 12.3 g

Temperature change, ΔT = 22.2°C - 39.3°C = -17.1°C

The specific heat of gaseous krypton, c = 0.248 J/g°C.

What to find:

The energy change, Q.

Step-by-step solution:

The energy change, Q can be determined using:

Q = mcΔT

Putting the values of the given parameters into the formula, this yields:

Therefore the energy change = -52.2 Joules

The ratio of the volume and temperature of the gas in the given table is as follows:

Charles's law, also known as the law of volumes, describes the relationship between the volume and temperature of a gas at a constant pressure. According to this law, the volume of a gas is directly proportional to its absolute temperature (measured in Kelvin) when the pressure is constant.

In other words, as the temperature of a gas increases, its volume will also increase proportionally, and vice versa. Mathematically, Charles's law can be expressed as:

V/T = k

where V is the volume of the gas, T is its temperature in Kelvin, and k is a constant of proportionality.

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Answer:

Electrolysis of Al₂O₃: 4Al³⁺ (s) + 6O²⁺ (g) → 4Al (s) + 3O₂ (g)

Reduction of Elemental Fe: 2Fe₂O₃ (s) + 3C (s) → 4Fe (s) + 3CO₂ (g)

Atom Economy for Electrolysis of Al₂O₃: 52.9227%

Atom Economy for Reduction of Fe₂O₃: 62.8534%

Explanation:

Step 1: Define Compounds

Aluminum Oxide - Al₂O₃

Iron Oxide - Fe₂O₃

Step 2: RxN

Al₂O₃ (s) → Al (s) + O₂ (g)

Fe₂O₃ (s) + C (s) → Fe (s) + CO₂ (g)

Step 3: Balance RxN

2Al₂O₃ (s) → 4Al (s) + 3O₂ (g)

This is ONLY the decomposition reaction for Aluminum oxide, NOT the electrolysis.

2Fe₂O₃ (s) + 3C (s) → 4Fe (s) + 3CO₂ (g)

This is the final single-replacement reaction for the reduction of Iron Oxide to Iron.

Step 4: Electrolysis of Al₂O₃

We will have to use oxidation-reduction reactions (half-reactions). Let's break up the reaction into it's elements.

Al³⁺ + ? → Al

Al³⁺ + 3e⁻ → Al

O²⁻ → O₂ + ?

2O²⁻ → O₂ + ?

2O²⁻ → O₂ + 4e⁻

Our half reactions:

Al³⁺ + 3e⁻ → Al

2O²⁻ → O₂ + 4e⁻

4 (Al³⁺ + 3e⁻ → Al) = 4Al³⁺ + 12e⁻ → 4Al

3 (2O²⁻ → O₂ + 4e⁻) = 6O²⁻ → 3O₂ + 12e⁻

4Al³⁺ + 12e⁻ + 6O²⁺ → 4Al + 3O₂ + 12e⁻

4Al³⁺ (s) + 6O²⁺ (g) → 4Al (s) + 3O₂ (g)

Step 5: Atom Economy

According to GCSE and my own deciphering, your equation for Atom Economy is essentially calculating for something similar to percent yield (but not quite).

\(Atom \hspace{3} Economy \hspace{3} = \hspace{3} \frac{Molar \hspace{3} Mass \hspace{3} of \hspace{3} Product}{Molar \hspace{3} Mass \hspace{3} of \hspace{3} All \hspace{3} Reactants} \cdot 100 \%\)

Molar Mass of Al - 26.98 g/mol

Molar Mass of O - 16.00 g/mol

Reactants: 4(26.98 g/mol) + 6(16.00 g/mol) = 203.92 g/mol

Products (Al as end product): 4(26.98 g/mol) = 107.92 g/mol

\(Atom \hspace{3} Economy \hspace{3} = \hspace{3} \frac{107.92 \hspace{3} g/mol}{203.92 \hspace{3} g/mol} \cdot 100 \%=52.9227 \%\)

Molar Mass of Fe - 55.85 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of C - 12.01 g/mol

Reactants: 4(55.85 g/mol) + 6(16.00 g/mol) + 3(12.01 g/mol) = 355.43 g/mol

Products (Fe as end product): 4(55.85 g/mol) = 223.4 g/mol

\(Atom \hspace{3} Economy \hspace{3} = \hspace{3} \frac{223.4 \hspace{3} g/mol}{355.43 \hspace{3} g/mol} \cdot 100 \%=62.8534\%\)

Step 6: Check for significant figures

Since we are not given any values, we don't really need to change any numbers to fit sig fig rules.

The statement is False

If the weather station is completely filled in, the sky is considered to have 8/8 cloud cover or 80/100 cloud cover, indicating that the entire sky is covered in clouds.

The small flag indicating wind direction on a station weather plot points in the direction from which the wind is coming. This convention is followed to ensure consistency and to avoid confusion. By pointing in the direction from which the wind is coming, it allows observers to easily understand the wind's direction relative to the station's location.

The amount of the sky covered in clouds can be determined by using a system called the cloud cover code, which is represented in eighths or octas. Each octa represents one-eighth of the sky. So, if the weather station is completely filled in, it means the sky is completely covered in clouds, which corresponds to eight octas or 8/8 cloud cover.

Cloud cover is often reported in terms of tenths as well. In this case, each tenth represents 1/10th of the sky. To convert from octas to tenths, we multiply the octas by 10. Therefore, if the sky is completely filled in with clouds (8 octas), it would be equivalent to 8/8 or 80/100 cloud cover, which is 80% of the sky covered in clouds.

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Explanation:

The molecules of solids are shrinked in there normal state . but as a heat energy is produced , the molecules starts curating fast and fast as temperature goes up . since they vibrate , they hit and collide each other breaking the bondings this increases the surface of area of the solid , and molecules consumes that space and they expand .

Answer:

The energy of the molecules in the apple decreased.

Explanation:

A.

The location of the nucleus within an atom can be determined by measuring half the distance between the nuclei of two bonded atoms.

The Covalent radius can be described as a value used to understand the covalently bonded atoms, while the atomic number can be described as the number of protons and neutrons that are present in the atomic nucleus, which permits us to get the relative distance between one atom and other atoms.

The atomic number is useful in order to determine different elements since they are made of a variable number of positively charged protons and neutrons, as well as the number of negatively charged electrons around the nucleus.

Therefore, the Covalent radius and atomic number are fundamental in order to determine the number of protons and neutrons. The covalent radius can be used to determine the location of the nucleus within an atom.

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Answer:

1) 40

2) 2.25 moles

3) 17

4) 120

5) Fe₂O₃

Explanation:

Please see attached picture for full solution.

Answer:

1) \(\boxed{Molar \ mass = 40\ g/mol}\)

2) \(\boxed{No.\ of\ Moles = 1.61 \ moles}\)

3) \(\boxed{Ammonia = 16\ g/mol}\)

4) \(\boxed{Sodium\ Hydrogen\ Sulphate= 120 \ g/mol}\)

5) \(\boxed{Fe_{2}O_{3}}\)

Explanation:

Question # 1:

Using Formula, No. of moles = Mass in grams / molar mass

Where moles = 0.375 mol. , mass = 15 g

=> Molar Mass = Mass in grams / No. of moles

=> Molar Mass = 15 / 0.375

=> Molar mass = 40 g/mol

Question # 2:

No. of moles = Mass in grams / Molar mass

Where Mass = 90 g ,

=> Molar Mass = \(MgO_{2}\)

=> MM = 24 + (16*2)

=> MM = 24 + 32

=> MM = 56 g/mol

No. of Moles = 90 / 56

No. of Moles = 1.61 moles

Question # 3:

Ammonia => \(NH_{3}\)

N has atomic mass 14 ang H has atomic mass 1

Ammonia = (14)+(1*2)

Ammonia = 14+2

Ammonia = 16 g/mol

Question # 4:

Sodium Hydrogen Sulphate => \(NaHSO_{4}\)

Where Na has atomic mass 23, H has atomic mass 1 , sulpher 32 and oxygen 16

\(NaHSO_{4}\) = 23+1+32+(16*4)

=> 56+64

=> 120 g/mol

Question # 5:

The metal which has relative atomic mass of 56 is Iron (Fe)

Given that the oxide contains 70.0 % of Metal

Mass of \(MO_{x}\) (Metal oxide) = 56 / 70 * 100

Mass of \(MO_{x}\) (Metal oxide)  = 0.8 * 100

Mass of \(MO_{x}\) (Metal oxide)  = 80

Mass of x O's = 80 - 56

Mass of x O's = 24

Now, Mass of O = 24 / 16

Mass of O = 1.5

So, Fe Metal and its oxide are in the ratio of

1 : 1.5

×2   ×2

2 : 3

So, the empirical formula of metal with its oxide is \(Fe_{2}O_{3}\)

Answer:

A. The largest value is 7 and the smallest value is 1. Find the difference. 7 - 1 = 6.

Explanation:

The answer to the problem 3.96 * 0.1159 is : 0.459 (3 significant figures)

Significant figures can be defined as numbers in a group of numbers that place number in the right value or worth.

Significant figures defined the value of measurement of  a particular number.

The rules of engagement in this case is the set of rules or laid down principles that direct how we interact with this significant figures and how they are used.

For this case the significant figures of the product will be the same as the figure with the least significant figure in the multiplication.

In conclusion, The answer to the problem 3.96 * 0.1159 is : 0.459 (3 significant figures)

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Steps of the technological design process include: identify a problem, research the problem, generate possible solutions, select the best solution, create a model, test the model, refine and retest the model as needed, and communicate the final solution.

Answer : The volume of kristas rock is 30 mL.

Explanation :

From the given image we conclude that:

Initial volume of liquid = 150 mL

Final volume of liquid = 180 mL

Now we have to determine the volume of kristas rock.

Volume of kristas rock = Final volume of liquid - Initial volume of liquid

Volume of kristas rock = 180 mL - 150 mL

Volume of kristas rock = 30 mL

Therefore, the volume of kristas rock is 30 mL.

Answer:

\(1.29 * 10^{24}\) particles of gold

Explanation:

To convert the number of moles of any substance, in this case gold, you need Avogadro's number.

Avogadro's number is always \(6.022\) × \(10^{23}\)

\(2.15\) moles Au × \(\frac{6.022*10^{23} particles}{1 mole Au}\) = \(1.29 * 10^{24}\) particles of gold

The number of representative particles in 2.15 moles of gold is 1.29 × 10 ²⁴.

The term mole is defined as the amount of  substance containing 6.023 × 10²³ particles. 1 mol = 6.023 × 10²³ particles. This number is also called Avogadro's number. The symbol of mole is denoted by M.

A mole is a very important unit of measurement that chemists use. By using moles, chemists have to measure for very small things like atoms, molecules, or other particles.

The quantity amount of substance is a measure of how many elementary entities of a given substance are present in it.

To convert the number of moles of any substance, we required Avogadro's number.

Avogadro's number is always equal to 6.023 × 10 ²³

2.15 moles Au × 6.023 × 10 ²³ particles / 1 mole of Au

= 1.29 × 10 ²⁴ particles of gold

Thus, the number of representative particles in 2.15 moles of gold is 1.29 × 10 ²⁴.

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To synthesize 2-methylpentan-3-one efficiently, following process has to be followed:

Start with the synthesis of 2-methylpentan-3-ol, which can be prepared via a Grignard reaction. Firstly, prepare 2-methylpentan-3-ol by reacting ethyl magnesium bromide with 3-methylbutanal.

Afterward, hydrolysis of this Grignard reagent using HCl or dilute sulfuric acid provides the alcohol.2-methylpentan-3-ol.

( Grignard reaction -The Grignard reaction is an organometallic chemical reaction in which carbon alkyl, allyl, vinyl, or aryl magnesium halides (Grignard reagent) are added to the carbonyl groups of either an aldehyde or ketone. This reaction is important for the formation of carbon–carbon bonds.)

Now,the oxidation of 2-methylpentan-3-ol is carried out using oxidizing agents like PCC (pyridinium chlorochromate), PDC (pyridinium dichromate), or Jones reagent to synthesize 2-methylpentan-3-one.Oxidation of 2-methylpentan-3-ol to synthesize 2-methylpentan-3-one can be represented as follows: PCC or PDC or Jones Reagent2-methylpentan-3-one.

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